Find the name of people whose age is greater than any engineer sorted by their age.
CREATE TABLE Person (name VARCHAR, age INTEGER, job VARCHAR); CREATE TABLE person (name VARCHAR, age INTEGER, job VARCHAR)
SELECT name FROM Person WHERE age > (SELECT MIN(age) FROM person WHERE job = 'engineer') ORDER BY age
### Context: CREATE TABLE Person (name VARCHAR, age INTEGER, job VARCHAR); CREATE TABLE person (name VARCHAR, age INTEGER, job VARCHAR) ### Question: Find the name of people whose age is greater than any engineer sorted by their age. ### Answer: SELECT name FROM Person WHERE age > (SELECT MIN(age) FROM person WHERE job = 'engineer') ORDER BY age