By simple inspection calculating the gain of a circuit
The DC case is also quite straightforward. Just analyze the resistor network:
$$\frac{V_o}{V_i}=\frac{R_2||(R_3+R_4)}{R_1+R_2||(R_3+R_4)}\frac{R_4}{R_3+R_4}\approx 0.003974$$
which corresponds to an attenuation of about \$48\$ dB.