Matching network for complex source and load
Start by looking at the source resistive component and the load resistive component.

Source resistance: 1.626 kΩ
Load resistance: 122 kΩ
Impedance ratio: step-up 1:75

You can match source and load resistances with a step-up transformer having a ratio of \$\sqrt{75}\$.
Then, you need to counteract the -j3.5 MΩ complex part of the load. Because it's negative we know it's capacitive so, an appropriate value series inductor would do the job. It will have an impedance of 3.5 MΩ at 10 kHz. So, if that inductor were put on the primary side of the transformer, the required impedance drops by 75 to 46.67 kΩ. At 10 kHz, that's an inductance of 742.7 mH.
But, you already have some inductance in the source; +j2280 Ω is an inductance of 36.3 mH so, all you need to do is add 706.4 mH in series with the source and you'll get optimum power transfer from source to load at 10 kHz (via the transformer).
Of course the main tricky part is the transformer but you should be able to engineer this from ferrite cores providing the power transfer isn't too high. Try and simulate what I've described is my advice.