You are given a list of code snippets in different programming languages and your task is to count the number of occurrences of a specific license in each snippet. The license is specified as a comment at the beginning of each snippet and is always in the format:

```
#
# This source code is licensed under the <License Name> found in
# the LICENSE.txt file in the root directory of this source tree.
```

Write a function `count_license_occurrences(snippets: List[str]) -> Dict[str, int]` that takes in a list of code snippets as input and returns a dictionary where the keys are the programming languages and the values are the number of occurrences of the license in each snippet.

**Example:**
```python
snippets = [
    """
    #
    # This source code is licensed under the Apache License, Version 2.0 found in
    # the LICENSE.txt file in the root directory of this source tree.
    """,
    """
    # License: MIT License

    # Code goes here...
    """,
    """
    // License: GNU General Public License v3.0

    // More code goes here...
    """
]

print(count_license_occurrences(snippets))
```

Output:
```
{
    'python': 1,
    'unknown': 1,
    'c': 1
}
```

**Constraints:**

* The input list `snippets` will contain between 1 and 1000 elements.
* Each snippet is a string consisting of printable ASCII characters.
* Each snippet will have at most 10,000 characters.
* The comment specifying the license will always start with a '#' character and is case-sensitive.
* The license name can contain letters, digits, spaces, and punctuation marks.
user
Sure, I'd be happy to help you write this function in Python. Here's a possible implementation:

```python
import re

def count_license_occurrences(snippets):
    licenses = {}
    license_pattern = r'#\n\W*?this(?: string )? is licensed\W*?(under\W*? the )? ([A-Za-z0-9\s\-\.\(\)\[\]\/\:\%\=\+\~]*)\s*? found\W*? in\W*? (the LICENSE\.txt|an (apache|mit|gplv3|etc)\.\d+\|an unknown license)\s*? file\W*? in the\W*? root directory\W*? of\W*? (this|an (unspecified|undetermined) source)\s*? (tree)?\b'

    for snippet in snippets:
        matches = re.findall(license_pattern, snippet, flags=re.MULTILINE)
        if not matches:
            continue
        for license, location in matches:
            language = snippet.partition('#')[0].strip()
            if language not in licenses:
                licenses[language] = 1
            licenses[language] += 1

    return licenses
```

This function uses a regular expression to find all licenses in each snippet. The regular expression matches comments that start with `#`, contain any non-word characters (`\W*?`) followed by "this is licensed", "under", "found in", "in the root directory", "in this tree", "an" (optional), and the license name, which is a sequence of letters, digits, spaces, hyphens, dots, parentheses, brackets, forward slashes, colons, percent signs, equals signs, plus signs, and tildes. The license name can also match one of "Apache License, Version 2.0", "MIT License", or "GNU General Public License v3.0" (optional), followed by a period and a number.

The function then counts the number of licenses in each language (or "unknown" if none are found) and returns a dictionary. The function is a simple demonstration of how you might approach this task with Python and PyPI's `re` module, and it may not be perfect in all cases. You could customize this function to better fit your use case, depending on your specific requirements.
assistant
You are given a list of code snippets in different programming languages and your task is to count the number of occurrences of a specific license in each snippet. The license is specified as a comment at the beginning of each snippet and is always in the format:

```
#
# This source code is licensed under the <License Name> found in
# the LICENSE.txt file in the root directory of this source tree.
```

Write a function `count_license_occurrences(snippets: List[str]) -> Dict[str, int]` that takes in a list of code snippets as input and returns a dictionary where the keys are the programming languages and the values are the number of occurrences of the license in each snippet.

**Example:**
```python
snippets = [
    """
    #
    # This source code is licensed under the Apache License, Version 2.0 found in
    # the LICENSE.txt file in the root directory of this source tree.
    """,
    """
    # License: MIT License

    # Code goes here...
    """,
    """
    // License: GNU General Public License v3.0

    // More code goes here...
    """
]

print(count_license_occurrences(snippets))
```

Output:
```
{
    'python': 1,
    'unknown': 1,
    'c': 1
}
```

**Constraints:**

* The input list `snippets` will contain between 1 and 1000 elements.
* Each snippet is a string consisting of printable ASCII characters.
* Each snippet will have at most 10,000 characters.
* The comment specifying the license will always start with a '#' character and is case-sensitive.
* The license name can contain letters, digits, spaces, and punctuation marks.
user
Here's a solution in Python:

```python
import re

LICENSE_PATTERN = re.compile(r'^\s*#\s*\n\s*#\s*This source code is licensed under the (.+) found in\s*\n\s*#\s*the LICENSE\.txt', re.MULTILINE | re.DOTALL)
COMMENT_PATTERNS = {
    'python': re.compile(r'^\s*#', re.MULTILINE),
    'unknown': re.compile(r'^\s*#', re.MULTILINE),
    'c': re.compile(r'^\s*//', re.MULTILINE),
}

def detect_language(snippet):
    for language, comment_pattern in COMMENT_PATTERNS.items():
        if comment_pattern.search(snippet):
            return language
    return 'unknown'

def count_license_occurrences(snippets):
    license_counts = {}
    for snippet in snippets:
        language = detect_language(snippet)
        license_match = LICENSE_PATTERN.search(snippet)
        if license_match:
            license_counts[language] = license_counts.get(language, 0) + 1
    return license_counts
```

Explanation:

1. We create two regular expressions: one for the license (`LICENSE_PATTERN`) and another one for detecting comments in different programming languages (`COMMENT_PATTERNS`, a dictionary where keys are language names, and values are the corresponding comment pattern).
2. We define a `detect_language` function that takes a code snippet and determines the programming language used by checking for comment patterns in the order of python, unknown, and C. If a comment pattern for a language is found, that language is returned; otherwise, 'unknown' is returned if no patterns are found.
3. We define the main function `count_license_occurrences`, which iterates through each snippet, detecting the programming language and looking for the license pattern using the `LICENSE_PATTERN` regular expression. If a match is found, we update the counter of occurrences for the detected programming language.
4. Finally, the function returns a dictionary with the programming languages as keys and the occurrences of the license as values.
assistant