Change in internal energy of a gas upon expansion against a constant external pressure
You did everything correctly with the exception of converting the units of your result for work.

First, calculate the work in joules:

$$w = -p\Delta V = (-2\,\mathrm{atm}) \times 9\,\mathrm{L} =
\left(-18\,\mathrm{L\cdot atm}\right) 
\left({101.325\,\mathrm{J}\over\mathrm{L\cdot atm}}\right) = -1823.85\,\mathrm{J}$$

Second, add the heat absorbed (already in joules):

$$\Delta E = 200\,\mathrm{J} - 1823.85\,\mathrm{J} = -1623.85\,\mathrm{J}$$

Third, always remember to check your units!