Name the nickname with age of 4.9
CREATE TABLE table_name_73 (nickname VARCHAR, age___ma__ VARCHAR)
SELECT nickname FROM table_name_73 WHERE age___ma__ = "4.9"
### Context: CREATE TABLE table_name_73 (nickname VARCHAR, age___ma__ VARCHAR) ### Question: Name the nickname with age of 4.9 ### Answer: SELECT nickname FROM table_name_73 WHERE age___ma__ = "4.9"