Intuitive explanation of the Fourier Transform for some of the functions
What might seem intuitive differs greatly between individuals.  But let's start with a few basic things about a Fourier transform that people who have studied it might know about it.  Intuitively or not.

Basic concept 1:
Something symmetric around t=0 in the time domain is strictly real in the frequency domain (as only cosine functions and DC are purely symmetric in the time domain).

Basic concept 2:
The duality principle of the FT implies that if any transform looks intuitive in one direction, the transform in the opposite direction should also.

Transform 1:
A DC level in the time domain corresponds to an impulse at 0 in the frequency domain.

Transform !B:
Getting away from impulses and infinities, but staying with the same picture, a strictly real and really skinny Gaussian pulse in the frequency domain at DC must convert to a really really wide Gaussian envelope in the time domain, also symmetric around t=0.  And vice versa.  Going in between those two (and depending on your graph scaling), a medium width Gaussian in one domain should correspond to a medium width Gaussian in its transform domain.

Possible intuitive transform concept 2 (if you have studied signal modulation concepts):
Adding strictly real and symmetric sidebands to a carrier in the frequency domain corresponds to AM modulation with a cosine sinusoid in the time domain.  The farther away the sidebands from the carrier center, the higher the frequency of the modulation.  The closer the sidebands, the lower the frequency of the modulating sinusoid.

Thus if we add symmetric wide sidebands to a wide Gaussian, that will correspond to a narrow Gaussian that is high frequency AM modulated in the other domain.  If we add only narrow sidebands close in to a narrow Gaussian, that will correspond to a really wide Gaussian with a low frequency AM modulation in the other domain.

Possible intuitive transform concept 3 (if you have done much filter design):
If you have had to design  FIR filters, you might know that the sharper the cut-off and the flatter the pass-band desired in the frequency domain, the longer the FIR filter becomes to meet those requirements, corresponding to a longer and wider impulse response in the time domain.  Or, in the other direction, the sharper-edged and flatter-topped a pulse becomes in the time domain, the wider the bulk of its frequency response spans in the frequency domain.

So, let's take that Gaussian pulse, and add some similar shaped side-bands within the bulk of its main lobe so that its top become flatter. The Gaussian in the other domain will get amplitude (AM) modulated with sinusoidal modulators, mostly of frequencies where the tops of the added sidebands are much higher that the original Gaussian roll-off. (To make it even flatter, perhaps remove the some or all of carrier (original Gaussian) to produce a modulation over 100%, e.g. that crosses zero.)

Let's also chop off the tails of the Gaussian with a brick wall filter and increase the flatness of the pass-band top even more to “square it up” in one domain.  In the other domain, that will cause lots of added ripples extending wider than before, or a “fattening up” of the tails of the original Gaussian.

So as we “square up” a Gaussian in one domain, it gets amplitude modulated plus fatter tails in the other domain.  

Thus, a skinny “squared up” Gaussian pulse in one domain might corresponds to a wide slowly AC modulated pulse with fat tails in the other domain,  And a wide but “squared up” Gaussian might correspond to something like a narrow pulse with fast AC modulation, but also with fat tails, in the other domain.

An AC modulated hump with fat tails starts to approach looking more similar to a Sinc waveform than the original Gaussian waveform, and with a width inversely proportional to the width of the "squared up" looking waveform in the other domain.

Intuitive?  Who knows…