List the full amount of week 36 results when week 32 is 13.2%.
CREATE TABLE table_23680576_3 (week_36 VARCHAR, week_32 VARCHAR)
SELECT COUNT(week_36) FROM table_23680576_3 WHERE week_32 = "13.2%"
<s>[INST] Write mssql query to answer the following question given the database schema. Schema: CREATE TABLE table_23680576_3 (week_36 VARCHAR, week_32 VARCHAR) Question: List the full amount of week 36 results when week 32 is 13.2%. [/INST] SELECT COUNT(week_36) FROM table_23680576_3 WHERE week_32 = "13.2%" </s>