XOR and OR of all N | Java program to find the XOR and OR of all Armstrong numbers of N digits ; Function to check if a number is Armstrong or not ; Function to find XOR of all N - digits Armstrong number ; To store the XOR and OR of all Armstrong number ; Starting N - digit Armstrong number ; Ending N - digit Armstrong number ; Iterate over starting and ending number ; To check if i is Armstrong or not ; Print the XOR and OR of all Armstrong number ; Driver Code
class GFG { static boolean isArmstrong ( int x , int n ) { int sum1 = 0 ; int temp = x ; while ( temp > 0 ) { int digit = temp % 10 ; sum1 += Math . pow ( digit , n ) ; temp /= 10 ; } return sum1 == x ; } static void CalculateXORandOR ( int n ) { int CalculateXOR = 0 ; int CalculateOR = 0 ; int start = ( int ) Math . pow ( 10 , n - 1 ) ; int end = ( int ) ( Math . pow ( 10 , n ) ) - 1 ; for ( int i = start ; i < end + 1 ; i ++ ) { if ( isArmstrong ( i , n ) ) { CalculateXOR = CalculateXOR ^ i ; CalculateOR = CalculateOR | i ; } } System . out . println ( " XOR ▁ = ▁ " + CalculateXOR ) ; System . out . println ( " OR ▁ = ▁ " + CalculateOR ) ; } public static void main ( String [ ] args ) { int n = 4 ; CalculateXORandOR ( n ) ; } }