Is electric power equal to its radiant flux?
It says that the power consume by the light source is equal to the light power emitted


That's probably not a true statement: at best it's intuitively misleading.

By the law of conservation of energy we know that all the electrical power consumed must go somewhere, but it doesn't need to go into light. Certainly not all of it goes into visible light: the LED also gets hot. There are other kinds of non-visible light that might be radiated: infrared light from the heat, and RF light from variations in the current in the device.

In practice the LED is probably in air, and is attached to wires. Some of the thermal energy is lost to the air by convection, and the wires by conduction. In practice this is where most of the energy that wasn't radiated as visible light will go.


  Is electric power equal to radiant flux?


Both of these things are measured in watts, so it's possible for a device that emits light and nothing else. But since there's convective and conductive cooling taking energy out of the system by a mechanism that isn't light, we can deduce there will always be some degree of discrepancy between input electric power (current times voltage), and output radiant flux (power of photons leaving the LED).