Problem with expected and actual current
Given a choice between Ohm's law and measurement error, I'm going to go with measurement error. After all, there is already a large math error on prominent display. 0.91V / 180 Ω = 0.00506 A making your initial calculation off by an order of magnitude.

Going with a typical mistake, I'll guess that you measured current across the load, thus short-circuiting the load and measuring at essentially 0 Volts. You are fortunate that your wind turbine only put out 0.12A, since a typical low-range ammeter fuse is 0.25A.







simulate this circuit &ndash; Schematic created using CircuitLab


Ammeters always go in SERIES with the load.
Voltmeters always go in PARALLEL with the load. 
A multimeter needs to be hooked up correctly for the mode it is being
used in.