Reaction between ruthenium and bleach
This paper actually explain the reason for which ruthenium is vulnerable to bleach. Bleach actually contains $\ce{OCl^-}$ ions which acts as an oxidising  agent and thus oxidises ruthenium. But the research on this phenomenon was done by using sodium hypochlorite, $\ce{NaOCl}$ in presence of a caustic alkali. 

The experiment was done in two-fold process. First only using $\ce{NaOH}$ and the second using both $\ce{NaOCl}$ and $\ce{NaOH}$. In the first attempt, there was nothing occuring. The solutions with  $\ce{NaOH}$ were stable for a considerable time, but after several weeks began to break down, giving a deposit of the black oxide. In the second process, when a little of hypochlorite was given, it gave a orange-red solution as you can see in the above video.



Some more attempts were made by repeating the experiments and found that concentrated alkali hypochlorite more or less dissolved any ruthenium present. From these experiments, the conclusions were made that ruthenium, is rather soluble in concentrated alkaline solutions of hypochlorites and this might help to distinguish ruthenium from other metals. The overall reaction of this process is(from the video):-

$$\ce{Ru + 3NaOCl + 2NaOH -&gt; Na2RuO4 + 3NaCl + H2O}$$

$$\ce{Ru + 7NaOCl + 2NaOH -&gt; 2NaRuO4 + 7NaCl + H2O}$$

$\ce{NaOCl -&gt; 2NaCl + H2O}$ (ruthenate catalyzed)

$$\ce{Na2RuO4 + NaOCl + H2O-&gt; RuO4 + NaCl + 2NaOH}$$