How to XOR two hex values and am I doing crib dragging correctly? (OTP)
Xoring this "hexadecmal" value of

7ECC555AB95BF6EC605E5F22B772D2B34FF4636340D32FABC29B 

with the hexadecimal value of 

73CB4855BE44F6EC60594C2BB47997B60EEE303049CD3CABC29B

will lead to:

0D071..... As the page told you.

Xoring is a so called modulo 2 addition without carry bit propagation. You are adding each bit with the corresponding bit of the other string. First you convert your hexadecimal representation into binary. Then you perform the modulo 2 addition. (dots are for better readability)

7ECC5 becomes 0111.1110.1100.1100.0101
73CB4 becomes 0111.0011.1100.1011.0100
--------------------------------------
XOR
--------------------------------------
              0000.1101.0000.0111.0001
which is converted into
              0    D    0    7    1


PS:

Apply the following rules for adding each bit.

0 xor 0 = 0
0 xor 1 = 1
1 xor 0 = 1
1 xor 1 = 0