Power of a specific signal
Note splitting pulse into 2 half triangles = 1 rectangle, 10Vp*13Ap = 130 Wp is a rectangular pulse which is equal to area under the curve. With t=50us of rectangle or peak to nearest zero crossing   and T=4ms, T/t = 4000/50=800 thus energy in 1 ohm is 130 Wp/800 = 160 mW average or 160mJ energy.
FYI , current must be same polarity as Voltage for R so probe orientation is reversed.  But no worries here except for measurement error.
Yet both V and I are ringing the same so it is not BW limit of probe but it should be 10V/1R = 10 A not 14A and shud be 100 W peak not 140W
( check probe load, may be defined like 1A/100mV)

or you left scope in 10:1 mode. on by mistake.

Does it need 50 Ohm load? that may account for calibration error.
So current probe is not calibrated or degaussed due to DC error or hysteresis or not setup correctly.


Since I was approximating raised cosine pulse as a rectangle of DC pulse, it is 100W pk RMS in that 50us and then averaged over 4ms time should be 100W/800 = 125mW RMS of equivalent heat energy.
Conclusion

calibrate probe.
compute Vp*Ip and measure t from peak to nearest crossing then divide by t/T

Math functions in scopes can do the ch1*ch2 part and some do average, mean or RMS.
Also consider the Sinc function. y=(sin x)/x
https://en.wikipedia.org/wiki/Sinc_function