Designing a circuit from a transfer function
Your transfer function can be obtained in different ways and one of them could be by cascading two stages with a buffer in-between. Your original expression follows the form

\$H(s)=H_0\frac{1+\frac{s}{\omega_{z1}}}{1+\frac{s}{\omega_{p1}}}\frac{1+\frac{s}{\omega_{z2}}}{1+\frac{s}{\omega_{p2}}}\$

If you design a first stage that introduces a pole-zero, you can already calculate the component values to get a first zero at 10 and a pole at 100. Then you buffer and drive another similar passive network this time loaded by resistor \$R_5\$. It will give you the required attenuation.







simulate this circuit &ndash; Schematic created using CircuitLab

If you apply the Fast Analytical Circuits Techniques (FACTs), you can show that poles and zeros are located as follows:

\$\omega_{p1}=\frac{1}{(R_1+R_2)C_1}\$
\$\omega_{z1}=\frac{1}{R_2C_1}\$
\$\omega_{p2}=\frac{1}{(R_4+R_5||R_3)C_2}\$
\$\omega_{z2}=\frac{1}{R_4C_2}\$
\$H_0=\frac{R_5}{R_3+R_5}\$

The component values for the 1st stage are easy to determine. For the second stage, you need to account for \$R_5\$ which also introduces attenuation but nothing insurmountable.

The FACTs are truly unbeatable in terms of execution speed to determine transfer functions of any kind (passive or active). Check out the following links to know more about them:

http://cbasso.pagesperso-orange.fr/Downloads/PPTs/Chris%20Basso%20APEC%20seminar%202016.pdf

and

http://cbasso.pagesperso-orange.fr/Downloads/Book/List%20of%20FACTs%20examples.pdf