Non-inverting output of transistor circuit (at NPN base) is 0.69V max. why?
The transistor base is not an output of this circuit.

It is where the input signal connects to the transistor. There is not expected to be any gain between the input and this node.

If you want a non-inverted output with gain, you can add another CE stage.

Or if you want both inverting and non-inverting outputs with equal amplitudes from a single circuit, you could add an inverting buffer circuit (perhaps based on an op-amp).

Or if you want inverting and non-inverting outputs with equal amplitude and equal phase delay, you will need to go to a fully differential amplifier circuit, like the emitter-coupled pair. Or just buy a fully differential op-amp.

Or if you just want a non-inverted replica of the input signal to drive another high-input-impedance circuit, you should just connect to LPT_STROBE rather than to NORMAL. If you want to connect more than 2 or 3 of these same circuits to a single CMOS output, you'll probably want to increase the value of the input resistor to something more than 1 kohm, though.

Note: As Bimplerekkie points out in comments, you could have much higher fan-out if you used an n-channel MOSFET in place of the BJT in your circuit.

Or just buy a CMOS buffer and inverter chips. One-gate versions are typically less than $0.10 in reasonable volumes, so buying the one-chip solution is usually cheaper than what you pay to place all the extra resistors in a discrete inverter circuit.