Input impedance of TTL driver in a RF switch
TTL-compatible....
A standard TTL input requires 1.6mA of the source when you pull it to logic low (gnd). To pull high, far less current in the opposite direction is required of the source. An &quot;input impedance&quot; calculated at 2.5k ohms assumes a TTL input is linear - it is not: forget about &quot;2.5k input impedance&quot;.
Minicircuits suggests that 2mA is required, not 1.6mA. It is likely that this 2mA flows when you pull that TTL-compatible input low, but current direction is not really clear. It is possible that 2mA is required to pull high, but that's unlikely, because Minicircuits claim of &quot;TTL-compatible&quot; would be untrue.
So is your 200 ohm source resistance acceptable, from a 3.3V signal?
If your source voltage pulls that TTL-input to ground through its 200 ohm resistance, the TTL input would see 0.4V. Maxiumum acceptable TTL-low input voltage is 0.8V, so you're within the limit by 0.4V. Not a lot of noise margin - you decide.
If your source voltage pulls that TTL-input to +3.3V through its 200 ohm resistance, we have to decide how much current flows. Is it 2mA? Or is it insignificant, as per TTL practice? The minimum acceptable TTL high is 2.0V:

TTL input current is 2mA: TTL gate sees 3.3-200*.002 = +2.9V
TTL input current is 0mA: TTL gate sees +3.3V

TLDR: Both cases are above the TTL &quot;high&quot; spec of +2.0V.
If you've characterized that 200 ohm source resistance with care, logic high input should be OK. The worst case is pulling TTL input to logic low, where you only have 0.4V noise margin.
You really don't care what this TTL buffer drives - that's Minicircuits problem. You only care that the TTL input meets TTL low/high logic levels with acceptable noise margins.