Implementation of Current Source for a Current Mirror
The first circuit is really a perfect current source made by an op-amp. Its function is to compensate the voltage drop across the load by adding the same voltage in series to the load (figuratively speaking, the op-amp output acts as a negative resistor with resistance -RL that neutralizes the positive resistance RL). As a result, the simple input current source (composed by VBIAS and R) "sees" zero virtual resistance and voltage (virtual ground)... and its current I = VBIAS/R does not depend on the load.

The problem of this circuit is that the load is "floating" (not connected to ground). So, if you want to pass its output current through the input part of the current mirror (as you have drawn in the third picture), there is only one way - to supply the op-amp circuit (or the current mirror) by a separate floating voltage source.

Fortunately, there is no need to make such a weird connection since the input part of the current mirror behaves as a "diode" (aka active diode) with low and relatively constant voltage across it, i.e., voltage stabilizer or a kind of virtual ground. This behavior is achieved by connecting the gate to the drain (a voltage type negative feedback). So this "load" will not affect the current and you can drive it directly by the humble current source VBIAS+R.