Emitter follower: Icq and Vceq calculation
You can't assume the base is at 6V. The divider R1/R2 has a parallel resistance to R2 in the emitter resistance. You'll have to multiply RE with HFE to get the resistance as seen from the base. Otherwise the setting point would be independent of HFE.

Like flpgr says the emitter resistor make the circuit less dependent of HFE, but not completely. Ignoring the HFE and \$R_E\$ for the calculation of the base setting voltage results in a 20% error for \$I_E\$. You can do the calculation for different values of HFE to see how much/little HFE changes the nominal 2.2 mA.