Common base amplifier output impedance
You can always use AC analysis (frequency response) and plot \$ R_{out} = V_1/I_1\$ . 

Here you have an example from LTspice (I don't have multisim)



\$V_1\$ is \$5V DC\$ source and \$1V\$ for AC analysis.  

And next, I plot \$ R_{out} = \frac{V_1}{I_1} =\frac{V(n001)}{I(V1)} \$ 

And read from the plot \$ R_{out} = 2.62\textrm{M}\Omega\$



In LTspice I used \$2N3904\$ with \$V_A = 100\textrm{V}\$ (Early voltage) and \$ \beta = 300 \$ 

The DC operation point is: 

$$I_E = \frac{5\textrm{V} - 0.75\textrm{V}}{15\textrm{k}\Omega}\approx 4.3\textrm{mA}$$ 

And BJT small-signal parameters:

$$g_m = \frac{I_C}{V_T} = \frac{4.3\textrm{mA}}{26\textrm{mV}} \approx 0.165\:\textrm{S}$$ 

$$r_O = \frac{V_A + V_{CE}}{I_C}\approx 24.45\textrm{k}\Omega$$

$$r_{\pi} = \frac{\beta}{gm}\approx 1.8\textrm{k}\Omega$$

And finally, we can calculate \$R_{out}\$ without \$R_C\$ resistor in the circuit.

$$R_{out}= r_o + (1 +g_m \cdot r_o)\cdot R_E||r_{\pi}\approx 2.61\textrm{M}\Omega$$