cout << k ;
if ( k == i or k == j ) : NEW_LINE INDENT continue NEW_LINE DEDENT print ( " YES " ) NEW_LINE K -= 2 NEW_LINE K = k // 2 NEW_LINE printLeftPath ( i , j , K ) NEW_LINE print ( f " { i } ▁ { j } ▁ { k } " ) NEW_LINE printRightPath ( j , k , K ) NEW_LINE return NEW_LINE print ( " NO " ) NEW_LINE