Which Interview subject has a Pictorials of vida guerra?
CREATE TABLE table_name_30 (interview_subject VARCHAR, pictorials VARCHAR)
SELECT interview_subject FROM table_name_30 WHERE pictorials = "vida guerra"
### Context: CREATE TABLE table_name_30 (interview_subject VARCHAR, pictorials VARCHAR) ### Question: Which Interview subject has a Pictorials of vida guerra? ### Answer: SELECT interview_subject FROM table_name_30 WHERE pictorials = "vida guerra"