Which Date has a Record of 19–16–8?
CREATE TABLE table_name_43 (date VARCHAR, record VARCHAR)
SELECT date FROM table_name_43 WHERE record = "19–16–8"
### Context: CREATE TABLE table_name_43 (date VARCHAR, record VARCHAR) ### Question: Which Date has a Record of 19–16–8? ### Answer: SELECT date FROM table_name_43 WHERE record = "19–16–8"