Help me about Advanced Encryption Standard (AES)
I'm going to assume that the comma $,$ operator used in your question means 'concatenate' (normally written $a||b||c$). Moreover, I'm assuming that $a,b,c$ are distinct.

In that case, With incredibly high probability, No: $V_1$ and $V_2$ will not be equal.

Think of it this way: if they were equal, then what would $D_k(V_1)$ be? Supposing $V_1=V_2$, we have:
$$a||b||c=D_k(E_k(a||b||c))=D_k(V_1)=D_k(V_2)=D_k(E_k(b||a||c))=b||a||c$$

That is, we would have to deduce that $a||b=b||a$ and thus $a=b$.