Extracting char array out of function
You should read something about C arrays and how they work. 

Anyway, if you use:

  Change(tabel1);

// ...

void Change(char * tabel)
{
  tabel[0] = 'n';
  tabel[1] = 'b';
}


It'll change passed array because it's passed as pointer to the first element of tabel1.