A question about the current value in a mains tester
At a frequency of 50/60 Hz, the body capacitance is essentially an "open," so ignore it.  that leaves the 500k in series with the 1.5k body resistance.
Since the 500K is much larger than 1.5K, you can also temporarily ignore it, so you are left with the voltage source (250V) in series with the 500k, making it a current source of (250V/500K =) 0.5ma. This current, into the 1.5K body resistance develops (.5ma x 1.5K =) 0.75V max (with feet grounded).

Your model should be as you have it, except the resistor needs to be grounded and the capacitor removed (or in parallel with the body resistor).