Can one build a one-way function from AES?
As Mike asked, it's not clear if you're asking about onewayness, or collision resistance (as you call the function a 'cryptographic compression function').

Assuming you're asking about onewayness, well, given a single 128 bit value $h(M)$, we obviously cannot uniquely deduce the 1408 bit value $M$.  However (hint), let us assume that we can ask for the value $h(M \oplus \Delta)$, for 1408 bit values $\Delta$ that we pick; how can we use that to recover $M$?  How can we extend this observation to cases where the length of $M$ is a multiple of 1408 bits?

Assuming you're asking about collision resistance, well, how can we pick a value $M$ so that $h(M)$ is a predetermined value?  Hint: look at how the AES uses the last round subkeys.