How many parties are needed to compute multiplication with BGW?
The BGW protocol has a semi-honest and a malicious version. For semi-honest, a simple honest majority is enough. In that case, 3 parties can run the protocol, with security against one (semi-honest) corrupted party. For malicious adversaries, BGW requires $t &lt; n/3$ meaning that with one corrupted party, you need at least 4 parties; with up to two corrupted parties, you need at least 7 parties.