Proving a language is not regular with pumping lemma
To expand a little on Ran G.'s comment, given a pumping length of $p$, we can take the string $s=a^{p}b^{p} \in A$, then splitting into $s=xyz$, the $y$ section (the part that can be pumped) must be all $a$s, so pumping up leaves us with a string $s'=a^{p+k}b^{p} \notin A$.