some simple algorithms and data structures when we ran this code it printed the value of the intdict is{ : , : , : , : , : , : , : , : : , : , : , : , : , : , : , : : , : , : , : the buckets are[( )[( )[[[[[( )[( )[( )[[( )[[( )[[[[[( )[( )[( )( )[( )( )[[( )( )[[( )( )( )[( )[[[( )when we violate the abstraction barrier and peek at the representation of the intdictwe see that many of the hash buckets are empty others contain onetwoor three tuples--depending upon the number of collisions that occurred what is the complexity of getvalueif there were no collisions it would be ( )because each hash bucket would be of length or butof coursethere might be collisions if everything hashed to the same bucketit would be (nwhere is the number of entries in the dictionarybecause the code would perform linear search on that hash bucket by making the hash table large enoughwe can reduce the number of collisions sufficiently to allow us to treat the complexity as ( that iswe can trade space for time but what is the tradeoffto answer this questionone needs to know tiny bit of probabilityso we defer the answer to since the integers were chosen at randomyou will probably get different results if you run it