Convert dB to resistance
You've got a voltage divider, the series element is a capacitor, and the output (shunt) element is a 50 ohm resistor.

Chances are you will not be loading your analog multiplexor with 50 ohms, but this is how the TI measurements are taken.

The attenuation level of -64dB (lets call it 60dB, for now, to ease the fears of using dB) means 1,000:1 voltage or 1,000,000:1 power.

Thus the crosstalk, thus the capacitances of FET junctions and FET gates and the non-ideal VDD bypassing and the non-ideal real-world package inductances, is 1/1,000 of the input level at 1MHz.

The shunt reactance is that 50 ohm resistor; the series reactance is 1,000X larger at 50,000 ohms at 1MHz ---- and is a capacitor.

Given 1pF at 1GHz is -j159 ohms, or -j159,000 ohms at 1MHz, we easily conclude
there is an effective 3pF (to produce -j53,000 ohms at 1MHz).

Thus your crosstalk circuit, or your isolation circuit, looks like this:







simulate this circuit &ndash; Schematic created using CircuitLab