Calculate the minimum absolute difference between the maximum and minimum number from the triplet of 3 arrays
Can you see the following equality?
 abs( max(a,b,c) - min(a,b,c) ) = max(abs(a - b), abs(b - c), abs(c - a))

Here is a hint to prove the equality.


   Without loss of generality, we can assume a >= b >= c.


By the way, the first abs is not necessary since max(a, b, c) is always no less than min (a, b, c).