Encrypted Hash vs MAC
Assuming you mean EK1(m) || EK2(H(m)) or EK(m || H(m)), it is not an approved MAC scheme in any standards and may have issues. Instead, you should probably use an HMAC, which involves taking the message and the key and hashing them together. An HMAC is defined by RFC 2104 as HMACK(m) = H((K ⊕ opad) || H((K ⊕ ipad) || m)) where opad and ipad are constants. An HMAC is a keyed hash function, which means the digest depends on both the message and the key.