Paginate children in a structure Or to say it in a different way, paginate siblings.

I found this question on stack: How do you page through child entries in a structure? which seems to have a working answer. However trying this myself I get no results.

To be clear, I have a two level structure.

Level 1 (parent)
 - Level 2 (child)
 - Level 2 (child)
 - and so on..


How can I paginate the children?

Thank you for any input!
There are many ways to paginate:

To show next / prev links

#1
getPrevSibling getNextSibling

{% if entry.getPrevSibling %}
    &lt;a href="{{entry.getPrevSibling.url}}"&gt;{{entry.getPrevSibling.title}}&lt;/a&gt;
{% endif %}

{% if entry.getNextSibling %}
    &lt;a href="{{entry.getNextSibling.url}}"&gt;{{entry.getNextSibling.title}}&lt;/a&gt;
{% endif %}


#2 getPrev getNext

{% set params = {section: entry.section.handle} %}
{% set prev = entry.getPrev(params) %}
{% set next = entry.getNext(params) %}

{% if prev %}
    &lt;a href="{{prev.url}}"&gt;{{prev.title}}&lt;/a&gt;
{% endif %}

{% if next %}
    &lt;a href="{{next.url}}"&gt;{{next.title}}&lt;/a&gt;
{% endif %}


To show list of children (single type page)

{% paginate %}

{% paginate craft.entries.section('sectionHandle').limit(10) as pageEntries %}

{% for entry in pageEntries %}
    &lt;article&gt;
        &lt;h1&gt;{{ entry.title }}&lt;/h1&gt;
        {{ entry.body }}
    &lt;/article&gt;
{% endfor %}

{% if pageInfo.prevUrl %}&lt;a href="{{ pageInfo.prevUrl }}"&gt;Previous Page&lt;/a&gt;{% endif %}
{% if pageInfo.nextUrl %}&lt;a href="{{ pageInfo.nextUrl }}"&gt;Next Page&lt;/a&gt;{% endif %}