RMS switch current in boost converter
I'm struck in calculating the I(switch,rms) in boost converter




\$I_{rms}= \sqrt{d_1\cdot\frac{1}{3}\cdot (I_1^2+I_1\cdot I_2+I_2^2)+ (1-d_1)\cdot I_0}\$ 

T is assumed to be 1 and hence \$d_1\$ becomes the duty cycle fraction.

For your example, the \$I_0\$ term can be ignored hence the formula reduces to: -

\$I_{rms}= \sqrt{d_1\cdot\frac{1}{3}\cdot (I_1^2+I_1\cdot I_2+I_2^2)}\$

Note - I did get in a pickle with this on previous edits and thanks to @oceanp for provoking me to rethink. Pictures and formula taken from here.