How to calculate the currents of \$I_R\$,\$I_L\$ and \$I_C\$?
R=? L=4.3mH C=220μF i(t)=15u1(t)A Mp≤16.3% ts±2%
   =10ms


My analysis as follows;


Using \$Q=X(f_0)/R= \frac{1}{2\zeta}\$ at resonant \$f_0\$
Mp=overshoot % 16.3% and from chart below  \$\zeta=0.35, \text { then } Q=1.4 \$
\$f_0=\frac{1}{2\pi\sqrt{LC}}=140Hz \$
thus \$R=Q*Z_L(140 Hz)= 1 * 2\pi 140[Hz]*4.3[mH]= 3.8 \text{ }  \Omega =R \$


Initial condition \$Ic(0)=15A,  I_L(0)=0A... I_R(0)=0 . . .                    V_R(0)=0V\$

Final condition \$Ic=0A,  I_L=15A. . . I_R=0 . . .V_R=0 \$




Response can be show from normalized for Q=1
Ts is redundant