diff --git "a/data/rust/data/humanevalbugs.jsonl" "b/data/rust/data/humanevalbugs.jsonl" --- "a/data/rust/data/humanevalbugs.jsonl" +++ "b/data/rust/data/humanevalbugs.jsonl" @@ -33,7 +33,7 @@ {"task_id": "Rust/32", "prompt": "\n/*\n xs are coefficients of a polynomial.\n find_zero find x such that poly(x) = 0.\n find_zero returns only only zero point, even if there are many.\n Moreover, find_zero only takes list xs having even number of coefficients\n and largest non zero coefficient as it guarantees\n a solution.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn poly(xs: &Vec, x: f64) -> f64 {\n\n", "canonical_solution": "\n let mut sum = 0.0;\n for i in 0..xs.len() {\n sum += xs[i] * x.powi(i as i32);\n }\n sum\n }\n \n fn find_zero(xs: &Vec) -> f64 {\n let mut ans = 0.0;\n let mut value = poly(xs, ans);\n while value.abs() > 1e-6 {\n let mut driv = 0.0;\n for i in 1..xs.len() {\n driv += xs[i] * ans.powi((i - 1) as i32) * (i as f64);\n }\n ans = ans - value / driv;\n value = poly(xs, ans);\n }\n ans\n }\n", "test": "\n\n#[cfg(test)]\nmod tests {\n use super::*;\n\n#[test]\n fn test_poly() {\n let mut rng = rand::thread_rng();\n let mut solution: f64;\n let mut ncoeff: i32;\n for _ in 0..100 {\n ncoeff = 2 * (1 + rng.gen_range(0, 4));\n let mut coeffs = vec![];\n for _ in 0..ncoeff {\n let coeff = -10 + rng.gen_range(0, 21);\n if coeff == 0 {\n coeffs.push(1.0);\n } else {\n coeffs.push(coeff as f64);\n }\n }\n solution = find_zero(&coeffs);\n assert!(poly(&coeffs, solution).abs() < 1e-3);\n }\n }\n\n}\n\n", "example_test": "None", "buggy_solution": "\n let mut sum = 0.0;\n for i in 0..xs.len() {\n sum += xs[i] * x.powi(i as i32);\n }\n sum\n }\n \n fn find_zero(xs: &Vec) -> f64 {\n let mut driv = 0.0;\n let mut ans = 0.0;\n let mut value = poly(xs, ans);\n while value.abs() > 1e-6 {\n for i in 1..xs.len() {\n driv += xs[i] * ans.powi((i - 1) as i32) * (i as f64);\n }\n ans = value - driv / ans;\n value = poly(xs, ans);\n }\n ans\n }\n", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "find_zero"} {"task_id": "Rust/33", "prompt": "\n/*\nThis function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn sort_third(l: Vec) -> Vec {\n\n", "canonical_solution": "\n let mut third = vec![];\n let mut out:Vec = vec![];\n\n for (indx,elem) in l.iter().enumerate(){\n if indx%3 == 0 && indx != 0{\n third.push(elem)\n }\n }\n third.sort();\n let mut indx_t:usize = 0;\n\n for i in 0..l.len() {\n if i%3 == 0 && i != 0{\n if indx_t < third.len(){\n out.push(*third[indx_t]);\n indx_t += 1;\n }\n }else{\n out.push(l[i]);\n }\n \n }\n return out;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_sort_third() {\n let mut l = vec![1, 2, 3];\n assert_eq!(sort_third(l), vec![1, 2, 3]);\n l = vec![5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10];\n assert_eq!(sort_third(l), vec![5, 3, -5, 1, -3, 3, 2, 0, 123, 9, -10]);\n l = vec![5, 8, -12, 4, 23, 2, 3, 11, 12, -10];\n assert_eq!(sort_third(l), vec![5, 8, -12, -10, 23, 2, 3, 11, 12, 4]);\n l = vec![5, 6, 3, 4, 8, 9, 2];\n assert_eq!(sort_third(l), vec![5, 6, 3, 2, 8, 9, 4]);\n l = vec![5, 8, 3, 4, 6, 9, 2];\n assert_eq!(sort_third(l), vec![5, 8, 3, 2, 6, 9, 4]);\n l = vec![5, 6, 9, 4, 8, 3, 2];\n assert_eq!(sort_third(l), vec![5, 6, 9, 2, 8, 3, 4]);\n l = vec![5, 6, 3, 4, 8, 9, 2, 1];\n assert_eq!(sort_third(l), vec![5, 6, 3, 2, 8, 9, 4, 1]);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut third = vec![];\n let mut out:Vec = vec![];\n\n for (indx,elem) in l.iter().enumerate(){\n if indx%3 == 0 && indx != 0{\n third.push(elem)\n }\n }\n let mut indx_t:usize = 0;\n\n for i in 0..l.len() {\n if i%3 == 0 && i != 0{\n if indx_t < third.len(){\n out.push(*third[indx_t]);\n indx_t += 1;\n }\n }else{\n out.push(l[i]);\n }\n \n }\n return out;\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "sort_third"} {"task_id": "Rust/34", "prompt": "\n/*\nReturn sorted unique elements in a list\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn unique(nmbs:Vec) -> Vec{\n\n", "canonical_solution": "\n let mut res:Vec = nmbs.clone();\n res.sort();\n res.dedup();\n return res;\n }\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_unique() {\n assert!(unique(vec![5, 3, 5, 2, 3, 3, 9, 0, 123]) == vec![0, 2, 3, 5, 9, 123]);\n }\n\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut res:Vec = nmbs.clone();\n res.sort();\n return res;\n }\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "unique"} -{"task_id": "Rust/35", "prompt": "\n/*\nReturn maximum element in the list.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn maximum(nmbs:Vec) -> i32{\n\n", "canonical_solution": "\n return *nmbs.iter().max().unwrap();\n }\n\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_maximum() {\n assert!(maximum(vec![1, 2, 3]) == 3);\n assert!(maximum(vec![5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124);\n }\n\n\n}\n", "example_test": "None", "buggy_solution": "\n return *nmbs.iter().min().unwrap();\n }\n\n", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "max_element"} +{"task_id": "Rust/35", "prompt": "\n/*\nReturn maximum element in the list.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn maximum(nmbs:Vec) -> i32{\n\n", "canonical_solution": "\n return *nmbs.iter().max().unwrap();\n }\n\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_maximum() {\n assert!(maximum(vec![1, 2, 3]) == 3);\n assert!(maximum(vec![5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124);\n }\n\n\n}\n", "example_test": "None", "buggy_solution": "\n return *nmbs.iter().min().unwrap();\n }\n\n", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "maximum"} {"task_id": "Rust/36", "prompt": "\n/*\nReturn the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn fizz_buzz(n:i32) -> i32{\n\n", "canonical_solution": "\n let mut ns:Vec = vec![];\n\n for i in 0..n{\n if i % 11 == 0 || i % 13 == 0{\n ns.push(i);\n }\n }\n\n let s:String = ns.into_iter().fold(String::new(),|s:String, n:i32| {s + &n.to_string()});\n let mut ans:i32 = 0;\n\n for c in s.chars(){\n if c == '7'{\n ans += 1;\n }\n }\n return ans;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n\n #[test]\n fn test_fizz_buzz() {\n assert!(fizz_buzz(50) == 0);\n assert!(fizz_buzz(78) == 2);\n assert!(fizz_buzz(79) == 3);\n assert!(fizz_buzz(100) == 3);\n assert!(fizz_buzz(200) == 6);\n assert!(fizz_buzz(4000) == 192);\n assert!(fizz_buzz(10000) == 639);\n assert!(fizz_buzz(100000) == 8026);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut ns:Vec = vec![];\n\n for i in 0..n{\n if i % 11 == 0 && i % 13 == 0{\n ns.push(i);\n }\n }\n\n let s:String = ns.into_iter().fold(String::new(),|s:String, n:i32| {s + &n.to_string()});\n let mut ans:i32 = 0;\n\n for c in s.chars(){\n if c == '7'{\n ans += 1;\n }\n }\n return ans;\n}\n", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "fizz_buzz"} {"task_id": "Rust/37", "prompt": "\n/*\nThis function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn sort_even(nmbs:Vec) -> Vec{\n\n", "canonical_solution": "\n let mut even = vec![];\n let mut out:Vec = vec![];\n\n for (indx,elem) in nmbs.iter().enumerate(){\n if indx%2 == 0{\n even.push(elem)\n }\n }\n even.sort();\n let mut indx_t:usize = 0;\n\n for i in 0..nmbs.len() {\n if i%2 == 0{\n if indx_t < even.len(){\n out.push(*even[indx_t]);\n indx_t += 1;\n }\n }else{\n out.push(nmbs[i]);\n }\n \n }\n return out;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_sort_even() {\n assert_eq!(sort_even(vec![1, 2, 3]), vec![1, 2, 3]);\n assert_eq!(\n sort_even(vec![5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]),\n vec![-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123]\n );\n assert_eq!(\n sort_even(vec![5, 8, -12, 4, 23, 2, 3, 11, 12, -10]),\n vec![-12, 8, 3, 4, 5, 2, 12, 11, 23, -10]\n );\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut even = vec![];\n let mut out:Vec = vec![];\n\n for (indx,elem) in nmbs.iter().enumerate(){\n if indx%2 == 0{\n even.push(elem)\n }\n }\n even.sort();\n let mut indx_t:usize = 0;\n\n for i in 0..nmbs.len() {\n if i%2 == 0{\n if indx_t < even.len(){\n out.push(*even[indx_t]);\n indx_t += 1;\n }\n }else{\n out.push(i as i32);\n }\n \n }\n return out;\n}\n", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "sort_even"} {"task_id": "Rust/38", "prompt": "\n/*\n\n takes as input string encoded with encode_cyclic function. Returns decoded string.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn decode_cyclic(s: &str) -> String {\n\n", "canonical_solution": "\n\n let l = s.len();\n let num = (l + 2) / 3;\n let mut output = String::new();\n for i in 0..num {\n let group = &s[i * 3..std::cmp::min(l, (i + 1) * 3)];\n // revert the cycle performed by the encode_cyclic function\n if group.len() == 3 {\n let x = format!(\"{}{}{}\", &group[2..3], &group[0..1], &group[1..2]);\n output.push_str(&x);\n } else {\n output.push_str(group);\n }\n }\n output\n}\n\npub fn encode_cyclic(s: &str) -> String {\n // returns encoded string by cycling groups of three characters.\n // split string to groups. Each of length 3.\n let l = s.len();\n let num = (l + 2) / 3;\n let mut output = String::new();\n for i in 0..num {\n let group = &s[i * 3..std::cmp::min(l, (i + 1) * 3)];\n // cycle elements in each group. Unless group has fewer elements than 3.