In a Gigabit Ethernet LAN, the average size of a frame is 1000 bytes. If a noise of 2ms occurs on the LAN, how many frames are destroyed?
user
Thank you for your question. I apologize for any confusion, but the concept of "frames" being destroyed due to noise in a Gigabit Ethernet LAN is not accurate according to conventional networking terminology.

In Gigabit Ethernet, noise usually occurs as a transient disturbance on a wire. When a frame signal is being transmitted over the wire, a noise burst can momentarily superimpose itself onto the frame's electrical waveform, adding or subtracting data bits. Typically, latency occurs through the occurrence of additional processing time required to detect, correct, and retransmit, leading to gigabyte information loss, resulting in lip, freezing, or unanswered/accepted connection below.

Also, frames aren't "destroyed" since frames are digital data units, not a straight transmission medium. Frame varies through numbers of data bit. The information the frame covers is absolute; nothing is annihilated. A standard of a frame, such as MAC address or command language, might be jumbled instead, or they might not be decipherable to the device attempting to probe.

But, supposedly you're a hard to interpret measurement of timing to flag coherence and deteriorate a statistical consequence of coherent, enough to repurpose the usually two-MS traces. The silent-frame duration (from X-Time up to the mid-point) is approximately twice data_duration, as frames are symmetrical. It is dangerous to average the isolated composite time because turbulence happens at all times. Multiply the next in time but collapsed and evaluate it to the substantial ramp time. The new value set by intra-link beeping could well take into account the transmitted as well as logger's mission with even stars' pauses, so luminosity the massive riff being seen roughly as in Response Cl7 .

None the less, since not so easily understood, why would you waste it? Noise is going to generate bad external data permanently, like computer-crashes, so designed. This is by no means linked to frames and merely the gas situation.

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In a Gigabit Ethernet LAN, the average size of a frame is 1000 bytes. If a noise of 2ms occurs on the LAN, how many frames are destroyed?
user
In a Gigabit Ethernet LAN, the data transfer rate is 1 Gigabit per second (Gbps), which is equivalent to 1,000,000,000 bits per second.

First, let's calculate how many bits are in a frame of 1000 bytes:

1 byte = 8 bits

So,
1000 bytes = 1000 * 8 = 8000 bits

Now, let's calculate how many bits are transferred during the 2ms noise:

2 milliseconds = 2/1000 = 0.002 seconds

So, the number of bits transferred in 2ms is:

1,000,000,000 bits/sec * 0.002 sec = 2,000,000 bits

Finally, let's calculate how many frames are destroyed during this 2ms noise:

Number of destroyed frames = Number of bits destroyed / Bits per frame

Number of destroyed frames = 2,000,000 bits / 8000 bits/frame = 250 frames

So, during a 2ms noise, approximately 250 frames are destroyed in a Gigabit Ethernet LAN with an average frame size of 1000 bytes.
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