How can this logic be formed by using the Karnaugh map?
There is a way to simplify further if you're allowed to use other logic gates than OR and AND.
"Diagonal" ones like in the first 4 cells indicate, that some XOR logic gates can be applied. Since KV-Diagrams are toruses the diagram can be rewiritten as follows:

┌──────┬────┬────┬────┬────┐
│ A/BC │ 01 │ 00 │ 10 │ 11 │
├──────┼────┼────┼────┼────┤
│    0 │  0 │  1 │  0 │  0 │
│    1 │  1 │  0 │  1 │  0 │
└──────┴────┴────┴────┴────┘


This reveleals another diagnonal structure, so we can begin to group them together. The first and the second colums are 1, when A and C are equal. This means a XNOR connection: $$\bar{ (A \oplus C) }\land\bar{B}$$
Same goes for the second and third row but with A and B:
 $$\bar{ (A \oplus B) } \land\bar{C}$$
So the whole expressions boils down to:
 $$(\bar{ (A \oplus C) } \land\bar{B}) \lor (\bar{ (A \oplus B) }\land\bar{C})$$

Two XNOR gates, Two AND gates and one OR gate.