text: Below is an context that describes a sql query, paired with an question that provides further information. Write an answer that appropriately completes the request.  # noqa: E501
  ### Context:
  CREATE TABLE MEDIATYPE (Name VARCHAR, MediaTypeId VARCHAR); CREATE TABLE TRACK (MediaTypeId VARCHAR)
  ### Question:
  What is the least common media type in all tracks?
  ### Answer:
  SELECT T1.Name FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId = T2.MediaTypeId GROUP BY T2.MediaTypeId ORDER BY COUNT(*) LIMIT 1