Current canceling circuit
This is one method: you can use a second capacitor, driven by the inverse of the source voltage. If your source is stiff enough (low internal resistance, or impedance), then you should be able to do a simple difference. Since you didn't give any values for the elements, I just used some random values:

U1 delivers the same signal as the source, V1, but with a different polarity. Since V1 has a 50 Ω output resistance, R10 compensates. Or, simply use I(C3) with an inverted sign. Same thing. The plot shows the overlapping I(L1) and I(R2) -- meaning I(C2) is cancelled -- compared to I(R6) -- which is what the current looks like without compensation. Note that, depending on what frequencies you are working with, you'll need an opamp with a sufficient GBW.