Variance of deterministic sine wave
If $x(t)$ is deterministic its variance is zero. Note that the mean of $x(t)$ (defined as an expectation) just simply equals $x(t)$:

$$\mu_x(t)=E\{x(t)\}=x(t)\tag{1}$$

where the last equality follows from the fact that $x(t)$ is deterministic. From $(1)$ we get the variance

$$E\{[x(t)-\mu_x(t)]^2\}=E\{[x(t)-x(t)]^2\}=0\tag{2}$$