How many under the category of Against have a Difference of 11
CREATE TABLE table_15352382_1 (against VARCHAR, difference VARCHAR)
SELECT COUNT(against) FROM table_15352382_1 WHERE difference = 11
### Context: CREATE TABLE table_15352382_1 (against VARCHAR, difference VARCHAR) ### Question: How many under the category of Against have a Difference of 11 ### Answer: SELECT COUNT(against) FROM table_15352382_1 WHERE difference = 11