Filter channel entries by slug Is there any way to output the content of a channel entry by their slug?

For example, say I have an asset field called "image" in each channel entry, I want to output the content of that field only for the channel entry filtered by the slug "home", I've tried both:

{% for item in craft.entries.section('images').slug('home') %}
    {{ item.image.first() }}
{% endfor %}


and

{% for item in craft.entries.section('images').find().slug('home') %}
    {{ item.image.first() }}
{% endfor %}


but neither work...
The second example won't work since .find() should be at the end of the ElementCriteriaModel. But since you treat the CriteriaModel like an array, you don't need to add it at all. 

Your first code looks correct, but you should check if the loop found an entry:

{% for item in craft.entries.section('images').slug('home') %}
    ....
{% else %}
    No entry found
{% endfor %}


Also your current code is only outputting the title of the AssetFileModel:


  Outputting an AssetFileModel object without attaching a property or
  method will return the asset’s Title


That's why you should add the "url" property, and also check whether the field contains an asset:

{% for item in craft.entries.section('images').slug('home') %}
    {% set asset = item.image.first() %}

    {% if asset %}
       {{ asset.url }}
    {% else %}
        No asset added to the field
    {% endif %}
{% else %}
    No entry found
{% endfor %}