Operating an inductor beyond its rated current
The temperature rise is stated to be 20°C at maximum current. You are suggesting putting 4.7 times as much current, so it should rise more than 400°C, which will destroy the wire insulation causing it to melt together with shorted turns. After some time it may open up. The inductance will also drop dramatically due to core saturation and will be little better than a very high resistance unreliable wire.

You do not need an inductor in this position, and 100uH is too low to make any significant difference at mains frequencies anyway (\$X_L = 2\pi f\cdot L \approx 0.075\Omega \$ at 120Hz). 

A short would be an infinitely better choice. 

Your capacitors are also very low for 1.5A current- more than 8Vp-p ripple at 1.5A, and you'll probably truncate their life with all that ripple current.