If an inductor is in series with each of the upper and lower MOSFETs of a half-bridge, will the switches experience zero current turn on?
Does this mean there will be relatively lossless turn on?


From the point of view of the power supply feeding the converter, energy will be delivered to the load and also stored in the inductor. The energy delivered to the load is somewhat delayed by the inductor charging up so, for a short period of time less energy is delivered to the load and this may or may not be a bad thing.

But, energy is being taken-up by the inductor as the current ramps up and, that energy can no longer be used by the load so, when the MOSFET turns off it all gets dissipated in the MOSFET because the inductor tries to maintain that current against the scenario of a rapidly open-circuiting MOSFET.

A side impact can easily be that the MOSFET gets too stretched on inductor back emf and gives up the ghost.

I don't see any net benefit; only problems but, if you have a cunning plan, please enlighten me.