How can I recover PbNO3 from PbI2?
The reaction is given here.

$$\ce{3PbI2 + 8HNO3 -&gt;[\Delta] 3Pb(NO3)2 + 3I2 + 2NO + 4H2O}$$


  Lead(II) iodide react with nitric acid to produce  lead(II) nitrate,
  iodine, nitrogen monoxide and water. Nitric acid - 30% solution. The
  reaction takes place in a boiling solution.