list both the id and number of shops for the company that produces the most expensive furniture in the same table
SELECT t1.manufacturer_id ,  t1.num_of_shops FROM manufacturer AS t1 JOIN furniture_manufacte AS t2 ON t1.manufacturer_id   =   t2.manufacturer_id ORDER BY t2.Price_in_Dollar DESC LIMIT 1
most expensive furniture refers to MAX(Price_in_Dollar); list both the id and number of shops refers to selecting manufacturer_id and num_of_shops;