diff --git "a/data/java/data/humanevalbugs.jsonl" "b/data/java/data/humanevalbugs.jsonl" --- "a/data/java/data/humanevalbugs.jsonl" +++ "b/data/java/data/humanevalbugs.jsonl" @@ -7,7 +7,7 @@ {"task_id": "Java/6", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parseNestedParens(\"(()()) ((())) () ((())()())\")\n [2, 3, 1, 3]\n */\n public List parseNestedParens(String paren_string) {\n", "canonical_solution": " String[] groups = paren_string.split(\" \");\n List result = new ArrayList<>(List.of());\n for (String group : groups) {\n if (group.length() > 0) {\n int depth = 0;\n int max_depth = 0;\n for (char c : group.toCharArray()) {\n if (c == '(') {\n depth += 1;\n max_depth = Math.max(depth, max_depth);\n } else {\n depth -= 1;\n }\n }\n result.add(max_depth);\n }\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.parseNestedParens(\"(()()) ((())) () ((())()())\").equals(Arrays.asList(2, 3, 1, 3)),\n s.parseNestedParens(\"() (()) ((())) (((())))\").equals(Arrays.asList(1, 2, 3, 4)),\n s.parseNestedParens(\"(()(())((())))\").equals(Arrays.asList(4))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level of nesting of parentheses.\n E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n >>> parseNestedParens(\"(()()) ((())) () ((())()())\")\n [2, 3, 1, 3]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List parseNestedParens(String paren_string) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.parseNestedParens(\"(()()) ((())) () ((())()())\").equals(Arrays.asList(2, 3, 1, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String[] groups = paren_string.split(\" \");\n List result = new ArrayList<>(List.of());\n for (String group : groups) {\n if (group.length() > 0) {\n int depth = 0;\n int max_depth = 0;\n for (char c : group.toCharArray()) {\n if (c == '(') {\n depth += 1;\n max_depth = Math.max(depth, max_depth);\n } else {\n max_depth -= 1;\n }\n }\n result.add(max_depth);\n }\n }\n return result;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "ParseNestedParens"} {"task_id": "Java/7", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Filter an input list of strings only for ones that contain given substring\n >>> filterBySubstring(List.of(), \"a\")\n []\n >>> filterBySubstring(Arrays.asList(\"abc\", \"bacd\", \"cde\", \"array\"), \"a\")\n [\"abc\", \"bacd\", \"array\"]\n */\n public List filterBySubstring(List strings, String substring) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (String x : strings) {\n if (x.contains(substring)) {\n result.add(x);\n }\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.filterBySubstring(new ArrayList<>(List.of()), \"john\").equals(List.of()),\n s.filterBySubstring(new ArrayList<>(Arrays.asList(\"xxx\", \"asd\", \"xxy\", \"john doe\", \"xxxAAA\", \"xxx\")), \"xxx\").equals(Arrays.asList(\"xxx\", \"xxxAAA\", \"xxx\")),\n s.filterBySubstring(new ArrayList<>(Arrays.asList(\"xxx\", \"asd\", \"aaaxxy\", \"john doe\", \"xxxAAA\", \"xxx\")), \"xx\").equals(Arrays.asList(\"xxx\", \"aaaxxy\", \"xxxAAA\", \"xxx\")),\n s.filterBySubstring(new ArrayList<>(Arrays.asList(\"grunt\", \"trumpet\", \"prune\", \"gruesome\")), \"run\").equals(Arrays.asList(\"grunt\", \"prune\"))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Filter an input list of strings only for ones that contain given substring\n >>> filterBySubstring(List.of(), \"a\")\n []\n >>> filterBySubstring(Arrays.asList(\"abc\", \"bacd\", \"cde\", \"array\"), \"a\")\n [\"abc\", \"bacd\", \"array\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List filterBySubstring(List strings, String substring) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.filterBySubstring(new ArrayList<>(List.of()), \"s\").equals(List.of()),\n s.filterBySubstring(new ArrayList<>(Arrays.asList(\"abc\", \"bacd\", \"cde\", \"array\")), \"a\").equals(Arrays.asList(\"abc\", \"bacd\", \"array\"))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (String x : strings) {\n if (substring.contains(x)) {\n result.add(x);\n }\n }\n return result;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "FilterBySubstring"} {"task_id": "Java/8", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n >>> sumProduct(List.of())\n [0, 1]\n >>> sumProduct(Arrays.asList(1, 2, 3, 4))\n [10, 24]\n */\n public List sumProduct(List numbers) {\n", "canonical_solution": " int sum = 0;\n int product = 1;\n\n for (int n : numbers) {\n sum += n;\n product *= n;\n }\n return Arrays.asList(sum, product);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sumProduct(new ArrayList<>(List.of())).equals(Arrays.asList(0, 1)),\n s.sumProduct(new ArrayList<>(Arrays.asList(1, 1, 1))).equals(Arrays.asList(3, 1)),\n s.sumProduct(new ArrayList<>(Arrays.asList(100, 0))).equals(Arrays.asList(100, 0)),\n s.sumProduct(new ArrayList<>(Arrays.asList(3, 5, 7))).equals(Arrays.asList(3 + 5 + 7, 3 * 5 * 7)),\n s.sumProduct(new ArrayList<>(List.of(10))).equals(Arrays.asList(10, 10))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and empty product should be equal to 1.\n >>> sumProduct(List.of())\n [0, 1]\n >>> sumProduct(Arrays.asList(1, 2, 3, 4))\n [10, 24]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List sumProduct(List numbers) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sumProduct(new ArrayList<>(List.of())).equals(Arrays.asList(0, 1)),\n s.sumProduct(new ArrayList<>(Arrays.asList(1, 2, 3,4))).equals(Arrays.asList(10, 24))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int sum = 0;\n int product = 0;\n\n for (int n : numbers) {\n sum += n;\n product *= n;\n }\n return Arrays.asList(sum, product);\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "SumProduct"} -{"task_id": "Java/9", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rollingMax(Arrays.asList(1, 2, 3, 2, 3, 4, 2))\n [1, 2, 3, 3, 3, 4, 4]\n */\n public List rollingMax(List numbers) {\n", "canonical_solution": " List result = new ArrayList<>();\n if (numbers.size() == 0) {\n return result;\n }\n int rollingMax = numbers.get(0);\n result.add(rollingMax);\n\n for (int i = 1; i < numbers.size(); i++) {\n if (numbers.get(i) > rollingMax) {\n rollingMax = numbers.get(i);\n }\n result.add(rollingMax);\n }\n\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rollingMax(new ArrayList<>(List.of())).equals(List.of()),\n s.rollingMax(new ArrayList<>(Arrays.asList(1, 2, 3, 4))).equals(Arrays.asList(1, 2, 3, 4)),\n s.rollingMax(new ArrayList<>(Arrays.asList(4, 3, 2, 1))).equals(Arrays.asList(4, 4, 4, 4)),\n s.rollingMax(new ArrayList<>(Arrays.asList(3, 2, 3, 100, 3))).equals(Arrays.asList(3, 3, 3, 100, 100))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rollingMax(Arrays.asList(1, 2, 3, 2, 3, 4, 2))\n [1, 2, 3, 3, 3, 4, 4]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List rollingMax(List numbers) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rollingMax(new ArrayList<>(List.of(1, 2, 3, 2, 3, 4, 2))).equals(List.of(1, 2, 3, 3, 3, 4, 4))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n if (numbers.size() == 0) {\n return result;\n }\n int rollingMax = 1;\n result.add(rollingMax);\n\n for (int i = 1; i < numbers.size(); i++) {\n if (numbers.get(i) > rollingMax) {\n rollingMax = numbers.get(i);\n }\n result.add(rollingMax);\n }\n\n return result;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "RollingMax"} +{"task_id": "Java/9", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rollingMax(Arrays.asList(1, 2, 3, 2, 3, 4, 2))\n [1, 2, 3, 3, 3, 4, 4]\n */\n public List rollingMax(List numbers) {\n", "canonical_solution": " List result = new ArrayList<>();\n if (numbers.size() == 0) {\n return result;\n }\n int rollingMax = numbers.get(0);\n result.add(rollingMax);\n\n for (int i = 1; i < numbers.size(); i++) {\n if (numbers.get(i) > rollingMax) {\n rollingMax = numbers.get(i);\n }\n result.add(rollingMax);\n }\n\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rollingMax(new ArrayList<>(List.of())).equals(List.of()),\n s.rollingMax(new ArrayList<>(Arrays.asList(1, 2, 3, 4))).equals(Arrays.asList(1, 2, 3, 4)),\n s.rollingMax(new ArrayList<>(Arrays.asList(4, 3, 2, 1))).equals(Arrays.asList(4, 4, 4, 4)),\n s.rollingMax(new ArrayList<>(Arrays.asList(3, 2, 3, 100, 3))).equals(Arrays.asList(3, 3, 3, 100, 100))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rollingMax(Arrays.asList(1, 2, 3, 2, 3, 4, 2))\n [1, 2, 3, 3, 3, 4, 4]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List rollingMax(List numbers) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rollingMax(new ArrayList<>(List.of(1, 2, 3, 2, 3, 4, 2))).equals(List.of(1, 2, 3, 3, 3, 4, 4))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n if (numbers.size() == 0) {\n return result;\n }\n int rollingMax = 1;\n result.add(rollingMax);\n\n for (int i = 1; i < numbers.size(); i++) {\n if (numbers.get(i) > rollingMax) {\n rollingMax = numbers.get(i);\n }\n result.add(rollingMax);\n }\n\n return result;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "RollingMax"} {"task_id": "Java/10", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Test if given string is a palindrome\n */\n public boolean isPalindrome(String string) {\n int i = 0;\n int j = string.length() - 1;\n while (i < j) {\n if (string.charAt(i)!= string.charAt(j)) {\n return false;\n }\n i++;\n j--;\n }\n return true;\n }\n /**\n Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n >>> makePalindrome(\"\")\n \"\"\n >>> makePalindrome(\"cat\")\n \"catac\"\n >>> makePalindrome(\"cata\")\n \"catac\"\n */\n public String makePalindrome(String string) {\n", "canonical_solution": " if (string.length() == 0) {\n return \"\";\n }\n\n int beginning_of_suffix = 0;\n\n while (!isPalindrome(string.substring(beginning_of_suffix))) {\n beginning_of_suffix++;\n }\n\n return string + new StringBuffer(string.substring(0, beginning_of_suffix)).reverse().toString();\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.makePalindrome(\"\"), \"\"),\n Objects.equals(s.makePalindrome(\"x\"), \"x\"),\n Objects.equals(s.makePalindrome(\"xyz\"), \"xyzyx\"),\n Objects.equals(s.makePalindrome(\"xyx\"), \"xyx\"),\n Objects.equals(s.makePalindrome(\"jerry\"), \"jerryrrej\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple:\n - Find the longest postfix of supplied string that is a palindrome.\n - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n >>> makePalindrome(\"\")\n \"\"\n >>> makePalindrome(\"cat\")\n \"catac\"\n >>> makePalindrome(\"cata\")\n \"catac\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Test if given string is a palindrome\n */\n public boolean isPalindrome(String string) {\n int i = 0;\n int j = string.length() - 1;\n while (i < j) {\n if (string.charAt(i)!= string.charAt(j)) {\n return false;\n }\n i++;\n j--;\n }\n return true;\n }\n public String makePalindrome(String string) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.makePalindrome(\"\"), \"\"),\n Objects.equals(s.makePalindrome(\"cat\"), \"catac\"),\n Objects.equals(s.makePalindrome(\"cata\"), \"catac\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (string.length() == 0) {\n return \"\";\n }\n\n int beginning_of_suffix = 0;\n\n while (!isPalindrome(string)) {\n beginning_of_suffix++;\n }\n\n return string + new StringBuffer(string.substring(0, beginning_of_suffix)).reverse().toString();\n }\n}", "bug_type": "missing logic", "failure_symptoms": "stackoverflow", "entry_point": "MakePalindrome"} {"task_id": "Java/11", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n >>> stringXor(\"010\", \"110\")\n \"100\"\n */\n public String stringXor(String a, String b) {\n", "canonical_solution": " StringBuilder result = new StringBuilder();\n for (int i = 0; i < a.length(); i++) {\n if (a.charAt(i) == b.charAt(i)) {\n result.append(\"0\");\n } else {\n result.append(\"1\");\n }\n }\n return result.toString();\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.stringXor(\"111000\", \"101010\"), \"010010\"),\n Objects.equals(s.stringXor(\"1\", \"1\"), \"0\"),\n Objects.equals(s.stringXor(\"0101\", \"0000\"), \"0101\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n >>> stringXor(\"010\", \"110\")\n \"100\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String stringXor(String a, String b) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.stringXor(\"010\", \"110\"), \"100\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " StringBuilder result = new StringBuilder();\n for (int i = 0; i < a.length(); i++) {\n if (a.charAt(i) == b.charAt(i)) {\n result.append(\"1\");\n } else {\n result.append(\"0\");\n }\n }\n return result.toString();\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "StringXor"} {"task_id": "Java/12", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n >>> longest(List.of())\n Optional.empty\n >>> longest(Arrays.asList(\"a\", \"b\", \"c\"))\n Optional[a]\n >>> longest(Arrays.asList(\"a\", \"bb\", \"ccc\"))\n Optional[ccc]\n */\n public Optional longest(List strings) {\n", "canonical_solution": " if (strings.isEmpty()) {\n return Optional.empty();\n }\n String longest = strings.get(0);\n for (String s : strings) {\n if (s.length() > longest.length()) {\n longest = s;\n }\n }\n return Optional.of(longest);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.longest(new ArrayList<>(List.of())).isEmpty(),\n Objects.equals(s.longest(new ArrayList<>(Arrays.asList(\"x\", \"y\", \"z\"))).get(), \"x\"),\n Objects.equals(s.longest(new ArrayList<>(Arrays.asList(\"x\", \"yyy\", \"zzzz\", \"www\", \"kkkk\", \"abc\"))).get(), \"zzzz\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input list is empty.\n >>> longest(List.of())\n Optional.empty\n >>> longest(Arrays.asList(\"a\", \"b\", \"c\"))\n Optional[a]\n >>> longest(Arrays.asList(\"a\", \"bb\", \"ccc\"))\n Optional[ccc]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public Optional longest(List strings) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.longest(new ArrayList<>(List.of())).isEmpty(),\n Objects.equals(s.longest(new ArrayList<>(Arrays.asList(\"a\", \"b\", \"c\"))).get(), \"a\"),\n Objects.equals(s.longest(new ArrayList<>(Arrays.asList(\"a\", \"bb\", \"ccc\"))).get(), \"ccc\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (strings.isEmpty()) {\n return Optional.empty();\n }\n String longest = strings.get(0);\n for (String s : strings) {\n if (s.length() < longest.length()) {\n longest = s;\n }\n }\n return Optional.of(longest);\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "Longest"} @@ -32,13 +32,13 @@ {"task_id": "Java/31", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return true if a given number is prime, and false otherwise.\n >>> isPrime(6)\n false\n >>> isPrime(101)\n true\n >>> isPrime(11)\n true\n >>> isPrime(13441)\n true\n >>> isPrime(61)\n true\n >>> isPrime(4)\n false\n >>> isPrime(1)\n false\n */\n public boolean isPrime(int n) {\n", "canonical_solution": " if (n < 2) {\n return false;\n }\n for (int k = 2; k < n; k++) {\n if (n % k == 0) {\n return false;\n }\n }\n return true;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n !s.isPrime(6),\n s.isPrime(101),\n s.isPrime(11),\n s.isPrime(13441),\n s.isPrime(61),\n !s.isPrime(4),\n !s.isPrime(1),\n s.isPrime(5),\n s.isPrime(11),\n s.isPrime(17),\n !s.isPrime(5 * 17),\n !s.isPrime(11 * 7),\n !s.isPrime(13441 * 19)\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return true if a given number is prime, and false otherwise.\n >>> isPrime(6)\n false\n >>> isPrime(101)\n true\n >>> isPrime(11)\n true\n >>> isPrime(13441)\n true\n >>> isPrime(61)\n true\n >>> isPrime(4)\n false\n >>> isPrime(1)\n false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean isPrime(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n !s.isPrime(6),\n s.isPrime(101),\n s.isPrime(11),\n s.isPrime(13441),\n s.isPrime(61),\n !s.isPrime(4),\n !s.isPrime(1)\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (n < 1) {\n return false;\n }\n for (int k = 1; k < n; k++) {\n if (n % k == 0) {\n return false;\n }\n }\n return true;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "IsPrime"} {"task_id": "Java/32", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n\n */\n public double poly(List xs, double x) {\n double result = 0;\n for (int i = 0; i < xs.size(); i++) {\n result += xs.get(i) * Math.pow(x, i);\n }\n return result;\n }\n \n /**\n xs are coefficients of a polynomial.\n findZero find x such that poly(x) = 0.\n findZero returns only only zero point, even if there are many.\n Moreover, findZero only takes list xs having even number of coefficients\n and largest non zero coefficient as it guarantees\n a solution.\n >>> findZero(Arrays.asList(1, 2)) // f(x) = 1 + 2x\n -0.5\n >>> findZero(Arrays.asList(-6, 11, -6, 1)) // (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n */\n public double findZero(List xs) {\n", "canonical_solution": " double begin = -1, end = 1;\n while (poly(xs, begin) * poly(xs, end) > 0) {\n begin *= 2;\n end *= 2;\n }\n while (end - begin > 1e-10) {\n double center = (begin + end) / 2;\n if (poly(xs, begin) * poly(xs, center) > 0) {\n begin = center;\n } else {\n end = center;\n }\n }\n return begin;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n Random rand = new Random(42);\n for (int i = 0; i < 100; i++) {\n int ncoeff = 2 * (rand.nextInt(3) + 1);\n List coeffs = new ArrayList<>();\n for (int j = 0; j < ncoeff; j++) {\n int coeff = rand.nextInt(20) - 10;\n if (coeff == 0) {\n coeff = 1;\n }\n coeffs.add((double) coeff);\n }\n double solution = s.findZero(coeffs);\n if (Math.abs(s.poly(coeffs, solution)) > 1e-4) {\n throw new AssertionError();\n }\n }\n }\n}", "text": " xs are coefficients of a polynomial.\n findZero find x such that poly(x) = 0.\n findZero returns only only zero point, even if there are many.\n Moreover, findZero only takes list xs having even number of coefficients\n and largest non zero coefficient as it guarantees\n a solution.\n >>> findZero(Arrays.asList(1, 2)) // f(x) = 1 + 2x\n -0.5\n >>> findZero(Arrays.asList(-6, 11, -6, 1)) // (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n\n */\n public double poly(List xs, double x) {\n double result = 0;\n for (int i = 0; i < xs.size(); i++) {\n result += xs.get(i) * Math.pow(x, i);\n }\n return result;\n }\n \n public double findZero(List xs) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Math.abs(s.findZero(new ArrayList<>(Arrays.asList(1.,2.)))+0.5)<1e-4,\n Math.abs(s.findZero(new ArrayList<>(Arrays.asList(-6.,11.,-6.,1.)))-1)<1e-4\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " double begin = -1, end = 1;\n while (poly(xs, begin) * poly(xs, end) > 0) {\n begin *= 2;\n end *= 2;\n }\n while (begin - end > 1e-10) {\n double center = (begin + end) / 2;\n if (poly(xs, begin) * poly(xs, center) > 0) {\n begin = center;\n } else {\n end = center;\n }\n }\n return begin;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "FindZero"} {"task_id": "Java/33", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sortThird(Arrays.asList(1, 2, 3))\n [1, 2, 3]\n >>> sortThird(Arrays.asList(5, 6, 3, 4, 8, 9, 2))\n [2, 6, 3, 4, 8, 9, 5]\n */\n public List sortThird(List l) {\n", "canonical_solution": " List thirds = new ArrayList<>();\n for (int i = 0; i < l.size(); i += 3) {\n thirds.add(l.get(i));\n }\n Collections.sort(thirds);\n List result = l;\n for (int i = 0; i < l.size(); i += 3) {\n result.set(i, thirds.get(i / 3));\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortThird(new ArrayList<>(Arrays.asList(5, 6, 3, 4, 8, 9, 2))).equals(Arrays.asList(2, 6, 3, 4, 8, 9, 5)),\n s.sortThird(new ArrayList<>(Arrays.asList(5, 8, 3, 4, 6, 9, 2))).equals(Arrays.asList(2, 8, 3, 4, 6, 9, 5)),\n s.sortThird(new ArrayList<>(Arrays.asList(5, 6, 9, 4, 8, 3, 2))).equals(Arrays.asList(2, 6, 9, 4, 8, 3, 5)),\n s.sortThird(new ArrayList<>(Arrays.asList(5, 6, 3, 4, 8, 9, 2, 1))).equals(Arrays.asList(2, 6, 3, 4, 8, 9, 5, 1))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sortThird(Arrays.asList(1, 2, 3))\n [1, 2, 3]\n >>> sortThird(Arrays.asList(5, 6, 3, 4, 8, 9, 2))\n [2, 6, 3, 4, 8, 9, 5]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List sortThird(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortThird(new ArrayList<>(Arrays.asList(1,2,3))).equals(Arrays.asList(1,2,3)),\n s.sortThird(new ArrayList<>(Arrays.asList(5, 6, 3, 4, 8, 9, 2))).equals(Arrays.asList(2, 6, 3, 4, 8, 9, 5))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List thirds = new ArrayList<>();\n for (int i = 0; i < l.size(); i += 3) {\n thirds.add(l.get(i));\n }\n List result = l;\n for (int i = 0; i < l.size(); i += 3) {\n result.set(i, thirds.get(i / 3));\n }\n return result;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "SortThird"} -{"task_id": "Java/34", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return sorted unique elements in a list\n >>> unique(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))\n [0, 2, 3, 5, 9, 123]\n */\n public List unique(List l) {\n", "canonical_solution": " List result = new ArrayList<>(new HashSet<>(l));\n Collections.sort(result);\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.unique(new ArrayList<>(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))).equals(Arrays.asList(0, 2, 3, 5, 9, 123))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return sorted unique elements in a list\n >>> unique(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))\n [0, 2, 3, 5, 9, 123]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List unique(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.unique(new ArrayList<>(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))).equals(Arrays.asList(0, 2, 3, 5, 9, 123))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>(new HashSet<>(l));\n return result;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "Unique"} +{"task_id": "Java/34", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return sorted unique elements in a list\n >>> unique(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))\n [0, 2, 3, 5, 9, 123]\n */\n public List unique(List l) {\n", "canonical_solution": " List result = new ArrayList<>(new HashSet<>(l));\n Collections.sort(result);\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.unique(new ArrayList<>(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))).equals(Arrays.asList(0, 2, 3, 5, 9, 123))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return sorted unique elements in a list\n >>> unique(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))\n [0, 2, 3, 5, 9, 123]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List unique(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.unique(new ArrayList<>(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))).equals(Arrays.asList(0, 2, 3, 5, 9, 123))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " Collections.sort(l);\n return l;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "Unique"} {"task_id": "Java/35", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return maximum element in the list.\n >>> maxElement(Arrays.asList(1, 2, 3))\n 3\n >>> maxElement(Arrays.asList(5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10))\n 123\n */\n public int maxElement(List l) {\n", "canonical_solution": " return Collections.max(l);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.maxElement(new ArrayList<>(Arrays.asList(1, 2, 3))) == 3,\n s.maxElement(new ArrayList<>(Arrays.asList(5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10))) == 124\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return maximum element in the list.\n >>> maxElement(Arrays.asList(1, 2, 3))\n 3\n >>> maxElement(Arrays.asList(5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10))\n 123", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int maxElement(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.maxElement(new ArrayList<>(Arrays.asList(1, 2, 3))) == 3,\n s.maxElement(new ArrayList<>(Arrays.asList(5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10))) == 123\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " return Collections.min(l);\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "MaxElement"} {"task_id": "Java/36", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizzBuzz(50)\n 0\n >>> fizzBuzz(78)\n 2\n >>> fizzBuzz(79)\n 3\n */\n public int fizzBuzz(int n) {\n", "canonical_solution": " int result = 0;\n for (int i = 1; i < n; i++) {\n if (i % 11 == 0 || i % 13 == 0) {\n char[] digits = String.valueOf(i).toCharArray();\n for (char c : digits) {\n if (c == '7') {\n result += 1;\n }\n }\n }\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.fizzBuzz(50) == 0,\n s.fizzBuzz(78) == 2,\n s.fizzBuzz(79) == 3,\n s.fizzBuzz(100) == 3,\n s.fizzBuzz(200) == 6,\n s.fizzBuzz(4000) == 192,\n s.fizzBuzz(10000) == 639,\n s.fizzBuzz(100000) == 8026\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizzBuzz(50)\n 0\n >>> fizzBuzz(78)\n 2\n >>> fizzBuzz(79)\n 3", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int fizzBuzz(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.fizzBuzz(50) == 0,\n s.fizzBuzz(78) == 2,\n s.fizzBuzz(79) == 3\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int result = 0;\n for (int i = 1; i < n; i++) {\n if (i % 11 == 0 && i % 13 == 0) {\n char[] digits = String.valueOf(i).toCharArray();\n for (char c : digits) {\n if (c == '7') {\n result += 1;\n }\n }\n }\n }\n return result;\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "FizzBuzz"} {"task_id": "Java/37", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sortEven(Arrays.asList(1, 2, 3))\n [1, 2, 3]\n >>> sortEven(Arrays.asList(5, 6, 3, 4))\n [3, 6, 5, 4]\n */\n public List sortEven(List l) {\n", "canonical_solution": " List even = new ArrayList<>();\n for (int i = 0; i < l.size(); i += 2) {\n even.add(l.get(i));\n }\n Collections.sort(even);\n List result = l;\n for (int i = 0; i < l.size(); i += 2) {\n result.set(i, even.get(i / 2));\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortEven(new ArrayList<>(Arrays.asList(1, 2, 3))).equals(Arrays.asList(1, 2, 3)),\n s.sortEven(new ArrayList<>(Arrays.asList(5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10))).equals(Arrays.asList(-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123)),\n s.sortEven(new ArrayList<>(Arrays.asList(5, 8, -12, 4, 23, 2, 3, 11, 12, -10))).equals(Arrays.asList(-12, 8, 3, 4, 5, 2, 12, 11, 23, -10))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sortEven(Arrays.asList(1, 2, 3))\n [1, 2, 3]\n >>> sortEven(Arrays.asList(5, 6, 3, 4))\n [3, 6, 5, 4]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List sortEven(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortEven(new ArrayList<>(Arrays.asList(1, 2, 3))).equals(Arrays.asList(1, 2, 3)),\n s.sortEven(new ArrayList<>(Arrays.asList(5,6,3,4))).equals(Arrays.asList(3,6,5,4))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List even = new ArrayList<>();\n for (int i = 0; i < l.size(); i += 2) {\n even.add(l.get(i));\n }\n Collections.sort(l);\n List result = l;\n for (int i = 0; i < l.size(); i += 2) {\n result.set(i, even.get(i / 2));\n }\n return result;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "SortEven"} {"task_id": "Java/38", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n returns encoded string by cycling groups of three characters.\n */\n public String encodeCyclic(String s) {\n // split string to groups. Each of length 3.\n List groups = new ArrayList<>();\n for (int i = 0; i < s.length(); i += 3) {\n groups.add(s.substring(i, Math.min(i + 3, s.length())));\n }\n // cycle elements in each group. Unless group has fewer elements than 3.\n for (int i = 0; i < groups.size(); i++) {\n if (groups.get(i).length() == 3) {\n groups.set(i, groups.get(i).substring(1) + groups.get(i).charAt(0));\n }\n }\n return String.join(\"\", groups);\n }\n\n /**\n takes as input string encoded with encodeCyclic function. Returns decoded string.\n */\n public String decodeCyclic(String s) {\n", "canonical_solution": " return encodeCyclic(encodeCyclic(s));\n }\n}", "test": "public class Main {\n static char[] letters = \"abcdefghijklmnopqrstuvwxyz\".toCharArray();\n static Random rand = new Random(42);\n public static String random_string(int length) {\n StringBuilder sb = new StringBuilder();\n for (int i = 0; i < length; i++) {\n sb.append(letters[rand.nextInt(26)]);\n }\n return sb.toString();\n }\n public static void main(String[] args) {\n Solution s = new Solution();\n for (int i = 0; i < 100; i++) {\n String str = random_string(rand.nextInt(10) + 10);\n String encode_str = s.encodeCyclic(str);\n if (!s.decodeCyclic(encode_str).equals(str)) {\n throw new AssertionError();\n }\n }\n }\n}", "text": " takes as input string encoded with encodeCyclic function. Returns decoded string.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n returns encoded string by cycling groups of three characters.\n */\n public String encodeCyclic(String s) {\n // split string to groups. Each of length 3.\n List groups = new ArrayList<>();\n for (int i = 0; i < s.length(); i += 3) {\n groups.add(s.substring(i, Math.min(i + 3, s.length())));\n }\n // cycle elements in each group. Unless group has fewer elements than 3.\n for (int i = 0; i < groups.size(); i++) {\n if (groups.get(i).length() == 3) {\n groups.set(i, groups.get(i).substring(1) + groups.get(i).charAt(0));\n }\n }\n return String.join(\"\", groups);\n }\n\n public String decodeCyclic(String s) {\n", "example_test": "", "buggy_solution": " return encodeCyclic(s);\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "DecodeCyclic"} {"task_id": "Java/39", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n primeFib returns n-th number that is a Fibonacci number and it's also prime.\n >>> primeFib(1)\n 2\n >>> primeFib(2)\n 3\n >>> primeFib(3)\n 5\n >>> primeFib(4)\n 13\n >>> primeFib(5)\n 89\n */\n public int primeFib(int n) {\n", "canonical_solution": " int f0 = 0, f1 = 1;\n while (true) {\n int p = f0 + f1;\n boolean is_prime = p >= 2;\n for (int k = 2; k < Math.min(Math.sqrt(p) + 1, p - 1); k++) {\n if (p % k == 0) {\n is_prime = false;\n break;\n }\n }\n if (is_prime) {\n n -= 1;\n }\n if (n == 0) {\n return p;\n }\n f0 = f1;\n f1 = p;\n }\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.primeFib(1) == 2,\n s.primeFib(2) == 3,\n s.primeFib(3) == 5,\n s.primeFib(4) == 13,\n s.primeFib(5) == 89,\n s.primeFib(6) == 233,\n s.primeFib(7) == 1597,\n s.primeFib(8) == 28657,\n s.primeFib(9) == 514229,\n s.primeFib(10) == 433494437\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " primeFib returns n-th number that is a Fibonacci number and it's also prime.\n >>> primeFib(1)\n 2\n >>> primeFib(2)\n 3\n >>> primeFib(3)\n 5\n >>> primeFib(4)\n 13\n >>> primeFib(5)\n 89", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int primeFib(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.primeFib(1) == 2,\n s.primeFib(2) == 3,\n s.primeFib(3) == 5,\n s.primeFib(4) == 13,\n s.primeFib(5) == 89\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int f0 = 0, f1 = 1;\n while (true) {\n int p = f0 + f1;\n boolean is_prime = p >= 2;\n for (int k = 2; k < Math.min(Math.sqrt(p), p); k++) {\n if (p % k == 0) {\n is_prime = false;\n break;\n }\n }\n if (is_prime) {\n n -= 1;\n }\n if (n == 0) {\n return p;\n }\n f0 = f1;\n f1 = p;\n }\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "PrimeFib"} -{"task_id": "Java/40", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n triplesSumToZero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triplesSumToZero(Arrays.asList(1, 3, 5, 0))\n false\n >>> triplesSumToZero(Arrays.asList(1, 3, -2, 1))\n true\n >>> triplesSumToZero(Arrays.asList(1, 2, 3, 7))\n false\n >>> triplesSumToZero(Arrays.asList(2, 4, -5, 3, 9, 7))\n true\n >>> triplesSumToZero(Arrays.asList(1))\n false\n */\n public boolean triplesSumToZero(List l) {\n", "canonical_solution": " for (int i = 0; i < l.size(); i++) {\n for (int j = i + 1; j < l.size(); j++) {\n for (int k = j + 1; k < l.size(); k++) {\n if (l.get(i) + l.get(j) + l.get(k) == 0) {\n return true;\n }\n }\n }\n }\n return false;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, 0))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, -1))),\n s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, -2, 1))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 2, 3, 7))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 2, 5, 7))),\n s.triplesSumToZero(new ArrayList<>(Arrays.asList(2, 4, -5, 3, 9, 7))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, -100))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(100, 3, 5, -100)))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " triplesSumToZero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triplesSumToZero(Arrays.asList(1, 3, 5, 0))\n false\n >>> triplesSumToZero(Arrays.asList(1, 3, -2, 1))\n true\n >>> triplesSumToZero(Arrays.asList(1, 2, 3, 7))\n false\n >>> triplesSumToZero(Arrays.asList(2, 4, -5, 3, 9, 7))\n true\n >>> triplesSumToZero(Arrays.asList(1))\n false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean triplesSumToZero(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, 0))),\n s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, -2, 1))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 2, 3, 7))),\n s.triplesSumToZero(new ArrayList<>(Arrays.asList(2, 4, -5, 3, 9, 7)))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " for (int i = 0; i < l.size(); i++) {\n for (int j = i + 1; j < l.size(); j++) {\n for (int k = i + 1; k < l.size(); k++) {\n if (l.get(i) + l.get(j) + l.get(k) == 0) {\n return true;\n }\n }\n }\n }\n return false;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "TriplesSumToZero"} +{"task_id": "Java/40", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n triplesSumToZero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triplesSumToZero(Arrays.asList(1, 3, 5, 0))\n false\n >>> triplesSumToZero(Arrays.asList(1, 3, -2, 1))\n true\n >>> triplesSumToZero(Arrays.asList(1, 2, 3, 7))\n false\n >>> triplesSumToZero(Arrays.asList(2, 4, -5, 3, 9, 7))\n true\n >>> triplesSumToZero(Arrays.asList(1))\n false\n */\n public boolean triplesSumToZero(List l) {\n", "canonical_solution": " for (int i = 0; i < l.size(); i++) {\n for (int j = i + 1; j < l.size(); j++) {\n for (int k = j + 1; k < l.size(); k++) {\n if (l.get(i) + l.get(j) + l.get(k) == 0) {\n return true;\n }\n }\n }\n }\n return false;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, 0))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, -1))),\n s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, -2, 1))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 2, 3, 7))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 2, 5, 7))),\n s.triplesSumToZero(new ArrayList<>(Arrays.asList(2, 4, -5, 3, 9, 7))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, -100))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(100, 3, 5, -100)))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " triplesSumToZero takes a list of integers as an input.\n it returns True if there are three distinct elements in the list that\n sum to zero, and False otherwise.\n\n >>> triplesSumToZero(Arrays.asList(1, 3, 5, 0))\n false\n >>> triplesSumToZero(Arrays.asList(1, 3, -2, 1))\n true\n >>> triplesSumToZero(Arrays.asList(1, 2, 3, 7))\n false\n >>> triplesSumToZero(Arrays.asList(2, 4, -5, 3, 9, 7))\n true\n >>> triplesSumToZero(Arrays.asList(1))\n false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean triplesSumToZero(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, 0))),\n s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 3, -2, 1))),\n !s.triplesSumToZero(new ArrayList<>(Arrays.asList(1, 2, 3, 7))),\n s.triplesSumToZero(new ArrayList<>(Arrays.asList(2, 4, -5, 3, 9, 7)))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " for (int i = 1; i < l.size(); i++) {\n for (int j = i + 1; j < l.size(); j++) {\n for (int k = j + 1; k < l.size(); k++) {\n if (l.get(i) + l.get(j) + l.get(k) == 0) {\n return true;\n }\n }\n }\n }\n return false;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "TriplesSumToZero"} {"task_id": "Java/41", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move in the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.\n */\n public int carRaceCollision(int n) {\n", "canonical_solution": " return n * n;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.carRaceCollision(2) == 4,\n s.carRaceCollision(3) == 9,\n s.carRaceCollision(4) == 16,\n s.carRaceCollision(8) == 64,\n s.carRaceCollision(10) == 100\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Imagine a road that's a perfectly straight infinitely long line.\n n cars are driving left to right; simultaneously, a different set of n cars\n are driving right to left. The two sets of cars start out being very far from\n each other. All cars move in the same speed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitely sturdy and strong; as a result, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of such collisions.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int carRaceCollision(int n) {\n", "example_test": "", "buggy_solution": " return n * n * n;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "CarRaceCollision"} {"task_id": "Java/42", "prompt": "import java.util.*;\nimport java.lang.*;\nimport java.util.stream.Collectors;\n\nclass Solution {\n /**\n Return list with elements incremented by 1.\n >>> incrList(Arrays.asList(1, 2, 3))\n [2, 3, 4]\n >>> incrList(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n */\n public List incrList(List l) {\n", "canonical_solution": " return l.stream().map(p -> p + 1).collect(Collectors.toList());\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.incrList(new ArrayList<>(Arrays.asList())).equals(List.of()),\n s.incrList(new ArrayList<>(Arrays.asList(3, 2, 1))).equals(Arrays.asList(4, 3, 2)),\n s.incrList(new ArrayList<>(Arrays.asList(5, 2, 5, 2, 3, 3, 9, 0, 123))).equals(Arrays.asList(6, 3, 6, 3, 4, 4, 10, 1, 124))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return list with elements incremented by 1.\n >>> incrList(Arrays.asList(1, 2, 3))\n [2, 3, 4]\n >>> incrList(Arrays.asList(5, 3, 5, 2, 3, 3, 9, 0, 123))\n [6, 4, 6, 3, 4, 4, 10, 1, 124]", "declaration": "import java.util.*;\nimport java.lang.*;\nimport java.util.stream.Collectors;\n\nclass Solution {\n public List incrList(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.incrList(new ArrayList<>(Arrays.asList(1, 2, 3))).equals(Arrays.asList(2, 3, 4)),\n s.incrList(new ArrayList<>(Arrays.asList(5, 2, 5, 2, 3, 3, 9, 0, 123))).equals(Arrays.asList(6, 3, 6, 3, 4, 4, 10, 1, 124))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " return l.stream().map(p -> p + 2).collect(Collectors.toList());\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "IncrList"} {"task_id": "Java/43", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n pairsSumToZero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n >>> pairsSumToZero(Arrays.asList(1, 3, 5, 0))\n false\n >>> pairsSumToZero(Arrays.asList(1, 3, -2, 1))\n false\n >>> pairsSumToZero(Arrays.asList(1, 2, 3, 7))\n false\n >>> pairsSumToZero(Arrays.asList(2, 4, -5, 3, 5, 7))\n true\n >>> pairsSumToZero(Arrays.asList(1))\n false\n */\n public boolean pairsSumToZero(List l) {\n", "canonical_solution": " for (int i = 0; i < l.size(); i++) {\n for (int j = i + 1; j < l.size(); j++) {\n if (l.get(i) + l.get(j) == 0) {\n return true;\n }\n }\n }\n return false;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n !s.pairsSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, 0))),\n !s.pairsSumToZero(new ArrayList<>(Arrays.asList(1, 3, -2, 1))),\n !s.pairsSumToZero(new ArrayList<>(Arrays.asList(1, 2, 3, 7))),\n s.pairsSumToZero(new ArrayList<>(Arrays.asList(2, 4, -5, 3, 5, 7))),\n !s.pairsSumToZero(new ArrayList<>(List.of(1))),\n s.pairsSumToZero(new ArrayList<>(Arrays.asList(-3, 9, -1, 3, 2, 30))),\n s.pairsSumToZero(new ArrayList<>(Arrays.asList(-3, 9, -1, 3, 2, 31))),\n !s.pairsSumToZero(new ArrayList<>(Arrays.asList(-3, 9, -1, 4, 2, 30))),\n !s.pairsSumToZero(new ArrayList<>(Arrays.asList(-3, 9, -1, 4, 2, 31)))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " pairsSumToZero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n >>> pairsSumToZero(Arrays.asList(1, 3, 5, 0))\n false\n >>> pairsSumToZero(Arrays.asList(1, 3, -2, 1))\n false\n >>> pairsSumToZero(Arrays.asList(1, 2, 3, 7))\n false\n >>> pairsSumToZero(Arrays.asList(2, 4, -5, 3, 5, 7))\n true\n >>> pairsSumToZero(Arrays.asList(1))\n false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean pairsSumToZero(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n !s.pairsSumToZero(new ArrayList<>(Arrays.asList(1, 3, 5, 0))),\n !s.pairsSumToZero(new ArrayList<>(Arrays.asList(1, 3, -2, 1))),\n !s.pairsSumToZero(new ArrayList<>(Arrays.asList(1, 2, 3, 7))),\n s.pairsSumToZero(new ArrayList<>(Arrays.asList(2, 4, -5, 3, 5, 7)))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " for (int i = 0; i < l.size(); i++) {\n for (int j = i; j < l.size(); j++) {\n if (l.get(i) + l.get(j) == 0) {\n return true;\n }\n }\n }\n return false;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "PairsSumToZero"} @@ -56,8 +56,8 @@ {"task_id": "Java/55", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return n-th Fibonacci number.\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n */\n public int fib(int n) {\n", "canonical_solution": " if (n == 0) {\n return 0;\n }\n if (n == 1) {\n return 1;\n }\n return fib(n - 1) + fib(n - 2);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.fib(10) == 55,\n s.fib(1) == 1,\n s.fib(8) == 21,\n s.fib(11) == 89,\n s.fib(12) == 144\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return n-th Fibonacci number.