Movement of Electricity in a Simple Circuit: A Few Simple Questions and a Diagram
This question is about steady-state dc analysis, and my answer applies to the steady state condition.


  Is this even true? why wouldn't some of the electrons from the battery on the right still try to flow to the battery on the left? (this kind of relates to question 3).


The battery on the right is not part of a complete circuit. Therefore no current will flow through it. To form a complete circuit there must be a path for current to flow from the + terminal back to the - terminal. 


  Also suppose that the cable extending from the negative terminal (the anode) of the battery on the left was many times longer than the length of the cable extending from anode of the battery on the right, in such a case would electricity be transferred from the anode of the battery on the right to the positive terminal (cathode) of the battery on the left? In other words do the electrons take the path of least resistance?


The battery on the right is still not part of a complete circuit, so no current will flow through it.


  Pardon the analogy that follows; would a sort of traffic jam be created where the blue and the red cable connect? I mean once the electron from one battery started flowing to the cathode, would they impede other electrons from joining the flow?


Without a complete circuit through the battery on the right, it doesn't matter.

Even if both batteries were connected in parallel, the connection of two wires would not cause a traffic jam and impede the flow of current.

However, the light bulb acts as a resistor. As such, if you apply a given voltage (12 V, say), it will only draw current according to its resistance. If the voltage is applied by two batteries in parallel, part of that current will come from one battery and part from another, so that Ohm's law is satisfied for the resistor (light bulb). In this way, you might consider the light bulb to be causing a kind of traffic jam, in that it resists the flow of current.