Reverse Cannizzaro reaction to make aldehydes?
No, this is not practicable because aldehydes are higher in free energy than either alcohols or acids.  Thus, the equilibrium constant of the Cannizaro reaction lies strongly against the aldehydes.

The case of formaldehyde may be even more extreme than the example reaction you gave, but it is what I could find data for.

The eQuilibrator database lists the equilibrium constant for the reaction of

$$\ce{2 HCHO + H2O &lt;=&gt; CH3OH + HCOOH}$$

as $$K'_{eq} = 3.4 × 10^{13}$$  

This is for each reactant at 1 mM in concentration, at pH 7 and an ionic strength of 0.1 mol / L.  Thus, you'd need a teramole or two of formaldehyde to get one mole of acid/alcohol.  The thermodynamics for other aldehydes may be slightly more "favorable" but you aren't going to get 13 orders of magnitude of favorability for any "regular" pair of aldehyde and acid/alcohol.