What score had a record of 17–18–6?
CREATE TABLE table_name_31 (score VARCHAR, record VARCHAR)
SELECT score FROM table_name_31 WHERE record = "17–18–6"
### Context: CREATE TABLE table_name_31 (score VARCHAR, record VARCHAR) ### Question: What score had a record of 17–18–6? ### Answer: SELECT score FROM table_name_31 WHERE record = "17–18–6"