Deterministic ECDSA signatures?
DSA relies on $k$ being independent from $d$. You define $k$ as:

$k=z^\prime d\mod n$

Substituting $k$ in the signing equation you get:

$s = k^{-1} (z+rd) \mod n$

$s z^\prime d = z + rd \mod n$

$d=z (sz^\prime -r)^{-1}  \mod n$

The attacker knows everything on the right side and can recover the private key.