Heat Absorption of Liquids
No. 

To answer your question we will assume certain things here.


Assume  $C_p = C_v$ for most liquids, where $C_p$ is the heat capacity at constant pressure, and $C_v$ is the heat capacity at constant volume.
Assume that $C$ is constant with respect to temperature, which is not the case in most real fluids. Here, in order to leave out the integration, we assume that it is a constant. 


Then,

$Q = C\Delta{}T$

As different liquids have different heat capacities, the same amount of heat supplied to the liquid would result in a different $\Delta{}T$, the temperature change.

The higher the heat capacity, the more heat is required to raise a unit mass(or mole) of substance  by a unit temperature. Likewise, more heat has to be removed from the unit mass of substance in order to decrease the temperature by a unit temperature. 

In other words, the higher the heat capacity, the more "reluctant" it is to change its temperature, for the same amount of heat supplied.