Make a math equation from the date
Python 3, 424 420 369 363 bytes
import time as t
r=range
x=len
d=list(t.strftime('%m%d%y'))
o=([[x,x+'(',x+')']for x in ['']+&quot;+ - == * / **&quot;.split()])
n=[]
for l in o:
    n=l+n
o=n
for p in r(x(o)**(x(d)-1)):
    e=''
    for i in r(x(d)-1):
        e+=str(d[i])+o[(p//(x(o)**i))%x(o)]
    e+=str(d[-1])
    try:
        if eval(e)and e.find('=')!=-1:
            print(e.replace('==','=').replace('**','^'))
            break
    except:pass

Brute-forces all possible combinations of operations in the numbers and stops when it finds one.
EDIT: Saved 4 bytes thanks to @NoOneIsHere
EDIT 2: Saved 51(!) bytes thanks to @ValueInk