Veroboard and solder traces current rating?
Each square of copper foil has 1/2000 ohm (0.000498 ohms, at 25 degree C) if the weight per square foot is the default 1 ounce of copper. This produces a 35 micron (0.035 milliMeters) or 1.4 mils (0.00014 inches) of foil.

The resistance of any square of this foil (any size, measured from opposite edges) is that 1/2000 ohm, if the holes are not present. Lets ignore that fact.

What is the power dissipation of 8 amps in 0.0005 ohms? P = I^2 * R

P = 8 *8 / 2000 = 64/2000 = 32/1000 = 32 milliWatts.

The thermal resistance of this foil is also 70 degree Centigrade per square, ignoring the holes and the etched gaps between the squares.

Assuming these squares are 0.1 inches, then you'll have 50 squares (with the etched gaps and the holes), with thermal resistance end-to-end of 50 * 70 = 3,500 degrees per watt. Your power dissipation (again ignoring the holes and the gaps ) will be 50 squares * 0.032 watts = 1.6 watts.

Assuming that 1.6 watts flows from one end to the other end, you'll have a temperature rise of 1.6 * 3,500 = 3500 + 2100 = 5,600 degree Centigrade.

Given the heat is (likely) uniformly generated, and flows both direction, you'll
have considerably less that 5,600 degree C rise in temperature.

This heat has 5 exit paths
(1) into the air (maybe your best bet, with a fan if needed)
(2) radiated out into space, if the squares become really really hot
(3) conducted along the line of squares, thru the heavy copper wire you've promised to solder along the 5" line of squares
(4) conducted THROUGH and DOWN and UP in the insulating board material (FR-4 ?) to the numerous adjacent squares that will serve as a poor-man's sloppy heatsink
(5) conducted DOWN and OVER to adjacent squares connected to some large mechanical structures to dump that 1.6 watts to a large area of the case

Note that 1.6 watts in a 1cm^2 surface will likely BURN your fingers. Your surface here is 1" by 0.5" equivalent surface, and it is metal, so you should be safe. 

However, any nearby temperature-sensitive components will not be at room temperature, and measurement errors become possible.