Angular, sort objects by their keys
Object assign via ... operator
There is a sorter way to do the property order if you use the spread operator to assign properties.
function propOrderFirst(key,objects){
     for(var i = 0; i &lt; objects.length; i++){
          objects[i] = {[key] : null, ...objects[i]};
     }
     return objects;
}

The problem is
const objs = [{name: 'name1', phone: 'phone1', email: 'email1'},
        {name: 'name1', phone: 'phone1', email: 'email2'},
        {name: 'name1', phone: 'phone1', email: 'email3'}];

const obj1 = obj[0];

objs = propOrderFirst(&quot;email&quot;,objs);

if(obj1 !== objs[0]) { // true as you have created a new instance 

Reorder in place
But you do lose the object reference that may not be the best option. You can reorder the object properties and still keep the object reference by using delete to remove properties.
A little more complex as you need to delete all the properties you want to move the new property position in-front of
function propOrderFirst(key, objects){
    const keys = Object.keys(objects[0]);  // assuming all objects have same properties
                                           // If not move this inside loop
    for (const object of objects) {
        const temp = {...object};     // get a copy of object
        for (const k of keys) { delete object[k] };  // remove all properties
        object[key] = temp[key];      // add the key you want first
        Object.assign(object, temp);  // assign the objects properties back
    }
    return objects;
 }

So now
const objs = [{name: 'name1', phone: 'phone1', email: 'email1'},
        {name: 'name1', phone: 'phone1', email: 'email2'},
        {name: 'name1', phone: 'phone1', email: 'email3'}];

const obj1 = obj[0];

objs = propOrderFirst(&quot;email&quot;,objs);

if(obj1 === objs[0]) { // true as you have reordered in place }