Precise measuring of frequency with high-speed ADC
What you are trying to do is very challenging. Frequency measurement boils down to measuring the time T between corresponding points on the signal waveform (e.g., rising zero crossings) over some number of periods N. The period of the waveform is T/N, and equivalently, the frequency is N/T.

Simple frequency counters just count the number of times that the signal crosses a fixed voltage threshold over a fixed amount of time, and the resulting measurement is relatively crude, with a potential error in N of &plusmn;1 whole cycle. This, combined with the accuracy of the counter's internal timebase, determines the accuracy of any particular measurement.

What you are proposing by using an ADC is much more sophisticated, but there are still many issues to overcome before you get to the level of accuracy you're proposing. You'll know N exactly, so the accuracy depends entirely on your ability to measure T. See the following diagram.



To start with, the samples you take are not going to be synchronized to the signal waveform, so it will be necessary to interpolate the position of the actual zero-crossing from the samples on either side of it. The problem is that each sample, represented by a "fuzzy" ellipse above, has a significant amount of uncertainty associated with it.

There are voltage errors, caused by:


the basic resolution of the ADC
nonlinearities
noise
calibration (scale and offset)


There are also timing errors, caused by:


sampling frequency error
jitter
ADC aperture error


This means that your estimate of the actual waveform (shown as the heavy black lines) could be anywhere in the "error band" represented by the dashed lines. In other words, the interpolated position of each zero crossing will have a timing uncertainty associated with it, shown as &Delta;T. Note that voltage errors contribute to &Delta;T because of the finite slope of the signal at each zero-crossing.

The overall period that you're measuring could be as small as T &#150; &Delta;T or as large as T + &Delta;T, for a total error of 2&Delta;T. This means that if you want 12 digits of accuracy, 2&Delta;T must be less than T &times; 10-12. Assuming you're taking measurements "quickly" (i.e., T is on the order of 1 second), this means that &Delta;T must be less than 0.5 ps. 15-digit accuracy would require &Delta;T less than 0.5 fs. These are not easy numbers to achieve.