Effect of substituents on Ullmann reaction
I think that the answer given in your textbook is wrong as they are trying to conduct ULLMANN reaction on a chloride a strong EWD needs to be present at the ortho/para positions for the reaction to be feasible. 

There Are generally 2 Mechanisms Proposed for the reaction :


Free Radical Mechanism
Ionic Mechanism



  FREE RADICAL MECHANISM
  The Copper Metal (used as catalyst) Generate a Aryl Radical By transferring a electron, and then 2 Aryl Radical combine to form the final product.
  
  
  IONIC MECHANISM
  Acording to this a Organometalic intermideate of Aryl copper halide is fromed. The copper is added to the Aryl halide by Oxidative addition. then a electron is transfered to the intermidiate to for a organocuppric radical which again perform the oxidative addition on another aryl halide which result in formation of a biaryl copper complex which in turn undergo reductive elimination and make the final product. 
  


You can easily see that we need a EWG to make the Reagent more reactive thus making the reaction feasible thus your answer must be either wrong or you might have checked it wrong. nevethless I also find this paper affirming mine and your belief.

Source:


https://link.springer.com/article/10.1007/s40828-016-0036-2
www.name-reaction.com/ullmann-reaction