The Tenacious Thai Calendar
Bash + coreutils, 35 bytes

factor $[`date +%Y`+543]|awk NF==11

Output is either a non-empty string (truthy) or an empty string (falsy).
Try it online!
Alternate version: 37 bytes.
date -d 543year +%Y|factor|awk NF==11

Not as golfy, but I like this one.
Try it online!
How it works
The arithmetic expansion
$[`date +%Y`+543]
executes date +%Y to get the current (full) year and adds 543 to the year.
Factor takes the sum as an argument and prints it prime factorization: first the number to be factored, then a list of individual prime factors.
Finally, awk filters the input, printing only lines with exactly 11 fields (the number plus 10 prime factors).