Should bias voltages still be in range without driver/output transistors?
Without a specific schematic, one can only speak in general terms. But yes, in a robust design, the actual bias current of the output devices should be a relatively small fraction of the total current through the bias network, in order to reduce the effects of the manufacturing tolerances of specific devices. This  means that the voltages you measure should be close to the values you would get with good devices in place.



Responding to the followup information you added, I can see that there is some confusion.

The bias is the voltage drop across Q804, which amounts to about 1.8V, based on your measurements. This seems like a reasonable value.

The fact that the common mode voltage is on the order of 37V just reflects the fact that the feedback path is currently open, because the output transistors are not in place. The differential amplifier is trying to increase the output voltage slightly, but since it can't tell that it's happening, it ends up driving to the positive rail.

If you temporarily connect the emitter of Q804 to P809, you'll create an alternate feedback path, and you should see the common mode voltage drop to close to 0V. Specifically, you should see Q804 emitter at 0V and its collector at +1.8V. If you instead connect its collector to P809, you should then see the collector at 0V and the emitter at -1.8V. These checks would verify that Q801-Q804 are all working correctly.