How many attempts did Charley Johnson have?
CREATE TABLE table_20906175_3 (attempts VARCHAR, name VARCHAR)
SELECT COUNT(attempts) FROM table_20906175_3 WHERE name = "Charley Johnson"
### Context: CREATE TABLE table_20906175_3 (attempts VARCHAR, name VARCHAR) ### Question: How many attempts did Charley Johnson have? ### Answer: SELECT COUNT(attempts) FROM table_20906175_3 WHERE name = "Charley Johnson"