Minimum operations required to modify the array such that parity of adjacent elements is different | Function to return the parity of a number ; Function to return the minimum number of operations required ; Operation needs to be performed ; Parity of previous element ; Parity of next element ; Update parity of current element to be other than the parities of the previous and the next number ; Driver Code
function parity ( a ) { return a % 3 ; } function solve ( array , size ) { var operations = 0 ; for ( var i = 0 ; i < size - 1 ; i ++ ) { if ( parity ( array [ i ] ) == parity ( array [ i + 1 ] ) ) { operations ++ ; if ( i + 2 < size ) { var pari1 = parity ( array [ i ] ) ; var pari2 = parity ( array [ i + 2 ] ) ; if ( pari1 == pari2 ) { if ( pari1 == 0 ) array [ i + 1 ] = 1 ; else if ( pari1 == 1 ) array [ i + 1 ] = 0 ; else array [ i + 1 ] = 1 ; } else { if ( ( pari1 == 0 && pari2 == 1 ) || ( pari1 == 1 && pari2 == 0 ) ) array [ i + 1 ] = 2 ; if ( ( pari1 == 1 && pari2 == 2 ) || ( pari1 == 2 && pari2 == 1 ) ) array [ i + 1 ] = 0 ; if ( ( pari1 == 2 && pari2 == 0 ) || ( pari1 == 0 && pari2 == 2 ) ) array [ i + 1 ] = 1 ; } } } } return operations ; } var array = [ 2 , 1 , 3 , 0 ] ; var size = array . length ; document . write ( solve ( array , size ) ) ;