you see how to perform this task in this caseyou create file so that you can run the application multiple times this example also appears with the downloadable source code as simpleif py open python file window you see an editor in which you can type the example code type the following code into the window -pressing enter after each linevalue int(input("type number between and ")if (value and (value < )print("you typed"valuethe example begins by obtaining an input value you have no idea what the user has typed other than that it' value of some sort the use of the int(function means that the user must type whole number (one without decimal portionotherwisethe application will raise an exception (an error indication describes exceptionsthis first check ensures that the input is at least of the correct type the if statement contains two conditions the first states that value must be greater than you could also present this condition as value > the second condition states that value must be less than or equal to only when value meets both of these conditions will the if statement succeed and print the value the user typed choose runrun module you see python shell window open with prompt to type number between and type and press enter the application determines that the number is in the right range and outputs the message shown in figure - repeat steps and but type instead of the application doesn' output anything because the number is in the wrong range whenever you type value that' outside the programmed rangethe statements that are part of the if block aren' executed repeat steps and but type instead of python displays the error message shown in figure - even though you may think of and as both being numberspython sees the first number as floating-point value and the second as an integer