Determine the number of bits before receiver misses a bit
The minimum sampling time to get the whole message is \$ 1/100 \$ or 10mS. Since the sampling time is 10.7ms a bit will be missed as soon as the samples line up at the end of bit 1 and the beginning of bit 3. The best scenario is when a sample lads at the beginning of a bit. Every following sample is then off set by 0.7ms until the sample strattles a bit. This would happen when the accumulated offset exeeds the sample time \$ 10/0.7 \$ or 14.28. This implies that the 15th bit will be missed.