Why transformers Secondary magnetizing inductnace and Secndary inductace are Not Considered while doing filter calculation for output ?
When you magnetize a core you do it through the driven winding hence it makes sense to only mention the magnetization inductance relative to the primary because that is assumed to be the driven winding i.e. the winding that magnetizes the core.

You can easily swap this around. If you know the turns ratio then the secondary magnetization inductance (if you wanted to drive the secondary rather than the primary) is \$\dfrac{L_{mp}}{(n_1/n_2)^2}\$.

But there is only one magnetization inductance i.e. don't go believing you have to account for it on both windings i.e. it's on one not both.

When it comes to secondary leakage inductance being unspecified you can estimate it by using the same formula as above. If \$L_{l1}\$ is 1 mH and the turns ratio is 10:1 then \$L_{l2}\$ would be about one-hundredth lower i.e. approximately 10 uH.

Be careful though; what some data sheets describe is the primary referred leakage inductance and this figure combines the actual primary leakage inductance AND the referred-to-primary secondary leakage inductance i.e. it is a composite figure that takes into account both leakages. You can of course split this back to individual figures if you know the turns ratio BUT, if you are making a filter it won't matter.