High Vce(sat) of 2SD1048
You should use a PNP eg. 2SB815 and invert the drive. Emitter to +3.3, and collector to the load.



simulate this circuit &ndash; Schematic created using CircuitLab
The way you are doing it will not saturate the transistor, because you would need more than 3.3V at the base resistor- it’s an emitter-follower which will always have at least one diode drop.
Something like this would give you the datasheet performance for the 2SD1048, however it's less convenient because you probably don't have a 6.6V supply or a way to level shift the control signal. There's also a potential issue if the load is removed the 3.3V supply could rise in value and damage something.



simulate this circuit
P.S. If by &quot;screen&quot; you mean only the backlight,  you can simply use the D1048 as a low-side switch, but that's not a great way to switch the entire display power.