How to represent a given sinusoidal equation?
In general, a sinusoid in the time domain (time is the independent variable), is represented as: \$ v(t) = A \sin(\omega t + \phi) \$. 

The informations you need are: Amplitude \$ A \$, angular frequency \$ \omega \$ and phase \$ \phi \$. 

You correctly calculated \$\omega =  2\pi f = \frac{2\pi}{T} = 1000\pi\$.

The amplitude is given: \$ A = 331 V\$

Now we need to calculate the phase. We know that \$ v(0.0002) = 331 \$.   

If we plug the previous value in the formula, we get: 

\$ v(t) = 331 \sin(1000\pi t + \phi )\$  

We plug also the peak values to get the phase:
\$ 331 = 331 \sin (1000\pi * 0.0002 + \phi)\ \Longrightarrow \sin(0.2\pi + \phi) = 1\$   

We know that \$\sin(\alpha) = 1 \$ when \$ \alpha = \frac{\pi}{2} \$, so we impose:
\$  0.2\pi + \phi = \frac{\pi}{2} \$ and solve for phi.

\$ \phi = \frac{3\pi}{10} \$

And we plug this into the equation. As a result, we have:
\$ v(t) = 331 \sin(1000\pi t + \frac{3\pi}{10}) \$.

Now you can plot it: