Inductor : how to choose toroidal ferrite core material
With an \$A_L\$ of 69 nH/turn\$^2\$, to get 2200 \$\mu H\$ requires 178.6 turns i.e. turns squared x 69 nH = 2201 \$\mu H\$.

With an \$A_L\$ of 4200 nH/turn\$^2\$, to get 2200 \$\mu H\$ requires 22.9 turns i.e. turns squared x 4200 nH = 2203 \$\mu H\$.

Both achieve the same inductance but the scenario with the fewest turns will saturate the core to a much greater extent. This is because of the relationship between B (flux density) and H (magnetic field strength). The higher the ratio between B and H the higher is the core permeability. 

When \$A_L\$ is a low value the permeability is naturally lower so, for a given H field, B is smaller and hence core saturation problems are not as big.

Notice that 178.6 turns is 7.8x as many turns as 22.9 BUT, notice that 4200 nH/turn\$^2\$ is nearly 61 times higher than 69 nH/turn\$^2\$. This makes all the difference. 

Cores with the same dimensions but having lower permeability (either due to material differences or gapping) will naturally saturate to a lesser extent for the same winding inductance. On the other hand, more turns means more \$I^2R\$ loss so you need to make choices and optimize what you want/need.