AppleScript - how to search a list for items containing numbers
This doesn't seem like a terribly efficient way to do it, but I think that's an AppleScript issue rather than my lack of creativity (I might be wrong):

    set mylist to {"table", "s01e01", "nam", "aces", "linear", "20160430", "01", "textless", "3840x2160", "000011", "jpg"}

    repeat with str in mylist
        set str to the contents of str

        repeat with i from 0 to 9
            if str contains i then
                set end of mylist to str
                exit repeat
            end if
        end repeat

        set mylist to the rest of mylist
    end repeat

    return mylist


You could do it much more gracefully using a bit of shell script:

    set mylist to {"table", "s01e01", "nam", "aces", "linear", "20160430", "01", "textless", "3840x2160", "000011", "jpg"}

    set the text item delimiters to space

    do shell script "grep -o '\\S*\\d\\S*' &lt;&lt;&lt; " &amp; the quoted form of (mylist as text)

    return the paragraphs of the result 


EDIT: I spoke a little too soon about my (lack of creativity), as I just came up with this slightly slicker method of doing it with AppleScript.  In theory, it should be faster than the first method too:

    set mylist to {"table", "s01e01", "nam", "aces", "linear", "20160430", "01", "textless", "3840x2160", "000011", "jpg"}

    set the text item delimiters to {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

    repeat with str in mylist
        set str to the contents of str as text

        if str ≠ the text items of str as text then ¬
            set the end of mylist to str

        set mylist to the rest of mylist
    end repeat

    return mylist