Op amp implementation
If another realization based on second-order filter functions is allowed (see the last sentence), you simply could split the given transfer function into two functions with the same denominator D(s): H1=2s/D(s) and H2=5/D(s). Now you have a bandpass (H1) in series with a lowpass function (H2). In total, this yould be realized with a minimum of two opamps. However, some knowledge about active filter realzations is reqired.