Changing the torque and excitation in an alternator
Ignoring losses...

excitation * speed * k = voltage
excitation * current * k = torque

where k is some constant (the same in each equation) dependent on the geometry of the alternator

It's not clear how you intend to 'increase torque' without specifying the characteristics of the load. To cut you some slack, let's assume the load is something for which we can easily see what will happen, something like a rectifier charging batteries with a substantially constant terminal voltage, accepting whatever charge current you throw at them. For a torque-limited driver, they will control the speed of the alternator by increasing the loading rapidly as the alternator voltage exceeds the battery voltage. In this case, increasing the torque will increase the charge current linearly with the torque, while the terminal voltage and alternator speed will change little. Other loads will behave differently.

Increasing the excitation is trickier to visualise, as the k constant rises. Other things being equal, increased excitation is like putting a gear-box on the shaft, reducing the speed and increasing the torque of the alternator. How the speed and load voltage reacts to that depends on the characteristics of the driver and the load.

If we multiply out to get power

mechanical power = speed * torque
electrical power = voltage * current

we can see that the excitation and the geometry constant have cancelled, and for no losses, input and output power are equal.