Calculate the parallel value of resistors at base of common emitter amplifier
I think the question is confusing because of the way "X" is indicated in the schematic.

What they likely want to ask about is the input resistance seen by the source \$V_{in}\$. 

First, assume the frequency is high enough that capacitor C1 can be ignored. Then, the input resistance of the circuit is essentially the resistance at "point X", if X were drawn pointing to the same node of the circuit, but somewhere to the left of where R1 and R2 connect to it.

That means the the input resistance of the amplifier is given by 
$$R_1 || R_2 || R_{in}$$
where \$R_{in}\$ is the input resistance of the emitter-degenerate common-emitter amplifier.

So you just have to work out what \$R_{in}\$ is (you have enough information in your schematic), and then find what needs to be put in parallel with that to get 10 kOhms.