What is Anna Rogowska's average result?
CREATE TABLE table_name_7 (result INTEGER, name VARCHAR)
SELECT AVG(result) FROM table_name_7 WHERE name = "anna rogowska"
### Context: CREATE TABLE table_name_7 (result INTEGER, name VARCHAR) ### Question: What is Anna Rogowska's average result? ### Answer: SELECT AVG(result) FROM table_name_7 WHERE name = "anna rogowska"