\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int fib(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.fib(10) == 55,\n s.fib(1) == 1,\n s.fib(8) == 21\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (n == 0) {\n return 0;\n }\n if (n == 1) {\n return 1;\n }\n if (n == 2) {\n return 2;\n }\n return fib(n - 1) + fib(n - 2);\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "Fib"} {"task_id": "Java/56", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n \n >>> correctBracketing(\"<\")\n false\n >>> correctBracketing(\"<>\")\n true\n >>> correctBracketing(\"<<><>>\")\n true\n >>> correctBracketing(\"><<>\")\n false\n */\n public boolean correctBracketing(String brackets) {\n", "canonical_solution": " int depth = 0;\n for (char b : brackets.toCharArray()) {\n if (b == '<') {\n depth += 1;\n } else {\n depth -= 1;\n }\n if (depth < 0) {\n return false;\n }\n }\n return depth == 0;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.correctBracketing(\"<>\"),\n s.correctBracketing(\"<<><>>\"),\n s.correctBracketing(\"<><><<><>><>\"),\n s.correctBracketing(\"<><><<<><><>><>><<><><<>>>\"),\n !s.correctBracketing(\"<<<><>>>>\"),\n !s.correctBracketing(\"><<>\"),\n !s.correctBracketing(\"<\"),\n !s.correctBracketing(\"<<<<\"),\n !s.correctBracketing(\">\"),\n !s.correctBracketing(\"<<>\"),\n !s.correctBracketing(\"<><><<><>><>><<>\"),\n !s.correctBracketing(\"<><><<><>><>>><>\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponding closing bracket.\n \n >>> correctBracketing(\"<\")\n false\n >>> correctBracketing(\"<>\")\n true\n >>> correctBracketing(\"<<><>>\")\n true\n >>> correctBracketing(\"><<>\")\n false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean correctBracketing(String brackets) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.correctBracketing(\"<>\"),\n s.correctBracketing(\"<<><>>\"),\n !s.correctBracketing(\"><<>\"),\n !s.correctBracketing(\"<\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int depth = 0;\n for (char b : brackets.toCharArray()) {\n if (b == '>') {\n depth += 1;\n } else {\n depth -= 1;\n }\n if (depth < 0) {\n return false;\n }\n }\n return depth == 0;\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "CorrectBracketing"} {"task_id": "Java/57", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return True is list elements are monotonically increasing or decreasing.\n >>> monotonic(Arrays.asList(1, 2, 4, 20))\n true\n >>> monotonic(Arrays.asList(1, 20, 4, 10))\n false\n >>> monotonic(Arrays.asList(4, 1, 0, -10))\n true\n */\n public boolean monotonic(List l) {\n", "canonical_solution": " List l1 = new ArrayList<>(l), l2 = new ArrayList<>(l);\n Collections.sort(l1);\n l2.sort(Collections.reverseOrder());\n return l.equals(l1) || l.equals(l2);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.monotonic(new ArrayList<>(Arrays.asList(1, 2, 4, 10))),\n s.monotonic(new ArrayList<>(Arrays.asList(1, 2, 4, 20))),\n !s.monotonic(new ArrayList<>(Arrays.asList(1, 20, 4, 10))),\n s.monotonic(new ArrayList<>(Arrays.asList(4, 1, 0, -10))),\n s.monotonic(new ArrayList<>(Arrays.asList(4, 1, 1, 0))),\n !s.monotonic(new ArrayList<>(Arrays.asList(1, 2, 3, 2, 5, 60))),\n s.monotonic(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 60))),\n s.monotonic(new ArrayList<>(Arrays.asList(9, 9, 9, 9)))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return True is list elements are monotonically increasing or decreasing.\n >>> monotonic(Arrays.asList(1, 2, 4, 20))\n true\n >>> monotonic(Arrays.asList(1, 20, 4, 10))\n false\n >>> monotonic(Arrays.asList(4, 1, 0, -10))\n true", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean monotonic(List l) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.monotonic(new ArrayList<>(Arrays.asList(1, 2, 4, 10))),\n !s.monotonic(new ArrayList<>(Arrays.asList(1, 20, 4, 10))),\n s.monotonic(new ArrayList<>(Arrays.asList(4, 1, 0, -10)))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List l1 = new ArrayList<>(l), l2 = new ArrayList<>(l);\n Collections.sort(l1);\n l2.sort(Collections.reverseOrder());\n return l.equals(l1) && l.equals(l2);\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "Monotonic"} -{"task_id": "Java/58", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return sorted unique common elements for two lists.\n >>> common(Arrays.asList(1, 4, 3, 34, 653, 2, 5), Arrays.asList(5, 7, 1, 5, 9, 653, 121))\n [1, 5, 653]\n >>> common(Arrays.asList(5, 3, 2, 8), Arrays.asList(3, 2))\n [2, 3]\n */\n public List common(List l1, List l2) {\n", "canonical_solution": " Set ret = new HashSet<>(l1);\n ret.retainAll(new HashSet<>(l2));\n List result = new ArrayList<>(ret);\n Collections.sort(result);\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.common(new ArrayList<>(Arrays.asList(1, 4, 3, 34, 653, 2, 5)), new ArrayList<>(Arrays.asList(5, 7, 1, 5, 9, 653, 121))).equals(Arrays.asList(1, 5, 653)),\n s.common(new ArrayList<>(Arrays.asList(5, 3, 2, 8)), new ArrayList<>(Arrays.asList(3, 2))).equals(Arrays.asList(2, 3)),\n s.common(new ArrayList<>(Arrays.asList(4, 3, 2, 8)), new ArrayList<>(Arrays.asList(3, 2, 4))).equals(Arrays.asList(2, 3, 4)),\n s.common(new ArrayList<>(Arrays.asList(4, 3, 2, 8)), new ArrayList<>(List.of())).equals(List.of())\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return sorted unique common elements for two lists.\n >>> common(Arrays.asList(1, 4, 3, 34, 653, 2, 5), Arrays.asList(5, 7, 1, 5, 9, 653, 121))\n [1, 5, 653]\n >>> common(Arrays.asList(5, 3, 2, 8), Arrays.asList(3, 2))\n [2, 3]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List common(List l1, List l2) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.common(new ArrayList<>(Arrays.asList(1, 4, 3, 34, 653, 2, 5)), new ArrayList<>(Arrays.asList(5, 7, 1, 5, 9, 653, 121))).equals(Arrays.asList(1, 5, 653)),\n s.common(new ArrayList<>(Arrays.asList(5, 3, 2, 8)), new ArrayList<>(Arrays.asList(3, 2))).equals(Arrays.asList(2, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " Set ret = new HashSet<>(l1);\n ret.retainAll(new HashSet<>(l2));\n List result = new ArrayList<>(ret);\n return result;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "Common"} -{"task_id": "Java/59", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largestPrimeFactor(13195)\n 29\n >>> largestPrimeFactor(2048)\n 2\n */\n public int largestPrimeFactor(int n) {\n", "canonical_solution": " int largest = 1;\n for (int j = 2; j <= n; j++) {\n if (n % j == 0) {\n boolean is_prime = j >= 2;\n for (int i = 2; i < j - 1; i++) {\n if (j % i == 0) {\n is_prime = false;\n break;\n }\n }\n if (is_prime) {\n largest = Math.max(largest, j);\n }\n }\n }\n return largest;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.largestPrimeFactor(15) == 5,\n s.largestPrimeFactor(27) == 3,\n s.largestPrimeFactor(63) == 7,\n s.largestPrimeFactor(330) == 11,\n s.largestPrimeFactor(13195) == 29\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largestPrimeFactor(13195)\n 29\n >>> largestPrimeFactor(2048)\n 2", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int largestPrimeFactor(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.largestPrimeFactor(2048) ==2,\n s.largestPrimeFactor(13195) == 29\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int largest = 1;\n for (int j = 2; j <= n; j++) {\n if (n % j == 0) {\n boolean is_prime = j >= 2;\n for (int i = 2; i < j - 2; i++) {\n if (j % i == 0) {\n is_prime = false;\n break;\n }\n }\n if (is_prime) {\n largest = Math.max(largest, j);\n }\n }\n }\n return largest;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "LargestPrimeFactor"} +{"task_id": "Java/58", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return sorted unique common elements for two lists.\n >>> common(Arrays.asList(1, 4, 3, 34, 653, 2, 5), Arrays.asList(5, 7, 1, 5, 9, 653, 121))\n [1, 5, 653]\n >>> common(Arrays.asList(5, 3, 2, 8), Arrays.asList(3, 2))\n [2, 3]\n */\n public List common(List l1, List l2) {\n", "canonical_solution": " Set ret = new HashSet<>(l1);\n ret.retainAll(new HashSet<>(l2));\n List result = new ArrayList<>(ret);\n Collections.sort(result);\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.common(new ArrayList<>(Arrays.asList(1, 4, 3, 34, 653, 2, 5)), new ArrayList<>(Arrays.asList(5, 7, 1, 5, 9, 653, 121))).equals(Arrays.asList(1, 5, 653)),\n s.common(new ArrayList<>(Arrays.asList(5, 3, 2, 8)), new ArrayList<>(Arrays.asList(3, 2))).equals(Arrays.asList(2, 3)),\n s.common(new ArrayList<>(Arrays.asList(4, 3, 2, 8)), new ArrayList<>(Arrays.asList(3, 2, 4))).equals(Arrays.asList(2, 3, 4)),\n s.common(new ArrayList<>(Arrays.asList(4, 3, 2, 8)), new ArrayList<>(List.of())).equals(List.of())\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return sorted unique common elements for two lists.\n >>> common(Arrays.asList(1, 4, 3, 34, 653, 2, 5), Arrays.asList(5, 7, 1, 5, 9, 653, 121))\n [1, 5, 653]\n >>> common(Arrays.asList(5, 3, 2, 8), Arrays.asList(3, 2))\n [2, 3]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List common(List l1, List l2) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.common(new ArrayList<>(Arrays.asList(1, 4, 3, 34, 653, 2, 5)), new ArrayList<>(Arrays.asList(5, 7, 1, 5, 9, 653, 121))).equals(Arrays.asList(1, 5, 653)),\n s.common(new ArrayList<>(Arrays.asList(5, 3, 2, 8)), new ArrayList<>(Arrays.asList(3, 2))).equals(Arrays.asList(2, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " Set ret = new HashSet<>(l1);\n List result = new ArrayList<>(ret);\n Collections.sort(result);\n return result;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "Common"} +{"task_id": "Java/59", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largestPrimeFactor(13195)\n 29\n >>> largestPrimeFactor(2048)\n 2\n */\n public int largestPrimeFactor(int n) {\n", "canonical_solution": " int largest = 1;\n for (int j = 2; j <= n; j++) {\n if (n % j == 0) {\n boolean is_prime = j >= 2;\n for (int i = 2; i < j - 1; i++) {\n if (j % i == 0) {\n is_prime = false;\n break;\n }\n }\n if (is_prime) {\n largest = Math.max(largest, j);\n }\n }\n }\n return largest;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.largestPrimeFactor(15) == 5,\n s.largestPrimeFactor(27) == 3,\n s.largestPrimeFactor(63) == 7,\n s.largestPrimeFactor(330) == 11,\n s.largestPrimeFactor(13195) == 29\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largestPrimeFactor(13195)\n 29\n >>> largestPrimeFactor(2048)\n 2", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int largestPrimeFactor(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.largestPrimeFactor(2048) ==2,\n s.largestPrimeFactor(13195) == 29\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int largest = 1;\n for (int j = 2; j <= n; j++) {\n if (n % j == 0) {\n boolean is_prime = j >= 2;\n for (int i = 2; i < j - 1; i++) {\n if (n % i == 0) {\n is_prime = false;\n break;\n }\n }\n if (is_prime) {\n largest = Math.max(largest, j);\n }\n }\n }\n return largest;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "LargestPrimeFactor"} {"task_id": "Java/60", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n sumToN is a function that sums numbers from 1 to n.\n >>> sumToN(30)\n 465\n >>> sumToN(100)\n 5050\n >>> sumToN(5)\n 15\n >>> sumToN(10)\n 55\n >>> sumToN(1)\n 1\n */\n public int sumToN(int n) {\n", "canonical_solution": " int result = 0;\n for (int i = 1; i <= n; i++) {\n result += i;\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sumToN(1) == 1,\n s.sumToN(6) == 21,\n s.sumToN(11) == 66,\n s.sumToN(30) == 465,\n s.sumToN(100) == 5050\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " sumToN is a function that sums numbers from 1 to n.\n >>> sumToN(30)\n 465\n >>> sumToN(100)\n 5050\n >>> sumToN(5)\n 15\n >>> sumToN(10)\n 55\n >>> sumToN(1)\n 1", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int sumToN(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sumToN(1) == 1,\n s.sumToN(5) == 15,\n s.sumToN(10) == 55,\n s.sumToN(30) == 465,\n s.sumToN(100) == 5050\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int result = 0;\n for (int i = 1; i < n; i++) {\n result += i;\n }\n return result;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "SumToN"} {"task_id": "Java/61", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correctBracketing(\"(\")\n false\n >>> correctBracketing(\"()\")\n true\n >>> correctBracketing(\"(()())\")\n true\n >>> correctBracketing(\")(()\")\n false\n */\n public boolean correctBracketing(String brackets) {\n", "canonical_solution": " int depth = 0;\n for (char b : brackets.toCharArray()) {\n if (b == '(') {\n depth += 1;\n } else {\n depth -= 1;\n }\n if (depth < 0) {\n return false;\n }\n }\n return depth == 0;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.correctBracketing(\"()\"),\n s.correctBracketing(\"(()())\"),\n s.correctBracketing(\"()()(()())()\"),\n s.correctBracketing(\"()()((()()())())(()()(()))\"),\n !s.correctBracketing(\"((()())))\"),\n !s.correctBracketing(\")(()\"),\n !s.correctBracketing(\"(\"),\n !s.correctBracketing(\"((((\"),\n !s.correctBracketing(\")\"),\n !s.correctBracketing(\"(()\"),\n !s.correctBracketing(\"()()(()())())(()\"),\n !s.correctBracketing(\"()()(()())()))()\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " brackets is a string of \"(\" and \")\".\n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correctBracketing(\"(\")\n false\n >>> correctBracketing(\"()\")\n true\n >>> correctBracketing(\"(()())\")\n true\n >>> correctBracketing(\")(()\")\n false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean correctBracketing(String brackets) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.correctBracketing(\"()\"),\n s.correctBracketing(\"(()())\"),\n !s.correctBracketing(\")(()\"),\n !s.correctBracketing(\"(\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int depth = 0;\n for (char b : brackets.toCharArray()) {\n if (b == '(') {\n depth += 1;\n } else {\n depth -= 1;\n }\n if (depth < 0) {\n return true;\n }\n }\n return depth == 0;\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "CorrectBracketing"} {"task_id": "Java/62", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n >>> derivative(Arrays.asList(3, 1, 2, 4, 5))\n [1, 4, 12, 20]\n >>> derivative(Arrays.asList(1, 2, 3]))\n [2, 6]\n */\n public List derivative(List xs) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (int i = 1; i < xs.size(); i++) {\n result.add(i * xs.get(i));\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.derivative(new ArrayList<>(Arrays.asList(3, 1, 2, 4, 5))).equals(Arrays.asList(1, 4, 12, 20)),\n s.derivative(new ArrayList<>(Arrays.asList(1, 2, 3))).equals(Arrays.asList(2, 6)),\n s.derivative(new ArrayList<>(Arrays.asList(3, 2, 1))).equals(Arrays.asList(2, 2)),\n s.derivative(new ArrayList<>(Arrays.asList(3, 2, 1, 0, 4))).equals(Arrays.asList(2, 2, 0, 16)),\n s.derivative(List.of(1)).equals(List.of())\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n >>> derivative(Arrays.asList(3, 1, 2, 4, 5))\n [1, 4, 12, 20]\n >>> derivative(Arrays.asList(1, 2, 3]))\n [2, 6]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List derivative(List xs) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.derivative(new ArrayList<>(Arrays.asList(3, 1, 2, 4, 5))).equals(Arrays.asList(1, 4, 12, 20)),\n s.derivative(new ArrayList<>(Arrays.asList(1, 2, 3))).equals(Arrays.asList(2, 6))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (int i = 0; i < xs.size(); i++) {\n result.add(i * xs.get(i));\n }\n return result;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "Derivative"} @@ -90,7 +90,7 @@ {"task_id": "Java/89", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt(\"hi\") returns \"lm\"\n encrypt(\"asdfghjkl\") returns \"ewhjklnop\"\n encrypt(\"gf\") returns \"kj\"\n encrypt(\"et\") returns \"ix\"\n */\n public String encrypt(String s) {\n", "canonical_solution": " StringBuilder sb = new StringBuilder();\n for (char c : s.toCharArray()) {\n if (Character.isLetter(c)) {\n sb.append((char) ('a' + (c - 'a' + 2 * 2) % 26));\n } else {\n sb.append(c);\n }\n }\n return sb.toString();\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.encrypt(\"hi\"), \"lm\"),\n Objects.equals(s.encrypt(\"asdfghjkl\"), \"ewhjklnop\"),\n Objects.equals(s.encrypt(\"gf\"), \"kj\"),\n Objects.equals(s.encrypt(\"et\"), \"ix\"),\n Objects.equals(s.encrypt(\"faewfawefaewg\"), \"jeiajeaijeiak\"),\n Objects.equals(s.encrypt(\"hellomyfriend\"), \"lippsqcjvmirh\"),\n Objects.equals(s.encrypt(\"dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh\"), \"hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl\"),\n Objects.equals(s.encrypt(\"a\"), \"e\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt(\"hi\") returns \"lm\"\n encrypt(\"asdfghjkl\") returns \"ewhjklnop\"\n encrypt(\"gf\") returns \"kj\"\n encrypt(\"et\") returns \"ix\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String encrypt(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.encrypt(\"hi\"), \"lm\"),\n Objects.equals(s.encrypt(\"asdfghjkl\"), \"ewhjklnop\"),\n Objects.equals(s.encrypt(\"gf\"), \"kj\"),\n Objects.equals(s.encrypt(\"et\"), \"ix\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " StringBuilder sb = new StringBuilder();\n for (char c : s.toCharArray()) {\n if (Character.isLetter(c)) {\n sb.append((char) ('a' + (c - 'a' + 2 * 2) % 24));\n } else {\n sb.append(c);\n }\n }\n return sb.toString();\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "Encrypt"} {"task_id": "Java/90", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given a list of integers.\n Write a function nextSmallest() that returns the 2nd smallest element of the list.\n Return null if there is no such element.\n

\n nextSmallest(Arrays.asList(1, 2, 3, 4, 5)) == Optional[2]\n nextSmallest(Arrays.asList(5, 1, 4, 3, 2)) == Optional[2]\n nextSmallest(Arrays.asList()) == Optional.empty\n nextSmallest(Arrays.asList(1, 1)) == Optional.empty\n */\n public Optional nextSmallest(List lst) {\n", "canonical_solution": " Set < Integer > set = new HashSet<>(lst);\n List l = new ArrayList<>(set);\n Collections.sort(l);\n if (l.size() < 2) {\n return Optional.empty();\n } else {\n return Optional.of(l.get(1));\n }\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.nextSmallest(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5))).get() == 2,\n s.nextSmallest(new ArrayList<>(Arrays.asList(5, 1, 4, 3, 2))).get() == 2,\n s.nextSmallest(new ArrayList<>(List.of())).isEmpty(),\n s.nextSmallest(new ArrayList<>(Arrays.asList(1, 1))).isEmpty(),\n s.nextSmallest(new ArrayList<>(Arrays.asList(1, 1, 1, 1, 0))).get() == 1,\n s.nextSmallest(new ArrayList<>(Arrays.asList(1, (int) Math.pow(0.0, 0.0)))).isEmpty(),\n s.nextSmallest(new ArrayList<>(Arrays.asList(-35, 34, 12, -45))).get() == -35\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given a list of integers.\n Write a function nextSmallest() that returns the 2nd smallest element of the list.\n Return null if there is no such element.\n

