How to realize these transfer functions through op-amp circuit?
EDIT - there was a basic error in this answer - I missed the negative term in the numerator - the numerator I should have read is \$(1+sT_1)(1-sT_2)\$ but Alfred Centauri has come to the rescue with a two op-amp scheme that achieves this part - see his answer for the second term in the numerator and my answer for the remainder.

The transfer function you have is this: -

H = \$\dfrac{(1+sT_1)(1+sT_2)}{as^2+bs+c}\$ (apart from the error as mentioned above)

And this can be realized with a cascade of three op-amp circuits. The denominator has the form of a 2nd order low pass filter and using a sallen key topology this can be realized: -



This stage covers the denominator and also introduces an element in the numerator, \$\omega_0^2\$ and this is a constant. To produce 1+s\$T_n\$ requires a differentiator circuit similar to this: -



If R1 and R2 are equal this becomes \$1+sR_2\$

Two of these circuits need to be cascaded to get the full numerator. These are then cascaded with the sallen key stage (above) and the transfer function will be: -

H = \$\dfrac{\omega_0^2(1+sCR_a)(1+sCR_b)}{s^2+s2\zeta\omega_0+\omega_0^2}\$

I think this is near enough to the original transfer function to show how it might be implemented in an analogue circuit using op-amps. Don't forget to look at Alfred's answer for the erroneous term I included.