 The IEEE 802. 16m Physical Layer (Part II) dividing the length of the sub-band CRUs in each partition by N1 4 and summing over the total number of partitions, hence: (10-9) For each frequency partition i, the total number of sub-band CRUs is given as follows: O<i<3 (10-10) Thus, the SLRUs can be indexed as follows: 0<i<3;0<k<N1NSE (10-11) The sub-bands are indexed as: 0<m<NsB (10-12) The interpretation of the RA field in DL Sub-band Assignment A-MAP IE is different from that of DL Basic Assignment A-MAP IE, depending on the value of NSB. For NSB < 4, SLRUs are allocated in a single instance using one Sub-band Assignment A-MAP IE. Each j-bit position in the RA field 0<j<3NsB indicates the allocation of particular SLRU indices using a bit-map method as shown in Figure 10-9. The j-bit positions in the RA field, for 3NSB <j < 12 are set to 0. For 5 < NSB < 11, SLRUs are allocated in a single instance using one Sub-band Assignment A-MAP IE. The MSB of the RA field is denoted as the IE Indication Field (IEF) which is identical to the Mode- Indicator. If IEF = 0, the 11 least significant bits of the RA field are denoted as the Resource Indexing Field (RIF) and each j-bit position in the RIF (O<j i<NSB) indicates the allocation or non-allocation of all N1 4 SLRUs within a particular sub-band, as shown in Figure 10-9. The j-bit positions in the RIF (NSB <j< 11) are set to 0. Otherwise, if IEF 1, the second MSB of the RA field is denoted by the Type Indication Field (TIF) followed by a 7-bit Resource Indication Field (RIF) and 3-bit Pattern Indication Field (PIF) as illustrated in Figure 10-9. The 5, 6, 7, 9, 10, or 11 SLRUs are allocated using the following method: If TIF 0, three sub-bands {SB[u], SB[v], SB[w]}, 0<u<v<w< 10 are defined and the 8 SLRUs are allocated in sub-bands SB[u] and SB[v], and 1, 2, or 3 SLRUs are allocated in SB[w]. The 1, 2, or 3 SLRUs in SB[w] are identified by the PIF bits where , v, and W are indexed using Cover's indexing method, i.e., RIF where (i) is the extended binomial coefficient. If TI