Who the Owner that has a Lengths Behind of 5½?
CREATE TABLE table_name_87 (owner VARCHAR, lengths_behind VARCHAR)
SELECT owner FROM table_name_87 WHERE lengths_behind = "5½"
### Context: CREATE TABLE table_name_87 (owner VARCHAR, lengths_behind VARCHAR) ### Question: Who the Owner that has a Lengths Behind of 5½? ### Answer: SELECT owner FROM table_name_87 WHERE lengths_behind = "5½"