Bus Bar voltage calculations for renewable integration to grid
The way to solve this is the same as I did but make sure that the power is the sum of all the powers at bus 1
Also assume 230v at all but bars
This gives you, the current I1 at bus 1
I.e. P=18Kw thus current at bus 1 I1=18000/230 =78.3A thus v2 = 78.3 *.2=15.7v
This is the voltage rise due to the PV at bus 1
Thus V1 = 230+16= 246
For Bus 2, P= 12Kw this I= 12000/230 =52A
V2 =52*0.2=10.4=10 (approx) thus 246 +10
V2 = 256v
Bus 3, P=6kw thus I =6000/230 =26A
V3= 26*0.2 =5.2v thus 256+5.2=261v