Electronic selector / gate
Inputs: I1, I2 and I3
Outputs: O1 and O2

The following table shows what I have understood from your question. Assumed that I2, I3 and O2 can be considered as digital signal

$$\begin{array}{cccc} &amp;\style{color:blue}{\mathbf{I_2}} &amp;\style{color:blue}{\mathbf{I_3}} &amp;\style{color:blue}{\mathbf{O_1}} &amp;\style{color:blue}{\mathbf{O_2}}\\
&amp;0 &amp;0 &amp;I_1 &amp;0\\
&amp;1 &amp;0 &amp;0 &amp;1\\
&amp;0 &amp;1 &amp;I_1 &amp;0\\
&amp;1 &amp;1 &amp;I_1 &amp;0\end{array}$$

Now implementing this logic is simple if you have a \$\mathrm{4\times 1}\$ analog multiplexer (eg:74HC4052). 

Connect I2 and I3 to the select lines of the MUX. And feed all inputs of MUX except the second input with I1. Connect ground to the second input and O1 to the output. 

You can implement \$O_2=I_2\overline{I_3}\$ with MUX or gates.