Name the awardee for tingya
CREATE TABLE table_24446718_3 (awardee_s_ VARCHAR, name_of_film VARCHAR)
SELECT awardee_s_ FROM table_24446718_3 WHERE name_of_film = "Tingya"
### Context: CREATE TABLE table_24446718_3 (awardee_s_ VARCHAR, name_of_film VARCHAR) ### Question: Name the awardee for tingya ### Answer: SELECT awardee_s_ FROM table_24446718_3 WHERE name_of_film = "Tingya"