Simple Power Dissipation Questions - Completely Stuck
Looks like you've gotten the answers a-c.  Here is an approach for d and e.  The difficulty here is that power is hard to think about since it is a nonlinear, squared, function of the things we have a feel for.  So for d use V^2/r to find the voltage must be 3V.  For e do the same thing to find the current must be 3A.  Now you probably see the 4V source, 3 Ohm and 9 Ohm resistor can be used to get 3V across the 9 Ohm and therefor 1 Watt.  Similarly you can use the 9 Ohm and 6 Ohm resistor as a current divider to get 3A through the 6 Ohm resistor from the 5A source.  3^2=9 9*6 is the 54 Watts.