IR2110 getting really hot in this high-side gate driver configuration
IMHO, the blogger is not a very good power electronics engineer.  His blog seems to be well read but most posts are of poor quality.


  
    In Fig. 9 we see the IR2110 being used as a single high-side driver. The circuit is simple enough and follows the same functionality described above. One thing to remember is that, since there is no low-side switch, there must a load connected from OUT to ground. Otherwise the bootstrap capacitors can not charge.
  


That is not true.  To charge the bootstrap cap, there needs to be a low-impedance path, such as a turned-on power switch would be.  

A series combination of a LED with a resistor, on the other hand, has resistance equal to the resistor value.

The IR2110 and IR2113 are bootstrap gate driver circuits.

The charge reservoir for the upper gate gets charged when the lower switch it turned on.

This schematic from the IR2110 datasheet does not even show the current path that would enable your circuit to work.  I assume your OUT terminal is connected to ground via a resistor in series with a LED.

There must be some stray current path inside the chip that is used when the chip is not configured as intended.

I suggest to put the switch to the low side and reconfigure the IR2110 to the LO output.

Btw.  I have burned a dozens of these gate drivers in the past.  They are notorious for being easy to burn out due to static electricity.