where did hancock get 3.09%
CREATE TABLE table_19681738_1 (county VARCHAR, hancock__percentage VARCHAR)
SELECT county FROM table_19681738_1 WHERE hancock__percentage = "3.09%"
### Context: CREATE TABLE table_19681738_1 (county VARCHAR, hancock__percentage VARCHAR) ### Question: where did hancock get 3.09% ### Answer: SELECT county FROM table_19681738_1 WHERE hancock__percentage = "3.09%"