quick conversion of dB to $\log_2$
The simple logarithmic rule says that

$$\log_b(x) = \frac{\log_a(x)}{\log_a(b)}$$

so in your case,

$$\log_2(37\text{ dB}) = \frac{\log_{10} (37\text{ dB})}{\log_{10}(2)}$$

Since 37 dB = $10^{3.7}$

$$\log_2(37\text{ dB}) = \frac{\log_{10} (10^{3.7})}{\log_{10}(2)}= \frac{3.7}{\log_{10}(2)}\approx \frac{3.7}{0.3}= \frac{37}3\approx 12.3$$