Calculate how many coins, coin values are 50, 20, 10 and 5
Invalid C code

OP’s C compiler may support various language extensions, but int &amp;amount is not supported in standard C  @Ben Steffan. This makes the code less portable and harder to review.

// void GetNum(int &amp;amount)
// scanf("%d%*c", &amp;amount);
void GetNum(int *amount)  // Let caller pass the address of `amount` instead
scanf("%d%*c", amount);


Lack of error checking/weak end-of-line consumption

scanf("%d%*c", &amp;amount); does not check the return value from scanf().  Should the user enter non-numeric data, nothing is scanned, amount will not be changed and offending input remains in stdin.
Alternative code;

int GetNum(int *amount) {
  printf("Enter an integer between 5 and 95 inclusive:\n");
  char buf[80];
  if (fgets(buf, sizeof buf, stdin)) return EOF;
  char ch;
  // Does input consists of one `int` and not trailing junk?
  if (sscanf(buf, "%d %c", amount, &amp;ch) != 1) return 0; // Invalid input
  return 1; // success;
}


Unneeded ()

// return(change);
return change;


Consider standard true/false and bool.

// #define TRUE 1
// #define FALSE 0
// int Verify(int amount)
//   return FALSE;

#include &lt;stdbool.h&gt;
bool Verify(int amount)
  return false;


See also to use '#include ' in VS 2010
 and We also added the new headers ..., stdbool.h,



Thought for a likely next assignment: 

Consider how to make 60c change when the available coins are only 50c,20c,20c,20c using the below algortim.

fifty = CalcChange(a, 50, 1);
twenty = CalcChange(a, 20, 3);
ten = CalcChange(a, 10, 0);