Energy loss by Hysteresis
No, it is not.

First of all, you must measure the input current, not voltage; The R1 resistor lets you to do that, the CH1 measurement divided by the R1 shunt resistor value is the input current of the circuit.

After dividing the CH1 measurement by the R1 value and plotting the CH1/R1 and CH2, now you can find the area inside the hysteresis curve and get the energy losses per period - in Joules, if you've plotted the CH1/R1 in amps and CH2 in volts. I have no idea where do you derive the N/m^2 units from, the energy units, joules, are N*m by definition.

To get the energy losses per second (that is - the power losses in watts) you need to multiply the energy losses per period by the signal frequency.