Basic circuit diagram question when current isn't given
3||2 = (1/3+1/2)^-1 = 6/5
Voltage divider after that:
V2 = 16*(6/5 / (6/5+2)) = 6

This works because V2 is the same for the 2 and 3 ohm in parallel. Therefore you combine the two in parallel. Now there's a 2 resistor voltage divider between 6/5 ohms and 2 ohms. 

If you want to do this the more basic way, after combining 3 and 2 in parallel, you would combine that with the to to get 2+6/5 ohms. 16 volts going into that would give you the current (5amps) through the series 2 ohms. 2 ohms times the current would give you the voltage on that half (10V) and 16V - that voltage would give you the voltage on the other side.