Given two waves, 441 Hz and 700 Hz, how many samples long is each wave's period if the sample-rate is 48 kHz?
Neither of these tones is an exact number of samples at 48 kHz, but you can calculate the periods as follows:

$\frac{48000}{441} = 108.84$ samples

$\frac{48000}{700} = 68.57$ samples