how to remove products from reaction space?(to apply LeChatelier's principle)
The scheme you ask about is effectively the same as $\ce{A &lt;=&gt;[k_1][k_{-1}] B -&gt;[k_2] C}$ where $k_2$ measures the effect of removing B making C the removed product. The actual reaction is much more complicated as presumably mixing/diffusion has to be taken into account. Leaving aside these complications  as $k_2$ increases then the amount of B in the reaction reduces and the amount of C increases if measured at a fixed time. As long as $k_2$ is not zero eventually all B is removed, you can see this in the figure which shows the amount of C for different rate constants $k_2$  assuming the initial amount of A = $1$ and $k_1= 1, \, k_{-1}=3$. When $k_2=0$ (top figure) no product is formed and A and B come to equilibrium. The lower figure show the effects on forming C by removing B.