What 1978 has a 1976 of 62%?
CREATE TABLE table_name_99 (Id VARCHAR)
SELECT 1978 FROM table_name_99 WHERE 1976 = "62%"
<s>[INST] Write mssql query to answer the following question given the database schema. Schema: CREATE TABLE table_name_99 (Id VARCHAR) Question: What 1978 has a 1976 of 62%? [/INST] SELECT 1978 FROM table_name_99 WHERE 1976 = "62%" </s>