What is the surface on 15 August 2009?
CREATE TABLE table_name_45 (surface VARCHAR, date VARCHAR)
SELECT surface FROM table_name_45 WHERE date = "15 august 2009"
### Context: CREATE TABLE table_name_45 (surface VARCHAR, date VARCHAR) ### Question: What is the surface on 15 August 2009? ### Answer: SELECT surface FROM table_name_45 WHERE date = "15 august 2009"