Difference between special honest verifier zero-knowledge and zero-knowledge property
"Can we say $\pi$ satisfies SHVZK?"

Yes you can. As any proof system which satisfies ZK property, also achieves SHVZK.

Regard to "My doubt is In SHVZK, simulator produces accepting transcript where as in ZK property there is no condition about acceptance of transcript generated by simulator."

Note that in the definition of ZK, it is mentioned that "Let $(P,V)$ be an interactive proof system". A proof system should be complete, meaning that a honest prover always convinces honest verifier, which implies that the proof should be acceptable. So, even if in the definition of ZK, clearly is not mentioned that the proof should be acceptable, but similar to the SHVZK proof, a simulated ZK proof should be acceptable by verifier.