Name the number of years for 18.5
CREATE TABLE table_2181798_1 (year VARCHAR, avg_finish VARCHAR)
SELECT COUNT(year) FROM table_2181798_1 WHERE avg_finish = "18.5"
### Context: CREATE TABLE table_2181798_1 (year VARCHAR, avg_finish VARCHAR) ### Question: Name the number of years for 18.5 ### Answer: SELECT COUNT(year) FROM table_2181798_1 WHERE avg_finish = "18.5"