Why Butterworth filter always starts my signal from from zero mark (amplitude)?
Filters do have a delay (a lag) since they do not act immediately on your signal. Also all samples before the time 0 are zeros, thus in general you will start from the "zero mark", as you said (just imagine your filter equation with all zeros).

There are ways to make a filter to have a zero lag. It is done by so called zero-phase filtering, also known as forward-backward filtering. The way you do it is by filtering your signal twice - in forward and in backward direction. Obviously this can work only for offline applications. In MATLAB you can do it very easily using the filtfilt function.

Please find below a code corresponding to your case.

fs = 100;
T = 2;
t = 0:1/fs:T;
f = 2;
s = 1.5*cos(2*pi*f*t) + 0.7*sin(2*pi*33*t);

[B,A]=butter(6, 5/fs,'low');
S=filter(B, A, s);
Sff=filtfilt(B, A, s);

plot(t, s)
hold on
plot(t, S)
plot(t, Sff)
grid on
legend({'Original signal', 'Signal filtered using filter', 'Signal filtered using filtfilt'})


That yields what I suspect you want: