Non-bonding molecular orbital in triatomic hydrogen
In order to draw the MO diagram for the H3+ system, it helps to first thing about the MO diagram for a simple diatomic case, and then mix in the additional s-orbital. 

The diagram below hopefully illustrates this technique (and can be found in many introductory textbooks). 



First consider two s-orbitals (the right hand side of the diagram). They can either mix in a symmetric (in phase) or anti-symmetric (out of phase) combination. 

The two atomic orbitals we initially combine can give rise to two molecular orbitals, as shown on the right hand side. 

We can give them symmetry labels to help us identify what kinds of things these molecular orbitals can then combine with to form the new molecular orbitals for the triatomic system. 

The labels g and u are related to whether the molecular orbital is symmetric or anti-symmetric with respect to an inversion centre. 

Once our two molecular orbitals for the diatomic system are formed, we can mix these orbitals with another hydrogen s-orbital in order to generate the final MO diagram as per your question.

Only the g molecular orbital from the diatomic system is of the correct symmetry to interact. This mixing creates two molecular orbitals (the top and bottom ones) for the triatomic system. The middle, non-bonding molecular orbital is simply the orbital of u symmetry from the initial diatomic system, which is unable to interact since there is nothing of the correct symmetry for it to do so.