Is time complexity of the greedy set cover algorithm cubic?
Acc. to Introductions to Algorithms (3e), given a "simple implementation" of the above given greedy set cover algorithm, and assuming the overall number of elements equals the overall number of sets ($|X| = |\mathcal{F}|$), the code runs in time $\mathcal{O}(|X|^3)$. So there are cases when the algorithm behaves cubic.