Output related to input in diode circuit
Well, I’m assuming those are ideal diodes, right? Start by simplifying your thoughts. D2 in series with 10V is the same as a diode conducting only above 10V, let’s call it D2’. So, before D2’ reaches 10V this is a non-conductive path. This means you can ignore the third 10K resistor since it doesn’t have current. The first two resistors act as a voltage divider, so D2’ will conduct only when the input voltage is 20V, which gives 10V over D2’, are you following? After 20V, D2’ starts conducting and the third resistor cannot be ignored anymore. But this part is easy too. Since D2’ is now conducting, any further raise in the input voltage is now clamped on D2’ and it stays at 10V.