linearize single arm wheatstone bridge output
Wheatstone bridges are mostly used for very small resistance changes in a sensor, like for a strain gage or something like that.  Your resistance change is huge, so you don't need one.  As most have been saying, put a constant current source into your sensor.  In the attached schematic, as the noninverting input of the op amp is at virtual ground, the current going through the sensor will be a constant 1ma.  You haven't offered enough of a response profile to allow us to help you to linearize (or if you even need to), but log and inverse log amps can be found here.  I have a feeling an inverse log amp will help.  Alternatively, you can sample the output (after inverting it once to make it positive), and use a lookup table if that gives you enough sensitivity in your range of interest







simulate this circuit &ndash; Schematic created using CircuitLab