Confusion in current calculation
If indeed the wire labelled I1 is a short circuit, then the diagram represents something that is logically impossible. It's not possible to have a 10 V voltage source across a short circuit, which always has 0 V across it. It's as nonsensical as trying to make sense of the equation 10 = 0.
If the wire has some undrawn components on it that take a current of I1, then the power supply can deliver 10 V, at a current of 2+I1 amps, 2 A for the resistor, and I1 for the 'wire'.
If you build that circuit in the real world, then one of two things will happen, depending on which of the power supply and the short is 'stronger'. If it's heavy wire doing the short-circuiting, then the battery voltage will collapse as the current rises to as much as it can supply. The supply may destroy itself, or survive if it's been built to limit safely, either way it will deliver about 0 V. If it's a heavy supply like a car battery and a thin piece of wire, then the wire will burn through.