Differential privacy definition
I can't give an example illustrating why leakage must be non-negligible for the utility of the mechanism, but I can give a proof of why leakage must be non-negligible for the utility of the mechanism.



Let $\;\; U \: = \: \left\{\langle D,D'\rangle : D,D' \text{ differ in one element}\right\} \;\;\;$.

By the triangle inequality, for all $D$ and $D'$, for all $S$,

$|\operatorname{Pr}(A(D) \in S)-\operatorname{Pr}(A(D') \in S)|$
$\leq$
number_of_elements $\cdot \operatorname{sup}(\{|\operatorname{Pr}(A(D) \in S)-\operatorname{Pr}(A(D') \in S)| : \langle D,D'\rangle \in U\}$

If number_of_elements is polynomial and $\:\operatorname{sup}(\{|\operatorname{Pr}(A(D) \in S)-\operatorname{Pr}(A(D') \in S)| : \langle D,D'\rangle \in U\})\:$ is negligible, then

for all $D$ and $D'$, for all $S$, $\:|\operatorname{Pr}(A(D) \in S)-\operatorname{Pr}(A(D') \in S)|\:$ is negligible.

If number_of_elements is polynomial and

$\operatorname{sup}(\{|\operatorname{Pr}(A(D) \in S)-\operatorname{Pr}(A(D') \in S)| : \langle D,D'\rangle \in U\})$

is negligible, then $A$ is statistically close to being independent of $D$.

Therefore, if $\:\operatorname{sup}(\{|\operatorname{Pr}(A(D) \in S)-\operatorname{Pr}(A(D') \in S)| : \langle D,D'\rangle \in U\})$

is negligible then the mechanism is not useful.