Relationship between volts and Mechanical Energy
Well yes, energy is energy. The only problem is converting it from one form of energy to another form of energy.

And you cannot take a random battery with 10&nbsp;V. It has to have enough charge to be able to do the work.

So in a perfect world, you would build some magic mechanism, which would be able to lift something at 100&nbsp;% efficiency when you supply it with 10&nbsp;V. You want to lift 1&nbsp;kg up 1&nbsp;m, so you need approximately 10&nbsp;J.

How much charge would you need? Well 1&nbsp;C, but that's not a really useful measure you usually get with a battery. Most of the time you get something like amperehours or watthours. 1&nbsp;Ah is equal to 3600&nbsp;C (1&nbsp;A is 1&nbsp;C per second). So your battery would just need to have 1/3600&nbsp;Ah. Or 2.8&nbsp;mWh. This is so little energy - your phone could do this work surely 20000 times before running out of juice. 

But your phone is running on 3.6&nbsp;V - the voltage doesn't really matter (it will in a practical application), if you restate the equation, you will get J = V * C, so if you have less voltage you just need more charge to get the same energy.

Problem is, in reality you will have losses everywhere and you might get something like 80&nbsp;% efficiency (conversion losses, friction in the mechanic) or something and so you will need more energy to do the work.

Devices like this do exist - they are called elevators.