Actual meteor sightings formula
The factor k, the fraction of sky you cannot see, is not adjusted because of the ground or your peripheral vision. When on a flat plain (a "sea-level" horizon) and none of the sky is covered by clouds, buildings, or trees, then k=0. (Therefore, F=1, and the Zenithal Hourly Rate is not diminished.)

I do not know how the light pollution map was created and whether it accounts for the humidity. The humidity can have a significant effect on the limiting magnitude. In other words, if it is a dry day and the air is clear, you can see fainter stars than if it is a humid day and the sky is murky. If your location is clear (so you have blue skies during the day and black skies at night), then assuming m=6.5 is realistic. (Note that when you click on a location on the light pollution map, it will give the Bortle classification. Clicking the link for the Bortle class will give the expected limiting magnitude.) Of course, the limiting magnitude also depends on your eyesight. Younger people can see fainter stars than older people. (I just tried the map for my location, and it predicts 5.5 to 6.0. I can usually only see stars in the range of 5.0 to 5.5 because of the light pollution and humidity.)