What will be the product of this reaction?
This reaction is one of a special kind. The one and onlyend product is 3-hydroxy,3- methylcyclohexan-1-one. As the Grignard reagent is in excess, and it is an $\alpha$- $\beta$ unsaturated ketone, there is a possibility of undergoing two different type of reaction mechanisms. But Surprisingly, both will give the same ultimate end product after two steps.   The major mechanism through which the reaction should undergo, is the direct nucleophilic attack of the grignard reagent at the electrophilic carbonyl carbon. As, Grignard reagent is a hard base , it's attack to hard acid centre of carbonyl carbon is more preffered. So, first it will undergo this addition after which it acidic hydrolysis is done, which cleaves the ether and forms an enol which tautomerises to give the final end product ketone. The reaction scheme is shown below, 

Now, the minor mechanism is the process of conjugated addition of the methyl group to that $\alpha$-$\beta$ unsaturated ketone. But again after tautomerisation and  hydrolysis it actually forms the same compound, which is 3-hydroxy,3-methyl cyclohexan-1-one. The reaction scheme is shown below,

So, it is seen that however the presence of excess reagent may interfere with the reaction mechanism but the end product is $100 $$\%$ $3$-hydroxy,$3$-methylcyclohexan-$1$-one.