Resistor will heat up on what amount of current?
The temperature rise of the resistor will depend on many things - its thermal impedance to air, what it is soldered to, what type of resistor it is and how much airflow there is across it. However, we can get a good idea of whether we are designing within the recommended specification of the resistor in question by calculating the power consumption.

Most cheap through-hole resistors (which I am going to assume that you are using) are rated at 0.25W - they tend to look like this:



The power dissipated in a resistor can be calculated in many ways, but the most useful for us here is 

\${P=I^2R}\$

Calculating that for the 220 Ohm resistor gives \${P=0.0215^2\times220=0.102W}\$. You can see that this is close to the maximum rated 0.25W, but well enough within for the temperature rise not to damage the resistor.

Now let's examine the same for the 10kOhm resistor: \${P=0.0215^2\times10000=4.62W}\$! This is way above the power rating for this resistor, and it will very quickly heat up, glow, and then burn off the resistive element, releasing smoke and causing your circuit to fail.

So how do we fix this? There are two options.


We could choose a 5 Watt resistor so that the power consumption was within limits. This will still work, but the 5 Watt resistor will get too hot to touch and will need to be mounted so that it is exposed to airflow and away from wiring and other components so that it cannot damage anything else.
We could increase the values of the resistors used. If you chose a 470k resistor to replace the 10k resistor you are currently using and a 10k resistor to replace the 220r resistor, your divider ratio would be almost the same (you can calculate this yourself) but the power dissipation in the 470k resistor would be only 0.098W - well within specification again.