What value should be used for an LED with current rating of 350mA ~ 1000mA
It isn’t possible to know the dropping resistor value without knowing also your supply. Know also that depending on your setup, the variation in Vf will result in large variations in current if you have both a low supply and low value for the dropping resistor.

Nevertheless, you can calculate the dropping resistor, same as for any other LED, using the following equation:


R(drop) = (Vcc - Vf) / I(led)


Power shed in the resistor is of course:


P(drop) = (Vcc - Vf) * I(led)


 

If you want to protect the LED, a way to do that is configure an adjustable LDO to sense the current.

But if you’re going to that much trouble... might as well use a DC-DC buck LED driver, like this one: https://www.diodes.com/part/view/PAM2804

Here it is on a board that can go in a flashlight: https://www.mouser.com/new/diodes-inc/diodes-inc-pam2804ev1-evaluation-board/