How many games are free of injury accidents?
CREATE TABLE injury_accident (id VARCHAR, game_id VARCHAR); CREATE TABLE game (id VARCHAR, game_id VARCHAR)
SELECT COUNT(*) FROM game WHERE NOT id IN (SELECT game_id FROM injury_accident)
### Context: CREATE TABLE injury_accident (id VARCHAR, game_id VARCHAR); CREATE TABLE game (id VARCHAR, game_id VARCHAR) ### Question: How many games are free of injury accidents? ### Answer: SELECT COUNT(*) FROM game WHERE NOT id IN (SELECT game_id FROM injury_accident)