Three Phase System: A balanced three phase three wire system has a y connected load
You got the phase voltage right.

The equivalent parallel of the three impedances is:

\$Z_{eq} = \frac{1}{\frac{1}{-100j}+\frac{1}{100}+\frac{1}{50+50j}} = 50 \Omega\$. 

The current can be calculated using:

\$I=\frac{V}{Z}=\frac{230.94/-30°}{50}=4.6188/-30° A\$ 

And total three-phase power (three times single-phase power):

\$S = 3 V_{ph}I^{*} = 3 (230.94/-30°)(4.6188/+30°) = 3200 W\$