pKa and pH behaviour of a drug lignocain
If I understand your question correctly, this should answer it:

An "uncharged" base with a high pKa is protonated to form an ionic species: 
$$\ce{B + HX &lt;=&gt; HB^+ + X^-}$$
$$Ex:\ \ce{NH3 + HCl &lt;=&gt;&gt; NH4^+ + Cl^-}$$

A negatively-charged base with a high pKa is protonated to form an uncharged species:
$$\ce{B^- + HX &lt;=&gt; HB + X^-}$$
$$Ex:\ \ce{OH^- + HCl &lt;=&gt;&gt; H2O + Cl^-}$$