Cost to Balance the parentheses | Java code to calculate the minimum cost to make the given parentheses balanced ; To store absolute count of balanced and unbalanced parenthesis ; o ( open bracket ) stores count of ' ( ' and c ( close bracket ) stores count of ' ) ' ; Driver code
import java . io . * ; class GFG { static int costToBalance ( String s ) { if ( s . length ( ) == 0 ) System . out . println ( 0 ) ; int ans = 0 ; int o = 0 , c = 0 ; for ( int i = 0 ; i < s . length ( ) ; i ++ ) { if ( s . charAt ( i ) == ' ( ' ) o ++ ; if ( s . charAt ( i ) == ' ) ' ) c ++ ; } if ( o != c ) return - 1 ; int [ ] a = new int [ s . length ( ) ] ; if ( s . charAt ( 0 ) == ' ( ' ) a [ 0 ] = 1 ; else a [ 0 ] = - 1 ; if ( a [ 0 ] < 0 ) ans += Math . abs ( a [ 0 ] ) ; for ( int i = 1 ; i < s . length ( ) ; i ++ ) { if ( s . charAt ( i ) == ' ( ' ) a [ i ] = a [ i - 1 ] + 1 ; else a [ i ] = a [ i - 1 ] - 1 ; if ( a [ i ] < 0 ) ans += Math . abs ( a [ i ] ) ; } return ans ; } public static void main ( String args [ ] ) { String s ; s = " ) ) ) ( ( ( " ; System . out . println ( costToBalance ( s ) ) ; s = " ) ) ( ( " ; System . out . println ( costToBalance ( s ) ) ; } }