Transimpedance amplifier with current amplifier circuit.
U1 will produce a voltage at the output to balance the input current, which is V2/120K, since the input of U1 is at virtual ground. That output voltage will be about -90/120 times V2. So if V2 is 100mV peak, you'll see about 75mV peak at the output of U1. 

You are feeding that voltage directly into the inverting input of U3 so you see the two outputs fighting each as they hit their respective current limits (the 10 ohm resistor won't make much difference). U3's output will try to drive its input to 0V (relative to the rail splitter output). 

I think you don't clearly understand what a transimpedance amplifer does (convert input current to voltage).