cannot convert error with pointers
karakterek is an array of char pointers.  It cannot be used to store pointers to char arrays.

I'm not sure it would be possible to store pointers to your 2 dimensional arrays since they are all of different dimensions.  Someone else might know a way to do that.

Here's how I would do it (using as similar as possible a structure):

char nulla[]={0,127,8,125,9,121,10,113,12,97,14,65,24,67,27,71,28,70,30,78,32,76,36,88,40,80,42,112,48,96,56,64,68,0};

char egy[]={0,0,9,4,16,6,18,2,21,3,27,7,28,6,30,14,32,12,36,24,40,16,42,48,48,32,51,96,56,64,68,0};

char ketto[]={0,98,7,99,8,97,12,113,14,81,20,89,21,88,24,74,27,78,30,70,32,68,36,64,68,0};

char harom[]={0,34,7,35,8,33,10,41,14,9,17,73,21,72,24,74,27,78,30,70,32,68,36,80,42,112,48,96,51,32,56,0,68,0};

char negy[]={0,7,7,6,8,4,9,0,10,8,21,9,24,11,27,15,28,14,32,12,36,24,40,16,42,48,48,32,51,96,56,64,68,0};

char ot[]={0,39,8,37,9,33,10,41,14,9,17,73,28,72,30,64,36,80,42,112,48,96,51,32,56,0,68,0};

char hat[]={0,62,7,63,8,61,9,57,12,41,14,9,17,73,21,72,24,74,30,66,32,64,36,80,42,112,48,96,51,32,56,0,68,0};

char het[]={0,7,8,5,9,1,24,3,27,7,28,6,30,14,32,12,36,24,40,16,42,48,48,32,51,96,56,64,68,0};

char nyolc[] = {0,127,8,125,9,121,12,105,14,73,24,75,27,79,28,78,32,76,36,88,40,80,42,112,48,96,56,64,68,0};

char kilenc[] = {0,79,8,77,9,73,24,75,27,79,28,78,32,76,36,88,40,80,42,112,48,96,56,64,68,0};

char kettospont[] = {0,0,9,4,12,20,18,16,24,0,68,0};

char* karakterek[]={nulla,egy,ketto,harom,negy,ot,hat,het,nyolc,kilenc,kettospont};


For starters, I'd make the char arrays single dimension.  Since the 2nd dimension is always a size of 2, you could index through your values reading index 0 into x0, index 1 to y0, index 2 to x1 and index 3 to y1 (I'm assuming these are x y co-ordinate pairs).

Secondly, I'd lose the hard-coded sizes for the arrays.  If you want to add or remove entries, you don't have to keep updating the sizes.

Finally, I'd lose the '&amp;' from your array of array pointers.  Referring to an array simply by its name gives you a pointer to it.  I think '&amp;' gives you a pointer to the pointer, but I could be wrong.