Function to calculate the maximum number of equal elements possible with atmost K increment of values . Here we have done sliding window to determine that whether there are x number of elements present which on increment will become equal . The loop here will run in fashion like 0. . . x - 1 , 1. . . x , 2. . . x + 1 , ... . , n - x - 1. . . n - 1
bool ElementsCalculationFunc ( int pre [ ] , int maxx [ ] , int x , int k , int n ) { for ( int i = 0 , j = x ; j <= n ; j ++ , i ++ ) {