How many against on the date of  08/06/1985?
CREATE TABLE table_name_64 (against INTEGER, date VARCHAR)
SELECT SUM(against) FROM table_name_64 WHERE date = "08/06/1985"
### Context: CREATE TABLE table_name_64 (against INTEGER, date VARCHAR) ### Question: How many against on the date of  08/06/1985? ### Answer: SELECT SUM(against) FROM table_name_64 WHERE date = "08/06/1985"