Consider all triplets and count if their product is equal to m
for ( int i = 0 ; i < n - 2 ; i ++ ) for ( int j = i + 1 ; j < n - 1 ; j ++ ) for ( int k = j + 1 ; k < n ; k ++ ) if ( arr [ i ] * arr [ j ] * arr [ k ] == m ) count ++ ; return count ; }