Current Flow indicator using LED
You can try something like this. R9 should be a 1W or 2W resistor. D6 prevents surge current from damaging the resistor. There are 4 op-amps in each LM324 so you would need two of them (or 3 LM358s). The 7805 creates a reference voltage which is divided down to the transition voltages for each LED. 20uA through the divider chain so steps of 40mV, representing 400mA through the load. 

Connections to R9 need to be kept low resistance and arranged as shown (split at the bottom end close to the resistor), 







simulate this circuit &ndash; Schematic created using CircuitLab



Edit: added explanation: 

The op-amp comparators have outputs that go high (illuminating the respective LED) when the "+" input exceeds the "-" input. 

The 6-resistor divider chain starting with R12 and ending with R13 creates the 5 comparison voltages for the five comparators. the nominal voltages are 40mV/80mV/120mV/160mV/200mV. 

All the current through the pump goes through the sense resistor R9. That steals a bit of voltage from the pump motor- 200mV at 2A. R11 and C1 form a low pass filter to smooth the pump current sensing a bit, but don't affect the average voltage sensed by R9. So, as the current through the pump increases from 0, the LED D5 illuminates at about 400mA, D4 illuminates at about 800mA and so on up to 2A where D1 illuminates (the lower current LEDs are still illuminated so it's like a thermometer code).