Solving an Op-amp circuit
I don't know how to proceed with this question or where to start.


If there is (net) negative feedback, then you proceed by setting the voltage across the op-amp input terminals equal to zero:

$$v_+ = v_-$$

Note that with zero volts across the input terminals, the 2k resistor in parallel with the current source is irrelevant; there is zero volts across it so there is zero current through it.  You may remove it from the circuit without changing the solution.

This should get you started.




  @AlfredCentauri I still don't see the bottom loop, do you mean the
  loop v+ connected to VB then connected to the voltage source and then
  the resistor and finally VA. Is that considered a loop even with the
  op-amp? And when I do I still don't get your equation.








simulate this circuit &ndash; Schematic created using CircuitLab

This is the bottom-most loop and KVL clock-wise 'round the loop starting with the voltage across the 1k resistor is:

$$i_1 \cdot 1k\Omega -2V + V_B - V_A = 0 $$

rearranging yields

$$V_B = V_A - i_1 \cdot 1k\Omega + 2V$$

If the presence of the voltage source above is puzzling, recall that the output of the ideal op-amp is an ideal (controlled) voltage voltage source referenced to ground which I've shown explicitly here.