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Fix JS 113

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  1. data/js/data/humanevalbugs.jsonl +1 -1
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@@ -110,7 +110,7 @@
110
  {"task_id": "JavaScript/109", "prompt": "/*We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return true else return false.\n If the given array is empty then return true.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n moveOneBall([3, 4, 5, 1, 2])==>true\n Explanation: By performin 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n moveOneBall([3, 5, 4, 1, 2])==>false\n Explanation:It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \n */\nconst moveOneBall = (arr) => {\n", "canonical_solution": " if (arr.length == 0) { return true }\n let k = 0\n let len = arr.length\n for (let i = 0; i < len; i++) {\n let t = 1;\n for (let j = 1; j < len; j++) {\n if (arr[j] < arr[j - 1]) {\n t = 0;\n break;\n }\n }\n if (t == 1) {\n k = 1;\n break;\n }\n arr.push(arr[0]);\n arr.shift()\n }\n if (k == 1) { return true }\n return false\n}\n\n", "test": "const testMoveOneBall = () => {\n console.assert(moveOneBall([3, 4, 5, 1, 2]) === true)\n console.assert(moveOneBall([3, 5, 10, 1, 2]) === true)\n console.assert(moveOneBall([4, 3, 1, 2]) === false)\n console.assert(moveOneBall([3, 5, 4, 1, 2]) === false)\n console.assert(moveOneBall([]) === true)\n}\n\ntestMoveOneBall()\n", "declaration": "\nconst moveOneBall = (arr) => {\n", "example_test": "const testMoveOneBall = () => {\n console.assert(moveOneBall([3, 4, 5, 1, 2]) === true)\n console.assert(moveOneBall([3, 5, 4, 1, 2]) === false)\n}\ntestMoveOneBall()\n", "buggy_solution": " if (arr.length == 0) { return true }\n let k = 0\n let len = arr.length\n for (let i = 0; i < len; i++) {\n let t = 1;\n for (let j = 1; j < len; j++) {\n if (arr[j] < arr[j - 1]) {\n t = 0;\n break;\n }\n }\n if (t == 1) {\n k = 1;\n break;\n }\n arr.push(arr[j]);\n arr.shift()\n }\n if (k == 1) { return true }\n return false\n}\n\n", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "MoveOneBall"}
111
  {"task_id": "JavaScript/110", "prompt": "/*In this problem, you will implement a function that takes two lists of numbers,\n and determines whether it is possible to perform an exchange of elements\n between them to make lst1 a list of only even numbers.\n There is no limit on the number of exchanged elements between lst1 and lst2.\n If it is possible to exchange elements between the lst1 and lst2 to make\n all the elements of lst1 to be even, return \"YES\".\n Otherwise, return \"NO\".\n For example:\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n It is assumed that the input lists will be non-empty.\n */\nconst exchange = (lst1, lst2) => {\n", "canonical_solution": " let k = lst1.length\n let t = 0\n for (let i = 0; i < lst1.length; i++) {\n if (lst1[i] % 2 == 0) { t++ }\n }\n for (let i = 0; i < lst2.length; i++) {\n if (lst2[i] % 2 == 0) { t++ }\n }\n if (t >= k) { return 'YES' }\n return 'NO'\n}\n\n", "test": "const testExchange = () => {\n console.assert(exchange([1, 2, 3, 4], [1, 2, 3, 4]) === 'YES')\n console.assert(exchange([1, 2, 3, 4], [1, 5, 3, 4]) === 'NO')\n console.assert(exchange([1, 2, 3, 4], [2, 1, 4, 3]) === 'YES')\n console.assert(exchange([5, 7, 3], [2, 6, 4]) === 'YES')\n console.assert(exchange([5, 7, 3], [2, 6, 3]) === 'NO')\n console.assert(exchange([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) === 'NO')\n console.assert(exchange([100, 200], [200, 200]) === 'YES')\n}\n\ntestExchange()\n", "declaration": "\nconst exchange = (lst1, lst2) => {\n", "example_test": "const testExchange = () => {\n console.assert(exchange([1, 2, 3, 4], [1, 2, 3, 4]) === 'YES')\n console.assert(exchange([1, 2, 3, 4], [1, 5, 3, 4]) === 'NO')\n}\ntestExchange()\n", "buggy_solution": " let k = lst1.length\n let t = 0\n for (let i = 0; i < lst1.length; i++) {\n if (lst1[i] % 2 == 0) { t++ }\n }\n for (let i = 0; i < lst2.length; i++) {\n if (lst2[i] % 2 == 0) { t++ }\n }\n if (k >= t) { return 'YES' }\n return 'NO'\n}\n\n", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "Exchange"}
