Show that there are infinitely more problems than we will ever be able to compute
Reformulating in a more mathematically precise way, what the lecturer is trying to say is this: Any algorithm can be (uniquely) encoded as a finite string of bits, and any finite string of bits (uniquely) encodes a program; hence, there is a bijection between $\mathbb{N}$ and the set of algorithms, so both are countable sets. Conversely, having fixed an ordering of strings, any decision problem $P$ can be (uniquely) encoded as an infinite string of bits, where the $i$-th bit represents whether the $i$-th string is in $P$ or not, and any infinite string of bits (uniquely) encodes a decision problem (in the same fashion); hence, $\mathbb{R}$ and the set of decision problems are both uncountable sets.