Which county has 728 (43%) listed under C. Abate?
CREATE TABLE table_name_4 (county VARCHAR, c_abate VARCHAR)
SELECT county FROM table_name_4 WHERE c_abate = "728 (43%)"
### Context: CREATE TABLE table_name_4 (county VARCHAR, c_abate VARCHAR) ### Question: Which county has 728 (43%) listed under C. Abate? ### Answer: SELECT county FROM table_name_4 WHERE c_abate = "728 (43%)"