Find a character with frequency different from freq1 .
let j , freq2 = 0 , count_freq2 = 0 ; for ( j = i + 1 ; j < CHARS ; j ++ ) { if ( freq [ j ] != 0 ) { if ( freq [ j ] == freq1 ) { count_freq1 ++ ; } else { count_freq2 = 1 ; freq2 = freq [ j ] ; break ; } } }