Find all pairs in above sorted array cube [ ] whose sum is equal to n
int l = 1 ; int r = cubeRoot ; while ( l < r ) { if ( cube [ l ] + cube [ r ] < n ) l ++ ; else if ( cube [ l ] + cube [ r ] > n ) r -- ; else { System . out . println ( " ( " + l + " , ▁ " + r + " ) " ) ; l ++ ; r -- ; } } }