Find subarray with given sum | Set 1 ( Nonnegative Numbers ) |  ; Returns true if the there is a subarray of arr [ ] with a sum equal to ' sum ' otherwise returns false . Also , prints the result ; Pick a starting point ; try all subarrays starting with ' i ' ; Driver Code
class SubarraySum { int subArraySum ( int arr [ ] , int n , int sum ) { int curr_sum , i , j ; for ( i = 0 ; i < n ; i ++ ) { curr_sum = arr [ i ] ; for ( j = i + 1 ; j <= n ; j ++ ) { if ( curr_sum == sum ) { int p = j - 1 ; System . out . println ( " Sum ▁ found ▁ between ▁ indexes ▁ " + i + " ▁ and ▁ " + p ) ; return 1 ; } if ( curr_sum > sum j == n ) break ; curr_sum = curr_sum + arr [ j ] ; } } System . out . println ( " No ▁ subarray ▁ found " ) ; return 0 ; } public static void main ( String [ ] args ) { SubarraySum arraysum = new SubarraySum ( ) ; int arr [ ] = { 15 , 2 , 4 , 8 , 9 , 5 , 10 , 23 } ; int n = arr . length ; int sum = 23 ; arraysum . subArraySum ( arr , n , sum ) ; } }