How many Years have Ratings of 10.9/23?
CREATE TABLE table_name_7 (year VARCHAR, ratings VARCHAR)
SELECT COUNT(year) FROM table_name_7 WHERE ratings = "10.9/23"
### Context: CREATE TABLE table_name_7 (year VARCHAR, ratings VARCHAR) ### Question: How many Years have Ratings of 10.9/23? ### Answer: SELECT COUNT(year) FROM table_name_7 WHERE ratings = "10.9/23"