112
  {"task_id": "JavaScript/111", "prompt": "/*Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n\n */\nconst histogram = (test) => {\n", "canonical_solution": " let d = {}\n let t = test.split(/\\s/)\n if (test == '') { t = [] }\n for (m in t) {\n if (t[m] in d) {\n d[t[m]]++\n }\n else {\n d[t[m]] = 1\n }\n }\n s = Object.keys(d).sort(function (a, b) { return - d[a] + d[b]; });\n if (s.length == 0) { return {} }\n let g = d[s[0]]\n let l = {}\n for (let ss=0; ss<s.length; ss++) {\n if (d[s[ss]] == g) {\n l[s[ss]] = d[s[ss]]\n }\n }\n return l\n}\n\n", "test": "const testHistogram = () => {\n console.assert(\n JSON.stringify(histogram('a b b a')) === JSON.stringify({ a: 2, b: 2 })\n )\n console.assert(\n JSON.stringify(histogram('a b c a b')) === JSON.stringify({ a: 2, b: 2 })\n )\n console.assert(\n JSON.stringify(histogram('a b c d g')) ===\n JSON.stringify({ a: 1, b: 1, c: 1, d: 1, g: 1 })\n )\n console.assert(\n JSON.stringify(histogram('r t g')) === JSON.stringify({ r: 1, t: 1, g: 1 })\n )\n console.assert(\n JSON.stringify(histogram('b b b b a')) === JSON.stringify({ b: 4 })\n )\n console.assert(\n JSON.stringify(histogram('r t g')) === JSON.stringify({ r: 1, t: 1, g: 1 })\n )\n console.assert(JSON.stringify(histogram('')) === JSON.stringify({}))\n console.assert(JSON.stringify(histogram('a')) === JSON.stringify({ a: 1 }))\n}\n\ntestHistogram()\n", "declaration": "\nconst histogram = (test) => {\n", "example_test": "const testHistogram = () => {\n console.assert(\n JSON.stringify(histogram('a b b a')) === JSON.stringify({ a: 2, b: 2 })\n )\n console.assert(\n JSON.stringify(histogram('a b c a b')) === JSON.stringify({ a: 2, b: 2 })\n )\n console.assert(\n JSON.stringify(histogram('a b c d g')) ===\n JSON.stringify({ a: 1, b: 1, c: 1, d: 1, g: 1 })\n )\n console.assert(\n JSON.stringify(histogram('a b c')) === JSON.stringify({ a: 1, b: 1, c: 1 })\n )\n console.assert(\n JSON.stringify(histogram('b b b b a')) === JSON.stringify({ b: 4 })\n )\n console.assert(JSON.stringify(histogram('')) === JSON.stringify({}))\n}\ntestHistogram()\n", "buggy_solution": " let d = {}\n let t = test.split(/\\s/)\n if (test == '') { t = [] }\n for (m in t) {\n if (t[m] in d) {\n d[t[m]]++\n }\n else {\n d[t[m]] = 1\n }\n }\n s = Object.keys(d).sort(function (a, b) { return - d[a] + d[b]; });\n if (s.length == 0) { return {} }\n let g = d[s[0]]\n let l = {}\n for (let ss=1; ss<s.length; ss++) {\n if (d[s[ss]] == g) {\n l[s[ss]] = d[s[ss]]\n }\n }\n return l\n}\n\n", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "Histogram"}
113
- {"task_id": "JavaScript/112", "prompt": "/*Task\n We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and true/false for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',false)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',false)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',true)\n */\nconst reverseDelete = (s, c) => {\n", "canonical_solution": " let t = ''\n for (let i = 0; i < s.length; i++) {\n let y = 1\n for (let j = 0; j < c.length; j++) {\n if (s[i] == c[j]) {\n y = 0\n }\n }\n if (y == 1) {\n t += s[i]\n }\n }\n let z = 1\n for (let i = 0; i < t.length; i++) {\n if (t[i] != t[t.length - i - 1]) {\n z = 0\n }\n }\n if (z == 0) {\n return (z, false)\n }\n return (z, true)\n}\n\n", "test": "const testReverseDelete = () => {\n console.assert(JSON.stringify(reverseDelete('abcde', 'ae')) ===\n JSON.stringify(['bcd', false]))\n console.assert(JSON.stringify(reverseDelete('abcdef', 'b')) ===\n JSON.stringify(['acdef', false]))\n console.assert(JSON.stringify(reverseDelete('abcdedcba', 'ab')) ===\n JSON.stringify(['cdedc', true]))\n console.assert(JSON.stringify(reverseDelete('dwik', 'w')) ===\n JSON.stringify(['dik', false]))\n console.assert(JSON.stringify(reverseDelete('a', 'a')) ===\n