What will be the behavior of this circuit?
1) When Q1 conducts, Vin is across L1 -> a constant voltage across an inductor leads to a linear current rise in that inductor. Vin is in parallel to L1 (neglecting the Transistor). The Circuit then looks like this:







simulate this circuit &ndash; Schematic created using CircuitLab

2) When Q1 turns off, the current from Vin to L1 abruptly cuts off but since the current in an Inductor is always steady (thats a fundamental law), it starts decresing but still flows through the inductor in the same direction. Since Q1 is off, the current flows via the C1 and D1 which now is vorward biased (C1 is charged by this current). Circuit looks like this:







simulate this circuit

3) Now if the current through L1 is close to 0 Q1 should conduct again. This the principle how a DC/DC Inverter or Buck/Boost converter would work. Remko Vink already gave you the right hint.

Concerning your question about singnals seen at the Load:
I do not understand what you mean, maybe you should put it more precisely.
But imagine C1 and Load are in parallel all the time. So the current through the Load (R) will always be: Voltage across C1 divided by R. In other words the current through the load is proportional to the Voltage C1 is charged up to.