Response of a first-order filter to a step input
Equivalence from time to freq. domain for 1st order filter.

Half Power (f) or 50% of V^2/R occurs thus for V,
 Vout(f)=0.707 of Vin(f) , where 0.707=1/root(2)

for the exponential time decay towards target step (1-1/e)=~63% input

\$   (1-1/e) * V_{step}=0.63 * V_{step}  \$

This is equivalent to exponential V(f) at \$ \omega=\dfrac{1}{T}~where ~t=T= RC , \omega=2\pi f\$

So you are correct.  OA's must be RRO types to go to 0V out or bipolar supply and have GBW much greater than f-3dB.  (lookup if the abbreviation is foreign)