How to find True power dissipated and apparent power?
I've forgotten how to find the true power dissipated and apparent
power.

You've already calculated true power in comments but not so accurately. True power is (as transistor points out) \$V^2/R\$ = 847.06 watts and, the current in the resistor is 3.5294 amps.
For the apparent power I'd calculate individually the currents in the inductor and capacitor, these being: -

Inductor current = 15.279 amps
Capacitor current = 4.2977 amps

And, the trick here is to realize that that actual current that flows into the pair of them is the difference current. This is because L and C form a partial tuned circuit.

Net LC current is 10.981 amps

Total current is resistive plus net reactive current added as phasors (or using pythagoras): -
$$\sqrt{3.5294^2+10.981^2}$$
And that equals 11.535 amps (this is the total RMS current from the 240 volt supply).
Hence apparent power is 240 x 11.535 = 2768.3 watts.