Level Shifting Circuit to output 0.2V-4.8V
Since the scale (max-min) of your input is different to the scale of your output, this is not just a shifting problem but also a scaling problem. To both shift and scale using an opamp, the Differential Amplifier circuit is a great tool.



simulate this circuit &ndash; Schematic created using CircuitLab
The defining equation for this circuit is:
\$V_{out}=(\frac{R_4}{R_2+R_4})(\frac{R_1+R_3}{R_1})V_{in}-(\frac{R_3}{R_1})V_{shift}\$
So suppose you have a 5V rail available, and according to your question you want \$V_{out}=(\frac{23}{30})V_{in}-\frac{43}{15}\$ then you might choose values like so:

\$V_{shift}=5V\$
\$R_{1} = 1.5k\Omega\$
\$R_{2} = 8k\Omega\$
\$R_{3} = 4.3k\Omega\$
\$R_{4} = 2k\Omega\$