Which source reported 32.60% of browsers used Chrome?
CREATE TABLE table_name_43 (source VARCHAR, chrome VARCHAR)
SELECT source FROM table_name_43 WHERE chrome = "32.60%"
### Context: CREATE TABLE table_name_43 (source VARCHAR, chrome VARCHAR) ### Question: Which source reported 32.60% of browsers used Chrome? ### Answer: SELECT source FROM table_name_43 WHERE chrome = "32.60%"