How to lift the Flip Flop D equations of an ASM-Chart?
Hint: build a truth table for the next-state logic as a function of the current-state and input values. Since there are 2 bits of current-state (x1,x0) and 3 bits of input (P,A,F), there will be at most 32 rows in the table (2^5=32) if you draw out the full grid.

The process is basically just following the edges that transition from one state to the next state. Wherever the edge goes through a decision condition, the next state also depends on that input condition. Note: I am assuming True=1 and False=0, and I'm using _ to represent a don't care term. Here's the basic pattern for a truth table for 4 states, without considering the input conditions.

x1  x0  P   A   F   |   D1  D0  
0   0   _   _   _   |   
0   1   _   _   _   |   
1   0   _   _   _   |   
1   1   _   _   _   |   


For the first state (0,0), the next state depends on input P. The inputs A and F are ignored in this state. So the truth table row for state=(0,0);P=0;A=0;F=0 must set next-state=(0,0); and the truth table row for state=(0,0);P=1;A=0;F=0 must set next-state=(0,1). 

x1  x0  P   A   F   |   D1  D0  
0   0   0   _   _   |   0   0  
0   0   1   _   _   |   0   1  
0   1   _   _   _   |   
1   0   _   _   _   |   
1   1   _   _   _   |   


We also get the same output if A is 1, so those two rows can be copied for the A=1 variation. The extra terms will be reduced when you do the K-map. Or you can eliminate the duplicated rows from the truth table by designating the A and F inputs as "don't care". (Often that is indicated by "X" instead of "0" or "1", which incidentally makes the instructor's choice of x as a variable name somewhat nonstandard. Usually in the real world we use "s" to indicate next state.) Since you're going to be writing out the equations manually, might as well just mark A and F as don't care, so there's less stuff to write.

From state (0,1), the next state depends on input A (but not the other inputs).

x1  x0  P   A   F   |   D1  D0  
0   0   0   _   _   |   0   0  
0   0   1   _   _   |   0   1  
0   1   _   0   _   |   
0   1   _   1   _   |   
1   0   _   _   _   |   
1   1   _   _   _   |   


The edge from state (0,1);A=0 leads to state (0,1).

x1  x0  P   A   F   |   D1  D0  
0   0   0   _   _   |   0   0  
0   0   1   _   _   |   0   1  
0   1   _   0   _   |   0   1   
0   1   _   1   _   |   
1   0   _   _   _   |   
1   1   _   _   _   |   


The edge from state (0,1);A=1 leads to state (1,0).

x1  x0  P   A   F   |   D1  D0  
0   0   0   _   _   |   0   0  
0   0   1   _   _   |   0   1  
0   1   _   0   _   |   0   1   
0   1   _   1   _   |   1   0   
1   0   _   _   _   |   
1   1   _   _   _   |   


Follow the same basic procedure to build out the rest of the truth table. The state machine output terms are developed in the same way.