Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant:  Human: How do I find the distance between two points?

Assistant: 
You need to provide more context.
But if you are talking about two points in the plane you can use the Pythagoras theorem. d = ( ( x_2 - x_1 )^2 + ( y_2 - y_1 )^2 )^½
If you are talking about two points in a 3 dimensional space you will need a generalization of Pythagoras. d = ( ( x_2 - x_1 )^2 + ( y_2 - y_1)^2 + (z_2 - z_1)^2  )^½ You can find the distance between two points by using the distance formula.
With points (x1, y1) and (x2,y2), the distance between them is given by

√((x2-x1)^2+(y2-y1)^2).

An example is to find the distance between the points (2,4) and (6, 1).
In this case, x1 = 2, y1 = 4, x2 = 6, and y2 = 1.
So plugging it in, we get
√((6-2)^2+(1-4)^2)
By doing the subtractions and then squaring, we get
√(16+9)=√(25)=5
So the distance between the two points is 5. You can use the Pythagorean Theorem to get the distance between the 2 points.

If this is in a 2d space you take the difference in the x axis and square it and you add that to the distance in the y axis squared. Then you take the square root of the total
for $(x_1,y_1)$ and $(x_2,y_2)$
$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
For 3d space you just add the third coordinate like this:
for $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$
$\sqrt{(x_2-x_1)^2+(y_2-y1)^2+(z_2-z_1)^2}$