Clock conversion from 3.3v CMOS to 2.5v
When you say you need to "level shift" the clock line, do you just mean its one more line to convert between 3.3 V logic and 2.5 V logic? Or do you mean you need this line to have non-standard levels at the output (like V_hi = 2.5 V, V_low = 1.25 V or something)?

If you just need to convert to 2.5 V CMOS levels, almost any discrete logic technology that does 2.5 V ought to be able to handle 10 MHz clocks with no problem. For example, the SN74AVCBH164245 you mentioned specifies a maximum propagation delay of 3.7 ns when translating from 3.3 V (on the "A" side) to 2.5 V (on the "B" side). This is less than 5% of your 100 ns clock period. 

As Gustavo pointed out in the comments, you also need to look at the rise and fall time of your signals. You need to work this out from the drive current available from your translating buffer (about 8 mA for the '164245 at 2.5 V) and the capacitance it's loaded with. You can roughly estimate

\$ t_{\mathrm{edge}} = \dfrac{\Delta{}V}{CI} \$

In this case you can have a load up to about 16 pF, and still be able to drive it over 2.5 V swing in about 5 ns, again much lower than your clock period.

As an aside, for one-way conversion from high voltage to low voltage, which it seems like you're doing with your clock, you can also look into using a 2.5 V buffer with "3.3-V-tolerant" inputs, for example SN74LVC1G34. This will be a slightly simpler and so probably a lower-cost solution.