Change in volume of two beakers on reaching equilibrium
Okay, so you know that the vapor pressure of the pure water is some value, $p_w$. And you know from Raoult's Law that a solution with a nonvolatile solute of mole fraction $\chi_s$ will have a vapor pressure $p=p_w \chi_w$, where $\chi_w = 1- \chi_s$, so $p=p_w(1-\chi_s)$.

Since $\chi_s &lt;1$, then $p &lt; p_w$. How do you use this information?

Well, as the system approaches equilibrium, the two beakers will want to exchange water through the vapor phase to equilibrate the vapor pressures. What will that look like when it happens?  Can it happen?

By this logic, you can determine where the water is in your system. However, you cannot determine the volume(s) in the beakers without the following additional information:


Volume of the enclosing vessel - helps determine what mass of water remains in the gas phase
Temperature of the system - determines initial vapor pressure of pure water
Concentration of the sugar solution. 
The non-ideal behavior of the sugar-water solution's volume.