Name the summary for the success rate for 68.75%
CREATE TABLE table_15829930_5 (summary VARCHAR, success_rate VARCHAR)
SELECT summary FROM table_15829930_5 WHERE success_rate = "68.75%"
### Context: CREATE TABLE table_15829930_5 (summary VARCHAR, success_rate VARCHAR) ### Question: Name the summary for the success rate for 68.75% ### Answer: SELECT summary FROM table_15829930_5 WHERE success_rate = "68.75%"