Very simple AC voltage question
You can just use KVL and represent the sources as phasors:
\begin{align*}
    V_1 - V_2 &amp;= IZ_T\\
    125e^{j(10)} - 150e^{j0} &amp;= I\left(4 + j(4 - 2) \right) 
\end{align*}

From there, just expand and you can solve for the current as well as the power for each element.