Check if N is Strong Prime | Java program to check if given number is strong prime ; Utility function to check if a number is prime or not ; Corner cases ; This is checked so that we can skip middle five numbers in below loop ; Function that returns true if n is a strong prime ; If n is not a prime number or n is the first prime then return false ; Initialize previous_prime to n - 1 and next_prime to n + 1 ; Find next prime number ; Find previous prime number ; Arithmetic mean ; If n is a strong prime ; Driver code
class GFG { static boolean isPrime ( int n ) { if ( n <= 1 ) return false ; if ( n <= 3 ) return true ; if ( n % 2 == 0 n % 3 == 0 ) return false ; for ( int i = 5 ; i * i <= n ; i = i + 6 ) if ( n % i == 0 || n % ( i + 2 ) == 0 ) return false ; return true ; } static boolean isStrongPrime ( int n ) { if ( ! isPrime ( n ) n == 2 ) return false ; int previous_prime = n - 1 ; int next_prime = n + 1 ; while ( ! isPrime ( next_prime ) ) next_prime ++ ; while ( ! isPrime ( previous_prime ) ) previous_prime -- ; int mean = ( previous_prime + next_prime ) / 2 ; if ( n > mean ) return true ; else return false ; } public static void main ( String args [ ] ) { int n = 11 ; if ( isStrongPrime ( n ) ) System . out . println ( " Yes " ) ; else System . out . println ( " No " ) ; } }