Simplifying the boolean expression xy + (!x)z + yz with boolean algebra?
$$
xy + \bar{x} z + yz =
xy + \bar{x} z + (x+\bar{x})yz =
xy + \bar{x} z + xyz + \bar{x}yz =
xy(1 + z) + \bar{x} z(1 + y) = xy + \bar{x}z.
$$