How does Al-Hg react with carbonyl in presence of concentrated HCl?
In comparision to Clemmensen reduction, both $\ce{Na-Hg}$ and $\ce{Al-Hg}$ cannot be used as direct substitutes for $\ce{Zn-Hg}$.
Reaction with $\ce{Na-Hg}$ amalgam:
$\ce{Na-Hg}$ amalgam is also a good reducing agent and is capable of reducing ketones/aldehydes to alcohols1. However, Do not use conc. $\ce{HCl}$ with $\ce{Na-Hg}$ amalgam, as there would be a vigorous reaction between the acid and the sodium in the amalgam. Instead, use an organic solvent such as absolute alcohol.
The mechanism for this reduction is a bit different than standard Clemmensen reduction:

\begin{align}
\ce{2(C6H5)2CO +2Na &amp;-&gt;2(C6H5)2C-ONa} \\
\ce{2(C6H5)2C-ONa&amp;&lt;=&gt;(C6H5)2C(ONa)-C(C6H5)2-ONa\tag{1}} \\
\ce{2(C6H5)2C-ONa + 2C2H5OH &amp;-&gt; 2(C6H5)2C-OH + 2C2H5ONa} \tag{2a} \\
\ce{2(C6H5)2CO &amp;-&gt; (C6H5)2CO +(C6H5)2CHOH \tag{2b}}
\end{align}

Reaction with $\ce{Al-Hg}$ amalgam:
Aluminium amalgam, like Sodium amalgam, vigorously reacts with water, and you cannot use concentrated $\ce{HCl}$ with it. With ethanol as a solvent, it is a mild reducing agent, can reduce cycloalkanones and aldehydes to alcohols. Acyclic ketones remain almost inert2



In some cases, it behaves similarily to $\ce{Mg-Hg}$ amalgam and promotes dimerization of ketones to form pinacols. Thus, your reaction would not take place, and instead pinacol would be the major product.



This question and this one cover some other reduction uses of $\ce{Al-Hg}$, such as reduction of imines to amines.
References:

Bachmann, W. E. “The Mechanism of Reduction by Sodium Amalgam and Alcohol. I. The Reduction of Aromatic Ketones to Hydrols.” Journal of the American Chemical Society, vol. 55, no. 2, Feb. 1933, pp. 770–74. doi:10.1021/ja01329a051.
Troyansky, Emmanuil I., and Meghan Baker. “Aluminum Amalgam.” Encyclopedia of Reagents for Organic Synthesis, John Wiley &amp; Sons, Ltd, 2016, pp. 1–6. doi:10.1002/047084289X.ra076.pub2.