Zeller's algorithm in Python
def input_value(input_name, prompt, min_num, max_num):


input_name is always a number - why are you calling it a 'name'? Also, there's no need to take it as an argument, since you never use its initial value in your function.

    while True:
        data = raw_input(prompt)
        if data:
            try:
                input_name = int(data)
            except ValueError:
                print 'Invalid input...'


Consider putting a continue here, for clarity. It isn't necessary, though.

            else:
                if input_name &gt;= min_num and input_name &lt;= max_num:


Python understands if min_num &lt;= input_name &lt;= max_num:

                    return input_name
                    break


You don't need break here, the return makes it unreachable.

                input_name = 'Please try again: '


Assigning a string to something that's otherwise always a number is odd, and this value is never used anyway. Nix this line.

        else:
            print 'Goodbye!'
            break


This will end up falling off the end of the function, and so returning None. The rest of your script will continue, but eventually fail horribly. This probably isn't what you want.

month = 0
day = 0
year = 0
century = 0


Only reason to initialise these to 0 is to pass them into input_value, but, as I said above, it never uses the zero values. So, you don't need this.    

month = input_value(month, "Please enter the month (from 1-12, where March is 1 and February is 12): ", 1, 12)


March = 1 is an odd system. Consider inputting it as January=1 and then transforming it with:

# Weirdify month counting
month = month - 2 if month &lt; 3 else month + 10


To not surprise your users.

day = input_value(day, "Please enter the day (from 1-31): ", 1, 31)
year = input_value(year, "Please enter the year (from 0 - 99, eg. 88 in 1988): ", 0, 99)
century = input_value(century, "Please enter the century (from 0 - 99, eg. 19 in 1988): ", 0, 99)


These lines are very long. You should wrap them per PEP8:

 year = input_value("Please enter the century (from 0 - 99, eg. 19 in 1988): ",
                     0, 99)


Also, you might consider inputting year and century as a single value ('1988') and separating it in the script.

A = month
B = day
C = year
D = century


Just use the long names throughout your formulae, eg X = year / 4. 

W = (13*A - 1) / 5
X = C / 4
Y = D / 4
Z = W + X + Y + B + C - 2*D
R = Z % 7

birthday = "You were born on " + str(B) + "/" + str(A+2) + "/" + str(D) + str(C) + " which was a "


Use string formatting instead of concatenation:
    birthday = "You were born on {}/{}/{}, which was a {}{}".format(day, month+2, 
                                                                    century, year)

if R == 0:
    print birthday + 'Sunday'
elif R == 1:
    print birthday + 'Monday'
elif R == 2:
    print birthday + 'Tuesday'
elif R == 3:
    print birthday + 'Wednesday'
elif R == 4:
    print birthday + 'Thursday'
elif R == 5:
    print birthday + 'Friday'
elif R == 6:
    print birthday + 'Saturday'


This can go into a list:

 days = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 
         'Thursday', 'Friday', 'Saturday']
 day_of_week = days[R]


And then that can go in the above string formatting instead of being concatenated on later.