What's the number of FFTs in Welch-based PSD?
It should really be 1 less than 2N/M. There's nothing to overlap the last &quot;half-transform&quot; (N/M) worth of samples.
You're also right, one could zero-pad that, but then that wouldn't be an Welch estimate.
So, I'll do something I rarely do: Blame Proakis for this :)