\n if group.len() == 3 {\n let x = format!(\"{}{}{}\", &group[1..2], &group[2..3], &group[0..1]);\n output.push_str(&x);\n } else {\n output.push_str(group);\n }\n }\n output\n}\n\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n#[test]\n fn test_decode_cyclic() {\n for _ in 0..100 {\n let l = 10 + rand::random::() % 11;\n let mut str = String::new();\n for _ in 0..l {\n let chr = 97 + rand::random::() % 26;\n str.push(chr as u8 as char);\n }\n let encoded_str = encode_cyclic(&str);\n assert_eq!(decode_cyclic(&encoded_str), str);\n }\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n\n let l = s.len();\n let num = (l + 2) / 3;\n let mut output = String::new();\n for i in 0..num {\n let group = &s[i * 3..std::cmp::min(l, (i + 1) * 3)];\n // revert the cycle performed by the encode_cyclic function\n if group.len() == 3 {\n let x = format!(\"{}{}\", &group[2..3], &group[0..1]);\n output.push_str(&x);\n } else {\n output.push_str(group);\n }\n }\n output\n}\n\npub fn encode_cyclic(s: &str) -> String {\n // returns encoded string by cycling groups of three characters.\n // split string to groups. Each of length 3.\n let l = s.len();\n let num = (l + 2) / 3;\n let mut output = String::new();\n for i in 0..num {\n let group = &s[i * 3..std::cmp::min(l, (i + 1) * 3)];\n // cycle elements in each group. Unless group has fewer elements than 3.\n if group.len() == 3 {\n let x = format!(\"{}{}{}\", &group[1..2], &group[2..3], &group[0..1]);\n output.push_str(&x);\n } else {\n output.push_str(group);\n }\n }\n output\n}\n\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "decode_cyclic"} @@ -112,7 +112,7 @@ {"task_id": "Rust/111", "prompt": "\n/*\nGiven a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn histogram(test:&str) -> HashMap{\n\n", "canonical_solution": "\n let mut res: HashMap = HashMap::new();\n if test == \"\" {\n return res;\n }\n for c in test.split_ascii_whitespace() {\n if res.contains_key(&c.chars().next().unwrap()) {\n res.entry(c.chars().next().unwrap()).and_modify(|n| {\n *n += 1;\n });\n } else {\n res.insert(c.chars().next().unwrap(), 1);\n }\n }\n let max: i32 = *res.values().max().unwrap();\n let non_maxs: Vec = res\n .keys()\n .filter(|k: &&char| *res.get(k).unwrap() != max)\n .map(|c| *c)\n .collect();\n non_maxs.iter().for_each(|c| {\n res.remove(c);\n });\n\n return res;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_histogram() {\n assert!(histogram(\"a b b a\") == HashMap::from([('a', 2), ('b', 2)]));\n assert!(histogram(\"a b c a b\") == HashMap::from([('a', 2), ('b', 2)]));\n assert!(\n histogram(\"a b c d g\")\n == HashMap::from([('a', 1), ('b', 1), ('c', 1), ('d', 1), ('g', 1)])\n );\n assert!(histogram(\"r t g\") == HashMap::from([('r', 1), ('t', 1), ('g', 1)]));\n assert!(histogram(\"b b b b a\") == HashMap::from([('b', 4)]));\n assert!(histogram(\"r t g\") == HashMap::from([('r', 1), ('t', 1), ('g', 1)]));\n assert!(histogram(\"\") == HashMap::new());\n assert!(histogram(\"a\") == HashMap::from([(('a', 1))]));\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut res: HashMap = HashMap::new();\n if test == \"\" {\n return res;\n }\n for c in test.split_ascii_whitespace() {\n if res.contains_key(&c.chars().next().unwrap()) {\n res.entry(c.chars().next().unwrap()).and_modify(|n| {\n *n += 2;\n });\n } else {\n res.insert(c.chars().next().unwrap(), 1);\n }\n }\n let max: i32 = *res.values().max().unwrap();\n let non_maxs: Vec = res\n .keys()\n .filter(|k: &&char| *res.get(k).unwrap() != max)\n .map(|c| *c)\n .collect();\n non_maxs.iter().for_each(|c| {\n res.remove(c);\n });\n\n return res;\n}\n", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "histogram"} {"task_id": "Rust/112", "prompt": "\n/*\nTask\n We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and True/False for the check.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn reverse_delete(s:&str, c:&str) -> Vec {\n\n", "canonical_solution": "\n let mut n = String::new();\n for i in 0..s.len() {\n if !c.contains(s.chars().nth(i).unwrap()) {\n n.push(s.chars().nth(i).unwrap());\n }\n }\n if n.len() == 0 {\n return vec![n, \"True\".to_string()];\n }\n let w: String = n.chars().rev().collect();\n if w == n {\n return vec![n, \"True\".to_string()];\n }\n return vec![n, \"False\".to_string()];\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_reverse_delete() {\n assert!(reverse_delete(\"abcde\", \"ae\") == [\"bcd\", \"False\"]);\n assert!(reverse_delete(\"abcdef\", \"b\") == [\"acdef\", \"False\"]);\n assert!(reverse_delete(\"abcdedcba\", \"ab\") == [\"cdedc\", \"True\"]);\n assert!(reverse_delete(\"dwik\", \"w\") == [\"dik\", \"False\"]);\n assert!(reverse_delete(\"a\", \"a\") == [\"\", \"True\"]);\n assert!(reverse_delete(\"abcdedcba\", \"\") == [\"abcdedcba\", \"True\"]);\n assert!(reverse_delete(\"abcdedcba\", \"v\") == [\"abcdedcba\", \"True\"]);\n assert!(reverse_delete(\"vabba\", \"v\") == [\"abba\", \"True\"]);\n assert!(reverse_delete(\"mamma\", \"mia\") == [\"\", \"True\"]);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut n = String::new();\n for i in 0..s.len() {\n if !c.contains(s.chars().nth(i).unwrap()) {\n n.push(s.chars().nth(i).unwrap());\n }\n }\n if n.len() != 0 {\n return vec![n, \"True\".to_string()];\n }\n let w: String = n.chars().rev().collect();\n if w == n {\n return vec![n, \"True\".to_string()];\n }\n return vec![n, \"False\".to_string()];\n}\n", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "reverse_delete"} {"task_id": "Rust/113", "prompt": "\n/*\nGiven a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn odd_count(lst:Vec<&str>) -> Vec{\n\n", "canonical_solution": "\n let mut out: Vec = Vec::new();\n for i in 0..lst.len() {\n let mut sum = 0;\n for j in 0..lst[i].len() {\n if lst[i].chars().nth(j).unwrap() >= '0'\n && lst[i].chars().nth(j).unwrap() <= '9'\n && lst[i].chars().nth(j).unwrap().to_digit(10).unwrap() % 2 == 1\n {\n sum += 1;\n }\n }\n let mut s = \"the number of odd elements in the string i of the input.\".to_string();\n let mut s2 = \"\".to_string();\n for j in 0..s.len() {\n if s.chars().nth(j).unwrap() == 'i' {\n s2.push_str(&sum.to_string());\n } else {\n s2.push(s.chars().nth(j).unwrap());\n }\n }\n out.push(s2);\n }\n return out;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_odd_count() {\n assert!(\n odd_count(vec![\"1234567\"])\n == [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n );\n assert!(\n odd_count(vec![\"3\", \"11111111\"])\n == [\n \"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"\n ]\n );\n assert!(\n odd_count(vec![\"271\", \"137\", \"314\"])\n == [\n \"the number of odd elements 2n the str2ng 2 of the 2nput.\",\n \"the number of odd elements 3n the str3ng 3 of the 3nput.\",\n \"the number of odd elements 2n the str2ng 2 of the 2nput.\"\n ]\n );\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut out: Vec = Vec::new();\n for i in 0..lst.len() {\n let mut sum = 0;\n for j in 0..lst[i].len() {\n if lst[i].chars().nth(j).unwrap() >= '0'\n && lst[i].chars().nth(j).unwrap() <= '9'\n && lst[i].chars().nth(j).unwrap().to_digit(10).unwrap() % 2 == 1\n {\n sum += 1;\n }\n }\n let mut s = \"the number of odd elements in the string i of i the input.\".to_string();\n let mut s2 = \"\".to_string();\n for j in 0..s.len() {\n if s.chars().nth(j).unwrap() == 'i' {\n s2.push_str(&sum.to_string());\n } else {\n s2.push(s.chars().nth(j).unwrap());\n }\n }\n out.push(s2);\n }\n return out;\n}\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "odd_count"} -{"task_id": "Rust/114", "prompt": "\n/*\n\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn min_sub_array_sum(nums: Vec) -> i64 {\n\n", "canonical_solution": "\n let mut current = nums[0];\n let mut min = nums[0];\n for i in 1..nums.len() {\n if current < 0 {\n current = current + nums[i];\n } else {\n current = nums[i];\n }\n if current < min {\n min = current;\n }\n }\n min\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_min_sub_array_sum() {\n assert!(min_sub_array_sum(vec![2, 3, 4, 1, 2, 4]) == 1);\n assert!(min_sub_array_sum(vec![-1, -2, -3]) == -6);\n assert!(min_sub_array_sum(vec![-1, -2, -3, 2, -10]) == -14);\n assert!(min_sub_array_sum(vec![-9999999999999999]) == -9999999999999999);\n assert!(min_sub_array_sum(vec![0, 10, 20, 1000000]) == 0);\n assert!(min_sub_array_sum(vec![-1, -2, -3, 10, -5]) == -6);\n assert!(min_sub_array_sum(vec![100, -1, -2, -3, 10, -5]) == -6);\n assert!(min_sub_array_sum(vec![10, 11, 13, 8, 3, 4]) == 3);\n assert!(min_sub_array_sum(vec![100, -33, 32, -1, 0, -2]) == -33);\n assert!(min_sub_array_sum(vec![-10]) == -10);\n assert!(min_sub_array_sum(vec![7]) == 7);\n assert!(min_sub_array_sum(vec![1, -1]) == -1);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut current = nums[0];\n let mut min = *nums.iter().max().unwrap();\n for i in 1..nums.len() {\n if current < 0 {\n current = current + nums[i];\n } else {\n current = nums[i];\n }\n if current < min {\n min = current;\n }\n }\n min\n}\n", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "minSubArraySum"} +{"task_id": "Rust/114", "prompt": "\n/*\n\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn min_sub_array_sum(nums: Vec) -> i64 {\n\n", "canonical_solution": "\n let mut current = nums[0];\n let mut min = nums[0];\n for i in 1..nums.len() {\n if current < 0 {\n current = current + nums[i];\n } else {\n current = nums[i];\n }\n if current < min {\n min = current;\n }\n }\n min\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_min_sub_array_sum() {\n assert!