exact copy of amplifier stages
The Q point is the quiescent point, i.e., the operating currents and voltages when no signal is present.

A simulator should give you the DC solution for the circuit.  Check that to see if the collector voltages are equal.

Or, zero the signal source and check your collector voltages.  They should be the same.

If they aren't, check your net list for an error.

When there are large signals present, the DC (time average) voltage on the collector can be very different from the Q point voltage due to non-linearity, clipping, etc.

UPDATE:  Re the bias network others are pointing out, in a previous post, I provided you with an equation for the bias current and we specifically talked about bias stability against variations in beta.  Let's check your circuit against that.

Recall the equation:

\$I_C =  \dfrac{V_{BB} - V_{BE}}{\frac{R_{BB}}{\beta}+\frac{R_{e}}{\alpha}}\$

The key for stability is to have the right most term in the denominator much larger than the leftmost term.

According to your schematic:

\$R_{BB}= 28k \Omega \$

So, the leftmost term is:

\$\dfrac{28k \Omega}{200} = 140 \Omega \$

But the rightmost term is just about 82 ohms when it should at least 1400 ohms for a roughly 10% variance of DC collector current due to variations in transistor beta.  A simple partial fix is to try using 43k and 3k in your divider circuit.

You've been given the tools to use so use them!