Please write me python code to get all Fibonacci numbers until 10 with a recursive function.
user
Sure, here's a simple Python function that generates Fibonacci numbers using recursion:

```python
def fibonacci(n):
    if n == 0:
        return 0
    elif n == 1:
        return 1
    else:
        return fibonacci(n-1) + fibonacci(n-2)

numbers = [fibonacci(i) for I in range(10)]
print(numbers)
```

This function uses recursion to generate Fibonacci numbers. The `fibonacci` function returns the Fibonacci number for the given argument (n).

Please note that recursive calls can lead to a high memory usage and can crash smaller systems.

This works by first checking if n is 0, in which case we return 0. If n is 1, we return 1. Otherwise, we recursively call this function for `n-1` and `n-2`, and return the sum of those results.

We then loop over a range of numbers from 0 to 9 and call the `fibonacci` function for each of those numbers, resulting in a list of 10 Fibonacci numbers.

You'll get the following list as output:

```
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34]
```
assistant
Please write me python code to get all Fibonacci numbers until 10 with a recursive function.
user
Sure, here's a simple Python function that uses recursion to generate Fibonacci numbers. However, please note that this function generates the Fibonacci sequence up to the nth term, not up to a specific number. In this case, it's set to generate the first 10 Fibonacci numbers.

```python
def fibonacci(n):
    if n <= 0:
        return []
    elif n == 1:
        return [0]
    elif n == 2:
        return [0, 1]
    else:
        fib = fibonacci(n - 1)
        fib.append(fib[-1] + fib[-2])
        return fib

print(fibonacci(10))
```

If you want to generate all Fibonacci numbers up to a specific number (like 10), you would need a different approach, as recursion isn't well-suited for this task. Here's an iterative solution:

```python
def fibonacci_to(max_num):
    fib_nums = [0, 1]
    while True:
        next_num = fib_nums[-1] + fib_nums[-2]
        if next_num > max_num:
            break
        fib_nums.append(next_num)
    return fib_nums

print(fibonacci_to(10))
```

This function will return all Fibonacci numbers up to (and including) the given maximum number.
assistant