Sponsored Topics. Seville is a village in Medina County, Ohio, United States. The population was 2,160 at the 2000 census. Seville is located at 41°0′56″N 81°51′52″W / 41.01556°N 81.86444°W / 41.01556; -81.86444 (41.015620, -81.864363). According to the United States Census Bureau, the village has a total area of 2.0 square miles (5.2 km²), all of it land.