Galvanic Cells, theoritical voltage
$$Pb^{2+} + 2e^{-}-&gt;Pb  E_{0}(Pb^{2+}) = -0.1263$$
$$Zn-&gt;Zn^{2+} +2e^{-}   E_{0}(Zn^{2+}) = -0.76 $$

$$[Zn^{2+}] = 0.1 mol/L [Pb^{2+}] = 10^{-4} mol/L$$

$$Qc= \frac{[Zn^{2+}]}{[Pb^{2+}]}$$
$$E_{0}(cell) = E_{0}(Pb^{2+})- E_{0}(Zn^{2+})= -0.1263 - (-0.76) $$
$$ E(cell)= E_{0}(cell) - \frac {RT ln Q_{c}}{nF}$$

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