Transistors Circuit Analysis
Name the transistor's base resistor that goes up to the INPUT as \$R_1\$ and the base resistor going to ground as \$R_2\$ and the emitter resistor as \$R_e\$. Then assuming the INPUT allows the BJT, in which it is the collector load, to be in the active region and also allows the emitter to be significantly above ground, the circuit will produce a current in the load of:

$$I_{LOAD}=\frac{\beta\cdot\left(V_{INPUT}\frac{R_2}{R_1+R_2}-V_{BE}\right)}{R_1\vert\vert R_2 +\left(\beta+1\right)\cdot R_e}$$

As everyone can see, as well, the rest of the circuit is there to distract.