Why does many to one reduction imply Turing reducibility?
To put it informally, $A\leq_{\mathrm{T}}B$ means "If I had a subroutine for&nbsp;$B$, then I could solve&nbsp;$A$", whereas $A\leq_{\mathrm{m}}B$ means, "If I had a subroutine for&nbsp;$B$, then I could solve&nbsp;$A$ using a program that calls the subroutine only once and, furthermore, just returns the answer of the subroutine without doing any further calculation."

If you can solve a problem using a subroutine such that blah blah blah, you can solve that problem using the subroutine.