Why this point in this schematic will begin at 2V at 0ms?
The solver in LTspice, unless special conditions apply, tries to calculate the operation point (OP) of the circuit prior to simulation, because the circuit is considered to have been running since the Big Bang and the simulation's t=0 means the start is somewhere down the road, which also means that the circuit had time to reach an OP, and that's what the solver tries to find.

If uic is explicitly set, that's a flag telling the solver that t=0 coincides with the creation of the Universe itself, and everything starts from zero. Note that this is different thatn specifying ic=X on a cap, for example, where that means the OP will still be calculated by the solver, but with a special, particular initial condition (IC) on that particular cap, only (or on any other element that uses ic). Setting uic disables any other particular ic.

I don't know how Cadence solves it, or if it has some additional setting, somewhere else, about solving for the op, but here's how LTspice shows the waveform when uic is set:



As you can see, it's nothing special, it just starts from zero and, eventually, it reaches the steady-state as seen in the previous answer.