(min_sub_array_sum(vec![2, 3, 4, 1, 2, 4]) == 1);\n assert!(min_sub_array_sum(vec![-1, -2, -3]) == -6);\n assert!(min_sub_array_sum(vec![-1, -2, -3, 2, -10]) == -14);\n assert!(min_sub_array_sum(vec![-9999999999999999]) == -9999999999999999);\n assert!(min_sub_array_sum(vec![0, 10, 20, 1000000]) == 0);\n assert!(min_sub_array_sum(vec![-1, -2, -3, 10, -5]) == -6);\n assert!(min_sub_array_sum(vec![100, -1, -2, -3, 10, -5]) == -6);\n assert!(min_sub_array_sum(vec![10, 11, 13, 8, 3, 4]) == 3);\n assert!(min_sub_array_sum(vec![100, -33, 32, -1, 0, -2]) == -33);\n assert!(min_sub_array_sum(vec![-10]) == -10);\n assert!(min_sub_array_sum(vec![7]) == 7);\n assert!(min_sub_array_sum(vec![1, -1]) == -1);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut current = nums[0];\n let mut min = *nums.iter().max().unwrap();\n for i in 1..nums.len() {\n if current < 0 {\n current = current + nums[i];\n } else {\n current = nums[i];\n }\n if current < min {\n min = current;\n }\n }\n min\n}\n", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "min_sub_array_sum"} {"task_id": "Rust/115", "prompt": "\n/*\n You are given a rectangular grid of wells. Each row represents a single well,\n and each 1 in a row represents a single unit of water.\n Each well has a corresponding bucket that can be used to extract water from it, \n and all buckets have the same capacity.\n Your task is to use the buckets to empty the wells.\n Output the number of times you need to lower the buckets.\n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn max_fill(grid:Vec>, capacity:i32) -> i32{\n\n", "canonical_solution": "\n let mut out: i32 = 0;\n\n for i in 0..grid.len() {\n let mut sum: i32 = 0;\n\n for j in 0..grid[i].len() {\n sum += grid[i][j];\n }\n if sum > 0 {\n out += (sum - 1) / capacity + 1;\n }\n }\n return out;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_max_fill() {\n assert!(\n max_fill(\n vec![vec![0, 0, 1, 0], vec![0, 1, 0, 0], vec![1, 1, 1, 1]],\n 1\n ) == 6\n );\n assert!(\n max_fill(\n vec![\n vec![0, 0, 1, 1],\n vec![0, 0, 0, 0],\n vec![1, 1, 1, 1],\n vec![0, 1, 1, 1]\n ],\n 2\n ) == 5\n );\n assert!(max_fill(vec![vec![0, 0, 0], vec![0, 0, 0]], 5) == 0);\n assert!(max_fill(vec![vec![1, 1, 1, 1], vec![1, 1, 1, 1]], 2) == 4);\n assert!(max_fill(vec![vec![1, 1, 1, 1], vec![1, 1, 1, 1]], 9) == 2);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut out: i32 = 0;\n\n for i in 0..grid.len() {\n let mut sum: i32 = 0;\n\n for j in 0..grid[i].len() {\n sum += grid[i][j];\n }\n if sum > 0 {\n out += (sum - 1) / capacity;\n }\n }\n return out;\n}\n", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "max_fill"} {"task_id": "Rust/116", "prompt": "\n/*\n\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn sort_array_1(arr:Vec) -> Vec{\n\n", "canonical_solution": "\n let mut arr_cp = arr.clone();\n let mut bin = vec![];\n let mut m;\n\n for i in 0..arr_cp.len() {\n let mut b = 0;\n let mut n = arr_cp[i].abs();\n while n > 0 {\n b += n % 2;\n n = n / 2;\n }\n bin.push(b);\n }\n for i in 0..arr_cp.len() {\n for j in 1..arr_cp.len() {\n if bin[j] < bin[j - 1] || (bin[j] == bin[j - 1] && arr_cp[j] < arr_cp[j - 1]) {\n m = arr_cp[j];\n arr_cp[j] = arr_cp[j - 1];\n arr_cp[j - 1] = m;\n m = bin[j];\n bin[j] = bin[j - 1];\n bin[j - 1] = m;\n }\n }\n }\n return arr_cp;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_sort_array_1() {\n assert!(sort_array_1(vec![1, 5, 2, 3, 4]) == vec![1, 2, 4, 3, 5]);\n assert!(sort_array_1(vec![-2, -3, -4, -5, -6]) == vec![-4, -2, -6, -5, -3]);\n assert!(sort_array_1(vec![1, 0, 2, 3, 4]) == vec![0, 1, 2, 4, 3]);\n assert!(sort_array_1(vec![]) == vec![]);\n assert!(\n sort_array_1(vec![2, 5, 77, 4, 5, 3, 5, 7, 2, 3, 4])\n == vec![2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]\n );\n assert!(sort_array_1(vec![3, 6, 44, 12, 32, 5]) == vec![32, 3, 5, 6, 12, 44]);\n assert!(sort_array_1(vec![2, 4, 8, 16, 32]) == vec![2, 4, 8, 16, 32]);\n assert!(sort_array_1(vec![2, 4, 8, 16, 32]) == vec![2, 4, 8, 16, 32]);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut arr_cp = arr.clone();\n let mut bin = vec![];\n let mut m;\n\n for i in 0..arr_cp.len() {\n let mut b = 0;\n let mut n = arr_cp[i].abs();\n while n > 0 {\n b += n % 2;\n n = n / 2;\n }\n bin.push(b);\n }\n for i in 0..arr_cp.len() {\n for j in 1..arr_cp.len() {\n if bin[j] < bin[j - 1] || (bin[j] == bin[j - 1] && arr_cp[j] < arr_cp[j - 1]) {\n m = arr_cp[j];\n arr_cp[j] = arr_cp[j - 1];\n arr_cp[j - 1] = m;\n m = bin[j];\n bin[j] = bin[j - 1];\n bin[j - 1] = m;\n }\n }\n }\n return bin;\n}\n", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "sort_array"} {"task_id": "Rust/117", "prompt": "\n/*\nGiven a string s and a natural number n, you have been tasked to implement \n a function that returns a list of all words from string s that contain exactly \n n consonants, in order these words appear in the string s.\n If the string s is empty then the function should return an empty list.\n Note: you may assume the input string contains only letters and spaces.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn select_words(s:&str, n:i32) -> Vec{\n\n", "canonical_solution": "\n let vowels = \"aeiouAEIOU\";\n let mut current = String::new();\n let mut out = Vec::new();\n let mut numc = 0;\n let mut s = s.to_string();\n s.push(' ');\n for i in 0..s.len() {\n if s.chars().nth(i).unwrap() == ' ' {\n if numc == n {\n out.push(current);\n }\n current = String::new();\n numc = 0;\n } else {\n current.push(s.chars().nth(i).unwrap());\n if (s.chars().nth(i).unwrap() >= 'A' && s.chars().nth(i).unwrap() <= 'Z')\n || (s.chars().nth(i).unwrap() >= 'a' && s.chars().nth(i).unwrap() <= 'z')\n {\n if !vowels.contains(s.chars().nth(i).unwrap()) {\n numc += 1;\n }\n }\n }\n }\n out\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_select_words() {\n assert_eq!(select_words(\"Mary had a little lamb\", 4), vec![\"little\"]);\n assert_eq!(\n select_words(\"Mary had a little lamb\", 3),\n vec![\"Mary\", \"lamb\"]\n );\n let v_empty: Vec<&str> = vec![];\n assert_eq!(select_words(\"simple white space\", 2), v_empty);\n assert_eq!(select_words(\"Hello world\", 4), vec![\"world\"]);\n assert_eq!(select_words(\"Uncle sam\", 3), vec![\"Uncle\"]);\n assert_eq!(select_words(\"\", 4), v_empty);\n assert_eq!(select_words(\"a b c d e f\", 1), vec![\"b\", \"c\", \"d\", \"f\"]);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let vowels = \"aeiouAEIOU\";\n let mut current = String::new();\n let mut out = Vec::new();\n let mut numc = 0;\n let mut s = s.to_string();\n s.push(' ');\n for i in 0..s.len() {\n if s.chars().nth(i).unwrap() == ' ' {\n if numc == n {\n out.push(current);\n }\n current = String::new();\n numc = 0;\n } else {\n current.push(s.chars().nth(i).unwrap());\n if (s.chars().nth(i).unwrap() >= 'A' && s.chars().nth(i).unwrap() <= 'Z')\n || (s.chars().nth(i).unwrap() >= 'a' && s.chars().nth(i).unwrap() <= 'z')\n {\n if vowels.contains(s.chars().nth(i).unwrap()) {\n numc += 1;\n }\n }\n }\n }\n out\n}\n", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "select_words"} @@ -127,7 +127,7 @@ {"task_id": "Rust/126", "prompt": "\n/*\n\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return False. Assume no negative numbers and only integers.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn is_sorted(lst: Vec) -> bool {\n\n", "canonical_solution": "\n for i in 1..lst.len() {\n if lst[i] < lst[i - 1] {\n return false;\n }\n if i >= 2 && lst[i] == lst[i - 1] && lst[i] == lst[i - 2] {\n return false;\n }\n }\n true\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_is_sorted() {\n assert_eq!(is_sorted(vec![5]), true);\n assert_eq!(is_sorted(vec![1, 2, 3, 4, 5]), true);\n assert_eq!(is_sorted(vec![1, 3, 2, 4, 5]), false);\n assert_eq!(is_sorted(vec![1, 2, 3, 4, 5, 6]), true);\n assert_eq!(is_sorted(vec![1, 2, 3, 4, 5, 6, 7]), true);\n assert_eq!(is_sorted(vec![1, 3, 2, 4, 5, 6, 7]), false);\n assert_eq!(is_sorted(vec![]), true);\n assert_eq!(is_sorted(vec![1]), true);\n assert_eq!(is_sorted(vec![3, 2, 1]), false);\n assert_eq!(is_sorted(vec![1, 2, 2, 2, 3, 4]), false);\n assert_eq!(is_sorted(vec![1, 2, 3, 3, 3, 4]), false);\n assert_eq!(is_sorted(vec![1, 2, 2, 3, 3, 4]), true);\n assert_eq!(is_sorted(vec![1, 2, 3, 4]), true);\n }\n\n\n}\n", "example_test": "None", "buggy_solution": "\n for i in 1..lst.len() {\n if i >= 2 && lst[i] == lst[i - 1] && lst[i] == lst[i - 2] {\n return false;\n }\n }\n true\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "is_sorted"} {"task_id": "Rust/127", "prompt": "\n/*\nYou are given two intervals,\n where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).\n The given intervals are closed which means that the interval (start, end)\n includes both start and end.