Messing with rgb leds and have a question
"Most light" usually means 20mA. Here is the generic equation for an LED:

\$ R = {(V_S-V_f)\over I_f}\$

Red:

\$ {(12\text{V}-2.17\text{V})\over 20\text{mA}} = 491.5\Omega \$

Green:

\$ {(12\text{V}-3.11\text{V})\over 20\text{mA}} = 444.5\Omega \$

Blue:

\$ {(12\text{V}-3.07\text{V})\over 20\text{mA}} = 446.5\Omega \$

So we're talking 510ohm for red and 470ohm for green and blue, assuming your supply is 12V. Otherwise substitute the correct value in the equations and recalculate.