Find profession in a special family | Java program to find profession of a person at given level and position ; Returns ' e ' if profession of node at given level and position is engineer . Else doctor . The function assumes that given position and level have valid values . ; Base case ; Recursively find parent 's  profession. If parent  is a Doctor, this node  will be a Doctor if it  is at odd position and an  engineer if at even position ; If parent is an engineer , then current node will be an engineer if at add position and doctor if even position . ; Driver code
import java . io . * ; class GFG { static char findProffesion ( int level , int pos ) { if ( level == 1 ) return ' e ' ; if ( findProffesion ( level - 1 , ( pos + 1 ) / 2 ) == ' d ' ) return ( pos % 2 > 0 ) ? ' d ' : ' e ' ; return ( pos % 2 > 0 ) ? ' e ' : ' d ' ; } public static void main ( String [ ] args ) { int level = 4 , pos = 2 ; if ( findProffesion ( level , pos ) == ' e ' ) System . out . println ( " Engineer " ) ; else System . out . println ( " Doctor " ) ; } }