Mystery! LED lights unplugged yet still lights perpetually
You have electric fields, at 120 volts RMS or 160 volts peak, at 60Hz(377 radians/second), coupling tiny currents thru the various wire-to-wire capacitances in that part of your house.

Assume a 1 meter wire (1mm diameter) is only 10mm away. Assume parallel-plate capacitance model, because when you have a jumble of wires, there is no sense to use the standard free-space wire-to-wire equations; besides the parallel-plate capacitance is low, and therefor conservative, compared to wire-to-wire maths.

Compute capacitance: C = (E0 * Er) * Area/Distance

C = 9e-12 Farad/meter * (1meter * 1mm) / 10 mm = 0.9pF

The current is computed as I = C * dV/dT

dV/dT is the slewrate of the voltage waveform. We'll assume this is pure sinusoid; the local behavior of any black-bricks switching supplies may greatly boost this slewrate.

The slewrate of 160 volt sin, at 377 radians/second, is approx. 150*400 = 60,000 volts
per second.

Now use the I = C * dV/dT

I = 0.9 pF * 60,000 volts/second = 54 * e-12 * e+3 = 54 e-12+3 = 54 e-9

I = 54 nanoAmps

I = 0.054 microAmps, assuming PURE SINUSOIDAL waveforms. And parallel-plate coupling model.

ON THE OTHER HAND, if that black-brick is working, and providing spikes, such as 200 volts in 200 nanoseconds, then the slewrate has increased from 60,000 volts/second to ONE BILLION volts per second.

In that case, all that charging and discharging will increase by 1,000,000,000 / 64,000 or about 16,000X. To the level of 1 milliamp.

Perhaps you can provide a diagram of the wirings.