How to find common emitter current gain (beta) from graph
Take the positive and negative peak values of both (peak-to-peak or Vp-p), subtract the negative value from the positive to get the actual signal Vp-p value for ic and ib, and then divide the ic by the ib to get the gain.
 I have tried 3 different approaches and for the one using a peak value approach I got the gain of about 194, with the method above I got about 190, and with another method I got 174 (most likely wrong).
 Either way, the scale on the right of the middle graph seems to be the gain, and the blue line is representing it because you have Ic(Q1)/Ib(Q1) in blue.
 However, this seems to be the DC gain which takes into account the quiescent current as well, showing the instantaneous DC voltage, and that's why it is a changing value.
 So, the approach of taking the difference between the positive and negative peaks will give you only the peak-to-peak value of the AC signal without the DC to skew the results (more accurate, and you get a single amplification value instead of a changing one).