Is Neutron radiation considered electromagnetic wave?
Electromagnetic radiation consists of electromagnetic waves (oscillations of the electric and magnetic field), whereas corpuscular radiation consists of actual particles. Certainly, wave–particle duality can make the distinction between waves and particles fuzzy. However, electromagnetic radiation (whether described as wave or as photons) is massless (its invariant mass is zero) and it travels at the speed of light. In contrast, the particles of corpuscular radiation have a non-zero mass and therefore a velocity below the speed of light. The particles of corpuscular radiation can be charged positively (e.g. α particles) or negatively (e.g. β− particles), or they can have no charge at all.

Neutron radiation is a corpuscular radiation because it consists of particles (i.e. neutrons). Neutrons are subatomic particles with no charge and a mass of $m=1.674\,927\,471(21) \times 10^{-27}\ \mathrm{kg}$ [source], which is slightly larger than the mass of a proton.

The kinetic energy of free neutrons can vary significantly. For example, the so-called fast neutrons, which are released during nuclear fission, have energies above $E_\text{kin} = 1\ \mathrm{MeV} \approx 1.6 \times 10^{-12}\ \mathrm{J}$. The thermal neutrons, which are used to initiate nuclear fission in moderated reactors, have energies below $E_\text{kin} = 0.1\ \mathrm{eV} \approx 1.6 \times 10^{-20}\ \mathrm{J}$.

Since, in classical mechanics, kinetic energy $E_\text{kin}$ is
$$E_\text{kin} = \tfrac{1}{2}mv^2$$
where $m$ is mass and $v$ is velocity,
the velocity of a neutron with a kinetic energy of $E_\text{kin} = 0.1\ \mathrm{eV} \approx 1.6 \times 10^{-20}\ \mathrm{J}$ may be estimated as
$$\begin{align}
v &amp;= \sqrt {2\frac{E}{m}}\\[6pt]
&amp;= \sqrt {2\frac{1.6 \times 10^{-20}\ \mathrm{J}}{1.674\,927\,471 \times 10^{-27}\ \mathrm{kg}}}\\[6pt]
&amp;= 4.4\times 10^3\ \mathrm{m\ s^{-1}}
\end{align}$$
which is clearly less than the speed of light.