Restriction enzyme type II
I suppose this is a homework, not a genuine curiosity. That being the case, I'm gonna give you two different answers here: the standard one, which is the one I believe your teacher/lecturer expects to see, and a more complicated one in the addendum.

The first thing that draws out attention in the question is the base percentages. Clearly, it doesn't follow the famous Watson-Crick pairing rule (A pairs with T, G pairs with C) and, because of that, we don't see the Chargaff's Rule in this nucleic acid.

Thus, this is not a double-stranded DNA (dsDNA), but a single-stranded DNA (ssDNA).

That being said, the answer to that question can be something along these lines:


  A Type II RE can't cut that nucleic acid because that is a ssDNA.


Addendum:

There is a complication here, which may render the previous answer questionable.

Type II Restriction Enzymes only cleave regular, that is, double-stranded DNAs. So, they cannot cleave ssDNAs, which corroborates the answer we just gave.

But the problem is that ssDNAs can form loop structures, in which there is pairing between bases in the same strand. In those structures, DNA is technically dsDNA and, as such, can be cleaved by Type II RE. For instance, have a look at this paper:
Type II restriction endonucleases cleave single-stranded DNAs in general.

That being said, Type II RE do, in fact, cleave ssDNA (in places where ssDNA form loops and structurally resembles a dsDNA), which makes the question itself meaningless.