Sum of Euler Totient Functions obtained for each divisor of N | C ++ program for the above approach ; Function to find the sum of Euler Totient Function of divisors of N ; Return the value of N ; Driver Code
#include <iostream> NEW_LINE using namespace std ; int sumOfDivisors ( int N ) { return N ; } int main ( ) { int N = 5 ; cout << sumOfDivisors ( N ) ; return 0 ; }