LTspice output of a bjt amplifier is offsetted
Your "ampout" output is unterminated, so there's no place for any charge on C27 to go.  If you start with supply voltages = 0, then when the collector voltage of Q1 goes up (presumably to 4.55V), it'll take "ampout" with it.

You should figure that the voltage of "ampout" at startup without the supplies starting at zero will be at the whim of the tool, and in this case the tool's whim is to have it be 0V.  Be thankful it doesn't just give you an error.

If you want things to be sensible, put a sensible resistance to ground -- either whatever you believe the DC impedance to ground will be in the real circuit, or something high enough so that the pole formed by C27 and your resistor is well below any frequency of interest.