How many July 1, 2013 projections have a Rank of 27?
CREATE TABLE table_name_58 (_2013_projection VARCHAR, july_1 VARCHAR, rank VARCHAR)
SELECT COUNT(july_1), _2013_projection FROM table_name_58 WHERE rank = "27"
### Context: CREATE TABLE table_name_58 (_2013_projection VARCHAR, july_1 VARCHAR, rank VARCHAR) ### Question: How many July 1, 2013 projections have a Rank of 27? ### Answer: SELECT COUNT(july_1), _2013_projection FROM table_name_58 WHERE rank = "27"