$\mathbf{NC_2}$ is closed under log-space reduction
We want to show that if $A\le_lB$ and $B\in NC_2$ then $A\in NC_2$.

Since $A\le_l B$ we have a Turing machine $M_{f,i}(x)$ calculating the i'th bit of the reduction output $f(x)_i$, using logarithmic space. 

$M_{f,i}(x)=1 \iff \left( G_{M_{f,i}(x)},c_{start},c_{acc} \right)\in PATH$

Where $G_{M_{f,i}(x)}$ is the configuration graph of the computation of the logspace machine $M_{f,i}$ on $x$,and $c_{start},c_{acc}$ are the initial and accepting configurations, correspondingly. 

Now your $NC_2$ circuit for $A$ will, "in parallel", compute all the bits of the reduction $f(x)$ (this can be done since you proved $PATH\in NC_2$) and send the result as input to the $NC_2$ circuit for $B$. This results in an $NC_2$ circuit for $A$.