text: We performed the same calculations of conductivities 
  and optical integrals as in the previous three cases. The 
  results are summarized in Figs. 17 - 22. Fig 17 shows con- 
  ductivities in the NS and the SCS for two couplings λ = 1 
  and λ = 10 (keeping λωsf constant). Other parameters 
  Zo and ωo are calculated according to the discussion after 
  Eq 21. for ωsf = 26 meV , λ = 1, we ﬁnd ωo = 40 meV , 
  Zo = 0.77. And for ωsf = 2.6 meV , λ = 10, we ﬁnd 
  ωo = 13.5 meV , Zo = 1.22. Note that the conductivity 
  in the SCS starts at 2∆ + ωo (i.e. the resonance energy 
  
  1 
  
  FIG. 20: ∆W (in meV) for λ = 1(top) and λ = 10(bottom). 
  We used ωsf = 26 meV /λ and ∆ = 30meV . The zero crossing 
  is not aﬀected because we keep λωsf constant. The notable 
  diﬀerence is the widening of the dip at a larger λ. 