How do dual RC filters interact?
With the 10k load resistor, the high-pass time constant is 10k * 10uF = 100 ms. The cutoff frequency is 1/ (100 ms * 2 * pi) = 1.6 Hz. Assuming the DAC output impedance is very low, the low-pass corner would be as you expect. ( 1 / (2 * pi * 47 us)).

The two filters will not interact very much because their corner frequencies are far apart. The DAC output impedance will shift the low-pass filter cutoff frequency downward.

In addition, the series resistance (RDAC and R902) combined with the 10k load impedance will act as a voltage divider in the passband of the high-pass filter. Assuming the series resistances are small, this should be a minor effect. But if you were to alter R902, or if you discover that the DAC output impedance is substantial, this could become significant. Also, if you reduce the 10k load impedance, then the effect could become more significant.

For this reason, if you wish to shift the highpass frequency upward, I suggest you do so by reducing C902.

I would also like to point out that if this circuit will drive an external amplifier, and you cannot control the input impedance of the amplifier, then you may find that the highpass frequency shifts, depending on which amplifier is connected. Hopefully that is OK.