What about Miller Indices of planes passing through origin?
Since a comment does not allow the inclusion of a picture, perhaps this way is helpful:

Have a look at the following picture, derived from an illustration about the Miller Indices on wikipedia.  It depicts a simplified situation of a unit cell which may occur if your crystal is of the cubic lattice system, i.e., the three vectors defining the unit cell are orthogonal to each other, and all are of same length. In the drawing, the author choosed $\vec{a_1}$, $\vec{a_2}$, and $\vec{a_3}$ for the unit cell's dimensions.



Not only the plane closest to the coordinate system's origin drawn is a valid Miller plane, equally so the second, farther one drawn.  For each set of Miller indices $(hkl)$, the corresponding Miller planes are parallel to each other.  The distance between these planes depends both on the indices, as well as on the symmetry of the crystal.

Since a crystal consists of many unit cells adjacent to each other, it is perfectly reasonable to draw Miller planes either in "positive direction" along vectors $\vec{a_1}$, $\vec{a_2}$, and $\vec{a_3}$ -- as shown here -- or in opposite direction along $-\vec{a_1}$, $-\vec{a_2}$, and $-\vec{a_3}$ with the same set of $(hkl)$.