What are the steps needed in finding capacitance from this circuit diagram?
Edit: The resistor limits the charge current, it does not prevent the capacitors from reaching 12 V, it only makes charging slower.   The resistor is not relevant in this question at all.

Original:


Series connected capacitors store the same charge (Q), but different voltage (U), C = Q*U.


Notice how these are similar to how you calculate total resistance, but the other way around.

Series: 1/C_Total = 1/C1 + 1/C2 + 1/C3 ...

Parallel: C_Total = C1 + C2 + C3 ...


This one is easy now when you know the total capacitance of the series connected capacitors.  Imagine that you replace the 60 and 70 pF capacitors with a single ?? pF capacitor.  The voltage over the ?? pF capacitor must be the same as over the 80 pF capacitor.
C = Q*U It could however be the power source and not the capacitors but I don't think that's a valid answer. :)
If you know the capacitance of the ?? pF capacitor, you can calculate its charge, remember C = Q*U.  Then you know that the 60 pF capacitor must contain the same charge.  The magic formula for energy stored in a capacitor is E = (1/2)QU.   (U in volts, Q in Coloumbs (Amperes*seconds), E in Joules)