\n For each given interval, it is assumed that its start is less or equal its end.\n Your task is to determine whether the length of intersection of these two \n intervals is a prime number.\n Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)\n which its length is 1, which not a prime number.\n If the length of the intersection is a prime number, return \"YES\",\n otherwise, return \"NO\".\n If the two intervals don't intersect, return \"NO\".\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn intersection(interval1: Vec, interval2: Vec) -> String {\n\n", "canonical_solution": "\n let inter1 = std::cmp::max(interval1[0], interval2[0]);\n let inter2 = std::cmp::min(interval1[1], interval2[1]);\n let l = inter2 - inter1;\n if l < 2 {\n return \"NO\".to_string();\n }\n for i in 2..l {\n if l % i == 0 {\n return \"NO\".to_string();\n }\n }\n return \"YES\".to_string();\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_intersection() {\n assert_eq!(intersection(vec![1, 2], vec![2, 3]), \"NO\");\n assert_eq!(intersection(vec![-1, 1], vec![0, 4]), \"NO\");\n assert_eq!(intersection(vec![-3, -1], vec![-5, 5]), \"YES\");\n assert_eq!(intersection(vec![-2, 2], vec![-4, 0]), \"YES\");\n assert_eq!(intersection(vec![-11, 2], vec![-1, -1]), \"NO\");\n assert_eq!(intersection(vec![1, 2], vec![3, 5]), \"NO\");\n assert_eq!(intersection(vec![1, 2], vec![1, 2]), \"NO\");\n assert_eq!(intersection(vec![-2, -2], vec![-3, -2]), \"NO\");\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let inter1 = std::cmp::max(interval1[0], interval2[0]);\n let inter2 = std::cmp::min(interval1[1], interval2[1]);\n let l = inter2 - inter1;\n for i in 2..l {\n if l % i == 0 {\n return \"NO\".to_string();\n }\n }\n return \"YES\".to_string();\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "intersection"} {"task_id": "Rust/128", "prompt": "\n/*\n\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn prod_signs(arr: Vec) -> i32 {\n\n", "canonical_solution": "\n if arr.is_empty() {\n return -32768;\n }\n let mut sum = 0;\n let mut prods = 1;\n for i in arr {\n sum += i.abs();\n if i == 0 {\n prods = 0;\n }\n if i < 0 {\n prods = -prods;\n }\n }\n sum * prods\n}\n\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_prod_signs() {\n assert_eq!(prod_signs(vec![1, 2, 2, -4]), -9);\n assert_eq!(prod_signs(vec![0, 1]), 0);\n assert_eq!(prod_signs(vec![1, 1, 1, 2, 3, -1, 1]), -10);\n assert_eq!(prod_signs(vec![]), -32768);\n assert_eq!(prod_signs(vec![2, 4, 1, 2, -1, -1, 9]), 20);\n assert_eq!(prod_signs(vec![-1, 1, -1, 1]), 4);\n assert_eq!(prod_signs(vec![-1, 1, 1, 1]), -4);\n assert_eq!(prod_signs(vec![-1, 1, 1, 0]), 0);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n if arr.is_empty() {\n return -32768;\n }\n let mut sum = 0;\n let mut prods = 1;\n for i in arr {\n sum += i.abs();\n if i == 0 {\n prods = 0;\n }\n if i < 0 {\n prods = -prods;\n }\n }\n 2 * sum * prods\n}\n\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "prod_signs"} -{"task_id": "Rust/129", "prompt": "\n/*\n\n Given a grid with N rows and N columns (N >= 2) and a positive integer k, \n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn min_path(grid: Vec>, k: i32) -> Vec {\n\n", "canonical_solution": "\n let mut out: Vec = vec![];\n let mut x = 0;\n let mut y = 0;\n let mut min: i32 = (grid.len() * grid.len()) as i32;\n for i in 0..grid.len() {\n for j in 0..grid[i].len() {\n if grid[i][j] == 1 {\n x = i;\n y = j;\n }\n }\n }\n if x > 0 && grid[x - 1][y] < min {\n min = grid[x - 1][y];\n }\n if x < grid.len() - 1 && grid[x + 1][y] < min {\n min = grid[x + 1][y];\n }\n if y > 0 && grid[x][y - 1] < min {\n min = grid[x][y - 1];\n }\n if y < grid.len() - 1 && grid[x][y + 1] < min {\n min = grid[x][y + 1];\n }\n let mut out = vec![];\n for i in 0..k {\n if i % 2 == 0 {\n out.push(1);\n } else {\n out.push(min);\n }\n }\n out\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_min_path() {\n assert_eq!(\n min_path(vec![vec![1, 2, 3], vec![4, 5, 6], vec![7, 8, 9]], 3),\n vec![1, 2, 1]\n );\n assert_eq!(\n min_path(vec![vec![5, 9, 3], vec![4, 1, 6], vec![7, 8, 2]], 1),\n vec![1]\n );\n assert_eq!(\n min_path(\n vec![\n vec![1, 2, 3, 4],\n vec![5, 6, 7, 8],\n vec![9, 10, 11, 12],\n vec![13, 14, 15, 16]\n ],\n 4\n ),\n vec![1, 2, 1, 2]\n );\n assert_eq!(\n min_path(\n vec![\n vec![6, 4, 13, 10],\n vec![5, 7, 12, 1],\n vec![3, 16, 11, 15],\n vec![8, 14, 9, 2]\n ],\n 7\n ),\n vec![1, 10, 1, 10, 1, 10, 1]\n );\n assert_eq!(\n min_path(\n vec![\n vec![8, 14, 9, 2],\n vec![6, 4, 13, 15],\n vec![5, 7, 1, 12],\n vec![3, 10, 11, 16]\n ],\n 5\n ),\n vec![1, 7, 1, 7, 1]\n );\n assert_eq!(\n min_path(\n vec![\n vec![11, 8, 7, 2],\n vec![5, 16, 14, 4],\n vec![9, 3, 15, 6],\n vec![12, 13, 10, 1]\n ],\n 9\n ),\n vec![1, 6, 1, 6, 1, 6, 1, 6, 1]\n );\n assert_eq!(\n min_path(\n vec![\n vec![12, 13, 10, 1],\n vec![9, 3, 15, 6],\n vec![5, 16, 14, 4],\n vec![11, 8, 7, 2]\n ],\n 12\n ),\n vec![1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]\n );\n assert_eq!(\n min_path(vec![vec![2, 7, 4], vec![3, 1, 5], vec![6, 8, 9]], 8),\n vec![1, 3, 1, 3, 1, 3, 1, 3]\n );\n\n assert_eq!(\n min_path(vec![vec![6, 1, 5], vec![3, 8, 9], vec![2, 7, 4]], 8),\n vec![1, 5, 1, 5, 1, 5, 1, 5]\n );\n\n assert_eq!(\n min_path(vec![vec![1, 2], vec![3, 4]], 10),\n vec![1, 2, 1, 2, 1, 2, 1, 2, 1, 2]\n );\n\n assert_eq!(\n min_path(vec![vec![1, 3], vec![3, 2]], 10),\n vec![1, 3, 1, 3, 1, 3, 1, 3, 1, 3]\n );\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut out: Vec = vec![];\n let mut x = 0;\n let mut y = 0;\n let mut min: i32 = (grid.len() * grid.len()) as i32;\n for i in 0..grid.len() {\n for j in 0..grid[i].len() {\n if grid[i][j] == 1 {\n x = i;\n y = j;\n }\n }\n }\n if x > 0 && grid[x - 1][y] < min {\n min = grid[x - 1][y];\n }\n if x < grid.len() && grid[x + 1][y] < min {\n min = grid[x][y];\n }\n if y > 0 && grid[x][y - 1] < min {\n min = grid[x][y - 1];\n }\n if y < grid.len() - 1 && grid[x][y + 1] < min {\n min = grid[x][y];\n }\n let mut out = vec![];\n for i in 0..k {\n if i % 2 == 0 {\n out.push(1);\n } else {\n out.push(min);\n }\n }\n out\n}\n", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "minPath"} +{"task_id": "Rust/129", "prompt": "\n/*\n\n Given a grid with N rows and N columns (N >= 2) and a positive integer k, \n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn min_path(grid: Vec>, k: i32) -> Vec {\n\n", "canonical_solution": "\n let mut out: Vec = vec![];\n let mut x = 0;\n let mut y = 0;\n let mut min: i32 = (grid.len() * grid.len()) as i32;\n for i in 0..grid.len() {\n for j in 0..grid[i].len() {\n if grid[i][j] == 1 {\n x = i;\n y = j;\n }\n }\n }\n if x > 0 && grid[x - 1][y] < min {\n min = grid[x - 1][y];\n }\n if x < grid.len() - 1 && grid[x + 1][y] < min {\n min = grid[x + 1][y];\n }\n if y > 0 && grid[x][y - 1] < min {\n min = grid[x][y - 1];\n }\n if y < grid.len() - 1 && grid[x][y + 1] < min {\n min = grid[x][y + 1];\n }\n let mut out = vec![];\n for i in 0..k {\n if i % 2 == 0 {\n out.push(1);\n } else {\n out.push(min);\n }\n }\n out\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_min_path() {\n assert_eq!(\n min_path(vec![vec![1, 2, 3], vec![4, 5, 6], vec![7, 8, 9]], 3),\n vec![1, 2, 1]\n );\n assert_eq!(\n min_path(vec![vec![5, 9, 3], vec![4, 1, 6], vec![7, 8, 2]], 1),\n vec![1]\n );\n assert_eq!(\n min_path(\n vec![\n vec![1, 2, 3, 4],\n vec![5, 6, 7, 8],\n vec![9, 10, 11, 12],\n vec![13, 14, 15, 16]\n ],\n 4\n ),\n vec![1, 2, 1, 2]\n );\n assert_eq!(\n min_path(\n vec![\n vec![6, 4, 13, 10],\n vec![5, 7, 12, 1],\n vec![3, 16, 11, 15],\n vec![8, 14, 9, 2]\n ],\n 7\n ),\n vec![1, 10, 1, 10, 1, 10, 1]\n );\n assert_eq!(\n min_path(\n vec![\n vec![8, 14, 9, 2],\n vec![6, 4, 13, 15],\n vec![5, 7, 1, 12],\n vec![3, 10, 11, 16]\n ],\n 5\n ),\n vec![1, 7, 1, 7, 1]\n );\n assert_eq!(\n min_path(\n vec![\n vec![11, 8, 7, 2],\n vec![5, 16, 14, 4],\n vec![9, 3, 15, 6],\n vec![12, 13, 10, 1]\n ],\n 9\n ),\n vec![1, 6, 1, 6, 1, 6, 1, 6, 1]\n );\n assert_eq!(\n min_path(\n vec![\n vec![12, 13, 10, 1],\n vec![9, 3, 15, 6],\n vec![5, 16, 14, 4],\n vec![11, 8, 7, 2]\n ],\n 12\n ),\n vec![1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]\n );\n assert_eq!(\n min_path(vec![vec![2, 7, 4], vec![3, 1, 5], vec![6, 8, 9]], 8),\n vec![1, 3, 1, 3, 1, 3, 1, 3]\n );\n\n assert_eq!(\n min_path(vec![vec![6, 1, 5], vec![3, 8, 9], vec![2, 7, 4]], 8),\n vec![1, 5, 1, 5, 1, 5, 1, 5]\n );\n\n assert_eq!(\n min_path(vec![vec![1, 2], vec![3, 4]], 10),\n vec![1, 2, 1, 2, 1, 2, 1, 2, 1, 2]\n );\n\n assert_eq!(\n min_path(vec![vec![1, 3], vec![3, 2]], 10),\n vec![1, 3, 1, 3, 1, 3, 1, 3, 1, 3]\n );\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut out: Vec = vec![];\n let mut x = 0;\n let mut y = 0;\n let mut min: i32 = (grid.len() * grid.len()) as i32;\n for i in 0..grid.len() {\n for j in 0..grid[i].len() {\n if grid[i][j] == 1 {\n x = i;\n y = j;\n }\n }\n }\n if x > 0 && grid[x - 1][y] < min {\n min = grid[x - 1][y];\n }\n if x < grid.len() && grid[x + 1][y] < min {\n min = grid[x][y];\n }\n if y > 0 && grid[x][y - 1] < min {\n min = grid[x][y - 1];\n }\n if y < grid.len() - 1 && grid[x][y + 1] < min {\n min = grid[x][y];\n }\n let mut out = vec![];\n for i in 0..k {\n if i % 2 == 0 {\n out.push(1);\n } else {\n out.push(min);\n }\n }\n out\n}\n", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "min_path"} {"task_id": "Rust/130", "prompt": "\n/*\nEveryone knows Fibonacci sequence, it was studied deeply by mathematicians in \n the last couple centuries. However, what people don't know is Tribonacci sequence.