Superluminous super nova output
This puts us in the realm of silly numbers.

A supernova has enough energy to rip a massive star apart. Putting all that energy into one small rigid body isn't going to end well.

A hypernova gives off about $10^{46}$ Joules. We will need the formula for relatavistic kinetic energy $E=mc^2(\gamma-1)$ where $\gamma$ depends on velocity. The mass of the shuttle is about $2\times 10^6$ kg, and $c^2=9\times 10^{16}$

So $10^{46} = (2\times 10^6) \times (9\times 10^{16}) (\gamma - 1)$. Rearranging, $\gamma = 5.5\times10^{22}$.

In relativity $\gamma = 1/\sqrt{1-v^2/c^2}$ So even this massive amount of energy won't make the shuttle go faster than light. It will make it go at

99.99999999999999999999999999999999999999999998% 

of the speed of light.