The real treasure was the numbers we made along the way
TI-BASIC (TI-84+ CE), \$238^3/14161 = 952.0\$

118-length("+×/ABCDEFGHIJK...


The 256 bytes in TI-BASIC break down thusly:


240 bytes are one-byte tokens that can be quoted
11 are the start of two-byte tokens
2 are unused
The remaining 3 are the ",→, and newline characters which break strings. 


The string contains all 237 allowable bytes in the first category not already in 118-length(.

The program calculates 238 distinct integers, ranging from 118 down to -119. The score is therefore $$ \frac{238^3}{\sum_{n = -119}^{118} |n|} = 952.$$