What 1984 has a 1978 of 46–15?
CREATE TABLE table_name_87 (Id VARCHAR)
SELECT 1984 FROM table_name_87 WHERE 1978 = "46–15"
<s>[INST] Write mssql query to answer the following question given the database schema. Schema: CREATE TABLE table_name_87 (Id VARCHAR) Question: What 1984 has a 1978 of 46–15? [/INST] SELECT 1984 FROM table_name_87 WHERE 1978 = "46–15" </s>