Calculate current with potentiometer
Since the pot is in series you should be able to vary the current- assuming the LED drops 2V you would have from (9-2)/220 = 32mA to (9-2)/10.2K = 0.7mA. 

Note that there is no need to have more than a couple significant figures for the current calculations- the battery voltage , LED drop and resistances are not that accurately defined. 

Modern LEDs can be fairly bright with 0.7mA DC so if you have a good LED it could well appear reasonably well illuminated. On the other hand, 32mA may be too much current for a small LED.