Ultra-Beginner Python FizzBuzz ... Am I missing something?
Lose the useless brackets

This:

while (count &lt; 101):


can just be:

while count &lt; 101:


Increment out of the ifs

Wouldn't be easier to do:

count = 0
while count &lt; 101:
    if count % 5 == 0 and count % 3 == 0:
        print "FizzBuzz"
    elif count % 3 == 0:
        print "Fizz"
    elif count % 5 == 0:
        print "Buzz"
    else:
        print count

    count = count + 1    # this will get executed every loop


A for loop will be better

for num in xrange(1,101):
    if num % 5 == 0 and num % 3 == 0:
        print "FizzBuzz"
    elif num % 3 == 0:
        print "Fizz"
    elif num % 5 == 0:
        print "Buzz"
    else:
        print num


I've also renamed count to num since it doesn't count much, is just a number between 1 and 100.

Let's use only one print

Why do 4 different print, when what is really changing is the printed message?

for num in xrange(1,101):
    if num % 5 == 0 and num % 3 == 0:
        msg = "FizzBuzz"
    elif num % 3 == 0:
        msg = "Fizz"
    elif num % 5 == 0:
        msg = "Buzz"
    else:
        msg = str(num)
    print msg


Light bulb!

"FizzBuzz" is the same of "Fizz" + "Buzz".

Let's try this one:

for num in xrange(1,101):
    msg = ''
    if num % 3 == 0:
        msg += 'Fizz'
    if num % 5 == 0:       # no more elif
        msg += 'Buzz'
    if not msg:      # check if msg is an empty string
        msg += str(num)
    print msg


Copy and paste this last piece of code here to see what it does. 

Python is a very flexible and powerful language, so I'm sure there could be other hundred and one different possible solutions to this problem :)

Edit: Improve more

There's still something "quite not right" with these lines:

if not msg:
    msg += str(num)


IMHO it would be better to do:

for num in xrange(1,101):
    msg = ''
    if num % 3 == 0:
        msg += 'Fizz'
    if num % 5 == 0:
        msg += 'Buzz'
    print msg or num


There! Now with:

print msg or num


is clear that num is the default value to be printed.