Having trouble finding Vo, V1 and V2 in this circuit (not homework)
After step 6, your circuit will be as shown below.







simulate this circuit &ndash; Schematic created using CircuitLab

Which can be further reduced as a 16V battery in series with 3k and 5k resistors.

Now, you will have 10V across this 5k resistance, ie, 10V across each parallel 10k. Splitting 10k into 6k+4k, you will have 4V across 4k resistance. From the polarity of v1 marked, V1= -4V.