Use xkcd's formula to approximate the world population
Pyth, 21 20 bytes

-1 byte by Dennis

c/J-*3.d3C\ᙹ4T+33J


These have the same byte count but are ASCII-only:

c/J%*3.d3 523 4T+33J
c/-J%*3.d3*44T33 4TJ


I don't know Pyth, so still probably possibly golfable. Using the same algorithm:

TI-BASIC, 23 bytes

max(3getDate-5753
{.1int(Ans/4),Ans+33


getDate returns a list of three floats {YYYY,MM,DD} in some order depending on the date format setting (TI-84s don't have a true int datatype); the max( will be the year. Multiplying and subtracting inside the max( saves a close-paren.