How do you model a "leaky inductor"?
You would expect a perfect capacitor to store charge when it's open circuited. A leaky capacitor has a large value resistor across its terminals to draw a small current, driven by its terminal voltage. This current reduces the charge stored on the capacitor.

You would expect a perfect inductor to maintain flux when it's short-circuited. A leaky (we usually say 'lossy') inductor has a small value resistor in series to generate a small voltage from this circulating current. This voltage ramps the current down, and with it, the flux.

'Leakage' flux is something else, and is only relevant for transformers. All cored inductors have some flux outside the core. In the case of a simple inductor, this does not represent an energy loss term per se, but merely makes it more difficult to compute accurately the inductance from the geometry. In the case of a transformer, it looks like a small series inductance, still not lossy, in series with the transformer. If the leakage flux couples to something lossy, like a steel fixing bracket, then that creates an energy loss by transformer action when the current and flux changes.