How many clubs have tries for count of 50?
CREATE TABLE table_12886178_5 (played VARCHAR, tries_for VARCHAR)
SELECT COUNT(played) FROM table_12886178_5 WHERE tries_for = "50"
### Context: CREATE TABLE table_12886178_5 (played VARCHAR, tries_for VARCHAR) ### Question: How many clubs have tries for count of 50? ### Answer: SELECT COUNT(played) FROM table_12886178_5 WHERE tries_for = "50"