Program to find Sum of the series 1 * 3 + 3 * 5 + ... . | C ++ program to find sum of first n terms ; Sn = n * ( 4 * n * n + 6 * n - 1 ) / 3 ; number of terms to be included in the sum ; find the Sn
#include <bits/stdc++.h> NEW_LINE using namespace std ; int calculateSum ( int n ) { return ( n * ( 4 * n * n + 6 * n - 1 ) / 3 ) ; } int main ( ) { int n = 4 ; cout << " Sum ▁ = ▁ " << calculateSum ( n ) ; return 0 ; }