DC-DC Boost Converter 12V .5A Output, 3.6V, 2A input
If you only have a maximum of 2A input at 3.6V, and you need a continuous 12V @ 0.5A output then you may have problems.  

If we assume around 82% efficiency (from your report) then:

0.82 * (3.6V * 2A) = 5.9W  

So there will not be enough power available to provide 12V @ 0.5A (6W) at the output. In your report the calculated RMS inductor current is given as 2.63A.
Also the 3.6V is given as Vin max, so things will get worse (input current will have to rise) for the given Vin min of 3V. 

To get a good idea of performance, as well as doing the calculations thoroughly, you should probably simulate this circuit in SPICE (TINA or whatever it is TI provide) or build a test jig.