Why does the recommended key size between symmetric and asymmetric encryption differ greatly?
Symmetric encryption and asymmetric encryption algorithms are built upon vastly different mathematical constructs.

In typical symmetric encryption algorithms, the key is quite literally just a random number in $\left[0 .. 2^n\right]$, where $n$ is the key length. The strength of the key is based upon its resistance to brute-force attacks, where an attacker would need to perform an attack with complexity $O\left(2^n\right)$ to correctly guess the key.

Asymmetric algorithms, on the other hand, use a different kind of key. For example, an RSA modulus is of the form $m = pq$, where $m$ is the modulus, and $p$ and $q$ are two large, distinct, randomly-chosen prime numbers of roughly equal sizes. The strength of the key is based upon the modulus' resistance to factorization into its prime components. An attacker using a general field number sieve would need to conduct an attack with complexity $O\left(\exp\left(\left(\left(\frac{64}{9} + o\left(1\right)\right) \cdot n\right)^\frac{1}{3}\left(\log n\right)^\frac{2}{3}\right)\right)$ to factor the modulus (and thus break the private key), given a modulus of bit-length $n$.