For each zip code, return the average mean temperature of August there.
CREATE TABLE weather (zip_code VARCHAR, mean_temperature_f INTEGER, date VARCHAR)
SELECT zip_code, AVG(mean_temperature_f) FROM weather WHERE date LIKE "8/%" GROUP BY zip_code
### Context: CREATE TABLE weather (zip_code VARCHAR, mean_temperature_f INTEGER, date VARCHAR) ### Question: For each zip code, return the average mean temperature of August there. ### Answer: SELECT zip_code, AVG(mean_temperature_f) FROM weather WHERE date LIKE "8/%" GROUP BY zip_code