Genotypic distribution of a population with two characteristics and linkage
You are...  done. You fully answered the question; if I were you, I might just put it in ratio format instead of probability, just to be safe.

The three times thing is a bit weird, but I have seen it before. First, let's look at the phenotypic ratio of the progeny: 9:3:3:1 for Dominant Both:Dominant A Recessive B:Recessive A Dominant B: Recessive Both.

Let's find out how many dominant and recessive there are for each trait. For the dominant A trait, you add up the 9 and 3, because they are the only two types of dominant phenotypes, and find that 12 different organisms of the 16 possible are dominant for Trait A, so the probability of getting trait A is 3/4 or 75%. This means that 4 of the 16 orgamisms are recessive for Trait A, so the probability of being recessive for Trait A is 4/16, or 25%. Therefore, the ratio of Dominant Organism probability:Recessive organism probability is 75% to 25%, or 3:1. This means that it is 3 times as likely to get the dominant trait than the recessive trait. Make sense?