Get the parameters of an elliptic curve's equation
04 indicates the uncompressed form of the public key.
The first half is the $x$-coordinate and the second half is the $y$-coordinate of the public key.
x= 5e:ff:47:19:80:be:93:5f:8f:51:14:45:d5:
   40:41:79:ca:48:be:85:97:bd:e2:0f:2b:a0:
   b2:7d:6c:37:74:39:44:ff:50:67:74:30:a8:
   10:ac:89:a6:6a:80:5a:1a:c9:

y =82:ff:2a:51:84:38:c8:f6:af:e0:46:e7:9f:
   d5:66:1b:20:75:7f:87:42:46:d9:6e:12:4f:
   74:38:4d:f4:9f:b1:13:27:9a:10:a8:0c:6b:
   4b:1f:f6:6c:bf:32:ee:a3:10

The parameters you are looking for are defined in the last part.
ASN1 OID: secp384r1
NIST CURVE: P-384

The parameters can be found in FIPS PUB 186-4 or SEC 2: Recommended Elliptic Curve Domain Parameters as sextuple
$$T = (p, a, b, G, n, h)$$
p = FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF 
    FFFFFFFF FFFFFFFE FFFFFFFF 00000000 00000000 FFFFFFFF

$$ p = 2^{384} − 2^{128} − 2^{96} + 2^{32} − 1$$
The curve $E: y^2 = x^3 + ax + b$ over $F_p$ is defined $b$;
a = FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF
    FFFFFFFF FFFFFFFE FFFFFFFF 00000000 00000000 FFFFFFFC

b = B3312FA7 E23EE7E4 988E056B E3F82D19 181D9C6E FE814112
    0314088F 5013875A C656398D 8A2ED19D 2A85C8ED D3EC2AEF

The basepoint $G$ in compressed form (03) indicates
G = 03 AA87CA22 BE8B0537 8EB1C71E F320AD74 6E1D3B62 8BA79B98
       59F741E0 82542A38 5502F25D BF55296C 3A545E38 72760AB7

The basepoint $G$ in uncompressed form (04) indicates
G = 04 AA87CA22 BE8B0537 8EB1C71E F320AD74 6E1D3B62 8BA79B98
       59F741E0 82542A38 5502F25D BF55296C 3A545E38 72760AB7
       3617DE4A 96262C6F 5D9E98BF 9292DC29 F8F41DBD 289A147C
       E9DA3113 B5F0B8C0 0A60B1CE 1D7E819D 7A431D7C 90EA0E5F

$n$ is the order of the basepoint $G$
n = FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF
    C7634D81 F4372DDF 581A0DB2 48B0A77A ECEC196A CCC52973

and the cofactor $h$ is:
h = 01

The cofactor is caluclated by $$h = \frac{|E(\mathbb{F_p})|}{n}$$

Printing via OpenSSL
Using OpenSSL Command-Line Elliptic Curve Operations it is possible to print the values, too
openssl ecparam -name secp384r1 -out secp384r1.pem
openssl ecparam -in secp384r1.pem -text -param_enc explicit -noout


The compression
The 0x02 or 0x03 indicates the distinction of $Y$ or $-Y$. Since in the elliptic curve $$Y^2 = X^3 + aX + b$$ if $(X,Y)$ is a point then $(X,-Y)$ is also a point on the curve. This is due to the square of $Y$ in the elliptic curve equation.
The distinction designed by the least significant bit of $Y$, 0x02 for 0, and 0x03 for 1.