Load capacitance of crystal
The effective capacitance on a crystal is the series equivalent of the attached capacitances.  The \$330\mathrm{k}\Omega\$ resistor isolates the crystal from the chip's output pin, so the effective capacitance is 33pF in series with the parallel combination of the 10pF cap and the microprocessor input pin.  So the 10pF cap plus  another 10pF of parasitic capacitance would get you to 12.5pF -- 10pF sounds high, but not unreasonable, to me.

But I suspect that a better question to ask would be the broader one of "why is this oscillator not oscillating", and the answer would be "either your board or your micro has aged" (Since you seem to have eliminated the crystal as a suspect).  You do need the \$330\mathrm{k}\Omega\$ resistor there to reduce the drive to the crystal, but you might be able to reduce the resistance for greater drive (I wouldn't go below \$100\mathrm{k}\Omega\$, but that's a pure guess on my part).