RLC Q factor measurement
The Q for any tuned LC circuit cannot be higher than the Q for the inductor itself and, if the inductors series resistance is high enough, it dominates the quality factor. 

So, given that you have witnessed a Q of 11.9 and that inductive reactance at 16.7 kHz is 1049, the ESR of the inductor must be about 88 ohms.

Now this may not directly translate to the measured DC resistance because of skin effect, proximity effect and possibly core losses but I would expect that the inductor you have chosen is a few tens of ohms in DC resistance.



From wiki, a series RLC tuned circuit has a Q of: -

\$\dfrac{1}{R}\sqrt{\dfrac{L}{C}}\$ and, if you rearrange the formula when the circuit is at resonance you get: -

Q = \$\dfrac{\omega_0L}{R}\$ and this is the same as the Q factor for an inductor.

What is the relevance of this you might ask? It's relevant because if you throw away the 100 k feed resistor you are left with L and C in series with the AC resistance of the coil; in other words, the best Q you can achieve is defined by the Q of a series tuned circuit driven from a perfect voltage source.