Thevenin's equivalent exercise
The Thevenin equivalent of the circuit between common and B. 


Open voltage 7.5 V
Equivalent resistor 23,5 ohm


This however does not solve the question. For that you need to calculate the Voltage between B and common being 2,7 mA x 47 ohm +0,7 BE = 9,8269 V. This brings the base current to 283,9 mA. 

Since the emiter current is only 2.7 mA the above is not possible. Therefore the given values are wrong or incomplete