diff --git "a/data/java/data/humanevalbugs.jsonl" "b/data/java/data/humanevalbugs.jsonl" --- "a/data/java/data/humanevalbugs.jsonl" +++ "b/data/java/data/humanevalbugs.jsonl" @@ -20,7 +20,7 @@ {"task_id": "Java/19", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Input is a space-delimited string of numberals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest\n >>> sortNumbers(\"three one five\")\n \"one three five\"\n */\n public String sortNumbers(String numbers) {\n", "canonical_solution": " String[] nums = numbers.split(\" \");\n List num = new ArrayList<>();\n for (String string : nums) {\n switch (string) {\n case \"zero\" -> num.add(0);\n case \"one\" -> num.add(1);\n case \"two\" -> num.add(2);\n case \"three\" -> num.add(3);\n case \"four\" -> num.add(4);\n case \"five\" -> num.add(5);\n case \"six\" -> num.add(6);\n case \"seven\" -> num.add(7);\n case \"eight\" -> num.add(8);\n case \"nine\" -> num.add(9);\n }\n }\n Collections.sort(num);\n List result = new ArrayList<>();\n for (int m : num) {\n switch (m) {\n case 0 -> result.add(\"zero\");\n case 1 -> result.add(\"one\");\n case 2 -> result.add(\"two\");\n case 3 -> result.add(\"three\");\n case 4 -> result.add(\"four\");\n case 5 -> result.add(\"five\");\n case 6 -> result.add(\"six\");\n case 7 -> result.add(\"seven\");\n case 8 -> result.add(\"eight\");\n case 9 -> result.add(\"nine\");\n }\n }\n return String.join(\" \", result);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortNumbers(\"\").equals(\"\"),\n s.sortNumbers(\"three\").equals(\"three\"),\n s.sortNumbers(\"three five nine\").equals(\"three five nine\"),\n s.sortNumbers(\"five zero four seven nine eight\").equals(\"zero four five seven eight nine\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Input is a space-delimited string of numberals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n Return the string with numbers sorted from smallest to largest\n >>> sortNumbers(\"three one five\")\n \"one three five\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String sortNumbers(String numbers) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortNumbers(\"three one five\").equals(\"one three five\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String[] nums = numbers.split(\" \");\n List num = new ArrayList<>();\n for (String string : nums) {\n switch (string) {\n case \"zero\" -> num.add(0);\n case \"one\" -> num.add(1);\n case \"two\" -> num.add(2);\n case \"three\" -> num.add(3);\n case \"four\" -> num.add(4);\n case \"five\" -> num.add(5);\n case \"six\" -> num.add(6);\n case \"seven\" -> num.add(7);\n case \"eight\" -> num.add(8);\n case \"nine\" -> num.add(9);\n }\n }\n List result = new ArrayList<>();\n for (int m : num) {\n switch (m) {\n case 0 -> result.add(\"zero\");\n case 1 -> result.add(\"one\");\n case 2 -> result.add(\"two\");\n case 3 -> result.add(\"three\");\n case 4 -> result.add(\"four\");\n case 5 -> result.add(\"five\");\n case 6 -> result.add(\"six\");\n case 7 -> result.add(\"seven\");\n case 8 -> result.add(\"eight\");\n case 9 -> result.add(\"nine\");\n }\n }\n return String.join(\" \", result);\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "sortNumbers"} {"task_id": "Java/20", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> findClosestElements(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0, 2.2))\n [2.0, 2.2]\n >>> findClosestElements(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0, 2.0))\n [2.0, 2.0]\n */\n public List findClosestElements(List numbers) {\n", "canonical_solution": " List closest_pair = new ArrayList<>();\n closest_pair.add(numbers.get(0));\n closest_pair.add(numbers.get(1));\n double distance = Math.abs(numbers.get(1) - numbers.get(0));\n for (int i = 0; i < numbers.size(); i++) {\n for (int j = i + 1; j < numbers.size(); j++) {\n if (Math.abs(numbers.get(i) - numbers.get(j)) < distance) {\n closest_pair.clear();\n closest_pair.add(numbers.get(i));\n closest_pair.add(numbers.get(j));\n distance = Math.abs(numbers.get(i) - numbers.get(j));\n }\n }\n }\n Collections.sort(closest_pair);\n return closest_pair;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.findClosestElements(new ArrayList<>(Arrays.asList(1.0, 2.0, 3.9, 4.0, 5.0, 2.2))).equals(Arrays.asList(3.9, 4.0)),\n s.findClosestElements(new ArrayList<>(Arrays.asList(1.0, 2.0, 5.9, 4.0, 5.0))).equals(Arrays.asList(5.0, 5.9)),\n s.findClosestElements(new ArrayList<>(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0, 2.2))).equals(Arrays.asList(2.0, 2.2)),\n s.findClosestElements(new ArrayList<>(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0, 2.0))).equals(Arrays.asList(2.0, 2.0)),\n s.findClosestElements(new ArrayList<>(Arrays.asList(1.1, 2.2, 3.1, 4.1, 5.1))).equals(Arrays.asList(2.2, 3.1))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> findClosestElements(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0, 2.2))\n [2.0, 2.2]\n >>> findClosestElements(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0, 2.0))\n [2.0, 2.0]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List findClosestElements(List numbers) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.findClosestElements(new ArrayList<>(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0, 2.2))).equals(Arrays.asList(2.0, 2.2)),\n s.findClosestElements(new ArrayList<>(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0, 2.0))).equals(Arrays.asList(2.0, 2.0))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List closest_pair = new ArrayList<>();\n closest_pair.add(numbers.get(0));\n closest_pair.add(numbers.get(1));\n double distance = Math.abs(numbers.get(1) - numbers.get(0));\n for (int i = 0; i < numbers.size(); i++) {\n for (int j = i + 1; j < numbers.size(); j++) {\n if (Math.abs(numbers.get(i) - numbers.get(j)) > distance) {\n closest_pair.clear();\n closest_pair.add(numbers.get(i));\n closest_pair.add(numbers.get(j));\n distance = Math.abs(numbers.get(i) - numbers.get(j));\n }\n }\n }\n Collections.sort(closest_pair);\n return closest_pair;\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "findClosestElements"} {"task_id": "Java/21", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1\n >>> rescaleToUnit(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0))\n [0.0, 0.25, 0.5, 0.75, 1.0]\n */\n public List rescaleToUnit(List numbers) {\n", "canonical_solution": " double min_number = Collections.min(numbers);\n double max_number = Collections.max(numbers);\n List result = new ArrayList<>();\n for (double x : numbers) {\n result.add((x - min_number) / (max_number - min_number));\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rescaleToUnit(new ArrayList<>(Arrays.asList(2.0, 49.9))).equals(Arrays.asList(0.0, 1.0)),\n s.rescaleToUnit(new ArrayList<>(Arrays.asList(100.0, 49.9))).equals(Arrays.asList(1.0, 0.0)),\n s.rescaleToUnit(new ArrayList<>(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0))).equals(Arrays.asList(0.0, 0.25, 0.5, 0.75, 1.0)),\n s.rescaleToUnit(new ArrayList<>(Arrays.asList(2.0, 1.0, 5.0, 3.0, 4.0))).equals(Arrays.asList(0.25, 0.0, 1.0, 0.5, 0.75)),\n s.rescaleToUnit(new ArrayList<>(Arrays.asList(12.0, 11.0, 15.0, 13.0, 14.0))).equals(Arrays.asList(0.25, 0.0, 1.0, 0.5, 0.75))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will become 1\n >>> rescaleToUnit(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0))\n [0.0, 0.25, 0.5, 0.75, 1.0]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List rescaleToUnit(List numbers) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.rescaleToUnit(new ArrayList<>(Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0))).equals(Arrays.asList(0.0, 0.25, 0.5, 0.75, 1.0))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " double min_number = Collections.min(numbers);\n double max_number = Collections.max(numbers);\n List result = new ArrayList<>();\n for (double x : numbers) {\n result.add((x - min_number) / (max_number + min_number));\n }\n return result;\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "rescaleToUnit"} -{"task_id": "Java/22", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Filter given list of any values only for integers\n >>> filter_integers(Arrays.asList('a', 3.14, 5))\n [5]\n >>> filter_integers(Arrays.asList(1, 2, 3, \"abc\", Map.of(), List.of()))\n [1, 2, 3]\n */\n public List filterIntergers(List values) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (Object x : values) {\n if (x instanceof Integer) {\n result.add((Integer) x);\n }\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.filterIntergers(new ArrayList<>(List.of())).equals(List.of()),\n s.filterIntergers(new ArrayList<>(Arrays.asList(4, Map.of(), List.of(), 23.2, 9, \"adasd\"))).equals(Arrays.asList(4, 9)),\n s.filterIntergers(new ArrayList<>(Arrays.asList(3, 'c', 3, 3, 'a', 'b'))).equals(Arrays.asList(3, 3, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Filter given list of any values only for integers\n >>> filter_integers(Arrays.asList('a', 3.14, 5))\n [5]\n >>> filter_integers(Arrays.asList(1, 2, 3, \"abc\", Map.of(), List.of()))\n [1, 2, 3]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List filterIntergers(List values) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.filterIntergers(new ArrayList<>(Arrays.asList('a', 3.14, 5))).equals(Arrays.asList(5)),\n s.filterIntergers(new ArrayList<>(Arrays.asList(1,2,3,\"abc\", Map.of(), List.of()))).equals(Arrays.asList(1,2,3)) \n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (Object x : values) {\n if (x instanceof Integer) {\n values.add((Integer) x);\n }\n }\n return result;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "filterIntegers"} +{"task_id": "Java/22", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Filter given list of any values only for integers\n >>> filter_integers(Arrays.asList('a', 3.14, 5))\n [5]\n >>> filter_integers(Arrays.asList(1, 2, 3, \"abc\", Map.of(), List.of()))\n [1, 2, 3]\n */\n public List filterIntegers(List values) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (Object x : values) {\n if (x instanceof Integer) {\n result.add((Integer) x);\n }\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.filterIntegers(new ArrayList<>(List.of())).equals(List.of()),\n s.filterIntegers(new ArrayList<>(Arrays.asList(4, Map.of(), List.of(), 23.2, 9, \"adasd\"))).equals(Arrays.asList(4, 9)),\n s.filterIntegers(new ArrayList<>(Arrays.asList(3, 'c', 3, 3, 'a', 'b'))).equals(Arrays.asList(3, 3, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Filter given list of any values only for integers\n >>> filter_integers(Arrays.asList('a', 3.14, 5))\n [5]\n >>> filter_integers(Arrays.asList(1, 2, 3, \"abc\", Map.of(), List.of()))\n [1, 2, 3]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List filterIntegers(List values) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.filterIntegers(new ArrayList<>(Arrays.asList('a', 3.14, 5))).equals(Arrays.asList(5)),\n s.filterIntegers(new ArrayList<>(Arrays.asList(1,2,3,\"abc\", Map.of(), List.of()))).equals(Arrays.asList(1,2,3)) \n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (Object x : values) {\n if (x instanceof Integer) {\n values.add((Integer) x);\n }\n }\n return result;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "filterIntegers"} {"task_id": "Java/23", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return length of given string\n >>> strlen(\"\")\n 0\n >>> strlen(\"abc\")\n 3\n */\n public int strlen(String string) {\n", "canonical_solution": " return string.length();\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.strlen(\"\") == 0,\n s.strlen(\"x\") == 1,\n s.strlen(\"asdasnakj\") == 9\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return length of given string\n >>> strlen(\"\")\n 0\n >>> strlen(\"abc\")\n 3", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int strlen(String string) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.strlen(\"\") == 0,\n s.strlen(\"abc\") == 3\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " return string.length() - 1;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "strlen"} {"task_id": "Java/24", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largestDivisor(15)\n 5\n */\n public int largestDivisor(int n) {\n", "canonical_solution": " for (int i = n - 1; i > 0; i--) {\n if (n % i == 0) {\n return i;\n }\n }\n return 1;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.largestDivisor(3) == 1,\n s.largestDivisor(7) == 1,\n s.largestDivisor(10) == 5,\n s.largestDivisor(100) == 50,\n s.largestDivisor(49) == 7\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largestDivisor(15)\n 5", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int largestDivisor(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.largestDivisor(15) == 5\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " for (int i = n - 1; i > 0; i--) {\n if (n - i == 0) {\n return i;\n }\n }\n return 1;\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "largestDivisor"} {"task_id": "Java/25", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n */\n public List factorize(int n) {\n", "canonical_solution": " List fact = new ArrayList<>();\n int i = 2;\n while (n > 1) {\n if (n % i == 0) {\n fact.add(i);\n n /= i;\n } else {\n i++;\n }\n }\n return fact;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.factorize(2).equals(List.of(2)),\n s.factorize(4).equals(Arrays.asList(2, 2)),\n s.factorize(8).equals(Arrays.asList(2, 2, 2)),\n s.factorize(3 * 19).equals(Arrays.asList(3, 19)),\n s.factorize(3 * 19 * 3 * 19).equals(Arrays.asList(3, 3, 19, 19)),\n s.factorize(3 * 19 * 3 * 19 * 3 * 19).equals(Arrays.asList(3, 3, 3, 19, 19, 19)),\n s.factorize(3 * 19 * 19 * 19).equals(Arrays.asList(3, 19, 19, 19)),\n s.factorize(3 * 2 * 3).equals(Arrays.asList(2, 3, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.\n Input number should be equal to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List factorize(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.factorize(8).equals(Arrays.asList(2, 2, 2)),\n s.factorize(25).equals(Arrays.asList(5,5)),\n s.factorize(70).equals(Arrays.asList(2,5,7))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List fact = new ArrayList<>();\n int i = 0;\n while (n > 1) {\n if (n % i == 0) {\n fact.add(i);\n n /= i;\n } else {\n i++;\n }\n }\n return fact;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "factorize"} @@ -64,7 +64,7 @@ {"task_id": "Java/63", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n Please write a function to efficiently compute the n-th element of the fibfib number sequence.\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n */\n public int fibfib(int n) {\n", "canonical_solution": " if (n == 0) {\n return 0;\n }\n if (n == 1) {\n return 0;\n }\n if (n == 2) {\n return 1;\n }\n return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.fibfib(2) == 1,\n s.fibfib(1) == 0,\n s.fibfib(5) == 4,\n s.fibfib(8) == 24,\n s.fibfib(10) == 81,\n s.fibfib(12) == 274,\n s.fibfib(14) == 927\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n Please write a function to efficiently compute the n-th element of the fibfib number sequence.\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int fibfib(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.fibfib(1) == 0,\n s.fibfib(5) == 4,\n s.fibfib(8) == 24\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (n == 0) {\n return 0;\n }\n if (n == 1) {\n return 1;\n }\n if (n == 2) {\n return 2;\n }\n return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3);\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "fibfib"} {"task_id": "Java/64", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function vowelsCount which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowelsCount(\"abcde\")\n 2\n >>> vowelsCount(\"ACEDY\")\n 3\n */\n public int vowelsCount(String s) {\n", "canonical_solution": " String vowels = \"aeiouAEIOU\";\n int n_vowels = 0;\n for (char c : s.toCharArray()) {\n if (vowels.indexOf(c) != -1) {\n n_vowels += 1;\n }\n }\n if (s.charAt(s.length() - 1) == 'y' || s.charAt(s.length() - 1) == 'Y') {\n n_vowels += 1;\n }\n return n_vowels;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.vowelsCount(\"abcde\") == 2,\n s.vowelsCount(\"Alone\") == 3,\n s.vowelsCount(\"key\") == 2,\n s.vowelsCount(\"bye\") == 1,\n s.vowelsCount(\"keY\") == 2,\n s.vowelsCount(\"bYe\") == 1,\n s.vowelsCount(\"ACEDY\") == 3\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function vowelsCount which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowelsCount(\"abcde\")\n 2\n >>> vowelsCount(\"ACEDY\")\n 3", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int vowelsCount(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.vowelsCount(\"abcde\") == 2,\n s.vowelsCount(\"ACEDY\") == 3\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String vowels = \"aeiouyAEIOUY\";\n int n_vowels = 0;\n for (char c : s.toCharArray()) {\n if (vowels.indexOf(c) != -1) {\n n_vowels += 1;\n }\n }\n return n_vowels;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "vowelsCount"} {"task_id": "Java/65", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n >>> circularShift(12, 1)\n \"21\"\n >>> circularShift(12, 2)\n \"12\"\n */\n public String circularShift(int x, int shift) {\n", "canonical_solution": " String s = String.valueOf(x);\n if (shift > s.length()) {\n return new StringBuilder(s).reverse().toString();\n } else {\n return s.substring(s.length() - shift) + s.substring(0, s.length() - shift);\n }\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.circularShift(100, 2).equals(\"001\"),\n s.circularShift(12, 2).equals(\"12\"),\n s.circularShift(97, 8).equals(\"79\"),\n s.circularShift(12, 1).equals(\"21\"),\n s.circularShift(11, 101).equals(\"11\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n >>> circularShift(12, 1)\n \"21\"\n >>> circularShift(12, 2)\n \"12\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String circularShift(int x, int shift) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.circularShift(12, 2).equals(\"12\"),\n s.circularShift(12, 1).equals(\"21\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String s = String.valueOf(x);\n if (shift > s.length()) {\n return new StringBuilder(s).reverse().toString();\n } else {\n return s.substring(0, s.length() - shift) + s.substring(s.length() - shift);\n }\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "circularShift"} -{"task_id": "Java/66", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n */\n public int digitSum(String s) {\n", "canonical_solution": " int sum = 0;\n for (char c : s.toCharArray()) {\n if (Character.isUpperCase(c)) {\n sum += c;\n }\n }\n return sum;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.digitSum(\"\") == 0,\n s.digitSum(\"abAB\") == 131,\n s.digitSum(\"abcCd\") == 67,\n s.digitSum(\"helloE\") == 69,\n s.digitSum(\"woArBld\") == 131,\n s.digitSum(\"aAaaaXa\") == 153,\n s.digitSum(\" How are yOu?\") == 151,\n s.digitSum(\"You arE Very Smart\") == 327\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int digitSum(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.digitSum(\"\") == 0,\n s.digitSum(\"abAB\") == 131,\n s.digitSum(\"abcCd\") == 67,\n s.digitSum(\"helloE\") == 69,\n s.digitSum(\"woArBld\") == 131,\n s.digitSum(\"aAaaaXa\") == 153\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int sum = 0;\n for (char c : s.toCharArray()) {\n if (Character.isLowerCase(c)) {\n sum += c;\n }\n }\n return sum;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "digitsum"} +{"task_id": "Java/66", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n */\n public int digitSum(String s) {\n", "canonical_solution": " int sum = 0;\n for (char c : s.toCharArray()) {\n if (Character.isUpperCase(c)) {\n sum += c;\n }\n }\n return sum;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.digitSum(\"\") == 0,\n s.digitSum(\"abAB\") == 131,\n s.digitSum(\"abcCd\") == 67,\n s.digitSum(\"helloE\") == 69,\n s.digitSum(\"woArBld\") == 131,\n s.digitSum(\"aAaaaXa\") == 153,\n s.digitSum(\" How are yOu?\") == 151,\n s.digitSum(\"You arE Very Smart\") == 327\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function that takes a string as input and returns the sum of the upper characters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int digitSum(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.digitSum(\"\") == 0,\n s.digitSum(\"abAB\") == 131,\n s.digitSum(\"abcCd\") == 67,\n s.digitSum(\"helloE\") == 69,\n s.digitSum(\"woArBld\") == 131,\n s.digitSum(\"aAaaaXa\") == 153\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int sum = 0;\n for (char c : s.toCharArray()) {\n if (Character.isLowerCase(c)) {\n sum += c;\n }\n }\n return sum;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "digitSum"} {"task_id": "Java/67", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n In this task, you will be given a string that represents a number of apples and oranges\n that are distributed in a basket of fruit this basket contains\n apples, oranges, and mango fruits. Given the string that represents the total number of\n the oranges and apples and an integer that represent the total number of the fruits\n in the basket return the number of the mango fruits in the basket.\n for examble:\n fruitDistribution(\"5 apples and 6 oranges\", 19) ->19 - 5 - 6 = 8\n fruitDistribution(\"0 apples and 1 oranges\",3) -> 3 - 0 - 1 = 2\n fruitDistribution(\"2 apples and 3 oranges\", 100) -> 100 - 2 - 3 = 95\n fruitDistribution(\"100 apples and 1 oranges\",120) -> 120 - 100 - 1 = 19\n */\n public int fruitDistribution(String s, int n) {\n", "canonical_solution": " List lis = new ArrayList<>();\n for (String i : s.split(\" \")) {\n try {\n lis.add(Integer.parseInt(i));\n } catch (NumberFormatException ignored) {\n\n }\n }\n return n - lis.stream().mapToInt(Integer::intValue).sum();\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.fruitDistribution(\"5 apples and 6 oranges\",19) == 8,\n s.fruitDistribution(\"5 apples and 6 oranges\",21) == 10,\n s.fruitDistribution(\"0 apples and 1 oranges\",3) == 2,\n s.fruitDistribution(\"1 apples and 0 oranges\",3) == 2,\n s.fruitDistribution(\"2 apples and 3 oranges\",100) == 95,\n s.fruitDistribution(\"2 apples and 3 oranges\",5) == 0,\n s.fruitDistribution(\"1 apples and 100 oranges\",120) == 19\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " In this task, you will be given a string that represents a number of apples and oranges\n that are distributed in a basket of fruit this basket contains\n apples, oranges, and mango fruits. Given the string that represents the total number of\n the oranges and apples and an integer that represent the total number of the fruits\n in the basket return the number of the mango fruits in the basket.\n for examble:\n fruitDistribution(\"5 apples and 6 oranges\", 19) ->19 - 5 - 6 = 8\n fruitDistribution(\"0 apples and 1 oranges\",3) -> 3 - 0 - 1 = 2\n fruitDistribution(\"2 apples and 3 oranges\", 100) -> 100 - 2 - 3 = 95\n fruitDistribution(\"100 apples and 1 oranges\",120) -> 120 - 100 - 1 = 19", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int fruitDistribution(String s, int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.fruitDistribution(\"5 apples and 6 oranges\",19) == 8,\n s.fruitDistribution(\"0 apples and 1 oranges\",3) == 2,\n s.fruitDistribution(\"2 apples and 3 oranges\",100) == 95,\n s.fruitDistribution(\"1 apples and 100 oranges\",120) == 19\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List lis = new ArrayList<>();\n for (String i : s.split(\" \")) {\n try {\n lis.add(Integer.parseInt(i));\n } catch (NumberFormatException ignored) {\n\n }\n }\n return n - 1 - lis.stream().mapToInt(Integer::intValue).sum();\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "fruitDistribution"} {"task_id": "Java/68", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n \"Given an array representing a branch of a tree that has non-negative integer nodes\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found return the node that has smallest index.\n\n The plucked node should be returned in a list, [ smalest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 3:\n Input: []\n Output: []\n\n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n */\n public List pluck(List arr) {\n", "canonical_solution": " List result = new ArrayList<>();\n if (arr.size() == 0) {\n return result;\n }\n int min = Integer.MAX_VALUE;\n int minIndex = -1;\n for (int i = 0; i < arr.size(); i++) {\n if (arr.get(i) % 2 == 0) {\n if (arr.get(i) < min) {\n min = arr.get(i);\n minIndex = i;\n }\n }\n }\n if (minIndex != -1) {\n result.add(min);\n result.add(minIndex);\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.pluck(new ArrayList<>(Arrays.asList(4, 2, 3))).equals(Arrays.asList(2, 1)),\n s.pluck(new ArrayList<>(Arrays.asList(1, 2, 3))).equals(Arrays.asList(2, 1)),\n s.pluck(new ArrayList<>(List.of())).equals(List.of()),\n s.pluck(new ArrayList<>(Arrays.asList(5, 0, 3, 0, 4, 2))).equals(Arrays.asList(0, 1)),\n s.pluck(new ArrayList<>(Arrays.asList(1, 2, 3, 0, 5, 3))).equals(Arrays.asList(0, 3)),\n s.pluck(new ArrayList<>(Arrays.asList(5, 4, 8, 4, 8))).equals(Arrays.asList(4, 1)),\n s.pluck(new ArrayList<>(Arrays.asList(7, 6, 7, 1))).equals(Arrays.asList(6, 1)),\n s.pluck(new ArrayList<>(Arrays.asList(7, 9, 7, 1))).equals(List.of())\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " \"Given an array representing a branch of a tree that has non-negative integer nodes\n your task is to pluck one of the nodes and return it.\n The plucked node should be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found return the node that has smallest index.\n\n The plucked node should be returned in a list, [ smalest_value, its index ],\n If there are no even values or the given array is empty, return [].\n\n Example 1:\n Input: [4,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Explanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 3:\n Input: []\n Output: []\n\n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanation: 0 is the smallest value, but there are two zeros,\n so we will choose the first zero, which has the smallest index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List pluck(List arr) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.pluck(new ArrayList<>(Arrays.asList(4, 2, 3))).equals(Arrays.asList(2, 1)),\n s.pluck(new ArrayList<>(Arrays.asList(1, 2, 3))).equals(Arrays.asList(2, 1)),\n s.pluck(new ArrayList<>(List.of())).equals(List.of()),\n s.pluck(new ArrayList<>(Arrays.asList(5, 0, 3, 0, 4, 2))).equals(Arrays.asList(0, 1))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n if (arr.size() == 0) {\n return result;\n }\n int min = Integer.MAX_VALUE;\n int minIndex = -1;\n for (int i = 0; i < arr.size(); i++) {\n if (arr.get(i) % 2 == 0) {\n if (arr.get(i) < min) {\n min = arr.get(i);\n minIndex = i;\n }\n }\n }\n if (minIndex != -1) {\n result.add(minIndex);\n result.add(min);\n }\n return result;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "pluck"} {"task_id": "Java/69", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than\n zero, and has a frequency greater than or equal to the value of the integer itself.\n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n Examples:\n search(Arrays.asList(4, 1, 2, 2, 3, 1)) == 2\n search(Arrays.asList(1, 2, 2, 3, 3, 3, 4, 4, 4)) == 3\n search(Arrays.asList(5, 5, 4, 4, 4)) == -1\n */\n public int search(List lst) {\n", "canonical_solution": " int[] frq = new int[Collections.max(lst) + 1];\n for (int i : lst) {\n frq[i] += 1;\n }\n int ans = -1;\n for (int i = 1; i < frq.length; i++) {\n if (frq[i] >= i) {\n ans = i;\n }\n }\n return ans;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.search(new ArrayList<>(Arrays.asList(5, 5, 5, 5, 1))) == 1,\n s.search(new ArrayList<>(Arrays.asList(4, 1, 4, 1, 4, 4))) == 4,\n s.search(new ArrayList<>(Arrays.asList(3, 3))) == -1,\n s.search(new ArrayList<>(Arrays.asList(8, 8, 8, 8, 8, 8, 8, 8))) == 8,\n s.search(new ArrayList<>(Arrays.asList(2, 3, 3, 2, 2))) == 2,\n s.search(new ArrayList<>(Arrays.asList(2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1))) == 1,\n s.search(new ArrayList<>(Arrays.asList(3, 2, 8, 2))) == 2,\n s.search(new ArrayList<>(Arrays.asList(6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10))) == 1,\n s.search(new ArrayList<>(Arrays.asList(8, 8, 3, 6, 5, 6, 4))) == -1,\n s.search(new ArrayList<>(Arrays.asList(6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9))) == 1,\n s.search(new ArrayList<>(Arrays.asList(1, 9, 10, 1, 3))) == 1,\n s.search(new ArrayList<>(Arrays.asList(6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10))) == 5,\n s.search(new ArrayList<>(List.of(1))) == 1,\n s.search(new ArrayList<>(Arrays.asList(8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5))) == 4,\n s.search(new ArrayList<>(Arrays.asList(2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10))) == 2,\n s.search(new ArrayList<>(Arrays.asList(1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3))) == 1,\n s.search(new ArrayList<>(Arrays.asList(9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4))) == 4,\n s.search(new ArrayList<>(Arrays.asList(2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7))) == 4,\n s.search(new ArrayList<>(Arrays.asList(9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1))) == 2,\n s.search(new ArrayList<>(Arrays.asList(5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8))) == -1,\n s.search(new ArrayList<>(List.of(10))) == -1,\n s.search(new ArrayList<>(Arrays.asList(9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2))) == 2,\n s.search(new ArrayList<>(Arrays.asList(5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8))) == 1,\n s.search(new ArrayList<>(Arrays.asList(7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6))) == 1,\n s.search(new ArrayList<>(Arrays.asList(3, 10, 10, 9, 2))) == -1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given a non-empty list of positive integers. Return the greatest integer that is greater than\n zero, and has a frequency greater than or equal to the value of the integer itself.\n The frequency of an integer is the number of times it appears in the list.\n If no such a value exist, return -1.\n Examples:\n search(Arrays.asList(4, 1, 2, 2, 3, 1)) == 2\n search(Arrays.asList(1, 2, 2, 3, 3, 3, 4, 4, 4)) == 3\n search(Arrays.asList(5, 5, 4, 4, 4)) == -1", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int search(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.search(new ArrayList<>(Arrays.asList(4, 1, 2, 2, 3, 1))) == 2,\n s.search(new ArrayList<>(Arrays.asList(1, 2, 2, 3, 3, 3, 4, 4, 4))) == 3,\n s.search(new ArrayList<>(Arrays.asList(5, 5, 4, 4, 4))) == -1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int[] frq = new int[Collections.max(lst) + 1];\n for (int i : lst) {\n frq[i] += 1;\n }\n int ans = 0;\n for (int i = 1; i < frq.length; i++) {\n if (frq[i] >= i) {\n ans = i;\n }\n }\n return ans;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "search"} @@ -97,9 +97,9 @@ {"task_id": "Java/96", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Implement a function that takes an non-negative integer and returns an array of the first n\n integers that are prime numbers and less than n.\n for example:\n countUpTo(5) => [2,3]\n countUpTo(11) => [2,3,5,7]\n countUpTo(0) => []\n countUpTo(20) => [2,3,5,7,11,13,17,19]\n countUpTo(1) => []\n countUpTo(18) => [2,3,5,7,11,13,17]\n */\n public List countUpTo(int n) {\n", "canonical_solution": " List primes = new ArrayList<>();\n for (int i = 2; i < n; i++) {\n boolean is_prime = true;\n for (int j = 2; j < i; j++) {\n if (i % j == 0) {\n is_prime = false;\n break;\n }\n }\n if (is_prime) {\n primes.add(i);\n }\n }\n return primes;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpTo(5).equals(Arrays.asList(2, 3)),\n s.countUpTo(6).equals(Arrays.asList(2, 3, 5)),\n s.countUpTo(7).equals(Arrays.asList(2, 3, 5)),\n s.countUpTo(10).equals(Arrays.asList(2, 3, 5, 7)),\n s.countUpTo(0).equals(List.of()),\n s.countUpTo(22).equals(Arrays.asList(2, 3, 5, 7, 11, 13, 17, 19)),\n s.countUpTo(1).equals(List.of()),\n s.countUpTo(18).equals(Arrays.asList(2, 3, 5, 7, 11, 13, 17)),\n s.countUpTo(47).equals(Arrays.asList(2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43)),\n s.countUpTo(101).equals(Arrays.asList(2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Implement a function that takes an non-negative integer and returns an array of the first n\n integers that are prime numbers and less than n.\n for example:\n countUpTo(5) => [2,3]\n countUpTo(11) => [2,3,5,7]\n countUpTo(0) => []\n countUpTo(20) => [2,3,5,7,11,13,17,19]\n countUpTo(1) => []\n countUpTo(18) => [2,3,5,7,11,13,17]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List countUpTo(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpTo(5).equals(Arrays.asList(2, 3)),\n s.countUpTo(11).equals(Arrays.asList(2, 3, 5, 7)),\n s.countUpTo(0).equals(List.of()),\n s.countUpTo(20).equals(Arrays.asList(2, 3, 5, 7, 11, 13, 17, 19)),\n s.countUpTo(1).equals(List.of()),\n s.countUpTo(18).equals(Arrays.asList(2, 3, 5, 7, 11, 13, 17))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List primes = new ArrayList<>();\n for (int i = 2; i < n; i++) {\n boolean is_prime = true;\n for (int j = 2; j < i; j++) {\n if (j % i == 0) {\n is_prime = false;\n break;\n }\n }\n if (is_prime) {\n primes.add(i);\n }\n }\n return primes;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "countUpTo"} {"task_id": "Java/97", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Complete the function that takes two integers and returns\n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.\n */\n public int multiply(int a, int b) {\n", "canonical_solution": " return Math.abs(a % 10) * Math.abs(b % 10);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.multiply(148, 412) == 16,\n s.multiply(19, 28) == 72,\n s.multiply(2020, 1851) == 0,\n s.multiply(14,-15) == 20,\n s.multiply(76, 67) == 42,\n s.multiply(17, 27) == 49,\n s.multiply(0, 1) == 0,\n s.multiply(0, 0) == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Complete the function that takes two integers and returns\n the product of their unit digits.\n Assume the input is always valid.\n Examples:\n multiply(148, 412) should return 16.\n multiply(19, 28) should return 72.\n multiply(2020, 1851) should return 0.\n multiply(14,-15) should return 20.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int multiply(int a, int b) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.multiply(148, 412) == 16,\n s.multiply(19, 28) == 72,\n s.multiply(2020, 1851) == 0,\n s.multiply(14,-15) == 20\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " return Math.abs(a % 10) * Math.abs(b % 10) * a * b;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "multiply"} {"task_id": "Java/98", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n countUpper(\"aBCdEf\") returns 1\n countUpper(\"abcdefg\") returns 0\n countUpper(\"dBBE\") returns 0\n */ \n public int countUpper(String s) {\n", "canonical_solution": " int count = 0;\n for (int i = 0; i < s.length(); i += 2) {\n if (\"AEIOU\".indexOf(s.charAt(i)) != -1) {\n count += 1;\n }\n }\n return count;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"aBCdEf\") == 1,\n s.countUpper(\"abcdefg\") == 0,\n s.countUpper(\"dBBE\") == 0,\n s.countUpper(\"B\") == 0,\n s.countUpper(\"U\") == 1,\n s.countUpper(\"\") == 0,\n s.countUpper(\"EEEE\") == 2\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a string s, count the number of uppercase vowels in even indices.\n \n For example:\n countUpper(\"aBCdEf\") returns 1\n countUpper(\"abcdefg\") returns 0\n countUpper(\"dBBE\") returns 0", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int countUpper(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"aBCdEf\") == 1,\n s.countUpper(\"abcdefg\") == 0,\n s.countUpper(\"dBBE\") == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int count = 0;\n for (int i = 0; i < s.length(); i += 2) {\n if (\"AEIOU\".indexOf(s.charAt(i)) != -1) {\n count += 2;\n }\n }\n return count;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "countUpper"} -{"task_id": "Java/99", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n */\n public int countUpper(String value) {\n", "canonical_solution": " if (value.contains(\".\")) {\n while (value.charAt(value.length() - 1) == '0') {\n value = value.substring(0, value.length() - 1);\n }\n }\n double num = Double.parseDouble(value);\n int res = 0;\n if (value.substring(Math.max(value.length() - 2, 0)).equals(\".5\")) {\n if (num > 0) {\n res = (int) Math.ceil(num);\n } else {\n res = (int) Math.floor(num);\n }\n } else if(value.length() > 0) {\n res = (int) Math.round(num);\n }\n return res;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"10\") == 10,\n s.countUpper(\"14.5\") == 15,\n s.countUpper(\"-15.5\") == -16,\n s.countUpper(\"15.3\") == 15,\n s.countUpper(\"0\") == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int countUpper(String value) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"10\") == 10,\n s.countUpper(\"15.3\") == 15\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (value.contains(\".\")) {\n while (value.charAt(value.length() - 1) == '0') {\n value = value.substring(0, value.length() - 1);\n }\n }\n double num = Double.parseDouble(value);\n int res = 0;\n if (value.substring(Math.max(value.length() - 2, 0)).equals(\".5\")) {\n if (num > 0) {\n res = (int) Math.floor(num);\n } else {\n res = (int) Math.ceil(num);\n }\n } else if(value.length() > 0) {\n res = (int) Math.round(num);\n }\n return res;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "closestInteger"} +{"task_id": "Java/99", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n */\n public int countUpper(String value) {\n", "canonical_solution": " if (value.contains(\".\")) {\n while (value.charAt(value.length() - 1) == '0') {\n value = value.substring(0, value.length() - 1);\n }\n }\n double num = Double.parseDouble(value);\n int res = 0;\n if (value.substring(Math.max(value.length() - 2, 0)).equals(\".5\")) {\n if (num > 0) {\n res = (int) Math.ceil(num);\n } else {\n res = (int) Math.floor(num);\n }\n } else if(value.length() > 0) {\n res = (int) Math.round(num);\n }\n return res;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"10\") == 10,\n s.countUpper(\"14.5\") == 15,\n s.countUpper(\"-15.5\") == -16,\n s.countUpper(\"15.3\") == 15,\n s.countUpper(\"0\") == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int countUpper(String value) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.countUpper(\"10\") == 10,\n s.countUpper(\"15.3\") == 15\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (value.contains(\".\")) {\n while (value.charAt(value.length() - 1) == '0') {\n value = value.substring(0, value.length() - 1);\n }\n }\n double num = Double.parseDouble(value);\n int res = 0;\n if (value.substring(Math.max(value.length() - 2, 0)).equals(\".5\")) {\n if (num > 0) {\n res = (int) Math.floor(num);\n } else {\n res = (int) Math.ceil(num);\n }\n } else if(value.length() > 0) {\n res = (int) Math.round(num);\n }\n return res;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "closest_integer"} {"task_id": "Java/100", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> makeAPile(3)\n [3, 5, 7]\n */\n public List makeAPile(int n) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (int i = 0; i < n; i++) {\n result.add(n + 2 * i);\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.makeAPile(3).equals(Arrays.asList(3, 5, 7)),\n s.makeAPile(4).equals(Arrays.asList(4, 6, 8, 10)),\n s.makeAPile(5).equals(Arrays.asList(5, 7, 9, 11, 13)),\n s.makeAPile(6).equals(Arrays.asList(6, 8, 10, 12, 14, 16)),\n s.makeAPile(8).equals(Arrays.asList(8, 10, 12, 14, 16, 18, 20, 22))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a positive integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n The number of stones in the next level is:\n - the next odd number if n is odd.