987_C. Three displays
It is the middle of 2018 and Maria Stepanovna, who lives outside Krasnokamensk (a town in Zabaikalsky region), wants to rent three displays to highlight an important problem.

There are n displays placed along a road, and the i-th of them can display a text with font size s_i only. Maria Stepanovna wants to rent such three displays with indices i < j < k that the font size increases if you move along the road in a particular direction. Namely, the condition s_i < s_j < s_k should be held.

The rent cost is for the i-th display is c_i. Please determine the smallest cost Maria Stepanovna should pay.

Input

The first line contains a single integer n (3 ≤ n ≤ 3 000) — the number of displays.

The second line contains n integers s_1, s_2, …, s_n (1 ≤ s_i ≤ 10^9) — the font sizes on the displays in the order they stand along the road.

The third line contains n integers c_1, c_2, …, c_n (1 ≤ c_i ≤ 10^8) — the rent costs for each display.

Output

If there are no three displays that satisfy the criteria, print -1. Otherwise print a single integer — the minimum total rent cost of three displays with indices i < j < k such that s_i < s_j < s_k.

Examples

Input

5
2 4 5 4 10
40 30 20 10 40


Output

90


Input

3
100 101 100
2 4 5


Output

-1


Input

10
1 2 3 4 5 6 7 8 9 10
10 13 11 14 15 12 13 13 18 13


Output

33

Note

In the first example you can, for example, choose displays 1, 4 and 5, because s_1 < s_4 < s_5 (2 < 4 < 10), and the rent cost is 40 + 10 + 40 = 90.

In the second example you can't select a valid triple of indices, so the answer is -1.
```python
mod = 1000000007
MOD = 998244353
ii = lambda :  int(input())
si = lambda :  input()
dgl = lambda : list(map(int, input()))
f = lambda :   map(int, input().split())
il = lambda :  list(map(int, input().split()))
it = lambda :  tuple(map(int, input().split()))
ls = lambda :  list(input())
n=ii()
l=il()
c=il()
mn=10**20
for i in range(1,n-1):
    lmn1=[c[j] for j in range(i) if l[j]<l[i]]
    lmn2=[c[j] for j in range(i+1,n) if l[j]>l[i]]
    if len(lmn1) and len(lmn2):
        mn=min(mn,min(lmn1)+min(lmn2)+c[i])
print(mn if mn!=10**20 else -1)
```