Summation of primes for large inputs
Your primes_sum function seems to be inspired by the sieve of Erathostenes, but there are a number of things in your implementation that don't work out too well:


Do not remove items from you num_list. That's an expensive operation which basically requires rewriting the whole list. Plus, it makes the following point impossible.
If you have a list of consecutive integers, and you know the position i of a number n, you do not need to do modulo operations to figure out its multiples. Instead, repeatedly add n to i. Addition is much cheaper than modulo.
You don't actually need to have a list of numbers: instead keep a list of boolean values, with their position in the list indicating the number they represent. Ideally this would be a bit array, for maximal memory saving. But a list of Python booleans will save you 4 or 8 bytes per entry already.


A very straightforward implementation of a sieve would look like:

def sum_primes(n):
    sieve = [False, False] + [True] * (n - 1)  # 0 and 1 not prime
    for number, is_prime in enumerate(sieve):
        if not is_prime:
            continue
        if number * number &gt; n:
            break
        for not_a_prime in range(number * number, n+1, number): #If you use range(__, n, __), the function leaves the last Boolean in the sieve list as True, whether or not it is a prime. If you change it to range(__, n+1, __), this problem is taken care of. 
            sieve[not_a_prime] = False
    return sum(num for num, is_prime in enumerate(sieve) if is_prime)


On my system this spits the answer for 2 * 10^6 in under a second, manages to get 2 * 10^7 in a few, and can even produce 2 * 10^8 in well under a minute.