NPN transistor controlling a PNP transistor
\$P=V×I=\frac{V^2}{R}\$

Here is the power draw for the two, presumably broken, resistors:


1 kΩ resistor  \$\rightarrow\frac{(\sim24)^2}{1000}=576\text{ mW}\$
2.2 kΩ resistor  \$\rightarrow\frac{(\sim24)^2}{2200}=261\text{ mW}\$


A resistor that would be safe would be 1 W resistors in this case, they are pretty bulky. I doubt that multisim selects those on default. 1/2 W and 1/4 W are way more common.

I don't have multisim available right now, but I think that the rated power is in the settings of the resistors, might be worth a look.



If I were to make this circuit, then I might have used 10 kΩ or higher. But it all depends on what you are actually trying to do.


The 1 kΩ resistor can be a 1 W resistor, or higher, not a 1/2 W or 1/4 W resistor.
The 2.2 kΩ resistor can be a 1/2 W resistor, or higher, not a 1/4 W resistor.


The power dissipated for a 10 kΩ resistor in the same setting is \$P = \frac{(\sim24)^2}{10000}=57.6\text{ mW}\$ 


With a 10kΩ resistor you can use a 1/4 W resistor, you can even go as low as 1/16 W resistor.