How to separate pin when I connect USB?
Welcome, Sava.
You've correctly implemented Option 1 in your schematic. As long as you are using an internal supply within the range of 1.7 to 3.6 VDC, VDD_HV and VDD are connected together, and fed with your internal power supply.
You also have VBUS correctly connected to the USB receptacle VBUS pin.
Option 2 is for internal power supplies, or USB power sources, in the 5 V range (3.6 to 5.5 VDC). In this mode, you would feed VDD_HV and leave VDD unconnected.
There is no mode where VDD_HV is left floating.
Edit: Here is the table 14 in the latest version of the datasheet (see link in OP):

The &quot;Yes&quot; and &quot;No&quot; indicates which pin (Vdd or Vdd_hv) is the primary power feed pin. I believe the &quot;Note 1&quot; footnote should have been included in column 3, just as in column 1, to indicate you tie VDD and VDD_HV together and feed them from your 3.3 V supply.
If you still are concerned -- and good for you, for not believing everything you hear on the Internet -- you should contact the manufacturer's support team for confirmation of your design.