Function to return count of integers that satisfy n % phi ( n ) = 0
int countIntegers ( ll l , ll r ) { ll ans = 0 , i = 1 ; ll v = power ( 2 , i ) ; while ( v <= r ) { while ( v <= r ) { if ( v >= l ) ans ++ ; v = v * 3 ; } i ++ ; v = power ( 2 , i ) ; } if ( l == 1 ) ans ++ ; return ans ; }