Does removing solution affect a supersaturated solution
When a solution is saturated, the remaining solid is in equilibrium with the solvent:
$$\ce{AB&lt;=&gt;[solv.]A+_{(solv)} + B-_{(solv)}}$$

That means that there is as much of your solid solved. If you take out some of the solution then the concentration remains the same, in your original flask as well as in the portion you withdraw.

If you remove only solvent, i.e. by heating your solution or diffusion over time. In this withdrawn portion crystals will form. The concentration will not change, only the amount of substance $n$ in your solution will change as the volume shrinks ($c=\frac{n}{V}$).