Help Me simplify: C*(A+B) + ~A*B
I will not give you the full solution, but the required non-trivial sidestep. You have got this far:

C(A + B) + A'B = AC + BC + A'B =


Now here is the sidestep. We know that (A+A') is 1, so we can do:

 = AC + (A + A')BC + A'B 


From here you will need to expand it and use the "OR absorption law" twice.