Major product of radical fluorination vs bromination
There is nearly no thermodynamic aspect to this reaction. The activation energy for any alkane hydrogen abstraction by a fluorine radical is essentially 0$^{[1]}$. This means that there is an equally likely chance of fluorinating at any given position. In this case, we need only know the proportions of homotopic hydrogen. Homotopic hydrogen are labelled with the same colors in the molecule:



The proportion in decreasing order is 9:6:1:1:1. That means that we should expect about the following yield of monofluorinated products:



As an aside, you would never realistically expect to obtain a monofluorinated product. The fluorination of alkanes is violent, extremely fast, and only gets faster upon fluorination.




$^{[1]}$ Chemistry StackExchange, Why are free radicals so reactive?