Need for enthalpy of vaporization in calculating bond dissociation enthalpy
Well, I think that you have to look up the actual way bond dissociation enthalpy is defined in your textbook/lecture notes, since it is a not quite standard term. IUPAC defines only bond-dissociation energy but not enthalpy.

bond-dissociation energy, $D$
The enthalpy (per mole) required to break a given bond of some
specific molecular entity by homolysis, e.g. for $\ce{CH4 -&gt; .CH3 + H.}$, symbolized as $D(\ce{CH3−H})$ (cf. heterolytic bond dissociation energy).

Many resources on the Internet claim that the IUPAC definition of the bond-dissociation energy refers to $\pu{0 K}$ (see e.g. Wikipedia, UC Davis ChemWiki) and that it differs from bond dissociation enthalpy, which refers to the enthalpy change at room temperature ($\ce{298K}$).
Wikipedia

The bond-dissociation energy is sometime also called the
bond-dissociation enthalpy (or bond enthalpy), but these terms are not
strictly equivalent, as they refer to the above reaction enthalpy at
standard conditions, and differ from $D_0$ by about $\pu{1.5 kcal mol-1} \pu{(6
kJ mol-1)}$ in the case of a bond to hydrogen in a large organic molecule.

UC Davis ChemWiki

Officially, the IUPAC definition of bond dissociation energy refers to
the energy change that occurs at $\pu{0 K}$, and the symbol is $D_0$. However,
it is commonly referred to as BDE, the bond dissociation energy, and
it is generally used, albeit imprecisely, interchangeably with the
bond dissociation enthalpy, which generally refers to the enthalpy
change at room temperature ($\pu{298K}$). Although there are technically
differences between BDEs at $\pu{0 K}$ and $\pu{298 K}$, those difference are not
large and generally do not affect interpretations of chemical
processes.

If we follow this definitions, then yeah, at standard conditions $\ce{HBr}$ is liquid so we have to add up $\pu{12 kJ mol-1}$ for its enthalpy of vaporization, and (almost) get the desired $\pu{364 kJ mol-1}$. The small discrepancy is probably due to slightly wrong value of enthalpy of vaporization which I just quickly found somewhere.