\n nextSmallest(Arrays.asList(1, 2, 3, 4, 5)) == Optional[2]\n nextSmallest(Arrays.asList(5, 1, 4, 3, 2)) == Optional[2]\n nextSmallest(Arrays.asList()) == Optional.empty\n nextSmallest(Arrays.asList(1, 1)) == Optional.empty", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public Optional nextSmallest(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.nextSmallest(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5))).get() == 2,\n s.nextSmallest(new ArrayList<>(Arrays.asList(5, 1, 4, 3, 2))).get() == 2,\n s.nextSmallest(new ArrayList<>(List.of())).isEmpty(),\n s.nextSmallest(new ArrayList<>(Arrays.asList(1, 1))).isEmpty()\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " Set < Integer > set = new HashSet<>(lst);\n List l = new ArrayList<>(set);\n Collections.sort(l);\n if (l.size() < 3) {\n return Optional.empty();\n } else {\n return Optional.of(l.get(1));\n }\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "NextSmallest"} {"task_id": "Java/91", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n\n For example:\n >>> isBored(\"Hello world\")\n 0\n >>> isBored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n */\n public int isBored(String S) {\n", "canonical_solution": " String [] sentences = S.split(\"[.?!]\\s*\");\n int count = 0;\n for (String sentence : sentences) {\n if (sentence.subSequence(0, 2).equals(\"I \")) {\n count += 1;\n }\n }\n return count;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isBored(\"Hello world\") == 0,\n s.isBored(\"Is the sky blue?\") == 0,\n s.isBored(\"I love It !\") == 1,\n s.isBored(\"bIt\") == 0,\n s.isBored(\"I feel good today. I will be productive. will kill It\") == 2,\n s.isBored(\"You and I are going for a walk\") == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You'll be given a string of words, and your task is to count the number\n of boredoms. A boredom is a sentence that starts with the word \"I\".\n Sentences are delimited by '.', '?' or '!'.\n\n For example:\n >>> isBored(\"Hello world\")\n 0\n >>> isBored(\"The sky is blue. The sun is shining. I love this weather\")\n 1", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int isBored(String S) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isBored(\"Hello world\") == 0,\n s.isBored(\"The sky is blue. The sun is shining. I love this weather\") == 1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String [] sentences = S.split(\"[.?!]\\s*\");\n int count = 0;\n for (String sentence : sentences) {\n if (sentence.subSequence(0, 2).equals(\" I\")) {\n count += 1;\n }\n }\n return count;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "IsBored"} -{"task_id": "Java/92", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n\n Examples\n anyInt(5, 2, 7) -> true\n\n anyInt(3, 2, 2) -> false\n\n anyInt(3, -2, 1) -> true\n\n anyInt(3.6, -2.2, 2) -> false\n */\n public boolean anyInt(Object x, Object y, Object z) {\n", "canonical_solution": " if (x instanceof Integer && y instanceof Integer && z instanceof Integer) {\n return (int) x + (int) y == (int) z || (int) x + (int) z == (int) y || (int) y + (int) z == (int) x;\n }\n return false;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.anyInt(2, 3, 1) == true,\n s.anyInt(2.5, 2, 3) == false,\n s.anyInt(1.5, 5, 3.5) == false,\n s.anyInt(2, 6, 2) == false,\n s.anyInt(4, 2, 2) == true,\n s.anyInt(2.2, 2.2, 2.2) == false,\n s.anyInt(-4, 6, 2) == true,\n s.anyInt(2, 1, 1) == true,\n s.anyInt(3, 4, 7) == true,\n s.anyInt(3.0, 4, 7) == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n\n Examples\n anyInt(5, 2, 7) -> true\n\n anyInt(3, 2, 2) -> false\n\n anyInt(3, -2, 1) -> true\n\n anyInt(3.6, -2.2, 2) -> false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean anyInt(Object x, Object y, Object z) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.anyInt(5, 2, 7) == true,\n s.anyInt(3, 2, 2) == false,\n s.anyInt(3, -2, 1) == true,\n s.anyInt(3.6, -2.2, 2) == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (x instanceof Integer && y instanceof Integer && z instanceof Integer) {\n return (int) x * (int) y == (int) z || (int) x * (int) z == (int) y || (int) y * (int) z == (int) x || (int) x + (int) y == (int) z || (int) x + (int) z == (int) y || (int) y + (int) z == (int) x || (int) x - (int) y == (int) z || (int) x - (int) z == (int) y || (int) y - (int) z == (int) x;\n }\n return false;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "AnyInt"} +{"task_id": "Java/92", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n\n Examples\n anyInt(5, 2, 7) -> true\n\n anyInt(3, 2, 2) -> false\n\n anyInt(3, -2, 1) -> true\n\n anyInt(3.6, -2.2, 2) -> false\n */\n public boolean anyInt(Object x, Object y, Object z) {\n", "canonical_solution": " if (x instanceof Integer && y instanceof Integer && z instanceof Integer) {\n return (int) x + (int) y == (int) z || (int) x + (int) z == (int) y || (int) y + (int) z == (int) x;\n }\n return false;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.anyInt(2, 3, 1) == true,\n s.anyInt(2.5, 2, 3) == false,\n s.anyInt(1.5, 5, 3.5) == false,\n s.anyInt(2, 6, 2) == false,\n s.anyInt(4, 2, 2) == true,\n s.anyInt(2.2, 2.2, 2.2) == false,\n s.anyInt(-4, 6, 2) == true,\n s.anyInt(2, 1, 1) == true,\n s.anyInt(3, 4, 7) == true,\n s.anyInt(3.0, 4, 7) == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function that takes 3 numbers.\n Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n Returns false in any other cases.\n\n Examples\n anyInt(5, 2, 7) -> true\n\n anyInt(3, 2, 2) -> false\n\n anyInt(3, -2, 1) -> true\n\n anyInt(3.6, -2.2, 2) -> false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean anyInt(Object x, Object y, Object z) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.anyInt(5, 2, 7) == true,\n s.anyInt(3, 2, 2) == false,\n s.anyInt(3, -2, 1) == true,\n s.anyInt(3.6, -2.2, 2) == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (x instanceof Integer && y instanceof Integer && z instanceof Integer) {\n return (int) x + (int) y == (int) z || (int) y + (int) z == (int) x;\n }\n return false;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "AnyInt"} {"task_id": "Java/93", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function that takes a message, and encodes in such a\n way that it swaps case of all letters, replaces all vowels in\n the message with the letter that appears 2 places ahead of that\n vowel in the english alphabet.\n Assume only letters.\n\n Examples:\n >>> encode(\"test\")\n \"TGST\"\n >>> encode(\"This is a message\")\n \"tHKS KS C MGSSCGG\"\n */\n public String encode(String message) {\n", "canonical_solution": " String vowels = \"aeiouAEIOU\";\n StringBuilder sb = new StringBuilder();\n for (char c : message.toCharArray()) {\n char ch = c;\n if (Character.isUpperCase(ch)) {\n ch = Character.toLowerCase(ch);\n if (vowels.indexOf(ch) != -1) {\n ch = (char) ('a' + ((ch - 'a' + 28) % 26));\n }\n } else if (Character.isLowerCase(ch)) {\n ch = Character.toUpperCase(ch);\n if (vowels.indexOf(ch) != -1) {\n ch = (char) ('A' + ((ch - 'A' + 28) % 26));\n }\n }\n sb.append(ch);\n }\n return sb.toString();\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.encode(\"TEST\"), \"tgst\"),\n Objects.equals(s.encode(\"Mudasir\"), \"mWDCSKR\"),\n Objects.equals(s.encode(\"YES\"), \"ygs\"),\n Objects.equals(s.encode(\"This is a message\"), \"tHKS KS C MGSSCGG\"),\n Objects.equals(s.encode(\"I DoNt KnOw WhAt tO WrItE\"), \"k dQnT kNqW wHcT Tq wRkTg\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function that takes a message, and encodes in such a\n way that it swaps case of all letters, replaces all vowels in\n the message with the letter that appears 2 places ahead of that\n vowel in the english alphabet.\n Assume only letters.\n\n Examples:\n >>> encode(\"test\")\n \"TGST\"\n >>> encode(\"This is a message\")\n \"tHKS KS C MGSSCGG\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String encode(String message) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.encode(\"test\"), \"TGST\"),\n Objects.equals(s.encode(\"This is a message\"), \"tHKS KS C MGSSCGG\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String vowels = \"aeiou\";\n StringBuilder sb = new StringBuilder();\n for (char c : message.toCharArray()) {\n char ch = c;\n if (Character.isUpperCase(ch)) {\n ch = Character.toLowerCase(ch);\n if (vowels.indexOf(ch) != -1) {\n ch = (char) ('a' + ((ch - 'a' + 28) % 26));\n }\n } else if (Character.isLowerCase(ch)) {\n ch = Character.toUpperCase(ch);\n if (vowels.indexOf(ch) != -1) {\n ch = (char) ('A' + ((ch - 'A' + 28) % 26));\n }\n }\n sb.append(ch);\n }\n return sb.toString();\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "Encode"} {"task_id": "Java/94", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given a list of integers.\n You need to find the largest prime value and return the sum of its digits.\n\n Examples:\n For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10\n For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25\n For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13\n For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11\n For lst = [0,81,12,3,1,21] the output should be 3\n For lst = [0,8,1,2,1,7] the output should be 7\n */\n public int skjkasdkd(List lst) {\n", "canonical_solution": " int maxx = 0;\n for (int i : lst) {\n if (i > maxx) {\n boolean isPrime = i != 1;\n for (int j = 2; j < Math.sqrt(i) + 1; j++) {\n if (i % j == 0) {\n isPrime = false;\n break;\n }\n }\n if (isPrime) {\n maxx = i;\n }\n }\n }\n int sum = 0;\n for (char c : String.valueOf(maxx).toCharArray()) {\n sum += (c - '0');\n }\n return sum;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.skjkasdkd(Arrays.asList(0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3)) == 10,\n s.skjkasdkd(Arrays.asList(1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1)) == 25,\n s.skjkasdkd(Arrays.asList(1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3)) == 13,\n s.skjkasdkd(Arrays.asList(0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6)) == 11,\n s.skjkasdkd(Arrays.asList(0, 81, 12, 3, 1, 21)) == 3,\n s.skjkasdkd(Arrays.asList(0, 8, 1, 2, 1, 7)) == 7,\n s.skjkasdkd(List.of(8191)) == 19,\n s.skjkasdkd(Arrays.asList(8191, 123456, 127, 7)) == 19,\n s.skjkasdkd(Arrays.asList(127, 97, 8192)) == 10\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given a list of integers.\n You need to find the largest prime value and return the sum of its digits.\n\n Examples:\n For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10\n For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25\n For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13\n For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11\n For lst = [0,81,12,3,1,21] the output should be 3\n For lst = [0,8,1,2,1,7] the output should be 7", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int skjkasdkd(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.skjkasdkd(Arrays.asList(0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3)) == 10,\n s.skjkasdkd(Arrays.asList(1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1)) == 25,\n s.skjkasdkd(Arrays.asList(1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3)) == 13,\n s.skjkasdkd(Arrays.asList(0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6)) == 11,\n s.skjkasdkd(Arrays.asList(0, 81, 12, 3, 1, 21)) == 3,\n s.skjkasdkd(Arrays.asList(0, 8, 1, 2, 1, 7)) == 7\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int maxx = 0;\n for (int i : lst) {\n if (i > maxx) {\n boolean isPrime = i != 1;\n for (int j = 2; j < Math.sqrt(i) + 1; j++) {\n if (i % j == 0) {\n isPrime = true;\n break;\n }\n }\n if (isPrime) {\n maxx = i;\n }\n }\n }\n int sum = 0;\n for (char c : String.valueOf(maxx).toCharArray()) {\n sum += (c - '0');\n }\n return sum;\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "Skjkasdkd"} {"task_id": "Java/95", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a map, return True if all keys are strings in lower\n case or all keys are strings in upper case, else return False.\n The function should return False is the given map is empty.\n Examples:\n checkDictCase({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n checkDictCase({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n checkDictCase({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n checkDictCase({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n checkDictCase({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n */\n public boolean checkDictCase(Map dict) {\n", "canonical_solution": " if (dict.isEmpty()) {\n return false;\n }\n String state = \"start\";\n for (Map.Entry entry : dict.entrySet()) {\n if (!(entry.getKey() instanceof String key)) {\n state = \"mixed\";\n break;\n }\n boolean is_upper = true, is_lower = true;\n for (char c : key.toCharArray()) {\n if (Character.isLowerCase(c)) {\n is_upper = false;\n } else if (Character.isUpperCase(c)) {\n is_lower = false;\n } else {\n is_upper = false;\n is_lower = false;\n }\n }\n if (state.equals(\"start\")) {\n if (is_upper) {\n state = \"upper\";\n } else if (is_lower) {\n state = \"lower\";\n } else {\n break;\n }\n } else if ((state.equals(\"upper\") && !is_upper) || (state.equals(\"lower\") && !is_lower)) {\n state = \"mixed\";\n break;\n }\n }\n return state.equals(\"upper\") || state.equals(\"lower\");\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n Map map1 = new HashMap<>();\n map1.put(\"p\", \"pineapple\");\n map1.put(\"b\", \"banana\");\n Map map2 = new HashMap<>();\n map2.put(\"p\", \"pineapple\");\n map2.put(\"A\", \"banana\");\n map2.put(\"B\", \"banana\");\n Map map3 = new HashMap<>();\n map3.put(\"p\", \"pineapple\");\n map3.put(5, \"banana\");\n map3.put(\"a\", \"banana\");\n Map map4 = new HashMap<>();\n map4.put(\"Name\", \"John\");\n map4.put(\"Age\", \"36\");\n map4.put(\"City\", \"Houston\");\n Map map5 = new HashMap<>();\n map5.put(\"STATE\", \"NC\");\n map5.put(\"ZIP\", \"12345\");\n Map map6 = new HashMap<>();\n map6.put(\"fruit\", \"Orange\");\n map6.put(\"taste\", \"Sweet\");\n Map map7 = new HashMap<>();\n List correct = Arrays.asList(\n s.checkDictCase(map1),\n !s.checkDictCase(map2),\n !s.checkDictCase(map3),\n !s.checkDictCase(map4),\n s.checkDictCase(map5),\n s.checkDictCase(map6),\n !s.checkDictCase(map7)\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a map, return True if all keys are strings in lower\n case or all keys are strings in upper case, else return False.\n The function should return False is the given map is empty.\n Examples:\n checkDictCase({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n checkDictCase({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n checkDictCase({\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n checkDictCase({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) should return False.\n checkDictCase({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean checkDictCase(Map dict) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n Map map1 = new HashMap<>();\n map1.put(\"p\", \"pineapple\");\n map1.put(\"b\", \"banana\");\n Map map2 = new HashMap<>();\n map2.put(\"p\", \"pineapple\");\n map2.put(\"A\", \"banana\");\n map2.put(\"B\", \"banana\");\n Map map3 = new HashMap<>();\n map3.put(\"p\", \"pineapple\");\n map3.put(8, \"banana\");\n map3.put(\"a\", \"banana\");\n Map map4 = new HashMap<>();\n map4.put(\"Name\", \"John\");\n map4.put(\"Age\", \"36\");\n map4.put(\"City\", \"Houston\");\n Map map5 = new HashMap<>();\n map5.put(\"STATE\", \"NC\");\n map5.put(\"ZIP\", \"12345\");\n Map map6 = new HashMap<>();\n map6.put(\"fruit\", \"Orange\");\n map6.put(\"taste\", \"Sweet\");\n Map map7 = new HashMap<>();\n List correct = Arrays.asList(\n s.checkDictCase(map1),\n !s.checkDictCase(map2),\n !s.checkDictCase(map3),\n !s.checkDictCase(map4),\n s.checkDictCase(map5)\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (dict.isEmpty()) {\n return false;\n }\n String state = \"start\";\n for (Map.Entry entry : dict.entrySet()) {\n if (!(entry.getKey() instanceof String key)) {\n state = \"mixed\";\n break;\n }\n boolean is_upper = true, is_lower = true;\n for (char c : key.toCharArray()) {\n if (Character.isLowerCase(c)) {\n is_upper = false;\n } else if (Character.isUpperCase(c)) {\n is_lower = false;\n } else {\n is_upper = false;\n is_lower = false;\n }\n }\n if (state.equals(\"start\")) {\n if (is_upper) {\n state = \"upper\";\n } else if (is_lower) {\n state = \"lower\";\n } else {\n break;\n }\n } else if ((state.equals(\"upper\") && !is_upper) && (state.equals(\"lower\") && !is_lower)) {\n state = \"mixed\";\n break;\n }\n }\n return state.equals(\"upper\") || state.equals(\"lower\");\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "CheckDictCase"} @@ -99,7 +99,7 @@ {"task_id": "Java/98", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n countUpper(\"aBCdEf\") returns 1\n countUpper(\"abcdefg\") returns 0\n countUpper(\"dBBE\") returns 0\n */ \n public int countUpper(String s) {\n", "canonical_solution": " int count = 0;\n for (int i = 0; i < s.length(); i += 2) {\n if (\"AEIOU\".indexOf(s.charAt(i)) != -1) {\n count += 1;\n }\n }\n return count;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"aBCdEf\") == 1,\n s.countUpper(\"abcdefg\") == 0,\n s.countUpper(\"dBBE\") == 0,\n s.countUpper(\"B\") == 0,\n s.countUpper(\"U\") == 1,\n s.countUpper(\"\") == 0,\n s.countUpper(\"EEEE\") == 2\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n countUpper(\"aBCdEf\") returns 1\n countUpper(\"abcdefg\") returns 0\n countUpper(\"dBBE\") returns 0", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int countUpper(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"aBCdEf\") == 1,\n s.countUpper(\"abcdefg\") == 0,\n s.countUpper(\"dBBE\") == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int count = 0;\n for (int i = 0; i < s.length(); i += 2) {\n if (\"AEIOU\".indexOf(s.charAt(i)) != -1) {\n count += 2;\n }\n }\n return count;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "CountUpper"} {"task_id": "Java/99", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n */\n public int countUpper(String value) {\n", "canonical_solution": " if (value.contains(\".\")) {\n while (value.charAt(value.length() - 1) == '0') {\n value = value.substring(0, value.length() - 1);\n }\n }\n double num = Double.parseDouble(value);\n int res = 0;\n if (value.substring(Math.max(value.length() - 2, 0)).equals(\".5\")) {\n if (num > 0) {\n res = (int) Math.ceil(num);\n } else {\n res = (int) Math.floor(num);\n }\n } else if(value.length() > 0) {\n res = (int) Math.round(num);\n }\n return res;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"10\") == 10,\n s.countUpper(\"14.5\") == 15,\n s.countUpper(\"-15.5\") == -16,\n s.countUpper(\"15.3\") == 15,\n s.countUpper(\"0\") == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int countUpper(String value) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"10\") == 10,\n s.countUpper(\"15.3\") == 15\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (value.contains(\".\")) {\n while (value.charAt(value.length() - 1) == '0') {\n value = value.substring(0, value.length() - 1);\n }\n }\n double num = Double.parseDouble(value);\n int res = 0;\n if (value.substring(Math.max(value.length() - 2, 0)).equals(\".5\")) {\n if (num > 0) {\n res = (int) Math.floor(num);\n } else {\n res = (int) Math.ceil(num);\n }\n } else if(value.length() > 0) {\n res = (int) Math.round(num);\n }\n return res;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "ClosestInteger"} {"task_id": "Java/100", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> makeAPile(3)\n [3, 5, 7]\n */\n public List makeAPile(int n) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (int i = 0; i < n; i++) {\n result.add(n + 2 * i);\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.makeAPile(3).equals(Arrays.asList(3, 5, 7)),\n s.makeAPile(4).equals(Arrays.asList(4, 6, 8, 10)),\n s.makeAPile(5).equals(Arrays.asList(5, 7, 9, 11, 13)),\n s.makeAPile(6).equals(Arrays.asList(6, 8, 10, 12, 14, 16)),\n s.makeAPile(8).equals(Arrays.asList(8, 10, 12, 14, 16, 18, 20, 22))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> makeAPile(3)\n [3, 5, 7]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List makeAPile(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.makeAPile(3).equals(Arrays.asList(3, 5, 7))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (int i = 0; i < n; i++) {\n result.add(n + 2 * i + i);\n }\n return result;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "MakeAPile"} -{"task_id": "Java/101", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\").equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\").equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n */\n public List wordStrings(String s) {\n", "canonical_solution": " if (s.length() == 0) {\n return List.of();\n }\n StringBuilder sb = new StringBuilder();\n\n for (char letter : s.toCharArray()) {\n if (letter == ',') {\n sb.append(' ');\n } else {\n sb.append(letter);\n }\n }\n\n return new ArrayList<>(Arrays.asList(sb.toString().split(\"\\s+\" )));\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.wordStrings(\"Hi, my name is John\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\" )),\n s.wordStrings(\"One, two, three, four, five, six\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" )),\n s.wordStrings(\"Hi, my name\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\" )),\n s.wordStrings(\"One,, two, three, four, five, six,\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" )),\n s.wordStrings(\"\" ).equals(List.of()),\n s.wordStrings(\"ahmed , gamal\" ).equals(Arrays.asList(\"ahmed\", \"gamal\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\").equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\").equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List wordStrings(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.wordStrings(\"Hi, my name is John\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\" )),\n s.wordStrings(\"One, two, three, four, five, six\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (s.length() == 0) {\n return List.of();\n }\n StringBuilder sb = new StringBuilder();\n\n for (char letter : s.toCharArray()) {\n if (letter == ',') {\n sb.append(' ');\n } else {\n sb.append(letter);\n }\n }\n\n return new ArrayList<>(Arrays.asList(sb.toString().split(\"\\s+\" )));\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "WordsString"} +{"task_id": "Java/101", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\").equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\").equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n */\n public List wordStrings(String s) {\n", "canonical_solution": " if (s.length() == 0) {\n return List.of();\n }\n StringBuilder sb = new StringBuilder();\n\n for (char letter : s.toCharArray()) {\n if (letter == ',') {\n sb.append(' ');\n } else {\n sb.append(letter);\n }\n }\n\n return new ArrayList<>(Arrays.asList(sb.toString().split(\"\\s+\" )));\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.wordStrings(\"Hi, my name is John\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\" )),\n s.wordStrings(\"One, two, three, four, five, six\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" )),\n s.wordStrings(\"Hi, my name\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\" )),\n s.wordStrings(\"One,, two, three, four, five, six,\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" )),\n s.wordStrings(\"\" ).equals(List.of()),\n s.wordStrings(\"ahmed , gamal\" ).equals(Arrays.asList(\"ahmed\", \"gamal\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\").equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\").equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List wordStrings(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.wordStrings(\"Hi, my name is John\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\" )),\n s.wordStrings(\"One, two, three, four, five, six\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (s.length() == 0) {\n return List.of();\n }\n StringBuilder sb = new StringBuilder();\n\n for (char letter : s.toCharArray()) {\n if (letter == ',') {\n sb.append(',');\n } else {\n sb.append(letter);\n }\n }\n\n return new ArrayList<>(Arrays.asList(sb.toString().split(\"\\s+\" )));\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "WordsString"} {"task_id": "Java/102", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If\n there's no such number, then the function should return -1.