MOSFET turn on/off curves misunderstanding
The answer is that all these plot shows in application notes are made by assuming the inductive load plus a flyback diode is switching by a MOSFET. As shown in fig 6. 

Additionally, the authors assume the MOSFET operates as a switch in the application when the inductive load is in "continuous current mode"(we replace the induction with a constant current source at the drain for this purpose). Thus, the current in the flyback diode and in the inductor is not at 0A at the beginning of a turn-on process. 

And due to the flyback diode current, the MOSFET Vds will start to decrease only when diode current reach 0A (the MOSFET needs to take over all the inductor current from the diode) before Vds starts to decreases. 

And the simulations confirm this: 



Try read here 

https://www.allaboutcircuits.com/technical-articles/switching-losses-effects-on-semiconductors/

But of course, for a pure resistance load, the situation looks different.

 

As you can see for a purely resistive load everything looks as we expect to be looking.