Current consumption calculation + Full wave Bridge rectifier
TL:DR Answer

Since the cap is across source Vac and not Vdc out, it is a rectified DC Voltage but no storage so the voltage is just a rectified sine but the current is not rectified as shown.  (Looks like an drawing error)

We expect Ipk ~ 320V/50k= 6.x mA  (Peak current)

Yes, you include Cap impedance, Zc=-j /2pifC =-j318 -j31.8 kOhms shunting the 2nd term in the denominator, resulting in a phasor current.  

With Vpk(AC)/Vf (diode) ratio being so small, you can neglect this, which only causes a small apparent crossover distortion of +/-1.2V in the current.

You can compute Thevenin equivalent voltage and source Zs’  (at Bridge then ignore it) for the AC analysis, then load current is V’/100k+(V’-Vzt)/100k for some threshold voltage Vzk since it is drawing a few mA where the ZK Zener Knee Voltage is rated in the datasheet.

How to do step 1? Like any serial-shunt divider, except use Zc=-j /2pifC



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Don't forget to add 0V symbol to DC output (-)=GND as I did.... to indicate V' properly

Simulation



Gnd symbol=0V and is not earth GND which is connected to Neutral at source.