Transistor operating region
Because of positive feedback the op-amp output will run hard against the positive rail and apply a high-level voltage to the base. This voltage cannot be determined from the circuit because power rails are not shown and the op-amp is only stated to be "ideal". If ideal means it can produce an infinite voltage on its output then that is what will be produced.

I suspect that the question is faulty and the inverting and non-inverting terminals are incorrectly shown with the intention being that this circuit is a VCCS (voltage-controlled-current-source).

If that is the case then the voltage at the collector would be 2 volts and the current through the 10.5 kohm would be 3 volts / 10,500 = 286 uA.

That current would flow through the load plus ~5% extra due to the base current and beta only being 20.

If the load resistance is too high to draw this current then this clearly is a situation where the idea behind the "intended" circuit has a limitation as with any form of voltage-controlled-current-source.

In this particular circuit and assuming the BJT is operating close to saturation (Vce = 0.2 volts), the maximum resistance of the load will be limited to about 1.8 volts / 286 uA = 6293 ohms.