How many heats does Julia Wilkinson have?
CREATE TABLE table_name_88 (heat VARCHAR, name VARCHAR)
SELECT COUNT(heat) FROM table_name_88 WHERE name = "julia wilkinson"
### Context: CREATE TABLE table_name_88 (heat VARCHAR, name VARCHAR) ### Question: How many heats does Julia Wilkinson have? ### Answer: SELECT COUNT(heat) FROM table_name_88 WHERE name = "julia wilkinson"