Parallel LC circuit Q factor inductance role
I'm wondering why Q factor in parallel LCR circuit is proportional of
C and inversely proportional to L

As a slight help, if you considered a resistor in series with an inductor, the Q of that circuit is: -
$$Q_S = \dfrac{\omega L_S}{R_S}$$
But, you have \$L_P\$ and \$R_P\$ and, the \$Q\$ of the parallel combination is: -
$$Q_P = \dfrac{R_P}{\omega L_P}$$
So, \$Q_P\$ is inversely proportional to inductance
For a parallel RC circuit, Q is: -
$$Q_P = R_P\cdot \omega C_P$$
So, \$Q_P\$ is proportional to capacitance.
Now I know it's more complication for an RLC but I didn't want to do half a sheet of math to prove it when you can get a feel for the answer by analysing the parts.