How can I improve my SQL statement with weekly results with week starting on Thursday or any other day of the week?
Here is a query I wrote up to give you the most recent thursday and the ending wednesday

SELECT thuwk_beg + INTERVAL 0 second thu_beg,
thuwk_beg + INTERVAL 604799 second wed_end
FROM (SELECT (DATE(NOW()) - INTERVAL daysbacktothursday DAY) thuwk_beg
FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE(NOW()) dt) AAAA) AAA) AA) A;


Here is an example for today, 2011-09-21

mysql&gt; SELECT
    -&gt; thuwk_beg + INTERVAL 0 second thu_beg,
    -&gt; thuwk_beg + INTERVAL 604799 second wed_end
    -&gt; FROM (SELECT (DATE(NOW()) - INTERVAL daysbacktothursday DAY) thuwk_beg
    -&gt; FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
    -&gt; FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE(NOW()) dt) AAAA) AAA) AA) A;
+---------------------+---------------------+
| thu_beg             | wed_end             |
+---------------------+---------------------+
| 2011-09-15 00:00:00 | 2011-09-21 23:59:59 |
+---------------------+---------------------+
1 row in set (0.00 sec)


Just replace the NOW() function calls with whatever datetime you like and you will have the week starting Thursday all the time for the give datetime you choose.

Here is another example using the specific date '2011-01-01'

mysql&gt; SELECT
    -&gt; thuwk_beg + INTERVAL 0 second thu_beg,
    -&gt; thuwk_beg + INTERVAL 604799 second wed_end
    -&gt; FROM (SELECT (DATE('2011-01-01') - INTERVAL daysbacktothursday DAY) thuwk_beg
    -&gt; FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
    -&gt; FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE('2011-01-01') dt) AAAA) AAA) AA) A;
+---------------------+---------------------+
| thu_beg             | wed_end             |
+---------------------+---------------------+
| 2010-12-30 00:00:00 | 2011-01-05 23:59:59 |
+---------------------+---------------------+
1 row in set (0.00 sec)


Your query of table referencing today would resemble something like this:

SELECT * from `table`,
(SELECT thuwk_beg + INTERVAL 0 second thu_beg,
thuwk_beg + INTERVAL 604799 second wed_end
FROM (SELECT (DATE(NOW()) - INTERVAL daysbacktothursday DAY) thuwk_beg
FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE(NOW()) dt) AAAA) AAA) AA) A) M
WHERE `date` &gt;= thu_beg
AND `date` &lt;= wed_end;


Give it a Try !!!

UPDATE 2011-09-22 16:27 EDT

This was my proposed query for marking Thu-Wed.

SELECT thuwk_beg + INTERVAL 0 second thu_beg,
thuwk_beg + INTERVAL 604799 second wed_end
FROM (SELECT (DATE(NOW()) - INTERVAL daysbacktothursday DAY) thuwk_beg
FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE(NOW()) dt) AAAA) AAA) AA) A;


How about other weeks ???


(SELECT SUBSTR('6012345',wkndx,1) does the week starting Mon ending Sun
(SELECT SUBSTR('5601234',wkndx,1) does the week starting Tue ending Mon
(SELECT SUBSTR('4560123',wkndx,1) does the week starting Wed ending Tue
(SELECT SUBSTR('3456012',wkndx,1) does the week starting Thu ending Wed
(SELECT SUBSTR('2345601',wkndx,1) does the week starting Fri ending Thu
(SELECT SUBSTR('1234560',wkndx,1) does the week starting Sat ending Fri
(SELECT SUBSTR('0123456',wkndx,1) does the week starting Sun ending Sat