Model for formula $\Box (\psi \vee \phi) \Rightarrow (\Box \psi) \vee (\Box \phi)$
If you're just asking for any model satisfying the formula, you simply try to make one of these the case


The left hand side false
The right hand side true


Let's just pick number 2.  You have to make a model (with a state $\sigma$) where $\Box \psi \lor \Box \phi$ is the case.  Even easier is $\Box \phi$.

Create a (trivial) model where every state $\sigma$ has $\sigma \models p$ for all propositions $p$.



If you want to see if the formula is valid then the answer is no.  You should now be able to create a model that falsifies the formula.