Bubble Sort implementation in Java
Efficiency


As someone else mentioned, the inner loop only needs to run up to m-1.
The standard optimization is that if an entire inner loop runs without ever swapping, then the array is now sorted and you can quit early.  Notice how it prints the same thing the last 4 times.


Style


If you've done bullet point 1 above, the only usage of n will be for (int m = n..., so you can just replace that with its definition and get rid of int n = array.length; above.
You don't need to declare 'int k;' at the top, Java is smart enough to make that optimization.  You can just use int k = i + 1;.
In swapNumbers, combine the first two lines into int temp = array[i];


Looking Forward

Right now, it's difficult to reuse bubbleSort because it spews output to the console.  I get that you want to see what it's doing, but once it's working you should take that out.  The sort function should only be responsible for sorting; the user of the function (in this case, the main method) can decide what to do with the results (e.g., print them).

If you want to be able to debug it in the future, then put it behind a debugging flag:

// this goes top-level in the BubbleSort class:
private static final boolean DEBUG = false;
// then, inside bubbleSort:
if (DEBUG)
    printNumbers(array);