\n \n For example:\n chooseNum(12, 15) = 14\n chooseNum(13, 12) = -1\n */\n public int chooseNum(int x, int y) {\n", "canonical_solution": " if (x > y) {\n return -1;\n }\n if (y % 2 == 0) {\n return y;\n }\n if (x == y) {\n return -1;\n }\n return y - 1;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.chooseNum(12, 15) == 14,\n s.chooseNum(13, 12) == -1,\n s.chooseNum(33, 12354) == 12354,\n s.chooseNum(5234, 5233) == -1,\n s.chooseNum(6, 29) == 28,\n s.chooseNum(27, 10) == -1,\n s.chooseNum(7, 7) == -1,\n s.chooseNum(546, 546) == 546\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If\n there's no such number, then the function should return -1.\n \n For example:\n chooseNum(12, 15) = 14\n chooseNum(13, 12) = -1", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int chooseNum(int x, int y) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.chooseNum(12, 15) == 14,\n s.chooseNum(13, 12) == -1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (x > y) {\n return -1;\n }\n if (y % 2 == 0) {\n return y;\n }\n if (x == y) {\n return -1;\n }\n return x - 1;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "ChooseNum"} {"task_id": "Java/103", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m).\n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n Example:\n roundedAvg(1, 5) => \"11\"\n roundedAvg(7, 5) => -1\n roundedAvg(10, 20) => \"1111\"\n roundedAvg(20, 33) => \"11011\"\n */\n public Object roundedAvg(int n, int m) {\n", "canonical_solution": " if (n > m) {\n return -1;\n }\n return Integer.toBinaryString((int) Math.round((double) (m + n) / 2));\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals((String) s.roundedAvg(1, 5), \"11\" ),\n Objects.equals((String) s.roundedAvg(7, 13), \"1010\" ),\n Objects.equals((String) s.roundedAvg(964, 977), \"1111001011\" ),\n Objects.equals((String) s.roundedAvg(996, 997), \"1111100101\" ),\n Objects.equals((String) s.roundedAvg(560, 851), \"1011000010\" ),\n Objects.equals((String) s.roundedAvg(185, 546), \"101101110\" ),\n Objects.equals((String) s.roundedAvg(362, 496), \"110101101\" ),\n Objects.equals((String) s.roundedAvg(350, 902), \"1001110010\" ),\n Objects.equals((String) s.roundedAvg(197, 233), \"11010111\" ),\n (int) s.roundedAvg(7, 5) == -1,\n (int) s.roundedAvg(5, 1) == -1,\n Objects.equals((String) s.roundedAvg(5, 5), \"101\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m).\n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n Example:\n roundedAvg(1, 5) => \"11\"\n roundedAvg(7, 5) => -1\n roundedAvg(10, 20) => \"1111\"\n roundedAvg(20, 33) => \"11011\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public Object roundedAvg(int n, int m) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals((String) s.roundedAvg(1, 5), \"11\" ),\n (int) s.roundedAvg(7, 5) == -1,\n Objects.equals((String) s.roundedAvg(10, 20), \"1111\" ),\n Objects.equals((String) s.roundedAvg(20, 33), \"11011\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (n > m) {\n return -1;\n }\n return Integer.toBinaryString((int) Math.round((double) (m + n + 1) / 2));\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "RoundedAvg"} {"task_id": "Java/104", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a list of positive integers x. return a sorted list of all\n elements that hasn't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> uniqueDigits(Arrays.asList(15, 33, 1422, 1))\n [1, 15, 33]\n >>> uniqueDigits(Arrays.asList(152, 323, 1422, 10))\n []\n */\n public List uniqueDigits(List x) {\n", "canonical_solution": " List odd_digit_elements = new ArrayList<>();\n for (int i : x) {\n boolean is_unique = true;\n for (char c : String.valueOf(i).toCharArray()) {\n if ((c - '0') % 2 == 0) {\n is_unique = false;\n break;\n }\n }\n if (is_unique) {\n odd_digit_elements.add(i);\n }\n }\n Collections.sort(odd_digit_elements);\n return odd_digit_elements;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.uniqueDigits(Arrays.asList(15, 33, 1422, 1)).equals(Arrays.asList(1, 15, 33)),\n s.uniqueDigits(Arrays.asList(152, 323, 1422, 10)).equals(List.of()),\n s.uniqueDigits(Arrays.asList(12345, 2033, 111, 151)).equals(Arrays.asList(111, 151)),\n s.uniqueDigits(Arrays.asList(135, 103, 31)).equals(Arrays.asList(31, 135))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a list of positive integers x. return a sorted list of all\n elements that hasn't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> uniqueDigits(Arrays.asList(15, 33, 1422, 1))\n [1, 15, 33]\n >>> uniqueDigits(Arrays.asList(152, 323, 1422, 10))\n []", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List uniqueDigits(List x) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.uniqueDigits(Arrays.asList(15, 33, 1422, 1)).equals(Arrays.asList(1, 15, 33)),\n s.uniqueDigits(Arrays.asList(152, 323, 1422, 10)).equals(List.of())\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List odd_digit_elements = new ArrayList<>();\n for (int i : x) {\n boolean is_unique = true;\n for (char c : String.valueOf(i).toCharArray()) {\n if ((c - '0') % 2 == 0) {\n is_unique = false;\n break;\n }\n }\n if (is_unique) {\n odd_digit_elements.add(i);\n odd_digit_elements.add(1);\n }\n }\n Collections.sort(odd_digit_elements);\n return odd_digit_elements;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "UniqueDigits"} @@ -112,7 +112,7 @@ {"task_id": "Java/111", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n\n Example:\n histogram(\"a b c\") == {\"a\": 1, \"b\": 1, \"c\": 1}\n histogram(\"a b b a\") == {\"a\": 2, \"b\": 2}\n histogram(\"a b c a b\") == {\"a\": 2, \"b\": 2}\n histogram(\"b b b b a\") == {\"b\": 4}\n histogram(\"\") == {}\n */\n public Map histogram(String test) {\n", "canonical_solution": " Map dict1 = new HashMap<>();\n List list1 = Arrays.asList(test.split(\" \" ));\n int t = 0;\n for (String i : list1) {\n if (Collections.frequency(list1, i) > t && !i.isEmpty()) {\n t = Collections.frequency(list1, i);\n }\n }\n if (t > 0) {\n for (String i : list1) {\n if (Collections.frequency(list1, i) == t) {\n dict1.put(i, t);\n }\n }\n }\n return dict1;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n Map map1 = new HashMap<>();\n map1.put(\"a\", 2);\n map1.put(\"b\", 2);\n Map map2 = new HashMap<>();\n map2.put(\"a\", 2);\n map2.put(\"b\", 2);\n Map map3 = new HashMap<>();\n map3.put(\"a\", 1);\n map3.put(\"b\", 1);\n map3.put(\"c\", 1);\n map3.put(\"d\", 1);\n map3.put(\"g\", 1);\n Map map4 = new HashMap<>();\n map4.put(\"r\", 1);\n map4.put(\"t\", 1);\n map4.put(\"g\", 1);\n Map map5 = new HashMap<>();\n map5.put(\"b\", 4);\n Map map6 = new HashMap<>();\n map6.put(\"r\", 1);\n map6.put(\"t\", 1);\n map6.put(\"g\", 1);\n Map map7 = new HashMap<>();\n Map map8 = new HashMap<>();\n map8.put(\"a\", 1);\n List correct = Arrays.asList(\n s.histogram(\"a b b a\" ).equals(map1),\n s.histogram(\"a b c a b\" ).equals(map2),\n s.histogram(\"a b c d g\" ).equals(map3),\n s.histogram(\"r t g\" ).equals(map4),\n s.histogram(\"b b b b a\" ).equals(map5),\n s.histogram(\"r t g\" ).equals(map6),\n s.histogram(\"\" ).equals(map7),\n s.histogram(\"a\" ).equals(map8)\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n\n Example:\n histogram(\"a b c\") == {\"a\": 1, \"b\": 1, \"c\": 1}\n histogram(\"a b b a\") == {\"a\": 2, \"b\": 2}\n histogram(\"a b c a b\") == {\"a\": 2, \"b\": 2}\n histogram(\"b b b b a\") == {\"b\": 4}\n histogram(\"\") == {}", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public Map histogram(String test) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n Map map1 = new HashMap<>();\n map1.put(\"a\", 2);\n map1.put(\"b\", 2);\n Map map2 = new HashMap<>();\n map2.put(\"a\", 2);\n map2.put(\"b\", 2);\n Map map3 = new HashMap<>();\n map3.put(\"a\", 1);\n map3.put(\"b\", 1);\n map3.put(\"c\", 1);\n map3.put(\"d\", 1);\n map3.put(\"g\", 1);\n Map map4 = new HashMap<>();\n map4.put(\"a\", 1);\n map4.put(\"b\", 1);\n map4.put(\"c\", 1);\n Map map5 = new HashMap<>();\n map5.put(\"b\", 4);\n Map map6 = new HashMap<>();\n map6.put(\"r\", 1);\n map6.put(\"t\", 1);\n map6.put(\"g\", 1);\n Map map7 = new HashMap<>();\n Map map8 = new HashMap<>();\n map8.put(\"a\", 1);\n List correct = Arrays.asList(\n s.histogram(\"a b b a\" ).equals(map1),\n s.histogram(\"a b c a b\" ).equals(map2),\n s.histogram(\"a b c\" ).equals(map4),\n s.histogram(\"b b b b a\" ).equals(map5),\n s.histogram(\"\" ).equals(map7)\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " Map dict1 = new HashMap<>();\n List list1 = Arrays.asList(test.split(\" \" ));\n int t = 1;\n for (String i : list1) {\n if (Collections.frequency(list1, i) > t && !i.isEmpty()) {\n t = Collections.frequency(list1, i);\n }\n }\n if (t > 0) {\n for (String i : list1) {\n if (Collections.frequency(list1, i) == t) {\n dict1.put(i, t);\n }\n }\n }\n return dict1;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "Histogram"} {"task_id": "Java/112", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Task\n We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and true/false for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be (\"bcd\",false)\n For s = \"abcdef\", c = \"b\" the result should be (\"acdef\",false)\n For s = \"abcdedcba\", c = \"ab\", the result should be (\"cdedc\",true)\n */\n public List reverseDelete(String s, String c) {\n", "canonical_solution": " StringBuilder sb = new StringBuilder();\n for (char ch : s.toCharArray()) {\n if (c.indexOf(ch) == -1) {\n sb.append(ch);\n }\n }\n return Arrays.asList(sb.toString(), sb.toString().equals(sb.reverse().toString()));\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.reverseDelete(\"abcde\", \"ae\" ).equals(Arrays.asList(\"bcd\", false)),\n s.reverseDelete(\"abcdef\", \"b\" ).equals(Arrays.asList(\"acdef\", false)),\n s.reverseDelete(\"abcdedcba\", \"ab\" ).equals(Arrays.asList(\"cdedc\", true)),\n s.reverseDelete(\"dwik\", \"w\" ).equals(Arrays.asList(\"dik\", false)),\n s.reverseDelete(\"a\", \"a\" ).equals(Arrays.asList(\"\", true)),\n s.reverseDelete(\"abcdedcba\", \"\" ).equals(Arrays.asList(\"abcdedcba\", true)),\n s.reverseDelete(\"abcdedcba\", \"v\" ).equals(Arrays.asList(\"abcdedcba\", true)),\n s.reverseDelete(\"vabba\", \"v\" ).equals(Arrays.asList(\"abba\", true)),\n s.reverseDelete(\"mamma\", \"mia\" ).equals(Arrays.asList(\"\", true))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Task\n We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and true/false for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be (\"bcd\",false)\n For s = \"abcdef\", c = \"b\" the result should be (\"acdef\",false)\n For s = \"abcdedcba\", c = \"ab\", the result should be (\"cdedc\",true)", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List reverseDelete(String s, String c) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.reverseDelete(\"abcde\", \"ae\" ).equals(Arrays.asList(\"bcd\", false)),\n s.reverseDelete(\"abcdef\", \"b\" ).equals(Arrays.asList(\"acdef\", false)),\n s.reverseDelete(\"abcdedcba\", \"ab\" ).equals(Arrays.asList(\"cdedc\", true))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " StringBuilder sb = new StringBuilder();\n for (char ch : s.toCharArray()) {\n if (c.indexOf(ch) != -1) {\n sb.append(ch);\n }\n }\n return Arrays.asList(sb.toString(), sb.toString().equals(sb.reverse().toString()));\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "ReverseDelete"} {"task_id": "Java/113", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i\"th string of the input.\n\n >>> oddCount(Arrays.asList(\"1234567\"))\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> oddCount(Arrays.asList(\"3\",\"11111111\"))\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n */\n public List oddCount(List lst) {\n", "canonical_solution": " List res = new ArrayList<>();\n for (String arr : lst) {\n int n = 0;\n for (char d : arr.toCharArray()) {\n if ((d - '0') % 2 == 1) {\n n += 1;\n }\n }\n res.add(\"the number of odd elements \" + n + \"n the str\" + n + \"ng \" + n + \" of the \" + n + \"nput.\" );\n }\n return res;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.oddCount(List.of(\"1234567\" )).equals(List.of(\"the number of odd elements 4n the str4ng 4 of the 4nput.\" )),\n s.oddCount(Arrays.asList(\"3\", \"11111111\" )).equals(Arrays.asList(\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\" )),\n s.oddCount(Arrays.asList(\"271\", \"137\", \"314\" )).equals(Arrays.asList(\n \"the number of odd elements 2n the str2ng 2 of the 2nput.\",\n \"the number of odd elements 3n the str3ng 3 of the 3nput.\",\n \"the number of odd elements 2n the str2ng 2 of the 2nput.\"\n ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i\"th string of the input.\n\n >>> oddCount(Arrays.asList(\"1234567\"))\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> oddCount(Arrays.asList(\"3\",\"11111111\"))\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List oddCount(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.oddCount(List.of(\"1234567\" )).equals(List.of(\"the number of odd elements 4n the str4ng 4 of the 4nput.\" )),\n s.oddCount(Arrays.asList(\"3\", \"11111111\" )).equals(Arrays.asList(\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List res = new ArrayList<>();\n for (String arr : lst) {\n int n = 0;\n for (char d : arr.toCharArray()) {\n if ((d - '0') % 2 == 1) {\n n += 1;\n }\n }\n res.add(\"the number of odd elements \" + n + \"n the str\" + n + \"ng \" + n + \" of \" + n + \" the \" + n + \"nput.\" );\n }\n return res;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "OddCount"} -{"task_id": "Java/114", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1\n minSubArraySum(Arrays.asList(-1, -2, -3)) == -6\n */\n public int minSubArraySum(List nums) {\n", "canonical_solution": " int minSum = Integer.MAX_VALUE;\n int sum = 0;\n for (Integer num : nums) {\n sum += num;\n if (minSum > sum) {\n minSum = sum;\n }\n if (sum > 0) {\n sum = 0;\n }\n }\n return minSum;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1,\n s.minSubArraySum(Arrays.asList(-1, -2, -3)) == -6,\n s.minSubArraySum(Arrays.asList(-1, -2, -3, 2, -10)) == -14,\n s.minSubArraySum(List.of(-999999999)) == -999999999,\n s.minSubArraySum(Arrays.asList(0, 10, 20, 1000000)) == 0,\n s.minSubArraySum(Arrays.asList(-1, -2, -3, 10, -5)) == -6,\n s.minSubArraySum(Arrays.asList(100, -1, -2, -3, 10, -5)) == -6,\n s.minSubArraySum(Arrays.asList(10, 11, 13, 8, 3, 4)) == 3,\n s.minSubArraySum(Arrays.asList(100, -33, 32, -1, 0, -2)) == -33,\n s.minSubArraySum(List.of(-10)) == -10,\n s.minSubArraySum(List.of(7)) == 7,\n s.minSubArraySum(Arrays.asList(1, -1)) == -1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1\n minSubArraySum(Arrays.asList(-1, -2, -3)) == -6", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int minSubArraySum(List nums) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1,\n s.minSubArraySum(Arrays.asList(-1, -2, -3)) == -6\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int minSum = Integer.MAX_VALUE;\n int sum = 0;\n for (Integer num : nums) {\n sum += num;\n if (minSum > sum) {\n minSum = sum + 1;\n }\n if (sum > 0) {\n sum = 0;\n }\n }\n return minSum;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "Minsubarraysum"} +{"task_id": "Java/114", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1\n minSubArraySum(Arrays.asList(-1, -2, -3)) == -6\n */\n public int minSubArraySum(List nums) {\n", "canonical_solution": " int minSum = Integer.MAX_VALUE;\n int sum = 0;\n for (Integer num : nums) {\n sum += num;\n if (minSum > sum) {\n minSum = sum;\n }\n if (sum > 0) {\n sum = 0;\n }\n }\n return minSum;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1,\n s.minSubArraySum(Arrays.asList(-1, -2, -3)) == -6,\n s.minSubArraySum(Arrays.asList(-1, -2, -3, 2, -10)) == -14,\n s.minSubArraySum(List.of(-999999999)) == -999999999,\n s.minSubArraySum(Arrays.asList(0, 10, 20, 1000000)) == 0,\n s.minSubArraySum(Arrays.asList(-1, -2, -3, 10, -5)) == -6,\n s.minSubArraySum(Arrays.asList(100, -1, -2, -3, 10, -5)) == -6,\n s.minSubArraySum(Arrays.asList(10, 11, 13, 8, 3, 4)) == 3,\n s.minSubArraySum(Arrays.asList(100, -33, 32, -1, 0, -2)) == -33,\n s.minSubArraySum(List.of(-10)) == -10,\n s.minSubArraySum(List.of(7)) == 7,\n s.minSubArraySum(Arrays.asList(1, -1)) == -1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1\n minSubArraySum(Arrays.asList(-1, -2, -3)) == -6", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int minSubArraySum(List nums) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1,\n s.minSubArraySum(Arrays.asList(-1, -2, -3)) == -6\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int minSum = Integer.MIN_VALUE;\n int sum = 0;\n for (Integer num : nums) {\n sum += num;\n if (minSum > sum) {\n minSum = sum ;\n }\n if (sum > 0) {\n sum = 0;\n }\n }\n return minSum;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "Minsubarraysum"} {"task_id": "Java/115", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given a rectangular grid of wells. Each row represents a single well,\n and each 1 in a row represents a single unit of water.\n Each well has a corresponding bucket that can be used to extract water from it,\n and all buckets have the same capacity.\n Your task is to use the buckets to empty the wells.\n Output the number of times you need to lower the buckets.\n\n Example 1:\n Input:\n grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n bucket_capacity : 1\n Output: 6\n\n Example 2:\n Input:\n grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n bucket_capacity : 2\n Output: 5\n\n Example 3:\n Input:\n grid : [[0,0,0], [0,0,0]]\n bucket_capacity : 5\n Output: 0\n\n Constraints:\n * all wells have the same length\n * 1 <= grid.length <= 10^2\n * 1 <= grid[:,1].length <= 10^2\n * grid[i][j] -> 0 | 1\n * 1 <= capacity <= 10\n */\n public int maxFill(List> grid, int capacity) {\n", "canonical_solution": " int sum = 0;\n for (List arr : grid) {\n sum += Math.ceil((double) arr.stream().reduce(Integer::sum).get() / capacity);\n }\n return sum;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 1, 0), Arrays.asList(0, 1, 0, 0), Arrays.asList(1, 1, 1, 1)), 1) == 6,\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 1, 1), Arrays.asList(0, 0, 0, 0), Arrays.asList(1, 1, 1, 1), Arrays.asList(0, 1, 1, 1)), 2) == 5,\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 0), Arrays.asList(0, 0, 0)), 5) == 0,\n s.maxFill(Arrays.asList(Arrays.asList(1, 1, 1, 1), Arrays.asList(1, 1, 1, 1)), 2) == 4,\n s.maxFill(Arrays.asList(Arrays.asList(1, 1, 1, 1), Arrays.asList(1, 1, 1, 1)), 9) == 2\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given a rectangular grid of wells. Each row represents a single well,\n and each 1 in a row represents a single unit of water.\n Each well has a corresponding bucket that can be used to extract water from it,\n and all buckets have the same capacity.\n Your task is to use the buckets to empty the wells.\n Output the number of times you need to lower the buckets.\n\n Example 1:\n Input:\n grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n bucket_capacity : 1\n Output: 6\n\n Example 2:\n Input:\n grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n bucket_capacity : 2\n Output: 5\n\n Example 3:\n Input:\n grid : [[0,0,0], [0,0,0]]\n bucket_capacity : 5\n Output: 0\n\n Constraints:\n * all wells have the same length\n * 1 <= grid.length <= 10^2\n * 1 <= grid[:,1].length <= 10^2\n * grid[i][j] -> 0 | 1\n * 1 <= capacity <= 10", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int maxFill(List> grid, int capacity) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 1, 0), Arrays.asList(0, 1, 0, 0), Arrays.asList(1, 1, 1, 1)), 1) == 6,\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 1, 1), Arrays.asList(0, 0, 0, 0), Arrays.asList(1, 1, 1, 1), Arrays.asList(0, 1, 1, 1)), 2) == 5,\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 0), Arrays.asList(0, 0, 0)), 5) == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int sum = 0;\n for (List arr : grid) {\n sum += Math.floor((double) arr.stream().reduce(Integer::sum).get() / capacity);\n }\n return sum;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "MaxFill"} {"task_id": "Java/116", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n

