Capacitor behavior on collector of a BJT?
Despite what the other answers suggest, this is not an oscillator !

Edit: it appears the schematic was more complex before and then it was or contained an oscillator.

Note how C1 and R2 are just in parallel with R1, which is the collector resistor.

A long time after you switch on this circuit (apply 9 V supply) the capacitor will be charged to whatever the voltage difference V1 - V2 is so you can consider C1 not to be there.

V1 is then easy, as it connects only through R2 to 9V, V1 = 9V

For V2 you have to calculate the current through R1. This is more complex as this current depends on the values of R1 and R3 and the mode of operation of TR1 (in saturation or out of saturation).

The easiest is to assume that TR1 is not in saturation, then Ic/Ib = beta. Assume Vbe of TR1 to be about 0.7 V then V(R3) = 9 - 0.7 = 6.3 V.
Now Ib can be determined, multiply by beta and you have Ic. Then calculate V(R1) = Ic * R1 Now you can calculate V2. Now also check that V2 has a realistic value, if V2 is between 0.5 - 9 V then TR1 can operate out of saturation. If V2 is lower than the VCE of TR1 will be low and it will be forced into saturation. Then you will have to make a solution for the saturation case. But then VCE must be given.