Grignard reaction with cycloheptatriene
The product A, shown below, is formed by first reducing the ketone to a secondary alcohol with $\ce{LiAlH_4}$ and then by adding a methyl group to form an ether using the reagent $\ce{CH_3I}$.
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Next the grignard reaction with product A will form two products. The grignard reagent $\ce{MeMgI}$ can attack A in a $1$,$2$ or in a $1$,$4$ mode, due to the unique aromaticity of cycloheptatriene, giving a mixture of products B and C, the structures of which are shown below.
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