How do microsequencers in CPUs parse data from RAM in the control unit/control store before determining what to do with the bits/voltages?
To answer your question about how the CPU turns RAM signals into circuit-level operations:
TL;DR
Logic gates.
Full answer
I think an example of what you're asking could be in some ways explained with a decoder, simply because a decoder can &quot;translate&quot; bits of information into something else. In this case, I'll try to explain how a decoder might allow you to access a memory address, based on a 4-bit input.
For example, say you have an 8-bit CPU. The 8 bits could theoretically be divided as so:
1100 | 0001
Where the leftmost bits (1100) represent an operation code, and the rightmost bits (0001) represent a memory address for one of the operands.
Since you allow each memory address to be composed of 4 bits, the largest base-10 number you can have is 16 (1111). And since you are running an 8-bit CPU, you might only be able to run 8 bits at a time through your bus. Thus, you might decide to restrict your RAM to only store 8 bits of information per memory address.
In other words:

16 total memory addresses, with each memory address containing 8 bits.
This gives you a total of 128 bits of memory.
Lets say each address has one input that, when it receives a pulse, will &quot;open&quot; up that address so that the 8 bits of information it holds in a series of 8 latches will be output to the bus.



simulate this circuit &ndash; Schematic created using CircuitLab
In the schematic, there would obviously be RAM 0 - 8, and RAM 11 - 15 to make up your total of 16 registers.
If you study the logic gates, you'll see they're cascaded in a way where any 4-bit input can be turned into only one &quot;enable pulse&quot;, which will correspond to the register of that input address.
I would strongly recommend YouTube user madmaxx's playlist Lets Build 8 Bit Computer.
Notes:
The logic gates I've used above accept two inputs. Based on those two inputs, each logic gate will output one signal.
The NOT gate is the triangle with the circle. This one is simple: if the input is 0 (no signal), the output will be 1 (however many volts your signal is, say, 5V).
The AND gate is the bullet-looking symbol. Only if both inputs are 1 (say, 5V), then the output will also be 1. Otherwise, the output will be 0. Here is what's called a &quot;truth table&quot; for the AND gate:
A|B|O

0 0 0

1 0 0

0 1 0

1 1 1
Where A and B are the two inputs, and O is the ouput.