Does current flow from the emitter through the base in this circuit?
Does this mean that Current flows from the Emitter through the Base?

No because this PNP will operate in active mode. That means that the current amplification:
\$\beta = \frac{I_C}{I_B}\$
still holds.
So if for example \$\beta = 100\$ then around 99% of the current will flow through the Collector and only around 1% will flow though the base.
Because I felt like it, I give you another example:
Here the NPN is used as a diode.



simulate this circuit &ndash; Schematic created using CircuitLab
Note how the current nicely divides so that \$\beta = \frac{I_C}{I_B}\$ remains valid.