How many no outs for an average of 56.38?
CREATE TABLE table_20367820_16 (not_out VARCHAR, average VARCHAR)
SELECT COUNT(not_out) FROM table_20367820_16 WHERE average = "56.38"
### Context: CREATE TABLE table_20367820_16 (not_out VARCHAR, average VARCHAR) ### Question: How many no outs for an average of 56.38? ### Answer: SELECT COUNT(not_out) FROM table_20367820_16 WHERE average = "56.38"