Adiabatic compressibility factor of ethyl alcohol
A calculation using the NIST Reference Fluid Thermodynamic and Transport Properties Database (REFPROP) – NIST Standard Reference Database 23, Version 9, and assuming a temperature of $T=15.5\ \mathrm{^\circ C}$ and a pressure of $p=1\ \mathrm{bar}$, yields an isothermal compressibility of ethanol of
$$\varkappa_T=-\frac1V\left(\frac{\partial V}{\partial p}\right)_T=1.0795\times10^{-9}\ \mathrm{Pa^{-1}}$$
and an adiabatic (or isentropic) compressibility of
$$\varkappa_S=-\frac1V\left(\frac{\partial V}{\partial p}\right)_S=9.1749\times10^{-10}\ \mathrm{Pa^{-1}}$$
The number of digits is the default setting of the software and does not necessarily correspond to the number of significant digits.

By way of comparison, the results for a temperature of $T=20\ \mathrm{^\circ C}$ and a pressure of $p=1\ \mathrm{bar}$ are
$$\varkappa_T=1.1130\times10^{-9}\ \mathrm{Pa^{-1}}$$
and
$$\varkappa_S=9.4729\times10^{-10}\ \mathrm{Pa^{-1}}$$
The data in “Pressure and Temperature Dependence of Liquid Density”, in CRC Handbook of Chemistry and Physics, 90th Edition (CD-ROM Version 2010), David R. Lide, ed., CRC Press/Taylor and Francis, Boca Raton, FL include a value of $\varkappa_T=1.119\times10^{-9}\ \mathrm{Pa^{-1}}$ for $T=20\ \mathrm{^\circ C}$. Therefore, it seems a likely supposition that the corresponding calculation result of $\varkappa_T=1.1130\times10^{-9}\ \mathrm{Pa^{-1}}$ is reasonable but the number of digits is excessive.