BJT working in saturation mode
Your circuit is:







simulate this circuit &ndash; Schematic created using CircuitLab

which means you bring Q2's emitter and collector to exactly the same potential, so this is identical to:







simulate this circuit

So, your Q2 isn't working as a transistor, but really just as a pair of diodes: The base-emitter junction and the base-collector junction.

There's no need for these two to be identical; in fact, it's pretty typical that the base-emitter junction is better-conducting.