Does an ideal wire dissipate energy?
If you accounted for the wires your circuit would look like the diagram below. It would have inductance from the magnetic field around the wire and resistance from the conductor.

The magnetic field effects are represented by the inductor and only apply if the current through the inductor is changing. Which in this circuit, once it is turned on the current is constant and the inductance does not matter. 

If you had an ideal wire with electromagnetic effects, you could nix the resistors and just model the inductance.







simulate this circuit &ndash; Schematic created using CircuitLab