Determine percentage of crow hybrids
In order to make your reasoning clearer, you should use more formal notations and explain your thinking step by step. Here's a proposition.

Let's use the following notations :


$C$: the total number of couples (mixed and not mixed)
$r$: the reproductive success
$F1_h$: the number of hybrids in the F1 generation
$F1_{nh}$: the number of non hybrids in the F1 generation


You are looking for the percentage of hydrids in the F1 generation, which is:
$x = \frac{F1_h}{F1_h + F1_{nh}}$

You know that $10~\%$ of the couples are mixed couples and that their reproductive success is reduced by $50~\%$. This can be written:
$\begin{cases} 0.9\cdot C \cdot r = F1_{nh} \\ 0.1\cdot C\cdot \frac{r}{2} = F1_h \end{cases}$

Thus: $\displaystyle x = \frac{F1_h}{F1_h + F1_{nh}} = \frac{0.05\cdot C\cdot r}{C\cdot r\cdot 0.95} = \frac{0.05}{0.95}$

This is indeed the result you suggested. So the correction you were given might not be correct. Or maybe there was some more information in your homework that you ignored...