lambda calculus with church numerals
Your term is the application $3\ 2\ succ\ 0$, where $succ$ is the successor function.  

If you task is to reduce this term to a beta normal form:  

First we can observe that for terms $M$ and $N$, the application $MN$ beta-reduces to the $M$-fold application of $N$, which is


in the case of $N$ an operation: the $M$-fold application of the operation $N$ to whatever term $P$ the term $MN$ is applied to; i.e., $MNP$ is $\underbrace{N(N(...N(}_{M\text{ times}} P)))$,
in the case of $N$ a church number: the (church number representation of the) exponentiation of $N$ with $M$; i.e, $MN$ with $M,N$ numbers is $N^M$.


as you can easily verify with simple numbers like $2$ and $3$.  

So $3\ 2$ is $2^3$, which beta-reduces to $8$, and $3\ 2\ succ$ creates an 8-fold application of $succ$, which is then applied to $0$.
So your term is the $2^3$-fold = $8$-fold application of the $succ$-function to the number $0$, that is, $\underbrace{succ(succ(...succ(}_{8 \text{ times}} 0)))$, which eventually beta-reduces to the church number $8$, $\lambda fx.f(f(f(f(f(f(f(f(x))))))))$.