Grignard Reagent and Ester
The answer is correct. After the first nucleophilic attack from $\ce{MeMgBr}$, the ethoxy group left and the ester is transformed into a ketone (Step 2 in the link), then another $\ce{MeMgBr}$ attacks and introduce an extra methyl group, resulting in a $3^\circ$ alcohol after hydrolysis. The process is well described in this page.