text: '''
  Create a function that counts from 1 to 2000 
  and specifies the value as odd or even
  
  '''
  
  def oddOrEven():
  	for index in range(1, 2001):
  		if (index % 2) == 0:
  			print 'Number is ' + str(index) + '. This is an even number'
  		else:
  			print 'Number is ' + str(index) + '. This is an odd number'
  
  oddOrEven()
  