You are given the implementation of a `version_gt()` function that checks if one version number is greater than another. The function takes in two arguments, `version1` and `version2`, which are both strings representing version numbers. The function returns `true` if `version1` is greater than `version2`, and `false` otherwise.

The version numbers consist of one or more dot-separated numeric components. Each component can contain one or more digits. The comparison is done based on the numeric value of each component, with higher numeric values considered greater.

For example, given the version numbers "1.2" and "1.1", the function `version_gt("1.2", "1.1")` should return `true`, indicating that "1.2" is greater than "1.1".

You need to reimplement the `version_gt()` function to match the behavior described above.

Write a function `version_gt(version1: str, version2: str) -> bool` to solve the problem.

Function Signature: `def version_gt(version1: str, version2: str) -> bool:`

**Input**
- Two strings, `version1` and `version2` (1 <= |version1|, |version2| <= 10^3), where |version| represents the length of the version string.

**Output**
- Return `True` if `version1` is greater than `version2`, `False` otherwise.

**Example**

```
version_gt("1.0", "0.9") => True
version_gt("2.1", "2.1.1") => False
version_gt("3", "2.1.8") => True
```
user
Sure, here's a Python function `version_gt` that should do what you're asking for based on the specification you provided:

```python
def version_gt(version1: str, version2: str) -> bool:
    """
    Return True if `version1` is greater than `version2`, False otherwise.

    Assumptions:
    - Version strings consist of one or more dot-separated numeric components.
    - Each component can contain one or more digits.
    - Components are compared based on their numeric value, with higher values considered greater.
    """
    # Ensure both version strings have the same number of components
    num_components = len(version1.split("."))
    assert num_components == len(version2.split(".")), "Both version strings must have the same number of components."

    # Traverse both version strings component-wise
    for I in range(num_components):
        try:
            # Compare numeric values of current components
            if int(version1.split(".")[i]) > int(version2.split(".")[i]):
                # If one component is greater, return True
                return True
        except ValueError:
            # If either component is not numeric, return False
            return False

    # If no component differs, return False
    return False
```

Note: This function assumes that both input strings have the same number of components. If that's not always true in your use case, you may need to handle that case separately. Also, note the `assert` statement, which raises a `AssertionError` if the condition is not true. This is a debugging tool and should be handled appropriately in production code.
assistant
You are given the implementation of a `version_gt()` function that checks if one version number is greater than another. The function takes in two arguments, `version1` and `version2`, which are both strings representing version numbers. The function returns `true` if `version1` is greater than `version2`, and `false` otherwise.

The version numbers consist of one or more dot-separated numeric components. Each component can contain one or more digits. The comparison is done based on the numeric value of each component, with higher numeric values considered greater.

For example, given the version numbers "1.2" and "1.1", the function `version_gt("1.2", "1.1")` should return `true`, indicating that "1.2" is greater than "1.1".

You need to reimplement the `version_gt()` function to match the behavior described above.

Write a function `version_gt(version1: str, version2: str) -> bool` to solve the problem.

Function Signature: `def version_gt(version1: str, version2: str) -> bool:`

**Input**
- Two strings, `version1` and `version2` (1 <= |version1|, |version2| <= 10^3), where |version| represents the length of the version string.

**Output**
- Return `True` if `version1` is greater than `version2`, `False` otherwise.

**Example**

```
version_gt("1.0", "0.9") => True
version_gt("2.1", "2.1.1") => False
version_gt("3", "2.1.8") => True
```
user
Sure, here's a Python implementation of the `version_gt()` function. This function splits the version strings into lists of numeric components, then compares the components pairwise. If it encounters a pair where the first version's component is greater than the second version's, it returns `True`. If it encounters a pair where the first version's component is less than the second version's, it returns `False`. If it exhausts all pairs without finding a difference, it considers the versions equal and returns `False`.

```python
def version_gt(version1: str, version2: str) -> bool:
    v1_components = list(map(int, version1.split('.')))
    v2_components = list(map(int, version2.split('.')))

    max_len = max(len(v1_components), len(v2_components))
    v1_components += [0] * (max_len - len(v1_components))
    v2_components += [0] * (max_len - len(v2_components))

    for i in range(max_len):
        if v1_components[i] > v2_components[i]:
            return True
        elif v1_components[i] < v2_components[i]:
            return False

    return False
```

This function first splits the version strings into lists of components, and maps each component string to an integer. It then pads the shorter list with zeros at the end, so that both lists have the same length. This is to handle cases where one version has more components than the other (e.g., "2.1" vs "2.1.0"). Finally, it compares the components pairwise, returning `True` if it finds a pair where the first version's component is greater, and `False` otherwise. If it exhausts all pairs without finding a difference, it returns `False`, indicating that the versions are equal.
assistant