Display Fibonacci numbers
The way sequence is used guarantees that the results will be wrong for the majority of inputs. It's clearly intended that sequence should be a continuous range starting at 0. So rather than require the range as input, it would make more sense to require the limit as input.




        numbers.append(0)
        if i == 0 or i == 1:
            numbers[i] = 1
            continue
        numbers[i] = numbers[i-1] + numbers[i-2]



This confused me briefly until I figured out that it appends 0 as a placeholder and then overwrites it with the appropriate Fibonacci number. Following the principle of KISS (keep it simple), it would make more sense to append the Fibonacci number directly.

IMO the expression is short enough to use a ternary:

        numbers.append(numbers[i-1] + numbers[i-2] if i &gt; 1 else 1)


Those two changes give

def spiral(n):
    numbers = []
    for i in range(n):
        numbers.append(numbers[i-1] + numbers[i-2] if i &gt; 1 else 1)
    return numbers
times = int(input("How many times do you want to go through? "))
fibonacci = spiral(times)
print(fibonacci)




The names seem quite opaque. Why spiral? Why times? They both seem to assume some context which isn't documented in the code.



It would be more Pythonic to write a generator, but since you say you're a beginner this may be a concept which you haven't encountered yet.