What is the average year with an award of platinum?
CREATE TABLE table_name_44 (year INTEGER, award_description_s_ VARCHAR)
SELECT AVG(year) FROM table_name_44 WHERE award_description_s_ = "platinum"
### Context: CREATE TABLE table_name_44 (year INTEGER, award_description_s_ VARCHAR) ### Question: What is the average year with an award of platinum? ### Answer: SELECT AVG(year) FROM table_name_44 WHERE award_description_s_ = "platinum"