LM317 Maida Style regulator
First, let's figure out how the circuit works.



Figure 1. The circuit works by dropping almost all the voltage across Q2.

This application is using the circuit built around Q2 as a pre-regulator.


R1 and D1 form a Zener voltage regulator which keeps the base of Q1 at 6.2 V higher than Vout.
Q1 and Q2 form a Darlington voltage follower. The voltage on the output of Q2 will follow that on the base of Q1 less two diode voltage drops.
The voltage between the LM317 input and output will be restricted to 4.8 V. As more current flows R3 will cause the voltage to drop even further. At 25 mA the drop will be 2.5 V giving the input voltage as Vout + 2.3 V. At this point we will be approaching the minimum headroom required for the LM317 to regulate.
The end effect is that the LM317 never has to dissipate much power and probably works without a heatsink. \$ P_{MAX} = VI = 2.3 \times 25m \approx 60~mW \$.
Note that Q2 is working much harder. If the output is set at 20 V and 25 mA is drawn then Q2 will dissipate about \$ VI \approx 150 \times 25m = 3.75~W\$. Heat sink required.



  On the schematic, Vin is 170 volts. Can this schematic be used with much lower voltages (let's say 60 V DC).


Certainly. Recalculate the resistance (and power) required for R7 to achieve your maximum output voltage.


  According to the schematic, output current is 25 mA but I need around 1 amp. Do I need to modify something to get 1 amp output?


Yes. As explained above R3 is designed to limit the current. For 2.5 V drop at 1 A R3 would be 2.5 Ω. The problem will be power dissipation in Q2. You would probably have to parallel several transistors and put resistors (maybe 0.1 Ω) in each emitter to balance out the currents.

Do the power calculations and you'll start to see the benefits of switched mode regulation.