def list_of_chars(list_chars):
    if list_chars:
        return list_chars[::-1]
    else:
        return None

for x in range(10):
    if x > 5:
        print(x, 'hi')
        if x % 2 == 0:
            print(x, 'ho')
        else:
            print(x, 'di')

"""
Explanation: <small><i>This notebook was prepared by Donne Martin. Source and license info is on GitHub.</i></small>
Challenge Notebook
Problem: Implement a function to reverse a string (a list of characters), in-place.

Constraints
Test Cases
Algorithm
Code
Unit Test
Solution Notebook

Constraints


Can I assume the string is ASCII?

Yes
Note: Unicode strings could require special handling depending on your language



Since Python string are immutable, can I use a list of characters instead?

Yes



Test Cases

None -> None
[''] -> ['']
['f', 'o', 'o', ' ', 'b', 'a', 'r'] -> ['r', 'a', 'b', ' ', 'o', 'o', 'f']

Algorithm
If you finish this quickly, try implementing three different ways.
Code
End of explanation
"""


# %load test_reverse_string.py
from nose.tools import assert_equal


class TestReverse(object):

    def test_reverse(self):
        assert_equal(list_of_chars(None), None)
        assert_equal(list_of_chars(['']), [''])
        assert_equal(list_of_chars(
            ['f', 'o', 'o', ' ', 'b', 'a', 'r']),
            ['r', 'a', 'b', ' ', 'o', 'o', 'f'])
        print('Success: test_reverse')


def main():
    test = TestReverse()
    test.test_reverse()


if __name__ == '__main__':
    main()

"""
Explanation: Unit Test
The following unit test is expected to fail until you solve the challenge.
End of explanation
"""


