question about resistors in a schematic
No, you are not right. AC5 is a pin of the chip. You have to place a 27 Ohms resistor near to that pin and connect the actual external circuitry to that resistor (on the diagram, this is called the AC5-Load). 

AC5 and AC5-Load are different things: AC5 is the pin, AC5-Load is the circuitry that should be connected to that pin (apart from the resistor, which is for Synchronous 245 mode).