Maximum number that can be display on Seven Segment Display using N segments |  ; Function to print maximum number that can be formed using N segments ; If n is odd ; use 3 three segment to print 7 ; remaining to print 1 ; If n is even ; print n / 2 1 s . ; Driver 's Code
#include <bits/stdc++.h> NEW_LINE using namespace std ; void printMaxNumber ( int n ) { if ( n & 1 ) { cout << "7" ; for ( int i = 0 ; i < ( n - 3 ) / 2 ; i ++ ) cout << "1" ; } else { for ( int i = 0 ; i < n / 2 ; i ++ ) cout << "1" ; } } int main ( ) { int n = 5 ; printMaxNumber ( n ) ; return 0 ; }