\n It must be implemented like this:\n >>> sortArray(Arrays.asList(1, 5, 2, 3, 4)).equals(Arrays.asList(1, 2, 3, 4, 5))\n >>> sortArray(Arrays.asList(-2, -3, -4, -5, -6)).equals(Arrays.asList(-6, -5, -4, -3, -2))\n >>> sortArray(Arrays.asList(1, 0, 2, 3, 4)).equals(Arrays.asList(0, 1, 2, 3, 4))\n */\n public List sortArray(List arr) {\n", "canonical_solution": " List < Integer > sorted_arr = new ArrayList<>(arr);\n sorted_arr.sort(new Comparator() {\n @Override\n public int compare(Integer o1, Integer o2) {\n int cnt1 = (int) Integer.toBinaryString(Math.abs(o1)).chars().filter(ch -> ch == '1').count();\n int cnt2 = (int) Integer.toBinaryString(Math.abs(o2)).chars().filter(ch -> ch == '1').count();\n if (cnt1 > cnt2) {\n return 1;\n } else if (cnt1 < cnt2) {\n return -1;\n } else {\n return o1.compareTo(o2);\n }\n }\n });\n return sorted_arr;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortArray(new ArrayList<>(Arrays.asList(1, 5, 2, 3, 4))).equals(Arrays.asList(1, 2, 4, 3, 5)),\n s.sortArray(new ArrayList<>(Arrays.asList(-2, -3, -4, -5, -6))).equals(Arrays.asList(-4, -2, -6, -5, -3)),\n s.sortArray(new ArrayList<>(Arrays.asList(1, 0, 2, 3, 4))).equals(Arrays.asList(0, 1, 2, 4, 3)),\n s.sortArray(new ArrayList<>(List.of())).equals(List.of()),\n s.sortArray(new ArrayList<>(Arrays.asList(2, 5, 77, 4, 5, 3, 5, 7, 2, 3, 4))).equals(Arrays.asList(2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77)),\n s.sortArray(new ArrayList<>(Arrays.asList(3, 6, 44, 12, 32, 5))).equals(Arrays.asList(32, 3, 5, 6, 12, 44)),\n s.sortArray(new ArrayList<>(Arrays.asList(2, 4, 8, 16, 32))).equals(Arrays.asList(2, 4, 8, 16, 32)),\n s.sortArray(new ArrayList<>(Arrays.asList(2, 4, 8, 16, 32))).equals(Arrays.asList(2, 4, 8, 16, 32))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n

\n It must be implemented like this:\n >>> sortArray(Arrays.asList(1, 5, 2, 3, 4)).equals(Arrays.asList(1, 2, 3, 4, 5))\n >>> sortArray(Arrays.asList(-2, -3, -4, -5, -6)).equals(Arrays.asList(-6, -5, -4, -3, -2))\n >>> sortArray(Arrays.asList(1, 0, 2, 3, 4)).equals(Arrays.asList(0, 1, 2, 3, 4))", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List sortArray(List arr) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortArray(new ArrayList<>(Arrays.asList(1, 5, 2, 3, 4))).equals(Arrays.asList(1, 2, 4, 3, 5)),\n s.sortArray(new ArrayList<>(Arrays.asList(-2, -3, -4, -5, -6))).equals(Arrays.asList(-4, -2, -6, -5, -3)),\n s.sortArray(new ArrayList<>(Arrays.asList(1, 0, 2, 3, 4))).equals(Arrays.asList(0, 1, 2, 4, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List < Integer > sorted_arr = new ArrayList<>(arr);\n sorted_arr.sort(new Comparator() {\n @Override\n public int compare(Integer o1, Integer o2) {\n int cnt1 = (int) Integer.toBinaryString(Math.abs(o1)).chars().filter(ch -> ch == '1').count();\n int cnt2 = (int) Integer.toBinaryString(Math.abs(o2)).chars().filter(ch -> ch == '1').count();\n if (cnt1 > cnt2) {\n return 1;\n } else if (cnt1 < cnt2) {\n return -1;\n } else {\n return o1.compareTo(o2);\n }\n }\n });\n return arr;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "SortArray"} {"task_id": "Java/117", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a string s and a natural number n, you have been tasked to implement\n a function that returns a list of all words from string s that contain exactly\n n consonants, in order these words appear in the string s.\n If the string s is empty then the function should return an empty list.\n Note: you may assume the input string contains only letters and spaces.\n Examples:\n selectWords(\"Mary had a little lamb\", 4) ==> [\"little\"]\n selectWords(\"Mary had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n selectWords(\"simple white space\", 2) ==> []\n selectWords(\"Hello world\", 4) ==> [\"world\"]\n selectWords(\"Uncle sam\", 3) ==> [\"Uncle\"]\n */\n public List selectWords(String s, int n) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (String word : s.split(\" \")) {\n int n_consonants = 0;\n for (char c : word.toCharArray()) {\n c = Character.toLowerCase(c);\n if (\"aeiou\".indexOf(c) == -1) {\n n_consonants += 1;\n }\n }\n if (n_consonants == n) {\n result.add(word);\n }\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.selectWords(\"Mary had a little lamb\", 4).equals(List.of(\"little\" )),\n s.selectWords(\"Mary had a little lamb\", 3).equals(Arrays.asList(\"Mary\", \"lamb\")),\n s.selectWords(\"simple white space\", 2).equals(List.of()),\n s.selectWords(\"Hello world\", 4).equals(List.of(\"world\" )),\n s.selectWords(\"Uncle sam\", 3).equals(List.of(\"Uncle\" )),\n s.selectWords(\"\", 4).equals(List.of()),\n s.selectWords(\"a b c d e f\", 1).equals(Arrays.asList(\"b\", \"c\", \"d\", \"f\"))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a string s and a natural number n, you have been tasked to implement\n a function that returns a list of all words from string s that contain exactly\n n consonants, in order these words appear in the string s.\n If the string s is empty then the function should return an empty list.\n Note: you may assume the input string contains only letters and spaces.\n Examples:\n selectWords(\"Mary had a little lamb\", 4) ==> [\"little\"]\n selectWords(\"Mary had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n selectWords(\"simple white space\", 2) ==> []\n selectWords(\"Hello world\", 4) ==> [\"world\"]\n selectWords(\"Uncle sam\", 3) ==> [\"Uncle\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List selectWords(String s, int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.selectWords(\"Mary had a little lamb\", 4).equals(List.of(\"little\" )),\n s.selectWords(\"Mary had a little lamb\", 3).equals(Arrays.asList(\"Mary\", \"lamb\")),\n s.selectWords(\"simple white space\", 2).equals(List.of()),\n s.selectWords(\"Hello world\", 4).equals(List.of(\"world\" )),\n s.selectWords(\"Uncle sam\", 3).equals(List.of(\"Uncle\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (String word : s.split(\" \")) {\n int n_consonants = 0;\n for (char c : word.toCharArray()) {\n c = Character.toLowerCase(c);\n if (\"aeiou\".indexOf(c) != -1) {\n n_consonants += 1;\n }\n }\n if (n_consonants == n) {\n result.add(word);\n }\n }\n return result;\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "SelectWords"} @@ -127,7 +127,7 @@ {"task_id": "Java/126", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return false. Assume no negative numbers and only integers.\n\n Examples\n isSorted(Arrays.asList(5)) -> true\n isSorted(Arrays.asList(1, 2, 3, 4, 5)) -> true\n isSorted(Arrays.asList(1, 3, 2, 4, 5)) -> false\n isSorted(Arrays.asList(1, 2, 3, 4, 5, 6)) -> true\n isSorted(Arrays.asList(1, 2, 3, 4, 5, 6, 7)) -> true\n isSorted(Arrays.asList(1, 3, 2, 4, 5, 6, 7)) -> false\n isSorted(Arrays.asList(1, 2, 2, 3, 3, 4)) -> true\n isSorted(Arrays.asList(1, 2, 2, 2, 3, 4)) -> false\n */\n public boolean isSorted(List lst) {\n", "canonical_solution": " List sorted_lst = new ArrayList<>(lst);\n Collections.sort(sorted_lst);\n if (!lst.equals(sorted_lst)) {\n return false;\n }\n for (int i = 0; i < lst.size() - 2; i++) {\n if (lst.get(i) == lst.get(i + 1) && lst.get(i) == lst.get(i + 2)) {\n return false;\n }\n }\n return true;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isSorted(new ArrayList<>(List.of(5))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 3, 2, 4, 5))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 6))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 6, 7))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 3, 2, 4, 5, 6, 7))) == false,\n s.isSorted(new ArrayList<>(List.of())) == true,\n s.isSorted(new ArrayList<>(List.of(1))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(3, 2, 1))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 2, 2, 3, 4))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 3, 3, 4))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 2, 3, 3, 4))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4))) == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return false. Assume no negative numbers and only integers.\n\n Examples\n isSorted(Arrays.asList(5)) -> true\n isSorted(Arrays.asList(1, 2, 3, 4, 5)) -> true\n isSorted(Arrays.asList(1, 3, 2, 4, 5)) -> false\n isSorted(Arrays.asList(1, 2, 3, 4, 5, 6)) -> true\n isSorted(Arrays.asList(1, 2, 3, 4, 5, 6, 7)) -> true\n isSorted(Arrays.asList(1, 3, 2, 4, 5, 6, 7)) -> false\n isSorted(Arrays.asList(1, 2, 2, 3, 3, 4)) -> true\n isSorted(Arrays.asList(1, 2, 2, 2, 3, 4)) -> false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean isSorted(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isSorted(new ArrayList<>(List.of(5))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 3, 2, 4, 5))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 6))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 6, 7))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 3, 2, 4, 5, 6, 7))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 2, 2, 3, 4))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 2, 3, 3, 4))) == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List sorted_lst = new ArrayList<>(lst);\n Collections.sort(sorted_lst);\n if (!lst.equals(sorted_lst)) {\n return false;\n }\n for (int i = 0; i < lst.size() - 2; i++) {\n if (lst.get(i) == lst.get(i + 1)) {\n return false;\n }\n }\n return true;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "IsSorted"} {"task_id": "Java/127", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given two intervals,\n where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).\n The given intervals are closed which means that the interval (start, end)\n includes both start and end.\n For each given interval, it is assumed that its start is less or equal its end.\n Your task is to determine whether the length of intersection of these two\n intervals is a prime number.\n Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)\n which its length is 1, which not a prime number.\n If the length of the intersection is a prime number, return \"YES\",\n otherwise, return \"NO\".\n If the two intervals don't intersect, return \"NO\".\n\n\n [input/output] samples:\n intersection((1, 2), (2, 3)) ==> \"NO\"\n intersection((-1, 1), (0, 4)) ==> \"NO\"\n intersection((-3, -1), (-5, 5)) ==> \"YES\"\n */\n public String intersection(List interval1, List interval2) {\n", "canonical_solution": " int l = Math.max(interval1.get(0), interval2.get(0));\n int r = Math.min(interval1.get(1), interval2.get(1));\n int length = r - l;\n if (length <= 0) {\n return \"NO\";\n }\n if (length == 1) {\n return \"NO\";\n }\n if (length == 2) {\n return \"YES\";\n }\n for (int i = 2; i < length; i++) {\n if (length % i == 0) {\n return \"NO\";\n }\n }\n return \"YES\";\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.intersection(Arrays.asList(1, 2), Arrays.asList(2, 3)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-1, 1), Arrays.asList(0, 4)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-3, -1), Arrays.asList(-5, 5)), \"YES\" ),\n Objects.equals(s.intersection(Arrays.asList(-2, 2), Arrays.asList(-4, 0)), \"YES\" ),\n Objects.equals(s.intersection(Arrays.asList(-11, 2), Arrays.asList(-1, -1)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(1, 2), Arrays.asList(3, 5)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(1, 2), Arrays.asList(1, 2)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-2, -2), Arrays.asList(-3, -2)), \"NO\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given two intervals,\n where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).\n The given intervals are closed which means that the interval (start, end)\n includes both start and end.\n For each given interval, it is assumed that its start is less or equal its end.\n Your task is to determine whether the length of intersection of these two\n intervals is a prime number.\n Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)\n which its length is 1, which not a prime number.\n If the length of the intersection is a prime number, return \"YES\",\n otherwise, return \"NO\".\n If the two intervals don't intersect, return \"NO\".\n\n\n [input/output] samples:\n intersection((1, 2), (2, 3)) ==> \"NO\"\n intersection((-1, 1), (0, 4)) ==> \"NO\"\n intersection((-3, -1), (-5, 5)) ==> \"YES\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String intersection(List interval1, List interval2) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.intersection(Arrays.asList(1, 2), Arrays.asList(2, 3)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-1, 1), Arrays.asList(0, 4)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-3, -1), Arrays.asList(-5, 5)), \"YES\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int l = Math.max(interval1.get(0), interval2.get(0));\n int r = Math.min(interval1.get(1), interval2.get(1));\n int length = r - l;\n if (length <= 0) {\n return \"NO\";\n }\n if (length == 1) {\n return \"NO\";\n }\n if (length == 2) {\n return \"YES\";\n }\n return \"YES\";\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "Intersection"} {"task_id": "Java/128", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prodSigns(Arrays.asList(1, 2, 2, -4)) == -9\n >>> prodSigns(Arrays.asList(0, 1)) == 0\n >>> prodSigns(Arrays.asList()) == None\n */\n public Optional prodSigns(List arr) {\n", "canonical_solution": " if (arr.size() == 0) {\n return Optional.empty();\n }\n if (arr.contains(0)) {\n return Optional.of(0);\n }\n int prod = (int) (-2 * (arr.stream().filter(p -> p < 0).count() % 2) + 1);\n return Optional.of(prod * (arr.stream().map(Math::abs).reduce(Integer::sum)).get());\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.prodSigns(Arrays.asList(1, 2, 2, -4)).get() == -9,\n s.prodSigns(Arrays.asList(0, 1)).get() == 0,\n s.prodSigns(Arrays.asList(1, 1, 1, 2, 3, -1, 1)).get() == -10,\n s.prodSigns(List.of()).isEmpty(),\n s.prodSigns(Arrays.asList(2, 4,1, 2, -1, -1, 9)).get() == 20,\n s.prodSigns(Arrays.asList(-1, 1, -1, 1)).get() == 4,\n s.prodSigns(Arrays.asList(-1, 1, 1, 1)).get() == -4,\n s.prodSigns(Arrays.asList(-1, 1, 1, 0)).get() == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prodSigns(Arrays.asList(1, 2, 2, -4)) == -9\n >>> prodSigns(Arrays.asList(0, 1)) == 0\n >>> prodSigns(Arrays.asList()) == None", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public Optional prodSigns(List arr) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.prodSigns(Arrays.asList(1, 2, 2, -4)).get() == -9,\n s.prodSigns(Arrays.asList(0, 1)).get() == 0,\n s.prodSigns(List.of()).isEmpty()\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (arr.size() == 0) {\n return Optional.empty();\n }\n if (arr.contains(0)) {\n return Optional.of(0);\n }\n int prod = (int) (-2 * (arr.stream().filter(p -> p < 0).count() % 2) + 1 * 2);\n return Optional.of(prod * (arr.stream().map(Math::abs).reduce(Integer::sum)).get());\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "ProdSigns"} -{"task_id": "Java/129", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a grid with N rows and N columns (N >= 2) and a positive integer k,\n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n\n Examples:\n\n Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n Output: [1, 2, 1]\n\n Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n Output: [1]\n */\n public List minPath(List> grid, int k) {\n", "canonical_solution": " int n = grid.size();\n int val = n * n + 1;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (grid.get(i).get(j) == 1) {\n List temp = new ArrayList<>();\n if (i != 0) {\n temp.add(grid.get(i - 1).get(j));\n }\n if (j != 0) {\n temp.add(grid.get(i).get(j - 1));\n }\n if (i != n - 1) {\n temp.add(grid.get(i + 1).get(j));\n }\n if (j != n - 1) {\n temp.add(grid.get(i).get(j + 1));\n }\n val = Collections.min(temp);\n }\n }\n }\n List ans = new ArrayList<>();\n for (int i = 0; i < k; i++) {\n if (i % 2 == 0) {\n ans.add(1);\n } else {\n ans.add(val);\n }\n }\n return ans;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3), Arrays.asList(4, 5, 6), Arrays.asList(7, 8, 9)), 3).equals(Arrays.asList(1, 2, 1)),\n s.minPath(Arrays.asList(Arrays.asList(5, 9, 3), Arrays.asList(4, 1, 6), Arrays.asList(7, 8, 2)), 1).equals(List.of(1)),\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3, 4), Arrays.asList(5, 6, 7, 8), Arrays.asList(9, 10, 11, 12), Arrays.asList(13, 14, 15, 16)), 4).equals(Arrays.asList(1, 2, 1, 2)),\n s.minPath(Arrays.asList(Arrays.asList(6, 4, 13, 10), Arrays.asList(5, 7, 12, 1), Arrays.asList(3, 16, 11, 15), Arrays.asList(8, 14, 9, 2)), 7).equals(Arrays.asList(1, 10, 1, 10, 1, 10, 1)),\n s.minPath(Arrays.asList(Arrays.asList(8, 14, 9, 2), Arrays.asList(6, 4, 13, 15), Arrays.asList(5, 7, 1, 12), Arrays.asList(3, 10, 11, 16)), 5).equals(Arrays.asList(1, 7, 1, 7, 1)),\n s.minPath(Arrays.asList(Arrays.asList(11, 8, 7, 2), Arrays.asList(5, 16, 14, 4), Arrays.asList(9, 3, 15, 6), Arrays.asList(12, 13, 10, 1)), 9).equals(Arrays.asList(1, 6, 1, 6, 1, 6, 1, 6, 1)),\n s.minPath(Arrays.asList(Arrays.asList(12, 13, 10, 1), Arrays.asList(9, 3, 15, 6), Arrays.asList(5, 16, 14, 4), Arrays.asList(11, 8, 7, 2)), 12).equals(Arrays.asList(1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6)),\n s.minPath(Arrays.asList(Arrays.asList(2, 7, 4), Arrays.asList(3, 1, 5), Arrays.asList(6, 8, 9)), 8).equals(Arrays.asList(1, 3, 1, 3, 1, 3, 1, 3)),\n s.minPath(Arrays.asList(Arrays.asList(6, 1, 5), Arrays.asList(3, 8, 9), Arrays.asList(2, 7, 4)), 8).equals(Arrays.asList(1, 5, 1, 5, 1, 5, 1, 5)),\n s.minPath(Arrays.asList(Arrays.asList(1, 2), Arrays.asList(3, 4)), 10).equals(Arrays.asList(1, 2, 1, 2, 1, 2, 1, 2, 1, 2)),\n s.minPath(Arrays.asList(Arrays.asList(1, 3), Arrays.asList(3, 2)), 10).equals(Arrays.asList(1, 3, 1, 3, 1, 3, 1, 3, 1, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a grid with N rows and N columns (N >= 2) and a positive integer k,\n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n\n Examples:\n\n Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n Output: [1, 2, 1]\n\n Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n Output: [1]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List minPath(List> grid, int k) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3), Arrays.asList(4, 5, 6), Arrays.asList(7, 8, 9)), 3).equals(Arrays.asList(1, 2, 1)),\n s.minPath(Arrays.asList(Arrays.asList(5, 9, 3), Arrays.asList(4, 1, 6), Arrays.asList(7, 8, 2)), 1).equals(List.of(1))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int n = grid.size();\n int val = n * 2 + 1;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (grid.get(i).get(j) == 1) {\n List temp = new ArrayList<>();\n if (i != 0) {\n temp.add(grid.get(i - 1).get(j));\n }\n if (j != 0) {\n temp.add(grid.get(i).get(j - 1));\n }\n if (i != n - 1) {\n temp.add(grid.get(i + 1).get(j));\n }\n if (j != n - 1) {\n temp.add(grid.get(i).get(j + 1));\n }\n val = Collections.min(temp);\n }\n }\n }\n List ans = new ArrayList<>();\n for (int i = 0; i < k; i++) {\n if (i % 2 == 0) {\n ans.add(1);\n } else {\n ans.add(val);\n }\n }\n return ans;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "Minpath"} +{"task_id": "Java/129", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a grid with N rows and N columns (N >= 2) and a positive integer k,\n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n\n Examples:\n\n Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n Output: [1, 2, 1]\n\n Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n Output: [1]\n */\n public List minPath(List> grid, int k) {\n", "canonical_solution": " int n = grid.size();\n int val = n * n + 1;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (grid.get(i).get(j) == 1) {\n List temp = new ArrayList<>();\n if (i != 0) {\n