▁from ▁both ▁matches : ▁the ▁winning ▁pair ▁of ▁players ▁could ▁be ▁AC , ▁AD , ▁BC ▁or ▁B D . ▁As ▁each ▁of ▁the ▁out comes ▁for ▁this ▁example ▁has ▁been ▁deliber ately ▁chosen ▁to ▁ensure ▁that ▁they ▁are ▁equally ▁likely ▁it ▁can ▁be ▁dedu ced ▁that ▁the ▁probability ▁of ▁each ▁outcome ▁occurr ing ▁is ▁ ▁or ▁ 0 . 2 5 ▁and ▁that ▁the ▁fraction al ▁odd s ▁against ▁each ▁one ▁occurr ing ▁is ▁ 3 - 1 . ▁A ▁bet ▁of ▁ 1 0 0 ▁units ▁( for ▁simplicity ) ▁on ▁any ▁of ▁the ▁four ▁combinations ▁would ▁produce ▁a ▁return ▁of ▁ 1 0 0 ▁× ▁( 3 / 1 ▁+ ▁ 1 ) ▁= ▁ 4 0 0 ▁units ▁if ▁successful , ▁reflect ing ▁decimal ▁odd s ▁of ▁ 4 . 0 . ▁ ▁The ▁decimal ▁odd s ▁of ▁a ▁multiple ▁bet ▁is ▁often ▁calculated ▁by ▁multip lying ▁the ▁decimal ▁odd s ▁of ▁the ▁individual ▁bet s , ▁the ▁idea ▁being ▁that ▁if ▁the ▁events ▁are ▁independent ▁then ▁the ▁imp lied ▁probability ▁should ▁be ▁the ▁product ▁of ▁the ▁imp lied ▁prob abilities ▁of ▁the ▁individual ▁bet s . ▁In ▁the ▁above ▁case ▁with ▁fraction al ▁odd s ▁of ▁ 5 - 6 , ▁the ▁decimal ▁odd s ▁are ▁. ▁So ▁the ▁decimal ▁odd s ▁of ▁the ▁double ▁bet ▁is ▁× = 1 . 8 3 3 ... × 1 . 8 3 3 ... = 3 . 3 6 1 1 ..., ▁or ▁fraction al ▁odd s ▁of ▁ 2