What happens to a radioactive carbon dioxide molecule when its carbon-14 atom decays?
An article by Snell and Pleasanton, 'The Atomic and Molecular Consequenses of Radioactive Decay', (J. Phys. Chem., 62 (11), pp 1377–1382, $1958$) supports Ben Norris's comment.


  It is clear ... that $\ce{^{14}CO2}$ remains predominantly bound as $\ce{NO2+}$, a result that is perhaps not surprising. [This occurs in] $81$% of the decays. In $\ce{^{14}CO2 -&gt; NO2^+}$ dissociation yielding $\ce{NO+}$, $\ce{O+}$ and $\ce{N+}$ follows [in], respectively, $8.4$, $5.9$, and $3.6$% of the decays.


A table summarising the results is given.

$$\begin{array}{|c|c|}
\hline
\mathbf{Ion} &amp; \mathbf{\%\  abundance} \\
\hline
\ce{NO2+} &amp; 81.4(16) \\
\ce{NO+} &amp; 8.4(4) \\
\ce{O+} &amp; 5.9(6)  \\
\ce{N+} &amp; 3.6(4) \\
\ce{NO2^{2+}} &amp; 0.40(06)\\
\hline
\end{array}$$