Voltage divider problem
You have forgotten that you are no longer dividing to ground. You are dividing to 1.65 V.

\$ V_O = \frac {(V_I - 1.65)}{10} + 1.65 \$.

At \$ V_I = 10~V \$ you get \$ V_O = \frac {(10 - 1.65)}{10} + 1.65 = 2.485~V \$.

For a simple (in)sanity check think what happens when \$ V_I = 1.65~V \$ and then when \$ V_I = 0~V \$.