BJT reverse base-emitter voltage 1 Volts?
It does not mean that the transistor is bad.
It only means that the multimeter, using the way it uses to measure in the diode mode, is able to push enough current that voltage is 1.08V.
And you don't know unless you remove it from the other circuits for measuring.
When you try to measure the emitter-base Veb, there are two leakage paths.
One is obviously the total resistance of 1330 ohms directly between the B and E nodes.
The other is via the zener diode. As effectively 12V is at 0V when power is not applied, -1.08V at base means that the zener should not conduct much.
Basically, it would be far easier to just measure voltages when the circuit is powered.