JSON.stringify(['', true]))\n console.assert(JSON.stringify(reverseDelete('abcdedcba', '')) ===\n JSON.stringify(['abcdedcba', true]))\n console.assert(JSON.stringify(reverseDelete('abcdedcba', 'v')) ===\n JSON.stringify(['abcdedcba', true]))\n console.assert(JSON.stringify(reverseDelete('vabba', 'v')) ===\n JSON.stringify(['abba', true]))\n console.assert(JSON.stringify(reverseDelete('mamma', 'mia')) ===\n JSON.stringify(['', true]))\n}\n\ntestReverseDelete()\n", "declaration": "\nconst reverseDelete = (s, c) => {\n", "example_test": "const testReverseDelete = () => {\n console.assert(JSON.stringify(reverseDelete('abcde', 'ae'))) ===\n JSON.stringify(['bcd', false])\n console.assert(JSON.stringify(reverseDelete('abcdef', 'b'))) ===\n JSON.stringify(['acdef', false])\n console.assert(JSON.stringify(reverseDelete('abcdedcba', 'ab'))) ===\n JSON.stringify(['cdedc', true])\n}\ntestReverseDelete()\n", "buggy_solution": " let t = ''\n for (let i = 0; i < s.length; i++) {\n let y = 1\n for (let j = 0; j < c.length; j++) {\n if (s[i] != c[j]) {\n y = 0\n }\n }\n if (y != 1) {\n t += s[i]\n }\n }\n let z = 1\n for (let i = 0; i < t.length; i++) {\n if (t[i] == t[t.length - i - 1]) {\n z = 0\n }\n }\n if (z == 0) {\n return (z, true)\n }\n return (z, false)\n}\n\n", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "ReverseDelete"}
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  {"task_id": "JavaScript/113", "prompt": "/*Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> oddCount(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> oddCount(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n */\nconst oddCount = (lst) => {\n", "canonical_solution": " let d = []\n for (let i = 0; i < lst.length; i++) {\n let p = 0;\n let h = lst[i].length\n for (let j = 0; j < h; j++) {\n if (lst[i][j].charCodeAt() % 2 == 1) { p++ }\n }\n p = p.toString()\n d.push('the number of odd elements ' + p + 'n the str' + p + 'ng ' + p + ' of the ' + p + 'nput.')\n }\n return d\n}\n\n", "test": "const testOddCount = () => {\n console.assert(\n JSON.stringify(oddCount(['1234567'])) ===\n JSON.stringify([\n 'the number of odd elements 4n the str4ng 4 of the 4nput.',\n ])\n )\n console.assert(JSON.stringify(\n oddCount(['3', '11111111'])) ===\n JSON.stringify([\n 'the number of odd elements 1n the str1ng 1 of the 1nput.',\n 'the number of odd elements 8n the str8ng 8 of the 8nput.',\n ])\n )\n console.assert(\n JSON.stringify(oddCount(['271', '137', '314'])) ===\n JSON.stringify([\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n ])\n )\n}\n\ntestOddCount()\n", "declaration": "\nconst oddCount = (lst) => {\n", "example_test": "const testOddCount = () => {\n console.assert(\n JSON.stringify(oddCount(['1234567'])) ===\n JSON.stringify([\n 'the number of odd elements 4n the str4ng 4 of the 4nput.',\n ])\n )\n console.assert(JSON.stringify(\n oddCount(['3', '11111111'])) ===\n JSON.stringify([\n 'the number of odd elements 1n the str1ng 1 of the 1nput.',\n 'the number of odd elements 8n the str8ng 8 of the 8nput.',\n ])\n )\n}\ntestOddCount()\n", "buggy_solution": " let d = []\n for (let i = 0; i < lst.length; i++) {\n let p = 0;\n let h = lst[i].length\n for (let j = 0; j < h; j++) {\n if (lst[i][j].charCodeAt() % 2 == 1) { p++ }\n }\n p = p.toString()\n d.push('the number of odd elements ' + p + 'n the str' + p + 'ng ' + p + ' of ' p + ' the ' + p + 'nput.')\n }\n return d\n}\n\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "OddCount"}
