Space requirement of a universal Turing machine
The constant depends on the size of the respective tape alphabets. If the two are the same and you're very careful, you can probably make do with only $n + O(1)$ space, where the constant only depends on the simulated machine. The idea is to store the tape of the simulated machine from the point of view of the cell pointed to by the head, interleaving both sides of the tape. This is not the most time-efficient simulation, but the blow-up in time is still only polynomial.