Deterministic function for getting today's date
You cannot use the function GETDATE() as the basis for a persisted view since the output of the function changes moment-by-moment.  This what SQL Server means in the error "because it is non-deterministic."  Function results MUST be predictably the same every time they are called in order for SQL Server to persist the results.  

Luckily, there is an easy way for you to persist this data once-per-day using a scheduled job.  Perhaps using SQL Server Agent, or Windows Job Scheduler, etc.

Here I'm creating the numbers table, and the table to hold the next 7 days:

CREATE TABLE dbo.Numbers
(
    Number INT NOT NULL
        CONSTRAINT PK_Numbers
        PRIMARY KEY CLUSTERED
);

;WITH cte AS
(
    SELECT TOP(100) Number = ROW_NUMBER() OVER (ORDER BY t1.num, t2.num)
    FROM (VALUES (1),(2),(3),(4),(5),(6),(7),(8),(9),(10)) t1(num)
        , (VALUES (1),(2),(3),(4),(5),(6),(7),(8),(9),(10)) t2(num)
    ORDER BY t1.num * t2.num
)
INSERT INTO dbo.Numbers (Number)
SELECT cte.Number
FROM cte;

CREATE TABLE dbo.Next7Days
(
    SettingDate DATETIME NOT NULL
        CONSTRAINT PK_Next8Days
        PRIMARY KEY CLUSTERED
);


Schedule this to happen once per day:

TRUNCATE TABLE dbo.Next7Days;

INSERT INTO dbo.Next7Days(SettingDate)
SELECT SettingDate = DATEADD(DAY, n.Number, DATEDIFF(DAY, 0, GETDATE()))
FROM dbo.Numbers n
WHERE n.Number &lt; 8;


Since the dates of the next 7 days only changes once per day, this solution should work well.

The dbo.Next7Days table contains the following after I ran the above code: