Which 2009–10 has a Rank 2013 of 18?
CREATE TABLE table_name_87 (rank_2013 VARCHAR)
SELECT 2009 AS _10 FROM table_name_87 WHERE rank_2013 = "18"
### Context: CREATE TABLE table_name_87 (rank_2013 VARCHAR) ### Question: Which 2009–10 has a Rank 2013 of 18? ### Answer: SELECT 2009 AS _10 FROM table_name_87 WHERE rank_2013 = "18"