Common Collector Amplifier DC Analysis (why not get the VTH and RTH like in Thevenin's Theorem?)
The schematic is roughly this:



simulate this circuit &ndash; Schematic created using CircuitLab
This is the same as (using a Thevenin divider approach):



simulate this circuit
From this it is easy to work out (from KVL) that:
$$V_\text{TH}-I_B\cdot R_\text{TH}-V_{\text{BE}_1}-I_E\cdot R_\text{E}=0\:\text{V}$$
But also you know that \$I_E=\left(\beta+1\right)\cdot I_B\$ so it follows that:
$$V_\text{TH}-I_B\cdot R_\text{TH}-V_{\text{BE}_1}-\left(\beta+1\right)\cdot I_B\cdot R_\text{E}=0\:\text{V}$$
And therefore that:
$$I_B=\frac{V_\text{TH}-V_{\text{BE}_1}}{R_\text{TH}+\left(\beta+1\right)\cdot R_\text{E}}$$
This means that if \$\beta\ge 100\$ then \$I_b\le 63\:\mu\text{A}\$ and that \$V_B=V_\text{TH}-I_B\cdot R_\text{TH}\ge 8.36\:\text{V}\$.
(With \$\beta\ge 300\$ this works out to \$V_B\approx 9.06\:\text{V}\$.)
From there, you can work out the rest.