Simple op amp circuit question
Step by step:

Let's assume the hypothetical super-power TL081 can drive the currents as per this task.
We have V+, V- and Vout in this circuit.

By OA theory, the voltage between V- and V+ will be always driven to zero with this negative feedback setup and under ideal conditions. Therefore the V- must be at +5V in the steady state. To make this happen the current over R1 must be -1A, for a drop of 5 V from the 10V source V1.

To keep V- at +5V the R3 must sink all this 1A current since an ideal OA have infinite impedance and the inputs don't consume any current. All current must be provided over R3.

Since R3 is 3 &Omega;, the voltage drop will be 3V. To get 3V across R3 the Vout must be at +2V, and this potential will be maintained by internal drivers of the OA. Therefore the Vout will be kept at +2V.

The load R2 is 1 &Omega; and therefore the dissipated power (with 2 V across) will be 2^2/1 = 4W.

The current over R1 is therefore 2 A; 1 A will come from R3, and another 1 A will be supplied by OA.