Circuit analysis with two loops, resistors, and independent/dependent sources
This is a very quick look at it, I might have some polarities mixed up. I think the idea here is that you need two KVL and one KCL to form 3 equations to solve together.

Left loop KVL clockwise from common:
15.2V + iB*10k + 0.8V + IR2*200 = 0  (eq1)

Right loop KVL anti clockwise from common:
25 + 500*29*iB + Vy + IR2*200 = 0 (eq2)

Center VCL:
iB + 29*iB = IR2 (eq3)

Now its just a matter of solving. Re-arrange eq3 to get iB as a function of IR2.
Then subsituation that iB value in to eq1 to get the value of IR2.
Then use IR2 in eq3 to get iB.
Now you have IR2 and iB for eq2 to get Vy.