How can you intutively figure what the impulse response will behave like?
Here's an idea...

In the first case, the impulse response has only positive coefficients. Groups of nearby samples will be averaged to yield the output signal. Thus, short term bumps/variations will be "averaged out", so the signal will be smoother. Furthermore, it looks like all coefficients sum up to 1 (there about 30 of them, in a triangle-like shape, the maximum is about 0.06, I suspect they sum to 1), so the overall amplitude / magnitude of the output waveform will be preserved. Last bit of information: the impulse response has its center of gravity at $n=15$, so the output signal will be delayed by 15 samples.

The second impulse response looks like a kronecker delta (at $n=15$) minus the impulse response from the previous example. Because convolution is a linear operation, the result will be the original signal shifted by 15 samples, minus the smoothed signal obtained in the previous example. In other words, the result will be whatever has been smoothed out in the previous example because of averaging - only the fast wiggles will remain.

Summing the output signals from example 1 and example 2 will yield the input signal delayed by 15 samples.