p01511 Three-way Branch
There is a grid that consists of W \times H cells. The upper-left-most cell is (1, 1). You are standing on the cell of (1,1) and you are going to move to cell of (W, H). You can only move to adjacent lower-left, lower or lower-right cells.

There are obstructions on several cells. You can not move to it. You cannot move out the grid, either. Write a program that outputs the number of ways to reach (W,H) modulo 1,000,000,009. You can assume that there is no obstruction at (1,1).



Input

The first line contains three integers, the width W, the height H, and the number of obstructions N. (1 \leq W \leq 75, 2 \leq H \leq 10^{18}, 0 \leq N \leq 30) Each of following N lines contains 2 integers, denoting the position of an obstruction (x_i, y_i).

The last test case is followed by a line containing three zeros.

Output

For each test case, print its case number and the number of ways to reach (W,H) modulo 1,000,000,009.

Example

Input

2 4 1
2 1
2 2 1
2 2
0 0 0


Output

Case 1: 4
Case 2: 0
```python
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools

sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**13
mod = 10**9+9
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]

def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)


class Matrix():
    def __init__(self, A):
        self.A = A
        self.row = len(A)
        self.col = len(A[0])

    def __iter__(self):
        return self.A.__iter__()

    def __getitem__(self, i):
        return self.A.__getitem__(i)

    def __add__(self, B):
        aa = self.A
        bb = B.A
        return Matrix([[aa[i][j] + bb[i][j] for j in range(self.col)] for i in range(self.row)])

    def __sub__(self, B):
        aa = self.A
        bb = B.A
        return Matrix([[aa[i][j] - bb[i][j] for j in range(self.col)] for i in range(self.row)])

    def __mul__(self, B):
        bb = [[B.A[j][i] for j in range(B.row)] for i in range(B.col)]
        return Matrix([[sum([ak * bk for ak,bk in zip(ai,bj)]) % mod for bj in bb] for ai in self.A])

    def __truediv__(self, x):
        pass

    def pow_init(self, a):
        self.PA = pa = {}
        t = self.pow(a[0])
        c = a[0]
        pa[c] = t
        for d in a[1:]:
            t = t * self.pow(d-c)
            pa[d] = t
            c = d

    def pow(self, n):
        if n in self.PA:
            return self.PA[n]
        A = self
        r = Matrix([[0 if j != i else 1 for j in range(self.row)] for i in range(self.row)])
        while n > 0:
            if n % 2 == 1:
                r = r * A
            A = A * A
            n //= 2
        return r

    def __str__(self):
        return self.A.__str__()

def main():
    rr = []

    def f(w,h,n):
        a = sorted([LI()[::-1] for _ in range(n)])
        aa = [[0]*w for _ in range(w)]
        for i in range(w):
            ai = aa[i]
            ai[i] = 1
            if i > 0:
                ai[i-1] = 1
            if i < w-1:
                ai[i+1] = 1
        A = Matrix(aa)
        A.pow_init(list(map(lambda x: x[0], a)) + [h])
        t = [[0] for _ in range(w)]
        t[0][0] = 1
        T = Matrix(t)
        c = 1
        for hi,wi in a:
            T = A.pow(hi-c) * T
            T.A[wi-1][0] = 0
            c = hi
        T = A.pow(h-c) * T
        return T.A[-1][0]

    ci = 0
    while 1:
        ci += 1
        n,m,l = LI()
        if n == 0:
            break
        rr.append('Case {}: {}'.format(ci, f(n,m,l)))

    return '\n'.join(map(str, rr))


print(main())


```