What will be mode of operation for BJT in figure?
the BJT will be in saturation, it might over-heat and burn in practice. Also this circuit will definitely not be amplifying anything as its in saturation and proper coupling doesnt exist b/w microphone and BJT.
The reason should be obvious, the Vbe on = .7V and Ic=Is*e^(-Vbe/Vt)$ where Vt=26mV. Thus Ic rises exponentially with increase in Vbe and results in saturation of the BJT.