How to create circuit for low voltage trigger of a relay
My question is how do I wire up the trigger. 


You have provided a diagram that shows you. Connect the 'T' input to GND (DC-) once for each change of state.


  Correct me if I'm wrong but I'm assuming that if I send 5 V, 2 A, to the trigger pin it will fry it. 



You don't send 5 V to it. You connect it to ground.
Circuits only draw the power they need. If you plug a 20 W lamp into your domestic supply it will draw the current it needs not what the supply is capable of.



  ... so how do I drop the multage 


'Multage' is not an engineering term I am familiar with.


  and or amperage to safely operate this relay. 


You don't. It will look after itself.


  No information came with the relay for the voltage/amperage requirements.


We recommend: "No datasheet? No sale."

The current required by the module will be 99% determined by the resistance of the relay coil. If you have a multimeter and can find the coil pins you can then measure the coil resistance, R. The current, I, can then be worked out from \$ I = \frac {V}{R} \$.

If, for example, the coil resistance is 200 Ω then the current required will be 
\$ I = \frac {5}{200} = 0.025 \ A = 25 \ mA\$.