Pull Up Resistor Value for temperature sensor
Depending on the cable you are planning to use (for relatively long distances), the pull-up resistor and the cable capacitance form a nice, one-stage low-pass filter which directly affects tr and tf.



tr (Rise Time): The duration that the signal rises from its 10% to its 90% level.

tf (Fall Time): The duration that the signal falls from its 90% to its 10% level.

tp (Pulse duration): The duration between 67% and 33%.

As a result, 

$$
t_r = t_f = 2.2 \ R_P \ C_L
$$

where RP is the pull-up resistor and CL is the total cable capacitance.

I will not fill in the answer with a proof. But it's easy - use the capacitor's charge and discharge equations.



For example, let's assume you are using a 20-meter-long cable with a capacitance of 30pF/m (running two cables: data and ground), so CL=600pF, and a pull-up resistor of RP = 10kOhm. 

From the formula above, tr = tf = 13.2μs. We can fairly assume that the width of a pulse will be decreased by ~10μs. It's also easy to say that this RC network will chop-off the incoming frequencies beyond fC= 1/(2 π RP CL) = ~26kHz.



From the datasheet of your sensor, the minimum pulse width is 26-28μs which allows us to make tr = tf = ~1μs. With the same cable in the example above, the maximum pull-up resistor can be calculated as RP = ~1Ω which is completely unacceptable and impractical. So, you should either decrease the length or use buffers-repeaters at both ends.