Short Fibonacci Heap
Corollary 1 in Fredman &amp; Tarjan's paper states:


  A node of rank $k$ in an F-heap has at least $F_{k+2} \ge \phi^k$ descendants,
  including itself; where $F_k$ is the $k$th Fibonacci number ($F_0 = 0$, $F_1 = 1$, $F_k = F_{k-2} + F_{k-1}$ for $k \ge 2$), and $\phi = (1 + \sqrt{5})/2$ is the golden ratio.


Any node of rank 4 must have at least $F_{4+2} = 8$ descendants including itself, but the root node in the example has only 5. Therefore it could not have been created using Fibonacci heap operations.