For sensing continuous Voltage and deamplifier circuit?
simulate this circuit &ndash; Schematic created using CircuitLab

Figure 1. Redrawn circuit split into three sections.

Redrawing the circuit can often clarify what is going on. In your case you have three sections:


A potential divider consisting of R3 and R4. The "gain" of this stage is \$ \frac {R4}{R3+R4} = \frac {220k}{1220k} = 0.18\$.
A non inverting op-amp with gain given by \$ (1 + \frac {R1}{R2}) = (1 + \frac {220k}{1000k}) = 1.22\$.
Another potential divider with "gain" of \$ \frac {R5}{R5+R6} = \frac {10k}{20k} = 0.5\$.


The "gain" of the whole circuit is the product of all three gains.

$$ G = 0.18 \times 1.22 \times 0.5 = 0.1098$$