how to draw a complement of a Turing Machine?
You cannot do it in general.  

It would make the complement of your language semi-decidable, like the language itself. Hence they would be both decidable by running both machines in parallel.

Of course, this concerns only the case of semi -decidable languages for which the TM does not always halt for words not in the language.

If you have a decidable language for which the TM always halt with a yes or a no, you just exchange the yes and the no.

However there are some precautions to be taken:


compatibility of accepting and non-accepting configurations

Depending on your chosen definition of Turing Machines, accepting and
halting non-accepting configurations may not be compatible, hence may
not be
interchangeable. If it is allowed for an accepting state to have
transitions that could be used, then making it a normal state may
just make the computation go on, rather than halt without
accepting. Hence some rather simple precautions must be taken
regarding how acceptance and rejection are identified and how to
exchange them.
non-deterministic machines

Non deterministic machines are anti-managers. When a manager says
"no" it means no, and when he says "yes" it means "maybe".

Non deterministic machines do the opposite: when they say "yes" it
means "yes", and when they seem to say "no" (halting in a non-accepting configuration) it means "maybe". The reason it means maybe is that it might have answered yes with a different non-deterministic choice of some transitions. Actually, non-deterministic automata should be more accurately supposed never to give a negative answer. It is convenient with deterministic automata, but means nothing with non-deterministic ones.
It is also "maybe" when they do not terminate, for two reasons: (1) another transition choice might have produced acceptance, and (2) you cannot assert non acceptance as the computation may go on.

Hence it is not easy to complement a language recognized by a
non-deterministic or non halting device. You cannot simply exchange
"yes" and "no", since you only have "yes" and "maybe". You would only
get a managerial machine answering only "no" or "maybe", not
recognized by the Automata Theory Union. Automata must accept by terminating and answering "yes" unambiguously iff the word to be recognized is in the
language. Being able to answer no in some cases is just a bonus of deterministic machines, when kind enough to halt.

So, you must first convert your machine into a deterministic
one. Then you can exchange accepting and rejecting configurations
(with due respect to the previous point above), assuming furthermore
that the machine always halt.

To get the complement of a regular set, it is convenient to first
buid a DFA that recognizes it. 

A Turing machine can always be turned into a deterministic one, but
it may not halt, thus leaving room for "maybe". Hence it is not
always possible to complement a language recognized by a Turing
Machine, as stated above. But it is possible for a (determinized) TM
that always halt with a yes/no answer.