Measuring voltage window with ADC
A simple but crude method would be to subtract 10V from the measured signal using a zener diode: -



So, if Vin is 16V, Vout will be 6V if the zener diode voltage is 10V. If instead of a single 10k resistor you used a potential divider, the 6V can be "tapped" to give 1.8 volts.

In case you've never used a zener, they have a defined reverse breakdown voltage like this: -



The part of the curve to the right is the "normal" forward conduction operation of any diode - just think about the left hand side.

You can also use a more accurate op-amp subtractor: -



Just set a 10V steady voltage at V1 (maybe with a voltage reference) and the output will be R2/R1 *(V2-10V). You can also "ratio" R2 and R1 to give you the required voltage range of 0V to 1.8 volts. Use a rail-to-rail op-amp for this but be aware that the bottom 20 mV to 50 mV range of the op-amp's output will fixed because although a rail-to-rail device is good it aint that good!