\n - the next even number if n is even.\n Return the number of stones in each level in a list, where element at index\n i represents the number of stones in the level (i+1).\n\n Examples:\n >>> makeAPile(3)\n [3, 5, 7]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List makeAPile(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.makeAPile(3).equals(Arrays.asList(3, 5, 7))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (int i = 0; i < n; i++) {\n result.add(n + 2 * i + i);\n }\n return result;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "makeAPile"} -{"task_id": "Java/101", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\").equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\").equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n */\n public List wordStrings(String s) {\n", "canonical_solution": " if (s.length() == 0) {\n return List.of();\n }\n StringBuilder sb = new StringBuilder();\n\n for (char letter : s.toCharArray()) {\n if (letter == ',') {\n sb.append(' ');\n } else {\n sb.append(letter);\n }\n }\n\n return new ArrayList<>(Arrays.asList(sb.toString().split(\"\\s+\" )));\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.wordStrings(\"Hi, my name is John\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\" )),\n s.wordStrings(\"One, two, three, four, five, six\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" )),\n s.wordStrings(\"Hi, my name\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\" )),\n s.wordStrings(\"One,, two, three, four, five, six,\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" )),\n s.wordStrings(\"\" ).equals(List.of()),\n s.wordStrings(\"ahmed , gamal\" ).equals(Arrays.asList(\"ahmed\", \"gamal\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\").equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\").equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List wordStrings(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.wordStrings(\"Hi, my name is John\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\" )),\n s.wordStrings(\"One, two, three, four, five, six\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (s.length() == 0) {\n return List.of();\n }\n StringBuilder sb = new StringBuilder();\n\n for (char letter : s.toCharArray()) {\n if (letter == ',') {\n sb.append(',');\n } else {\n sb.append(letter);\n }\n }\n\n return new ArrayList<>(Arrays.asList(sb.toString().split(\"\\s+\" )));\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "wordsString"} +{"task_id": "Java/101", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\").equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\").equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n */\n public List wordStrings(String s) {\n", "canonical_solution": " if (s.length() == 0) {\n return List.of();\n }\n StringBuilder sb = new StringBuilder();\n\n for (char letter : s.toCharArray()) {\n if (letter == ',') {\n sb.append(' ');\n } else {\n sb.append(letter);\n }\n }\n\n return new ArrayList<>(Arrays.asList(sb.toString().split(\"\\s+\" )));\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.wordStrings(\"Hi, my name is John\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\" )),\n s.wordStrings(\"One, two, three, four, five, six\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" )),\n s.wordStrings(\"Hi, my name\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\" )),\n s.wordStrings(\"One,, two, three, four, five, six,\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" )),\n s.wordStrings(\"\" ).equals(List.of()),\n s.wordStrings(\"ahmed , gamal\" ).equals(Arrays.asList(\"ahmed\", \"gamal\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You will be given a string of words separated by commas or spaces. Your task is\n to split the string into words and return an array of the words.\n \n For example:\n words_string(\"Hi, my name is John\").equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n words_string(\"One, two, three, four, five, six\").equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List wordStrings(String s) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.wordStrings(\"Hi, my name is John\" ).equals(Arrays.asList(\"Hi\", \"my\", \"name\", \"is\", \"John\" )),\n s.wordStrings(\"One, two, three, four, five, six\" ).equals(Arrays.asList(\"One\", \"two\", \"three\", \"four\", \"five\", \"six\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (s.length() == 0) {\n return List.of();\n }\n StringBuilder sb = new StringBuilder();\n\n for (char letter : s.toCharArray()) {\n if (letter == ',') {\n sb.append(',');\n } else {\n sb.append(letter);\n }\n }\n\n return new ArrayList<>(Arrays.asList(sb.toString().split(\"\\s+\" )));\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "words_string"} {"task_id": "Java/102", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If\n there's no such number, then the function should return -1.\n \n For example:\n chooseNum(12, 15) = 14\n chooseNum(13, 12) = -1\n */\n public int chooseNum(int x, int y) {\n", "canonical_solution": " if (x > y) {\n return -1;\n }\n if (y % 2 == 0) {\n return y;\n }\n if (x == y) {\n return -1;\n }\n return y - 1;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.chooseNum(12, 15) == 14,\n s.chooseNum(13, 12) == -1,\n s.chooseNum(33, 12354) == 12354,\n s.chooseNum(5234, 5233) == -1,\n s.chooseNum(6, 29) == 28,\n s.chooseNum(27, 10) == -1,\n s.chooseNum(7, 7) == -1,\n s.chooseNum(546, 546) == 546\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " This function takes two positive numbers x and y and returns the\n biggest even integer number that is in the range [x, y] inclusive. If\n there's no such number, then the function should return -1.\n \n For example:\n chooseNum(12, 15) = 14\n chooseNum(13, 12) = -1", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int chooseNum(int x, int y) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.chooseNum(12, 15) == 14,\n s.chooseNum(13, 12) == -1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (x > y) {\n return -1;\n }\n if (y % 2 == 0) {\n return y;\n }\n if (x == y) {\n return -1;\n }\n return x - 1;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "chooseNum"} {"task_id": "Java/103", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m).\n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n Example:\n roundedAvg(1, 5) => \"11\"\n roundedAvg(7, 5) => -1\n roundedAvg(10, 20) => \"1111\"\n roundedAvg(20, 33) => \"11011\"\n */\n public Object roundedAvg(int n, int m) {\n", "canonical_solution": " if (n > m) {\n return -1;\n }\n return Integer.toBinaryString((int) Math.round((double) (m + n) / 2));\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals((String) s.roundedAvg(1, 5), \"11\" ),\n Objects.equals((String) s.roundedAvg(7, 13), \"1010\" ),\n Objects.equals((String) s.roundedAvg(964, 977), \"1111001011\" ),\n Objects.equals((String) s.roundedAvg(996, 997), \"1111100101\" ),\n Objects.equals((String) s.roundedAvg(560, 851), \"1011000010\" ),\n Objects.equals((String) s.roundedAvg(185, 546), \"101101110\" ),\n Objects.equals((String) s.roundedAvg(362, 496), \"110101101\" ),\n Objects.equals((String) s.roundedAvg(350, 902), \"1001110010\" ),\n Objects.equals((String) s.roundedAvg(197, 233), \"11010111\" ),\n (int) s.roundedAvg(7, 5) == -1,\n (int) s.roundedAvg(5, 1) == -1,\n Objects.equals((String) s.roundedAvg(5, 5), \"101\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given two positive integers n and m, and your task is to compute the\n average of the integers from n through m (including n and m).\n Round the answer to the nearest integer and convert that to binary.\n If n is greater than m, return -1.\n Example:\n roundedAvg(1, 5) => \"11\"\n roundedAvg(7, 5) => -1\n roundedAvg(10, 20) => \"1111\"\n roundedAvg(20, 33) => \"11011\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public Object roundedAvg(int n, int m) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals((String) s.roundedAvg(1, 5), \"11\" ),\n (int) s.roundedAvg(7, 5) == -1,\n Objects.equals((String) s.roundedAvg(10, 20), \"1111\" ),\n Objects.equals((String) s.roundedAvg(20, 33), \"11011\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (n > m) {\n return -1;\n }\n return Integer.toBinaryString((int) Math.round((double) (m + n + 1) / 2));\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "roundedAvg"} {"task_id": "Java/104", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a list of positive integers x. return a sorted list of all\n elements that hasn't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> uniqueDigits(Arrays.asList(15, 33, 1422, 1))\n [1, 15, 33]\n >>> uniqueDigits(Arrays.asList(152, 323, 1422, 10))\n []\n */\n public List uniqueDigits(List x) {\n", "canonical_solution": " List odd_digit_elements = new ArrayList<>();\n for (int i : x) {\n boolean is_unique = true;\n for (char c : String.valueOf(i).toCharArray()) {\n if ((c - '0') % 2 == 0) {\n is_unique = false;\n break;\n }\n }\n if (is_unique) {\n odd_digit_elements.add(i);\n }\n }\n Collections.sort(odd_digit_elements);\n return odd_digit_elements;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.uniqueDigits(Arrays.asList(15, 33, 1422, 1)).equals(Arrays.asList(1, 15, 33)),\n s.uniqueDigits(Arrays.asList(152, 323, 1422, 10)).equals(List.of()),\n s.uniqueDigits(Arrays.asList(12345, 2033, 111, 151)).equals(Arrays.asList(111, 151)),\n s.uniqueDigits(Arrays.asList(135, 103, 31)).equals(Arrays.asList(31, 135))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a list of positive integers x. return a sorted list of all\n elements that hasn't any even digit.\n\n Note: Returned list should be sorted in increasing order.\n \n For example:\n >>> uniqueDigits(Arrays.asList(15, 33, 1422, 1))\n [1, 15, 33]\n >>> uniqueDigits(Arrays.asList(152, 323, 1422, 10))\n []", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List uniqueDigits(List x) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.uniqueDigits(Arrays.asList(15, 33, 1422, 1)).equals(Arrays.asList(1, 15, 33)),\n s.uniqueDigits(Arrays.asList(152, 323, 1422, 10)).equals(List.of())\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List odd_digit_elements = new ArrayList<>();\n for (int i : x) {\n boolean is_unique = true;\n for (char c : String.valueOf(i).toCharArray()) {\n if ((c - '0') % 2 == 0) {\n is_unique = false;\n break;\n }\n }\n if (is_unique) {\n odd_digit_elements.add(i);\n odd_digit_elements.add(1);\n }\n }\n Collections.sort(odd_digit_elements);\n return odd_digit_elements;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "uniqueDigits"} @@ -112,7 +112,7 @@ {"task_id": "Java/111", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n\n Example:\n histogram(\"a b c\") == {\"a\": 1, \"b\": 1, \"c\": 1}\n histogram(\"a b b a\") == {\"a\": 2, \"b\": 2}\n histogram(\"a b c a b\") == {\"a\": 2, \"b\": 2}\n histogram(\"b b b b a\") == {\"b\": 4}\n histogram(\"\") == {}\n */\n public Map histogram(String test) {\n", "canonical_solution": " Map dict1 = new HashMap<>();\n List list1 = Arrays.asList(test.split(\" \" ));\n int t = 0;\n for (String i : list1) {\n if (Collections.frequency(list1, i) > t && !i.isEmpty()) {\n t = Collections.frequency(list1, i);\n }\n }\n if (t > 0) {\n for (String i : list1) {\n if (Collections.frequency(list1, i) == t) {\n dict1.put(i, t);\n }\n }\n }\n return dict1;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n Map map1 = new HashMap<>();\n map1.put(\"a\", 2);\n map1.put(\"b\", 2);\n Map map2 = new HashMap<>();\n map2.put(\"a\", 2);\n map2.put(\"b\", 2);\n Map map3 = new HashMap<>();\n map3.put(\"a\", 1);\n map3.put(\"b\", 1);\n map3.put(\"c\", 1);\n map3.put(\"d\", 1);\n map3.put(\"g\", 1);\n Map map4 = new HashMap<>();\n map4.put(\"r\", 1);\n map4.put(\"t\", 1);\n map4.put(\"g\", 1);\n Map map5 = new HashMap<>();\n map5.put(\"b\", 4);\n Map map6 = new HashMap<>();\n map6.put(\"r\", 1);\n map6.put(\"t\", 1);\n map6.put(\"g\", 1);\n Map map7 = new HashMap<>();\n Map map8 = new HashMap<>();\n map8.put(\"a\", 1);\n List correct = Arrays.asList(\n s.histogram(\"a b b a\" ).equals(map1),\n s.histogram(\"a b c a b\" ).equals(map2),\n s.histogram(\"a b c d g\" ).equals(map3),\n s.histogram(\"r t g\" ).equals(map4),\n s.histogram(\"b b b b a\" ).equals(map5),\n s.histogram(\"r t g\" ).equals(map6),\n s.histogram(\"\" ).equals(map7),\n s.histogram(\"a\" ).equals(map8)\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a string representing a space separated lowercase letters, return a dictionary\n of the letter with the most repetition and containing the corresponding count.\n If several letters have the same occurrence, return all of them.\n\n Example:\n histogram(\"a b c\") == {\"a\": 1, \"b\": 1, \"c\": 1}\n histogram(\"a b b a\") == {\"a\": 2, \"b\": 2}\n histogram(\"a b c a b\") == {\"a\": 2, \"b\": 2}\n histogram(\"b b b b a\") == {\"b\": 4}\n histogram(\"\") == {}", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public Map histogram(String test) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n Map map1 = new HashMap<>();\n map1.put(\"a\", 2);\n map1.put(\"b\", 2);\n Map map2 = new HashMap<>();\n map2.put(\"a\", 2);\n map2.put(\"b\", 2);\n Map map3 = new HashMap<>();\n map3.put(\"a\", 1);\n map3.put(\"b\", 1);\n map3.put(\"c\", 1);\n map3.put(\"d\", 1);\n map3.put(\"g\", 1);\n Map map4 = new HashMap<>();\n map4.put(\"a\", 1);\n map4.put(\"b\", 1);\n map4.put(\"c\", 1);\n Map map5 = new HashMap<>();\n map5.put(\"b\", 4);\n Map map6 = new HashMap<>();\n map6.put(\"r\", 1);\n map6.put(\"t\", 1);\n map6.put(\"g\", 1);\n Map map7 = new HashMap<>();\n Map map8 = new HashMap<>();\n map8.put(\"a\", 1);\n List correct = Arrays.asList(\n s.histogram(\"a b b a\" ).equals(map1),\n s.histogram(\"a b c a b\" ).equals(map2),\n s.histogram(\"a b c\" ).equals(map4),\n s.histogram(\"b b b b a\" ).equals(map5),\n s.histogram(\"\" ).equals(map7)\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " Map dict1 = new HashMap<>();\n List list1 = Arrays.asList(test.split(\" \" ));\n int t = 1;\n for (String i : list1) {\n if (Collections.frequency(list1, i) > t && !i.isEmpty()) {\n t = Collections.frequency(list1, i);\n }\n }\n if (t > 0) {\n for (String i : list1) {\n if (Collections.frequency(list1, i) == t) {\n dict1.put(i, t);\n }\n }\n }\n return dict1;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "histogram"} {"task_id": "Java/112", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Task\n We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and true/false for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be (\"bcd\",false)\n For s = \"abcdef\", c = \"b\" the result should be (\"acdef\",false)\n For s = \"abcdedcba\", c = \"ab\", the result should be (\"cdedc\",true)\n */\n public List reverseDelete(String s, String c) {\n", "canonical_solution": " StringBuilder sb = new StringBuilder();\n for (char ch : s.toCharArray()) {\n if (c.indexOf(ch) == -1) {\n sb.append(ch);\n }\n }\n return Arrays.asList(sb.toString(), sb.toString().equals(sb.reverse().toString()));\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.reverseDelete(\"abcde\", \"ae\" ).equals(Arrays.asList(\"bcd\", false)),\n s.reverseDelete(\"abcdef\", \"b\" ).equals(Arrays.asList(\"acdef\", false)),\n s.reverseDelete(\"abcdedcba\", \"ab\" ).equals(Arrays.asList(\"cdedc\", true)),\n s.reverseDelete(\"dwik\", \"w\" ).equals(Arrays.asList(\"dik\", false)),\n s.reverseDelete(\"a\", \"a\" ).equals(Arrays.asList(\"\", true)),\n s.reverseDelete(\"abcdedcba\", \"\" ).equals(Arrays.asList(\"abcdedcba\", true)),\n s.reverseDelete(\"abcdedcba\", \"v\" ).equals(Arrays.asList(\"abcdedcba\", true)),\n s.reverseDelete(\"vabba\", \"v\" ).equals(Arrays.asList(\"abba\", true)),\n s.reverseDelete(\"mamma\", \"mia\" ).equals(Arrays.asList(\"\", true))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Task\n We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c\n then check if the result string is palindrome.\n A string is called palindrome if it reads the same backward as forward.\n You should return a tuple containing the result string and true/false for the check.\n Example\n For s = \"abcde\", c = \"ae\", the result should be (\"bcd\",false)\n For s = \"abcdef\", c = \"b\" the result should be (\"acdef\",false)\n For s = \"abcdedcba\", c = \"ab\", the result should be (\"cdedc\",true)", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List reverseDelete(String s, String c) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.reverseDelete(\"abcde\", \"ae\" ).equals(Arrays.asList(\"bcd\", false)),\n s.reverseDelete(\"abcdef\", \"b\" ).equals(Arrays.asList(\"acdef\", false)),\n s.reverseDelete(\"abcdedcba\", \"ab\" ).equals(Arrays.asList(\"cdedc\", true))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " StringBuilder sb = new StringBuilder();\n for (char ch : s.toCharArray()) {\n if (c.indexOf(ch) != -1) {\n sb.append(ch);\n }\n }\n return Arrays.asList(sb.toString(), sb.toString().equals(sb.reverse().toString()));\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "reverseDelete"} {"task_id": "Java/113", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i\"th string of the input.\n\n >>> oddCount(Arrays.asList(\"1234567\"))\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> oddCount(Arrays.asList(\"3\",\"11111111\"))\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n */\n public List oddCount(List lst) {\n", "canonical_solution": " List res = new ArrayList<>();\n for (String arr : lst) {\n int n = 0;\n for (char d : arr.toCharArray()) {\n if ((d - '0') % 2 == 1) {\n n += 1;\n }\n }\n res.add(\"the number of odd elements \" + n + \"n the str\" + n + \"ng \" + n + \" of the \" + n + \"nput.\" );\n }\n return res;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.oddCount(List.of(\"1234567\" )).equals(List.of(\"the number of odd elements 4n the str4ng 4 of the 4nput.\" )),\n s.oddCount(Arrays.asList(\"3\", \"11111111\" )).equals(Arrays.asList(\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\" )),\n s.oddCount(Arrays.asList(\"271\", \"137\", \"314\" )).equals(Arrays.asList(\n \"the number of odd elements 2n the str2ng 2 of the 2nput.\",\n \"the number of odd elements 3n the str3ng 3 of the 3nput.\",\n \"the number of odd elements 2n the str2ng 2 of the 2nput.\"\n ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i\"th string of the input.\n\n >>> oddCount(Arrays.asList(\"1234567\"))\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> oddCount(Arrays.asList(\"3\",\"11111111\"))\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List oddCount(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.oddCount(List.of(\"1234567\" )).equals(List.of(\"the number of odd elements 4n the str4ng 4 of the 4nput.\" )),\n s.oddCount(Arrays.asList(\"3\", \"11111111\" )).equals(Arrays.asList(\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List res = new ArrayList<>();\n for (String arr : lst) {\n int n = 0;\n for (char d : arr.toCharArray()) {\n if ((d - '0') % 2 == 1) {\n n += 1;\n }\n }\n res.add(\"the number of odd elements \" + n + \"n the str\" + n + \"ng \" + n + \" of \" + n + \" the \" + n + \"nput.