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  {"task_id": "JavaScript/114", "prompt": "/*\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n */\nconst minSubArraySum = (nums) => {\n", "canonical_solution": " let min = nums[0]\n for (let i = 0; i < nums.length; i++) {\n for (let j = i + 1; j <= nums.length; j++) {\n let s = 0;\n for (let k = i; k < j; k++) {\n s += nums[k]\n }\n if (s < min) { min = s }\n }\n }\n return min\n}\n\n", "test": "const testMinSubArraySum = () => {\n console.assert(minSubArraySum([2, 3, 4, 1, 2, 4]) === 1)\n console.assert(minSubArraySum([-1, -2, -3]) === -6)\n console.assert(minSubArraySum([-1, -2, -3, 2, -10]) === -14)\n console.assert(minSubArraySum([-9999999999999999]) === -9999999999999999)\n console.assert(minSubArraySum([0, 10, 20, 1000000]) === 0)\n console.assert(minSubArraySum([-1, -2, -3, 10, -5]) === -6)\n console.assert(minSubArraySum([100, -1, -2, -3, 10, -5]) === -6)\n console.assert(minSubArraySum([10, 11, 13, 8, 3, 4]) === 3)\n console.assert(minSubArraySum([100, -33, 32, -1, 0, -2]) === -33)\n console.assert(minSubArraySum([-10]) === -10)\n console.assert(minSubArraySum([7]) === 7)\n console.assert(minSubArraySum([1, -1]) === -1)\n}\n\ntestMinSubArraySum()\n", "declaration": "\nconst minSubArraySum = (nums) => {\n", "example_test": "const testMinSubArraySum = () => {\n console.assert(minSubArraySum([2, 3, 4, 1, 2, 4]) === 1)\n console.assert(minSubArraySum([-1, -2, -3]) === -6)\n}\ntestMinSubArraySum()\n", "buggy_solution": " let min = Math.min(nums)\n for (let i = 0; i < nums.length; i++) {\n for (let j = i + 1; j <= nums.length; j++) {\n let s = 0;\n for (let k = i; k < j; k++) {\n s += nums[k]\n }\n if (s < min) { min = s }\n }\n }\n return min\n}\n\n", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "Minsubarraysum"}
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  {"task_id": "JavaScript/115", "prompt": "/*\n You are given a rectangular grid of wells. Each row represents a single well,\n and each 1 in a row represents a single unit of water.\n Each well has a corresponding bucket that can be used to extract water from it, \n and all buckets have the same capacity.\n Your task is to use the buckets to empty the wells.\n Output the number of times you need to lower the buckets.\n\n Example 1:\n Input: \n grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n bucket_capacity : 1\n Output: 6\n\n Example 2:\n Input: \n grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n bucket_capacity : 2\n Output: 5\n \n Example 3:\n Input: \n grid : [[0,0,0], [0,0,0]]\n bucket_capacity : 5\n Output: 0\n\n Constraints:\n * all wells have the same length\n * 1 <= grid.length <= 10^2\n * 1 <= grid[:,1].length <= 10^2\n * grid[i][j] -> 0 | 1\n * 1 <= capacity <= 10\n */\nconst maxFill = (grid, capacity) => {\n", "canonical_solution": " let p = 0\n for (let i = 0; i < grid.length; i++) {\n let m = 0\n for (let j = 0; j < grid[i].length; j++) {\n if (grid[i][j] == 1) { m++ }\n }\n while (m > 0) {\n m -= capacity;\n p++;\n }\n }\n return p\n}\n\n", "test": "const testMaxFill = () => {\n console.assert(\n maxFill(\n [\n [0, 0, 1, 0],\n [0, 1, 0, 0],\n [1, 1, 1, 1],\n ],\n 1\n ) === 6\n )\n console.assert(\n maxFill(\n [\n [0, 0, 1, 1],\n [0, 0, 0, 0],\n [1, 1, 1, 1],\n [0, 1, 1, 1],\n ],\n 2\n ) === 5\n )\n console.assert(\n maxFill(\n [\n [0, 0, 0],\n [0, 0, 0],\n ],\n 5\n ) === 0\n )\n console.assert(\n maxFill(\n [\n [1, 1, 1, 1],\n [1, 1, 1, 1],\n ],\n 2\n ) === 4\n )\n console.assert(\n maxFill(\n [\n [1, 1, 1, 1],\n [1, 1, 1, 1],\n ],\n 9\n ) === 2\n )\n}\n\ntestMaxFill()\n", "declaration": "\nconst maxFill = (grid, capacity) => {\n", "example_test": "const testMaxFill = () => {\n console.assert(\n maxFill(\n [\n [0, 0, 1, 0],\n [0, 1, 0, 0],\n [1, 1, 1, 1],\n ],\n 1\n ) === 6\n )\n console.assert(\n maxFill(\n [\n [0, 0, 1, 1],\n [0, 0, 0, 0],\n [1, 1, 1, 1],\n [0, 1, 1, 1],\n ],\n 2\n ) === 5\n )\n console.assert(\n maxFill(\n [\n [0, 0, 0],\n [0, 0, 0],\n ],\n 5\n ) === 0\n )\n}\ntestMaxFill()\n", "buggy_solution": " let p = 0\n for (let i = 0; i < grid.length; i++) {\n let m = 0\n for (let j = 1; j < grid[i].length; j++) {\n if (grid[i][j] == 1) { m++ }\n }\n while (m > 0) {\n m -= capacity;\n p++;\n }\n }\n return p\n}\n\n", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "MaxFill"}
 
110
