Output voltage when turned off
The opamp output you are seeing is normal.  

If we examine the circuit, starting with the opamp non-inverting input. We assume the input is infinite impedance so we first work out what voltage it's seeing:

We work out the bottom of the divider:  

((R139 + R141) || R142)) = 1/(1/269.9 + 1/1000) = 212.54 ohms.

The top of the divider is R327 1k, so the voltage at the centre is:

3.3V * (212.54 / (1000 + 212.54)) = 0.578V

So the non-inverting input sees 578mV.

Now we look at the inverting side. We know that if the non-inverting input is 578mV, the inverting side must be at 578mV too. We also know that if the DAC outputs are off, then effectively the input is 0V, and the input resistance is R140 + R137.  

So the input resistance is 269.9 ohms, and the feedback resistance (R326 || R136) is 1k || 1k = 500 ohms.
We assume the inverting input has infinite resistance, so we are left with a voltage divider.
With 0V at one side of the voltage divider, 578mV in the middle, the top side should be 0.578 * (269.9 / (500 + 269.9)) = 1.65V, which is what you are seeing.