Total inductance of two Parallel aiding inductors each with an inductor in series
Inductors add just like resistors. So combine the inductors in series to get just 2 inductors in parallel. Then add those two parallel inductors by adding together their reciprocals. 

Edit: Then take the reciprocal of that answer. I forgot about this last part. Very important. 

\$\frac{(L_{1}+L_{2})(L_{3}+L{4})}{L_{1}+L_{2}+L_{3}+L_{4}}\$

Formula for calculating inductors in parallel is the following:

\$ \frac{1}{L_{total}} = \sum\limits_{n = 1}^{N}\,\frac{1}{L_{n}} = \frac{1}{L_{1}}+\frac{1}{L_{2}}\,...+\frac{1}{L_{N}}\$

Formula for calculating inductors in series:

\$ L_{total} = \sum\limits_{n = 1}^{N}{L_{n}} = L_{1}+L_{2}\,...+ \,{L_{N}}\$