  {"task_id": "JavaScript/109", "prompt": "/*We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The\n numbers in the array will be randomly ordered. Your task is to determine if\n it is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to perform right shift operation any number of times.\n \n One right shift operation means shifting all elements of the array by one\n position in the right direction. The last element of the array will be moved to\n the starting position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return true else return false.\n If the given array is empty then return true.\n\n Note: The given list is guaranteed to have unique elements.\n\n For Example:\n \n moveOneBall([3, 4, 5, 1, 2])==>true\n Explanation: By performin 2 right shift operations, non-decreasing order can\n be achieved for the given array.\n moveOneBall([3, 5, 4, 1, 2])==>false\n Explanation:It is not possible to get non-decreasing order for the given\n array by performing any number of right shift operations.\n \n */\nconst moveOneBall = (arr) => {\n", "canonical_solution": " if (arr.length == 0) { return true }\n let k = 0\n let len = arr.length\n for (let i = 0; i < len; i++) {\n let t = 1;\n for (let j = 1; j < len; j++) {\n if (arr[j] < arr[j - 1]) {\n t = 0;\n break;\n }\n }\n if (t == 1) {\n k = 1;\n break;\n }\n arr.push(arr[0]);\n arr.shift()\n }\n if (k == 1) { return true }\n return false\n}\n\n", "test": "const testMoveOneBall = () => {\n console.assert(moveOneBall([3, 4, 5, 1, 2]) === true)\n console.assert(moveOneBall([3, 5, 10, 1, 2]) === true)\n console.assert(moveOneBall([4, 3, 1, 2]) === false)\n console.assert(moveOneBall([3, 5, 4, 1, 2]) === false)\n console.assert(moveOneBall([]) === true)\n}\n\ntestMoveOneBall()\n", "declaration": "\nconst moveOneBall = (arr) => {\n", "example_test": "const testMoveOneBall = () => {\n console.assert(moveOneBall([3, 4, 5, 1, 2]) === true)\n console.assert(moveOneBall([3, 5, 4, 1, 2]) === false)\n}\ntestMoveOneBall()\n", "buggy_solution": " if (arr.length == 0) { return true }\n let k = 0\n let len = arr.length\n for (let i = 0; i < len; i++) {\n let t = 1;\n for (let j = 1; j < len; j++) {\n if (arr[j] < arr[j - 1]) {\n t = 0;\n break;\n }\n }\n if (t == 1) {\n k = 1;\n break;\n }\n arr.push(arr[j]);\n arr.shift()\n }\n if (k == 1) { return true }\n return false\n}\n\n", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "MoveOneBall"}
111
  {"task_id": "JavaScript/110", "prompt": "/*In this problem, you will implement a function that takes two lists of numbers,\n and determines whether it is possible to perform an exchange of elements\n between them to make lst1 a list of only even numbers.\n There is no limit on the number of exchanged elements between lst1 and lst2.\n If it is possible to exchange elements between the lst1 and lst2 to make\n all the elements of lst1 to be even, return \"YES\".\n Otherwise, return \"NO\".\n For example:\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n It is assumed that the input lists will be non-empty.\n */\nconst exchange = (lst1, lst2) => {\n", "canonical_solution": " let k = lst1.length\n let t = 0\n for (let i = 0; i < lst1.length; i++) {\n if (lst1[i] % 2 == 0) { t++ }\n }\n for (let i = 0; i < lst2.length; i++) {\n if (lst2[i] % 2 == 0) { t++ }\n }\n if (t >= k) { return 'YES' }\n return 'NO'\n}\n\n", "test": "const testExchange = () => {\n console.assert(exchange([1, 2, 3, 4], [1, 2, 3, 4]) === 'YES')\n console.assert(exchange([1, 2, 3, 4], [1, 5, 3, 4]) === 'NO')\n console.assert(exchange([1, 2, 3, 4], [2, 1, 4, 3]) === 'YES')\n console.assert(exchange([5, 7, 3], [2, 6, 4]) === 'YES')\n console.assert(exchange([5, 7, 3], [2, 6, 3]) === 'NO')\n console.assert(exchange([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) === 'NO')\n console.assert(exchange([100, 200], [200, 200]) === 'YES')\n}\n\ntestExchange()\n", "declaration": "\nconst exchange = (lst1, lst2) => {\n", "example_test": "const testExchange = () => {\n console.assert(exchange([1, 2, 3, 4], [1, 2, 3, 4]) === 'YES')\n console.assert(exchange([1, 2, 3, 4], [1, 5, 3, 4]) === 'NO')\n}\ntestExchange()\n", "buggy_solution": " let k = lst1.length\n let t = 0\n for (let i = 0; i < lst1.length; i++) {\n if (lst1[i] % 2 == 0) { t++ }\n }\n for (let i = 0; i < lst2.length; i++) {\n if (lst2[i] % 2 == 0) { t++ }\n }\n if (k >= t) { return 'YES' }\n return 'NO'\n}\n\n", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "Exchange"}
