RLC Circuit with a resistance combined with the inductor. Is my solution correct?
Have I made any mistakes here?


Editing your question after I made my answer is a really big mistake. I can see you are ignoring my request so I point out here that changing your mind from RMS to p-p does not alter the problem you have. Current I (as calculated by V/R or V/Xc) does not match what you have calculated and neither do they match each other. Now stop amending your question thus causing me to make amendments to my answer and wasting my time. I'm trying to help you yet all you are doing is wasting my time.

If VR is 0.8 V RMS and R has a resistance value of 480 ohms then the current I has a magnitude of 0.8/480 amps = 1.667 mA. Clearly your calculated current of 23.8 mA is a mile out.

Sanity check: 3.8 volts across Xc and Xc = 144.7 ohms hence I is 26.3 mA.

The only feasible conclusion is that you have made mistakes in posting the detail of the question or the question is misleading.