Current through capacitors
First find the impedance offered the capacitors. Two capacitors C1 and C2 in series will produce an impedance,  \$Z = \dfrac{1}{j\omega C_1} + \dfrac{1}{j\omega C_2}\$.

Then calculate the current, \$I= V/Z\$.

Now the current through the capacitors \$\mathrm{= min(I,I_{max})}\$. Where \$I_{max}\$ is the maximum current the supply can provide.