Comparing the number of neighbouring 1 s with given ranges
if ( arr [ i ] [ j ] == 1 ) { if ( c >= range1a && c <= range1b ) b [ i ] [ j ] = 1 ; else b [ i ] [ j ] = 0 ; } if ( arr [ i ] [ j ] == 0 ) { if ( c >= range0a && c <= range0b ) b [ i ] [ j ] = 1 ; else b [ i ] [ j ] = 0 ; } } }