MC34063 Current Mode
Make R1 a pull-down. Instead of connecting Q1-c to M1 and Q1-e to ground, connect Q1-c to Vin and Q1-e to M1-gate with R1 pull-down to ground. Make R1 ~ 30 \$\Omega\$ (maybe 100mA will be enough to turn off FET fast enough). Connect M1 source to ground and M1 drain to L1 and D1 anode. (Note: This approach of using R1 as a pull-down assumes that Q1 is the Q1 internal to the MC34063. This seemed to be the intent of the OP. If there is an additional or external BJT, the Vbe drop from Vin would be too great and FET would likely not turn on.)

MC34063 normally operates in DCM since it is a hysteretic controller, and these types of controllers are more stable with DCM. (Note that boosts in CCM can have very high Q power modulator response that can ring with hysteretic control.) 

Boosts operate kind of like a bucket brigade, switch turns on charging inductor with energy, switch turns off - inductor dumps energy through diode to output. Fill then dump, fill then dump ... repeat. Hence boosts always output pulsed current through D1, and rely on the output capacitance to smooth out the output.

If you are operating at a switching frequency of 33kHz, make L1 ~ 10uH for DCM (needs to be less than 11uH). Of course, peak inductor current will be about 3A. Find a 3A Schottky for D1.