if infinitely many solutions available
if ( noOfSolutions == -1 ) { cout << " For ▁ A ▁ = ▁ " << A << " ▁ and ▁ B ▁ = ▁ " << B << " , ▁ X ▁ can ▁ take ▁ Infinitely ▁ many ▁ values " " ▁ greater ▁ than ▁ " << A << " STRNEWLINE " ; } else { cout << " For ▁ A ▁ = ▁ " << A << " ▁ and ▁ B ▁ = ▁ " << B << " , ▁ X ▁ can ▁ take ▁ " << noOfSolutions << " ▁ values STRNEWLINE " ; } }