Name the tries with tries against of 38
CREATE TABLE table_name_35 (tries_for VARCHAR, tries_against VARCHAR)
SELECT tries_for FROM table_name_35 WHERE tries_against = "38"
### Context: CREATE TABLE table_name_35 (tries_for VARCHAR, tries_against VARCHAR) ### Question: Name the tries with tries against of 38 ### Answer: SELECT tries_for FROM table_name_35 WHERE tries_against = "38"