What is this equipment called?
The unit is a motor driven by a gearbox.
 A driven motor is a genertor or alternetor (subject to cetain conditions), which is the point he is making.

The motor speed is increased by gearbox action so the voltage produced is greater than without the gearbox as Vout is ~ proportional to speed.

Re torques - it's a gearbox with a motor on the end.
Standard gearbox dynamics apply.
The force on the higher speed end -  actually the torque, which is rotational force, will be LOWER at higher speed. 

Power = k x torque x RPM. So   

RPM_In x Torque_In x efficiency  = RPM_Out x Torque_Out  or

Torque_Out = RPM_In / RPM_Out x Torque_In x efficiency