Total current at the load?
At the cathode of D1 relative to ground (the bottom line on your diagram) there is +30V. V2 and V3 are equal and in parallel and subtract 10V from the 30V leaving 20 volts relative to ground i.e. the load sees 20 volts and diode D1 does not conduct.

If the induced voltage was produced by an alternating field it will change direction after some time and the diode will become forward biased and may indeed destroy itself with that current.