Is C → A B C | A left-factorizable?
Your proposed factoring won't work correctly because both productions start with the same nonterminal. Remember that for an LL(1) parser you cannot have two productions that start with the same nonterminal (usually) because if you see anything in the FIRST set for that nonterminal, you wouldn't know which production to pick.

To left-factor the grammar, try something like this:


  C &rarr; AX
  
  X &rarr; BC | &epsilon;


Notice that this gives you the same strings as before, but (assuming that at least one of B and C doesn't produce &epsilon;) is LL(1).