A few questions about AC Circuits
Frequency (calculated by me) is 23.215 kHz, \$\omega L\$ = 685.6 ohms, current is 10mA therefore voltage across L is 6.856 volts. 

This means Q is the same because Q = \$\dfrac{\omega L}{R}\$ and at resonance this is \$\dfrac{1}{R}\sqrt{\dfrac{L}{C}}\$.

You have made a mistake somewhere for part A. Maybe your resistor was 200 ohms?

Use the current thru the 100 ohm resistor and bear in mind at resonance the current should be zero because, at resonance, a parallel LC has infinite impedance. You know this because the two currents are exactly equal and opposite (180 degrees apart), therefore current into the parallel LC MUST ALWAYS be zero at resonance. Clearly this long term and not transient analysis of things.