112
  {"task_id": "JavaScript/111", "prompt": "/*Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n\n */\nconst histogram = (test) => {\n", "canonical_solution": " let d = {}\n let t = test.split(/\\s/)\n if (test == '') { t = [] }\n for (m in t) {\n if (t[m] in d) {\n d[t[m]]++\n }\n else {\n d[t[m]] = 1\n }\n }\n s = Object.keys(d).sort(function (a, b) { return - d[a] + d[b]; });\n if (s.length == 0) { return {} }\n let g = d[s[0]]\n let l = {}\n for (let ss=0; ss<s.length; ss++) {\n if (d[s[ss]] == g) {\n l[s[ss]] = d[s[ss]]\n }\n }\n return l\n}\n\n", "test": "const testHistogram = () => {\n console.assert(\n JSON.stringify(histogram('a b b a')) === JSON.stringify({ a: 2, b: 2 })\n )\n console.assert(\n JSON.stringify(histogram('a b c a b')) === JSON.stringify({ a: 2, b: 2 })\n )\n console.assert(\n JSON.stringify(histogram('a b c d g')) ===\n JSON.stringify({ a: 1, b: 1, c: 1, d: 1, g: 1 })\n )\n console.assert(\n JSON.stringify(histogram('r t g')) === JSON.stringify({ r: 1, t: 1, g: 1 })\n )\n console.assert(\n JSON.stringify(histogram('b b b b a')) === JSON.stringify({ b: 4 })\n )\n console.assert(\n JSON.stringify(histogram('r t g')) === JSON.stringify({ r: 1, t: 1, g: 1 })\n )\n console.assert(JSON.stringify(histogram('')) === JSON.stringify({}))\n console.assert(JSON.stringify(histogram('a')) === JSON.stringify({ a: 1 }))\n}\n\ntestHistogram()\n", "declaration": "\nconst histogram = (test) => {\n", "example_test": "const testHistogram = () => {\n console.assert(\n JSON.stringify(histogram('a b b a')) === JSON.stringify({ a: 2, b: 2 })\n )\n console.assert(\n JSON.stringify(histogram('a b c a b')) === JSON.stringify({ a: 2, b: 2 })\n )\n console.assert(\n JSON.stringify(histogram('a b c d g')) ===\n JSON.stringify({ a: 1, b: 1, c: 1, d: 1, g: 1 })\n )\n console.assert(\n JSON.stringify(histogram('a b c')) === JSON.stringify({ a: 1, b: 1, c: 1 })\n )\n console.assert(\n JSON.stringify(histogram('b b b b a')) === JSON.stringify({ b: 4 })\n )\n console.assert(JSON.stringify(histogram('')) === JSON.stringify({}))\n}\ntestHistogram()\n", "buggy_solution": " let d = {}\n let t = test.split(/\\s/)\n if (test == '') { t = [] }\n for (m in t) {\n if (t[m] in d) {\n d[t[m]]++\n }\n else {\n d[t[m]] = 1\n }\n }\n s = Object.keys(d).sort(function (a, b) { return - d[a] + d[b]; });\n if (s.length == 0) { return {} }\n let g = d[s[0]]\n let l = {}\n for (let ss=1; ss<s.length; ss++) {\n if (d[s[ss]] == g) {\n l[s[ss]] = d[s[ss]]\n }\n }\n return l\n}\n\n", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "Histogram"}
113
+ {"task_id": "JavaScript/112", "prompt": "/*Task\n We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and true/false for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be ('bcd',false)\n For s = \"abcdef\", c = \"b\" the result should be ('acdef',false)\n For s = \"abcdedcba\", c = \"ab\", the result should be ('cdedc',true)\n */\nconst reverseDelete = (s, c) => {\n", "canonical_solution": " let t = ''\n for (let i = 0; i < s.length; i++) {\n let y = 1\n for (let j = 0; j < c.length; j++) {\n if (s[i] == c[j]) {\n y = 0\n }\n }\n if (y == 1) {\n t += s[i]\n }\n }\n let isPalindrome = true\n for (let i = 0; i < Math.floor(t.length / 2); i++) {\n if (t[i] != t[t.length - i - 1]) {\n isPalindrome = false\n break\n }\n }\n return [t, isPalindrome];\n}\n\n", "test": "const testReverseDelete = () => {\n console.assert(JSON.stringify(reverseDelete('abcde', 'ae')) ===\n JSON.stringify(['bcd', false]))\n console.assert(JSON.stringify(reverseDelete('abcdef', 'b')) ===\n JSON.stringify(['acdef', false]))\n