Clarification reg. jump consistent hashing
I suggest this as a better version of the paragraph.

Now, for a given $i$ and $k$, we generate a pseudo­random variable, $r$, that is uniformly distributed between 0 and 1, and set $j = \lfloor(b+1) / r\rfloor$. This gives $P(j \ge i) = (b+1) / i$, as we want:
$P(j \ge i)$
$ = P(\lfloor(b+1) / r\rfloor ≥ i)\quad$ substituting the definition of j
$ = P((b+1) / r \ge i)\quad$ because $i$ is an integer
$ = P(r \le (b+1) / i)\quad$ solving the inequality for $r$
$ = (b+1) / i\quad$ because $r$ is uniformly distributed between 0 and 1