Find the last remaining element after repeated removal of odd and even indexed elements alternately | Function to calculate the last remaining element from the sequence ; If dp [ n ] is already calculated ; Base Case : ; Recursive Call ; Return the value of dp [ n ] ; Given N ; Stores the ; Function Call
def lastRemaining ( n , dp ) : NEW_LINE INDENT if n in dp : NEW_LINE INDENT return dp [ n ] NEW_LINE DEDENT if n == 1 : NEW_LINE INDENT return 1 NEW_LINE DEDENT else : NEW_LINE INDENT dp [ n ] = 2 * ( 1 + n // 2 - lastRemaining ( n // 2 , dp ) ) NEW_LINE DEDENT return dp [ n ] NEW_LINE DEDENT N = 5 NEW_LINE dp = { } NEW_LINE print ( lastRemaining ( N , dp ) ) NEW_LINE