How hyperperfect am I?
Jelly, 5 bytes
:Æṣ’$

:       integer divide
Æṣ’$    the decremented divisor sum

This uses \$\lfloor\frac{n}{\sigma(n)-n-1}\rfloor\$ instead of \$\frac{n-1}{\sigma(n)-n-1}\$, but it still works because \$\frac{1}{\sigma(n)-n-1}\$ can never be greater than or equal to 1.
Try it online!