Whats wrong with my El Gamal signature example
In general case, $k^{-1}$ is equal to $x$ such that $x \cdot k=1$. In your question, to computing $11^{-1}$, you must find $x$ such that $x\cdot11=1 \pmod {8368}$. You can compute $x$ by using the extended Euclidean algorithm.