LM139 Comparator question
"Since the output of the LM139 is an open collector, when both comparators are "HI"(the input signal is in between the non-inverting pin of comp 1 and the inverting pin of comp 2), would that not sink the current to ground by turning on the internal transistor and not allow the voltage source to activate the external transistor?"

It would be the other way round - if the input is less than VrefHI the output transistor of the upper comparator would not be conducting.  Since the input is above VrefLO the output transistor of the lower comparator also would not be conducting. So the current from the 10K resistor would flow into the transistor and cause the lamp to light.

The polarity of open-collector comparators is treated the same as an equivalent opamp - if the positive input is higher than the negative input the output would go positive. That is the output transistor does not conduct.