Which 2002 has a 2008 of 3–3?
CREATE TABLE table_name_79 (Id VARCHAR)
SELECT 2002 FROM table_name_79 WHERE 2008 = "3–3"
### Context: CREATE TABLE table_name_79 (Id VARCHAR) ### Question: Which 2002 has a 2008 of 3–3? ### Answer: SELECT 2002 FROM table_name_79 WHERE 2008 = "3–3"