what is the preliminary average score when the interview score is 8.600 (6)?
CREATE TABLE table_name_78 (preliminary_average VARCHAR, interview VARCHAR)
SELECT preliminary_average FROM table_name_78 WHERE interview = "8.600 (6)"
### Context: CREATE TABLE table_name_78 (preliminary_average VARCHAR, interview VARCHAR) ### Question: what is the preliminary average score when the interview score is 8.600 (6)? ### Answer: SELECT preliminary_average FROM table_name_78 WHERE interview = "8.600 (6)"