\" );\n }\n return res;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "oddCount"} -{"task_id": "Java/114", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1\n minSubArraySum(Arrays.asList(-1, -2, -3)) == -6\n */\n public int minSubArraySum(List nums) {\n", "canonical_solution": " int minSum = Integer.MAX_VALUE;\n int sum = 0;\n for (Integer num : nums) {\n sum += num;\n if (minSum > sum) {\n minSum = sum;\n }\n if (sum > 0) {\n sum = 0;\n }\n }\n return minSum;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1,\n s.minSubArraySum(Arrays.asList(-1, -2, -3)) == -6,\n s.minSubArraySum(Arrays.asList(-1, -2, -3, 2, -10)) == -14,\n s.minSubArraySum(List.of(-999999999)) == -999999999,\n s.minSubArraySum(Arrays.asList(0, 10, 20, 1000000)) == 0,\n s.minSubArraySum(Arrays.asList(-1, -2, -3, 10, -5)) == -6,\n s.minSubArraySum(Arrays.asList(100, -1, -2, -3, 10, -5)) == -6,\n s.minSubArraySum(Arrays.asList(10, 11, 13, 8, 3, 4)) == 3,\n s.minSubArraySum(Arrays.asList(100, -33, 32, -1, 0, -2)) == -33,\n s.minSubArraySum(List.of(-10)) == -10,\n s.minSubArraySum(List.of(7)) == 7,\n s.minSubArraySum(Arrays.asList(1, -1)) == -1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1\n minSubArraySum(Arrays.asList(-1, -2, -3)) == -6", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int minSubArraySum(List nums) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1,\n s.minSubArraySum(Arrays.asList(-1, -2, -3)) == -6\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int minSum = Integer.MIN_VALUE;\n int sum = 0;\n for (Integer num : nums) {\n sum += num;\n if (minSum > sum) {\n minSum = sum ;\n }\n if (sum > 0) {\n sum = 0;\n }\n }\n return minSum;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "minsubarraysum"} +{"task_id": "Java/114", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1\n minSubArraySum(Arrays.asList(-1, -2, -3)) == -6\n */\n public int minSubArraySum(List nums) {\n", "canonical_solution": " int minSum = Integer.MAX_VALUE;\n int sum = 0;\n for (Integer num : nums) {\n sum += num;\n if (minSum > sum) {\n minSum = sum;\n }\n if (sum > 0) {\n sum = 0;\n }\n }\n return minSum;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1,\n s.minSubArraySum(Arrays.asList(-1, -2, -3)) == -6,\n s.minSubArraySum(Arrays.asList(-1, -2, -3, 2, -10)) == -14,\n s.minSubArraySum(List.of(-999999999)) == -999999999,\n s.minSubArraySum(Arrays.asList(0, 10, 20, 1000000)) == 0,\n s.minSubArraySum(Arrays.asList(-1, -2, -3, 10, -5)) == -6,\n s.minSubArraySum(Arrays.asList(100, -1, -2, -3, 10, -5)) == -6,\n s.minSubArraySum(Arrays.asList(10, 11, 13, 8, 3, 4)) == 3,\n s.minSubArraySum(Arrays.asList(100, -33, 32, -1, 0, -2)) == -33,\n s.minSubArraySum(List.of(-10)) == -10,\n s.minSubArraySum(List.of(7)) == 7,\n s.minSubArraySum(Arrays.asList(1, -1)) == -1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given an array of integers nums, find the minimum sum of any non-empty sub-array\n of nums.\n Example\n minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1\n minSubArraySum(Arrays.asList(-1, -2, -3)) == -6", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int minSubArraySum(List nums) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minSubArraySum(Arrays.asList(2, 3, 4, 1, 2, 4)) == 1,\n s.minSubArraySum(Arrays.asList(-1, -2, -3)) == -6\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int minSum = Integer.MIN_VALUE;\n int sum = 0;\n for (Integer num : nums) {\n sum += num;\n if (minSum > sum) {\n minSum = sum ;\n }\n if (sum > 0) {\n sum = 0;\n }\n }\n return minSum;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "minSubarraySum"} {"task_id": "Java/115", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given a rectangular grid of wells. Each row represents a single well,\n and each 1 in a row represents a single unit of water.\n Each well has a corresponding bucket that can be used to extract water from it,\n and all buckets have the same capacity.\n Your task is to use the buckets to empty the wells.\n Output the number of times you need to lower the buckets.\n\n Example 1:\n Input:\n grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n bucket_capacity : 1\n Output: 6\n\n Example 2:\n Input:\n grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n bucket_capacity : 2\n Output: 5\n\n Example 3:\n Input:\n grid : [[0,0,0], [0,0,0]]\n bucket_capacity : 5\n Output: 0\n\n Constraints:\n * all wells have the same length\n * 1 <= grid.length <= 10^2\n * 1 <= grid[:,1].length <= 10^2\n * grid[i][j] -> 0 | 1\n * 1 <= capacity <= 10\n */\n public int maxFill(List> grid, int capacity) {\n", "canonical_solution": " int sum = 0;\n for (List arr : grid) {\n sum += Math.ceil((double) arr.stream().reduce(Integer::sum).get() / capacity);\n }\n return sum;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 1, 0), Arrays.asList(0, 1, 0, 0), Arrays.asList(1, 1, 1, 1)), 1) == 6,\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 1, 1), Arrays.asList(0, 0, 0, 0), Arrays.asList(1, 1, 1, 1), Arrays.asList(0, 1, 1, 1)), 2) == 5,\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 0), Arrays.asList(0, 0, 0)), 5) == 0,\n s.maxFill(Arrays.asList(Arrays.asList(1, 1, 1, 1), Arrays.asList(1, 1, 1, 1)), 2) == 4,\n s.maxFill(Arrays.asList(Arrays.asList(1, 1, 1, 1), Arrays.asList(1, 1, 1, 1)), 9) == 2\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given a rectangular grid of wells. Each row represents a single well,\n and each 1 in a row represents a single unit of water.\n Each well has a corresponding bucket that can be used to extract water from it,\n and all buckets have the same capacity.\n Your task is to use the buckets to empty the wells.\n Output the number of times you need to lower the buckets.\n\n Example 1:\n Input:\n grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n bucket_capacity : 1\n Output: 6\n\n Example 2:\n Input:\n grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n bucket_capacity : 2\n Output: 5\n\n Example 3:\n Input:\n grid : [[0,0,0], [0,0,0]]\n bucket_capacity : 5\n Output: 0\n\n Constraints:\n * all wells have the same length\n * 1 <= grid.length <= 10^2\n * 1 <= grid[:,1].length <= 10^2\n * grid[i][j] -> 0 | 1\n * 1 <= capacity <= 10", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int maxFill(List> grid, int capacity) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 1, 0), Arrays.asList(0, 1, 0, 0), Arrays.asList(1, 1, 1, 1)), 1) == 6,\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 1, 1), Arrays.asList(0, 0, 0, 0), Arrays.asList(1, 1, 1, 1), Arrays.asList(0, 1, 1, 1)), 2) == 5,\n s.maxFill(Arrays.asList(Arrays.asList(0, 0, 0), Arrays.asList(0, 0, 0)), 5) == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int sum = 0;\n for (List arr : grid) {\n sum += Math.floor((double) arr.stream().reduce(Integer::sum).get() / capacity);\n }\n return sum;\n }\n}", "bug_type": "function misuse", "failure_symptoms": "incorrect output", "entry_point": "maxFill"} {"task_id": "Java/116", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n

\n It must be implemented like this:\n >>> sortArray(Arrays.asList(1, 5, 2, 3, 4)).equals(Arrays.asList(1, 2, 3, 4, 5))\n >>> sortArray(Arrays.asList(-2, -3, -4, -5, -6)).equals(Arrays.asList(-6, -5, -4, -3, -2))\n >>> sortArray(Arrays.asList(1, 0, 2, 3, 4)).equals(Arrays.asList(0, 1, 2, 3, 4))\n */\n public List sortArray(List arr) {\n", "canonical_solution": " List < Integer > sorted_arr = new ArrayList<>(arr);\n sorted_arr.sort(new Comparator() {\n @Override\n public int compare(Integer o1, Integer o2) {\n int cnt1 = (int) Integer.toBinaryString(Math.abs(o1)).chars().filter(ch -> ch == '1').count();\n int cnt2 = (int) Integer.toBinaryString(Math.abs(o2)).chars().filter(ch -> ch == '1').count();\n if (cnt1 > cnt2) {\n return 1;\n } else if (cnt1 < cnt2) {\n return -1;\n } else {\n return o1.compareTo(o2);\n }\n }\n });\n return sorted_arr;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortArray(new ArrayList<>(Arrays.asList(1, 5, 2, 3, 4))).equals(Arrays.asList(1, 2, 4, 3, 5)),\n s.sortArray(new ArrayList<>(Arrays.asList(-2, -3, -4, -5, -6))).equals(Arrays.asList(-4, -2, -6, -5, -3)),\n s.sortArray(new ArrayList<>(Arrays.asList(1, 0, 2, 3, 4))).equals(Arrays.asList(0, 1, 2, 4, 3)),\n s.sortArray(new ArrayList<>(List.of())).equals(List.of()),\n s.sortArray(new ArrayList<>(Arrays.asList(2, 5, 77, 4, 5, 3, 5, 7, 2, 3, 4))).equals(Arrays.asList(2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77)),\n s.sortArray(new ArrayList<>(Arrays.asList(3, 6, 44, 12, 32, 5))).equals(Arrays.asList(32, 3, 5, 6, 12, 44)),\n s.sortArray(new ArrayList<>(Arrays.asList(2, 4, 8, 16, 32))).equals(Arrays.asList(2, 4, 8, 16, 32)),\n s.sortArray(new ArrayList<>(Arrays.asList(2, 4, 8, 16, 32))).equals(Arrays.asList(2, 4, 8, 16, 32))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " In this Kata, you have to sort an array of non-negative integers according to\n number of ones in their binary representation in ascending order.\n For similar number of ones, sort based on decimal value.\n

\n It must be implemented like this:\n >>> sortArray(Arrays.asList(1, 5, 2, 3, 4)).equals(Arrays.asList(1, 2, 3, 4, 5))\n >>> sortArray(Arrays.asList(-2, -3, -4, -5, -6)).equals(Arrays.asList(-6, -5, -4, -3, -2))\n >>> sortArray(Arrays.asList(1, 0, 2, 3, 4)).equals(Arrays.asList(0, 1, 2, 3, 4))", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List sortArray(List arr) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sortArray(new ArrayList<>(Arrays.asList(1, 5, 2, 3, 4))).equals(Arrays.asList(1, 2, 4, 3, 5)),\n s.sortArray(new ArrayList<>(Arrays.asList(-2, -3, -4, -5, -6))).equals(Arrays.asList(-4, -2, -6, -5, -3)),\n s.sortArray(new ArrayList<>(Arrays.asList(1, 0, 2, 3, 4))).equals(Arrays.asList(0, 1, 2, 4, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List < Integer > sorted_arr = new ArrayList<>(arr);\n sorted_arr.sort(new Comparator() {\n @Override\n public int compare(Integer o1, Integer o2) {\n int cnt1 = (int) Integer.toBinaryString(Math.abs(o1)).chars().filter(ch -> ch == '1').count();\n int cnt2 = (int) Integer.toBinaryString(Math.abs(o2)).chars().filter(ch -> ch == '1').count();\n if (cnt1 > cnt2) {\n return 1;\n } else if (cnt1 < cnt2) {\n return -1;\n } else {\n return o1.compareTo(o2);\n }\n }\n });\n return arr;\n }\n}", "bug_type": "variable misuse", "failure_symptoms": "incorrect output", "entry_point": "sortArray"} {"task_id": "Java/117", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a string s and a natural number n, you have been tasked to implement\n a function that returns a list of all words from string s that contain exactly\n n consonants, in order these words appear in the string s.\n If the string s is empty then the function should return an empty list.\n Note: you may assume the input string contains only letters and spaces.\n Examples:\n selectWords(\"Mary had a little lamb\", 4) ==> [\"little\"]\n selectWords(\"Mary had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n selectWords(\"simple white space\", 2) ==> []\n selectWords(\"Hello world\", 4) ==> [\"world\"]\n selectWords(\"Uncle sam\", 3) ==> [\"Uncle\"]\n */\n public List selectWords(String s, int n) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (String word : s.split(\" \")) {\n int n_consonants = 0;\n for (char c : word.toCharArray()) {\n c = Character.toLowerCase(c);\n if (\"aeiou\".indexOf(c) == -1) {\n n_consonants += 1;\n }\n }\n if (n_consonants == n) {\n result.add(word);\n }\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.selectWords(\"Mary had a little lamb\", 4).equals(List.of(\"little\" )),\n s.selectWords(\"Mary had a little lamb\", 3).equals(Arrays.asList(\"Mary\", \"lamb\")),\n s.selectWords(\"simple white space\", 2).equals(List.of()),\n s.selectWords(\"Hello world\", 4).equals(List.of(\"world\" )),\n s.selectWords(\"Uncle sam\", 3).equals(List.of(\"Uncle\" )),\n s.selectWords(\"\", 4).equals(List.of()),\n s.selectWords(\"a b c d e f\", 1).equals(Arrays.asList(\"b\", \"c\", \"d\", \"f\"))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a string s and a natural number n, you have been tasked to implement\n a function that returns a list of all words from string s that contain exactly\n n consonants, in order these words appear in the string s.\n If the string s is empty then the function should return an empty list.\n Note: you may assume the input string contains only letters and spaces.\n Examples:\n selectWords(\"Mary had a little lamb\", 4) ==> [\"little\"]\n selectWords(\"Mary had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n selectWords(\"simple white space\", 2) ==> []\n selectWords(\"Hello world\", 4) ==> [\"world\"]\n selectWords(\"Uncle sam\", 3) ==> [\"Uncle\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List selectWords(String s, int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.selectWords(\"Mary had a little lamb\", 4).equals(List.of(\"little\" )),\n s.selectWords(\"Mary had a little lamb\", 3).equals(Arrays.asList(\"Mary\", \"lamb\")),\n s.selectWords(\"simple white space\", 2).equals(List.of()),\n s.selectWords(\"Hello world\", 4).equals(List.of(\"world\" )),\n s.selectWords(\"Uncle sam\", 3).equals(List.of(\"Uncle\" ))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (String word : s.split(\" \")) {\n int n_consonants = 0;\n for (char c : word.toCharArray()) {\n c = Character.toLowerCase(c);\n if (\"aeiou\".indexOf(c) != -1) {\n n_consonants += 1;\n }\n }\n if (n_consonants == n) {\n result.add(word);\n }\n }\n return result;\n }\n}", "bug_type": "operator misuse", "failure_symptoms": "incorrect output", "entry_point": "selectWords"} @@ -127,7 +127,7 @@ {"task_id": "Java/126", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return false. Assume no negative numbers and only integers.\n\n Examples\n isSorted(Arrays.asList(5)) -> true\n isSorted(Arrays.asList(1, 2, 3, 4, 5)) -> true\n isSorted(Arrays.asList(1, 3, 2, 4, 5)) -> false\n isSorted(Arrays.asList(1, 2, 3, 4, 5, 6)) -> true\n isSorted(Arrays.asList(1, 2, 3, 4, 5, 6, 7)) -> true\n isSorted(Arrays.asList(1, 3, 2, 4, 5, 6, 7)) -> false\n isSorted(Arrays.asList(1, 2, 2, 3, 3, 4)) -> true\n isSorted(Arrays.asList(1, 2, 2, 2, 3, 4)) -> false\n */\n public boolean isSorted(List lst) {\n", "canonical_solution": " List sorted_lst = new ArrayList<>(lst);\n Collections.sort(sorted_lst);\n if (!lst.equals(sorted_lst)) {\n return false;\n }\n for (int i = 0; i < lst.size() - 2; i++) {\n if (lst.get(i) == lst.get(i + 1) && lst.get(i) == lst.get(i + 2)) {\n return false;\n }\n }\n return true;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isSorted(new ArrayList<>(List.of(5))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 3, 2, 4, 5))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 6))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 6, 7))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 3, 2, 4, 5, 6, 7))) == false,\n s.isSorted(new ArrayList<>(List.of())) == true,\n s.isSorted(new ArrayList<>(List.of(1))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(3, 2, 1))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 2, 2, 3, 4))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 3, 3, 4))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 2, 3, 3, 4))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4))) == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a list of numbers, return whether or not they are sorted\n in ascending order. If list has more than 1 duplicate of the same\n number, return false. Assume no negative numbers and only integers.\n\n Examples\n isSorted(Arrays.asList(5)) -> true\n isSorted(Arrays.asList(1, 2, 3, 4, 5)) -> true\n isSorted(Arrays.asList(1, 3, 2, 4, 5)) -> false\n isSorted(Arrays.asList(1, 2, 3, 4, 5, 6)) -> true\n isSorted(Arrays.asList(1, 2, 3, 4, 5, 6, 7)) -> true\n isSorted(Arrays.asList(1, 3, 2, 4, 5, 6, 7)) -> false\n isSorted(Arrays.asList(1, 2, 2, 3, 3, 4)) -> true\n isSorted(Arrays.asList(1, 2, 2, 2, 3, 4)) -> false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean isSorted(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isSorted(new ArrayList<>(List.of(5))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 3, 2, 4, 5))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 6))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 6, 7))) == true,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 3, 2, 4, 5, 6, 7))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 2, 2, 3, 4))) == false,\n s.isSorted(new ArrayList<>(Arrays.asList(1, 2, 2, 3, 3, 4))) == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List sorted_lst = new ArrayList<>(lst);\n Collections.sort(sorted_lst);\n if (!lst.equals(sorted_lst)) {\n return false;\n }\n for (int i = 0; i < lst.size() - 2; i++) {\n if (lst.get(i) == lst.get(i + 1)) {\n return false;\n }\n }\n return true;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "isSorted"} {"task_id": "Java/127", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given two intervals,\n where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).\n The given intervals are closed which means that the interval (start, end)\n includes both start and end.\n For each given interval, it is assumed that its start is less or equal its end.\n Your task is to determine whether the length of intersection of these two\n intervals is a prime number.\n Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)\n which its length is 1, which not a prime number.\n If the length of the intersection is a prime number, return \"YES\",\n otherwise, return \"NO\".\n If the two intervals don't intersect, return \"NO\".\n\n\n [input/output] samples:\n intersection((1, 2), (2, 3)) ==> \"NO\"\n intersection((-1, 1), (0, 4)) ==> \"NO\"\n intersection((-3, -1), (-5, 5)) ==> \"YES\"\n */\n public String intersection(List interval1, List interval2) {\n", "canonical_solution": " int l = Math.max(interval1.get(0), interval2.get(0));\n int r = Math.min(interval1.get(1), interval2.get(1));\n int length = r - l;\n if (length <= 0) {\n return \"NO\";\n }\n if (length == 1) {\n return \"NO\";\n }\n if (length == 2) {\n return \"YES\";\n }\n for (int i = 2; i < length; i++) {\n if (length % i == 0) {\n return \"NO\";\n }\n }\n return \"YES\";\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.intersection(Arrays.asList(1, 2), Arrays.asList(2, 3)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-1, 1), Arrays.asList(0, 4)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-3, -1), Arrays.asList(-5, 5)), \"YES\" ),\n Objects.equals(s.intersection(Arrays.asList(-2, 2), Arrays.asList(-4, 0)), \"YES\" ),\n Objects.equals(s.intersection(Arrays.asList(-11, 2), Arrays.asList(-1, -1)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(1, 2), Arrays.asList(3, 5)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(1, 2), Arrays.asList(1, 2)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-2, -2), Arrays.asList(-3, -2)), \"NO\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given two intervals,\n where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).\n The given intervals are closed which means that the interval (start, end)\n includes both start and end.\n For each given interval, it is assumed that its start is less or equal its end.\n Your task is to determine whether the length of intersection of these two\n intervals is a prime number.\n Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)\n which its length is 1, which not a prime number.\n If the length of the intersection is a prime number, return \"YES\",\n otherwise, return \"NO\".\n If the two intervals don't intersect, return \"NO\".