Adding concentrations to obtain mass
Your working equation is correct.
$$\ce{H2SO4 + 2NaCl -&gt;Na2SO4 + 2HCl}$$


Find the amount of substance of protons of each solution via $n=c\cdot V$.



   $n(\ce{H+})=2~\mathrm{mol}$, $n(\ce{Cl-})=0.25~\mathrm{mol}$



What is the limiting agent?



   Chlorine



How many moles of hydrogen chloride can only be formed?



   $n(\ce{HCl})=0.25~\mathrm{mol}$



Calculate the mass of hydrogen chloride via $m = n\cdot M$



   $M(\ce{HCl})=36.5~\mathrm{g/mol}$, $m(\ce{HCl})=9.1~\mathrm{g}$