Nitric acid plus Hydroiodic acid
Nitrate is a strong oxidant which oxidizes the iodide to iodine.

$$\ce{NO_3^- + 2I^- + 2H^+\rightarrow NO_2^- + I_2 \uparrow + H2O}$$

Note that the oxidation number of the nitrogen atom in $\ce{NO3-}$ is $+V$ and in $\ce{NO2-}$ it's $+III$, so over all, we have a reduction equation of:

$$\ce{NO_3^- + 2e^- + 2H^+\rightarrow NO_2^- + H2O}$$

On the oxidation side we want to form $\ce{I_2}$ out of $\ce{I^-}$, so the oxidation equation is:

$$\ce{2I^- \rightarrow I_2 + 2e^-}$$