p02692 AtCoder Beginner Contest 166 - Three Variables Game
There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A
```python
#from collections import deque,defaultdict
printn = lambda x: print(x,end='')
inn = lambda : int(input())
inl   = lambda: list(map(int, input().split()))
inm   = lambda:      map(int, input().split())
ins = lambda : input().strip()
DBG = True # and False
BIG = 10**18
R = 10**9 + 7

def ddprint(x):
  if DBG:
    print(x)

n,a,b,c = inm()
s = []
for i in range(n):
    s.append(ins())
ans = []
for i in range(n):
    #ddprint(f"{i=} si {s[i]} {a=} {b=} {c=}")
    if s[i]=='AB':
        if a==b==0:
            print('No')
            exit()
        elif a>b or a==b and i<n-1 and s[i+1]=='BC':
            ans.append('B')
            a -= 1
            b += 1
        else:
            ans.append('A')
            b -= 1
            a += 1
    if s[i]=='AC':
        if a==c==0:
            print('No')
            exit()
        elif a>c or a==c and i<n-1 and s[i+1]=='BC':
            ans.append('C')
            a -= 1
            c += 1
        else:
            ans.append('A')
            c -= 1
            a += 1
    if s[i]=='BC':
        if c==b==0:
            print('No')
            exit()
        elif c>b or c==b and i<n-1 and s[i+1]=='AB':
            ans.append('B')
            c -= 1
            b += 1
        else:
            ans.append('C')
            b -= 1
            c += 1
print('Yes')
for x in ans:
    print(x)

```