Issue a citation based on speed, with lenience for your birthday
This function should probably be static, since it does not rely on any instance variables.

On your birthday, your speed can be 5 higher in all cases — so don't make three more cases for the birthday.

If you have already determined that the speed is not &lt;= 60, then there is no point in testing 61 &lt;= speed — that will always be the case.

Since all three branches similarly return an expression, I would use a ternary statement.

public static int caughtSpeeding(int speed, boolean isBirthday) {
    int birthdayAdjustedSpeed = isBirthday ? speed - 5 : speed;
    return (birthdayAdjustedSpeed &lt;= 60) ? 0 :
           (birthdayAdjustedSpeed &lt;= 80) ? 1 :
                                           2;
}