Trouble understanding thevenin's model from AoE Lab
You're close. I'm not sure how the AoE book approaches things, but I'd say you're introducing the load resistor too early. The point of using a Thévenin equivalent circuit is to obtain a model for the (sub)circuit in question, and then put a load on there and see how the circuit behaves.

In your case we have the following simple circuit (note that, for the time being, I will ignore the exact numerical values of the resistances and just focus on the general solution).







simulate this circuit &ndash; Schematic created using CircuitLab

I'm calling the output node "out" instead of "Vout" because we will be worrying about both its voltage and its current.

As you correctly point out, to determine the open-circuit voltage \$V_{oc}\$, we leave the output node open-circuit (infinite impedance to ground) and calculate the voltage at the node "out", which in this case is a simple voltage divider:

$$
V_{oc} = V_s \cdot {R2 \over R1 + R2}
$$

In calculating the short-circuit current \$I_{sc}\$, we short this output node to ground (zero impedance to ground). Since the output node is at ground potential, there is zero volts across R2 and therefore no current flows through it.

$$
I_{sc} = {V_s \over R1}
$$

Note that your approach above had an error, since you were using \$V_{oc}\$ instead of \$V_s\$ in this calculation.

As a side note, we can alternatively view the above two circuit setups in terms of parallel resistors. (Remember that, if you have two resistors in parallel, then the resultant resistance is always less than or equal to the smaller of the two resistances.)


In the \$V_{oc}\$ calculation, the low-side resistance is R2 in parallel with an infinitely high resistor, which is equal to R2.
In the \$I_{sc}\$ calculation, the low-side resistance is R2 in parallel with zero ohms, which is equal to zero.


Finally, to get the Thévenin resistance \$R_{th}\$, we can just divide the open-circuit voltage by the short-circuit current:

$$
R_{th} = {V_{oc} \over I_{sc}} = {V_s \cdot {R2 \over R1 + R2} \over {V_s \over R1}} = {R1 \cdot R2 \over R1 + R2} = {R1 \parallel R2}
$$