Name the city with Feb of 66 °f / 18.9 °c
CREATE TABLE table_name_63 (city VARCHAR, feb VARCHAR)
SELECT city FROM table_name_63 WHERE feb = "66 °f / 18.9 °c"
### Context: CREATE TABLE table_name_63 (city VARCHAR, feb VARCHAR) ### Question: Name the city with Feb of 66 °f / 18.9 °c ### Answer: SELECT city FROM table_name_63 WHERE feb = "66 °f / 18.9 °c"