\n\n\n [input/output] samples:\n intersection((1, 2), (2, 3)) ==> \"NO\"\n intersection((-1, 1), (0, 4)) ==> \"NO\"\n intersection((-3, -1), (-5, 5)) ==> \"YES\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String intersection(List interval1, List interval2) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.intersection(Arrays.asList(1, 2), Arrays.asList(2, 3)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-1, 1), Arrays.asList(0, 4)), \"NO\" ),\n Objects.equals(s.intersection(Arrays.asList(-3, -1), Arrays.asList(-5, 5)), \"YES\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int l = Math.max(interval1.get(0), interval2.get(0));\n int r = Math.min(interval1.get(1), interval2.get(1));\n int length = r - l;\n if (length == 1) {\n return \"NO\";\n }\n return \"YES\";\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "intersection"} {"task_id": "Java/128", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prodSigns(Arrays.asList(1, 2, 2, -4)) == -9\n >>> prodSigns(Arrays.asList(0, 1)) == 0\n >>> prodSigns(Arrays.asList()) == None\n */\n public Optional prodSigns(List arr) {\n", "canonical_solution": " if (arr.size() == 0) {\n return Optional.empty();\n }\n if (arr.contains(0)) {\n return Optional.of(0);\n }\n int prod = (int) (-2 * (arr.stream().filter(p -> p < 0).count() % 2) + 1);\n return Optional.of(prod * (arr.stream().map(Math::abs).reduce(Integer::sum)).get());\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.prodSigns(Arrays.asList(1, 2, 2, -4)).get() == -9,\n s.prodSigns(Arrays.asList(0, 1)).get() == 0,\n s.prodSigns(Arrays.asList(1, 1, 1, 2, 3, -1, 1)).get() == -10,\n s.prodSigns(List.of()).isEmpty(),\n s.prodSigns(Arrays.asList(2, 4,1, 2, -1, -1, 9)).get() == 20,\n s.prodSigns(Arrays.asList(-1, 1, -1, 1)).get() == 4,\n s.prodSigns(Arrays.asList(-1, 1, 1, 1)).get() == -4,\n s.prodSigns(Arrays.asList(-1, 1, 1, 0)).get() == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product of all signs\n of each number in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prodSigns(Arrays.asList(1, 2, 2, -4)) == -9\n >>> prodSigns(Arrays.asList(0, 1)) == 0\n >>> prodSigns(Arrays.asList()) == None", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public Optional prodSigns(List arr) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.prodSigns(Arrays.asList(1, 2, 2, -4)).get() == -9,\n s.prodSigns(Arrays.asList(0, 1)).get() == 0,\n s.prodSigns(List.of()).isEmpty()\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (arr.size() == 0) {\n return Optional.empty();\n }\n if (arr.contains(0)) {\n return Optional.of(0);\n }\n int prod = (int) (-2 * (arr.stream().filter(p -> p < 0).count() % 2) + 1 * 2);\n return Optional.of(prod * (arr.stream().map(Math::abs).reduce(Integer::sum)).get());\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "prodSigns"} -{"task_id": "Java/129", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a grid with N rows and N columns (N >= 2) and a positive integer k,\n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n\n Examples:\n\n Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n Output: [1, 2, 1]\n\n Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n Output: [1]\n */\n public List minPath(List> grid, int k) {\n", "canonical_solution": " int n = grid.size();\n int val = n * n + 1;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (grid.get(i).get(j) == 1) {\n List temp = new ArrayList<>();\n if (i != 0) {\n temp.add(grid.get(i - 1).get(j));\n }\n if (j != 0) {\n temp.add(grid.get(i).get(j - 1));\n }\n if (i != n - 1) {\n temp.add(grid.get(i + 1).get(j));\n }\n if (j != n - 1) {\n temp.add(grid.get(i).get(j + 1));\n }\n val = Collections.min(temp);\n }\n }\n }\n List ans = new ArrayList<>();\n for (int i = 0; i < k; i++) {\n if (i % 2 == 0) {\n ans.add(1);\n } else {\n ans.add(val);\n }\n }\n return ans;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3), Arrays.asList(4, 5, 6), Arrays.asList(7, 8, 9)), 3).equals(Arrays.asList(1, 2, 1)),\n s.minPath(Arrays.asList(Arrays.asList(5, 9, 3), Arrays.asList(4, 1, 6), Arrays.asList(7, 8, 2)), 1).equals(List.of(1)),\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3, 4), Arrays.asList(5, 6, 7, 8), Arrays.asList(9, 10, 11, 12), Arrays.asList(13, 14, 15, 16)), 4).equals(Arrays.asList(1, 2, 1, 2)),\n s.minPath(Arrays.asList(Arrays.asList(6, 4, 13, 10), Arrays.asList(5, 7, 12, 1), Arrays.asList(3, 16, 11, 15), Arrays.asList(8, 14, 9, 2)), 7).equals(Arrays.asList(1, 10, 1, 10, 1, 10, 1)),\n s.minPath(Arrays.asList(Arrays.asList(8, 14, 9, 2), Arrays.asList(6, 4, 13, 15), Arrays.asList(5, 7, 1, 12), Arrays.asList(3, 10, 11, 16)), 5).equals(Arrays.asList(1, 7, 1, 7, 1)),\n s.minPath(Arrays.asList(Arrays.asList(11, 8, 7, 2), Arrays.asList(5, 16, 14, 4), Arrays.asList(9, 3, 15, 6), Arrays.asList(12, 13, 10, 1)), 9).equals(Arrays.asList(1, 6, 1, 6, 1, 6, 1, 6, 1)),\n s.minPath(Arrays.asList(Arrays.asList(12, 13, 10, 1), Arrays.asList(9, 3, 15, 6), Arrays.asList(5, 16, 14, 4), Arrays.asList(11, 8, 7, 2)), 12).equals(Arrays.asList(1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6)),\n s.minPath(Arrays.asList(Arrays.asList(2, 7, 4), Arrays.asList(3, 1, 5), Arrays.asList(6, 8, 9)), 8).equals(Arrays.asList(1, 3, 1, 3, 1, 3, 1, 3)),\n s.minPath(Arrays.asList(Arrays.asList(6, 1, 5), Arrays.asList(3, 8, 9), Arrays.asList(2, 7, 4)), 8).equals(Arrays.asList(1, 5, 1, 5, 1, 5, 1, 5)),\n s.minPath(Arrays.asList(Arrays.asList(1, 2), Arrays.asList(3, 4)), 10).equals(Arrays.asList(1, 2, 1, 2, 1, 2, 1, 2, 1, 2)),\n s.minPath(Arrays.asList(Arrays.asList(1, 3), Arrays.asList(3, 2)), 10).equals(Arrays.asList(1, 3, 1, 3, 1, 3, 1, 3, 1, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a grid with N rows and N columns (N >= 2) and a positive integer k,\n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n\n Examples:\n\n Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n Output: [1, 2, 1]\n\n Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n Output: [1]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List minPath(List> grid, int k) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3), Arrays.asList(4, 5, 6), Arrays.asList(7, 8, 9)), 3).equals(Arrays.asList(1, 2, 1)),\n s.minPath(Arrays.asList(Arrays.asList(5, 9, 3), Arrays.asList(4, 1, 6), Arrays.asList(7, 8, 2)), 1).equals(List.of(1))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int n = grid.size();\n int val = n * n + 1;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (grid.get(i).get(j) == 1) {\n List temp = new ArrayList<>();\n if (i != 0) {\n temp.add(grid.get(i).get(j));\n }\n if (j != 0) {\n temp.add(grid.get(i).get(j));\n }\n if (i != n - 1) {\n temp.add(grid.get(i).get(j));\n }\n if (j != n - 1) {\n temp.add(grid.get(i).get(j));\n }\n val = Collections.min(temp);\n }\n }\n }\n List ans = new ArrayList<>();\n for (int i = 0; i < k; i++) {\n if (i == 0) {\n ans.add(1);\n } else {\n ans.add(val);\n }\n }\n return ans;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "minpath"} +{"task_id": "Java/129", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a grid with N rows and N columns (N >= 2) and a positive integer k,\n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n\n Examples:\n\n Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n Output: [1, 2, 1]\n\n Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n Output: [1]\n */\n public List minPath(List> grid, int k) {\n", "canonical_solution": " int n = grid.size();\n int val = n * n + 1;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (grid.get(i).get(j) == 1) {\n List temp = new ArrayList<>();\n if (i != 0) {\n temp.add(grid.get(i - 1).get(j));\n }\n if (j != 0) {\n temp.add(grid.get(i).get(j - 1));\n }\n if (i != n - 1) {\n temp.add(grid.get(i + 1).get(j));\n }\n if (j != n - 1) {\n temp.add(grid.get(i).get(j + 1));\n }\n val = Collections.min(temp);\n }\n }\n }\n List ans = new ArrayList<>();\n for (int i = 0; i < k; i++) {\n if (i % 2 == 0) {\n ans.add(1);\n } else {\n ans.add(val);\n }\n }\n return ans;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3), Arrays.asList(4, 5, 6), Arrays.asList(7, 8, 9)), 3).equals(Arrays.asList(1, 2, 1)),\n s.minPath(Arrays.asList(Arrays.asList(5, 9, 3), Arrays.asList(4, 1, 6), Arrays.asList(7, 8, 2)), 1).equals(List.of(1)),\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3, 4), Arrays.asList(5, 6, 7, 8), Arrays.asList(9, 10, 11, 12), Arrays.asList(13, 14, 15, 16)), 4).equals(Arrays.asList(1, 2, 1, 2)),\n s.minPath(Arrays.asList(Arrays.asList(6, 4, 13, 10), Arrays.asList(5, 7, 12, 1), Arrays.asList(3, 16, 11, 15), Arrays.asList(8, 14, 9, 2)), 7).equals(Arrays.asList(1, 10, 1, 10, 1, 10, 1)),\n s.minPath(Arrays.asList(Arrays.asList(8, 14, 9, 2), Arrays.asList(6, 4, 13, 15), Arrays.asList(5, 7, 1, 12), Arrays.asList(3, 10, 11, 16)), 5).equals(Arrays.asList(1, 7, 1, 7, 1)),\n s.minPath(Arrays.asList(Arrays.asList(11, 8, 7, 2), Arrays.asList(5, 16, 14, 4), Arrays.asList(9, 3, 15, 6), Arrays.asList(12, 13, 10, 1)), 9).equals(Arrays.asList(1, 6, 1, 6, 1, 6, 1, 6, 1)),\n s.minPath(Arrays.asList(Arrays.asList(12, 13, 10, 1), Arrays.asList(9, 3, 15, 6), Arrays.asList(5, 16, 14, 4), Arrays.asList(11, 8, 7, 2)), 12).equals(Arrays.asList(1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6)),\n s.minPath(Arrays.asList(Arrays.asList(2, 7, 4), Arrays.asList(3, 1, 5), Arrays.asList(6, 8, 9)), 8).equals(Arrays.asList(1, 3, 1, 3, 1, 3, 1, 3)),\n s.minPath(Arrays.asList(Arrays.asList(6, 1, 5), Arrays.asList(3, 8, 9), Arrays.asList(2, 7, 4)), 8).equals(Arrays.asList(1, 5, 1, 5, 1, 5, 1, 5)),\n s.minPath(Arrays.asList(Arrays.asList(1, 2), Arrays.asList(3, 4)), 10).equals(Arrays.asList(1, 2, 1, 2, 1, 2, 1, 2, 1, 2)),\n s.minPath(Arrays.asList(Arrays.asList(1, 3), Arrays.asList(3, 2)), 10).equals(Arrays.asList(1, 3, 1, 3, 1, 3, 1, 3, 1, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a grid with N rows and N columns (N >= 2) and a positive integer k,\n each cell of the grid contains a value. Every integer in the range [1, N * N]\n inclusive appears exactly once on the cells of the grid.\n\n You have to find the minimum path of length k in the grid. You can start\n from any cell, and in each step you can move to any of the neighbor cells,\n in other words, you can go to cells which share an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k cells (not\n necessarily distinct).\n You CANNOT go off the grid.\n A path A (of length k) is considered less than a path B (of length k) if\n after making the ordered lists of the values on the cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographically less\n than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Return an ordered list of the values on the cells that the minimum path go through.\n\n Examples:\n\n Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n Output: [1, 2, 1]\n\n Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n Output: [1]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List minPath(List> grid, int k) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.minPath(Arrays.asList(Arrays.asList(1, 2, 3), Arrays.asList(4, 5, 6), Arrays.asList(7, 8, 9)), 3).equals(Arrays.asList(1, 2, 1)),\n s.minPath(Arrays.asList(Arrays.asList(5, 9, 3), Arrays.asList(4, 1, 6), Arrays.asList(7, 8, 2)), 1).equals(List.of(1))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int n = grid.size();\n int val = n * n + 1;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (grid.get(i).get(j) == 1) {\n List temp = new ArrayList<>();\n if (i != 0) {\n temp.add(grid.get(i).get(j));\n }\n if (j != 0) {\n temp.add(grid.get(i).get(j));\n }\n if (i != n - 1) {\n temp.add(grid.get(i).get(j));\n }\n if (j != n - 1) {\n temp.add(grid.get(i).get(j));\n }\n val = Collections.min(temp);\n }\n }\n }\n List ans = new ArrayList<>();\n for (int i = 0; i < k; i++) {\n if (i == 0) {\n ans.add(1);\n } else {\n ans.add(val);\n }\n }\n return ans;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "minPath"} {"task_id": "Java/130", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in\n the last couple centuries. However, what people don't know is Tribonacci sequence.\n Tribonacci sequence is defined by the recurrence:\n tri(1) = 3\n tri(n) = 1 + n / 2, if n is even.\n tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.\n For example:\n tri(2) = 1 + (2 / 2) = 2\n tri(4) = 3\n tri(3) = tri(2) + tri(1) + tri(4)\n = 2 + 3 + 3 = 8\n You are given a non-negative integer number n, you have to a return a list of the\n first n + 1 numbers of the Tribonacci sequence.\n Examples:\n tri(3) = [1, 3, 2, 8]\n */\n public List tri(int n) {\n", "canonical_solution": " if (n == 0) {\n return List.of(1);\n }\n List my_tri = new ArrayList<>(Arrays.asList(1, 3));\n for (int i = 2; i <= n; i++) {\n if (i % 2 == 0) {\n my_tri.add(i / 2 + 1);\n } else {\n my_tri.add(my_tri.get(my_tri.size() - 1) + my_tri.get(my_tri.size() - 2) + (i + 3) / 2);\n }\n }\n return my_tri;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.tri(3).equals(Arrays.asList(1, 3, 2, 8)),\n s.tri(4).equals(Arrays.asList(1, 3, 2, 8, 3)),\n s.tri(5).equals(Arrays.asList(1, 3, 2, 8, 3, 15)),\n s.tri(6).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4)),\n s.tri(7).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4, 24)),\n s.tri(8).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4, 24, 5)),\n s.tri(9).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4, 24, 5, 35)),\n s.tri(20).equals(Arrays.asList(1, 3, 2, 8, 3, 15, 4, 24, 5, 35, 6, 48, 7, 63, 8, 80, 9, 99, 10, 120, 11)),\n s.tri(0).equals(List.of(1)),\n s.tri(1).equals(Arrays.asList(1, 3))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in\n the last couple centuries. However, what people don't know is Tribonacci sequence.\n Tribonacci sequence is defined by the recurrence:\n tri(1) = 3\n tri(n) = 1 + n / 2, if n is even.\n tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.\n For example:\n tri(2) = 1 + (2 / 2) = 2\n tri(4) = 3\n tri(3) = tri(2) + tri(1) + tri(4)\n = 2 + 3 + 3 = 8\n You are given a non-negative integer number n, you have to a return a list of the\n first n + 1 numbers of the Tribonacci sequence.\n Examples:\n tri(3) = [1, 3, 2, 8]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List tri(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.tri(3).equals(Arrays.asList(1, 3, 2, 8))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (n == 0) {\n return List.of(1);\n }\n List my_tri = new ArrayList<>(Arrays.asList(1, 3));\n for (int i = 2; i <= n; i++) {\n if (i % 2 == 0) {\n my_tri.add(i / 2 + 1);\n } else {\n my_tri.add(my_tri.get(my_tri.size() - 1) + my_tri.get(my_tri.size() - 2) + i + (i + 3) / 2);\n }\n }\n return my_tri;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "tri"} {"task_id": "Java/131", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n */\n public int digits(int n) {\n", "canonical_solution": " int product = 1, odd_count = 0;\n for (char digit : String.valueOf(n).toCharArray()) {\n int int_digit = digit - '0';\n if (int_digit % 2 == 1) {\n product *= int_digit;\n odd_count += 1;\n }\n }\n if (odd_count == 0) {\n return 0;\n } else {\n return product;\n }\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.digits(5) == 5,\n s.digits(54) == 5,\n s.digits(120) == 1,\n s.digits(5014) == 5,\n s.digits(98765) == 315,\n s.digits(5576543) == 2625\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int digits(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.digits(1) == 1,\n s.digits(4) == 0,\n s.digits(235) == 15\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int product = 1, odd_count = 0;\n for (char digit : String.valueOf(n).toCharArray()) {\n int int_digit = digit - '0';\n if (int_digit % 2 == 1) {\n product *= product*int_digit;\n odd_count += 1;\n }\n }\n if (odd_count == 0) {\n return 0;\n } else {\n return product;\n }\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "digits"} {"task_id": "Java/132", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function that takes a string as input which contains only square brackets.\n The function should return true if and only if there is a valid subsequence of brackets\n where at least one bracket in the subsequence is nested.\n\n isNested(\"[[]]\") -> true\n isNested(\"[]]]]]]][[[[[]\") -> false\n isNested(\"[][]\") -> false\n isNested(\"[]\") -> false\n isNested(\"[[][]]\") -> true\n isNested(\"[[]][[\") -> true\n */\n public boolean isNested(String string) {\n", "canonical_solution": " List opening_bracket_index = new ArrayList<>(), closing_bracket_index = new ArrayList<>();\n for (int i = 0; i < string.length(); i++) {\n if (string.charAt(i) == '[') {\n opening_bracket_index.add(i);\n } else {\n closing_bracket_index.add(i);\n }\n }\n Collections.reverse(closing_bracket_index);\n int i = 0, l = closing_bracket_index.size();\n for (int idx : opening_bracket_index) {\n if (i < l && idx < closing_bracket_index.get(i)) {\n i += 1;\n }\n }\n return i >= 2;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isNested(\"[[]]\" ),\n !s.isNested(\"[]]]]]]][[[[[]\" ),\n !s.isNested(\"[][]\" ),\n !s.isNested(\"[]\" ),\n s.isNested(\"[[[[]]]]\" ),\n !s.isNested(\"[]]]]]]]]]]\" ),\n s.isNested(\"[][][[]]\" ),\n !s.isNested(\"[[]\" ),\n !s.isNested(\"[]]\" ),\n s.isNested(\"[[]][[\" ),\n s.isNested(\"[[][]]\" ),\n !s.isNested(\"\" ),\n !s.isNested(\"[[[[[[[[\" ),\n !s.isNested(\"]]]]]]]]\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function that takes a string as input which contains only square brackets.\n The function should return true if and only if there is a valid subsequence of brackets\n where at least one bracket in the subsequence is nested.\n\n isNested(\"[[]]\") -> true\n isNested(\"[]]]]]]][[[[[]\") -> false\n isNested(\"[][]\") -> false\n isNested(\"[]\") -> false\n isNested(\"[[][]]\") -> true\n isNested(\"[[]][[\") -> true", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean isNested(String string) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isNested(\"[[]]\" ),\n !s.isNested(\"[]]]]]]][[[[[]\" ),\n !s.isNested(\"[][]\" ),\n !s.isNested(\"[]\" ),\n s.isNested(\"[[]][[\" ),\n s.isNested(\"[[][]]\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List opening_bracket_index = new ArrayList<>(), closing_bracket_index = new ArrayList<>();\n for (int i = 0; i < string.length(); i++) {\n if (string.charAt(i) == '(') {\n opening_bracket_index.add(i);\n } else {\n closing_bracket_index.add(i);\n }\n }\n Collections.reverse(closing_bracket_index);\n int i = 0, l = closing_bracket_index.size();\n for (int idx : opening_bracket_index) {\n if (i < l && idx < closing_bracket_index.get(i)) {\n i += 1;\n }\n }\n return i >= 2;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "isNested"} @@ -139,19 +139,19 @@ {"task_id": "Java/138", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers\n Example\n isEqualToSumEven(4) == false\n isEqualToSumEven(6) == false\n isEqualToSumEven(8) == true\n */\n public boolean isEqualToSumEven(int n) {\n", "canonical_solution": " return n % 2 == 0 && n >= 8;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isEqualToSumEven(4) == false,\n s.isEqualToSumEven(6) == false,\n s.isEqualToSumEven(8) == true,\n s.isEqualToSumEven(10) == true,\n s.isEqualToSumEven(11) == false,\n s.isEqualToSumEven(12) == true,\n s.isEqualToSumEven(13) == false,\n s.isEqualToSumEven(16) == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers\n Example\n isEqualToSumEven(4) == false\n isEqualToSumEven(6) == false\n isEqualToSumEven(8) == true", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean isEqualToSumEven(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.isEqualToSumEven(4) == false,\n s.isEqualToSumEven(6) == false,\n s.isEqualToSumEven(8) == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " return n % 2 == 0 && n >= 8 && n <= 8;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "isEqualToSumEven"} {"task_id": "Java/139", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n The Brazilian factorial is defined as:\n brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n where n > 0\n\n For example:\n >>> specialFactorial(4)\n 288\n\n The function will receive an integer as input and should return the special\n factorial of this integer.