Power loss from an inductive load
Pure inductors don't dissipate power.  However, look at the problem statement carefully.  Note the 1/sqrt(2) power factor, meaning 45&deg;.  A pure inductance would be 90&deg; and a power factor of 0.  This load therefore has both a resistive and inductive component.  The overal load is drawing 5 MW, which of course is all going into the resistive part of the load.

The term "inductive load" was used only to point out that the load has a significant inductive component.  Giving the specific power factor then provides all the details.

Added:

In electric power engineering, the term reactive power is often used for the voltage times the current drawn by the inductive component of the load.  Since the voltage and current of the reactive power are always 90&deg; out of phase, no actual power is transferred.  For utilities, thinking of any load demand as a combination of real and reactive powers is a useful abstraction since the two are often dealt with sepearately.  For example, a bank of capacitors is a reactive power generator.