LogNap ⁡ ( a ⋅ b ) = LogNap ⁡ ( a ) + LogNap ⁡ ( b ) − LogNap ⁡ ( 1 ) {\displaystyle \operatorname {LogNap} (a\cdot b)=\operatorname {LogNap} (a)+\operatorname {LogNap} (b)-\operatorname {LogNap} (1)}