A question about negative phase angles in Bode plots
At 0.5 Hz, the output signal is lagging the input signal by 460 degrees and this tells you a lot about what is going on in terms of overall signal delay: -

If you viewed the waveforms associated with the construction of this bode plot, it would look like (on the face of it) that the output is lagging the input by 100 degrees. In other words a lag of 460 degrees appears to be a lag of 100 degrees. And, that may be acceptable to you but, it disguises the fact that the system or filter producing this lag is actually introducing a delay equivalent to 460 degrees at 0.5 Hz.
Given that 0.5 Hz has a period of 2 seconds, the overall input to output delay is in fact 2.556 seconds. And, this may be more important to know than assuming the delay is only 0.556 seconds (100 degree lag) in terms of how stable the system or filter might be.

Taking the point -460° as an example, can we say that this is
equivalent to +100°?

No, it is equivalent to -100° but, it's only equivalent if you are ignoring that the overall delay is equivalent to a phase lag of 460°.