Confusion around LEDs on a breadboard
Scenario 1 fails because yellow and green LEDs have forward voltages of about 2V each, so when putting 3 in series, you need a forward voltage to light them that exceeds the 5V available.

Scenario 2 fails because the wire you have in parallel with the LED provides a path with a very low voltage drop (close to 0V), so the path through the LED with a ~2V voltage drop is not taken (and if you remove the wire, the same reasoning as in scenario 1 applies, so nothing would work).

BTW, you should never run LEDs without a series resistor, as your experiments will surely demonstrate to you soon ;-)