Name the city with july of 88 °f / 31.1 °c
CREATE TABLE table_name_74 (city VARCHAR, jul VARCHAR)
SELECT city FROM table_name_74 WHERE jul = "88 °f / 31.1 °c"
### Context: CREATE TABLE table_name_74 (city VARCHAR, jul VARCHAR) ### Question: Name the city with july of 88 °f / 31.1 °c ### Answer: SELECT city FROM table_name_74 WHERE jul = "88 °f / 31.1 °c"