Two heterozygote mice for skin color are reproduced. Find the probability that in 3 children 2 will be dark and one white
You are on the right track, but you have to keep in mind there are multiple ways to have two dark and one child in a group of three. You have to add the probabilities of each unique outcome that results in two dark and one light child. So, the probability is (1/4) x (3/4) x (3/4) PLUS (3/4) x (1/4) x (3/4) PLUS (3/4) x (3/4) x (1/4)