What was the percentage of firefox was chrome was 23.90%
CREATE TABLE table_name_95 (firefox VARCHAR, chrome VARCHAR)
SELECT firefox FROM table_name_95 WHERE chrome = "23.90%"
### Context: CREATE TABLE table_name_95 (firefox VARCHAR, chrome VARCHAR) ### Question: What was the percentage of firefox was chrome was 23.90% ### Answer: SELECT firefox FROM table_name_95 WHERE chrome = "23.90%"