If the language $A$ is decidable and the language $B$ is recognizable, then the language $A \cap B$ is recognizable?
You are correct, without further information we can only say that $A\cap B$ is recognizable. 

A simple example would be to let $B$ be any recognizable (but not decidable) language - the Halting Problem for example, if you want to be melodramatic, and let $A = \Sigma^{\ast}$. Then $A \cap B = B$, so clearly can't be decidable.

It is of course possible that the intersection happens to be decidable, (for example if $A \cap B = \emptyset$ is a trivial example), but this may not be true in general.