How is the Collector-Base region reverse biased in Common Collector configuration of BJT?
You are right; the diagram is wrong. With the polarity of VBB as shown, both junctions are forward biased &mdash; the BC junction by VBB alone, and the BE junction by the sum of VBB and VEE. There is no "transistor action"; they're just wasting power as heat. Redrawing the schematic to show the relative voltages makes this a little clearer:







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For the transistor to be in active mode, the sign of VBB would have to be reversed. Note that this means that current would be flowing "backward" through the VBB supply. If it really is a battery, it would be getting charged by the VEE supply.

Normally, you would draw the common-collector circuit with the collector as being the most positive point in the circuit:







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