Are electron orbitals in a helium atom degenerate?
The energy of orbitals for hydrogen atom is dependent only on the principal quantum number: $$E_{n}(\rm{eV})=-\frac{13.6}{n^2}$$
For atoms with more than one electron (all the atoms except hydrogen atom and hydrogenoid ions), the energy of orbitals  is dependent  on the principal quantum number and the azimuthal quantum number according to the equation: $$E_{n,l}(\rm{eV})=-\frac{13.6Z^{*2}}{n^2}$$
Where $Z^{*}$ is the  effective nuclear charge: $Z^{*}=Z-\sigma$. 

where$Z$ is the atomic number and $\sigma (n,l)$ is the screen (shielding) constant and it depends on the principal quantum number and the azimuthal quantum number.

According to this, the atomic orbitals $2s$ and $2p$, that are at the same energy in the case of hydrogen atom, are no longer at the same energy for the atom of helium.