How charge moves through a diode during the reverse recovery time?
So, you reverse the bias and the battery begins pulling electrons out of the N type silicon and holes out of the P-type silicon *, eventually the area around the junction becomes charged up like a capacitor and the current stops flowing.

(*) you could picture this as filling the holes with electrons, but either way  because of the electric field of the battery the holes move to the metal, and then accepting an electron from the metal, they disappear.