296_C. Greg and Array
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.

Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.

Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.

Input

The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.

Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).

Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).

The numbers in the lines are separated by single spaces.

Output

On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

Examples

Input

3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3


Output

9 18 17


Input

1 1 1
1
1 1 1
1 1


Output

2


Input

4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3


Output

5 18 31 20
```python
n, m, k = [int(n) for n in input().split()]
a = [int(n) for n in input().split()]
instructions = []
temp = []
for i in range(n+1):
	temp.append(0)
for i in range(m):
	instructions.append([int(n) for n in input().split()])
queries = []
for i in range(m+1):
	queries.append(0)
for i in range(k):
	x, y = [int(n) for n in input().split()]
	x-=1
	y-=1
	queries[x]+=1
	queries[y+1]-=1

num_queries = 0
for i in range(m):
	num_queries += queries[i]
	temp[instructions[i][0]-1] += num_queries*instructions[i][2]
	temp[instructions[i][1]] -= num_queries*instructions[i][2]
#print(temp[0]+a[0], end=" ")
x = temp[0]
print(x + a[0], end=" ")
for i in range(1, n):
	x += temp[i]
	print(x + a[i], end=" ")
print()
```