Minimum minutes needed to make the time palindromic | Java program for the above approach ; Function to get the required minutes ; Storing hour and minute value in integral form ; Keep iterating till first digit hour becomes equal to second digit of minute and second digit of hour becomes equal to first digit of minute ; If mins is 60 , increase hour , and reinitilialized to 0 ; If hours is 60 , reinitialized to 0 ; Return the required time ; Driver code ; Given Time as a string ; Function Call
class GFG { public static int get_palindrome_time ( String str ) { int hh , mm ; hh = ( str . charAt ( 0 ) - 48 ) * 10 + ( str . charAt ( 1 ) - 48 ) ; mm = ( str . charAt ( 3 ) - 48 ) * 10 + ( str . charAt ( 4 ) - 48 ) ; int requiredTime = 0 ; while ( hh % 10 != mm / 10 hh / 10 != mm % 10 ) { ++ mm ; if ( mm == 60 ) { mm = 0 ; ++ hh ; } if ( hh == 24 ) hh = 0 ; ++ requiredTime ; } return requiredTime ; } public static void main ( String [ ] args ) { String str = "05:39" ; System . out . println ( get_palindrome_time ( str ) ) ; } }