Name the june when it has july of 84 °f / 28.9 °c
CREATE TABLE table_name_28 (jun VARCHAR, jul VARCHAR)
SELECT jun FROM table_name_28 WHERE jul = "84 °f / 28.9 °c"
<s>[INST] Write mssql query to answer the following question given the database schema. Schema: CREATE TABLE table_name_28 (jun VARCHAR, jul VARCHAR) Question: Name the june when it has july of 84 °f / 28.9 °c [/INST] SELECT jun FROM table_name_28 WHERE jul = "84 °f / 28.9 °c" </s>