Identification of an unknown organic molecule from only 1H NMR and 13C NMR
The doublet at $4.2\ \mathrm{ppm}$ is almost assuredly an alcohol group or ether group.  Since we only have one carbon that is bonded to an oxygen at $59\ \mathrm{ppm}$, we conclude this is a primary alcohol. The situation of being a doublet says smoething else is lurking around.

$5.4\ \mathrm{ppm}$ is far enough down field, we start thinking alkenes, but the multiplicity is mysterious for the moment.

$1.68\ \mathrm{ppm}$ and $1.75\ \mathrm{ppm}$ are in the range of allyl methyl groups, and the carbon signals are okay with this as well.  Additionally singlets for these groups indicate a geminal dimethyl compound with a third substituent on an alkene justifying different chemical shifts.

Finally the peak at $1.16\ \mathrm{ppm}$ is difficult to explain.  However, we know we have an alcohol, and they can have a fairly wide range of values.  If this peak is broadened at all, I would immediately assign it to the alcohol.  It being a singlet is also worrisome, but if exchange is occurring, this is not out of the question.

The multiplicity of the alkene proton indicates there are some long-range things going on, and these don't always resolve well.   My guess is you are picking up some long-range coupling and is not resolving nicely in the methyl groups, which appear to be singlets.