Delay of Moon passing a defined meridian each day
The Moon is moving around the Earth in the same direction it is rotating. This means that it would be moving across the sky in the opposite direction the stars are, in case the Earth stopped rotating, however, the Moon is moving in the same direction as the stars due to diurnal motion (only slower, because it also has velocity in the opposite direction). Its angular speed across the celestial sphere will be 

$\omega = \frac{2*\pi}{T_{stars}} - \frac{2*\pi}{T_M} = \frac{2*\pi}{T}$

where $T_M$ and $T_{stars}$ are the sidereal period of the Moon and the sidereal day length. Substituting the values above, we get that the Moon takes about 51 minute over 24h to go around the celestial sphere, crossing the same meridian. Note that this is a rough approximation because the Moon's orbit is not circular, but it explains the value you mentioned.