I'm designing a preamp to connect 10K load. I need 2vptp at output from an 200mVptp input. but I want these bias conditions
In your current circuit the base of T1 is at 75/(75+15)* 9 = 7.5 V.
The emitter of T2 will be at about the same level, 7.5 V.
T2's bias emitter current (and roughly its collector current) will therefore be (9-7.5)/(530+22) = 2.7 mA. So in the current configuration its collector voltage is about 2.7*1.8 = 4.86 V. Its emitter voltage is 9-(0.530+0.022)*2.7 = 7.5 V.
If you want a gain of 10 you'd have to make R5' = 10 * R8 = 5.3k.
But then its collector voltage would become 2.7*5.3 = 14.3 V which is not possible with a 9 V supply.
You'll get 1 V range (2 Vpp) if the collector of T2 is just 1 V, I guess we can take 2 V. Then the emitter is at 9 - 0.2 (- 0.05 for the decoupled resistor) = 8.75 V. So we'll have to change R1, R2 accordingly, say, R1 = 2.5k, R2 = 87.5k.
For the same bias current in T2 we need R8 = 0.25V/2.7mA = 92.5 and R4 = 23.
Then R5 = 10 * 92.5 = 925 and the T3 collector is at 2.7*0.925 = 2.5 V.
This will probably work.