Convert $1.75\times10^{15}$ to IEEE-32 format?
You need to understand how the IEEE-754 standard for floating point numbers works. It is not simply converting the number to binary.

Instead, the 32 bits that compose the representation of the floating-point number are split into 3 fields: sign, exponent, mantissa. Their sizes are 1bit, 8bit, and 23bit, respectively. 
Each field is written in binary basis (unsigned).

If the value of the exponent field is $e$, and the value of the mantissa field is $m$ then, the these 32bits represent the number
$$ 2^{e-127} \times (1 + m\cdot 2^{-23})$$
the $s$ bit determines if the number is positive or negative.

So, to represent the number $1.5\cdot 10^{15}$ you will need to set:
$s=0$ (positive), $e=177$, and $m=2787263$. Calculate
$2^{e-127} \times (1 + m\cdot 2^{-23}) = 2^{50} + 2787263\cdot 2^{27} = 1500000014041088$, which is the closest you can get to $1.5\cdot 10^{15}$ with 32bit representation.

Use https://www.h-schmidt.net/FloatConverter/IEEE754.html as a simple converter and a way to learn how this representation works.



(Oops, I demonstrated the above for 1.5e15, while the question was about 1.75e15. Nevermind, replace with $m=4649908$ to get 1.74999999e15).