Mixed-strategy Nash equilibria
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No. The easiest way to prove this is by counterexample. Expanding matching pennies, we can create a game with two mixed strategies (players either mix between A and B or between C and D):



What might be true about that statement is for a mix of particular pure strategies for two players, there is a unique mixed strategy equilibrium. This presumes that there is a threshold  after which you switch from using strategy $0$ to strategy $1$. At this threshold, your opponent is ambivalent between her strategies. As depicted below, the intersection (and hence mix) will be unique.