Voltage on the secondary of current transformer
There's no contradiction. When you limit the secondary voltage by putting a load across it, the primary voltage becomes proportionally lower, too.

You can think of it as having the secondary load resistance "appearing" in parallel with the primary, but with a value that's reduced by a factor of \$(\frac{N_2}{N_1})^2\$. When you put a given current through this combined impedance, the voltage drop across the primary is much lower than it otherwise would be.