Basic question I would like to be solved
In order to measure voltage, you place the meter in parallel with the element that you are trying to measure the voltage across so the meter must have very high, or in an ideal case infinite, resistance to avoid drawing current and messing up your measurement. So for simplicity let's assume we have an ideal voltmeter with infinite resistance. Now, you can analyze the circuit using Kirchhoff's voltage law (KVL). 







simulate this circuit &ndash; Schematic created using CircuitLab

Starting from the battery.

\$9V - I_{Loop}\times R_{1} - V_{Voltmeter} - I_{Loop}\times R_{2} = 0\$

Since the voltmeter has infinite series resistance, we can model it as an open circuit thus \$I_{Loop} = 0\$.

Since \$I_{Loop} = 0\$

\$9V - 0\times R_{1} - V_{Voltmeter} - 0\times R_{2} = 0\$

Or

\$V_{Voltmeter} = 9V\$