Resistors in paralel on pcb schematics?
This circuit (in the black circle) causes a pulse on the pin connected to it. If the capacitor is empty it starts filling through the resistor. As the capacitor fills with charge, the current through the resistor slowly falls, and the voltage on the pin also falls. Once the capacitor is full no more current will flow an there will be "0V" on the pin.

I would also regard this as a bad design practice.

EDIT:

As the +5V supply voltage collapse to zero, the 10uF capacitor will attempt to discharge through the 10k resistor and whatever parasitic components are forming the input pin. The faster the +5V supply voltage collapses, the faster the capacitor will have to be discharged, which would cause the stress on the said parasitic components inside the integrated circuit to increase. If the stress is big enough the circuit will fail.

All of the above holds for a typical pin topology, we do not actually know how much negative voltage or current can this pin tolerate until we see the datasheet of the integrated circuit.

EDIT 1: Datasheet