temp.add(grid.get(i - 1).get(j));\n }\n if (j != 0) {\n temp.add(grid.get(i).get(j - 1));\n }\n if (i != n - 1) {\n temp.add(grid.get(i + 1).get(j));\n }\n if (j != n - 1) {\n temp.add(grid.get(i).get(j + 1));\n }\n val = Collections.min(temp);\n }\n }\n }\n List ans = new ArrayList<>();\n for (int i = 0; i < k; i++) {\n if (i % 2 == 0) {\n ans.add(1);\n } else {\n ans.add(val);\n }\n }\n return ans;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3), Arrays.asList(4, 5, 6), Arrays.asList(7, 8, 9)), 3).equals(Arrays.asList(1, 2, 1)),\n s.minPath(Arrays.asList(Arrays.asList(5, 9, 3), Arrays.asList(4, 1, 6), Arrays.asList(7, 8, 2)), 1).equals(List.of(1)),\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3, 4), Arrays.asList(5, 6, 7, 8), Arrays.asList(9, 10, 11, 12), Arrays.asList(13, 14, 15, 16)), 4).equals(Arrays.asList(1, 2, 1, 2)),\n s.minPath(Arrays.asList(Arrays.asList(6, 4, 13, 10), Arrays.asList(5, 7, 12, 1), Arrays.asList(3, 16, 11, 15), Arrays.asList(8, 14, 9, 2)), 7).equals(Arrays.asList(1, 10, 1, 10, 1, 10, 1)),\n s.minPath(Arrays.asList(Arrays.asList(8, 14, 9, 2), Arrays.asList(6, 4, 13, 15), Arrays.asList(5, 7, 1, 12), Arrays.asList(3, 10, 11, 16)), 5).equals(Arrays.asList(1, 7, 1, 7, 1)),\n s.minPath(Arrays.asList(Arrays.asList(11, 8, 7, 2), Arrays.asList(5, 16, 14, 4), Arrays.asList(9, 3, 15, 6), Arrays.asList(12, 13, 10, 1)), 9).equals(Arrays.asList(1, 6, 1, 6, 1, 6, 1, 6, 1)),\n s.minPath(Arrays.asList(Arrays.asList(12, 13, 10, 1), Arrays.asList(9, 3, 15, 6), Arrays.asList(5, 16, 14, 4), Arrays.asList(11, 8, 7, 2)), 12).equals(Arrays.asList(1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6)),\n s.minPath(Arrays.asList(Arrays.asList(2, 7, 4), Arrays.asList(3, 1, 5), Arrays.asList(6, 8, 9)), 8).equals(Arrays.asList(1, 3, 1, 3, 1, 3, 1, 3)),\n s.minPath(Arrays.asList(Arrays.asList(6, 1, 5), Arrays.asList(3, 8, 9), Arrays.asList(2, 7, 4)), 8).equals(Arrays.asList(1, 5, 1, 5, 1, 5, 1, 5)),\n s.minPath(Arrays.asList(Arrays.asList(1, 2), Arrays.asList(3, 4)), 10).equals(Arrays.asList(1, 2, 1, 2, 1, 2, 1, 2, 1, 2)),\n s.minPath(Arrays.asList(Arrays.asList(1, 3), Arrays.asList(3, 2)), 10).equals(Arrays.asList(1, 3, 1, 3, 1, 3, 1, 3, 1, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a grid with N rows and N columns (N >= 2) and a positive integer k,\n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n\n Examples:\n\n Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n Output: [1, 2, 1]\n\n Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n Output: [1]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List minPath(List> grid, int k) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3), Arrays.asList(4, 5, 6), Arrays.asList(7, 8, 9)), 3).equals(Arrays.asList(1, 2, 1)),\n s.minPath(Arrays.asList(Arrays.asList(5, 9, 3), Arrays.asList(4, 1, 6), Arrays.asList(7, 8, 2)), 1).equals(List.of(1))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int n = grid.size();\n int val = n * n + 1;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (grid.get(i).get(j) == 1) {\n List temp = new ArrayList<>();\n if (i != 0) {\n temp.add(grid.get(i).get(j));\n }\n if (j != 0) {\n temp.add(grid.get(i).get(j));\n }\n if (i != n - 1) {\n temp.add(grid.get(i).get(j));\n }\n if (j != n - 1) {\n temp.add(grid.get(i).get(j));\n }\n val = Collections.min(temp);\n }\n }\n }\n List ans = new ArrayList<>();\n for (int i = 0; i < k; i++) {\n if (i % 2 == 0) {\n ans.add(1);\n } else {\n ans.add(val);\n }\n }\n return ans;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "Minpath"} {"task_id": "Java/130", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in\n the last couple centuries. However, what people don't know is Tribonacci sequence.\n Tribonacci sequence is defined by the recurrence:\n tri(1) = 3\n tri(n) = 1 + n / 2, if n is even.\n tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.\n For example:\n tri(2) = 1 + (2 / 2) = 2\n tri(4) = 3\n tri(3) = tri(2) + tri(1) + tri(4)\n = 2 + 3 + 3 = 8\n You are given a non-negative integer number n, you have to a return a list of the\n first n + 1 numbers of the Tribonacci sequence.\n Examples:\n tri(3) = [1, 3, 2, 8]\n */\n public List tri(int n) {\n", "canonical_solution": " if (n == 0) {\n return List.of(1);\n }\n List my_tri = new ArrayList<>(Arrays.asList(1, 3));\n for (int i = 2; i <= n; i++) {\n if (i % 2 == 0) {\n my_tri.add(i / 2 + 1);\n } else {\n my_tri.add(my_tri.get(my_tri.size() - 1) + my_tri.get(my_tri.size() - 2) + (i + 3) / 2);\n }\n }\n return my_tri;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.tri(3).equals(Arrays.asList(1, 3, 2, 8)),\n s.tri(4).equals(Arrays.asList(1, 3, 2, 8, 3)),\n s.tri(5).equals(Arrays.asList(1, 3, 2, 8, 3, 15)),\n s.tri(6).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4)),\n s.tri(7).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4, 24)),\n s.tri(8).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4, 24, 5)),\n s.tri(9).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4, 24, 5, 35)),\n s.tri(20).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4, 24, 5, 35, 6, 48, 7, 63, 8, 80, 9, 99, 10, 120, 11)),\n s.tri(0).equals(List.of(1)),\n s.tri(1).equals(Arrays.asList(1, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in\n the last couple centuries. However, what people don't know is Tribonacci sequence.\n Tribonacci sequence is defined by the recurrence:\n tri(1) = 3\n tri(n) = 1 + n / 2, if n is even.\n tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.\n For example:\n tri(2) = 1 + (2 / 2) = 2\n tri(4) = 3\n tri(3) = tri(2) + tri(1) + tri(4)\n = 2 + 3 + 3 = 8\n You are given a non-negative integer number n, you have to a return a list of the\n first n + 1 numbers of the Tribonacci sequence.\n Examples:\n tri(3) = [1, 3, 2, 8]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List tri(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.tri(3).equals(Arrays.asList(1, 3, 2, 8))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (n == 0) {\n return List.of(1);\n }\n List my_tri = new ArrayList<>(Arrays.asList(1, 3));\n for (int i = 2; i <= n; i++) {\n if (i % 2 == 0) {\n my_tri.add(i / 2 + 1);\n } else {\n my_tri.add(my_tri.get(my_tri.size() - 1) + my_tri.get(my_tri.size() - 2) + i + (i + 3) / 2);\n }\n }\n return my_tri;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "Tri"} {"task_id": "Java/131", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n */\n public int digits(int n) {\n", "canonical_solution": " int product = 1, odd_count = 0;\n for (char digit : String.valueOf(n).toCharArray()) {\n int int_digit = digit - '0';\n if (int_digit % 2 == 1) {\n product *= int_digit;\n odd_count += 1;\n }\n }\n if (odd_count == 0) {\n return 0;\n } else {\n return product;\n }\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.digits(5) == 5,\n s.digits(54) == 5,\n s.digits(120) == 1,\n s.digits(5014) == 5,\n s.digits(98765) == 315,\n s.digits(5576543) == 2625\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int digits(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.digits(1) == 1,\n s.digits(4) == 0,\n s.digits(235) == 15\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int product = 1, odd_count = 0;\n for (char digit : String.valueOf(n).toCharArray()) {\n int int_digit = digit - '0';\n if (int_digit % 2 == 1) {\n product *= product*int_digit;\n odd_count += 1;\n }\n }\n if (odd_count == 0) {\n return 0;\n } else {\n return product;\n }\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "Digits"} {"task_id": "Java/132", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function that takes a string as input which contains only square brackets.\n The function should return true if and only if there is a valid subsequence of brackets\n where at least one bracket in the subsequence is nested.\n\n isNested(\"[[]]\") -> true\n isNested(\"[]]]]]]][[[[[]\") -> false\n isNested(\"[][]\") -> false\n isNested(\"[]\") -> false\n isNested(\"[[][]]\") -> true\n isNested(\"[[]][[\") -> true\n */\n public boolean isNested(String string) {\n", "canonical_solution": " List opening_bracket_index = new ArrayList<>(), closing_bracket_index = new ArrayList<>();\n for (int i = 0; i < string.length(); i++) {\n if (string.charAt(i) == '[') {\n opening_bracket_index.add(i);\n } else {\n closing_bracket_index.add(i);\n }\n }\n Collections.reverse(closing_bracket_index);\n int i = 0, l = closing_bracket_index.size();\n for (int idx : opening_bracket_index) {\n if (i < l && idx < closing_bracket_index.get(i)) {\n i += 1;\n }\n }\n return i >= 2;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isNested(\"[[]]\" ),\n !s.isNested(\"[]]]]]]][[[[[]\" ),\n !s.isNested(\"[][]\" ),\n !s.isNested(\"[]\" ),\n s.isNested(\"[[[[]]]]\" ),\n !s.isNested(\"[]]]]]]]]]]\" ),\n s.isNested(\"[][][[]]\" ),\n !s.isNested(\"[[]\" ),\n !s.isNested(\"[]]\" ),\n s.isNested(\"[[]][[\" ),\n s.isNested(\"[[][]]\" ),\n !s.isNested(\"\" ),\n !s.isNested(\"[[[[[[[[\" ),\n !s.isNested(\"]]]]]]]]\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function that takes a string as input which contains only square brackets.\n The function should return true if and only if there is a valid subsequence of brackets\n where at least one bracket in the subsequence is nested.\n\n isNested(\"[[]]\") -> true\n isNested(\"[]]]]]]][[[[[]\") -> false\n isNested(\"[][]\") -> false\n isNested(\"[]\") -> false\n isNested(\"[[][]]\") -> true\n isNested(\"[[]][[\") -> true", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean isNested(String string) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isNested(\"[[]]\" ),\n !s.isNested(\"[]]]]]]][[[[[]\" ),\n !s.isNested(\"[][]\" ),\n !s.isNested(\"[]\" ),\n s.isNested(\"[[]][[\" ),\n s.isNested(\"[[][]]\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List opening_bracket_index = new ArrayList<>(), closing_bracket_index = new ArrayList<>();\n for (int i = 0; i < string.length(); i++) {\n if (string.charAt(i) == '(') {\n opening_bracket_index.add(i);\n } else {\n closing_bracket_index.add(i);\n }\n }\n Collections.reverse(closing_bracket_index);\n int i = 0, l = closing_bracket_index.size();\n for (int idx : opening_bracket_index) {\n if (i < l && idx < closing_bracket_index.get(i)) {\n i += 1;\n }\n }\n return i >= 2;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "IsNested"} @@ -152,10 +152,10 @@ {"task_id": "Java/151", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n\n doubleTheDifference(Arrays.asList(1, 3, 2, 0)) == 1 + 9 + 0 + 0 = 10\n doubleTheDifference(Arrays.asList(-1, -2, 0)) == 0\n doubleTheDifference(Arrays.asList(9, -2)) == 81\n doubleTheDifference(Arrays.asList(0)) == 0\n\n If the input list is empty, return 0.\n */\n public int doubleTheDifference(List lst) {\n", "canonical_solution": " return lst.stream().filter(i -> i instanceof Integer p && p > 0 && p % 2 != 0).map(i -> (Integer) i * (Integer) i).reduce(Integer::sum).orElse(0);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.doubleTheDifference(List.of()) == 0,\n s.doubleTheDifference(Arrays.asList(5, 4)) == 25,\n s.doubleTheDifference(Arrays.asList(0.1, 0.2, 0.3)) == 0,\n s.doubleTheDifference(Arrays.asList(-10, -20, -30)) == 0,\n s.doubleTheDifference(Arrays.asList(-1, -2, 8)) == 0,\n s.doubleTheDifference(Arrays.asList(0.2, 3, 5)) == 34\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n List lst = new ArrayList<>();\n for (int i = -99; i < 100; i += 2) {\n lst.add(i);\n }\n int odd_sum = lst.stream().filter(i -> i instanceof Integer p && p % 2 != 0 && p > 0).map(i -> (Integer) i * (Integer) i).reduce(Integer::sum).orElse(0);\n assert s.doubleTheDifference(lst) == odd_sum;\n }\n}", "text": " Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n\n doubleTheDifference(Arrays.asList(1, 3, 2, 0)) == 1 + 9 + 0 + 0 = 10\n doubleTheDifference(Arrays.asList(-1, -2, 0)) == 0\n doubleTheDifference(Arrays.asList(9, -2)) == 81\n doubleTheDifference(Arrays.asList(0)) == 0\n\n If the input list is empty, return 0.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int doubleTheDifference(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.doubleTheDifference(Arrays.asList(1,3,2,0)) == 10,\n s.doubleTheDifference(Arrays.asList(-1,-2,0)) == 0,\n s.doubleTheDifference(Arrays.asList(9,-2)) == 81,\n s.doubleTheDifference(Arrays.asList(0)) == 0\n );\n }\n}\n", "buggy_solution": " return lst.stream().filter(i -> i instanceof Integer p && p > 0).map(i -> (Integer) i * (Integer) i).reduce(Integer::sum).orElse(0);\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "DoubleTheDifference"} {"task_id": "Java/152", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n I think we all remember that feeling when the result of some long-awaited\n event is finally known. The feelings and thoughts you have at that moment are\n definitely worth noting down and comparing.\n Your task is to determine if a person correctly guessed the results of a number of matches.\n You are given two arrays of scores and guesses of equal length, where each index shows a match.\n Return an array of the same length denoting how far off each guess was. If they have guessed correctly,\n the value is 0, and if not, the value is the absolute difference between the guess and the score.\n\n example:\n\n compare(Arrays.asList(1,2,3,4,5,1),Arrays.asList(1,2,3,4,2,-2)) -> [0,0,0,0,3,3]\n compare(Arrays.asList(0,5,0,0,0,4),Arrays.asList(4,1,1,0,0,-2)) -> [4,4,1,0,0,6]\n */\n public List compare(List game, List guess) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (int i = 0; i < game.size(); i++) {\n result.add(Math.abs(game.get(i) - guess.get(i)));\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.compare(Arrays.asList(1, 2, 3, 4, 5, 1), Arrays.asList(1, 2, 3, 4, 2, -2)).equals(Arrays.asList(0, 0, 0, 0, 3, 3)),\n s.compare(Arrays.asList(0,5,0,0,0,4), Arrays.asList(4,1,1,0,0,-2)).equals(Arrays.asList(4,4,1,0,0,6)),\n s.compare(Arrays.asList(1, 2, 3, 4, 5, 1), Arrays.asList(1, 2, 3, 4, 2, -2)).equals(Arrays.asList(0, 0, 0, 0, 3, 3)),\n s.compare(Arrays.asList(0, 0, 0, 0, 0, 0), Arrays.asList(0, 0, 0, 0, 0, 0)).equals(Arrays.asList(0, 0, 0, 0, 0, 0)),\n s.compare(Arrays.asList(1, 2, 3), Arrays.asList(-1, -2, -3)).equals(Arrays.asList(2, 4, 6)),\n s.compare(Arrays.asList(1, 2, 3, 5), Arrays.asList(-1, 2, 3, 4)).equals(Arrays.asList(2, 0, 0, 1))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " I think we all remember that feeling when the result of some long-awaited\n event is finally known. The feelings and thoughts you have at that moment are\n definitely worth noting down and comparing.\n Your task is to determine if a person correctly guessed the results of a number of matches.\n You are given two arrays of scores and guesses of equal length, where each index shows a match.\n Return an array of the same length denoting how far off each guess was. If they have guessed correctly,\n the value is 0, and if not, the value is the absolute difference between the guess and the score.\n\n example:\n\n compare(Arrays.asList(1,2,3,4,5,1),Arrays.asList(1,2,3,4,2,-2)) -> [0,0,0,0,3,3]\n compare(Arrays.asList(0,5,0,0,0,4),Arrays.asList(4,1,1,0,0,-2)) -> [4,4,1,0,0,6]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List compare(List game, List guess) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.compare(Arrays.asList(1, 2, 3, 4, 5, 1), Arrays.asList(1, 2, 3, 4, 2, -2)).equals(Arrays.asList(0, 0, 0, 0, 3, 3)),\n s.compare(Arrays.asList(0,5,0,0,0,4), Arrays.asList(4,1,1,0,0,-2)).equals(Arrays.asList(4,4,1,0,0,6))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (int i = 0; i < game.size(); i++) {\n result.add(Math.abs(game.get(i) - guess.get(i))+Math.abs(guess.get(i) - game.get(i)));\n }\n return result;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "Compare"} {"task_id": "Java/153", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You will be given the name of a class (a string) and a list of extensions.\n The extensions are to be used to load additional classes to the class. The\n strength of the extension is as follows: Let CAP be the number of the uppercase\n letters in the extension's name, and let SM be the number of lowercase letters\n in the extension's name, the strength is given by the fraction CAP - SM.\n You should find the strongest extension and return a string in this\n format: ClassName.StrongestExtensionName.\n If there are two or more extensions with the same strength, you should\n choose the one that comes first in the list.\n For example, if you are given \"Slices\" as the class and a list of the\n extensions: [\"SErviNGSliCes\", \"Cheese\", \"StuFfed\"] then you should\n return \"Slices.SErviNGSliCes\" since \"SErviNGSliCes\" is the strongest extension\n (its strength is -1).\n Example:\n for StrongestExtension(\"my_class\", [\"AA\", \"Be\", \"CC\"]) == \"my_class.AA\"\n */\n public String StrongestExtension(String class_name, List extensions) {\n", "canonical_solution": " String strong = extensions.get(0);\n int my_val = (int) (strong.chars().filter(Character::isUpperCase).count() - strong.chars().filter(Character::isLowerCase).count());\n for (String s : extensions) {\n int val = (int) (s.chars().filter(Character::isUpperCase).count() - s.chars().filter(Character::isLowerCase).count());\n if (val > my_val) {\n strong = s;\n my_val = val;\n }\n }\n return class_name + \".\" + strong;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.StrongestExtension(\"Watashi\", Arrays.asList(\"tEN\", \"niNE\", \"eIGHt8OKe\")), \"Watashi.eIGHt8OKe\"),\n Objects.equals(s.StrongestExtension(\"Boku123\", Arrays.asList(\"nani\", \"NazeDa\", \"YEs.WeCaNe\", \"32145tggg\")), \"Boku123.YEs.WeCaNe\"),\n Objects.equals(s.StrongestExtension(\"__YESIMHERE\", Arrays.asList(\"t\", \"eMptY\", \"nothing\", \"zeR00\", \"NuLl__\", \"123NoooneB321\")), \"__YESIMHERE.NuLl__\"),\n Objects.equals(s.StrongestExtension(\"K\", Arrays.asList(\"Ta\", \"TAR\", \"t234An\", \"cosSo\")), \"K.TAR\"),\n Objects.equals(s.StrongestExtension(\"__HAHA\", Arrays.asList(\"Tab\", \"123\", \"781345\", \"-_-\")), \"__HAHA.123\"),\n Objects.equals(s.StrongestExtension(\"YameRore\", Arrays.asList(\"HhAas\", \"okIWILL123\", \"WorkOut\", \"Fails\", \"-_-\")), \"YameRore.okIWILL123\"),\n Objects.equals(s.StrongestExtension(\"finNNalLLly\", Arrays.asList(\"Die\", \"NowW\", \"Wow\", \"WoW\")), \"finNNalLLly.WoW\"),\n Objects.equals(s.StrongestExtension(\"_\", Arrays.asList(\"Bb\", \"91245\")), \"_.Bb\"),\n Objects.equals(s.StrongestExtension(\"Sp\", Arrays.asList(\"671235\", \"Bb\")), \"Sp.671235\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You will be given the name of a class (a string) and a list of extensions.\n The extensions are to be used to load additional classes to the class. The\n strength of the extension is as follows: Let CAP be the number of the uppercase\n letters in the extension's name, and let SM be the number of lowercase letters\n in the extension's name, the strength is given by the fraction CAP - SM.\n You should find the strongest extension and return a string in this\n format: ClassName.StrongestExtensionName.\n If there are two or more extensions with the same strength, you should\n choose the one that comes first in the list.\n For example, if you are given \"Slices\" as the class and a list of the\n extensions: [\"SErviNGSliCes\", \"Cheese\", \"StuFfed\"] then you should\n return \"Slices.SErviNGSliCes\" since \"SErviNGSliCes\" is the strongest extension\n (its strength is -1).