Series capacitor equivalence
Capacitors associations

Series association

This association gives a lower total capacity than any of its component capacitors. The total capacity, for \$n\$ capacitors is

$$
C_{eq} = \dfrac{1}{\sum\limits_{n}\dfrac{1}{C_n}}
$$

Parallel association

This association gives a greater total capacity than any of its component capacitors. The total capacity, for \$n\$ capacitors is

$$
C_{eq} = \sum\limits_nC_n
$$

So, for your question, the answer is yes. You must connect 10 capacitors of 1\$\mu\$F in series.