Show all allergies with type food.
CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food"
### Context: CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR) ### Question: Show all allergies with type food. ### Answer: SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food"