Transfer function for Small signal model of inductor series peaking
Assuming no external load at Vo, you need to calculate the impedance seen by the current source. It's the parallel combination of C and (R in series with L): -

Z = \$\dfrac{\frac{R+sL}{sC}}{R+sL+\frac{1}{sC}}\$

Multiply through by sC to get: -

\$\dfrac{R+sL}{1+sCR+s^2LC}\$

So, your current source x the impedance above produces a voltage across C (Vc). To find Vo you have a potential divider problem: -

Vo = Vc\$\dfrac{R}{R+sL}\$

So, 

\$I_{in}\times \dfrac{R+sL}{1+sCR+s^2LC}\times \dfrac{R}{R+sL} = V_o\$

So,

\$\dfrac{V_0}{I_{in}}=\dfrac{R}{1+sCR+s^2LC}\$


  Any help would be appreciated


I see little sign of that!