console.assert(JSON.stringify(reverseDelete('abcdedcba', 'ab')) ===\n JSON.stringify(['cdedc', true]))\n console.assert(JSON.stringify(reverseDelete('dwik', 'w')) ===\n JSON.stringify(['dik', false]))\n console.assert(JSON.stringify(reverseDelete('a', 'a')) ===\n JSON.stringify(['', true]))\n console.assert(JSON.stringify(reverseDelete('abcdedcba', '')) ===\n JSON.stringify(['abcdedcba', true]))\n console.assert(JSON.stringify(reverseDelete('abcdedcba', 'v')) ===\n JSON.stringify(['abcdedcba', true]))\n console.assert(JSON.stringify(reverseDelete('vabba', 'v')) ===\n JSON.stringify(['abba', true]))\n console.assert(JSON.stringify(reverseDelete('mamma', 'mia')) ===\n JSON.stringify(['', true]))\n}\n\ntestReverseDelete()\n", "declaration": "\nconst reverseDelete = (s, c) => {\n", "example_test": "const testReverseDelete = () => {\n console.assert(JSON.stringify(reverseDelete('abcde', 'ae'))) ===\n JSON.stringify(['bcd', false])\n console.assert(JSON.stringify(reverseDelete('abcdef', 'b'))) ===\n JSON.stringify(['acdef', false])\n console.assert(JSON.stringify(reverseDelete('abcdedcba', 'ab'))) ===\n JSON.stringify(['cdedc', true])\n}\ntestReverseDelete()\n", "buggy_solution": " let t = ''\n for (let i = 0; i < s.length; i++) {\n let y = 1\n for (let j = 0; j < c.length; j++) {\n if (s[i] == c[j]) {\n y = 0\n }\n }\n if (y == 1) {\n t += s[i]\n }\n }\n let isPalindrome = false\n for (let i = 0; i < Math.floor(t.length / 2); i++) {\n if (t[i] != t[t.length - i - 1]) {\n isPalindrome = true\n break\n }\n }\n return [t, isPalindrome];\n}\n\n", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "ReverseDelete"}
114
  {"task_id": "JavaScript/113", "prompt": "/*Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> oddCount(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> oddCount(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n */\nconst oddCount = (lst) => {\n", "canonical_solution": " let d = []\n for (let i = 0; i < lst.length; i++) {\n let p = 0;\n let h = lst[i].length\n for (let j = 0; j < h; j++) {\n if (lst[i][j].charCodeAt() % 2 == 1) { p++ }\n }\n p = p.toString()\n d.push('the number of odd elements ' + p + 'n the str' + p + 'ng ' + p + ' of the ' + p + 'nput.')\n }\n return d\n}\n\n", "test": "const testOddCount = () => {\n console.assert(\n JSON.stringify(oddCount(['1234567'])) ===\n JSON.stringify([\n 'the number of odd elements 4n the str4ng 4 of the 4nput.',\n ])\n )\n console.assert(JSON.stringify(\n oddCount(['3', '11111111'])) ===\n JSON.stringify([\n 'the number of odd elements 1n the str1ng 1 of the 1nput.',\n 'the number of odd elements 8n the str8ng 8 of the 8nput.',\n ])\n )\n console.assert(\n JSON.stringify(oddCount(['271', '137', '314'])) ===\n JSON.stringify([\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n ])\n )\n}\n\ntestOddCount()\n", "declaration": "\nconst oddCount = (lst) => {\n", "example_test": "const testOddCount = () => {\n console.assert(\n JSON.stringify(oddCount(['1234567'])) ===\n JSON.stringify([\n 'the number of odd elements 4n the str4ng 4 of the 4nput.',\n ])\n )\n console.assert(JSON.stringify(\n oddCount(['3', '11111111'])) ===\n JSON.stringify([\n 'the number of odd elements 1n the str1ng 1 of the 1nput.',\n 'the number of odd elements 8n the str8ng 8 of the 8nput.',\n ])\n )\n}\ntestOddCount()\n", "buggy_solution": " let d = []\n for (let i = 0; i < lst.length; i++) {\n let p = 0;\n let h = lst[i].length\n for (let j = 0; j < h; j++) {\n if (lst[i][j].charCodeAt() % 2 == 1) { p++ }\n }\n p = p.toString()\n d.push('the number of odd elements ' + p + 'n the str' + p + 'ng ' + p + ' of ' p + ' the ' + p + 'nput.')\n }\n return d\n}\n\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "OddCount"}
115
