I can't figure out this circuit. How do I obtain the three currents?
Thanks everyone for helping me figure it out! \$i_2\$ has to be 0 because it has no loop to go through.

So I solved the left hand side and right hand side separately and I got these results:

\$V_{\Delta} = \dfrac{10}{10 + 2} \times 24 = 20 V\$ (voltage divider)

So the current source is \$0.8 \times V_{\Delta} = 16 A\$

Then I used a current divider to get \$i_1\$ and \$i_0\$.

\$i_1 = \dfrac{5}{20 + 5} \times ( -16 ) = -3.2 A\$

\$i_0 = \dfrac{20}{20 + 5} \times ( -16 ) = -12.8 A\$

I think this is the correct way to do it?