1389_C. Good String
Let's call left cyclic shift of some string t_1 t_2 t_3 ... t_{n - 1} t_n as string t_2 t_3 ... t_{n - 1} t_n t_1.

Analogically, let's call right cyclic shift of string t as string t_n t_1 t_2 t_3 ... t_{n - 1}.

Let's say string t is good if its left cyclic shift is equal to its right cyclic shift.

You are given string s which consists of digits 0–9.

What is the minimum number of characters you need to erase from s to make it good?

Input

The first line contains single integer t (1 ≤ t ≤ 1000) — the number of test cases.

Next t lines contains test cases — one per line. The first and only line of each test case contains string s (2 ≤ |s| ≤ 2 ⋅ 10^5). Each character s_i is digit 0–9.

It's guaranteed that the total length of strings doesn't exceed 2 ⋅ 10^5.

Output

For each test case, print the minimum number of characters you need to erase from s to make it good.

Example

Input


3
95831
100120013
252525252525


Output


3
5
0

Note

In the first test case, you can erase any 3 characters, for example, the 1-st, the 3-rd, and the 4-th. You'll get string 51 and it is good.

In the second test case, we can erase all characters except 0: the remaining string is 0000 and it's good.

In the third test case, the given string s is already good.
```python
t = int(input())
for i in range(t):
    s=input()
    ans=0
    e=len(s)
    qr=0
    for j in range(10):
        for q in range(10):
            b=False
            r=0
            for i in range(len(s)):
                if j!=q:
                    
                    if (s[i]==str(j)) and (not b):
                        b=True
                        r+=1
                    if (s[i]==str(q)) and b:
                        b=False
                        r+=1
                else:
                    if s[i]==str(j):
                        r+=1
                   
                   
                   

            
            if j==q:
                ans=max(ans,r)
            else:
                r=r-r%2
                ans=max(ans,r)
    print(e-ans)

    


    
        

```