Opposite of a transistor
A J110 N channel JFET will do what you ask. Source, drain and gate are connected as shown: -



Source is ground, drain is a load resistor connected up to (say) 5V. Gate is the control pin and should be taken negative to source(0V) to turn off the transistor.

The J110 JFET has a Vgs(cut-off) of somewhere between -0.5V and -4.0V. This means that if gate is at 0V the device has good conductivity between drain and source and will pass current through the load resistor. 

BUT if the gate is taken below the cut-off voltage the load current will fall to below 10nA (according to the Fairchild spec). J110 is just one JFET. It is closely related to J108 and J109 - these have different cut-off voltages to suit different applications.