Calculate bandwidth of a signal for Nyquist–Shannon sampling theorem
So apply the following principals to get to a solution:


Shifts in the time domain don't affect the bandwidth, so the $-4$ and the $+3$ can be ignored.
Reversal of the time domain axis doesn't affect the bandwidth, so you can ignore the negative sign on the $-2t$.
The $\mathrm{sinc}()$ function has a Fourier transform that is a rectangle function of a particular width.
Scaling the time axis (lengthening or contracting) of a function, scales the frequency axis in the opposite manner (contracting or lengthening) for the Fourier transform.
Multiplication of functions in the time domain, results in the convolution of those two functions' Fourier transforms in the frequency domain.
The convolution of two Fourier transforms in the frequency domain, will result in a Fourier transform whose bandwidth is the sum of the bandwidth of those initial two Fourier Transforms.


That should give you enough to come up with an answer.