Sheffield Lake is a city in Lorain County, Ohio, United States. The population was 9,371 at the 2000 census. Sheffield Lake is located at 41°29′20″N 82°5′59″W / 41.48889°N 82.09972°W / 41.48889; -82.09972 (41.488939, -82.099694). According to the United States Census Bureau, the city has a total area of 2.5 square miles (6.5 km²), all of it land.