Matching and pushing array
You could take advantage of the fact that push accepts more than one argument so you only call push once. Build the arguments array and use apply.

Array.prototype.push.apply($scope.committees, Object.keys(data).map(function(key){
  return data[key];
}));


Or if you're just putting values instead of actually appending to the existing array:

$scope.committees = Object.keys(data).map(function(key){
  return data[key];
});


Now for the AJAX part, you don't need to have a sequential request, that's that last thing you'd want to do in AJAX (besides making them synchronous). You'll need something like Promise.all or jQuery's $.when, fire them at the same time and resolve when all is done.

var comitteePromise = $http({method: 'GET', url: 'data.php'});
var employeePromise = $http({method: 'GET', url: 'data2.php'});

Promise.all([comitteePromise, employeePromise]).then(function(values){
  var committees = values[0];
  var employees = values[1];
  ...
});


The further I look into your code, what you're just doing is merging the data from both arrays. You can build a lookup for one array, and iterate the other. That way, two loops and not to the power of two loops.

var comitteePromise = $http({method: 'GET', url: 'data.php'});
var employeePromise = $http({method: 'GET', url: 'data2.php'});

Promise.all([comitteePromise, employeePromise]).then(function(values){
  var committees = values[0];
  var employees = values[1];

  // Use the committee code (assuming it's unique) as a key for lookup
  var committeesByCode = committees.reduce(function(carry, committee){
    carry[committee.code] = committee;
    return carry;
  }, {});

  // For each employee, lookup the committee and add in the data
  $scope.arr = employees.map(function(employee){
    var committee = committeesByCode[employee.code];
    return {
      committee: committee.name,
      color: committee.color,
      members: committee.members,
      femaleAnnual: employee.femaleAnnual,
      maleAnnual: employee.maleAnnual,
      totalAnnual: employee.totalAnnual
    };
  });

});