Finding the voltage and charge across capacitor
It is a simple series/parallel circuit, V1 does nothing if \$V_{D}\$ is ideal, \$C_{1}\$ can be ignored. 

\$C_{X}\$ parallel \$C_{2}=C_{n}=C_{X}+C_{2}\$

\$C_{N}\$ series \$C_{l} = (C_{N} *C_{l})/(C_{N} +C_{L})=C_{tot}\$

\$Q_{tot}=C*U=C_{tot} *V_{d}\$

\$V_{l}=C_{N}/C_{tot} *V_{d}\$

\$V_{N}=C_{L}/C_{tot} *V_{D}\$

Rest:  

\$Q=C*U\$