Power output by an RF switch
It appears that this chip can switch an RF signal of up to 38.5 dBm, which is 27 V peak in 50 ohm, even though it is controlled from a single 5 V supply.

So the 5 V is not related in any way to the maximum RF power the chip can handle.

I am curious how they do that because this is not something you can easily do in most RF ICs.

Update:
It appears that the manufacturer of this chip has a list of their patents on their website. Number 6,804,502 "Switch Circuit and Method of Switching Radio Frequency Signals" seems applicable. Find it on Google patent search.

So what they do is that they series connect several MOSFETs to handle the voltage (that 27 Vpeak). And an on-chip capacitive voltage multiplier to make the voltages needed to control the gates of those MOSFETs. Clever ! :-)