Wire gage - Distance - Doubling - DC/AC
In order to mount a proper argument, if the resistance of the 2/18 versus the resistance of 4/22 configurations is at issue, it's only necessary to consult a copper wire table (shown below) to resolve the problem.

Looking at the entry for 22 AWG indicates a resistance of 16.5 ohms per thousand feet, while for 18 AWG we find a resistance of 6.51 ohms per thousand feet.

Paralleling two one thousand foot long strands of #22 will result in a total resistance of:

$$ Rt = \frac{16.5\Omega \times 16.5 \Omega}{16.5\Omega + 16.5\Omega} = 8.25 \text { ohms} $$ 

Then, since a single thousand foot long strand of 18 AWG will have a resistance of 6.51 ohms per thousand feet and a paralleled thousand foot long double strand of 22 AWG will have a resistance of 8.25 ohms, for equal lengths the 22 AWG arrangement's resistance will always be higher than the 18 AWG's