Pohlig-Hellman Algorithm: Adding up the solution via CRT
Because $x$ is defined modulo $28$ ($2^{28} = 2^0$ in $(\mathbf{Z}/29\mathbf{Z})^*$), you can view $x$ as an element of $\mathbf{Z}/28\mathbf{Z}$, while $2$ and $3$ are elements of $(\mathbf{Z}/29\mathbf{Z})^*$.