If Dealer is dealt an ace, and then dealt another card, will he bust?
An Ace has a value of 11, unless it would bust your hand, at which point it becomes 1

Quoting from Wikipedia (due to lack of an official online source for blackjack rules):


  If a player holds an ace valued as 11, the hand is called "soft", meaning that the player cannot go bust by taking an additional card; the value of the ace will become 1 to prevent the hand from exceeding 21. Otherwise, the hand is "hard".


In your example of an Ace an a 2, that's a Soft 13. If you draw another card, and that card would push you past 21, you don't bust because your Ace will now count as a 1.



A common rule for casino tables is that the dealer must hit on a Soft 17 (meaning a hand with a value of 17, containing an Ace valued 11) - if they were operating under rules as suggested in the question, that would make the Ace the worst draw for a dealer (and therefore the casino), as a 17 containing an Ace would mean only a 2, 3 or 4 would not make them bust. It doesn't take a genius to figure out that casinos wouldn't blow themselves out in such a manner.