Minimum cost to make two strings identical by deleting the digits | C ++ code to find minimum cost to make two strings identical ; Function to returns cost of removing the identical characters in LCS for X [ 0. . m - 1 ] , Y [ 0. . n - 1 ] ; Following steps build L [ m + 1 ] [ n + 1 ] in bottom up fashion . Note that L [ i ] [ j ] contains cost of removing identical characters in LCS of X [ 0. . i - 1 ] and Y [ 0. . j - 1 ] ; If both characters are same , add both of them ; Otherwise find the maximum cost among them ; Returns cost of making X [ ] and Y [ ] identical ; Find LCS of X [ ] and Y [ ] ; Initialize the cost variable ; Find cost of all characters in both strings ; Driver program to test above function
#include <bits/stdc++.h> NEW_LINE using namespace std ; int lcs ( char * X , char * Y , int m , int n ) { int L [ m + 1 ] [ n + 1 ] ; for ( int i = 0 ; i <= m ; ++ i ) { for ( int j = 0 ; j <= n ; j ++ ) { if ( i == 0 j == 0 ) L [ i ] [ j ] = 0 ; else if ( X [ i - 1 ] == Y [ j - 1 ] ) L [ i ] [ j ] = L [ i - 1 ] [ j - 1 ] + 2 * ( X [ i - 1 ] - '0' ) ; else L [ i ] [ j ] = max ( L [ i - 1 ] [ j ] , L [ i ] [ j - 1 ] ) ; } } return L [ m ] [ n ] ; } int findMinCost ( char X [ ] , char Y [ ] ) { int m = strlen ( X ) , n = strlen ( Y ) ; int cost = 0 ; for ( int i = 0 ; i < m ; ++ i ) cost += X [ i ] - '0' ; for ( int i = 0 ; i < n ; ++ i ) cost += Y [ i ] - '0' ; return cost - lcs ( X , Y , m , n ) ; } int main ( ) { char X [ ] = "3759" ; char Y [ ] = "9350" ; cout << " Minimum ▁ Cost ▁ to ▁ make ▁ two ▁ strings ▁ " << " identical ▁ is ▁ = ▁ " << findMinCost ( X , Y ) ; return 0 ; }