Identification of solutions by solubility when mixed with each other
Since It is a Homework Question I would Like to add a hint instead of giving full solution.

You might not be able to Watch the difference Carefully.

For Your information

$\ce{PbCl2}$ = insoluble

$\ce{PbSO4}$ = insoluble 

$\ce{AgCl}$ = insoluble 

$\ce{Ag2SO4}$ = slightly soluble 

Try doing it again and watch the difference carefully afterall now you know which one is soluble.

Hope it helps.