Difference between exothermic and exergonic
The classifications endothermic and exothermic refer to transfer of heat $q$ or changes in enthalpy $\Delta_\mathrm{R} H$. The classifications endergonic and exergonic refer to changes in free energy (usually the Gibbs Free Energy) $\Delta_\mathrm{R} G$.


If reactions are characterized and balanced by solely by heat transfer (or change in enthalpy), then you're going to use reaction enthalpy $\Delta{}_{\mathrm{R}}H$.  

Then there are three cases to distinguish:


$\Delta{}_{\mathrm{R}}H &lt; 0$, an exothermic reaction that releases heat to the surroundings (temperature increases) 
$\Delta{}_{\mathrm{R}}H = 0$, no net exchange of heat  
$\Delta{}_{\mathrm{R}}H &gt; 0$, an endothermic reaction that absorbs heat from the surroundings (temperature decreases)


In 1876, Thomson and Berthelot described this driving force in a principle regarding affinities of reactions. According to them, only exothermic reactions were possible.

Yet how would you explain, for example, wet cloths being suspended on a cloth-line -- dry, even during cold winter? Thanks to works by von Helmholtz,  van't Hoff, Boltzmann (and others) we may do. Entropy $S$, depending on the number of accessible realisations of the reactants ("describing the degree of order") necessarily is to be taken into account, too. 

These two contribute to the maximum work a reaction may produce, described by the Gibbs free energy $G$. This is of particular importance considering reactions with gases, because the number of accessible realisations of the reactants ("degree or order") may change ($\Delta_\mathrm{R} S$ may be large).  For a given reaction, the change in reaction Gibbs free energy is $\Delta{}_{\mathrm{R}}G = \Delta{}_{\mathrm{R}}H - T\Delta{}_{\mathrm{}R}S$.

Then there are three cases to distinguish:


$\Delta{}_{\mathrm{R}}G &lt; 0$, an exergonic reaction, "running voluntarily" from the left to the right side of the reaction equation (react is spontaneous as written)
$\Delta{}_{\mathrm{R}}G = 0$, the state of thermodynamic equilibrium, i.e. on a macroscopic level, there is no net reaction or
$\Delta{}_{\mathrm{R}}G &gt; 0$, an endergonic reaction, which either needs energy input from outside to run from the left to the right side of the reaction equation or otherwise runs backwards, from the right to the left side (reaction is spontaneous in the reverse direction)


Reactions may be classified according to reaction enthalpy, reaction entropy, free reaction enthalpy -- even simultaneously -- always favouring an exergonic reaction:


Example, combustion of propane with oxygen, $\ce{5 O2 + C3H8 -&gt; 4H2O + 3CO2}$. Since both heat dissipation ($\Delta_{\mathrm{R}}H &lt; 0$, exothermic) and increase of the number of particles ($\Delta_{\mathrm{R}}S &gt; 0$) favour the reaction, it is an exergonic reaction ($\Delta_{\mathrm{R}}G &lt; 0$).
Example, reaction of dioxygen to ozone, $\ce{3 O2 -&gt; 2 O3}$. This is an endergonic reaction ($\Delta_{\mathrm{R}}G &gt; 0$), because the number of molecules decreases ($\Delta_{\mathrm{R}}S &lt; 0$) and simultaneously it is endothermic ($\Delta_{\mathrm{R}}H &gt; 0$), too.
Water gas reaction, where water vapour is guided over solid carbon $\ce{H2O + C &lt;=&gt; CO + H2}$. Only at temperatures $T$ yielding an entropic contribution $T \cdot \Delta_{\mathrm{R}}S &gt; \Delta_{\mathrm{R}}H$, an endothermic reaction may become exergonic.
Reaction of hydrogen and oxygen to yield water vapour, $\ce{2 H2 + O2 -&gt; 2 H2O}$.  This is an exothermic reaction ($\Delta_{\mathrm{R}}H &lt; 0$) with decreasing number of particles ($\Delta_{\mathrm{R}}S &lt; 0$). Only at temperatures at or below $T$ with $|T \cdot \Delta_{\mathrm{R}}S| &lt; |\Delta_{\mathrm{R}}H|$ there is a macroscopic reaction.  In other words, while the reaction works fine at room temperature, at high temperatures (e.g. 6000 K), this reaction does not run.


After all, please keep in mind this is about thermodynamics, and not kinetics. There are also indications of spontaneity of a reaction.