Voltage divider homework
You seem to have answered your question in the comment above.  It's easy enough to calculate the value for \$R_L\$ given the voltage and power:
$$R_L = V_L^2/P_L = 277.8 k\Omega$$
What may have been stumping you is that the problem has an extra degree of freedom; you can choose the value for either \$R_1\$ or \$R_2\$ and calculate the other.  Your answer above is correct, but a simpler solution can be had if you choose \$R_2 = R_L\$, then \$R_2|| R_L =R_L/2\$, and since \$V_L\$ is \$1/3\$ of the supplied voltage, the required value of \$R_1\$ is twice that parallel combination, so \$R_1=R_L\$ as well.