\n Tribonacci sequence is defined by the recurrence:\n tri(1) = 3\n tri(n) = 1 + n / 2, if n is even.\n tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.\n For example:\n tri(2) = 1 + (2 / 2) = 2\n tri(4) = 3\n tri(3) = tri(2) + tri(1) + tri(4)\n = 2 + 3 + 3 = 8 \n You are given a non-negative integer number n, you have to a return a list of the \n first n + 1 numbers of the Tribonacci sequence.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn tri(n: i32) -> Vec {\n\n", "canonical_solution": "\n let mut out = vec![1, 3];\n if n == 0 {\n return vec![1];\n }\n for i in 2..=n {\n if i % 2 == 0 {\n out.push(1 + i / 2);\n } else {\n out.push(out[(i - 1) as usize] + out[(i - 2) as usize] + 1 + (i + 1) / 2);\n }\n }\n out\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_tri() {\n assert!(tri(3) == vec![1, 3, 2, 8]);\n assert!(tri(4) == vec![1, 3, 2, 8, 3]);\n assert!(tri(5) == vec![1, 3, 2, 8, 3, 15]);\n assert!(tri(6) == vec![1, 3, 2, 8, 3, 15, 4]);\n assert!(tri(7) == vec![1, 3, 2, 8, 3, 15, 4, 24]);\n assert!(tri(8) == vec![1, 3, 2, 8, 3, 15, 4, 24, 5]);\n assert!(tri(9) == vec![1, 3, 2, 8, 3, 15, 4, 24, 5, 35]);\n assert!(\n tri(20)\n == vec![1, 3, 2, 8, 3, 15, 4, 24, 5, 35, 6, 48, 7, 63, 8, 80, 9, 99, 10, 120, 11]\n );\n assert!(tri(0) == vec![1]);\n assert!(tri(1) == vec![1, 3]);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut out = vec![1, 3];\n if n == 0 {\n return vec![1];\n }\n for i in 2..=n {\n if i % 2 == 0 {\n out.push(1 + i / 2);\n } else {\n out.push(out[(i - 1) as usize] + out[(i - 2) as usize] + 1 + i * (i + 1) / 2);\n }\n }\n out\n}\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "tri"} {"task_id": "Rust/131", "prompt": "\n/*\nGiven a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn digits(n: i32) -> i32 {\n\n", "canonical_solution": "\n let mut prod: i32 = 1;\n let mut has = 0;\n let s = n.to_string();\n for i in 0..s.len() {\n if s.chars().nth(i).unwrap().to_digit(10).unwrap() % 2 == 1 {\n has = 1;\n prod = prod * (s.chars().nth(i).unwrap().to_digit(10).unwrap()) as i32;\n }\n }\n if has == 0 {\n return 0;\n }\n prod\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_digits() {\n assert_eq!(digits(5), 5);\n assert_eq!(digits(54), 5);\n assert_eq!(digits(120), 1);\n assert_eq!(digits(5014), 5);\n assert_eq!(digits(98765), 315);\n assert_eq!(digits(5576543), 2625);\n assert_eq!(digits(2468), 0);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut prod: i32 = 1;\n let mut has = 0;\n let s = n.to_string();\n for i in 0..s.len() {\n if s.chars().nth(i).unwrap().to_digit(10).unwrap() % 2 == 1 {\n has = 1;\n prod *= prod * (s.chars().nth(i).unwrap().to_digit(10).unwrap()) as i32;\n }\n }\n if has == 0 {\n return 0;\n }\n prod\n}\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "digits"} {"task_id": "Rust/132", "prompt": "\n/*\n\n Create a function that takes a string as input which contains only square brackets.\n The function should return True if and only if there is a valid subsequence of brackets \n where at least one bracket in the subsequence is nested.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn is_nested(str: &str) -> bool {\n\n", "canonical_solution": "\n let mut count = 0;\n let mut maxcount = 0;\n for i in 0..str.len() {\n if str.chars().nth(i).unwrap() == '[' {\n count += 1;\n }\n if str.chars().nth(i).unwrap() == ']' {\n count -= 1;\n }\n if count < 0 {\n count = 0;\n }\n if count > maxcount {\n maxcount = count;\n }\n if count <= maxcount - 2 {\n return true;\n }\n }\n return false;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_is_nested() {\n assert_eq!(is_nested(\"[[]]\"), true);\n assert_eq!(is_nested(\"[]]]]]]][[[[[]\"), false);\n assert_eq!(is_nested(\"[][]\"), false);\n assert_eq!(is_nested(\"[]\"), false);\n assert_eq!(is_nested(\"[[[[]]]]\"), true);\n assert_eq!(is_nested(\"[]]]]]]]]]]\"), false);\n assert_eq!(is_nested(\"[][][[]]\"), true);\n assert_eq!(is_nested(\"[[]\"), false);\n assert_eq!(is_nested(\"[]]\"), false);\n assert_eq!(is_nested(\"[[]][[\"), true);\n assert_eq!(is_nested(\"[[][]]\"), true);\n assert_eq!(is_nested(\"\"), false);\n assert_eq!(is_nested(\"[[[[[[[[\"), false);\n assert_eq!(is_nested(\"]]]]]]]]\"), false);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut count = 0;\n let mut maxcount = 0;\n for i in 0..str.len() {\n if str.chars().nth(i).unwrap() == '(' {\n count += 1;\n }\n if str.chars().nth(i).unwrap() == ')' {\n count -= 1;\n }\n if count < 0 {\n count = 0;\n }\n if count > maxcount {\n maxcount = count;\n }\n if count <= maxcount - 2 {\n return true;\n }\n }\n return false;\n}\n", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "is_nested"} @@ -144,14 +144,14 @@ {"task_id": "Rust/143", "prompt": "\n/*\n\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn words_in_sentence(sentence: &str) -> String {\n\n", "canonical_solution": "\n let mut out = String::new();\n let mut current = String::new();\n let mut sentence = sentence.to_string();\n sentence.push(' ');\n\n for i in 0..sentence.len() {\n if sentence.chars().nth(i).unwrap() != ' ' {\n current.push(sentence.chars().nth(i).unwrap());\n } else {\n let mut isp = true;\n let l = current.len();\n if l < 2 {\n isp = false;\n }\n for j in 2..(l as f64).sqrt() as usize + 1 {\n if l % j == 0 {\n isp = false;\n }\n }\n if isp {\n out.push_str(¤t);\n out.push(' ');\n }\n current = String::new();\n }\n }\n if out.len() > 0 {\n out.pop();\n }\n out\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_words_in_sentence() {\n assert_eq!(words_in_sentence(\"This is a test\"), \"is\");\n assert_eq!(words_in_sentence(\"lets go for swimming\"), \"go for\");\n assert_eq!(\n words_in_sentence(\"there is no place available here\"),\n \"there is no place\"\n );\n assert_eq!(words_in_sentence(\"Hi I am Hussein\"), \"Hi am Hussein\");\n assert_eq!(words_in_sentence(\"go for it\"), \"go for it\");\n assert_eq!(words_in_sentence(\"here\"), \"\");\n assert_eq!(words_in_sentence(\"here is\"), \"is\");\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut out = String::new();\n let mut current = String::new();\n let mut sentence = sentence.to_string();\n sentence.push(' ');\n\n for i in 0..sentence.len() {\n if sentence.chars().nth(i).unwrap() != ' ' {\n current.push(sentence.chars().nth(i).unwrap());\n } else {\n let mut isp = true;\n let l = current.len();\n if l < 2 {\n isp = false;\n }\n for j in 2..(l as f64).sqrt() as usize + 1 {\n if l % j == 0 {\n isp = false;\n }\n }\n if isp {\n out.push_str(¤t);\n }\n current = String::new();\n }\n }\n if out.len() > 0 {\n out.pop();\n }\n out\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "words_in_sentence"} {"task_id": "Rust/144", "prompt": "\n/*\nYour task is to implement a function that will simplify the expression\n x * n. The function returns True if x * n evaluates to a whole number and False\n otherwise. Both x and n, are string representation of a fraction, and have the following format,\n / where both numerator and denominator are positive whole numbers.\n\n You can assume that x, and n are valid fractions, and do not have zero as denominator.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn simplify(x: &str, n: &str) -> bool {\n\n", "canonical_solution": "\n let mut a = 0;\n let mut b = 0;\n let mut c = 0;\n let mut d = 0;\n let mut i = 0;\n for i in 0..x.len() {\n if x.chars().nth(i).unwrap() == '/' {\n a = x\n .chars()\n .take(i)\n .collect::()\n .parse::()\n .unwrap();\n b = x\n .chars()\n .skip(i + 1)\n .collect::()\n .parse::()\n .unwrap();\n }\n }\n for i in 0..n.len() {\n if n.chars().nth(i).unwrap() == '/' {\n c = n\n .chars()\n .take(i)\n .collect::()\n .parse::()\n .unwrap();\n d = n\n .chars()\n .skip(i + 1)\n .collect::()\n .parse::()\n .unwrap();\n }\n }\n if (a * c) % (b * d) == 0 {\n return true;\n }\n return false;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_simplify() {\n assert_eq!(simplify(\"1/5\", \"5/1\"), true);\n assert_eq!(simplify(\"1/6\", \"2/1\"), false);\n assert_eq!(simplify(\"5/1\", \"3/1\"), true);\n assert_eq!(simplify(\"7/10\", \"10/2\"), false);\n assert_eq!(simplify(\"2/10\", \"50/10\"), true);\n assert_eq!(simplify(\"7/2\", \"4/2\"), true);\n assert_eq!(simplify(\"11/6\", \"6/1\"), true);\n assert_eq!(simplify(\"2/3\", \"5/2\"), false);\n assert_eq!(simplify(\"5/2\", \"3/5\"), false);\n assert_eq!(simplify(\"2/4\", \"8/4\"), true);\n assert_eq!(simplify(\"2/4\", \"4/2\"), true);\n assert_eq!(simplify(\"1/5\", \"5/1\"), true);\n assert_eq!