Measuring input and output resistance of the hybrid model
No, you have a dependent source here (CCCS). So, you cannot turn it OFF, as we usually do with the "normal" (independent) current sources.

And \$R_{OUT} = R_C\$ is only true because when we are trying to find the output resistance we are setting/forcing the \$V_{IN}\$ to \$0V\$, hence no base current will flow due to input signal. And because your small-signal model do not contain \$h_{22} = h_{OE} = 1/ro\$. The dependent current source will be OFF in this case.    

But if we add \$h_{22} = h_{OE}\$ the siutiation will be defrent.  

See the example here: 

BJT common-base output resistance derivation

Calculation of output impedance of CE emitter bias configuration( unbypassed) with r_0

I/O Resistance of common source MOSFET with source degeneration