\n */\n public long specialFactorial(int n) {\n", "canonical_solution": " long fact_i = 1, special_fact = 1;\n for (int i = 1; i <= n; i++) {\n fact_i *= i;\n special_fact *= fact_i;\n }\n return special_fact;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.specialFactorial(4) == 288,\n s.specialFactorial(5) == 34560,\n s.specialFactorial(7) == 125411328000L,\n s.specialFactorial(1) == 1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " The Brazilian factorial is defined as:\n brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n where n > 0\n\n For example:\n >>> specialFactorial(4)\n 288\n\n The function will receive an integer as input and should return the special\n factorial of this integer.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public long specialFactorial(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.specialFactorial(4) == 288\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " long fact_i = 1, special_fact = 1;\n for (int i = 1; i <= n; i++) {\n i *= n;\n fact_i *= i;\n special_fact *= fact_i;\n }\n return special_fact;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "specialFactorial"} {"task_id": "Java/140", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a string text, replace all spaces in it with underscores,\n and if a string has more than 2 consecutive spaces,\n then replace all consecutive spaces with -\n\n fixSpaces(\"Example\") == \"Example\"\n fixSpaces(\"Example 1\") == \"Example_1\"\n fixSpaces(\" Example 2\") == \"_Example_2\"\n fixSpaces(\" Example 3\") == \"_Example-3\"\n */\n public String fixSpaces(String text) {\n", "canonical_solution": " StringBuilder sb = new StringBuilder();\n int start = 0, end = 0;\n for (int i = 0; i < text.length(); i++) {\n if (text.charAt(i) == ' ') {\n end += 1;\n } else {\n if (end - start > 2) {\n sb.append('-');\n } else if (end - start > 0) {\n sb.append(\"_\".repeat(end - start));\n }\n sb.append(text.charAt(i));\n start = i + 1;\n end = i + 1;\n }\n }\n if (end - start > 2) {\n sb.append('-');\n } else if (end - start > 0) {\n sb.append(\"_\".repeat(end - start));\n }\n return sb.toString();\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.fixSpaces(\"Example\" ), \"Example\" ),\n Objects.equals(s.fixSpaces(\"Mudasir Hanif \" ), \"Mudasir_Hanif_\" ),\n Objects.equals(s.fixSpaces(\"Yellow Yellow Dirty Fellow\" ), \"Yellow_Yellow__Dirty__Fellow\" ),\n Objects.equals(s.fixSpaces(\"Exa mple\" ), \"Exa-mple\" ),\n Objects.equals(s.fixSpaces(\" Exa 1 2 2 mple\" ), \"-Exa_1_2_2_mple\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a string text, replace all spaces in it with underscores,\n and if a string has more than 2 consecutive spaces,\n then replace all consecutive spaces with -\n\n fixSpaces(\"Example\") == \"Example\"\n fixSpaces(\"Example 1\") == \"Example_1\"\n fixSpaces(\" Example 2\") == \"_Example_2\"\n fixSpaces(\" Example 3\") == \"_Example-3\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String fixSpaces(String text) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.fixSpaces(\"Example\" ), \"Example\" ),\n Objects.equals(s.fixSpaces(\"Example 1\" ), \"Example_1\" ),\n Objects.equals(s.fixSpaces(\" Example 2\" ), \"_Example_2\" ),\n Objects.equals(s.fixSpaces(\" Example 3\" ), \"_Example-3\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " StringBuilder sb = new StringBuilder();\n int start = 0, end = 0;\n for (int i = 0; i < text.length(); i++) {\n if (text.charAt(i) == ' ') {\n end += 1;\n } else {\n if (end - start > 2) {\n sb.append('-');\n } else if (end - start > 0) {\n sb.append(\"_\".repeat(end - start));\n }\n sb.append(text.charAt(i));\n start = i + 1;\n end = i + 1;\n }\n }\n if (end - start > 2) {\n sb.append('-');\n } else if (end - start > 0) {\n sb.append(\"__\".repeat(end - start));\n }\n return sb.toString();\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "fixSpaces"} -{"task_id": "Java/141", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function which takes a string representing a file's name, and returns\n \"Yes\" if the the file's name is valid, and returns \"No\" otherwise.\n A file's name is considered to be valid if and only if all the following conditions\n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from\n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: [\"txt\", \"exe\", \"dll\"]\n Examples:\n file_name_check(\"example.txt\") # => \"Yes\"\n file_name_check(\"1example.dll\") # => \"No\" (the name should start with a latin alphapet letter)\n */\n public String filenameCheck(String file_name) {\n", "canonical_solution": " List suf = Arrays.asList(\"txt\", \"exe\", \"dll\");\n String[] lst = file_name.split(\"\\\\.\" );\n if (lst.length != 2 || !suf.contains(lst[1]) || lst[0].isEmpty() || !Character.isLetter(lst[0].charAt(0))) {\n return \"No\";\n }\n int t = (int) lst[0].chars().map(x -> (char) x).filter(Character::isDigit).count();\n if (t > 3) {\n return \"No\";\n }\n return \"Yes\";\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.filenameCheck(\"example.txt\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"1example.dll\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"s1sdf3.asd\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"K.dll\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"MY16FILE3.exe\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"His12FILE94.exe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"_Y.txt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"?aREYA.exe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"/this_is_valid.dll\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"this_is_valid.wow\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"this_is_valid.txt\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"this_is_valid.txtexe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"#this2_i4s_5valid.ten\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"@this1_is6_valid.exe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"this_is_12valid.6exe4.txt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"all.exe.txt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"I563_No.exe\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"Is3youfault.txt\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"no_one#knows.dll\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"1I563_Yes3.exe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"I563_Yes3.txtt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"final..txt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"final132\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"_f4indsartal132.\" ), \"No\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function which takes a string representing a file's name, and returns\n \"Yes\" if the the file's name is valid, and returns \"No\" otherwise.\n A file's name is considered to be valid if and only if all the following conditions\n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from\n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: [\"txt\", \"exe\", \"dll\"]\n Examples:\n file_name_check(\"example.txt\") # => \"Yes\"\n file_name_check(\"1example.dll\") # => \"No\" (the name should start with a latin alphapet letter)", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String filenameCheck(String file_name) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.filenameCheck(\"example.txt\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"1example.dll\" ), \"No\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List suf = Arrays.asList(\"txt\", \"exe\", \"dll\");\n String[] lst = file_name.split(\"\\\\.\" );\n if (lst.length != 2 || lst[0].isEmpty() || !Character.isLetter(lst[0].charAt(0))) {\n return \"No\";\n }\n int t = (int) lst[0].chars().map(x -> (char) x).filter(Character::isDigit).count();\n if (t > 3) {\n return \"No\";\n }\n return \"Yes\";\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "fileNameCheck"} +{"task_id": "Java/141", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Create a function which takes a string representing a file's name, and returns\n \"Yes\" if the the file's name is valid, and returns \"No\" otherwise.\n A file's name is considered to be valid if and only if all the following conditions\n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from\n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: [\"txt\", \"exe\", \"dll\"]\n Examples:\n file_name_check(\"example.txt\") # => \"Yes\"\n file_name_check(\"1example.dll\") # => \"No\" (the name should start with a latin alphapet letter)\n */\n public String filenameCheck(String file_name) {\n", "canonical_solution": " List suf = Arrays.asList(\"txt\", \"exe\", \"dll\");\n String[] lst = file_name.split(\"\\\\.\" );\n if (lst.length != 2 || !suf.contains(lst[1]) || lst[0].isEmpty() || !Character.isLetter(lst[0].charAt(0))) {\n return \"No\";\n }\n int t = (int) lst[0].chars().map(x -> (char) x).filter(Character::isDigit).count();\n if (t > 3) {\n return \"No\";\n }\n return \"Yes\";\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.filenameCheck(\"example.txt\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"1example.dll\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"s1sdf3.asd\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"K.dll\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"MY16FILE3.exe\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"His12FILE94.exe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"_Y.txt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"?aREYA.exe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"/this_is_valid.dll\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"this_is_valid.wow\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"this_is_valid.txt\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"this_is_valid.txtexe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"#this2_i4s_5valid.ten\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"@this1_is6_valid.exe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"this_is_12valid.6exe4.txt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"all.exe.txt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"I563_No.exe\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"Is3youfault.txt\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"no_one#knows.dll\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"1I563_Yes3.exe\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"I563_Yes3.txtt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"final..txt\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"final132\" ), \"No\" ),\n Objects.equals(s.filenameCheck(\"_f4indsartal132.\" ), \"No\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Create a function which takes a string representing a file's name, and returns\n \"Yes\" if the the file's name is valid, and returns \"No\" otherwise.\n A file's name is considered to be valid if and only if all the following conditions\n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The file's name contains exactly one dot '.'\n - The substring before the dot should not be empty, and it starts with a letter from\n the latin alphapet ('a'-'z' and 'A'-'Z').\n - The substring after the dot should be one of these: [\"txt\", \"exe\", \"dll\"]\n Examples:\n file_name_check(\"example.txt\") # => \"Yes\"\n file_name_check(\"1example.dll\") # => \"No\" (the name should start with a latin alphapet letter)", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String filenameCheck(String file_name) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.filenameCheck(\"example.txt\" ), \"Yes\" ),\n Objects.equals(s.filenameCheck(\"1example.dll\" ), \"No\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List suf = Arrays.asList(\"txt\", \"exe\", \"dll\");\n String[] lst = file_name.split(\"\\\\.\" );\n if (lst.length != 2 || lst[0].isEmpty() || !Character.isLetter(lst[0].charAt(0))) {\n return \"No\";\n }\n int t = (int) lst[0].chars().map(x -> (char) x).filter(Character::isDigit).count();\n if (t > 3) {\n return \"No\";\n }\n return \"Yes\";\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "filenameCheck"} {"task_id": "Java/142", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a\n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not\n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries.\n\n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126\n */\n public int sumSquares(List lst) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (int i = 0; i < lst.size(); i++) {\n if (i % 3 == 0) {\n result.add(lst.get(i) * lst.get(i));\n } else if (i % 4 == 0) {\n result.add((int) Math.pow(lst.get(i), 3));\n } else {\n result.add(lst.get(i));\n }\n }\n return result.stream().reduce(Integer::sum).orElse(0);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sumSquares(Arrays.asList(1,2,3)) == 6,\n s.sumSquares(Arrays.asList(1,4,9)) == 14,\n s.sumSquares(List.of()) == 0,\n s.sumSquares(Arrays.asList(1,1,1,1,1,1,1,1,1)) == 9,\n s.sumSquares(Arrays.asList(-1,-1,-1,-1,-1,-1,-1,-1,-1)) == -3,\n s.sumSquares(List.of(0)) == 0,\n s.sumSquares(Arrays.asList(-1,-5,2,-1,-5)) == -126,\n s.sumSquares(Arrays.asList(-56,-99,1,0,-2)) == 3030,\n s.sumSquares(Arrays.asList(-1,0,0,0,0,0,0,0,-1)) == 0,\n s.sumSquares(Arrays.asList(-16, -9, -2, 36, 36, 26, -20, 25, -40, 20, -4, 12, -26, 35, 37)) == -14196,\n s.sumSquares(Arrays.asList(-1, -3, 17, -1, -15, 13, -1, 14, -14, -12, -5, 14, -14, 6, 13, 11, 16, 16, 4, 10)) == -1448\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a\n multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not\n change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries.\n\n Examples:\n For lst = [1,2,3] the output should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the output should be -126", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int sumSquares(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.sumSquares(Arrays.asList(1,2,3)) == 6,\n s.sumSquares(List.of()) == 0,\n s.sumSquares(Arrays.asList(-1,-5,2,-1,-5)) == -126\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (int i = 0; i < lst.size(); i++) {\n if (i % 3 == 0) {\n result.add(lst.get(i) * lst.get(i));\n } else {\n result.add(lst.get(i));\n }\n }\n return result.stream().reduce(Integer::sum).orElse(0);\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "sumSquares"} {"task_id": "Java/143", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n */\n public String wordsInSentence(String sentence) {\n", "canonical_solution": " List new_lst = new ArrayList<>();\n for (String word : sentence.split(\" \" )) {\n boolean flg = true;\n if (word.length() == 1) {\n continue;\n }\n for (int i = 2; i < word.length(); i++) {\n if (word.length() % i == 0) {\n flg = false;\n break;\n }\n }\n if (flg) {\n new_lst.add(word);\n }\n }\n return String.join(\" \", new_lst);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.wordsInSentence(\"This is a test\" ), \"is\" ),\n Objects.equals(s.wordsInSentence(\"lets go for swimming\" ), \"go for\" ),\n Objects.equals(s.wordsInSentence(\"there is no place available here\" ), \"there is no place\" ),\n Objects.equals(s.wordsInSentence(\"Hi I am Hussein\" ), \"Hi am Hussein\" ),\n Objects.equals(s.wordsInSentence(\"go for it\" ), \"go for it\" ),\n Objects.equals(s.wordsInSentence(\"here\" ), \"\" ),\n Objects.equals(s.wordsInSentence(\"here is\" ), \"is\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a string that contains the words from the original sentence,\n whose lengths are prime numbers,\n the order of the words in the new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a test\"\n Output: \"is\"\n\n Example 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"go for\"\n\n Constraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String wordsInSentence(String sentence) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.wordsInSentence(\"This is a test\" ), \"is\" ),\n Objects.equals(s.wordsInSentence(\"lets go for swimming\" ), \"go for\" )\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List new_lst = new ArrayList<>();\n for (String word : sentence.split(\" \" )) {\n boolean flg = true;\n for (int i = 2; i < word.length(); i++) {\n if (word.length() % i == 0) {\n flg = false;\n break;\n }\n }\n if (flg) {\n new_lst.add(word);\n }\n }\n return String.join(\" \", new_lst);\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "wordsInSentence"} {"task_id": "Java/144", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Your task is to implement a function that will simplify the expression\n x * n. The function returns true if x * n evaluates to a whole number and false\n otherwise. Both x and n, are string representation of a fraction, and have the following format,\n / where both numerator and denominator are positive whole numbers.\n\n You can assume that x, and n are valid fractions, and do not have zero as denominator.\n\n simplify(\"1/5\", \"5/1\") = true\n simplify(\"1/6\", \"2/1\") = false\n simplify(\"7/10\", \"10/2\") = false\n */\n public boolean simplify(String x, String n) {\n", "canonical_solution": " String[] a = x.split(\"/\");\n String[] b = n.split(\"/\");\n int numerator = Integer.parseInt(a[0]) * Integer.parseInt(b[0]);\n int denom = Integer.parseInt(a[1]) * Integer.parseInt(b[1]);\n return numerator / denom * denom == numerator;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.simplify(\"1/5\", \"5/1\") == true,\n s.simplify(\"1/6\", \"2/1\") == false,\n s.simplify(\"5/1\", \"3/1\") == true,\n s.simplify(\"7/10\", \"10/2\") == false,\n s.simplify(\"2/10\", \"50/10\") == true,\n s.simplify(\"7/2\", \"4/2\") == true,\n s.simplify(\"11/6\", \"6/1\") == true,\n s.simplify(\"2/3\", \"5/2\") == false,\n s.simplify(\"5/2\", \"3/5\") == false,\n s.simplify(\"2/4\", \"8/4\") == true,\n s.simplify(\"2/4\", \"4/2\") == true,\n s.simplify(\"1/5\", \"5/1\") == true,\n s.simplify(\"1/5\", \"1/5\") == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Your task is to implement a function that will simplify the expression\n x * n. The function returns true if x * n evaluates to a whole number and false\n otherwise. Both x and n, are string representation of a fraction, and have the following format,\n / where both numerator and denominator are positive whole numbers.\n\n You can assume that x, and n are valid fractions, and do not have zero as denominator.\n\n simplify(\"1/5\", \"5/1\") = true\n simplify(\"1/6\", \"2/1\") = false\n simplify(\"7/10\", \"10/2\") = false", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean simplify(String x, String n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.simplify(\"1/5\", \"5/1\") == true,\n s.simplify(\"1/6\", \"2/1\") == false,\n s.simplify(\"7/10\", \"10/2\") == false\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String[] a = x.split(\"/\");\n String[] b = n.split(\"/\");\n int numerator = Integer.parseInt(a[0]) * Integer.parseInt(b[0]);\n int denom = Integer.parseInt(a[1]) * Integer.parseInt(b[1]) * numerator;\n return numerator / denom * denom == numerator;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "simplify"} {"task_id": "Java/145", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> orderByPoints(Arrays.asList(1, 11, -1, -11, -12)) == [-1, -11, 1, -12, 11]\n >>> orderByPoints(Arrays.asList()) == []\n */\n public List orderByPoints(List nums) {\n", "canonical_solution": " List result = new ArrayList<>(nums);\n result.sort((o1, o2) -> {\n int sum1 = 0;\n int sum2 = 0;\n\n for (int i = 0; i < String.valueOf(o1).length(); i++) {\n if (i != 0 || o1 >= 0) {\n sum1 += (String.valueOf(o1).charAt(i) - '0' );\n if (i == 1 && o1 < 0) {\n sum1 = -sum1;\n }\n }\n }\n for (int i = 0; i < String.valueOf(o2).length(); i++) {\n if (i != 0 || o2 >= 0) {\n sum2 += (String.valueOf(o2).charAt(i) - '0' );\n if (i == 1 && o2 < 0) {\n sum2 = -sum2;\n }\n }\n }\n return Integer.compare(sum1, sum2);\n });\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.orderByPoints(new ArrayList<>(Arrays.asList(1, 11, -1, -11, -12))).equals(Arrays.asList(-1, -11, 1, -12, 11)),\n s.orderByPoints(new ArrayList<>(Arrays.asList(1234, 423, 463, 145, 2, 423, 423, 53, 6, 37, 3457, 3, 56, 0, 46))).equals(Arrays.asList(0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457)),\n s.orderByPoints(new ArrayList<>(List.of())).equals(List.of()),\n s.orderByPoints(new ArrayList<>(Arrays.asList(1, -11, -32, 43, 54, -98, 2, -3))).equals(Arrays.asList(-3, -32, -98, -11, 1, 2, 43, 54)),\n s.orderByPoints(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11))).equals(Arrays.asList(1, 10, 2, 11, 3, 4, 5, 6, 7, 8, 9)),\n s.orderByPoints(new ArrayList<>(Arrays.asList(0, 6, 6, -76, -21, 23, 4))).equals(Arrays.asList(-76, -21, 0, 4, 23, 6, 6))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function which sorts the given list of integers\n in ascending order according to the sum of their digits.