What happens to charge in a 3-capacitor loop when link between two capacitors is opened and closed?
Once the capacitors are all charged and no current is flowing in them the cicuit you get is this one:







simulate this circuit &ndash; Schematic created using CircuitLab

disconnect the wire between the two capacitors Co and the circuit you get looks like this







simulate this circuit

Since VCo=VC1/2 we now have a voltage between the terminals (split wire ends) of -VCo+VC1-VCo=0v

Now you can of course reconnect the two wire ends, but as there is no voltage difference between them no current will flow.

As Neil sayed a lot of nothing happens.

HOWEVER;

If you were to actually change the capacitance of a capacitor while it is charged what would happen is that the voltage would change. considder this schenario;

You have a capacitor (two plates opposite each other) charged to some voltage. now you move them appart by some distance, the capacity is going to decrease but because there is the same amount of energy stored in the capacitor the voltage will increase to compensate so that Q=(V^2*C)/2 stayes unchanged.