For superconducting inductors, does the "magnetic current" flowing in the ferrite of an inductor suffer from "magnetic resistance"?
The magnetic field is a vector field that forms loops, but there is no actual &quot;magnetic current&quot; — nothing that &quot;flows&quot; along those loops.
Yes, there is energy (work) associated with changing (increasing or decreasing) a magnetic field, but the only losses would stem from the electrical losses associated with secondary (&quot;eddy&quot;) currents in nearby non-superconductors.