How can I activate lights with 6-pin DIN?
simulate this circuit &ndash; Schematic created using CircuitLab
You don't need a Raspberry Pi for this, you don't need an Arduino for this, either.
Arduino and Raspberry would just add an unnecessary complexity to the circuit.
The alarm device already has a buit-in relay; but, it does allow maximum voltage of 28 VDC, maximum current of 750mA, and maximum power of 10W. If you want more power than this, you would need an additional relay - what wouldn't be complex to do, either.
Look at the device datasheet:
&quot;When the accessory relay is energized, its contacts close and present a short across pins 2 and 3 of the connector. The relay contacts are rated for 10 watts maximum at 28 VDC/AC 10-watt rating the closed contacts can handle up to 750 mA continuously and switch up to 400 mA ofcurrent. Relay contact rating: 750 mA maximum @ 28 VDC.&quot;
You just need to use a charge that can be handled by this relay (750 mA @ 28 VDC), or just wire a power source and another relay to the pins 2 and 3, and the another relay would handle the charge that you need.
With maximum ratings of 10 W, 750 mA and 28 VDC, you can light up a board with red LEDs (and current limiting) enough to wake up everyone. I suggest you stay with 12V, there are plenty of options, with 12V and 750mA you can reach 9W, which can light red LED's VERY bright!
You could use an automotive red bulb (be sure that you use the ones with LEDs), they have built-in resistors, and a LED brake tail-light bulb would draw only about 500 mA at 12V There are plenty of options; search Ebay for &quot;12v red led beacon&quot;.