An op-amp connected to another op-amp, the one with ground and the other with virtual ground
OK Since you are not telling us where your grounds are connected I have to assume left ground is connected to the bottom of the 20V supply in your original post. 

You have also not indicated which voltage U1, U2 and Uo are referenced to, so again I will make the assumption it is to the same side of the 20V supply.

As such you have the following circuit.







simulate this circuit &ndash; Schematic created using CircuitLab

The formula for the second stage is

\$U_o = V_1 - (U_2- V_1).\frac{R_4}{R_3} \$

\$  = (\frac{R_4}{R_3}+1)V_1 - \frac{R_4}{R_3}.U_2\$ 

We know 

\$U_2 = -\frac{R_2}{R_1}.U_1\$

So 

\$U_o = (\frac{R_4}{R_3}+1)V_1 + \frac{R_4}{R_3}.\frac{R_2}{R_1}.U_1\$ 

Of course if the first of amp does not have a negative rail.. the above may be nonsense.