Starting current of an induction motor
There is no way to calculate the Starting Current or Locked Rotor Current  (LRA) without more information!

Single-phase or three-phase?  NEMA Motor Design B, C or D?

What does academic education's sake mean?  A voltage of 15V with a power of 132kW is meaningless for an induction motor.  You just can't make up numbers.  You are also using \$P = V\ I\$, which is DC power.  

You'd be better off looking up a motor nameplate and going from there.

Take a 150hp, 1789rpm, 460V, Design B, Code G, 3-phase induction motor.  So rated current is 163A, with a power factor of 0.897 lagging and an efficiency of 96.2%.

Code G gives you locked rotor kVA on a per hp basis.  Locked rotor kVA will allow you to calculate LRA.  Code G = 5.6 up to but not including 6.3.  Worst case = 6.3.

$$150hp \times 6.3 = 945 kVA$$

$$ S = \sqrt {3}\ V_{Line}\ I_{Line} $$
$$ I_{Line} = \frac {S} {\sqrt {3}\ V_{Line}} = \frac {945 kVA} {\sqrt {3} \times 460V} = 1,186A $$

LRA will be between 1,102A and &lt; 1,186A vs 163A or 676% to 728% of full-load current.