Number of participants with a score 8.895 in preliminary
CREATE TABLE table_17088705_2 (interview VARCHAR, preliminary VARCHAR)
SELECT COUNT(interview) FROM table_17088705_2 WHERE preliminary = "8.895"
### Context: CREATE TABLE table_17088705_2 (interview VARCHAR, preliminary VARCHAR) ### Question: Number of participants with a score 8.895 in preliminary ### Answer: SELECT COUNT(interview) FROM table_17088705_2 WHERE preliminary = "8.895"