Phase Angles in Series/Parallel networks
The easiest way of solving such problems is to use complex phasors. The total complex impedance is

$$Z_T=R_1+R_2||j\omega L=R_1+\frac{j\omega R_2L}{R_2+j\omega L}=877.18\cdot e^{30.67^{\circ}}\Omega$$

with \$\omega=2\pi\cdot 10,000 Hz\$, \$R_1=470\Omega\$, \$R_2=988\Omega\$, and \$L=10mH\$ (as shown in your circuit diagram).

This gives for the total current

$$I_s=\frac{V_0}{Z_T}=9.12\cdot e^{-30.67^{\circ}} mA$$
with \$V_0=8V\$.

The voltage across \$R_1\$ is

$$V_1=I_sR_1=4.28\cdot e^{-30.67^{\circ}} V$$

The voltage across \$R_2\$ and \$L\$ is

$$V_2=I_s(R_2||j\omega L)=I_s\frac{j\omega R_2L}{R_2+j\omega L}=4.83\cdot e^{26.88^{\circ}} V\quad(=V_0-V_1)$$

The current through \$R_2\$ is

$$I_2=\frac{V_2}{R_2}=4.89\cdot e^{26.88^{\circ}} mA$$

The current through the inductor is

$$I_L=\frac{V_2}{j\omega L}=7.70\cdot e^{-63.12^{\circ}} mA\quad(=I_s-I_2)$$

I realize that there are quite a few differences between these results and your calculations and measurements. I just used the values you gave in the circuit diagram, and I did my best to avoid any errors.