Calculating daily growth using previous row value in new column - SQL Server
I just read this article adressing this topic and I suppose you might be interested, because it uses the lag function to solve exactly your Task:

https://www.mssqltips.com/sqlservertip/3690/identify-sql-server-database-growth-rates/

The Author created the following Script using the LAG Window function:

SELECT DISTINCT
    A.[database_name]
,   AVG( A.[Backup Size (MB)] - A.[Previous Backup Size (MB)] ) OVER ( PARTITION BY A.[database_name] ) AS [Avg Size Diff From Previous (MB)]
,   MAX( A.[Backup Size (MB)] - A.[Previous Backup Size (MB)] ) OVER ( PARTITION BY A.[database_name] ) AS [Max Size Diff From Previous (MB)]
,   MIN( A.[Backup Size (MB)] - A.[Previous Backup Size (MB)] ) OVER ( PARTITION BY A.[database_name] ) AS [Min Size Diff From Previous (MB)]
,   A.[Sample Size]
FROM 
(
    SELECT
        s.[database_name]
    --, s.[backup_start_date]
    ,   COUNT(*) OVER ( PARTITION BY s.[database_name] ) AS [Sample Size]
    ,   CAST ( ( s.[backup_size] / 1024 / 1024 ) AS INT ) AS [Backup Size (MB)]
    ,   CAST ( ( LAG(s.[backup_size] ) 
            OVER ( PARTITION BY s.[database_name] ORDER BY s.[backup_start_date] ) / 1024 / 1024 ) AS INT ) AS [Previous Backup Size (MB)]
    FROM 
        [msdb]..[backupset] s
    WHERE
        s.[type] = 'D' --full backup
    --ORDER BY
    --  s.[database_name]
    --, s.[backup_start_date]
) AS A
ORDER BY
    [Avg Size Diff From Previous (MB)] DESC;
GO