How does the current flow in purely inductive circuit?
If the value of resistance tends to zero, the induced emf becomes
  equal and opposite to applied emf resulting in no net current.


No, not remotely so.  You're caught in the trap of thinking that an equal and opposite induced emf to the applied emf implies zero current but that does not logically follow.

What's required here is clarity of thought.

Carefully consider the consequences of the following conditions for an ideal inductor:


there is an emf, proportional to the rate of change of current
through, that tends to oppose the change in current
there is an applied voltage that is precisely opposite the emf


Logically, if the above hold (which they must for an ideal inductor), the rate of change of current through the inductor is proportional to the applied voltage across.

If the voltage across an ideal inductor is a constant, non-zero value, it is illogical to conclude that the current is zero.  The logical conclusion is that the rate of change of current is constant.

If the inductor current were constantly zero, the induced emf would be zero but that would be inconsistent with a non-zero applied voltage since it would imply 'infinite' current for an inductor with vanishing resistance.

Put another way, if the current is to be finite for a non-zero applied voltage across, there must be an emf precisely opposite the applied voltage and that implies a non-zero rate of change of current.