(simplify(\"1/5\", \"1/5\"), false);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut a = 0;\n let mut b = 0;\n let mut c = 0;\n let mut d = 0;\n let mut i = 0;\n for i in 0..x.len() {\n if x.chars().nth(i).unwrap() == '/' {\n a = x\n .chars()\n .take(i)\n .collect::()\n .parse::()\n .unwrap();\n b = x\n .chars()\n .skip(i + 1)\n .collect::()\n .parse::()\n .unwrap();\n }\n }\n for i in 0..n.len() {\n if n.chars().nth(i).unwrap() == '/' {\n c = n\n .chars()\n .take(i)\n .collect::()\n .parse::()\n .unwrap();\n d = n\n .chars()\n .skip(i + 1)\n .collect::()\n .parse::()\n .unwrap();\n }\n }\n if (a * b * c) % (b * d) == 0 {\n return true;\n }\n return false;\n}\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "simplify"} {"task_id": "Rust/145", "prompt": "\n/*\n\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn order_by_points(arr: Vec) -> Vec {\n\n", "canonical_solution": "\n let mut result = arr.clone();\n result.sort_by_key(|&x| (sum_of_digits(x)));\n result\n}\n\npub fn sum_of_digits(n: i32) -> i32 {\n let mut sum = 0;\n let mut n = n;\n if n < 0 {\n let right = n / 10;\n let mut left;\n\n if right != 0 {\n left = n % 10;\n left = -1 * left;\n } else {\n left = n % 10;\n }\n sum = right + left;\n return sum;\n }\n\n while n > 0 {\n sum += n % 10;\n n /= 10;\n }\n sum\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_order_by_points() {\n assert_eq!(\n order_by_points(vec![1, 11, -1, -11, -12]),\n vec![-1, -11, 1, -12, 11]\n );\n assert_eq!(\n order_by_points(vec![\n 1234, 423, 463, 145, 2, 423, 423, 53, 6, 37, 3457, 3, 56, 0, 46\n ]),\n vec![0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]\n );\n assert_eq!(order_by_points(vec![]), vec![]);\n assert_eq!(\n order_by_points(vec![1, -11, -32, 43, 54, -98, 2, -3]),\n vec![-3, -32, -98, -11, 1, 2, 43, 54]\n );\n assert_eq!(\n order_by_points(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]),\n vec![1, 10, 2, 11, 3, 4, 5, 6, 7, 8, 9]\n );\n assert_eq!(\n order_by_points(vec![0, 6, 6, -76, -21, 23, 4]),\n vec![-76, -21, 0, 4, 23, 6, 6]\n );\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut result = arr.clone();\n result.sort_by_key(|&x| (sum_of_digits(x)));\n result\n}\n\npub fn sum_of_digits(n: i32) -> i32 {\n let mut sum = 0;\n let mut n = n;\n if n < 0 {\n let right = n / 10;\n let mut left;\n\n if right != 0 {\n left = n % 10;\n left = -1 * left + n;\n } else {\n left = n % 10;\n }\n sum = right + left;\n return sum;\n }\n\n while n > 0 {\n sum += n % 10;\n n /= 10;\n }\n sum\n}\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "order_by_points"} -{"task_id": "Rust/146", "prompt": "\n/*\nWrite a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn special_filter(nums: Vec) -> i32 {\n\n", "canonical_solution": "\n let mut num = 0;\n for i in 0..nums.len() {\n if nums[i] > 10 {\n let w = nums[i].to_string();\n if w.chars().nth(0).unwrap().to_digit(10).unwrap() % 2 == 1\n && w.chars().last().unwrap().to_digit(10).unwrap() % 2 == 1\n {\n num += 1;\n }\n }\n }\n num\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_special_filter() {\n assert_eq!(special_filter(vec![5, -2, 1, -5]), 0);\n assert_eq!(special_filter(vec![15, -73, 14, -15]), 1);\n assert_eq!(special_filter(vec![33, -2, -3, 45, 21, 109]), 2);\n assert_eq!(special_filter(vec![43, -12, 93, 125, 121, 109]), 4);\n assert_eq!(special_filter(vec![71, -2, -33, 75, 21, 19]), 3);\n assert_eq!(special_filter(vec![1]), 0);\n assert_eq!(special_filter(vec![]), 0);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut num = 0;\n for i in 0..nums.len() {\n if nums[i] > 10 {\n let w = nums[i].to_string();\n if w.chars().nth(0).unwrap().to_digit(10).unwrap() + 1 % 2 == 1\n && w.chars().last().unwrap().to_digit(10).unwrap() % 2 == 1\n {\n num += 1;\n }\n }\n }\n num\n}\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "specialFilter"} -{"task_id": "Rust/147", "prompt": "\n/*\n\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn get_matrix_triples(n: i32) -> i32 {\n\n", "canonical_solution": "\n let mut a = vec![];\n let mut sum = vec![vec![0, 0, 0]];\n let mut sum2 = vec![vec![0, 0, 0]];\n\n for i in 1..=n {\n a.push((i * i - i + 1) % 3);\n sum.push(sum[sum.len() - 1].clone());\n sum[i as usize][a[i as usize - 1] as usize] += 1;\n }\n\n for times in 1..3 {\n for i in 1..=n {\n sum2.push(sum2[sum2.len() - 1].clone());\n if i >= 1 {\n for j in 0..=2 {\n sum2[i as usize][(a[i as usize - 1] + j) as usize % 3] +=\n sum[i as usize - 1][j as usize];\n }\n }\n }\n sum = sum2.clone();\n sum2 = vec![vec![0, 0, 0]];\n }\n\n return sum[n as usize][0];\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_get_matrix_triples() {\n assert_eq!(get_matrix_triples(5), 1);\n assert_eq!(get_matrix_triples(6), 4);\n assert_eq!(get_matrix_triples(10), 36);\n assert_eq!(get_matrix_triples(100), 53361);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut a = vec![];\n let mut sum = vec![vec![0, 0, 0]];\n let mut sum2 = vec![vec![0, 0, 0]];\n\n for i in 1..=n {\n a.push((i * i) % 3);\n sum.push(sum[sum.len() - 1].clone());\n sum[i as usize][a[i as usize - 1] as usize] += 1;\n }\n\n for times in 1..3 {\n for i in 1..=n {\n sum2.push(sum2[sum2.len() - 1].clone());\n if i >= 1 {\n for j in 0..=2 {\n sum2[i as usize][(a[i as usize - 1] + j) as usize % 3] +=\n sum[i as usize - 1][j as usize];\n }\n }\n }\n sum = sum2.clone();\n sum2 = vec![vec![0, 0, 0]];\n }\n\n return sum[n as usize][0];\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "get_max_triples"} +{"task_id": "Rust/146", "prompt": "\n/*\nWrite a function that takes an array of numbers as input and returns \n the number of elements in the array that are greater than 10 and both \n first and last digits of a number are odd (1, 3, 5, 7, 9).\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn special_filter(nums: Vec) -> i32 {\n\n", "canonical_solution": "\n let mut num = 0;\n for i in 0..nums.len() {\n if nums[i] > 10 {\n let w = nums[i].to_string();\n if w.chars().nth(0).unwrap().to_digit(10).unwrap() % 2 == 1\n && w.chars().last().unwrap().to_digit(10).unwrap() % 2 == 1\n {\n num += 1;\n }\n }\n }\n num\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_special_filter() {\n assert_eq!(special_filter(vec![5, -2, 1, -5]), 0);\n assert_eq!(special_filter(vec![15, -73, 14, -15]), 1);\n assert_eq!(special_filter(vec![33, -2, -3, 45, 21, 109]), 2);\n assert_eq!(special_filter(vec![43, -12, 93, 125, 121, 109]), 4);\n assert_eq!(special_filter(vec![71, -2, -33, 75, 21, 19]), 3);\n assert_eq!(special_filter(vec![1]), 0);\n assert_eq!(special_filter(vec![]), 0);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut num = 0;\n for i in 0..nums.len() {\n if nums[i] > 10 {\n let w = nums[i].to_string();\n if w.chars().nth(0).unwrap().to_digit(10).unwrap() + 1 % 2 == 1\n && w.chars().last().unwrap().to_digit(10).unwrap() % 2 == 1\n {\n num += 1;\n }\n }\n }\n num\n}\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "special_filter"} +{"task_id": "Rust/147", "prompt": "\n/*\n\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n and a[i] + a[j] + a[k] is a multiple of 3.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn get_matrix_triples(n: i32) -> i32 {\n\n", "canonical_solution": "\n let mut a = vec![];\n let mut sum = vec![vec![0, 0, 0]];\n let mut sum2 = vec![vec![0, 0, 0]];\n\n for i in 1..=n {\n a.push((i * i - i + 1) % 3);\n sum.push(sum[sum.len() - 1].clone());\n sum[i as usize][a[i as usize - 1] as usize] += 1;\n }\n\n for times in 1..3 {\n for i in 1..=n {\n sum2.push(sum2[sum2.len() - 1].clone());\n if i >= 1 {\n for j in 0..=2 {\n sum2[i as usize][(a[i as usize - 1] + j) as usize % 3] +=\n sum[i as usize - 1][j as usize];\n }\n }\n }\n sum = sum2.clone();\n sum2 = vec![vec![0, 0, 0]];\n }\n\n return sum[n as usize][0];\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_get_matrix_triples() {\n assert_eq!(get_matrix_triples(5), 1);\n assert_eq!(get_matrix_triples(6), 4);\n assert_eq!(get_matrix_triples(10), 36);\n assert_eq!(get_matrix_triples(100), 53361);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut a = vec![];\n let mut sum = vec![vec![0, 0, 0]];\n let mut sum2 = vec![vec![0, 0, 0]];\n\n for i in 1..=n {\n a.push((i * i) % 3);\n sum.push(sum[sum.len() - 1].clone());\n sum[i as usize][a[i as usize - 1] as usize] += 1;\n }\n\n for times in 1..3 {\n for i in 1..=n {\n sum2.push(sum2[sum2.len() - 1].clone());\n if i >= 1 {\n for j in 0..=2 {\n sum2[i as usize][(a[i as usize - 1] + j) as usize % 3] +=\n sum[i as usize - 1][j as usize];\n }\n }\n }\n sum = sum2.clone();\n sum2 = vec![vec![0, 0, 0]];\n }\n\n return sum[n as usize][0];\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "get_matrix_triples"} {"task_id": "Rust/148", "prompt": "\n/*\n\n There are eight planets in our solar system: the closerst to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sorted by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct planet names. \n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn bf(planet1: &str, planet2: &str) -> Vec {\n\n", "canonical_solution": "\n let planets = vec![\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\",\n ];\n let mut pos1: i32 = -1;\n let mut pos2: i32 = -1;\n let mut m;\n for m in 0..planets.len() {\n if planets[m] == planet1 {\n pos1 = m as i32;\n }\n if planets[m] == planet2 {\n pos2 = m as i32;\n }\n }\n if pos1 == -1 || pos2 == -1 {\n return vec![];\n }\n if pos1 > pos2 {\n m = pos1;\n pos1 = pos2;\n pos2 = m;\n }\n let mut out = vec![];\n for m in pos1 + 1..pos2 {\n out.push(planets[m as usize].to_string());\n }\n return out;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_bf() {\n assert_eq!