Context taxonomy term
This is a bit of code can help you I hope,

 &lt;?php
   check_vocabulary = FALSE;
     $path = drupal_get_path_alias($_GET['q']); 
     $pathnew = explode('/', $path);
     if ($pathnew[2]) {
        $vocabulary = explode('+', $pathnew[2]);
     }
    if ($vocabulary[0] == "your taxonomy") {
       check_vocabulary = TRUE;
    }
  return check_vocabulary;
?&gt;


You should put it in the block under the tab Page specificy visibility setting, click on Show if the following PHP code returns TRUE (PHP-mode, experts only).

Now I'm not sure it's going to work with your setting and name but it could be a way for a solution.

 check_vocabulary = FALSE;


As we know, the system wants you to return TRUE to print the block so we set it false in the beginning so it's no going to print it and then remove it.

$path = drupal_get_path_alias($_GET['q']); 
$pathnew = explode('/', $path);


In this part we take the path and we explode it so we get an array like this.

$pathnew[0]; Taxonomy
$pathnew[1]; Term
$pathnew[2]; Term_id_1+term_id_2

if ($pathnew[2]) {
    $vocabulary = explode('+', $pathnew[2]);
  }


We check first that $pathnew[2] exists and then we explode it to get all the vocabularies (if you want it separated). We split it by + so you will get

$vocabulary[0]; Term_id_1
$vocabulary[1]; term_id_2


Now we create the condition;

if ($vocabulary[0] == "your taxonomy") {
   check_vocabulary = TRUE;
}


You can compare what you want, that is just an example.

check_vocabulary = TRUE;


This is what the system wants to print the block.

return check_vocabulary;


This will return the variable FALSE or TRUE.

Let me know if it works.