Is it possible to get the current in this circuit?
The situation depicted in the circuit is not possible.

Consider for a minute only the 12v source and the load resistor apparently dissipating 12 watts.   If these were the only two components, the current through the resistor would be 1 amp.

Now put the 10 ohm resistor back in the circuit.  What is the voltage drop required to push an amp through 10 ohms?   Clearly enough that there can no longer be 12 watts dissipated across the other resistor as indicated.

Put the allegedly measured 4v drop back into the circuit and it gets even further from reality.

You have either a trick question, or a miscopied question.