What does an RSA signature look like?
An RSA signature is a sequence of bytes of the same size of the modulus. If the key uses a 1024-bit modulus $n$, then the signature value is, numerically, an integer in the $1..n-1$ range, and the PKCS#1 standard specifies that this integer should be encoded as a sequence of bytes of the same length as would be needed to encode the modulus, i.e. 128 bytes for a 1024-bit modulus (big-endian unsigned convention).

The signature process looks like this:


The message to be signed $m$ is hashed with hash value $h$, yielding $h(m)$, which is a sequence of bytes (say, 32 bytes if $h$ is SHA-256).
The hash value is padded: a byte sequence is assembled, consisting of, in that order: a byte of value 0x00, a byte of value 0x01, some bytes of value 0xFF, a byte of value 0x00, a fixed header sequence H, and then $h(m)$. The header sequence H identifies the hash function (strictly speaking, there are for each hash function two possible header values, and I have encountered both). The number of 0xFF bytes is adjusted so that the total sequence length is exactly equal to the encoding length of the modulus (i.e. 128 bytes for a 1024-bit modulus).
The padded value is then interpreted as an integer $x$, by decoding it with the big-endian convention. Due to the sequence size and the fact that the sequence begins with a 0x00, the value $x$ is necessarily in the $1..n-1$ range.
The value $x$ is raised to the power $d$ (private exponent) modulo $n$, yielding $s = x^d \pmod n$.
The $s$ value is encoded into a sequence of the same length as $n$; that's the signature.


To verify, the signature is decoded back into the integer $s$, then $x$ is recovered with $x = s^e \pmod n$, and encoded back. The verifier then checks that the padding as explained above has the proper format, and that it ends with $h(m)$ for the message $m$.

All of the above is the "v1.5" PKCS#1 padding. The standard also defines a newer one, called "PSS", which is a bit more complex, but allows for some kinds of security proofs.