What would happen if I choose a connector with current rating smaller than the actual current?
all connector junctions have ESR contact resistance, as well as the incremental resistance of wire with length,
total resistance creates a voltage divider and thus a (Norton equiv.) current limiter.
Inductive loads have a DCR that defines the peak current load possible, but limited by your poor solution with higher ESR.
Current limit translates to loss of torque or force. 
then analyze I^2*ESR loss times Rja thermal resistance of wire junction to determine temp rise and melting of contacts. (estimates are required)


I leave you to test/verify this or do the math with typical contact resistances of your connector and wire and undefined load.


conversely do a test and then measure the short term and long term values for contact resistance from voltage drop and current limit with temperature rise of the hot junction. Start with constant current of 10A then step to 100A, then actual load.