BJT problem. Are my calculations correct?
\frac{V_4  + 3}{4300} is the equation for I_{E2}. Therefore, it needs to be multiplied by (1 – \alpha) to obtain I_{B2}.\
Thus 
$$
2.25 \cdot 10^{-4} &amp;= \frac{V_3  + 3}{9100} + \frac{V_4  + 3}{4300}(1 – \alpha)\