Deleting temporary rows and columns from 21-sheet workbook
Portland Runner gave some good hints in the comments. Your selection and view changes do not add any value to what you want to achieve. I was able to remove all of them without issues. When doing macro-based Excel manipulation, you should always consider:


Setting Application.ScreenUpdating to False
Setting Application.Calculation to xlManual
Setting Application.EnableEvents to False
Resetting all of these values when you have completed the work


Of course, there will be exceptions, but these should be rare.

Always remember Option Explicit in VBA

Looking at absolute values:

For Each xWs In Application.ActiveWorkbook.Worksheets
    xWs.Select
    ViewMode = ActiveWindow.View
    ActiveWindow.View = xlNormalView
    xWs.DisplayPageBreaks = False
    xWs.UsedRange.Value = xWs.UsedRange.Value
Next


This can simply be:

For Each xWs In Application.ActiveWorkbook.Worksheets
    xWs.UsedRange.Value = xWs.UsedRange.Value
Next


Cleaner, easier to see what it does, and easier to maintain.

Looking at Column B conditionals:

For Each xWs In Application.ActiveWorkbook.Worksheets
    xWs.Select
    ViewMode = ActiveWindow.View
    ActiveWindow.View = xlNormalView
    xWs.DisplayPageBreaks = False
    Firstrow = xWs.UsedRange.Cells(1).Row
    Lastrow = xWs.UsedRange.Rows(xWs.UsedRange.Rows.count).Row
    For Lrow = Lastrow To Firstrow Step -1
        With xWs.Cells(Lrow, "B")
            If Not IsError(.Value) Then
                If .Value = "0" Then .EntireRow.Delete
            End If
        End With
    Next Lrow
Next


Can become:

For Each xWs In Application.ActiveWorkbook.Worksheets
    Firstrow = xWs.UsedRange.Cells(1).Row
    Lastrow = xWs.UsedRange.Rows(xWs.UsedRange.Rows.count).Row
    For Lrow = Lastrow To Firstrow Step -1
        With xWs.Cells(Lrow, "B")
            If Not IsError(.Value) Then
                If .Value = "0" Then .EntireRow.Delete
            End If
        End With
    Next Lrow
Next


But I see repetition here. You can save your self a small loop. Admittedly, in the example you gave not a big issue but still a good practice to have.

Combining the loops - take note of the order in which I have done this. Do the most work first, and then do the simple clean-up. You could do it the other way (unless the xlError gets converted to a value on the way through?) but considering how much work is done in each step and how each step impacts on the amount of future work is a good habit.

For Each xWs In Application.ActiveWorkbook.Worksheets
    Firstrow = xWs.UsedRange.Cells(1).Row
    Lastrow = xWs.UsedRange.Rows(xWs.UsedRange.Rows.count).Row ' this is yet another different way I have seen to get the last row!
    For Lrow = Lastrow To Firstrow Step -1 ' Good that you know to go backwards.
        With xWs.Cells(Lrow, "B")
            If Not IsError(.Value) Then
                If .Value = "0" Then .EntireRow.Delete
            End If
        End With
    Next Lrow
    xWs.UsedRange.Value = xWs.UsedRange.Value ' Good that you know the simple way to convert formulas to values.
Next


Deleting extra columns - I see a lot of repetition here, and room for a subroutine.

Private Sub Delete78(xWs as Worksheet) 'Sheet could also include a Chart sheet
    xWS.Columns(8).EntireColumn.Delete
    xWS.Columns(7).EntireColumn.Delete
End Sub


Interestingly, you could also do Col7.Del, and then Col7.Del again to achieve the same effect! But at least the way you have written it shows the intent to remove the two columns.

You main part of the code then becomes:

Delete78 Sheets("IP-FSW")
Delete78 Sheets("IP-2070")
Delete78 Sheets("IP-MNTR")
Delete78 Sheets("IP-BBS")
Delete78 Sheets("IP-DET")
Delete78 Sheets("IP-TTR")
Delete78 Sheets("IP-CCTV")


Still some repetition - and this could be fixed as well. But that can be another day. Or perhaps now. Because your last code block seems different but is really the same. So let us try a new subroutine.

Private Sub DeleteColumnBlock(xWs as Worksheet, LastColumn as Long, FirstColumn as Long) ' Get the user to enter the values in a logical order. I chose this way.
    Dim ColIterator as Long
    ' Do some input validation. If they have entered bad values, fix it.
    For ColIterator = LastColumn to FirstColumn Step -1
        xWs.Columns(ColIterator).EntireColumn.Delete
    Next ColIterator
End Sub


Because we are dealing with a contiguous block, you could also do the slightly more obscure - same effect, but slightly harder to see at a glance what you intend to do. Add some good comments if you intend to do this!

For ColIterator = FirstColumn to LastColumn
    xWs.Columns(FirstColumn).EntireColumn.Delete ' continually remove a column until the right number have been removed.
Next ColIterator


Your main part of that entire block then becomes:

DeleteColumnBlock Sheets("IP-FSW"), 8, 7
DeleteColumnBlock Sheets("IP-2070"), 8, 7
DeleteColumnBlock Sheets("IP-MNTR"), 8, 7
DeleteColumnBlock Sheets("IP-BBS"), 8, 7
DeleteColumnBlock Sheets("IP-DET"), 8, 7
DeleteColumnBlock Sheets("IP-TTR"), 8, 7
DeleteColumnBlock Sheets("IP-CCTV"), 8, 7
DeleteColumnBlock Sheets("IP-Unassigned"), 16, 8


Summary


Turn off the parts of Excel that you don't need when doing grunt
work. 
Try to run through a loop only once, don't repeat your loops
unless it is really really necessary.
DRY (don't repeat yourself) - repetition is a sign that you can
modularise some code making it easier to maintain.
Use explicit addressing, avoid Active and Select unless there is
no other way (e.g. copying sheets to a new workbook is a subroutine,
not a function so ActiveWorkbook is the only way to immediately
reference that new workbook).
-- If you do Activate or Select, make sure your following code is    actually using those elements.
-- And then consider if you can already reference it explicitly and do    so!


Addendum

In my examples above, I provided a very mechanistic way of deleting columns (based on the OP code). Two more ways to do this without using a loop are to set a range:


e.g. xWS.Range(xWS.Cells(1,7), xWS.Cells(1,8).EntireColumn.Delete
Setting a union of the columns, and then deleting