Even a clock that isn't working gets the time right two or three times a day
JavaScript (ES6), 13 bytes
Takes input as (h)(m). Returns true for 01:00, 02:00 and 13:00, or false for anything else.

h=&gt;m=&gt;26%h&lt;!m

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How?
Testing \$26\bmod h&lt;\delta_m\$ is equivalent to test that we have \$m=0\$ and \$26\equiv 0\pmod h\$.
For \$0&lt;h\le23\$, we have \$26\equiv 0\pmod h\$ iff \$h\$ divides \$26\$, i.e. \$h\in\{1,2,13\}\$.
For the edge case \$h=0\$, 26%h results in NaN which is neither greater nor lower than any other value, so the test returns false as expected, no matter the value of \$m\$.
Other possible values
This program generates all possible values \$n&lt;1000\$ for the expression \$n\bmod h\$.

for(n = 1; n &lt; 1000; n++) {
  A = [...Array(24)].map((_, x) =&gt; x).filter(x =&gt; n % x == 0);
  if(A.length == 3 &amp;&amp; A.some(x =&gt; A.includes(x + 12))) {
    console.log(n, A);
  }
}

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