PSU First stage with IRCL Voltage rails swapped
A very complicated circuit that does not do what you'd like it to do (I assume, as you don't tell us what you want it to do, just what you've done).

I assume you want two DC outputs, one with full wave rectified 18v on it, one with full wave rectified 36v. So roughly 24v and 48v supplies. Am I correct?

One problem is that the BRx components contains 4 diodes. Unfortunately, you have paralleled one AC input on the transformer side, and one DC output on the output side, and they are cross coupling. Consider what happens when the common AC input is negative, and BR1's AC input is positive. Draw it out.

There is a second complication, you don't need all these resistors. Bridge rectifiers are built for the purpose, they withstand capacitor filter inrush. Get a data sheet for your rectifiers, and look up the 'single cycle surge' specification. You may be surprised at the large number. You should find that for 'few amp' sized rectifiers, the switch on surge that they are rated to withstand is 30 to 100 times their continuous current. They really are as tough as old boots. 







simulate this circuit &ndash; Schematic created using CircuitLab

This is all you need. I've drawn out what's inside the bridge rectifier as discrete diodes, I have labelled the equivalent bridge connections. Fewer components, less diode drop. 

If you take a load current from just C1, it will still give you balanced transformer load, which is important, trace it out. C1 and C2 can have different values, if you want to draw different currents. That's OK. 

You may need to think a bit to change the capacitor values from those you had, as they are connected in series, not parallel. Each output capacitor gets charged up to sqrt(2)*18v - a diode drop, about 24v or so. They are connected in series, so you can take an output of 24v or 48v. The input transformer provides isolation, so you can ground any of the capacitor output terminals.