Base case
for ( let i = 1 ; i <= 6 ; i ++ ) dp [ 1 ] [ i ] = ( 1.0 / 6 ) ; for ( let i = 2 ; i <= N ; i ++ ) { for ( let j = i ; j <= 6 * i ; j ++ ) { for ( let k = 1 ; k <= 6 && k <= j ; k ++ ) { dp [ i ] [ j ] = dp [ i ] [ j ] + dp [ i - 1 ] [ j - k ] / 6 ; } } }