What are the steps to integrate the common rate law to find the integrated rate law for any order
The integrated rate laws can be derived by equating two expressions for the rate of the reaction. This gives us a first order differential equation which can be manipulated to get the integrated rate law. The steps that you need to follow are actually quite simple and structured. Here is an example for deriving the first order integrated rate law:

Step 1: Equate the two expressions for the rate of the reaction

For first order reactions, the two expressions for the rate of the reaction are: $$ r = -\frac{\mathrm{d}[A]}{\mathrm{d}t}$$ and $$r = k[A]$$ Equating them we get: $$-\frac{\mathrm{d}[A]}{\mathrm{d}t} = k[A]$$ 

Step 2: Rearrange so that all the same variables are on the same side to form an first order differential equation

So we rearrange this expression to get all of the same variables on the same side (note that k is a constant, not a variable, so it doesn't matter which side it is on) to get: $$\frac{\mathrm{d}[A]}{[A]} = -k\mathrm{d}t$$ 

Step 3: Integrate both sides

Now we integrate both sides: $$\int_{[A_0]}^{[A]}{\frac{\mathrm{d}[A]}{[A]}} = -\int_{t_i}^{t_f}k\mathrm{d}t$$
$$\mathrm{ln}[A] - \mathrm{ln}[A_0] = -kt$$

Step 4: Using some algebraic manipulation, rearrange expression to get an equation for [A]
$$\mathrm{ln}\frac{[A]}{[A_0]} = -kt$$
$$\frac{[A]}{[A_0]} = \mathrm{e}^{-kt}$$ Therefore we get as required:
$$[A] = [A_0]\cdot e^{-kt}$$

Using this guide, you should be able to derive the other integrated rate laws. If you have any trouble, feel free to ask. 

Edit:

Since you have also mentioned that you are struggling with deriving the second order integrated rate law, I will show you how to derive it, using the steps that I have outlined above.

Step 1:

$$r = - \frac{\mathrm{d}[A]}{\mathrm{d}t} = k[A]^2$$

Step 2:

$$\frac{\mathrm{d}[A]}{[A]^2} = -k\mathrm{d}t$$

Step 3:

$$\int_{[A]_0}^{[A]}\frac{\mathrm{d}[A]}{[A]^2} = \int_{t_i}^{t_f}k\mathrm{d}t$$

$$\frac{-1}{[A]} + \frac{1}{[A]_0} = -kt$$

Step 4:

Okay now everything up to here has been exactly the same thing we did for deriving the first order integrated rate law. We have gotten an equation relating $[A], [A]_0$ and $t$. To make $[A]$ the subject, we multiply by $[A]$ and put all the terms containing $[A]$ on one side:
$$\frac{[A]}{[A]_0} + kt[A] = 1$$ Now we factorise $[A]$ out on the left hand side and divide both sides so that the left hand side equals to $[A]$:
$$[A]\left(\frac{1}{[A]_0} + kt\right) = 1$$
$$[A] = \frac{1}{\frac{1}{[A]_0} + kt}$$
Now we multiply the right hand side by $[A]_0$/$[A]_0$ and we get the required equation: 
$$[A] = \frac{[A]_0}{1 + kt\dot~ [A]_0}$$