Reactivity of different alcohols with NaNH2 and CH3I
I suspect, possibly just to a minor extent, that you have also managed to produce an expected photolysis product here (see below).
Interestingly, the photo sensitive methyl iodide, in the presence of a suitable catalyst ($\ce{CO2, Cu,}$..) with lab light (rich in UV) may have commenced in a radical reaction chain in the presence of ethanol:
$$\ce{CH3I -&gt;[$h \nu$] ^.CH3 + I^.}$$
$$\ce{C2H5OH + I^. -&gt; HI + C2H5O^.}$$
$$\ce{C2H5O^. + C2H5O^. -&gt; (C2H5)2O2}$$
$$\ce{(C2H5)2O2 + ^.CH3 -&gt; (C2H5)2O + CH3O^.}$$
....(the reaction chain continues)
where, I have stopped at the formation of Ether, albeit possibly created in very small amounts but detectable by its smell, nevertheless.
Repeat the experiment controlling for light/catalyst and see if you can still smell the Ether.
My advice, any time working with a photoreactive iodides, be mindful of light exposure.
[EDIT] The implication of my analysis, check your product yields, reagents and procedure, as a minor photo-induced side product may not (but still could) be connected to your results. In particular, I would start with the $\ce{NaNH2}$ as per Wikipedia:

$\ce{NaNH2 + H2O → NH3 + NaOH}$
$\ce{4 NaNH2 + 7 O2 → 2 Na2O + 4 NO2 + 4 H2O}$

which suggests that either exposure to moisture/water/air can degrade the compound.