What is the peak of the short circuit current
If you want precise measurements you should not rely on the cursors: they are handy, but only for quick references, as you can see in the time values of the two readings. Instead, use .meas for an optional interval:

.meas Imax max I(V2) from 0 to 100n


Here I chose 100n as the final time because I only wanted to measure the initial peak current.

You should also know your tool before you use it: inductors have a default series resistance of 1m&Omega;, which can be seen when right-clicking on the inductor (message at the bottom of the settings window). Also, there is a default Rpar, to allow damping, setting which can be altered in Tools &gt; Control Panel &gt; Hacks! &gt; Supply a min inductor damping.... It seems to default to gmin*L = 1e12*L, so if your inductance is small enough, it may become influential enough. Directly setting Rpar to zero is much quicker and doesn't influence the rest of the schematic(s), since the Control Panel setting is remembered.

The capacitors also have the hidden Rpar, which seems to default to gmin, which isn't that much problematic. Still, since your example relies on ideal elements, you should probably take time to set to zero the builtin parasitic elements for both L and C. It's enough to do it once, for one, and then simply copy-paste for the rest.

Finally, you may want to impose a tighter timestep, for better resolution, and also disable waveform compression with .opt plotwinsize=0, since the default 300 points is not that much precise.

Considering your other question, it seems you need to rely on some simulator or another for your learning, so it would do you good to deal with the friendly, but rather spartan manual when things seem to not work properly. The undocumented LTspice can provide additional help.