Voltage divider with diode
Follow the arrows below. The first transition is due to making a Thevenin equivalent out of \$V_1\$, \$R_1\$, and \$R_2\$. The second transition is just summing the remaining two resistors:







simulate this circuit &ndash; Schematic created using CircuitLab

There will therefore be about \$600\:\textrm{mV}\$ subtracted away from the Thevenin voltage, leaving \$5\:\textrm{V}\$ across the total resistance of \$10\:\textrm{k}\Omega\$. About \$500\:\mu\textrm{A}\$.