Count of 0 s in an N | C ++ implementation of the approach ; Function to return the count of 0 s in an n - level hexagon ; Driver code
#include <bits/stdc++.h> NEW_LINE using namespace std ; int count ( int n ) { return 3 * n * ( n - 1 ) + 1 ; } int main ( ) { int n = 3 ; cout << count ( n ) ; return 0 ; }