How do you find probabilites of carrying an X linked recessive disease in a blank pedigree given only one phenotype?
Assume the disease is rare. The parents of the affected male are thus probably X/Y and Xc/X. Their daughter (the sister of the affected male) has a probability of 1/2 of being a carrier (Xc/X). Her daughter also has a 1/2 probability of being a carrier. Her son has a 1/2 probability receiving the mutant X chromosome. Therefore, the probability that the son is affected is 1/2 * 1/2 * 1/2 = 1/8.

I can’t right now, but I’ll try and make it clearer with a figure tomorrow.