Printing current when using sinus voltage source?
V1 0 1 SIN(0 0.75 60 0 0)


This is a sinusoidal source with amplitude 0.75 V and period ~16.7 ms.


  .tran 10ns 400ns 300ns


This says simulate the time window from 0.0003 to 0.0004 ms in 0.00001 ms steps.

So your voltage source has the equation

$$V(t) = (0.75\ {\rm V})\sin\left(2\pi 60 t\right)$$

What is the maximum value of this source in the window you're simulating?

$$(0.75\ {\rm V})\ \sin\left(2\pi 60 [400\times 10^{-9}]\right)=1.97\times 10^{-6}\ {\rm V}$$

With 2 uV applied to your resistor, you shouldn't expect to see much current through it.

The real mystery is why you were seeing ~60 uA instead of the ~2 uA I would have expected. Are you sure the input file you shared is exactly the one used to produce the results you included in your post?


  what I expect is values between -0.75 and 0.75,


To see this you need to simulate over the whole ~17 ms period of the source, not just a tiny 100 ns time window.