(bf(\"Jupiter\", \"Neptune\"), vec![\"Saturn\", \"Uranus\"]);\n assert_eq!(bf(\"Earth\", \"Mercury\"), vec![\"Venus\"]);\n assert_eq!(\n bf(\"Mercury\", \"Uranus\"),\n vec![\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\"]\n );\n assert_eq!(\n bf(\"Neptune\", \"Venus\"),\n vec![\"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\"]\n );\n let v_empty: Vec<&str> = vec![];\n assert_eq!(bf(\"Earth\", \"Earth\"), v_empty);\n assert_eq!(bf(\"Mars\", \"Earth\"), v_empty);\n assert_eq!(bf(\"Jupiter\", \"Makemake\"), v_empty);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let planets = vec![\n \"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupyter\", \"Saturn\", \"Uranus\", \"Neptune\",\n ];\n let mut pos1: i32 = -1;\n let mut pos2: i32 = -1;\n let mut m;\n for m in 0..planets.len() {\n if planets[m] == planet1 {\n pos1 = m as i32;\n }\n if planets[m] == planet2 {\n pos2 = m as i32;\n }\n }\n if pos1 == -1 || pos2 == -1 {\n return vec![];\n }\n if pos1 > pos2 {\n m = pos1;\n pos1 = pos2;\n pos2 = m;\n }\n let mut out = vec![];\n for m in pos1 + 1..pos2 {\n out.push(planets[m as usize].to_string());\n }\n return out;\n}\n", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "bf"} {"task_id": "Rust/149", "prompt": "\n/*\nWrite a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn sorted_list_sum(lst: Vec<&str>) -> Vec<&str> {\n\n", "canonical_solution": "\n let mut out: Vec<&str> = Vec::new();\n for i in 0..lst.len() {\n if lst[i].len() % 2 == 0 {\n out.push(lst[i]);\n }\n }\n out.sort();\n for i in 0..out.len() {\n for j in 1..out.len() {\n if out[j].len() < out[j - 1].len() {\n let mid = out[j];\n out[j] = out[j - 1];\n out[j - 1] = mid;\n }\n }\n }\n return out;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_sorted_list_sum() {\n assert_eq!(sorted_list_sum(vec![\"aa\", \"a\", \"aaa\"]), vec![\"aa\"]);\n assert_eq!(\n sorted_list_sum(vec![\"school\", \"AI\", \"asdf\", \"b\"]),\n vec![\"AI\", \"asdf\", \"school\"]\n );\n let v_empty: Vec<&str> = vec![];\n assert_eq!(sorted_list_sum(vec![\"d\", \"b\", \"c\", \"a\"]), v_empty);\n assert_eq!(\n sorted_list_sum(vec![\"d\", \"dcba\", \"abcd\", \"a\"]),\n vec![\"abcd\", \"dcba\"]\n );\n assert_eq!(\n sorted_list_sum(vec![\"AI\", \"ai\", \"au\"]),\n vec![\"AI\", \"ai\", \"au\"]\n );\n assert_eq!(sorted_list_sum(vec![\"a\", \"b\", \"b\", \"c\", \"c\", \"a\"]), v_empty);\n assert_eq!(\n sorted_list_sum(vec![\"aaaa\", \"bbbb\", \"dd\", \"cc\"]),\n vec![\"cc\", \"dd\", \"aaaa\", \"bbbb\"]\n );\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut out: Vec<&str> = Vec::new();\n for i in 0..lst.len() {\n if lst[i].len() % 2 == 0 {\n out.push(lst[i]);\n }\n }\n for i in 0..out.len() {\n for j in 1..out.len() {\n if out[j].len() < out[j - 1].len() {\n let mid = out[j];\n out[j] = out[j - 1];\n out[j - 1] = mid;\n }\n }\n }\n return out;\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "sorted_list_sum"} {"task_id": "Rust/150", "prompt": "\n/*\nA simple program which should return the value of x if n is \n a prime number and should return the value of y otherwise.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn x_or_y(n: i32, x: i32, y: i32) -> i32 {\n\n", "canonical_solution": "\n let mut isp = true;\n if n < 2 {\n isp = false;\n }\n for i in 2..=n / 2 {\n if n % i == 0 {\n isp = false;\n }\n }\n if isp {\n return x;\n }\n return y;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_x_or_y() {\n assert_eq!(x_or_y(7, 34, 12), 34);\n assert_eq!(x_or_y(15, 8, 5), 5);\n assert_eq!(x_or_y(3, 33, 5212), 33);\n assert_eq!(x_or_y(1259, 3, 52), 3);\n assert_eq!(x_or_y(7919, -1, 12), -1);\n assert_eq!(x_or_y(3609, 1245, 583), 583);\n assert_eq!(x_or_y(91, 56, 129), 129);\n assert_eq!(x_or_y(6, 34, 1234), 1234);\n assert_eq!(x_or_y(1, 2, 0), 0);\n assert_eq!(x_or_y(2, 2, 0), 2);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut isp = true;\n if n < 2 {\n isp = false;\n }\n for i in 2..=n / 2 {\n if n % i - 1 == 0 {\n isp = false;\n }\n }\n if isp {\n return x;\n }\n return y;\n}\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "x_or_y"} {"task_id": "Rust/151", "prompt": "\n/*\n\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n \n If the input list is empty, return 0.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn double_the_difference(lst: Vec) -> i64 {\n\n", "canonical_solution": "\n let mut sum: i64 = 0;\n for i in 0..lst.len() {\n if (lst[i] - lst[i].round()).abs() < 1e-4 {\n if lst[i] > 0.0 && (lst[i].round() as i64) % 2 == 1 {\n sum += (lst[i].round() as i64) * (lst[i].round() as i64);\n }\n }\n }\n return sum;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_double_the_difference() {\n assert_eq!(double_the_difference(vec![]), 0);\n assert_eq!(double_the_difference(vec![5.0, 4.0]), 25);\n assert_eq!(double_the_difference(vec![0.1, 0.2, 0.3]), 0);\n assert_eq!(double_the_difference(vec![-10.0, -20.0, -30.0]), 0);\n assert_eq!(double_the_difference(vec![-1.0, -2.0, 8.0]), 0);\n assert_eq!(double_the_difference(vec![0.2, 3.0, 5.0]), 34);\n\n let mut lst = vec![];\n let mut odd_sum = 0;\n for i in -99..100 {\n lst.push(i as f32);\n if i > 0 && i % 2 == 1 {\n odd_sum += i * i;\n }\n }\n assert_eq!(double_the_difference(lst), odd_sum);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut sum: i64 = 0;\n for i in 0..lst.len() {\n if (lst[i] - lst[i].round()).abs() < 1e-4 {\n if lst[i] > 0.0 {\n sum += (lst[i].round() as i64) * (lst[i].round() as i64);\n }\n }\n }\n return sum;\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "double_the_difference"} {"task_id": "Rust/152", "prompt": "\n/*\nI think we all remember that feeling when the result of some long-awaited\n event is finally known. The feelings and thoughts you have at that moment are\n definitely worth noting down and comparing.\n Your task is to determine if a person correctly guessed the results of a number of matches.\n You are given two arrays of scores and guesses of equal length, where each index shows a match. \n Return an array of the same length denoting how far off each guess was. If they have guessed correctly,\n the value is 0, and if not, the value is the absolute difference between the guess and the score.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn compare(game: Vec, guess: Vec) -> Vec {\n\n", "canonical_solution": "\n let mut out: Vec = Vec::new();\n for i in 0..game.len() {\n out.push(i32::abs(game[i] - guess[i]));\n }\n return out;\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_compare() {\n assert_eq!(\n compare(vec![1, 2, 3, 4, 5, 1], vec![1, 2, 3, 4, 2, -2]),\n vec![0, 0, 0, 0, 3, 3]\n );\n assert_eq!(\n compare(vec![0, 5, 0, 0, 0, 4], vec![4, 1, 1, 0, 0, -2]),\n vec![4, 4, 1, 0, 0, 6]\n );\n assert_eq!(\n compare(vec![1, 2, 3, 4, 5, 1], vec![1, 2, 3, 4, 2, -2]),\n vec![0, 0, 0, 0, 3, 3]\n );\n assert_eq!(\n compare(vec![0, 0, 0, 0, 0, 0], vec![0, 0, 0, 0, 0, 0]),\n vec![0, 0, 0, 0, 0, 0]\n );\n assert_eq!(compare(vec![1, 2, 3], vec![-1, -2, -3]), vec![2, 4, 6]);\n assert_eq!(\n compare(vec![1, 2, 3, 5], vec![-1, 2, 3, 4]),\n vec![2, 0, 0, 1]\n );\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut out: Vec = Vec::new();\n for i in 0..game.len() {\n out.push(i32::abs(game[i] - guess[i]) + i32::abs(guess[i] - game[i]));\n }\n return out;\n}\n", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "compare"} -{"task_id": "Rust/153", "prompt": "\n/*\nYou will be given the name of a class (a string) and a list of extensions.\n The extensions are to be used to load additional classes to the class. The\n strength of the extension is as follows: Let CAP be the number of the uppercase\n letters in the extension's name, and let SM be the number of lowercase letters \n in the extension's name, the strength is given by the fraction CAP - SM. \n You should find the strongest extension and return a string in this \n format: ClassName.StrongestExtensionName.\n If there are two or more extensions with the same strength, you should\n choose the one that comes first in the list.\n For example, if you are given \"Slices\" as the class and a list of the\n extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should\n return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension \n (its strength is -1).\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn strongest_extension(class_name: &str, extensions: Vec<&str>) -> String { \n\n", "canonical_solution": "\n let mut strongest = \"\";\n let mut max = -1000;\n for i in 0..extensions.len() {\n let mut strength = 0;\n for j in 0..extensions[i].len() {\n let chr = extensions[i].chars().nth(j).unwrap();\n if chr >= 'A' && chr <= 'Z' {\n strength += 1;\n }\n if chr >= 'a' && chr <= 'z' {\n strength -= 1;\n }\n }\n if strength > max {\n max = strength;\n strongest = extensions[i];\n }\n }\n format!(\"{}.{}\", class_name, strongest)\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_strongest_extension() {\n assert_eq!(\n strongest_extension(\"Watashi\", vec![\"tEN\", \"niNE\", \"eIGHt8OKe\"]),\n \"Watashi.eIGHt8OKe\"\n );\n assert_eq!