NCl₃ + H₂O → NH₃ + HOCl , the resulting solution is acidic, basic or neutral?
Here's our initial reaction, $$\ce{NCl3 + 3H2O -&gt; NH3 + 3HOCl}$$ $\ce{NH3}$ is a weak base and $\ce{HOCl}$ is a weak acid, but there is more of the acid, so at this point the solution would be mildly acidic. However $\ce{NH3}$ and $\ce{HOCl}$ are known to react as follows $$\ce{NH3 + HOCl-&gt;NH2Cl + H2O}$$ and in aqueous solution the resultant chloramine can decompose as shown in the following equation $$\ce{3 NH2Cl ⟶ N2 + NH4Cl + 2 HCl}$$  Clearly, an acid is generated in this last reaction.  So although the initial products are neutral, eventually the solution will be strongly acidic.