Is there a formulaic way to reverse the order of a list in Apple Numbers?
One way to do this is to use the INDIRECT function. If you give that the string "A1", it'll give you the value currently in the cell A1.

Let's say the list of numbers is in column A, and we want the reversed list in column B. Let's say there are 10 rows.

So: we need to make these formulae:

B1 = INDIRECT("A10")
B2 = INDIRECT("A9")
B3 = INDIRECT("A8")
...
B10 = INDIRECT("A1")


Ok. The first character of the string we are giving to INDIRECT here is always "A", so we can just hard code that.

Now we need the reversed row number. See the formulae above: if there are 10 rows, the reverse of row 1 is 10. The reverse of 2 is 9, and so on. So: the reverse of row R is total number of rows - R + 1.

The function ROWS(column name) will give us the total number of rows currently in column name. The function ROW() will give us the row number R (if we used ROW() in a formula in cell B5, it would return the number 5).

So... putting the formula INDIRECT("A" &amp; ROWS(A) - ROW() + 1) into each cell in column B works for me, using Numbers 3.6.1 on a Mac.