Transfer Function of an Op-Amp Circuit
That's a differentiator. It has a zero at 0 Hz, so it has zero gain at DC, and its gain increases as a function of frequency. As drawn, that circuit will likely become unstable at some high frequency due to real world op-amp limitations.

I used my circuit simulation tool, Zero (not a coincidence!), to calculate your circuit's transfer function:



The input file used for Zero is (called with e.g. zero liso file.txt --save-figure tf.png):

c c1 2u n1 n2
op op1 OP00 gnd n2 n3
r r1 1M n2 n3

freq log 1 1M 1000
uinput n1
uoutput n3


Note that this transfer function will look different for a real-world op-amp, which has poles in its feedback. In this case, the phase starts to lag at high frequencies because the op-amp I modelled has a pole somewhere above 1 GHz. In reality, the transfer function will depend on the op-amp you use, but the low frequency response should be similar to that above. If you build this circuit, it would be a good idea to add a capacitor in parallel to the feedback resistor (1Mohm in your case) to help stabilise the feedback.