Common Collector Biasing
A transistor has three terminals. An abstract "input-output" box has two ports -- an input port with two terminals and an output port with two terminals. That's four, altogether.

One terminal of the input can be connected to one terminal on the transistor. One terminal of the output can be connected to one other terminal on the transistor. This leaves one transistor terminal for the two remaining port terminals. Whichever transistor terminal gets tied both ways -- to a terminal on the input and to a terminal on the output -- is the "common" terminal of the transistor.

This means there are common collector, common emitter, and common base possibilities. And that's all there are.

All of the above has nothing whatever to do with the determination of a node called "ground," which might not even be ANY of the terminals under consideration. You might have a transistor in some odd-ball corner of a circuit and it STILL will have to be operating in one of those three arrangements if it is being used as an input-output port device and it STILL will have none of the terminals at GND. The one idea has nothing necessarily to do with the other. It's just a coincidence that it is often much easier for a designer to arrange their signalling so that it's single-ended and there is a "common" bus, so to speak, for the circuit and that doing so can also help simplify solving equations.

Also, your schematic doesn't show a GND node, anyway. So far as I can tell, it's part of some other circuit that has GND at some other node not shown there.

But by inspection you can easily see that the collector is "common."

Here's an experiment for you. Take your diagram and turn it upside down and look at it, then. Also, feel free to select ANY of the terminals and label it GND (so long as you don't label any of the others GND at the same time, of course -- just one.) None of that changes the operation. But perhaps it will change your perspective.