You are given a code snippet that contains a conditional statement. Inside the `else` block of the statement, there is code that assigns a value to the variable `url` based on the value of `response.request.url`.

Your task is to write a function that takes in a URL as a string and returns the assigned value of `url` based on the following rules:

- If the URL starts with "http://" or "https://", assign the URL itself to `url`.
- If the URL does not start with "http://" or "https://", assign "http://" followed by the URL to `url`.

Implement function:
```python
def assign_url(url: str) -> str:
    pass
```

**Input**
- A string `url` (1 <= len(url) <= 100), containing only lowercase letters, digits, and special characters.

**Output**
- Return the value of `url` based on the given rules.

**Example**
```python
assert assign_url("example.com") == "http://example.com"
assert assign_url("https://google.com") == "https://google.com"
```
user
Sure, here's a simple Python function that should do the job:

```python
def assign_url(url):
    if url.startswith("http://") or url.startswith("https://"):
        return url
    else:
        return "http://" + url
```

This function first checks if the URL starts with "http://" or "https://". If it does, it simply returns the URL. If it doesn't, it appends "http://" to the URL and returns the result.
assistant
You are given a code snippet that contains a conditional statement. Inside the `else` block of the statement, there is code that assigns a value to the variable `url` based on the value of `response.request.url`.

Your task is to write a function that takes in a URL as a string and returns the assigned value of `url` based on the following rules:

- If the URL starts with "http://" or "https://", assign the URL itself to `url`.
- If the URL does not start with "http://" or "https://", assign "http://" followed by the URL to `url`.

Implement function:
```python
def assign_url(url: str) -> str:
    pass
```

**Input**
- A string `url` (1 <= len(url) <= 100), containing only lowercase letters, digits, and special characters.

**Output**
- Return the value of `url` based on the given rules.

**Example**
```python
assert assign_url("example.com") == "http://example.com"
assert assign_url("https://google.com") == "https://google.com"
```
user
Sure, I can help you implement the function `assign_url` based on the given rules. Here's how you can do it:

```python
def assign_url(url: str) -> str:
    if url.startswith("http://") or url.startswith("https://"):
        return url
    else:
        return "http://" + url
```

In this function, we first check if the input URL starts with "http://" or "https://". If it does, we return the URL as it is. If it doesn't, we prepend "http://" to the URL and return the new URL. This function should work for the examples you provided and any other URL that follows the input constraints you specified.
assistant