Do we analyze real poles the same way you analyze complex conjugate poles?
I would recommend to factor the original formula in a low-entropy form and match the normalized polynomial of a second-order system which is: \$H(s)=\frac{a_0}{b_0}\frac{1+a_1s+a_2s^2}{1+b_1s+b_2s^2}\$ which after proper rearrangement leads to the correct form where a leading term defines the dc gain in your case: \$H(s)=H_0\frac{1+\frac{s}{\omega_{0N}Q_{0N}}+(\frac{s}{\omega_{0N}})^2}{1+\frac{s}{\omega_{0D}Q_{0D}}+(\frac{s}{\omega_{0D}})^2}\$ where the \$N\$ and \$D\$ subscripts respectively refer to the numerator and denominator.
If the quality factor is below 0.5, it implies that roots are real and not coincident: there are no imaginary parts and the system is well damped. For a low quality factor, the poles (or zeroes) are well spread and one of them dominates the low-frequency spectrum while the other one the upper portion. In this case, you can apply the so-called low-\$Q\$ approximation:
\$1+\frac{s}{\omega_{0}Q_{0}}+(\frac{s}{\omega_{0}})^2\ \approx (1+\frac{s}{\omega_{p1}})(1+\frac{s}{\omega_{p2}})\$ where \$\omega_{p1}=\omega_0Q\$ and \$\omega_{p2}=\frac{\omega_0}{Q}\$.
In your case, you can rework the expression by factoring 987654 in the numerator and \$2.48\;10^8\$ in the denominator. This shows a dc attenuation of 48 dB followed by the two zeroes over the two poles. A Mathcad sheet shows the typical response of the factored form and compares it with the original expression:

With the given values, you see a boost in phase around 1kHz, perhaps to compensate a control system?

It is important to properly format transfer functions following a design-oriented analysis or D-OA: the transfer function should describe a system and unveil if it has gains, poles or zeroes. Respecting the format associating a leading term (if any) with a fraction starting by 1+... type of format naturally fulfills this requirement in my opinion.