What 1973 has a 1978 of 75%?
CREATE TABLE table_name_31 (Id VARCHAR)
SELECT 1973 FROM table_name_31 WHERE 1978 = "75%"
<s>[INST] Write mssql query to answer the following question given the database schema. Schema: CREATE TABLE table_name_31 (Id VARCHAR) Question: What 1973 has a 1978 of 75%? [/INST] SELECT 1973 FROM table_name_31 WHERE 1978 = "75%" </s>