load sharing in parallel generators
My question is that since every generator in the parallel circuit gives half power in the ideal case it would mean that the generator 1 that gives 220v 20A that is half the power can not "see" the resistance of 5.5 ohms because if "seen" this resistance he had to give complete current [edit: I think a full-stop was required at this point.]




Figure 1. Two equine traction units on a common load.

With reference to Figure 1:


Each of the parallel horses (generators) gives half of the power. 
If one horse stops (generator going off line) then the other horse takes up the full load (the plough). 
If one horse (generator) is not strong enough the system will slow down (generator frequency or voltage or both decreases).
If one horse is strong enough the system may continue but if the maximum pull (power) of the drawlines (fuses and cables) is exceeded they will break (blow / trip) and the plough (load) will be disconnected.


Note that the horses will never be exactly evenly matched but this doesn't matter. They both contribute to the effort of pulling the load and the fraction of load borne by each will be proportional to the effort of each.


  in [sic] that case we have two problem [:] generator 1 burned because it is not made for such a current problem 


No. The circuit breaker or fuse will trip to protect the generator.


  two [sic] if generator 2 gives the same current then the law on energy conservation is not worth what is absolutely not possible 


Sorry, I don't know what this group of words means.



Note that paralleling AC generators requires proper synchronisation control equipment. You can not just wire them up together.