Integrator with Voltage on IN+ and measuring Vout and V-?
Following the superposition theorem you can calculate Vout (node 2) as a result of Vn1 (node 1) and V1=1V:

Vout=V1 + (V1-Vn1)/s*R1C3

For V1=0 this simplifies to the well-known MILLER integrator formula
Vout=-Vn1/S*R1C3.