If \(x \neq -1\), 1, or 3, which of the following is equivalent to \(\frac { x^2 - x } { 2x - 6 } \times \frac { x^2 - 2x - 3 } { x^2 - 1 } \) ?
(A)\(\frac { x } { 2 } \) (B)\(\frac { x + 3 } { 2(x - 3) } \) (C)\(\frac { x - 1 } { 2x - 6 } \) (D)\(\frac { x^2 - 3x - 3 } { 2x - 7 } \) (E)\(\frac { x^2 - x - 3 } { -7 } \)
A