How many uninterrupted ranks does john dingell have?
CREATE TABLE table_name_87 (uninterrupted_rank VARCHAR, name VARCHAR)
SELECT COUNT(uninterrupted_rank) FROM table_name_87 WHERE name = "john dingell"
### Context: CREATE TABLE table_name_87 (uninterrupted_rank VARCHAR, name VARCHAR) ### Question: How many uninterrupted ranks does john dingell have? ### Answer: SELECT COUNT(uninterrupted_rank) FROM table_name_87 WHERE name = "john dingell"