Help balancing reaction between Iron (II) chloride and potassium phosphate
This question was the continuation of your question and since both question are related,  I am answering the question by emphasizing the mistake you are doing and adding a relevant portion to explain it. 



Mistake:

Iron(II) chloride and potassium phosphate react. Write and balance the molecular, ionic, and net ionic equations.

You need to consider potassium phosphate to be $\ce{K3PO4}$ not $\ce{KH2PO4}$ according to IUPAC's Red book (see sections IR-8.2 and IR-8.4 and the anions in question are explicitly named in table IR-8.1 therein.)

If $\ce{KH2PO4}$ is meant to be added, the correct term should be potassium dihydrogenphosphate.



Extra info.:

Iron hydrogen phosphate are new in this world and has been recently synthesised and as not as stable as iron phosphates. So, only iron (II and  III) phosphate and potassium chloride forms from the reaction.

$$\ce{3FeCl2 + 2K3PO4 ⟶ Fe3(PO4)2 + 6KCl}$$

$$\ce{Fe3(PO4)2 -&gt;[air oxidn⋅,400C] FePO4}$$

or actually 

$$\ce{4Fe3(PO4)2 + 3O2 -&gt;[400 C] 8FePO4 + 2Fe2O3}$$



Iron hydrogen phosphate can be made by reacting iron(II) phosphate with dilute hydrochloric acid.

$$\ce{Fe3(PO4)2 + 2HCl → 2FeHPO4 + FeCl2}$$