High frequency response of capacitors
capacitor does not like the fact that voltage is changed across it since it acts as a short circuit initially


I don't know what the capacitor likes or doesn't like, but I think your reasoning is backwards.

First, we usually say "the voltage across an ideal capacitor cannot change instantly" rather than say what the capacitor likes or doesn't like (we might say the capacitor doesn't "like" having a voltage higher than its WV rating across it, or a current greater than its ripple current rating through it, because those things will damage the capacitor).

Second, the reason for the voltage not changing instantly is the capacitor's defining relation:

$$V = \frac{Q}{C}$$

This means that in order to change the voltage (V) instantly, you'd have to change the separated charge (Q) instantly. That would require delivering an infinite current through the capacitor (if only for an instant).

Similarly, the reason the capacitor "acts as a short circuit" for short time periods in a transient analysis is again that its voltage waveform can't be discontinuous without its current waveform including singularities, not the other way around.


  If this is true than why does it acts a short circuit(or low impedance) in case of AC signals which have alternating or changing voltages every moment.


Remember

$$V=\frac{Q}{C}$$

Another thing this means is that for the voltage to change quickly (as in a high frequency AC signal), the charge must be moved quickly in and out of the capacitor plates. 

Charge moving quickly means large currents.

And large currents through it producing only small voltage changes is exactly what it means to say that a component has a low impedance. When the impedance of the capacitor is much lower than that of other components in our circuit, then we say the capacitor acts like a short circuit.