Questions about RD snubber circuits
Calculate the peak current flowing through L1. If you are switching at a very low frequency that peak current tends to become V1 / R1. If you are using a reasonable switching frequency, the peak current in the inductor is mainly determined by the inductor.

When the inductor is open circuited that current has to flow somewhere and this is where the diode comes in. It acts as a path for that current to flow through R2 then to the supply rail, through R1 and back to the other terminal of the inductor. Because it passes through R2 you can calculate directly what the peak voltage seen on the transistor collector is.

Is it below the max rating of the transistor - if yes (and by a decent margin (say) 70%) then the transistor will survive.