Removing values from FFT result same as filtering?
If you only have a finite number of samples and are using a finite length FFT, then you will end up with a finite number of FFT frequency result bins.  Each bin has a one-to-one relationship ONLY with frequencies that are exactly integer periodic in the FFT length.  Any other spectrum frequencies that are not exactly periodic in the FFT aperture will not have that one-to-one relationship, but instead will have their energy spattered across the entire FFT result (a sampled periodic Sinc or Dirichlet function).  Thus, zero-ing just the nearest neighbor frequency bin will not have the effect you think.

Zero-ing a bin is the same as adding an exactly periodic sinusoid of the same magnitude but of the opposite phase.  If what you are trying to filter out is spectrum of a very slightly different frequency from that of the bin center, then instead of zero-ing it out by exact cancellation, the result will be an added beat pattern.  Which is not the same as (FIR, IIR) filtering.

ADDED (in regards to ideal filtering) : 

The basis vectors of a DFT are all orthogonal to one another.  Any other sinusoid (non-periodic-in-aperture) will be orthogonal to none of the basis vectors.  Which means it that that sinusoid will be represented, or have some energy end up in every DFT bin (because of not being orthogonal to any bin).

Therefore no subset of all the bins (a sequence of lower FFT/DFT bins for example) can exactly represent that signal.  Therefore zero-ing only a sequence of lower bins in an attempt to create a canceling signal will be imperfect, or non-ideal for that signal.  Thus a filter created by such a method cannot be ideal.

One might be able to get close for a signal near the center of a large sequence of filter bins.  But not for a signal near the edges of any sequence of bins, as a large portion of the signal's energy will be represented by those bins just outside the sharp edge of the filter rectangle.