Calculate the next state for flip flop sequential circuit
Since QB is connected to both J and K we know that QA(t+1) will toggle when B is 1 and will remain the same if B is 0

QC(t+1) = QC since T is always 0

Lastly B will always toggle since the QB' goes to the input.

So starting from state 7 (111):

QC(t+1) = 1
QB(t+1) = 0
QA(t+1) = 0 (it toggles since J and K are both 1)

So now we have the state (001).
Next state:

QC(t+1) = 1 (input is 0 so QC remains high)
QB(t+1) = 1 (QB' = 0)
QA(t+1) = 0 (it stays 0 since J and K are both 0)

~~

So in short:
(111) -&gt; (001) -&gt; (011)