Back EMF of an inductor in a DC circuit?
Assuming the above circuit has been sitting for a while since the power supply was turned on and has reached steady state, then the current in the circuit will be the normal expected I=V/R. At steady state, inductors are basically just resistors. There will be no voltage drop or rise across L1 (assuming it is ideal and has no resistance) because the current is constant so di/dt=0. 

Inductors only act differently than resistors when the current though them is changing. If you start with PS at zero volts and ramp up to a final voltage, then di/dt will be non-zero during the ramp up period and the inductor will have a negative voltage across it resisting the current flow until it reaches steady state. 

Make sense?

Check out the resources listed at the end of this answer...

How is the current induced in this circuit?

...for lots of great references I think you'll enjoy!