1238_F. The Maximum Subtree
Assume that you have k one-dimensional segments s_1, s_2, ... s_k (each segment is denoted by two integers — its endpoints). Then you can build the following graph on these segments. The graph consists of k vertexes, and there is an edge between the i-th and the j-th vertexes (i ≠ j) if and only if the segments s_i and s_j intersect (there exists at least one point that belongs to both of them).

For example, if s_1 = [1, 6], s_2 = [8, 20], s_3 = [4, 10], s_4 = [2, 13], s_5 = [17, 18], then the resulting graph is the following:

<image>

A tree of size m is good if it is possible to choose m one-dimensional segments so that the graph built on these segments coincides with this tree.

You are given a tree, you have to find its good subtree with maximum possible size. Recall that a subtree is a connected subgraph of a tree.

Note that you have to answer q independent queries.

Input

The first line contains one integer q (1 ≤ q ≤ 15 ⋅ 10^4) — the number of the queries. 

The first line of each query contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the number of vertices in the tree.

Each of the next n - 1 lines contains two integers x and y (1 ≤ x, y ≤ n) denoting an edge between vertices x and y. It is guaranteed that the given graph is a tree.

It is guaranteed that the sum of all n does not exceed 3 ⋅ 10^5.

Output

For each query print one integer — the maximum size of a good subtree of the given tree.

Example

Input


1
10
1 2
1 3
1 4
2 5
2 6
3 7
3 8
4 9
4 10


Output


8

Note

In the first query there is a good subtree of size 8. The vertices belonging to this subtree are {9, 4, 10, 2, 5, 1, 6, 3}.
```python
import sys
input = sys.stdin.readline
t = int(input())
for _ in range(t):
  n = int(input())
  ab = [list(map(int,input().split())) for i in range(n-1)]
  graph = [[] for i in range(n+1)]
  deg = [0]*(n+1)
  for a,b in ab:
    graph[a].append(b)
    graph[b].append(a)
    deg[a] += 1
    deg[b] += 1
  pnt = [max(deg[i]-1,1) for i in range(n+1)]
  root = 1
  stack = [root]
  dist = [0]*(n+1)
  dist[root] = pnt[root]
  while stack:
    x = stack.pop()
    for y in graph[x]:
      if dist[y] == 0:
        dist[y] = dist[x]+pnt[y]
        stack.append(y)
  far = dist.index(max(dist))
  root = far
  stack = [root]
  dist = [0]*(n+1)
  dist[root] = pnt[root]
  while stack:
    x = stack.pop()
    for y in graph[x]:
      if dist[y] == 0:
        dist[y] = dist[x]+pnt[y]
        stack.append(y)
  print(max(dist))
```