Eggs dropping puzzle ( Binomial Coefficient and Binary Search Solution ) | Java program to find minimum number of trials in worst case . ; Find sum of binomial coefficients xCi ( where i varies from 1 to n ) . If the sum becomes more than K ; Do binary search to find minimum number of trials in worst case . ; Initialize low and high as 1 st and last floors ; Do binary search , for every mid , find sum of binomial coefficients and check if the sum is greater than k or not . ; Driver code
class Geeks { static int binomialCoeff ( int x , int n , int k ) { int sum = 0 , term = 1 ; for ( int i = 1 ; i <= n && sum < k ; ++ i ) { term *= x - i + 1 ; term /= i ; sum += term ; } return sum ; } static int minTrials ( int n , int k ) { int low = 1 , high = k ; while ( low < high ) { int mid = ( low + high ) / 2 ; if ( binomialCoeff ( mid , n , k ) < k ) low = mid + 1 ; else high = mid ; } return low ; } public static void main ( String args [ ] ) { System . out . println ( minTrials ( 2 , 10 ) ) ; } }