voltage divider with 2 power sources, Vout?
Answers:


  A) I would like to request some help on how to solve it when v2 = 3.3 volts is present. Please do not skip steps if you answer it.


You need to use the full equation here.

\$V_{OUT} = V_B + (V_A - V_B) * R_2/(R_1 + R_2)\$

which in your example is

\$V_{OUT} = 3.3 + (5 - 3.3) * 667/(200 + 667) = 3.3 + 1.7 * 667 / 867 = 4.61V\$


  B) Vout is calculated with reference to GND. Right? If yes, that means the voltage drop at R2 equals to Vout = Vout - GND = Vout - 0 = Vout assuming GND as reference point?


Ok that is a confusing sentence, but essentially correct.


  C) Is it correct to say the voltage drop at R2 = Vout - VB? (So in this case i do not take GND as a reference point).


No, the voltage drop ACROSS R2 is Vout-VB.


  D) So there are 2 different ways to describe voltage drop? Like case B) and case C).Am i correct?


Since you got off course with C, then this assumption is also incorrect.