text: -- a)
  -- Answer: C)
  SELECT
      s.name,
      count(m.title) AS cnt
  FROM
      studio s
      JOIN movie m ON s.name = m.studioname
  GROUP BY
      s.name
  HAVING
      count(m.title) < 2;
  
  -- b)
  SELECT
      me.name
  FROM
      movieexec me
  WHERE
      me.networth = (
          SELECT
              min(networth)
          FROM
              movieexec);
  
  