\n Example:\n for StrongestExtension(\"my_class\", [\"AA\", \"Be\", \"CC\"]) == \"my_class.AA\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String StrongestExtension(String class_name, List extensions) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.StrongestExtension(\"my_class\", Arrays.asList(\"AA\", \"Be\", \"CC\")), \"my_class.AA\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String strong = extensions.get(0);\n int my_val = (int) (strong.chars().filter(Character::isUpperCase).count() - strong.chars().filter(Character::isLowerCase).count());\n for (String s : extensions) {\n int val = (int) (s.chars().filter(Character::isUpperCase).count() - s.chars().filter(Character::isLowerCase).count());\n if (val > my_val) {\n strong = s;\n my_val = val;\n }\n }\n return class_name + strong;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "StrongestExtension"} -{"task_id": "Java/154", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word\n cycpatternCheck(\"abcd\",\"abd\") => false\n cycpatternCheck(\"hello\",\"ell\") => true\n cycpatternCheck(\"whassup\",\"psus\") => false\n cycpatternCheck(\"abab\",\"baa\") => true\n cycpatternCheck(\"efef\",\"eeff\") => false\n cycpatternCheck(\"himenss\",\"simen\") => true\n */\n public boolean cycpatternCheck(String a, String b) {\n", "canonical_solution": " int l = b.length();\n String pat = b + b;\n for (int i = 0; i <= a.length() - l; i++) {\n for (int j = 0; j <= l; j++) {\n if (a.substring(i, i + l).equals(pat.substring(j, j + l))) {\n return true;\n }\n }\n }\n return false;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.cycpatternCheck(\"xyzw\", \"xyw\") == false,\n s.cycpatternCheck(\"yello\", \"ell\") == true,\n s.cycpatternCheck(\"whattup\", \"ptut\") == false,\n s.cycpatternCheck(\"efef\", \"fee\") == true,\n s.cycpatternCheck(\"abab\", \"aabb\") == false,\n s.cycpatternCheck(\"winemtt\", \"tinem\") == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word\n cycpatternCheck(\"abcd\",\"abd\") => false\n cycpatternCheck(\"hello\",\"ell\") => true\n cycpatternCheck(\"whassup\",\"psus\") => false\n cycpatternCheck(\"abab\",\"baa\") => true\n cycpatternCheck(\"efef\",\"eeff\") => false\n cycpatternCheck(\"himenss\",\"simen\") => true", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean cycpatternCheck(String a, String b) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.cycpatternCheck(\"abcd\", \"abd\") == false,\n s.cycpatternCheck(\"hello\", \"ell\") == true,\n s.cycpatternCheck(\"whassup\", \"psus\") == false,\n s.cycpatternCheck(\"abab\", \"baa\") == true,\n s.cycpatternCheck(\"efef\", \"eeff\") == false,\n s.cycpatternCheck(\"himenss\", \"simen\") == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int l = b.length();\n String pat = b + b;\n for (int i = 0; i < a.length() - l; i++) {\n for (int j = 0; j < l; j++) {\n if (a.substring(i, i + l).equals(pat.substring(j, j + l))) {\n return true;\n }\n }\n }\n return false;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "CycpatternCheck"} +{"task_id": "Java/154", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word\n cycpatternCheck(\"abcd\",\"abd\") => false\n cycpatternCheck(\"hello\",\"ell\") => true\n cycpatternCheck(\"whassup\",\"psus\") => false\n cycpatternCheck(\"abab\",\"baa\") => true\n cycpatternCheck(\"efef\",\"eeff\") => false\n cycpatternCheck(\"himenss\",\"simen\") => true\n */\n public boolean cycpatternCheck(String a, String b) {\n", "canonical_solution": " int l = b.length();\n String pat = b + b;\n for (int i = 0; i <= a.length() - l; i++) {\n for (int j = 0; j <= l; j++) {\n if (a.substring(i, i + l).equals(pat.substring(j, j + l))) {\n return true;\n }\n }\n }\n return false;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.cycpatternCheck(\"xyzw\", \"xyw\") == false,\n s.cycpatternCheck(\"yello\", \"ell\") == true,\n s.cycpatternCheck(\"whattup\", \"ptut\") == false,\n s.cycpatternCheck(\"efef\", \"fee\") == true,\n s.cycpatternCheck(\"abab\", \"aabb\") == false,\n s.cycpatternCheck(\"winemtt\", \"tinem\") == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word\n cycpatternCheck(\"abcd\",\"abd\") => false\n cycpatternCheck(\"hello\",\"ell\") => true\n cycpatternCheck(\"whassup\",\"psus\") => false\n cycpatternCheck(\"abab\",\"baa\") => true\n cycpatternCheck(\"efef\",\"eeff\") => false\n cycpatternCheck(\"himenss\",\"simen\") => true", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean cycpatternCheck(String a, String b) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.cycpatternCheck(\"abcd\", \"abd\") == false,\n s.cycpatternCheck(\"hello\", \"ell\") == true,\n s.cycpatternCheck(\"whassup\", \"psus\") == false,\n s.cycpatternCheck(\"abab\", \"baa\") == true,\n s.cycpatternCheck(\"efef\", \"eeff\") == false,\n s.cycpatternCheck(\"himenss\", \"simen\") == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int l = b.length();\n String pat = b + b;\n for (int i = 0; i <= a.length() - l; i++) {\n for (int j = 0; j <= b.length() - l; j++) {\n if (a.substring(i, i + l).equals(pat.substring(j, j + l))) {\n return true;\n }\n }\n }\n return false;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "CycpatternCheck"} {"task_id": "Java/155", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given an integer. return a tuple that has the number of even and odd digits respectively.\n \n Example:\n evenOddCount(-12) ==> (1, 1)\n evenOddCount(123) ==> (1, 2)\n */\n public List evenOddCount(int num) {\n", "canonical_solution": " int even_count = 0, odd_count = 0;\n for (char i : String.valueOf(Math.abs(num)).toCharArray()) {\n if ((i - '0') % 2 == 0) {\n even_count += 1;\n } else {\n odd_count += 1;\n }\n }\n return Arrays.asList(even_count, odd_count);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.evenOddCount(7).equals(Arrays.asList(0, 1)),\n s.evenOddCount(-78).equals(Arrays.asList(1, 1)),\n s.evenOddCount(3452).equals(Arrays.asList(2, 2)),\n s.evenOddCount(346211).equals(Arrays.asList(3, 3)),\n s.evenOddCount(-345821).equals(Arrays.asList(3, 3)),\n s.evenOddCount(-2).equals(Arrays.asList(1, 0)),\n s.evenOddCount(-45347).equals(Arrays.asList(2, 3)),\n s.evenOddCount(0).equals(Arrays.asList(1, 0))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given an integer. return a tuple that has the number of even and odd digits respectively.\n \n Example:\n evenOddCount(-12) ==> (1, 1)\n evenOddCount(123) ==> (1, 2)", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List evenOddCount(int num) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.evenOddCount(-12).equals(Arrays.asList(1, 1)),\n s.evenOddCount(123).equals(Arrays.asList(1, 2))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int even_count = 0, odd_count = 0;\n for (char i : String.valueOf(Math.abs(num)).toCharArray()) {\n if (i % 2 == 0) {\n even_count += 1;\n } else {\n odd_count += 1;\n }\n }\n return Arrays.asList(even_count, odd_count);\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "EvenOddCount"} {"task_id": "Java/156", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> intToMiniRoman(19) == \"xix\"\n >>> intToMiniRoman(152) == \"clii\"\n >>> intToMiniRoman(426) == \"cdxxvi\"\n */\n public String intToMiniRoman(int number) {\n", "canonical_solution": " List num = Arrays.asList(1, 4, 5, 9, 10, 40, 50, 90, 100, 400, 500, 900, 1000);\n List sym = Arrays.asList(\"I\", \"IV\", \"V\", \"IX\", \"X\", \"XL\", \"L\", \"XC\", \"C\", \"CD\", \"D\", \"CM\", \"M\");\n int i = 12;\n String res = \"\";\n while (number > 0) {\n int div = number / num.get(i);\n number %= num.get(i);\n while (div != 0) {\n res += sym.get(i);\n div -= 1;\n }\n i -= 1;\n }\n return res.toLowerCase();\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.intToMiniRoman(19), \"xix\"),\n Objects.equals(s.intToMiniRoman(152), \"clii\"),\n Objects.equals(s.intToMiniRoman(251), \"ccli\"),\n Objects.equals(s.intToMiniRoman(426), \"cdxxvi\"),\n Objects.equals(s.intToMiniRoman(500), \"d\"),\n Objects.equals(s.intToMiniRoman(1), \"i\"),\n Objects.equals(s.intToMiniRoman(4), \"iv\"),\n Objects.equals(s.intToMiniRoman(43), \"xliii\"),\n Objects.equals(s.intToMiniRoman(90), \"xc\"),\n Objects.equals(s.intToMiniRoman(94), \"xciv\"),\n Objects.equals(s.intToMiniRoman(532), \"dxxxii\"),\n Objects.equals(s.intToMiniRoman(900), \"cm\"),\n Objects.equals(s.intToMiniRoman(994), \"cmxciv\"),\n Objects.equals(s.intToMiniRoman(1000), \"m\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> intToMiniRoman(19) == \"xix\"\n >>> intToMiniRoman(152) == \"clii\"\n >>> intToMiniRoman(426) == \"cdxxvi\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String intToMiniRoman(int number) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.intToMiniRoman(19), \"xix\"),\n Objects.equals(s.intToMiniRoman(152), \"clii\"),\n Objects.equals(s.intToMiniRoman(426), \"cdxxvi\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List num = Arrays.asList(1, 4, 5, 9, 10, 40, 50, 90, 100, 400, 500, 900, 1000);\n List sym = Arrays.asList(\"I\", \"IV\", \"V\", \"IX\", \"X\", \"XL\", \"L\", \"XC\", \"C\", \"CD\", \"D\", \"CM\", \"M\");\n int i = 12;\n String res = \"\";\n while (number > 0) {\n int div = number / num.get(i);\n while (div != 0) {\n res += sym.get(i);\n div -= 1;\n }\n i -= 1;\n }\n return res.toLowerCase();\n }\n}", "bug_type": "missing logic", "failure_symptoms": "infinite loop", "entry_point": "IntToMiniRoman"} -{"task_id": "Java/157", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given the lengths of the three sides of a triangle. Return true if the three\n sides form a right-angled triangle, false otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or\n 90 degree.\n Example:\n rightAngleTriangle(3, 4, 5) == true\n rightAngleTriangle(1, 2, 3) == false\n */\n public boolean rightAngleTriangle(int a, int b, int c) {\n", "canonical_solution": " return a * a == b * b + c * c || b * b == a * a + c * c || c * c == a * a + b * b;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rightAngleTriangle(3, 4, 5) == true,\n s.rightAngleTriangle(1, 2, 3) == false,\n s.rightAngleTriangle(10, 6, 8) == true,\n s.rightAngleTriangle(2, 2, 2) == false,\n s.rightAngleTriangle(7, 24, 25) == true,\n s.rightAngleTriangle(10, 5, 7) == false,\n s.rightAngleTriangle(5, 12, 13) == true,\n s.rightAngleTriangle(15, 8, 17) == true,\n s.rightAngleTriangle(48, 55, 73) == true,\n s.rightAngleTriangle(1, 1, 1) == false,\n s.rightAngleTriangle(2, 2, 10) == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given the lengths of the three sides of a triangle. Return true if the three\n sides form a right-angled triangle, false otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or\n 90 degree.\n Example:\n rightAngleTriangle(3, 4, 5) == true\n rightAngleTriangle(1, 2, 3) == false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean rightAngleTriangle(int a, int b, int c) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rightAngleTriangle(3, 4, 5) == true,\n s.rightAngleTriangle(1, 2, 3) == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " return a * a == b * b + c * c || c * c == a * a + b * b;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "RightAngleTriangle"} +{"task_id": "Java/157", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given the lengths of the three sides of a triangle. Return true if the three\n sides form a right-angled triangle, false otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or\n 90 degree.\n Example:\n rightAngleTriangle(3, 4, 5) == true\n rightAngleTriangle(1, 2, 3) == false\n */\n public boolean rightAngleTriangle(int a, int b, int c) {\n", "canonical_solution": " return a * a == b * b + c * c || b * b == a * a + c * c || c * c == a * a + b * b;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rightAngleTriangle(3, 4, 5) == true,\n s.rightAngleTriangle(1, 2, 3) == false,\n s.rightAngleTriangle(10, 6, 8) == true,\n s.rightAngleTriangle(2, 2, 2) == false,\n s.rightAngleTriangle(7, 24, 25) == true,\n s.rightAngleTriangle(10, 5, 7) == false,\n s.rightAngleTriangle(5, 12, 13) == true,\n s.rightAngleTriangle(15, 8, 17) == true,\n s.rightAngleTriangle(48, 55, 73) == true,\n s.rightAngleTriangle(1, 1, 1) == false,\n s.rightAngleTriangle(2, 2, 10) == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given the lengths of the three sides of a triangle. Return true if the three\n sides form a right-angled triangle, false otherwise.\n A right-angled triangle is a triangle in which one angle is right angle or\n 90 degree.\n Example:\n rightAngleTriangle(3, 4, 5) == true\n rightAngleTriangle(1, 2, 3) == false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean rightAngleTriangle(int a, int b, int c) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rightAngleTriangle(3, 4, 5) == true,\n s.rightAngleTriangle(1, 2, 3) == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " return c * c == a * a + b * b;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "RightAngleTriangle"} {"task_id": "Java/158", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n findMax([\"name\", \"of\", \"string\"]) == \"string\"\n findMax([\"name\", \"enam\", \"game\"]) == \"enam\"\n findMax([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"\"aaaaaaa\"\n */\n public String findMax(List words) {\n", "canonical_solution": " List words_sort = new ArrayList<>(words);\n words_sort.sort(new Comparator() {\n @Override\n public int compare(String o1, String o2) {\n Set s1 = new HashSet<>();\n for (char ch : o1.toCharArray()) {\n s1.add(ch);\n }\n Set s2 = new HashSet<>();\n for (char ch : o2.toCharArray()) {\n s2.add(ch);\n }\n if (s1.size() > s2.size()) {\n return 1;\n } else if (s1.size() < s2.size()) {\n return -1;\n } else {\n return -o1.compareTo(o2);\n }\n }\n });\n return words_sort.get(words_sort.size() - 1);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.findMax(new ArrayList<>(Arrays.asList(\"name\", \"of\", \"string\"))).equals(\"string\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"name\", \"enam\", \"game\"))).equals(\"enam\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"aaaaaaa\", \"bb\", \"cc\"))).equals(\"aaaaaaa\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"abc\", \"cba\"))).equals(\"abc\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"play\", \"this\", \"game\", \"of\", \"footbott\"))).equals(\"footbott\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"we\", \"are\", \"gonna\", \"rock\"))).equals(\"gonna\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"we\", \"are\", \"a\", \"mad\", \"nation\"))).equals(\"nation\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"this\", \"is\", \"a\", \"prrk\"))).equals(\"this\"),\n s.findMax(new ArrayList<>(List.of(\"b\"))).equals(\"b\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"play\", \"play\", \"play\"))).equals(\"play\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function that accepts a list of strings.\n The list contains different words. Return the word with maximum number\n of unique characters. If multiple strings have maximum number of unique\n characters, return the one which comes first in lexicographical order.\n\n findMax([\"name\", \"of\", \"string\"]) == \"string\"\n findMax([\"name\", \"enam\", \"game\"]) == \"enam\"\n findMax([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"\"aaaaaaa\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String findMax(List words) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.findMax(new ArrayList<>(Arrays.asList(\"name\", \"of\", \"string\"))).equals(\"string\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"name\", \"enam\", \"game\"))).equals(\"enam\"),\n s.findMax(new ArrayList<>(Arrays.asList(\"aaaaaaa\", \"bb\", \"cc\"))).equals(\"aaaaaaa\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List words_sort = new ArrayList<>(words);\n words_sort.sort(new Comparator() {\n @Override\n public int compare(String o1, String o2) {\n Set s1 = new HashSet<>();\n for (char ch : o1.toCharArray()) {\n s1.add(ch);\n }\n Set s2 = new HashSet<>();\n for (char ch : o2.toCharArray()) {\n s2.add(ch);\n }\n if (s1.size() > s2.size()) {\n return 1;\n } else {\n return -o1.compareTo(o2);\n }\n }\n });\n return words_sort.get(words_sort.size() - 1);\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "FindMax"} {"task_id": "Java/159", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n\n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n\n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots thet exist in stock\n\n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n */\n public List eat(int number, int need, int remaining) {\n", "canonical_solution": " if (need <= remaining) {\n return Arrays.asList(number + need, remaining - need);\n } else {\n return Arrays.asList(number + remaining, 0);\n }\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.eat(5, 6, 10).equals(Arrays.asList(11, 4)),\n s.eat(4, 8, 9).equals(Arrays.asList(12, 1)),\n s.eat(1, 10, 10).equals(Arrays.asList(11, 0)),\n s.eat(2, 11, 5).equals(Arrays.asList(7, 0)),\n s.eat(4, 5, 7).equals(Arrays.asList(9, 2)),\n s.eat(4, 5, 1).equals(Arrays.asList(5, 0))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You're a hungry rabbit, and you already have eaten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an array of [ total number of eaten carrots after your meals,\n the number of carrots left after your meals ]\n if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n\n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [12, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n\n Variables:\n @number : integer\n the number of carrots that you have eaten.\n @need : integer\n the number of carrots that you need to eat.\n @remaining : integer\n the number of remaining carrots thet exist in stock\n\n Constrain:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List eat(int number, int need, int remaining) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.eat(5, 6, 10).equals(Arrays.asList(11, 4)),\n s.eat(4, 8, 9).equals(Arrays.asList(12, 1)),\n s.eat(1, 10, 10).equals(Arrays.asList(11, 0)),\n s.eat(2, 11, 5).equals(Arrays.asList(7, 0))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (need <= remaining) {\n return Arrays.asList(number + need, number + remaining - need);\n } else {\n return Arrays.asList(number + need + remaining, 0);\n }\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "Eat"} {"task_id": "Java/160", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given two lists operator, and operand. The first list has basic algebra operations, and\n the second list is a list of integers. Use the two given lists to build the algebric\n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + )\n Subtraction ( - )\n Multiplication ( * )\n Floor division ( / )\n Exponentiation ( ** )\n\n Example:\n operator[\"+\", \"*\", \"-\"]\n array = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.\n */\n public int doAlgebra(List operator, List operand) {\n", "canonical_solution": " List ops = new ArrayList<>(operator);\n List nums = new ArrayList<>(operand);\n for (int i = ops.size() - 1; i >= 0; i--) {\n if (ops.get(i).equals(\"**\")) {\n nums.set(i, (int) Math.round(Math.pow(nums.get(i), nums.get(i + 1))));\n nums.remove(i + 1);\n ops.remove(i);\n }\n }\n for (int i = 0; i < ops.size(); i++) {\n if (ops.get(i).equals(\"*\")) {\n nums.set(i, nums.get(i) * nums.get(i + 1));\n nums.remove(i + 1);\n ops.remove(i);\n i--;\n } else if (ops.get(i).equals(\"/\")) {\n nums.set(i, nums.get(i) / nums.get(i + 1));\n nums.remove(i + 1);\n ops.remove(i);\n i--;\n }\n }\n for (int i = 0; i < ops.size(); i++) {\n if (ops.get(i).equals(\"+\")) {\n nums.set(i, nums.get(i) + nums.get(i + 1));\n nums.remove(i + 1);\n ops.remove(i);\n i--;\n } else if (ops.get(i).equals(\"-\")) {\n nums.set(i, nums.get(i) - nums.get(i + 1));\n nums.remove(i + 1);\n ops.remove(i);\n i--;\n }\n }\n return nums.get(0);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.doAlgebra(new ArrayList<>(Arrays.asList(\"**\", \"*\", \"+\")), new ArrayList<>(Arrays.asList(2, 3, 4, 5))) == 37,\n s.doAlgebra(new ArrayList<>(Arrays.asList(\"+\", \"*\", \"-\")), new ArrayList<>(Arrays.asList(2, 3, 4, 5))) == 9,\n s.doAlgebra(new ArrayList<>(Arrays.asList(\"/\", \"*\")), new ArrayList<>(Arrays.asList(7, 3, 4))) == 8,\n s.doAlgebra(new ArrayList<>(Arrays.asList(\"+\", \"**\", \"**\")), new ArrayList<>(Arrays.asList(7, 5, 3, 2))) == 1953132\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given two lists operator, and operand. The first list has basic algebra operations, and\n the second list is a list of integers. Use the two given lists to build the algebric\n expression and return the evaluation of this expression.\n\n The basic algebra operations:\n Addition ( + )\n Subtraction ( - )\n Multiplication ( * )\n Floor division ( / )\n Exponentiation ( ** )\n\n Example:\n operator[\"+\", \"*\", \"-\"]\n array = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The length of operator list is equal to the length of operand list minus one.\n Operand is a list of of non-negative integers.\n Operator list has at least one operator, and operand list has at least two operands.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int doAlgebra(List operator, List operand) {\n", "example_test": "", "buggy_solution": " List ops = new ArrayList<>(operator);\n List nums = new ArrayList<>(operand);\n for (int i = ops.size() - 1; i >= 0; i--) {\n if (ops.get(i).equals(\"**\")) {\n nums.set(i, (int) Math.round(Math.pow(nums.get(i + 1), nums.get(i + 1))));\n nums.remove(i + 1);\n ops.remove(i);\n }\n }\n for (int i = 0; i < ops.size(); i++) {\n if (ops.get(i).equals(\"*\")) {\n nums.set(i, nums.get(i) * nums.get(i + 1));\n nums.remove(i + 1);\n ops.remove(i);\n i--;\n } else if (ops.get(i).equals(\"/\")) {\n nums.set(i, nums.get(i) / nums.get(i + 1));\n nums.remove(i + 1);\n ops.remove(i);\n i--;\n }\n }\n for (int i = 0; i < ops.size(); i++) {\n if (ops.get(i).equals(\"+\")) {\n nums.set(i, nums.get(i) + nums.get(i + 1));\n nums.remove(i + 1);\n ops.remove(i);\n i--;\n } else if (ops.get(i).equals(\"-\")) {\n nums.set(i, nums.get(i) - nums.get(i + 1));\n nums.remove(i + 1);\n ops.remove(i);\n i--;\n }\n }\n return nums.get(0);\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "DoAlgebra"}