listing finding the location of target value using the binary search modified version of the binary search that returns the index within sorted sequence indicating where the target should be located def findsortedpositionthelisttarget )low high len(thelist while low <high mid (high low/ if thelist[mid=target return mid index of the target elif target thelist[midhigh mid else low mid return low index where the target value should be value into the list the findorderedposition(function can also be used with lists containing duplicate valuesbut there is no guarantee where the new value will be placed in relation to the other duplicate values beyond the proper ordering requirement that they be adjacent merging sorted lists sometimes it may be necessary to take two sorted lists and merge them to create new sorted list consider the following code segmentlista listb newlist mergesortedlistslistalistb printnewlist which creates two lists with the items ordered in ascending order and then calls user-defined function to create and return new list created by merging the other two printing the new merged list produces [ problem solution this problem can be solved by simulating the action person might take to merge two stacks of exam paperseach of which are in alphabetical order start by choosing the exam from the two stacks with the name that comes first in alphabetical order flip it over on the table to start new stack againchoose the exam from the top of the two stacks that comes next in alphabetical order and flip it over and place it on top of first one repeat this process until one of the two original stacks is exhausted the exams in the remaining stack can be flipped over on top of the new stack as they are already in alphabetical order and alphabetically follow the