What is the surface of the match on July 5, 2009?
CREATE TABLE table_name_95 (surface VARCHAR, date VARCHAR)
SELECT surface FROM table_name_95 WHERE date = "july 5, 2009"
### Context: CREATE TABLE table_name_95 (surface VARCHAR, date VARCHAR) ### Question: What is the surface of the match on July 5, 2009? ### Answer: SELECT surface FROM table_name_95 WHERE date = "july 5, 2009"