Circuit that would meet this requirement
Check the numbers in your last formula and Math.  Multiply by 1e12 to get pF.

$$L = 100\mu H$$

$$X_L = 6.28*526.5*10^3Hz*100*10^{-6}H = 330.642 \Omega = X_C $$

$$ C = \frac{1}{6.28*f*Xc} = \frac{1}{6.28*526.5*10^3Hz*330.642 \Omega} = 913.8pF $$

$$ X_L = 6.28*1606.5*10^3Hz*100*10^{-6}H = 1,009.4 \Omega = X_C$$

$$ C = \frac{1}{6.28*f*Xc} = \frac{1}{6.28*1606.5*10^3Hz* \mathbf {1,009.4 \Omega}} = 98.1pF $$

Range of C: 98.1pF to 913.8pF.

\$X_C\$ is inversely proportional to C and f.  As \$X_C\$ and f increases, C must get smaller.