Nitration of N-phenylbenzamide
You should not be looking at $\ce{-NH-CO\bond{-}}$ as two different functional groups i.e. as $\ce{-NH-}$ and $\ce{-CO-}$.

Since as in $\ce{-(NH-CO)\bond{-}}$: $\ce{N}$'s lone pair are actually in resonance with the carbonyl group.

The left handed phenyl ring is more activated than the right handed phenyl ring. Hence the electrophile would preferentially attack on the left handed phenyl ring.

The amide group is too weak base to be protonated by the acid and therefore it does not direct the electrophile to meta position.

Ortho position is hindered due to steric hindrance of the another phenyl ring.

And therefore


   the attack takes place at para position of the left handed phenyl ring


so answer should be option B.