Name the city with september of 83 °f / 28.3 °c
CREATE TABLE table_name_15 (city VARCHAR, sep VARCHAR)
SELECT city FROM table_name_15 WHERE sep = "83 °f / 28.3 °c"
### Context: CREATE TABLE table_name_15 (city VARCHAR, sep VARCHAR) ### Question: Name the city with september of 83 °f / 28.3 °c ### Answer: SELECT city FROM table_name_15 WHERE sep = "83 °f / 28.3 °c"