Voltage Drop on parallel resistor
This is not a parallel connection, because the transistor's base and collector are not at the same voltage. As a general rule of thumb, NPN transistor common-emitter amplifier like this will have Vbe about 0.6v or 0.7v. Since emitter is grounded, assume Vb is 0.6v. You can also assume that the LED has a somewhat constant voltage when lit, about 1.5V for Red LED if I remebver correcfly. Now you have an estimate for the voltage across the series resistors. Use that to estimate the current through the left branch, which is the transistor's base current. Now you can calculate the collector current by multiplying the base current by the transistor's current gain (beta) from the datasheet. Finally, the collector current lets you determine the voltage drop in the 470ohm resistor, and you can again assume roughly constant LED voltage when lit.

Measuring a 1Mohm resistor is not trivial. The measurement is affected by the measurement system. Your voltmeter is not shown in the circuit, but it will look like another high resistance in paralell with whatever you're measuring. If the voltmeter input is 10Mohm equivalent, and you connect it across a 1Mohm resistor, you're really measuring 10M in paralell with 1M. At some point the input resistance can be cinsidered negligible, but 1Mohm may be too close to the input resistance. Your voltmeter should have a datasheet or manual, that will list the equivalent input resistance of the volts measurement.

Also note that you can measure voltage while the circuit is powered on, but you cannot directly measure ohms of a resistor that is part of a circuit. The DMM ohms range can be used when sorting individual resistors before connecting them into a curcuit. DMM ohms measurement actually drives a test current through the resistor and measures the resulting voltage drop; this will not work right if there is already an operational current flowing.