Relating change in internal energy and to that in enthalpy
You are right. B is the correct choice.

$$\Delta H = \Delta E + \Delta PV$$

Since $\Delta E $ is more negative than $\Delta H$, $$\Delta H &gt; \Delta E$$.
Hence $$\Delta PV&gt;0$$

$\Delta E \space $has to be negative. So option A is ruled out.

Among the other choices, B is the only one where number of gaseous moles are increasing from left to right, leading to a positive value of $\Delta V$ and hence $\Delta PV$.