Superposition of energy
No.

Couple of things:

Superposition applies to currents and voltages, and you must actually calculate the sum of these to calculate power: for example, in this very simple circuit, 0 A flow through the resistor, and hence 0 W is dissipated. If you switch on only either current source, 1 W will be dissipated. But the sum of these two powers (2 W) is not 0 W.

Logically, superposition applies because a system is linear. Power, however, is not a linear property of these networks: it's calculated on the square of current or voltage, and hence, voltage and current "superpositionability" doesn't apply to power – in fact, it even implies that power can't be superpositioned directly.







simulate this circuit &ndash; Schematic created using CircuitLab