Need help determining smoothing capacitor(s) for rectifier
using Q = C *V, take the derivative with respect to Time, and get

dQ/dT = C * dV/dT + dC/dT * V

Now define dV/dT to be zero (the capacitance is constant), and we have the useful ripple prediction formula

dQ/dT = C *dV/dT

Now define dQ/dT to be the current (I) and we have

I= C * dV/dT

So what? Let I = 1 ampere, dV = 1 volt, dT = 1/(2*50Hertz) = 0.01 second

What must the smoothing capacitor be?

1 amp = C_farads * 1 / 0.01

and we have

1= C* 100,

or

C= 1/100 or 10,000uF

=========================================================

Example with ONE UF and 1 AMPERE load:







simulate this circuit &ndash; Schematic created using CircuitLab