How many titles had an average rating of 8.9%?
CREATE TABLE table_18539834_2 (romaji_title VARCHAR, average_ratings VARCHAR)
SELECT COUNT(romaji_title) FROM table_18539834_2 WHERE average_ratings = "8.9%"
### Context: CREATE TABLE table_18539834_2 (romaji_title VARCHAR, average_ratings VARCHAR) ### Question: How many titles had an average rating of 8.9%? ### Answer: SELECT COUNT(romaji_title) FROM table_18539834_2 WHERE average_ratings = "8.9%"