Identify the Kaomoji!
JavaScript (ES6), Score 643
 656 651 646  642 bytes, no error
Returns an integer from 1 to 13.
s=&gt;`qv%s!u.r0vPyqv*s&quot;r'yqyu@y2r%{ }1u!v(u{y8|!ru;rur&amp;z+z,w'z-{){{0x'r*z/{Py$t w#z,xFt,}qzr.{#s$t%vv6{@s&amp;v z$x@{!{6v,sCr6s&lt;v z.r s*w=w,r0u5s r){,y!s-s%v8t.xrqyWr7r?z#uBz9r&amp;v#v5yBw+w&quot;})vNw-u4sz)y&quot;zEu/z r&quot;}/rqw w\\t0|(r*rw(uAw&amp;v {uYw#x wqz*|)v2u/|'v!r#sBs}0w&amp;r2y&amp;s r%r6w+}){&quot;r2{-usqw'}C|/v$y={!r!x!t/rt&gt;r1r&quot;svuCy*{qr&gt;v1x2r6x#{5{.wv8wGwqr!r:vJ|#r#u%uqst-}'r&quot;z\`zqw uHy$sYr-z0w#|3{8x7vqz.w!|Ez$uvw!z.{t'w+{5x&amp;|.xmrt&quot;s,u&quot;vuqwy{$t5u&amp;s'wAv&quot;vsTw#z%u*z0s r/w v#}+w'r9}0r0|AvxHv,r*}qw:x r3w}!u0v(w{qvv&quot;y.rSr0w4yr#r.}qw&quot;}%s&quot;v#r!w!u/| tCs u`.replace(/[ -p]/g,c=&gt;&quot;q&quot;.repeat(c[C='charCodeAt']()-30))[C]([...s].map((c,i)=&gt;s^=c[C]()&lt;&lt;i%5)|s%8788*3672%4051)%56

Try it online!
Or test all kaomojis.
How?
The input string is turned into an integer N with:
[...s].reduce((p, c, i) =&gt; p ^ c.charCodeAt() &lt;&lt; i % 5, 0)

(using .map() instead of .reduce() in the golfed code)
Example for ٩(◕‿◕｡)۶:
 code | &lt;&lt; |  shifted bit-mask
------+----+--------------------
 1641 |  0 |        11001101001
   40 |  1 |            101000.
 9685 |  2 |   10010111010101..
 8255 |  3 |  10000000111111...
 9685 |  4 | 10010111010101....
65377 |  0 |   1111111101100001
   41 |  1 |            101001.
 1782 |  2 |      11011110110..
------+----+--------------------
       XOR = 110010100100101110 = 207150

In the lookup string:

The emotions are encoded as 'q' to '}' (ASCII codes 113 to 125).
The characters ' ' to 'p' (ASCII codes 32 to 112) encode a run of consecutive 'q' (which, in addition to 'joy', also depicts an unused slot). The length of such a run is ord(c) - 30 (minimum = 2, maximum = 82).

We first expand the lookup string to 4048 characters by replacing /[ -p]/g with the runs of 'q' and then extract the relevant character with the following hash formula, which was found by brute-forcing some random values during a few minutes:
N % 8788 * 3672 % 4051

The final answer is the ASCII code of the character modulo 56.