Basic electric Circuit with inductors
Sanity check

The 0.1H impedance at 2\$\pi\$F = 100 rad/sec is 40 ohms.

Reflecting \$R_0\$ to the left gives you 20 ohms and therefore the total circuit impedance is: - \$\sqrt{40^2 + (10 + 20)^2}\$ = 50 ohms.

Given that the drive voltage is 25 V, this has to mean the current from the supply is 0.5 A.

This current flows through the 20 ohms (reflected) producing a voltage of 10V. This has a power of 5W and therefore if the resistor was placed back on the right-hand side you'd have the same power and expect a voltage of: -

V = \$\sqrt{5W\times 5\Omega}\$ = 5V

Looks like we're all getting 5V!