Designing a boost converter
A boost converter works by storing energy and releasing it thousands of times per second. It stores energy in an inductor and this energy gets released into the load.

The amount of energy stored is proportional to the square of the current accumulated in the inductor over the 1st half of the switching cycle. So let's say you are operating at 50% duty cycle and you are storing 100 uJ. Let's also say your switching frequency is 100 kHz. From those two bits of information you can calculate power into the load because power = joules per second hence power is 10 watts.

If your load doesn't exactly take 10 watts then the output voltage will get bigger or get smaller until your output load does take 10 watts. 

This is why a boost regulator needs a pretty good feedback control mechanism to cope with: -


Output load changes
Input voltage changes
Temperature related changes


In your circuit I see none of these things yet you have specifically said you want to double the voltage from input to output. How much of a discrepency can you therefore live with? You need to think about this and decide whether or not you are going to implement a closed loop controller to turn a thing that pushes out constant power to a thing that pushes out constant voltage.