Finding the odd row between two tables in Oracle
One-to-one based on what?

You have no reliable and permanent way of identifying/sorting rows in TableA. You have A03, Pineapple twice. Which will be the 3rd and which will be the 4th?

Sure, you can do the below, but forget this right away and fix your data. Rowids can change when moving data so the order is never guaranteed.

create table tablea(id varchar2(3 char), fruit varchar2(9 char));
create table tableb(id varchar2(3 char), fruit varchar2(9 char));

insert into tablea values ('A01', 'Apple');
insert into tablea values ('A02', 'Orange');
insert into tablea values ('A03', 'Pineapple');
insert into tablea values ('A03', 'Pineapple');
insert into tablea values ('A05', 'Banana');

insert into tableb values ('A01', 'Apple');
insert into tableb values ('A02', 'Orange');
insert into tableb values ('A03', 'Pineapple');
insert into tableb values ('A04', 'Pineapple');
insert into tableb values ('A05', 'Banana');

commit;

select
  a.id ida, a.fruit fruita,
  b.id idb, b.fruit fruitb
from
  (select t.*, row_number() over (order by id, rowid) as rn from tablea t) a
join
  (select t.*, row_number() over (order by id, rowid) as rn from tableb t) b
on (a.rn = b.rn and (a.id != b.id or a.fruit != b.fruit));

IDA FRUITA    IDB FRUITB   
--- --------- --- ---------
A03 Pineapple A04 Pineapple