KCL Current Law calculations
Sanity check

Current from 5V supply is \$\dfrac{5V}{10\Omega + parallel resistors}\$

Parallel resistors are \$\dfrac{1}{\frac{1}{20}+\frac{1}{40}+\frac{1}{80}}\$ = 11.43 ohms

Therefore current is \$\dfrac{5V}{21.43\Omega}\$ = 233.33 mA and this means total power is 1.1667 W.

Voltage across the three parallel resistors = 5V - \$10\Omega\times 0.23333 = 2.6667V\$

From this you can calculate the currents in the individual resistors.

This is what you should be getting whatever method you use.