Side product obtained in reduction of cuprous oxide with carbon
@ Paras Khosla. Your first equation is correct, but not your second one : $\ce{Cu_2O}$ reacts with $\ce{C}$ without getting decomposed previously into $\ce{Cu + O_2}$. $\ce{Cu_2O}$ is more stable than $\ce{CuO}$ above $1000$°C
Furthermore, $\ce{Cu_2O}$ does not react easily with Carbon in the solid state. The contact between the reacting solids is not good. The contact is better if $\ce{Cu_2O}$ is liquid. But $\ce{Cu_2O}$ melts at $1026$°C. So, the reaction starts at this temperature, forming $\ce{CO}$ which is more stable than $\ce{CO_2}$ at such a high temperature.