What internet explorer has 7.89% as the safari, and 8.22% as the chrome?
CREATE TABLE table_name_31 (internet_explorer VARCHAR, safari VARCHAR, chrome VARCHAR)
SELECT internet_explorer FROM table_name_31 WHERE safari = "7.89%" AND chrome = "8.22%"
<s>[INST] Write mssql query to answer the following question given the database schema. Schema: CREATE TABLE table_name_31 (internet_explorer VARCHAR, safari VARCHAR, chrome VARCHAR) Question: What internet explorer has 7.89% as the safari, and 8.22% as the chrome? [/INST] SELECT internet_explorer FROM table_name_31 WHERE safari = "7.89%" AND chrome = "8.22%" </s>