negative voltage current limit circuit to control LDO enable
Here is one way.

To get an idea how this works, assume the betas are very large. When the current limit (of around 2mA) is reached, Q1 is held off from passing more current. Your current limit circuit then functions with R1 as the equivalent resistance.

With R1 being 100K, with more than 0.006mA above the current limit, >0.6V develops across R1 to turn on Q10. Q11 and D1 prevents LDO_EN from dropping below 0V. Q11 insulate Q10 from seeing V_PLUS, allowing Q10 to work under 32V.

The current limit 2mA is low. And the transistor betas are unfortunately not infinite, so you have to juggle the reistances and currents to get limits acceptable to you.