Do Sulfuric Acid and Calcium Hydroxide Completely Neutralize One Another?
The first proton transfer is simple enough and you have no doubts.

$$\ce{H2SO4 + Ca^2+ + 2 OH- -&gt; HSO4- + Ca^2+ + OH- + H2O}\tag{1}$$

Now, you wonder whether hydrogensulphate is a strong enough acid to combine with the remaining hydroxide. Well, hydrogensulphate may be a weak acid but hydroxide is a strong base. So even the second step will go to completion:

$$\ce{HSO4- + Ca^2+ + OH- + H2O -&gt; SO4^2- + Ca^2+ + 2 H2O}\tag{2}$$

Frankly, it does not end there. Calcium and sulphate form a salt with a very low solubility so this salt will precipitate out of solution.

$$\ce{SO4^2- + Ca^2+ + 2 H2O -&gt; CaSO4 v + 2 H2O}\tag{3}$$

So the only thing you are left with in reasonable amounts is water and a precipitate. This, of course, is a neutral solution.

However, you don’t really always have to go that far. Check if there are strong acids and bases (don’t forget hydroxides), cancel them away and then check what remains. If you had done that, you would have noticed that there are as many hydroxide ions as acidic protons, overall giving an approximately neutral solution.