(\n strongest_extension(\"Boku123\", vec![\"nani\", \"NazeDa\", \"YEs.WeCaNe\", \"32145tggg\"]),\n \"Boku123.YEs.WeCaNe\"\n );\n assert_eq!(\n strongest_extension(\n \"__YESIMHERE\",\n vec![\"t\", \"eMptY\", \"(nothing\", \"zeR00\", \"NuLl__\", \"123NoooneB321\"]\n ),\n \"__YESIMHERE.NuLl__\"\n );\n assert_eq!(\n strongest_extension(\"K\", vec![\"Ta\", \"TAR\", \"t234An\", \"cosSo\"]),\n \"K.TAR\"\n );\n assert_eq!(\n strongest_extension(\"__HAHA\", vec![\"Tab\", \"123\", \"781345\", \"-_-\"]),\n \"__HAHA.123\"\n );\n assert_eq!(\n strongest_extension(\n \"YameRore\",\n vec![\"HhAas\", \"okIWILL123\", \"WorkOut\", \"Fails\", \"-_-\"]\n ),\n \"YameRore.okIWILL123\"\n );\n assert_eq!(\n strongest_extension(\"finNNalLLly\", vec![\"Die\", \"NowW\", \"Wow\", \"WoW\"]),\n \"finNNalLLly.WoW\"\n );\n assert_eq!(strongest_extension(\"_\", vec![\"Bb\", \"91245\"]), \"_.Bb\");\n assert_eq!(strongest_extension(\"Sp\", vec![\"671235\", \"Bb\"]), \"Sp.671235\");\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut strongest = \"\";\n let mut max = -1000;\n for i in 0..extensions.len() {\n let mut strength = 0;\n for j in 0..extensions[i].len() {\n let chr = extensions[i].chars().nth(j).unwrap();\n if chr >= 'A' && chr <= 'Z' {\n strength += 1;\n }\n if chr >= 'a' && chr <= 'z' {\n strength -= 1;\n }\n }\n if strength > max {\n max = strength;\n strongest = extensions[i];\n }\n }\n format!(\"{}{}\", class_name, strongest)\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "Strongest_Extension"} +{"task_id": "Rust/153", "prompt": "\n/*\nYou will be given the name of a class (a string) and a list of extensions.\n The extensions are to be used to load additional classes to the class. The\n strength of the extension is as follows: Let CAP be the number of the uppercase\n letters in the extension's name, and let SM be the number of lowercase letters \n in the extension's name, the strength is given by the fraction CAP - SM. \n You should find the strongest extension and return a string in this \n format: ClassName.StrongestExtensionName.\n If there are two or more extensions with the same strength, you should\n choose the one that comes first in the list.\n For example, if you are given \"Slices\" as the class and a list of the\n extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should\n return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension \n (its strength is -1).\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn strongest_extension(class_name: &str, extensions: Vec<&str>) -> String { \n\n", "canonical_solution": "\n let mut strongest = \"\";\n let mut max = -1000;\n for i in 0..extensions.len() {\n let mut strength = 0;\n for j in 0..extensions[i].len() {\n let chr = extensions[i].chars().nth(j).unwrap();\n if chr >= 'A' && chr <= 'Z' {\n strength += 1;\n }\n if chr >= 'a' && chr <= 'z' {\n strength -= 1;\n }\n }\n if strength > max {\n max = strength;\n strongest = extensions[i];\n }\n }\n format!(\"{}.{}\", class_name, strongest)\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_strongest_extension() {\n assert_eq!(\n strongest_extension(\"Watashi\", vec![\"tEN\", \"niNE\", \"eIGHt8OKe\"]),\n \"Watashi.eIGHt8OKe\"\n );\n assert_eq!(\n strongest_extension(\"Boku123\", vec![\"nani\", \"NazeDa\", \"YEs.WeCaNe\", \"32145tggg\"]),\n \"Boku123.YEs.WeCaNe\"\n );\n assert_eq!(\n strongest_extension(\n \"__YESIMHERE\",\n vec![\"t\", \"eMptY\", \"(nothing\", \"zeR00\", \"NuLl__\", \"123NoooneB321\"]\n ),\n \"__YESIMHERE.NuLl__\"\n );\n assert_eq!(\n strongest_extension(\"K\", vec![\"Ta\", \"TAR\", \"t234An\", \"cosSo\"]),\n \"K.TAR\"\n );\n assert_eq!(\n strongest_extension(\"__HAHA\", vec![\"Tab\", \"123\", \"781345\", \"-_-\"]),\n \"__HAHA.123\"\n );\n assert_eq!(\n strongest_extension(\n \"YameRore\",\n vec![\"HhAas\", \"okIWILL123\", \"WorkOut\", \"Fails\", \"-_-\"]\n ),\n \"YameRore.okIWILL123\"\n );\n assert_eq!(\n strongest_extension(\"finNNalLLly\", vec![\"Die\", \"NowW\", \"Wow\", \"WoW\"]),\n \"finNNalLLly.WoW\"\n );\n assert_eq!(strongest_extension(\"_\", vec![\"Bb\", \"91245\"]), \"_.Bb\");\n assert_eq!(strongest_extension(\"Sp\", vec![\"671235\", \"Bb\"]), \"Sp.671235\");\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut strongest = \"\";\n let mut max = -1000;\n for i in 0..extensions.len() {\n let mut strength = 0;\n for j in 0..extensions[i].len() {\n let chr = extensions[i].chars().nth(j).unwrap();\n if chr >= 'A' && chr <= 'Z' {\n strength += 1;\n }\n if chr >= 'a' && chr <= 'z' {\n strength -= 1;\n }\n }\n if strength > max {\n max = strength;\n strongest = extensions[i];\n }\n }\n format!(\"{}{}\", class_name, strongest)\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "strongest_extension"} {"task_id": "Rust/154", "prompt": "\n/*\nYou are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn cycpattern_check(a: &str, b: &str) -> bool {\n\n", "canonical_solution": "\n for i in 0..b.len() {\n let rotate = format!(\"{}{}\", &b[i..], &b[..i]);\n if a.contains(&rotate) {\n return true;\n }\n }\n false\n}\n\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_cycpattern_check() {\n assert_eq!(cycpattern_check(\"xyzw\", \"xyw\"), false);\n assert_eq!(cycpattern_check(\"yello\", \"ell\"), true);\n assert_eq!(cycpattern_check(\"whattup\", \"ptut\"), false);\n assert_eq!(cycpattern_check(\"efef\", \"fee\"), true);\n assert_eq!(cycpattern_check(\"abab\", \"aabb\"), false);\n assert_eq!(cycpattern_check(\"winemtt\", \"tinem\"), true);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n for i in 1..b.len() {\n let rotate = format!(\"{}{}\", &b[i..], &b[..i]);\n if a.contains(&rotate) {\n return true;\n }\n }\n false\n}\n\n", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "cycpattern_check"} {"task_id": "Rust/155", "prompt": "\n/*\nGiven an integer. return a tuple that has the number of even and odd digits respectively.\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn even_odd_count(num: i32) -> Vec {\n\n", "canonical_solution": "\n let w = num.abs().to_string();\n let mut n1 = 0;\n let mut n2 = 0;\n for i in 0..w.len() {\n if w.chars().nth(i).unwrap().to_digit(10).unwrap() % 2 == 1 {\n n1 += 1;\n } else {\n n2 += 1;\n }\n }\n vec![n2, n1]\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_even_odd() {\n assert_eq!(even_odd_count(7), vec![0, 1]);\n assert_eq!(even_odd_count(-78), vec![1, 1]);\n assert_eq!(even_odd_count(3452), vec![2, 2]);\n assert_eq!(even_odd_count(346211), vec![3, 3]);\n assert_eq!(even_odd_count(-345821), vec![3, 3]);\n assert_eq!(even_odd_count(-2), vec![1, 0]);\n assert_eq!(even_odd_count(-45347), vec![2, 3]);\n assert_eq!(even_odd_count(0), vec![1, 0]);\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let w = num.abs().to_string();\n let mut n1 = 0;\n let mut n2 = 0;\n for i in 0..w.len() {\n if w.chars().nth(i).unwrap().to_digit(10).unwrap() % 2 == 1 {\n n1 += 1;\n }\n }\n vec![n2, n1]\n}\n", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "even_odd_count"} {"task_id": "Rust/156", "prompt": "\n/*\n\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n \n*/\n", "declaration": "\nuse std::{slice::Iter, cmp::{max, self}, mem::replace, collections::{HashSet, HashMap}, ops::Index, ascii::AsciiExt};\nuse rand::Rng;\nuse regex::Regex;\nuse md5;\nuse std::any::{Any, TypeId};\n\nfn int_to_mini_romank(number: i32) -> String {\n\n", "canonical_solution": "\n let mut current = String::new();\n let mut number = number;\n let rep = vec![\n \"m\", \"cm\", \"d\", \"cd\", \"c\", \"xc\", \"l\", \"xl\", \"x\", \"ix\", \"v\", \"iv\", \"i\",\n ];\n let num = vec![1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1];\n let mut pos = 0;\n while number > 0 {\n while number >= num[pos] {\n current.push_str(rep[pos]);\n number -= num[pos];\n }\n if number > 0 {\n pos += 1;\n }\n }\n current\n}\n", "test": "\n#[cfg(test)]\nmod tests {\n use super::*;\n\n #[test]\n fn test_int_to_mini_romank() {\n assert_eq!(int_to_mini_romank(19), \"xix\");\n assert_eq!(int_to_mini_romank(152), \"clii\");\n assert_eq!(int_to_mini_romank(251), \"ccli\");\n assert_eq!(int_to_mini_romank(426), \"cdxxvi\");\n assert_eq!(int_to_mini_romank(500), \"d\");\n assert_eq!(int_to_mini_romank(1), \"i\");\n assert_eq!(int_to_mini_romank(4), \"iv\");\n assert_eq!(int_to_mini_romank(43), \"xliii\");\n assert_eq!(int_to_mini_romank(90), \"xc\");\n assert_eq!(int_to_mini_romank(94), \"xciv\");\n assert_eq!(int_to_mini_romank(532), \"dxxxii\");\n assert_eq!(int_to_mini_romank(900), \"cm\");\n assert_eq!(int_to_mini_romank(994), \"cmxciv\");\n assert_eq!(int_to_mini_romank(1000), \"m\");\n }\n\n}\n", "example_test": "None", "buggy_solution": "\n let mut current = String::new();\n let mut number = number;\n let rep = vec![\n \"m\", \"cm\", \"d\", \"cd\", \"c\", \"xc\", \"l\", \"xl\", \"x\", \"ix\", \"v\", \"iv\", \"i\",\n ];\n let num = vec![1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1];\n let mut pos = 0;\n while number > 0 {\n while number >= num[pos] {\n current.push_str(rep[pos]);\n }\n if number > 0 {\n pos += 1;\n }\n }\n current\n}\n", "bug_type": "missing logic", "failure_symptoms": "infinite loop", "entry_point": "int_to_mini_roman"}