Capacitor voltage divider in quasi-DC circuit
The top circuit uses half wave rectification, C1 is only charged during the positive part of the sinewave at the input. C2 is only charged during the negative part.

The second circuit is a full wave rectifier so it charges on both positive and negative parts of the input voltage.

However you have not one capacitor, as is common in this configuration, but you have 2 capacitors in series.

That would work if you do not have a DC current flowing through the node between C1 and C2.

If such a current was slowing it would for example discharge C1 but also charge C2 at the same time. This would make the voltages across C1 and C2 unequal.

If this DC current causing imbalance is very small, you could place resistors in parallel with C1 and C2. It is not a very neat solution but can work in some situations.

So the voltages across the capacitors would remain equal only if you load the positive and negative supplies equally (no DC current between C1 and C2). But I would never rely on this unless I'm absolutely sure I can do that.

It is better to have a centretap connection on the transformer feeding this circuit and connect that centretap to the point between C1 and C2.

This is what is used when symmetrical supply voltages are needed.