Which score has a record of 58–15–8?
CREATE TABLE table_name_80 (score VARCHAR, record VARCHAR)
SELECT score FROM table_name_80 WHERE record = "58–15–8"
### Context: CREATE TABLE table_name_80 (score VARCHAR, record VARCHAR) ### Question: Which score has a record of 58–15–8? ### Answer: SELECT score FROM table_name_80 WHERE record = "58–15–8"