What is the result of multiplying O(n) and Ω(n)?
Basically, without further information you know nothing about the asymptotic growth of $f \cdot g$.

Let's unfold the definitions:

$\qquad f \in \Omega(n) \implies f(n) \leq cn$ and

$\qquad g \in O(n)      \implies g(n) \geq dn$

for some $c,d \in \mathbb{N}$ and $n$ greater than some constant.

Now it's clear that you get no bound on $g \cdot f$; you have no upper bound for one factor and no lower for the other. In fact, you can get arbitrarily slowly and fast growing results:


For $f : n \mapsto n$ and $g_k : n \mapsto n^{-k}$, we get $f \cdot g_k : n \mapsto n^{-k+1}$. Note that the induced sequence of functions is properly decreasing in terms of asymptotic growth.
For $f_k : n \mapsto n^k$ and $g : n \mapsto n$, we get $f_k \cdot g : n \mapsto n^{k+1}$. Note that the induced sequence of functions is properly increasing in terms of asymptotic growth.


If you restrict yourself to (eventually) non-decreasing functions -- that is $f,g \in \Omega(1)$ -- you get one of the missing bounds and thus $f \cdot g \in \Omega(n)$.