Which of the following is equivalent to \(\frac { 2x^2 - 8 } { x^2 - 4x + 4 } \)?
(A)2 (B)\(\frac { 2(x + 2 } { x - 2 } \) (C)\(\frac { 2(x + 4) } { x - 4 } \) (D)\(\frac { 2x + 2 } { x - 2 } \) (E)\(\frac { 6 } { 4x - 4 } \)
B