eqv :: [LispVal] -> ThrowsError LispVal
eqv [(Bool arg1), (Bool arg2)] = return $ Bool $ arg1 == arg2
eqv :: [LispVal] -> ThrowsError LispVal
eqv [(Bool arg1), (Bool arg2)] = return $ Bool $ arg1 == arg2
eqv [(Bool arg1), (Bool arg2)] = return $ Bool $ arg1 == arg2