\n Note: if there are several items with similar sum of their digits,\n order them based on their index in original list.\n\n For example:\n >>> orderByPoints(Arrays.asList(1, 11, -1, -11, -12)) == [-1, -11, 1, -12, 11]\n >>> orderByPoints(Arrays.asList()) == []", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List orderByPoints(List nums) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.orderByPoints(new ArrayList<>(Arrays.asList(1, 11, -1, -11, -12))).equals(Arrays.asList(-1, -11, 1, -12, 11)),\n s.orderByPoints(new ArrayList<>(List.of())).equals(List.of())\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>(nums);\n result.sort((o1, o2) -> {\n int sum1 = 0;\n int sum2 = 0;\n\n for (int i = 0; i < String.valueOf(o1).length(); i++) {\n if (i != 0 || o1 >= 0) {\n sum1 += (String.valueOf(o1).charAt(i) - '0' );\n if (i == 1 && o1 < 0) {\n sum1 = -sum1;\n }\n }\n }\n for (int i = 0; i < String.valueOf(o2).length(); i++) {\n if (i != 0 || o2 >= 0) {\n sum2 += (String.valueOf(o2).charAt(i) - '0' );\n if (i == 1 && o2 < 0) {\n sum2 = -sum2 + sum1;\n }\n }\n }\n return Integer.compare(sum1, sum2);\n });\n return result;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "orderByPoints"} -{"task_id": "Java/146", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function that takes an array of numbers as input and returns\n the number of elements in the array that are greater than 10 and both\n first and last digits of a number are odd (1, 3, 5, 7, 9).\n For example:\n specialFilter(Arrays.asList(15, -73, 14, -15)) => 1\n specialFilter(Arrays.asList(33, -2, -3, 45, 21, 109)) => 2\n */\n public int specialFilter(List nums) {\n", "canonical_solution": " int count = 0;\n for (int num : nums) {\n if (num > 10) {\n String odd_digits = \"13579\";\n String number_as_string = String.valueOf(num);\n if (odd_digits.indexOf(number_as_string.charAt(0)) != -1 && odd_digits.indexOf(number_as_string.charAt(number_as_string.length() - 1)) != -1) {\n count += 1;\n }\n }\n }\n return count;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.specialFilter(Arrays.asList(5, -2, 1, -5)) == 0,\n s.specialFilter(Arrays.asList(15, -73, 14, -15)) == 1,\n s.specialFilter(Arrays.asList(33, -2, -3, 45, 21, 109)) == 2,\n s.specialFilter(Arrays.asList(43, -12, 93, 125, 121, 109)) == 4,\n s.specialFilter(Arrays.asList(71, -2, -33, 75, 21, 19)) == 3,\n s.specialFilter(List.of(1)) == 0,\n s.specialFilter(List.of()) == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function that takes an array of numbers as input and returns\n the number of elements in the array that are greater than 10 and both\n first and last digits of a number are odd (1, 3, 5, 7, 9).\n For example:\n specialFilter(Arrays.asList(15, -73, 14, -15)) => 1\n specialFilter(Arrays.asList(33, -2, -3, 45, 21, 109)) => 2", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int specialFilter(List nums) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.specialFilter(Arrays.asList(15, -73, 14, -15)) == 1,\n s.specialFilter(Arrays.asList(33, -2, -3, 45, 21, 109)) == 2\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int count = 0;\n for (int num : nums) {\n if (num > 10) {\n String odd_digits = \"123579\";\n String number_as_string = String.valueOf(num);\n if (odd_digits.indexOf(number_as_string.charAt(0)) != -1 && odd_digits.indexOf(number_as_string.charAt(number_as_string.length() - 1)) != -1) {\n count += 1;\n }\n }\n }\n return count;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "specialfilter"} +{"task_id": "Java/146", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function that takes an array of numbers as input and returns\n the number of elements in the array that are greater than 10 and both\n first and last digits of a number are odd (1, 3, 5, 7, 9).\n For example:\n specialFilter(Arrays.asList(15, -73, 14, -15)) => 1\n specialFilter(Arrays.asList(33, -2, -3, 45, 21, 109)) => 2\n */\n public int specialFilter(List nums) {\n", "canonical_solution": " int count = 0;\n for (int num : nums) {\n if (num > 10) {\n String odd_digits = \"13579\";\n String number_as_string = String.valueOf(num);\n if (odd_digits.indexOf(number_as_string.charAt(0)) != -1 && odd_digits.indexOf(number_as_string.charAt(number_as_string.length() - 1)) != -1) {\n count += 1;\n }\n }\n }\n return count;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.specialFilter(Arrays.asList(5, -2, 1, -5)) == 0,\n s.specialFilter(Arrays.asList(15, -73, 14, -15)) == 1,\n s.specialFilter(Arrays.asList(33, -2, -3, 45, 21, 109)) == 2,\n s.specialFilter(Arrays.asList(43, -12, 93, 125, 121, 109)) == 4,\n s.specialFilter(Arrays.asList(71, -2, -33, 75, 21, 19)) == 3,\n s.specialFilter(List.of(1)) == 0,\n s.specialFilter(List.of()) == 0\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function that takes an array of numbers as input and returns\n the number of elements in the array that are greater than 10 and both\n first and last digits of a number are odd (1, 3, 5, 7, 9).\n For example:\n specialFilter(Arrays.asList(15, -73, 14, -15)) => 1\n specialFilter(Arrays.asList(33, -2, -3, 45, 21, 109)) => 2", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int specialFilter(List nums) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.specialFilter(Arrays.asList(15, -73, 14, -15)) == 1,\n s.specialFilter(Arrays.asList(33, -2, -3, 45, 21, 109)) == 2\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int count = 0;\n for (int num : nums) {\n if (num > 10) {\n String odd_digits = \"123579\";\n String number_as_string = String.valueOf(num);\n if (odd_digits.indexOf(number_as_string.charAt(0)) != -1 && odd_digits.indexOf(number_as_string.charAt(number_as_string.length() - 1)) != -1) {\n count += 1;\n }\n }\n }\n return count;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "specialFilter"} {"task_id": "Java/147", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 <= i <= n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,\n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation:\n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n */\n public int getMaxTriples(int n) {\n", "canonical_solution": " List A = new ArrayList<>();\n for (int i = 1; i <= n; i++) {\n A.add(i * i - i + 1);\n }\n int count = 0;\n for (int i = 0; i < A.size(); i++) {\n for (int j = i + 1; j < A.size(); j++) {\n for (int k = j + 1; k < A.size(); k++) {\n if ((A.get(i) + A.get(j) + A.get(k)) % 3 == 0) {\n count += 1;\n }\n }\n }\n }\n return count;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.getMaxTriples(5) == 1,\n s.getMaxTriples(6) == 4,\n s.getMaxTriples(10) == 36,\n s.getMaxTriples(100) == 53361\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 <= i <= n), the value of a[i] = i * i - i + 1.\n Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,\n and a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation:\n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int getMaxTriples(int n) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.getMaxTriples(5) == 1\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List A = new ArrayList<>();\n for (int i = 1; i <= n; i++) {\n A.add(i * i);\n }\n int count = 0;\n for (int i = 0; i < A.size(); i++) {\n for (int j = i + 1; j < A.size(); j++) {\n for (int k = j + 1; k < A.size(); k++) {\n if ((A.get(i) + A.get(j) + A.get(k)) % 3 == 0) {\n count += 1;\n }\n }\n }\n }\n return count;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "getMaxTriples"} {"task_id": "Java/148", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n There are eight planets in our solar system: the closerst to the Sun\n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,\n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2.\n The function should return a tuple containing all planets whose orbits are\n located between the orbit of planet1 and the orbit of planet2, sorted by\n the proximity to the sun.\n The function should return an empty tuple if planet1 or planet2\n are not correct planet names.\n Examples\n bf(\"Jupiter\", \"Neptune\") ==> [\"Saturn\", \"Uranus\"]\n bf(\"Earth\", \"Mercury\") ==> [\"Venus\"]\n bf(\"Mercury\", \"Uranus\") ==> [\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\"]\n */\n public List bf(String planet1, String planet2) {\n", "canonical_solution": " List planet_names = Arrays.asList(\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\");\n if (!planet_names.contains(planet1) || !planet_names.contains(planet2) || planet1.equals(planet2)) {\n return List.of();\n }\n int planet1_index = planet_names.indexOf(planet1);\n int planet2_index = planet_names.indexOf(planet2);\n if (planet1_index < planet2_index) {\n return planet_names.subList(planet1_index + 1, planet2_index);\n } else {\n return planet_names.subList(planet2_index + 1, planet1_index);\n }\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.bf(\"Jupiter\", \"Neptune\").equals(Arrays.asList(\"Saturn\", \"Uranus\")),\n s.bf(\"Earth\", \"Mercury\").equals(List.of(\"Venus\")),\n s.bf(\"Mercury\", \"Uranus\").equals(Arrays.asList(\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")),\n s.bf(\"Neptune\", \"Venus\").equals(Arrays.asList(\"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\")),\n s.bf(\"Earth\", \"Earth\").equals(List.of()),\n s.bf(\"Mars\", \"Earth\").equals(List.of()),\n s.bf(\"Jupiter\", \"Makemake\").equals(List.of())\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " There are eight planets in our solar system: the closerst to the Sun\n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,\n Uranus, Neptune.\n Write a function that takes two planet names as strings planet1 and planet2.\n The function should return a tuple containing all planets whose orbits are\n located between the orbit of planet1 and the orbit of planet2, sorted by\n the proximity to the sun.\n The function should return an empty tuple if planet1 or planet2\n are not correct planet names.\n Examples\n bf(\"Jupiter\", \"Neptune\") ==> [\"Saturn\", \"Uranus\"]\n bf(\"Earth\", \"Mercury\") ==> [\"Venus\"]\n bf(\"Mercury\", \"Uranus\") ==> [\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List bf(String planet1, String planet2) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.bf(\"Jupiter\", \"Neptune\").equals(Arrays.asList(\"Saturn\", \"Uranus\")),\n s.bf(\"Earth\", \"Mercury\").equals(List.of(\"Venus\")),\n s.bf(\"Mercury\", \"Uranus\").equals(Arrays.asList(\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\"))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List planet_names = Arrays.asList(\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupyter\", \"Saturn\", \"Uranus\", \"Neptune\");\n if (!planet_names.contains(planet1) || !planet_names.contains(planet2) || planet1.equals(planet2)) {\n return List.of();\n }\n int planet1_index = planet_names.indexOf(planet1);\n int planet2_index = planet_names.indexOf(planet2);\n if (planet1_index < planet2_index) {\n return planet_names.subList(planet1_index + 1, planet2_index);\n } else {\n return planet_names.subList(planet2_index + 1, planet1_index);\n }\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "bf"} -{"task_id": "Java/149", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert listSort(Arrays.asList(\"aa\", \"a\", \"aaa\")) => [\"aa\"]\n assert listSort(Arrays.asList(\"ab\", \"a\", \"aaa\", \"cd\")) => [\"ab\", \"cd\"]\n */\n public List listSort(List lst) {\n", "canonical_solution": " List lst_sorted = new ArrayList<>(lst);\n Collections.sort(lst_sorted);\n List new_lst = new ArrayList<>();\n for (String i : lst_sorted) {\n if (i.length() % 2 == 0) {\n new_lst.add(i);\n }\n }\n new_lst.sort(Comparator.comparingInt(String::length));\n return new_lst;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.listSort(new ArrayList<>(Arrays.asList(\"aa\", \"a\", \"aaa\"))).equals(List.of(\"aa\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"school\", \"AI\", \"asdf\", \"b\"))).equals(Arrays.asList(\"AI\", \"asdf\", \"school\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"d\", \"b\", \"c\", \"a\"))).equals(List.of()),\n s.listSort(new ArrayList<>(Arrays.asList(\"d\", \"dcba\", \"abcd\", \"a\"))).equals(Arrays.asList(\"abcd\", \"dcba\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"AI\", \"ai\", \"au\"))).equals(Arrays.asList(\"AI\", \"ai\", \"au\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"a\", \"b\", \"b\", \"c\", \"c\", \"a\"))).equals(List.of()),\n s.listSort(new ArrayList<>(Arrays.asList(\"aaaa\", \"bbbb\", \"dd\", \"cc\"))).equals(Arrays.asList(\"cc\", \"dd\", \"aaaa\", \"bbbb\"))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert listSort(Arrays.asList(\"aa\", \"a\", \"aaa\")) => [\"aa\"]\n assert listSort(Arrays.asList(\"ab\", \"a\", \"aaa\", \"cd\")) => [\"ab\", \"cd\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List listSort(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.listSort(new ArrayList<>(Arrays.asList(\"aa\", \"a\", \"aaa\"))).equals(List.of(\"aa\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"ab\", \"a\", \"aaa\", \"cd\"))).equals(Arrays.asList(\"ab\", \"cd\"))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List lst_sorted = new ArrayList<>(lst);\n Collections.sort(lst_sorted);\n List new_lst = new ArrayList<>();\n for (String i : lst_sorted) {\n if (i.length() % 2 == 0) {\n new_lst.add(i);\n }\n }\n return new_lst;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "sortedListSum"} +{"task_id": "Java/149", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert listSort(Arrays.asList(\"aa\", \"a\", \"aaa\")) => [\"aa\"]\n assert listSort(Arrays.asList(\"ab\", \"a\", \"aaa\", \"cd\")) => [\"ab\", \"cd\"]\n */\n public List listSort(List lst) {\n", "canonical_solution": " List lst_sorted = new ArrayList<>(lst);\n Collections.sort(lst_sorted);\n List new_lst = new ArrayList<>();\n for (String i : lst_sorted) {\n if (i.length() % 2 == 0) {\n new_lst.add(i);\n }\n }\n new_lst.sort(Comparator.comparingInt(String::length));\n return new_lst;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.listSort(new ArrayList<>(Arrays.asList(\"aa\", \"a\", \"aaa\"))).equals(List.of(\"aa\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"school\", \"AI\", \"asdf\", \"b\"))).equals(Arrays.asList(\"AI\", \"asdf\", \"school\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"d\", \"b\", \"c\", \"a\"))).equals(List.of()),\n s.listSort(new ArrayList<>(Arrays.asList(\"d\", \"dcba\", \"abcd\", \"a\"))).equals(Arrays.asList(\"abcd\", \"dcba\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"AI\", \"ai\", \"au\"))).equals(Arrays.asList(\"AI\", \"ai\", \"au\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"a\", \"b\", \"b\", \"c\", \"c\", \"a\"))).equals(List.of()),\n s.listSort(new ArrayList<>(Arrays.asList(\"aaaa\", \"bbbb\", \"dd\", \"cc\"))).equals(Arrays.asList(\"cc\", \"dd\", \"aaaa\", \"bbbb\"))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert listSort(Arrays.asList(\"aa\", \"a\", \"aaa\")) => [\"aa\"]\n assert listSort(Arrays.asList(\"ab\", \"a\", \"aaa\", \"cd\")) => [\"ab\", \"cd\"]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List listSort(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.listSort(new ArrayList<>(Arrays.asList(\"aa\", \"a\", \"aaa\"))).equals(List.of(\"aa\")),\n s.listSort(new ArrayList<>(Arrays.asList(\"ab\", \"a\", \"aaa\", \"cd\"))).equals(Arrays.asList(\"ab\", \"cd\"))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List lst_sorted = new ArrayList<>(lst);\n Collections.sort(lst_sorted);\n List new_lst = new ArrayList<>();\n for (String i : lst_sorted) {\n if (i.length() % 2 == 0) {\n new_lst.add(i);\n }\n }\n return new_lst;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "listSort"} {"task_id": "Java/150", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n A simple program which should return the value of x if n is\n a prime number and should return the value of y otherwise.\n\n Examples:\n for xOrY(7, 34, 12) == 34\n for xOrY(15, 8, 5) == 5\n */\n public int xOrY(int n, int x, int y) {\n", "canonical_solution": " if (n == 1) {\n return y;\n }\n for (int i = 2; i < n; i++) {\n if (n % i == 0) {\n return y;\n }\n }\n return x;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.xOrY(7, 34, 12) == 34,\n s.xOrY(15, 8, 5) == 5,\n s.xOrY(3, 33, 5212) == 33,\n s.xOrY(1259, 3, 52) == 3,\n s.xOrY(7919, -1, 12) == -1,\n s.xOrY(3609, 1245, 583) == 583,\n s.xOrY(91, 56, 129) == 129,\n s.xOrY(6, 34, 1234) == 1234,\n s.xOrY(1, 2, 0) == 0,\n s.xOrY(2, 2, 0) == 2\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " A simple program which should return the value of x if n is\n a prime number and should return the value of y otherwise.\n\n Examples:\n for xOrY(7, 34, 12) == 34\n for xOrY(15, 8, 5) == 5", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int xOrY(int n, int x, int y) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.xOrY(7, 34, 12) == 34,\n s.xOrY(15, 8, 5) == 5\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " if (n == 1) {\n return y;\n }\n for (int i = 2; i < n; i++) {\n if (n % i - 1 == 0) {\n return y;\n }\n }\n return x;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "xOrY"} {"task_id": "Java/151", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n\n doubleTheDifference(Arrays.asList(1, 3, 2, 0)) == 1 + 9 + 0 + 0 = 10\n doubleTheDifference(Arrays.asList(-1, -2, 0)) == 0\n doubleTheDifference(Arrays.asList(9, -2)) == 81\n doubleTheDifference(Arrays.asList(0)) == 0\n\n If the input list is empty, return 0.\n */\n public int doubleTheDifference(List lst) {\n", "canonical_solution": " return lst.stream().filter(i -> i instanceof Integer p && p > 0 && p % 2 != 0).map(i -> (Integer) i * (Integer) i).reduce(Integer::sum).orElse(0);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.doubleTheDifference(List.of()) == 0,\n s.doubleTheDifference(Arrays.asList(5, 4)) == 25,\n s.doubleTheDifference(Arrays.asList(0.1, 0.2, 0.3)) == 0,\n s.doubleTheDifference(Arrays.asList(-10, -20, -30)) == 0,\n s.doubleTheDifference(Arrays.asList(-1, -2, 8)) == 0,\n s.doubleTheDifference(Arrays.asList(0.2, 3, 5)) == 34\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n List lst = new ArrayList<>();\n for (int i = -99; i < 100; i += 2) {\n lst.add(i);\n }\n int odd_sum = lst.stream().filter(i -> i instanceof Integer p && p % 2 != 0 && p > 0).map(i -> (Integer) i * (Integer) i).reduce(Integer::sum).orElse(0);\n assert s.doubleTheDifference(lst) == odd_sum;\n }\n}", "text": " Given a list of numbers, return the sum of squares of the numbers\n in the list that are odd. Ignore numbers that are negative or not integers.