Hydrolysis of Aspartame with a warmed alkali
This looks like it's from an exam so there's a very high possibility that the person setting the question and answer intended the ester group on the right to be something else. I am largely of the opinion that the answer should be A.

However, there is one way I can imagine that you can try justify "B" being the answer (although it is a long shot):


  Under alkali conditions, we can expect the acid group from aspartic
  acid to be deprotonated to carboxylate which can act as an
  intramolecular nucleophile. 
  
  We take note that intramolecular reactions are generally faster than
  intermolecular reactions. The carboxylate can attack either the ester
  group or the amide group. An attack on the amide results in a
  5-membered ring transition state, and an attack on the ester results
  in a 9-membered ring transition state. Since 5-member rings are more
  stable, the carboxylate attacks and breaks bond 1, leaving bond 2
  alone. Aqueous alkali then destroys the acid anhydride that is formed.


That said, this is highly unlikely given that esters are less stable to base-catalyzed hydrolysis than amides. So if Bond 1 Breaks, Bond 2 must have also broken.