Does using a resistor in series on a breadboard track work as expected?
Yes. Essentially you have a 0.0Ω* resistor (The Breadboard wire trace) parallel a 10k resistor. Therefore the equivalent resistance will be 0.0Ω.

(Non-Zero, insignificantly small resistance that can be assumed to be Zero Ohms for this illustrative purpose)



$$R_{eq} = \frac{1}{\frac{1}{R1}+\frac{1}{R2}} = \frac{R1*R2}{R1+R2} = 0 $$