Is the runtime for the general number sieve given in base 10, e or 2?
Wikipedia gives the running time as
$$
\approx \exp \sqrt[3]{\frac{64}{9}} (\ln n)^{1/3} (\ln \ln n)^{2/3},
$$
where $n$ is the integer being factored. Here $\ln n$ is the natural logarithm (logarithm to base $e$).