Can I in any way connect +ve side of my led to uln2083a output pin?If no can I do it with M54562 transistor array?
ULN2003 only sinks current (connects load- to Gnd). It does not source current (connect load+ to +5).
For that, you need a part like MIC5891, which is a shift register with high current source outputs.
https://www.digikey.com/product-detail/en/microchip-technology/MIC5891YN/576-1310-ND/771779

If you don't need that much current, or the latch capability from the shift register, then a line driver such 74AC541 can drive 24mA loads
https://www.digikey.com/product-detail/en/texas-instruments/CD74AC541E/296-4248-5-ND/375631

Or other parts in the 74AC family if you need something in a smaller package
https://www.digikey.com/products/en/integrated-circuits-ics/logic-gates-and-inverters/705?k=74ac&amp;k=&amp;pkeyword=74ac&amp;sv=0&amp;pv69=80&amp;sf=1&amp;FV=ffe002c1&amp;quantity=&amp;ColumnSort=0&amp;page=1&amp;stock=1&amp;pageSize=25