How many teams have 62 tries against?
CREATE TABLE table_15467476_3 (points_difference VARCHAR, tries_against VARCHAR)
SELECT COUNT(points_difference) FROM table_15467476_3 WHERE tries_against = "62"
### Context: CREATE TABLE table_15467476_3 (points_difference VARCHAR, tries_against VARCHAR) ### Question: How many teams have 62 tries against? ### Answer: SELECT COUNT(points_difference) FROM table_15467476_3 WHERE tries_against = "62"