write a php routine that will take 100 names of people at an event and seat them at 10 tables randomly. Then, allow for the program to allocate the same 100 names to new tables where no two people are at the same table. For the third itteration, continue to allocate the names to new tables where the same people are not sat together again.
user
Sure, I can provide a PHP pseudocode for this, but please keep in mind that this is just an example, and it assumes that you already have an array of 100 names.

1. First, let's set the number of tables, which would be 10 in our case.

```php
$numTables = 10;
```

2. Next, we'll create an empty array to store the seats for each table.

```php
$seats = [];
for ($i = 0; $i < $numTables; $i++) {
    $seats[$i] = [];
}
```

3. Now, let's randomly allocate each name to a table.

```php
// Seed for random numbers
srand(time());

// Loop through all names
for ($i = 0; $i < 100; $i++) {
    // Generate a random table number
    $table = rand(0, $numTables - 1);

    // If the table already has someone, increment the table ranking
    if (count($seats[$table]) != 0) {
        $table++;
        if ($table >= $numTables) {
            $table = 0;
        }
    }

    // Add the name to the table
    $seats[$table][] = $names[$i];
}
```

4. For the second iteration, we'll create a new array to avoid mixing names from one table to another.

```php
// If you want to reuse the first array, you can make a copy of it
$newSeats = $seats;

// Otherwise, create a new array
$newSeats = [];
for ($i = 0; $i < $numTables; $i++) {
    $newSeats[$i] = [];
}

// Remove all the prior names already occupied
foreach ($newSeats as $table => $tableNames) {
    foreach ($tableNames as $name) {
        unset($seats[$table][array_search($name, $seats[$table])]);
    }
}

// Allocate each person to another table based on the previous table
for ($i = 0; $i < 100; $i++) {
    $table = rand(0, $numTables - 1);

    // If the table already has someone, increment the table ranking
    if (count($newSeats[$table]) != 0) {
        $table++;
        if ($table >= $numTables) {
            $table = 0;
        }
    }

    $newSeats[$table][] = $names[$i];
}
```

5. For the third time, you'll repeat the above method.

I hope this helps. Bear in mind that this is just a high-level pseudocode, and the actual implementation may be more complex than that. The algorithm is just one example, and it meets the overall request but does not guarantee that every person is spread across all tables or always perfectly rebalanced.
assistant
write a php routine that will take 100 names of people at an event and seat them at 10 tables randomly. Then, allow for the program to allocate the same 100 names to new tables where no two people are at the same table. For the third itteration, continue to allocate the names to new tables where the same people are not sat together again.
user
Here's a PHP routine that should accomplish what you're looking for. This script assumes that you have an array of 100 names. It creates a function called `seatAtRandomTables` that takes the array of names and the number of tables as arguments. The function will randomly seat people at tables, ensuring that no two people are at the same table in consecutive iterations.

```php
<?php

function seatAtRandomTables($people, $numTables)
{
    $currentSeating = [];
    $previousSeating = [];

    for ($i = 0; $i < $numTables; $i++) {
        $currentSeating[] = [];
        $previousSeating[] = [];
    }

    for ($iteration = 0; $iteration < 3; $iteration++) {
        shuffle($people);
        foreach ($people as $index => $person) {
            $tableIndex = $index % $numTables;

            // check if the person was seated at this table in the previous iteration
            if (in_array($person, $previousSeating[$tableIndex])) {
                $ TableToSwapWith = null;
                $personToSwapWith = null;

                // find a person that was not seated with this person in the previous iteration and swap tables
                for ($j = 0; $j < $numTables; $j++) {
                    if ($j != $tableIndex && !in_array($person, $previousSeating[$j])) {
                        $TableToSwapWith = $j;
                        $personToSwapWith = $previousSeating[$j][count($currentSeating[$tableIndex])];
                        break;
                    }
                }

                if ($TableToSwapWith !== null && $personToSwapWith !== null) {
                    array_push($currentSeating[$TableToSwapWith], $person);
                    array_push($currentSeating[$tableIndex], $personToSwapWith);
                } else {
                    array_push($currentSeating[$tableIndex], $person);
                }
            } else {
                array_push($currentSeating[$tableIndex], $person);
            }
        }

        // copy current seating to previous seating for the next iteration
        $previousSeating = $currentSeating;

        echo "Iteration " . ($iteration + 1) . "\n";
        foreach ($currentSeating as $tableIndex => $table) {
            echo "Table " . ($tableIndex + 1) . ": " . implode(", ", $table) . "\n";
        }
        echo "\n";
    }
}

$people = []; // Array of 100 names

for ($i = 0; $i < 100; $i++) {
    $people[] = 'Person_' . ($i + 1);
}

seatAtRandomTables($people, 10);

?>
```

This script will randomize the seating in three iterations and print the result for each iteration. It tries to avoid seating people from the same previous table, but please note that given the constraints (only 10 tables), it might not always be possible to prevent some overlap in all cases.
assistant