finding the current in a branch with resistor, capactor and a voltage source
In your circuit Vc(s) is impressed across each of the 5 branches.  You can write a node equation on that top node fairly easily.  The current leaving that node in the leftmost branch is Vc(s)/20.  Look carefully at the second branch from left and you will see that the current flowing down that branch is [Vc(s) + 1V]/(20+2s).  You should be able to work it out from this point.