How can I generate a 13GHz sinosoidal wave with a multipilier circuit?
by using a 100MHz OCXO and a multiplier circuit with a multiplier factor of 100 we can obtain a 10Ghz with low phase noise.

You would have to have an ultra-ultra-low noise 100 MHz signal to get &quot;low phasenoise&quot; at 10 GHz after multiplication. Also, your frequency multiplier circuit would need to be very good so that it doesn't add noise.
Realize that every time that you double a frequency with an ideal frequency multiplier (one that adds zero noise), your phasenoise will degrade by 6 dB.
So if I multiply a:
100 MHz, PN = -80 dBc @ 10 kHz signal
with an ideal 2x multiplier I get:
200 MHz, PN = -74 dBc @ 10 kHz signal
This is the reverse of dividing a frequency down, here's an article explaining that.
Note that this a theoretical limit so there's no way around that, in real life, things are always worse.
This is only multiplication by 2, for a multiplication factor of 130 the phasenoise degradation would be 42 dB. If that gives you &quot;low phasenoise&quot; depends on your needs.
Note that nearly all (integrated in an IC) transceivers work like you describe. A &quot;low frequency&quot; (20 MHz to 100 MHz) crystal oscillator is used to generate a reference frequency clock. Then a PLL is used to multiply that clock up to the value that is needed.
The phasenoise will then degrade as mentioned above. However, as long as the phasenoise is good enough that is not an issue.