How to use a 0505 dc-dc isolator?
I would suggest against the 0505 because they are only 1W isolators. This means that the current at 5V would have to be less than 200mA. I would suggest going for 
Hi-Link 220V to 5V converters such as this one from eBay.

This module is 3W so the charging current would be 3 times higher at 600mA. You can use 3 of these modules in parallel.

Make sure you configure the TP4056 resistors to limit the current.

If you must use the 0505 due to its small size or other constraints (like you only have a +5V source), it's very simple to use. Supply +5V and GND at the input and you'll get isolated +5V and GND at the output (see datasheet for pinouts). You will have to cut the 6 wires going to + and - of TP4056 and inject the 0505 between them (use the cut up end of the wires close to the power supply as input and the other end as output of the 0505).

Just remember to limit the TP4056 charging current to 100mA or so to ensure a long life of 0505 otherwise they might have a reduced life span.