Need help with adding elements to hashtable with linear probing
It's not explicitly defined - rather there's an implicit subindex (based off the table's size) to the hash-function. At the start we had e.g., $h(0) = h_7(0) = 3$. They are then informing you that $h_14(0) = 8$. There is no explained reason for this. They then re-insert the data to the larger hash table going over the old data in the order it appears in the hash table.