Shunt capacitance in applications not involving photo diodes
In general, assuming an inverting amplifier with an op-amp, and the network you show being in series with a zero-impedance voltage source (several assumptions), then you can simply use the same network as the feedback, with capacitance divided and resistance multiplied by the desired gain (invert the sign, of course). 

So if you want a gain of -10, you could use a feedback network of 10K in series with (10K  parallel with 100pF). 

Edit: This is what I mean.. if you run the simulation on the schematic, you'll see that the circuit has a gain (20dB) that is flat from 1Hz to over 100kHz, down about 3dB at a bit over 300kHz, which is about what you'd expect since that op-amp has a gain-bandwidth product of 3MHz, and the gain is (minus) 10. 

The impedance of the feedback network is 10 times the impedance of the input network at all frequencies.







simulate this circuit &ndash; Schematic created using CircuitLab