Multiple Minimal Expression for a given logical function
Multiple minimal expressions occur when the solution requires some overlap in grouping or the grouping can be arraigned in a different way. Drawing a K-map is an easy way to visualize the groupings.

Overlap example (Condition \$ABC\$(all 1's) should be pair with \$A\bar{B}C\$ or \$AB\bar{C}\$):

$$
\begin{array}{c|c}
\text{K-map}&amp;\text{Functions}\\
\begin{array}{r|cccc}
  &amp;BC\\
  &amp;00&amp;01&amp;11&amp;10 \\
  \hline A\phantom{2}0&amp;\color{blue}{}0&amp;1&amp;0&amp;1 \\
  1&amp;0&amp;1&amp;1&amp;1 \\
\end{array}&amp;\begin{align}\\
F &amp; = \bar{B}C + B\bar{C} + \color{red}{AB} \\
&amp; = \bar{B}C + B\bar{C} + \color{red}{AC} \\
\end{align}\\
\end{array}
$$

Grouping example (horizontal grouping, vertical grouping, plus Product-of-Sums):
$$
\begin{array}{c|c}
\text{K-map}&amp;\text{Functions}\\
\begin{array}{r|cccc}
  &amp;CD\\
  &amp;00&amp;01&amp;11&amp;10 \\
  \hline AB\phantom{2}00&amp;1&amp;1&amp;0&amp;0 \\
  01&amp;0&amp;1&amp;1&amp;0 \\
  11&amp;0&amp;0&amp;1&amp;1 \\
  10&amp;1&amp;0&amp;0&amp;1 \\
\end{array}&amp;\begin{align}\\
F_{SoP} &amp; = \bar{A}\bar{B}\bar{C} + \bar{A}BD + ABC + A\bar{B}\bar{D} \phantom{2}\color{blue}{\text{ // horizontal}}\\
&amp; = \bar{B}\bar{C}\bar{D} + \bar{A}\bar{C}D + BCD + AC\bar{D} \phantom{2}\color{blue}{\text{  // vertical}} \\
\hline F_{PoS} &amp; = (A+B+\bar{C}) (A+\bar{B}+D) (\bar{A}+\bar{B}+C) (\bar{A}+B+\bar{D}) \\
&amp; = (\bar{B}+C+D)(\bar{A}+C+\bar{D})(B+\bar{C}+\bar{D})(A+\bar{C}+D) \\
\hline F_{SoP} &amp; \equiv F_{PoS} \\
\end{align}\\
\end{array}
$$