The gain of two op amps in series at high frequencies
Your DC gain is correct.  Now, given the gain bandwidth of 7MHz, the 3dB bandwidth of the first stage is 7/(1+24/180)  MHz or 6.18 MHz  The second stage bandwidth is 7/(1+2.7/7.5) MHz or 5.15MHz.  Now a single pole transfer function for each stage is Adc/(1+s/wo) where wo = 2*pi*BW.  So the gain at 13MHz relative to the DC gain is 1 over the magnitude of each denominator multiplied together, with 2*pi*13MHz for j*w, and each bandwidth (calculated above) for wo.  I get .429 and .368 for each stage, multiplied together that's .158 or -16.034dB.

Note that you use the "noise gain" or non-inverting equivalent gain to compute the bandwidth for the first stage because the gain-bandwidth is always referred to the non-inverting gain.