Inverting a (voltage-) transfer function using opamp
Your overall gain 0.1 , which by design is the inverse of the feedback gain = 10 as OA1 reduces its output so that 10 times its output matches the input of the OA1 as an &quot;error amplifier&quot;.
So that rather than a resistor attenuator for feedback to get gain, you have gain feedback to make an attenuator.
Each is internally compensated to get a typical phase margin at a unity gain of 60 deg. (IDK what your IC specs are but I'll look later)  Now cascading in closed-loop two amplifiers with some phase margin each overall reduces the phase margin.
Now understand if the output doesn't change in a linear amplifier due to diode limiting or saturation, all single-stage amplifiers and comparators alike the loop gain drops to zero, Av=Δout/Δin=0.  If that happens to your x10 feedback amplifier, it becomes a closed-loop noise oscillator amplifier with rail-to-rail saturation noise feeding while operating non-linearly from no gain at one rail then racing back towards the other rail while amplifying the very low input thermal noise by 1e5 or more.
This configuration is inherently unstable at some point whenever the initial condition or transient condition, the output of OA2 happens to saturate, causing OA1 to oscillate with its input noise amplified by its open-loop gain and the open-loop gain of OA2.
By reducing the input signal with a sinewave to say 100mV max and restarting, it might be barely stable but as you increase the level where the phase margin at high frequency drops to &lt;=0 you have by Barhausen criteria, a closed-loop feedback oscillator of input noise.