HELP! How will pH 14 affect enzyme structure?
This is a very chemical explanation. Here goes.

$\ce{pH = -log[H+]}$

$\ce{pOH = -log[OH-]}$

$\ce{pH + pOH = 14}$

Therefore, at a $\ce{pH}$ of $14$, $\ce{pOH}$ is zero, so there is 1 mole of $\ce{OH-}$ and $10^{-14}$ moles of $\ce{H+}$ in a liter of your substance.