Why theoretically the higher voltages do not generate the bigger losses
Let's say we want to transfer a power "P" over a distribution line. Assume two ways to do this:

Higher voltage lower current: P = V1*I1 where I1 = P/V1

Lower voltage higher current: P = V2*I2 where I2 = P/V2

Thus V1 > V2 and I1 &lt; I2

Any distribution channel will have definite resistance "R"

Power loss in both cases:

Power loss 1 = I1*I1*R = PPR / V1

Power loss 2 = I2*I2*R = PPR / V2

Since V1 > V2, Power loss 1 &lt; Power loss 2

Hence it's preferred to transmit power at higher voltages and lower currents.