IR2110 driver output causing shoothrough despite deadtime
The IR2110 is designed to supply +/-2A to drive the gate of your output devices.

You have an asymmetric drive caused by the 47 Ohm and diode across it. 

You have not specified what 2VM1 is, but assuming it's no more than a 15V supply your maximum gate drive current is about 0.3A during turn on. During turn off you may be exceeding the gate drive capability of the IR2110 since you then have 47 Ohm with whatever the effective Vf slope resistance of the diode is (along with a 0.8-0.9V offset).  

I'd suggest you could remove D2, 3, 5, 6 and replace the 47 Ohm with 10 Ohm resistors. This will make the turn on/off delays the same which is important. With a 15V VCC that will give you 1.5A charge/discharge current.