how to calculate mols Ag from AgNO3 solution
If I titrate something with 1 molar AgNO3, adding 50 ml of AgNO3 solution... How would I calculate how many mols of Ag that equates to? 


A 1 molar solution of $\ce{AgNO3}$ is 1 mole per liter. 50 ml is 0.050 liters

$ 1 \dfrac{\text{mole }\ce{AgNO3}}{\text{liter}}\times0.050\text{ liters} = 0.050 \text{ moles }\ce{AgNO3}$


  So then how many mols of Ag are there in 0.05 mol of AgNO3? Is there just 0.05 mols of Ag in AGNO3 or do I need to somehow take into consideration the proportion of the rest of the elements?


$0.050 \text{ moles }\ce{AgNO3}$ is correct since there is only one atom of silver per "molecule" of $\ce{AgNO3}$. There would also only be 0.050 moles of N atoms, but 0.150 moles of O atoms in 0.050 moles of $\ce{AgNO3}$.