760_A. Petr and a calendar
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
```python
def read_input():
    line = input().strip().split()
    m = int(line[0])
    week = int(line[1])
    days31 = {1,3,5,7,8,10,12}
    if m == 2:
        days = 28
    elif m in days31:
        days = 31
    else:
        days = 30
    z = (days + week - 1)
    return z//7 if z % 7 == 0 else z//7 + 1

if __name__ == "__main__":
    print(read_input())
```