What is Meant by Mole Percent?
Eli, you should have read the paper very carefully before asking questions. I think you are very intelligent person, so don't choose easy way out. Now, to answer your question, about mol%. It is right in the paper. As you already figured out and also Orthocresol pointed out in his comment, The amount equals to given mol% is $LR \times \frac{given \ mol\%}{100}$. It is in the General procedure A of given reference:


  Condensations of phenols and naphthols with $\alpha,\beta$-unsaturated ketones. An oven-dried $\pu{25 mL}$ Schlenk tube equipped with a teflon-coated magnetic stir bar was evacuated and purged with argon. The phenol ($\pu{0.2 mmol}$), pentafluorophenylboronic acid ($\pu{8.5 mg}, \ \pu{0.04 mmol}, \ \pu{20 mol\%}$), diphenylphoshinic acid ($\pu{8.7 mg}, \ \pu{0.04 mmol}, \ \pu{20 mol\%}$), $\alpha,\beta$-unsaturated ketone ($\pu{0.4 mmol}$) and heptane ($\pu{1 mL}$) were added to the tube under argon.....


Accordingly, The phenol used: $\pu{0.2 mmol}$ ($LR$), pentafluorophenylboronic acid used: ($\pu{0.04 mmol}$ meaning $0.2 \times \pu{20 mol\%}$), and diphenylphoshinic acid ($\pu{0.04 mmol}$ meaning $0.2 \times \pu{20 mol\%}$).