\n\n doubleTheDifference(Arrays.asList(1, 3, 2, 0)) == 1 + 9 + 0 + 0 = 10\n doubleTheDifference(Arrays.asList(-1, -2, 0)) == 0\n doubleTheDifference(Arrays.asList(9, -2)) == 81\n doubleTheDifference(Arrays.asList(0)) == 0\n\n If the input list is empty, return 0.", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public int doubleTheDifference(List lst) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.doubleTheDifference(Arrays.asList(1,3,2,0)) == 10,\n s.doubleTheDifference(Arrays.asList(-1,-2,0)) == 0,\n s.doubleTheDifference(Arrays.asList(9,-2)) == 81,\n s.doubleTheDifference(Arrays.asList(0)) == 0\n );\n }\n}\n", "buggy_solution": " return lst.stream().filter(i -> i instanceof Integer p && p > 0).map(i -> (Integer) i * (Integer) i).reduce(Integer::sum).orElse(0);\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "doubleTheDifference"} {"task_id": "Java/152", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n I think we all remember that feeling when the result of some long-awaited\n event is finally known. The feelings and thoughts you have at that moment are\n definitely worth noting down and comparing.\n Your task is to determine if a person correctly guessed the results of a number of matches.\n You are given two arrays of scores and guesses of equal length, where each index shows a match.\n Return an array of the same length denoting how far off each guess was. If they have guessed correctly,\n the value is 0, and if not, the value is the absolute difference between the guess and the score.\n\n example:\n\n compare(Arrays.asList(1,2,3,4,5,1),Arrays.asList(1,2,3,4,2,-2)) -> [0,0,0,0,3,3]\n compare(Arrays.asList(0,5,0,0,0,4),Arrays.asList(4,1,1,0,0,-2)) -> [4,4,1,0,0,6]\n */\n public List compare(List game, List guess) {\n", "canonical_solution": " List result = new ArrayList<>();\n for (int i = 0; i < game.size(); i++) {\n result.add(Math.abs(game.get(i) - guess.get(i)));\n }\n return result;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.compare(Arrays.asList(1, 2, 3, 4, 5, 1), Arrays.asList(1, 2, 3, 4, 2, -2)).equals(Arrays.asList(0, 0, 0, 0, 3, 3)),\n s.compare(Arrays.asList(0,5,0,0,0,4), Arrays.asList(4,1,1,0,0,-2)).equals(Arrays.asList(4,4,1,0,0,6)),\n s.compare(Arrays.asList(1, 2, 3, 4, 5, 1), Arrays.asList(1, 2, 3, 4, 2, -2)).equals(Arrays.asList(0, 0, 0, 0, 3, 3)),\n s.compare(Arrays.asList(0, 0, 0, 0, 0, 0), Arrays.asList(0, 0, 0, 0, 0, 0)).equals(Arrays.asList(0, 0, 0, 0, 0, 0)),\n s.compare(Arrays.asList(1, 2, 3), Arrays.asList(-1, -2, -3)).equals(Arrays.asList(2, 4, 6)),\n s.compare(Arrays.asList(1, 2, 3, 5), Arrays.asList(-1, 2, 3, 4)).equals(Arrays.asList(2, 0, 0, 1))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " I think we all remember that feeling when the result of some long-awaited\n event is finally known. The feelings and thoughts you have at that moment are\n definitely worth noting down and comparing.\n Your task is to determine if a person correctly guessed the results of a number of matches.\n You are given two arrays of scores and guesses of equal length, where each index shows a match.\n Return an array of the same length denoting how far off each guess was. If they have guessed correctly,\n the value is 0, and if not, the value is the absolute difference between the guess and the score.\n\n example:\n\n compare(Arrays.asList(1,2,3,4,5,1),Arrays.asList(1,2,3,4,2,-2)) -> [0,0,0,0,3,3]\n compare(Arrays.asList(0,5,0,0,0,4),Arrays.asList(4,1,1,0,0,-2)) -> [4,4,1,0,0,6]", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List compare(List game, List guess) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.compare(Arrays.asList(1, 2, 3, 4, 5, 1), Arrays.asList(1, 2, 3, 4, 2, -2)).equals(Arrays.asList(0, 0, 0, 0, 3, 3)),\n s.compare(Arrays.asList(0,5,0,0,0,4), Arrays.asList(4,1,1,0,0,-2)).equals(Arrays.asList(4,4,1,0,0,6))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List result = new ArrayList<>();\n for (int i = 0; i < game.size(); i++) {\n result.add(Math.abs(game.get(i) - guess.get(i))+Math.abs(guess.get(i) - game.get(i)));\n }\n return result;\n }\n}", "bug_type": "excess logic", "failure_symptoms": "incorrect output", "entry_point": "compare"} -{"task_id": "Java/153", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You will be given the name of a class (a string) and a list of extensions.\n The extensions are to be used to load additional classes to the class. The\n strength of the extension is as follows: Let CAP be the number of the uppercase\n letters in the extension's name, and let SM be the number of lowercase letters\n in the extension's name, the strength is given by the fraction CAP - SM.\n You should find the strongest extension and return a string in this\n format: ClassName.StrongestExtensionName.\n If there are two or more extensions with the same strength, you should\n choose the one that comes first in the list.\n For example, if you are given \"Slices\" as the class and a list of the\n extensions: [\"SErviNGSliCes\", \"Cheese\", \"StuFfed\"] then you should\n return \"Slices.SErviNGSliCes\" since \"SErviNGSliCes\" is the strongest extension\n (its strength is -1).\n Example:\n for StrongestExtension(\"my_class\", [\"AA\", \"Be\", \"CC\"]) == \"my_class.AA\"\n */\n public String StrongestExtension(String class_name, List extensions) {\n", "canonical_solution": " String strong = extensions.get(0);\n int my_val = (int) (strong.chars().filter(Character::isUpperCase).count() - strong.chars().filter(Character::isLowerCase).count());\n for (String s : extensions) {\n int val = (int) (s.chars().filter(Character::isUpperCase).count() - s.chars().filter(Character::isLowerCase).count());\n if (val > my_val) {\n strong = s;\n my_val = val;\n }\n }\n return class_name + \".\" + strong;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.StrongestExtension(\"Watashi\", Arrays.asList(\"tEN\", \"niNE\", \"eIGHt8OKe\")), \"Watashi.eIGHt8OKe\"),\n Objects.equals(s.StrongestExtension(\"Boku123\", Arrays.asList(\"nani\", \"NazeDa\", \"YEs.WeCaNe\", \"32145tggg\")), \"Boku123.YEs.WeCaNe\"),\n Objects.equals(s.StrongestExtension(\"__YESIMHERE\", Arrays.asList(\"t\", \"eMptY\", \"nothing\", \"zeR00\", \"NuLl__\", \"123NoooneB321\")), \"__YESIMHERE.NuLl__\"),\n Objects.equals(s.StrongestExtension(\"K\", Arrays.asList(\"Ta\", \"TAR\", \"t234An\", \"cosSo\")), \"K.TAR\"),\n Objects.equals(s.StrongestExtension(\"__HAHA\", Arrays.asList(\"Tab\", \"123\", \"781345\", \"-_-\")), \"__HAHA.123\"),\n Objects.equals(s.StrongestExtension(\"YameRore\", Arrays.asList(\"HhAas\", \"okIWILL123\", \"WorkOut\", \"Fails\", \"-_-\")), \"YameRore.okIWILL123\"),\n Objects.equals(s.StrongestExtension(\"finNNalLLly\", Arrays.asList(\"Die\", \"NowW\", \"Wow\", \"WoW\")), \"finNNalLLly.WoW\"),\n Objects.equals(s.StrongestExtension(\"_\", Arrays.asList(\"Bb\", \"91245\")), \"_.Bb\"),\n Objects.equals(s.StrongestExtension(\"Sp\", Arrays.asList(\"671235\", \"Bb\")), \"Sp.671235\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You will be given the name of a class (a string) and a list of extensions.\n The extensions are to be used to load additional classes to the class. The\n strength of the extension is as follows: Let CAP be the number of the uppercase\n letters in the extension's name, and let SM be the number of lowercase letters\n in the extension's name, the strength is given by the fraction CAP - SM.\n You should find the strongest extension and return a string in this\n format: ClassName.StrongestExtensionName.\n If there are two or more extensions with the same strength, you should\n choose the one that comes first in the list.\n For example, if you are given \"Slices\" as the class and a list of the\n extensions: [\"SErviNGSliCes\", \"Cheese\", \"StuFfed\"] then you should\n return \"Slices.SErviNGSliCes\" since \"SErviNGSliCes\" is the strongest extension\n (its strength is -1).\n Example:\n for StrongestExtension(\"my_class\", [\"AA\", \"Be\", \"CC\"]) == \"my_class.AA\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String StrongestExtension(String class_name, List extensions) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.StrongestExtension(\"my_class\", Arrays.asList(\"AA\", \"Be\", \"CC\")), \"my_class.AA\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String strong = extensions.get(0);\n int my_val = (int) (strong.chars().filter(Character::isUpperCase).count() - strong.chars().filter(Character::isLowerCase).count());\n for (String s : extensions) {\n int val = (int) (s.chars().filter(Character::isUpperCase).count() - s.chars().filter(Character::isLowerCase).count());\n if (val > my_val) {\n strong = s;\n my_val = val;\n }\n }\n return class_name + strong;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "strongestExtension"} +{"task_id": "Java/153", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You will be given the name of a class (a string) and a list of extensions.\n The extensions are to be used to load additional classes to the class. The\n strength of the extension is as follows: Let CAP be the number of the uppercase\n letters in the extension's name, and let SM be the number of lowercase letters\n in the extension's name, the strength is given by the fraction CAP - SM.\n You should find the strongest extension and return a string in this\n format: ClassName.StrongestExtensionName.\n If there are two or more extensions with the same strength, you should\n choose the one that comes first in the list.\n For example, if you are given \"Slices\" as the class and a list of the\n extensions: [\"SErviNGSliCes\", \"Cheese\", \"StuFfed\"] then you should\n return \"Slices.SErviNGSliCes\" since \"SErviNGSliCes\" is the strongest extension\n (its strength is -1).\n Example:\n for StrongestExtension(\"my_class\", [\"AA\", \"Be\", \"CC\"]) == \"my_class.AA\"\n */\n public String StrongestExtension(String class_name, List extensions) {\n", "canonical_solution": " String strong = extensions.get(0);\n int my_val = (int) (strong.chars().filter(Character::isUpperCase).count() - strong.chars().filter(Character::isLowerCase).count());\n for (String s : extensions) {\n int val = (int) (s.chars().filter(Character::isUpperCase).count() - s.chars().filter(Character::isLowerCase).count());\n if (val > my_val) {\n strong = s;\n my_val = val;\n }\n }\n return class_name + \".\" + strong;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.StrongestExtension(\"Watashi\", Arrays.asList(\"tEN\", \"niNE\", \"eIGHt8OKe\")), \"Watashi.eIGHt8OKe\"),\n Objects.equals(s.StrongestExtension(\"Boku123\", Arrays.asList(\"nani\", \"NazeDa\", \"YEs.WeCaNe\", \"32145tggg\")), \"Boku123.YEs.WeCaNe\"),\n Objects.equals(s.StrongestExtension(\"__YESIMHERE\", Arrays.asList(\"t\", \"eMptY\", \"nothing\", \"zeR00\", \"NuLl__\", \"123NoooneB321\")), \"__YESIMHERE.NuLl__\"),\n Objects.equals(s.StrongestExtension(\"K\", Arrays.asList(\"Ta\", \"TAR\", \"t234An\", \"cosSo\")), \"K.TAR\"),\n Objects.equals(s.StrongestExtension(\"__HAHA\", Arrays.asList(\"Tab\", \"123\", \"781345\", \"-_-\")), \"__HAHA.123\"),\n Objects.equals(s.StrongestExtension(\"YameRore\", Arrays.asList(\"HhAas\", \"okIWILL123\", \"WorkOut\", \"Fails\", \"-_-\")), \"YameRore.okIWILL123\"),\n Objects.equals(s.StrongestExtension(\"finNNalLLly\", Arrays.asList(\"Die\", \"NowW\", \"Wow\", \"WoW\")), \"finNNalLLly.WoW\"),\n Objects.equals(s.StrongestExtension(\"_\", Arrays.asList(\"Bb\", \"91245\")), \"_.Bb\"),\n Objects.equals(s.StrongestExtension(\"Sp\", Arrays.asList(\"671235\", \"Bb\")), \"Sp.671235\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You will be given the name of a class (a string) and a list of extensions.\n The extensions are to be used to load additional classes to the class. The\n strength of the extension is as follows: Let CAP be the number of the uppercase\n letters in the extension's name, and let SM be the number of lowercase letters\n in the extension's name, the strength is given by the fraction CAP - SM.\n You should find the strongest extension and return a string in this\n format: ClassName.StrongestExtensionName.\n If there are two or more extensions with the same strength, you should\n choose the one that comes first in the list.\n For example, if you are given \"Slices\" as the class and a list of the\n extensions: [\"SErviNGSliCes\", \"Cheese\", \"StuFfed\"] then you should\n return \"Slices.SErviNGSliCes\" since \"SErviNGSliCes\" is the strongest extension\n (its strength is -1).\n Example:\n for StrongestExtension(\"my_class\", [\"AA\", \"Be\", \"CC\"]) == \"my_class.AA\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String StrongestExtension(String class_name, List extensions) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.StrongestExtension(\"my_class\", Arrays.asList(\"AA\", \"Be\", \"CC\")), \"my_class.AA\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " String strong = extensions.get(0);\n int my_val = (int) (strong.chars().filter(Character::isUpperCase).count() - strong.chars().filter(Character::isLowerCase).count());\n for (String s : extensions) {\n int val = (int) (s.chars().filter(Character::isUpperCase).count() - s.chars().filter(Character::isLowerCase).count());\n if (val > my_val) {\n strong = s;\n my_val = val;\n }\n }\n return class_name + strong;\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "StrongestExtension"} {"task_id": "Java/154", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word\n cycpatternCheck(\"abcd\",\"abd\") => false\n cycpatternCheck(\"hello\",\"ell\") => true\n cycpatternCheck(\"whassup\",\"psus\") => false\n cycpatternCheck(\"abab\",\"baa\") => true\n cycpatternCheck(\"efef\",\"eeff\") => false\n cycpatternCheck(\"himenss\",\"simen\") => true\n */\n public boolean cycpatternCheck(String a, String b) {\n", "canonical_solution": " int l = b.length();\n String pat = b + b;\n for (int i = 0; i <= a.length() - l; i++) {\n for (int j = 0; j <= l; j++) {\n if (a.substring(i, i + l).equals(pat.substring(j, j + l))) {\n return true;\n }\n }\n }\n return false;\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.cycpatternCheck(\"xyzw\", \"xyw\") == false,\n s.cycpatternCheck(\"yello\", \"ell\") == true,\n s.cycpatternCheck(\"whattup\", \"ptut\") == false,\n s.cycpatternCheck(\"efef\", \"fee\") == true,\n s.cycpatternCheck(\"abab\", \"aabb\") == false,\n s.cycpatternCheck(\"winemtt\", \"tinem\") == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word\n cycpatternCheck(\"abcd\",\"abd\") => false\n cycpatternCheck(\"hello\",\"ell\") => true\n cycpatternCheck(\"whassup\",\"psus\") => false\n cycpatternCheck(\"abab\",\"baa\") => true\n cycpatternCheck(\"efef\",\"eeff\") => false\n cycpatternCheck(\"himenss\",\"simen\") => true", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public boolean cycpatternCheck(String a, String b) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.cycpatternCheck(\"abcd\", \"abd\") == false,\n s.cycpatternCheck(\"hello\", \"ell\") == true,\n s.cycpatternCheck(\"whassup\", \"psus\") == false,\n s.cycpatternCheck(\"abab\", \"baa\") == true,\n s.cycpatternCheck(\"efef\", \"eeff\") == false,\n s.cycpatternCheck(\"himenss\", \"simen\") == true\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int l = b.length();\n String pat = b + b;\n for (int i = 0; i <= a.length() - l; i++) {\n for (int j = 0; j <= b.length() - l; j++) {\n if (a.substring(i, i + l).equals(pat.substring(j, j + l))) {\n return true;\n }\n }\n }\n return false;\n }\n}", "bug_type": "value misuse", "failure_symptoms": "incorrect output", "entry_point": "cycpatternCheck"} {"task_id": "Java/155", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given an integer. return a tuple that has the number of even and odd digits respectively.\n \n Example:\n evenOddCount(-12) ==> (1, 1)\n evenOddCount(123) ==> (1, 2)\n */\n public List evenOddCount(int num) {\n", "canonical_solution": " int even_count = 0, odd_count = 0;\n for (char i : String.valueOf(Math.abs(num)).toCharArray()) {\n if ((i - '0') % 2 == 0) {\n even_count += 1;\n } else {\n odd_count += 1;\n }\n }\n return Arrays.asList(even_count, odd_count);\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.evenOddCount(7).equals(Arrays.asList(0, 1)),\n s.evenOddCount(-78).equals(Arrays.asList(1, 1)),\n s.evenOddCount(3452).equals(Arrays.asList(2, 2)),\n s.evenOddCount(346211).equals(Arrays.asList(3, 3)),\n s.evenOddCount(-345821).equals(Arrays.asList(3, 3)),\n s.evenOddCount(-2).equals(Arrays.asList(1, 0)),\n s.evenOddCount(-45347).equals(Arrays.asList(2, 3)),\n s.evenOddCount(0).equals(Arrays.asList(1, 0))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given an integer. return a tuple that has the number of even and odd digits respectively.\n \n Example:\n evenOddCount(-12) ==> (1, 1)\n evenOddCount(123) ==> (1, 2)", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public List evenOddCount(int num) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n s.evenOddCount(-12).equals(Arrays.asList(1, 1)),\n s.evenOddCount(123).equals(Arrays.asList(1, 2))\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " int even_count = 0, odd_count = 0;\n for (char i : String.valueOf(Math.abs(num)).toCharArray()) {\n if (i % 2 == 0) {\n even_count += 1;\n }\n }\n return Arrays.asList(even_count, odd_count);\n }\n}", "bug_type": "missing logic", "failure_symptoms": "incorrect output", "entry_point": "evenOddCount"} {"task_id": "Java/156", "prompt": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n /**\n Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> intToMiniRoman(19) == \"xix\"\n >>> intToMiniRoman(152) == \"clii\"\n >>> intToMiniRoman(426) == \"cdxxvi\"\n */\n public String intToMiniRoman(int number) {\n", "canonical_solution": " List num = Arrays.asList(1, 4, 5, 9, 10, 40, 50, 90, 100, 400, 500, 900, 1000);\n List sym = Arrays.asList(\"I\", \"IV\", \"V\", \"IX\", \"X\", \"XL\", \"L\", \"XC\", \"C\", \"CD\", \"D\", \"CM\", \"M\");\n int i = 12;\n String res = \"\";\n while (number > 0) {\n int div = number / num.get(i);\n number %= num.get(i);\n while (div != 0) {\n res += sym.get(i);\n div -= 1;\n }\n i -= 1;\n }\n return res.toLowerCase();\n }\n}", "test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.intToMiniRoman(19), \"xix\"),\n Objects.equals(s.intToMiniRoman(152), \"clii\"),\n Objects.equals(s.intToMiniRoman(251), \"ccli\"),\n Objects.equals(s.intToMiniRoman(426), \"cdxxvi\"),\n Objects.equals(s.intToMiniRoman(500), \"d\"),\n Objects.equals(s.intToMiniRoman(1), \"i\"),\n Objects.equals(s.intToMiniRoman(4), \"iv\"),\n Objects.equals(s.intToMiniRoman(43), \"xliii\"),\n Objects.equals(s.intToMiniRoman(90), \"xc\"),\n Objects.equals(s.intToMiniRoman(94), \"xciv\"),\n Objects.equals(s.intToMiniRoman(532), \"dxxxii\"),\n Objects.equals(s.intToMiniRoman(900), \"cm\"),\n Objects.equals(s.intToMiniRoman(994), \"cmxciv\"),\n Objects.equals(s.intToMiniRoman(1000), \"m\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}", "text": " Given a positive integer, obtain its roman numeral equivalent as a string,\n and return it in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examples:\n >>> intToMiniRoman(19) == \"xix\"\n >>> intToMiniRoman(152) == \"clii\"\n >>> intToMiniRoman(426) == \"cdxxvi\"", "declaration": "import java.util.*;\nimport java.lang.*;\n\nclass Solution {\n public String intToMiniRoman(int number) {\n", "example_test": "public class Main {\n public static void main(String[] args) {\n Solution s = new Solution();\n List correct = Arrays.asList(\n Objects.equals(s.intToMiniRoman(19), \"xix\"),\n Objects.equals(s.intToMiniRoman(152), \"clii\"),\n Objects.equals(s.intToMiniRoman(426), \"cdxxvi\")\n );\n if (correct.contains(false)) {\n throw new AssertionError();\n }\n }\n}\n", "buggy_solution": " List num = Arrays.asList(1, 4, 5, 9, 10, 40, 50, 90, 100, 400, 500, 900, 1000);\n List sym = Arrays.asList(\"I\", \"IV\", \"V\", \"IX\", \"X\", \"XL\", \"L\", \"XC\", \"C\", \"CD\", \"D\", \"CM\", \"M\");\n int i = 12;\n String res = \"\";\n while (number > 0) {\n int div = number / num.get(i);\n while (div != 0) {\n res += sym.get(i);\n div -= 1;\n }\n i -= 1;\n }\n return res.toLowerCase();\n }\n}", "bug_type": "missing logic", "failure_symptoms": "infinite loop", "entry_point": "intToMiniRoman"}