private int reversal(int input){
		/*
		   Three things you need to know: 
			1. Taking the input integer and modding (%) by 10 will extract off the rightmost digit. example: (1234 % 10) = 4
			2. Multiplying an integer by 10 will "push it left" exposing a zero to the right of that number, example: (5 * 10) = 50
			3. Dividing an integer by 10 will remove the rightmost digit. (75 / 10) = 7
			
			Pseudocode:
			a. Extract off the rightmost digit of your input number. (1234 % 10) = 4
			b. Take that digit (4) and add it into a new reversedNum. 
			c. Multiply reversedNum by 10 (4 * 10) = 40, this exposes a zero to the right of your (4).
			d. Divide the input by 10, (removing the rightmost digit). (1234 / 10) = 123
			e. Rinse lather and repeat. 
		 */
		int reversedNum = 0;
		
		while (input != 0) {
		    reversedNum = reversedNum * 10 + input % 10;
		    input = input / 10;   
		}

		return reversedNum;
	}