How to calculate voltage and current of a circuit with input / output MCU pins
The current into or out of the enable pin will be determined by the design of the LDO, so you need to examine the datasheet for the LDO. 

Once you know the voltage-current characteristic (and some things about the MCU- see below) you can calculate the current and voltage for any given situation. I would say there are four possibilities for the enable pin given the switch may be pressed or not, and the MCU output may be high or not. 

The input pin would not normally figure into this, but I would divine from this particular circuit that the MCU may be switching its own power, so there may be a case where significant current will flow into input pin (likely briefly as the LDO and MCU power up). For this circuit to be useful it would also probably have an internal (or not-shown external) pull-down resistor on the MCU input- probably enabled by firmware. Perhaps 50K or something like that. Realize that this is totally an educated guess on my part and what actually happens will depend on things not shown in your schematic. 

The capacitors are across fixed supplies so ideally they conduct no current except when the power comes on. If you look a bit closer, they will conduct current depending on the (not shown) loads during normal operation since the source voltage and the LDO will have some non-zero output impedance that varies with frequency.