Calculating resistor and capacitor values for an op amp differentiator circuit design
That formula is all you need...in theory.

In practice the circuit tends to be unstable due to the capacitance on the input interacting with the finite bandwidth of the op-amp. This is remedied by placing a resistor in series with the input capacitor:



This link gives an elementary explanation of why this works. It will also modify your differentiating characteristic somewhat, adding a pole at 1/(2*pi*R1*C1)
So basically, it's an ideal differentiator at lower frequencies only. A more complete explanation of the stability issue can be found here.