What is the equivalent capacitance when a capacitor is connected in parallel with a conducting wire?
The top half of your circuit does nothing because it's shorted in the middle.  The bottom half is 1 capacitor in parallel with a series connection of two groups of two capacitors in parallel.

Resulting capacitance = 1uF // ( 1uF//1uF + 1uF//1uF ) = 2uF

Your text is correct.