Calculating base current
It's simple. You are ignoring \$R_E\$. Here is the correct solution:

\$I_B = \dfrac{V_{IN} - V_{BE}}{R_B + 201 \cdot R_E}\$

\$I_B = \dfrac{5 - 0.6}{440k + 201 \cdot 3.3k}\$

So,

\$I_B = 3.988{\mu}A\$

\$I_C = 200 \cdot I_B = 0.8mA\$