Electroplating a spoon (electrolytic cell) using a electrochemical voltaic cell
Let's start with the last question: The points A and C have the same potential, because we  generally neglect the resistance of the wire. The same argument is valid for points B and D. But according to your scheme, you have a short circuit (as C and D are connected).

Now, to electroplate the spoon, you want the silver to be oxidized at the silver electrode. So, silver electrode is the anode, and must be connected to pole (+) of the voltaic cell (point B):
$$\ce{Ag -&gt; Ag+ + e- }$$
The spoon is the electrode where ion silver will be reduced. So, it's the cathode and must be connected to pole (-) of of the voltaic cell (point A). The electrons enter the cathode and reduced the silver ion according to the equation:
$$\ce{Ag+ + e- -&gt; Ag}$$

So, you're right!