  {"task_id": "JavaScript/114", "prompt": "/*\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n */\nconst minSubArraySum = (nums) => {\n", "canonical_solution": " let min = nums[0]\n for (let i = 0; i < nums.length; i++) {\n for (let j = i + 1; j <= nums.length; j++) {\n let s = 0;\n for (let k = i; k < j; k++) {\n s += nums[k]\n }\n if (s < min) { min = s }\n }\n }\n return min\n}\n\n", "test": "const testMinSubArraySum = () => {\n console.assert(minSubArraySum([2, 3, 4, 1, 2, 4]) === 1)\n console.assert(minSubArraySum([-1, -2, -3]) === -6)\n console.assert(minSubArraySum([-1, -2, -3, 2, -10]) === -14)\n console.assert(minSubArraySum([-9999999999999999]) === -9999999999999999)\n console.assert(minSubArraySum([0, 10, 20, 1000000]) === 0)\n console.assert(minSubArraySum([-1, -2, -3, 10, -5]) === -6)\n console.assert(minSubArraySum([100, -1, -2, -3, 10, -5]) === -6)\n console.assert(minSubArraySum([10, 11, 13, 8, 3, 4]) === 3)\n console.assert(minSubArraySum([100, -33, 32, -1, 0, -2]) === -33)\n console.assert(minSubArraySum([-10]) === -10)\n console.assert(minSubArraySum([7]) === 7)\n console.assert(minSubArraySum([1, -1]) === -1)\n}\n\ntestMinSubArraySum()\n", "declaration": "\nconst minSubArraySum = (nums) => {\n", "example_test": "const testMinSubArraySum = () => {\n console.assert(minSubArraySum([2, 3, 4, 1, 2, 4]) === 1)\n console.assert(minSubArraySum([-1, -2, -3]) === -6)\n}\ntestMinSubArraySum()\n", "buggy_solution": " let min = Math.min(nums)\n for (let i = 0; i < nums.length; i++) {\n for (let j = i + 1; j <= nums.length; j++) {\n let s = 0;\n for (let k = i; k < j; k++) {\n s += nums[k]\n }\n if (s < min) { min = s }\n }\n }\n return min\n}\n\n", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "Minsubarraysum"}
116
  {"task_id": "JavaScript/115", "prompt": "/*\n You are given a rectangular grid of wells. Each row represents a single well,\n and each 1 in a row represents a single unit of water.\n Each well has a corresponding bucket that can be used to extract water from it, \n and all buckets have the same capacity.\n Your task is to use the buckets to empty the wells.\n Output the number of times you need to lower the buckets.\n\n Example 1:\n Input: \n grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n bucket_capacity : 1\n Output: 6\n\n Example 2:\n Input: \n grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n bucket_capacity : 2\n Output: 5\n \n Example 3:\n Input: \n grid : [[0,0,0], [0,0,0]]\n bucket_capacity : 5\n Output: 0\n\n Constraints:\n * all wells have the same length\n * 1 <= grid.length <= 10^2\n * 1 <= grid[:,1].length <= 10^2\n * grid[i][j] -> 0 | 1\n * 1 <= capacity <= 10\n */\nconst maxFill = (grid, capacity) => {\n", "canonical_solution": " let p = 0\n for (let i = 0; i < grid.length; i++) {\n let m = 0\n for (let j = 0; j < grid[i].length; j++) {\n if (grid[i][j] == 1) { m++ }\n }\n while (m > 0) {\n m -= capacity;\n p++;\n }\n }\n return p\n}\n\n", "test": "const testMaxFill = () => {\n console.assert(\n maxFill(\n [\n [0, 0, 1, 0],\n [0, 1, 0, 0],\n [1, 1, 1, 1],\n ],\n 1\n ) === 6\n )\n console.assert(\n maxFill(\n [\n [0, 0, 1, 1],\n [0, 0, 0, 0],\n [1, 1, 1, 1],\n [0, 1, 1, 1],\n ],\n 2\n ) === 5\n )\n console.assert(\n maxFill(\n [\n [0, 0, 0],\n [0, 0, 0],\n ],\n 5\n ) === 0\n )\n console.assert(\n maxFill(\n [\n [1, 1, 1, 1],\n [1, 1, 1, 1],\n ],\n 2\n ) === 4\n )\n console.assert(\n maxFill(\n [\n [1, 1, 1, 1],\n [1, 1, 1, 1],\n ],\n 9\n ) === 2\n )\n}\n\ntestMaxFill()\n", "declaration": "\nconst maxFill = (grid, capacity) => {\n", "example_test": "const testMaxFill = () => {\n console.assert(\n maxFill(\n [\n [0, 0, 1, 0],\n [0, 1, 0, 0],\n [1, 1, 1, 1],\n ],\n 1\n ) === 6\n )\n console.assert(\n maxFill(\n [\n [0, 0, 1, 1],\n [0, 0, 0, 0],\n [1, 1, 1, 1],\n [0, 1, 1, 1],\n ],\n 2\n ) === 5\n )\n console.assert(\n maxFill(\n [\n [0, 0, 0],\n [0, 0, 0],\n ],\n 5\n ) === 0\n )\n}\ntestMaxFill()\n", "buggy_solution": " let p = 0\n for (let i = 0; i < grid.length; i++) {\n let m = 0\n for (let j = 1; j < grid[i].length; j++) {\n if (grid[i][j] == 1) { m++ }\n }\n while (m > 0) {\n m -= capacity;\n p++;\n }\n }\n return p\n}\n\n", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "MaxFill"}