1352_B. Same Parity Summands
You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).

In other words, find a_1, a_2, …, a_k such that all a_i>0, n = a_1 + a_2 + … + a_k and either all a_i are even or all a_i are odd at the same time.

If such a representation does not exist, then report it.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100).

Output

For each test case print:

  * YES and the required values a_i, if the answer exists (if there are several answers, print any of them); 
  * NO if the answer does not exist. 



The letters in the words YES and NO can be printed in any case.

Example

Input


8
10 3
100 4
8 7
97 2
8 8
3 10
5 3
1000000000 9


Output


YES
4 2 4
YES
55 5 5 35
NO
NO
YES
1 1 1 1 1 1 1 1
NO
YES
3 1 1
YES
111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111120
```python
T = int(input())
for test in range(T):
    n, k = map(int, input().split())
    if n % 2 != 0 and k % 2 == 0:
        print("NO")
    else:
        if n % 2 != 0: # Ak is odd
            if (n - (k-1)) > 0 and (n - (k-1)) % 2 == 1:
                print("YES")
                temp = [1 for _ in range(k-1)]+[(n - (k-1))]
                for i in temp:
                    print(i, end = ' ')
                print()
            else:
                print("NO")
        else: # n is even ak is even
            if (n - 2*(k-1)) > 1 and (n - 2* (k-1)) % 2 == 0:
                print("YES")
                temp = [2 for _ in range(k - 1)] + [(n - 2*(k - 1))]
                for i in temp:
                    print(i, end = ' ')
                print()
            else:
                if (n - (k - 1)) > 0 and (n - (k - 1)) % 2 == 1:
                    print("YES")
                    temp = [1 for _ in range(k - 1)] + [(n - (k - 1))]
                    for i in temp:
                        print(i, end=' ')
                    print()
                else:
                    print("NO")







```