Solving a circuit with a directional loop
The diode is reverse biased, so no current will flow thru it (other than leagkage, but you said ideal components and that would be much much smaller than the resistor currents anyway).  You therefore are simply left with two 4.7 k&Omega; resistor in series with a 5 V supply.  The resistances add, for a total of 9.4 k&Omega;.  From Ohm's law, the current is 5V / 94.k&Omega; = 532&micro;A.  Since the resistors are equal, the node between them will be at half the supply voltage, which is 2.5 V.  Yes, it really is that simple.