Help With Resistor Type?
So, that's clearly an inductor (see the labeling "L1"). Probably a Bourns 78F470J.

The hard part really is


  where can I purchase a ton of this


because, well, I don't know why you need a certain mass of this, but considering the weight according to mouser is 185 mg, and 1 ton = 1 Mg, you'll need 5,405,406 of these.

That's a real problem right there. Even the largest known inventory (according to octopart.com) doesn't come close to that number (more like 70,000-ish); combining all sources together, you might not even hit one tenth of that. Also, your purchase would probably instantly increase the price for wirewound axial inductors.

So, you probably have to live with the 6 weeks lead time of Bourns, at the very least. Good news is that you can probably just call them right now and place the order. At this quantity for this class of device, they will certainly have an open ear for your customer needs.

I really don't know the distributor markup on these, but it's realistic they'll demand no less than $0.03 apiece, so that your order would have a volume of around 162 k$.

A bit of interesting knowledge: The maximum specified DC current through this inductor is 205 mA. The energy stored in a magnetic field is 
$$E=\frac12 LI^2\text,$$
leading to a total maximum energy stored in your ton of inductors of
\begin{align}
E_{tot}&amp;=N\cdot\frac12 LI^2\\
&amp;=\left\lceil\frac{1\,\text{Mg}}{185\,\text{mg}} \right\rceil\cdot \frac12 47\,\mathrm\mu\text{H}\,\left(205\,\text{mA}\right)^2\\
&amp;\approx 5.4\cdot 10^6\,\cdot\, 2.4\cdot10^{-6} \,\text{kg}\,\text{m}^2\,\text{s}^{−2}\,\text{A}^{−2}\,\cdot \,4.2\cdot10^{-3}\,\text{A}^2\\
&amp;=5.4\cdot2.4\cdot4.2\cdot10^{-3}\,\text{N·m}\\
&amp;\approx 54 \,\text{J.}
\end{align}

That is, disappointingly, the energy that it takes to trigger your xenon camera flash (not your smartphone's "flash" LED, a proper flash) five times.