HackerRank, Sherlock and Array
The flaw in your algorithm is that you're summing for each item in each array. That means you get \$O(n^2)\$ for time complexity.

Sum once, then add to the left side whilst removing from the right side. This will give a time complexity of \$O(2n)\$ (once to sum, another to move each element over from the left to the right side).

Additionally, once you have found 1 case in which both sides match, you can stop looking for that testcase.