Find the structural compound from carbon and proton NMR spectrum
Interesting Problem and quite a nailbiter.
I will try to sort some of my ideas, even thought this won't be a full answer.

This looks like a question from an exam. Did you have any reactions during study with hydrochloric acid and propanoyl chloride (acid chloride of propionic acid). So maybe look into different reactions of acid chlorides.
As @MethewMahindaratne mentioned, it is hard without integration but for carbon we dont need integration. We have 7 Carbons, some hydrogen, pretty sure some oxygen and for sure some nitrogen. Why? Because only nitrogen is able to produce odd numbered masses. If we have CH compound, there will be always an even number of hydrogens and carbon has a mass of 12  so overall its even. When we create double bonds or add oxygen, the amount of hydrogen is decreased by 2 so it remains uneven. Only with nitrogen, we can add 1 hydrogen per nitrogen, therefore we have 1 or 3 or 5 etc. nitrogens in it.
The proton g is also quite specific. This high shift in proton NMR usally comes from a carboxylic group. So we have $C_7O_2H_xN_y$.The idea of the carboxylic group is also supported by the C atom at 175 which is a really high shift.
With a molecular mass of 201 g/mol this leaves quite some but not endless options. We can take of 7 x 12 (for the seven carbons) and 2 x 16 (for oxygen carboxylic group) and 1 (for hydrogen carboxylic group) leaving us with a mass of 84 split along oxygen, hydrogen and nitrogen.
This is a lot. On the bottom line it is mentioned, that W consists of certain things. halogenides which usally make compounds heavy are not included there.
Appart from the carboxylic group we are left with 6 carbons which could give the idea of a benzene. But I think it is not benzene because we could only attach $NH_2$ or $OH$ groups onto it and even with 5 $NH_2$ groups we get not enought mass. In addition, aromatic C atoms have high shifts usally 120-150. But we only have 3 others (next to our carbon from the carboxylic group) so not enought for a six membered ring.
But also not enought for just one alkene which I would prefer. Alkene shift ist around 110-140 and fits well.
Now that is all I could provide without crazy speculations.

I can throw in some suggestions but they are realy wild and you need to look in deeper.

The big peek a looks a bit like some alkohols I worked with so maybe a hydroxylic group?
Maybe Carbon Atom u contains 2 or even 3 peaks? (the line looks thicker than the others)= that would contribute to the idea of a substituted benzene ring and provide more carbons so we could add other groups.
Could $H_f$ be two dupletts instead of a quartett so that could come from a double bond?
With integrals you could look at the singuletts and determine wheather it is an amine (singulett with an integrall of 2)
Maybe my whole carbon acid idea is wrong and it is an ester or something.
If we are allowed to include hallogens, then it is pretty sure a benzene with a carboxylic group maybe hydroxylic and a hallogen atom.
If you have more information, maybe you can use the sdbs data base https://sdbs.db.aist.go.jp
I was not able to find an entry that fits.

Hope this brings the project forward.I am very happy to hear, what the compound was when you get a result.