simple triac current limiter
Your electric fan speed regulator will have to be controlled by something, what will it be? Because I doubt the heater has something like that inside. Also, a gate resistor will only limit the command current but not the current through the device itself.

The way I see it, if you want to control the heating resistance's current (temperature) with a triac you'd have to resort to a dimmer-like circuit:



Do note, though, that you're dealing with \$ \frac{2kW}{230V_{RMS}} \approx 8.7A_{RMS} \$, which is quite a bit higher than your average light-bulb.

As for the heat-sink, it may well be the case. The dissipated power would be:

\$ P_d = V_{t0} I_{T_{AVG}} + R_d I_{T_{RMS}}^2 \$ 

With the catalog values and the previously calculated one:

\$ Pd = 0.85V \cdot 8.7A*\frac{2\sqrt{2}}{\pi} + 10m\Omega \cdot 8.7^2 = 7.41W  \$

\$ T_j = P_d R_{th_{j-a}}+T_a = 7.41W\cdot 50\frac{^\circ C}{W} + 25^\circ C = 395.5^\circ C &gt; T_{j_{MAX}}=125^\circ C \$

I assumed \$25^\circ C\$ ambient temperature, which means you'll need a heat-sink. After a quick math (involving some graphs), you'll need an \$ R_{th_{h-a}} \approx 13\frac{^\circ C}{W}\$ , which would be an aluminium square of 7.5cm (~3in) with a thickness of 1mm. Of course, conditions vary and this is an informative note, only. What thermal contact you're using, how you're mounting the heat-sink, etc, have an influence on the final result.