How do you find the voltage across a capacitor at time t= 0 and t = infinity?
Hints:

A capacitor's voltage-current response is governed by:
\begin{equation}
I = C \frac{dV_c}{dt}
\end{equation}

At \$t = 0\$: think about what happens when you integrate in the limit as \$dt \rightarrow 0\$ (i.e. what is a capacitor unable to do with respect to really fast transients?)

\begin{equation}
\lim_{\delta \rightarrow 0^+} \int_{0^-}^{\delta} I dt = \lim_{\delta \rightarrow 0^+} C \int_{0^-}^{\delta} \frac{d V_c}{dt} dt
\end{equation}
Note that this equation does not imply \$I(0^+) = 0\$; it only provides a mathematical "weak" guarantee that it's integral doesn't change over the infinitesimal.

At \$t \rightarrow \infty\$, think of what happens when all transient behavior goes away (\$\frac{d &lt;value&gt;}{dt} = 0\$).