I was told that the more exothermic the solution, the more soluble the salt. Is this statement wrong?
Does that mean that I should disregard the statement "the more exothermic the solution, the more soluble the salt."? 


No, based on the Gibbs free energy equation $$\Delta G = \Delta H -T \Delta S$$ and the condition that $\Delta G&lt;0$ for spontaneous dissolution, if you assume $\Delta S$ is constant then the statement is true.

The point of that other post is that as a general rule you should not simply ignore the $\Delta S$ term since sometimes it is the decisive factor determining solubility (such as in the case of endothermic dissolution reaction).