Ammeter with 2 voltage sources without superposition
Okay, I think I have actually managed to solve it.
I of R2ohm is 3amps
I of R3ohm is 4amps
I of R5ohm is 3.6amps
Writing down a KVL on the top right node we get -7.6 amps of current flowing through the 12V source, then another KVL at the node left to the ammeter we actually get the -10.6 amps.