Convert long to char array and back
I suggest using a union:

union {
    char myByte[4];
    long mylong;
} foo;


Char to Long:

Then you can just add the bytes:

foo myUnion;
myUnion.myByte[0] = buf[0];
myUnion.myByte[1] = buf[1];
myUnion.myByte[2] = buf[2];
myUnion.myByte[3] = buf[3];


Then you can access the long as:

myUnion.myLong;


Long to Char:

The same if you want to go the other way from long to char array:

foo myUnion
myUnion.myLong = 1234L;


To access bytes:

myUnion.myByte[0];
myUnion.myByte[1];
myUnion.myByte[2];
myUnion.myByte[3];