Common Emmiter BJT config
It's a mistake. 

The first order analysis assumes \$V_{BE}\approx 0.7V\$ for NPN to conduct. You can easily calculate that the value of \$V_B\$ imposed by this voltage divider is close to the above value + the value of \$V_E\$ won't be exactly zero.

I conclude that the values used for the divider are correct, but whoever wrote the text just made a mistake (maybe he wrote it at 2.a.m?)