p00010 Circumscribed Circle of a Triangle
Write a program which prints the central coordinate $(p_x, p_y)$ and the radius $r$ of a circumscribed circle of a triangle which is constructed by three points $(x_1, y_1)$, $(x_2, y_2)$ and $(x_3, y_3)$ on the plane surface.

Constraints

* $-100 \leq x_1, y_1, x_2, y_2, x_3, y_3 \leq 100$
* $ n \leq 20$

Input

Input consists of several datasets. In the first line, the number of datasets $n$ is given. Each dataset consists of:

$x_1$ $y_1$ $x_2$ $y_2$ $x_3$ $y_3$

in a line. All the input are real numbers.

Output

For each dataset, print $p_x$, $p_y$ and $r$ separated by a space in a line. Print the solution to three places of decimals. Round off the solution to three decimal places.

Example

Input

1
0.0 0.0 2.0 0.0 2.0 2.0


Output

1.000 1.000 1.414
```python
import sys
f = sys.stdin

def take2(iterable):
    while True:
        yield next(iterable), next(iterable)
#外積
def cross(v1, v2):
    return v1.real * v2.imag - v1.imag * v2.real
# 線分13と線分24の交点を求める
def get_intersection(p1,p2,p3,p4):
    a1 = p4 - p2
    b1 = p2 - p3
    b2 = p1 - p2
    s1 = cross(a1, b2) / 2
    s2 = cross(a1, b1) / 2
    return p1 + (p3 - p1) * s1 / (s1 + s2)

n = int(f.readline())
for i in range(n):
    p1, p2, p3 = [x + y * 1j for x, y in take2(map(float, f.readline().split()))]
    p12 = (p1 + p2) / 2
    p13 = (p1 + p3) / 2
    pxy = get_intersection(p12,p13,p12 + (p2 - p1) * 1j,p13 + (p1 - p3) * 1j)
    r = abs(pxy - p1)
    print('{:.3f} {:.3f} {:.3f}'.format(pxy.real,pxy.imag,r))
```