Capacitor Voltage in RC Network Circuit
\$ F(s) = \frac{V_C}{V_1} = k \cdot \frac{1+a_1 \cdot s}{1+b_1 \cdot s+b_2 \cdot s^2}\$

\$k = \frac{R_2+R_3}{R_1+R_2+R_3}\$

\$a_1 = \frac{R_2 R_3 C_1}{R_2+R_3}\$

\$b_1 = \frac{C_1 R_3 (R_1+R_2) +C_2 R_1 (R_2+R_3)}{R_1+R_2+R_3}\$

\$b_2 = \frac{C_1 C_2 R_1 R_2 R_3}{R_1+R_2+R_3}\$

Inverse Laplace of the step response (\$F(s) \cdot \frac{24}{s}\$) at \$t=16 \cdot 10^{-6}\$ gives 2.26538 V.