Convert this to standard POS
You meant canonical form by saying 'standard POS', then,

$$A(A + C')(A + B) = (A+BB'+CC')(A+BB'+C)(A+B+CC')$$
$$=(A+B+CC')(A+B'+CC')(A+B+C')(A+B'+C')(A+B+C)(A+B+C')$$
$$=(A+B+C)(A+B+C')(A+B'+C')(A+B'+C)(A+B+C')(A+B'+C')(A+B+C)(A+B+C')$$
$$= (A+B+C)(A+B+C')(A+B'+C)(A+B'+C')$$

But if you meant simplified by 'standard POS', then 
$$A(A + C')(A + B) = A$$