Find current of RL-C of AC circuit
Your \$Z\$, the parallel of the series \$RL\$ and \$C\$ (as you have done), is a complex number. I got \$(60.6+j68.7)\ \Omega\$ for it from my calculations.

Current \$I = \frac{V}{Z}\$ is:
$$I = \frac{230 V}{(60.6+j68.7)\ \Omega} = (1.658-j1.882)\ A$$

From the complex number in the rectangular form we can get to the polar form:
$$ \|I\| = \sqrt{\Re(I)^{2}+\Im(I)^{2}} = 2.5\ A$$
$$ \angle I = \text{atan}\frac{\Im(I)}{\Re(I)} = -48.62^\circ$$