Simplest combination of logic gates to produce a given set of outputs
This problem is discussed in Circuit Minimization Problem, by V. Kabanets and J.-Y. Cai.

Obviously the decision version is in NP (does there exists a circuit of size $\le k$ which agrees with the given truth table), since you could provide the circuit $\mathcal{C}$ and verify that $\forall x\in\left\{0,1\right\}^n : \mathcal{C}(x)=f(x)$. This can be done in polynomial time (relative to the input's size), since the size of the truth table is $2^n$.

It's an open question how hard the problem is.  The above paper shows that any proof that this problem is in $P$, or any proof that it is $NP$-complete, would extend our current knowledge and imply a solution to long-standing open problems in complexity theory. 

If the Circuit Minimization Problem is in $P$, then it is shown that $BPP=ZPP$ (so for now, showing your problem is in $P$ is open). 

Since this is believed to happen anyway (under the assumption that $P=BPP$), they give more consequences which are less likely. For example, it is enough to show $2^n/n$ circuit lower bound for the class $E$ to obtain a $2^{c\cdot n}$ lower bound (If high circuit complexity functions exist in $E$, then very high circuit complexity functions exist too). They also show how to factor Blum integers efficiently on average (Which, they say, is the strongest evidence for the fact that this problem lies outside of $P$).

If the Circuit Minimization Problem is $NP$-hard (under what they call a "natural reduction", where the reduction's output size depends only on the input's size and not structure) then $BPP\subseteq SUBEXP$ and $BPP=P$ unless the exponential time hypothesis fails.