text: # Time:  O(n^2)
  # Space: O(1)
  #
  # Given an array S of n integers,
  # are there elements a, b, c in S such that a + b + c = 0?
  # Find all unique triplets in the array which gives the sum of zero.
  #
  # Note:
  # Elements in a triplet (a,b,c) must be in non-descending order. (ie, a <= b <= c)
  # The solution set must not contain duplicate triplets.
  #    For example, given array S = {-1 0 1 2 -1 -4},
  #
  #    A solution set is:
  #    (-1, 0, 1)
  #    (-1, -1, 2)
  import collections
  
  
  class Solution(object):
      def threeSum(self, nums):
          """
          :type nums: List[int]
          :rtype: List[List[int]]
          """
          nums, result, i = sorted(nums), [], 0
          while i < len(nums) - 2:
              if i == 0 or nums[i] != nums[i - 1]:
                  j, k = i + 1, len(nums) - 1
                  while j < k:
                      if nums[i] + nums[j] + nums[k] < 0:
                          j += 1
                      elif nums[i] + nums[j] + nums[k] > 0:
                          k -= 1
                      else:
                          result.append([nums[i], nums[j], nums[k]])
                          j, k = j + 1, k - 1
                          while j < k and nums[j] == nums[j - 1]:
                              j += 1
                          while j < k and nums[k] == nums[k + 1]:
                              k -= 1
              i += 1
          return result
  
      def threeSum2(self, nums):
          """
          :type nums: List[int]
          :rtype: List[List[int]]
          """
          d = collections.Counter(nums)
          nums_2 = [x[0] for x in d.items() if x[1] > 1]
          nums_new = sorted([x[0] for x in d.items()])
          rtn = [[0, 0, 0]] if d[0] >= 3 else []
          for i, j in enumerate(nums_new):
              if j <= 0:
                  numss2 = nums_new[i + 1:]
                  for x, y in enumerate(numss2):
                      if 0 - j - y in [j, y] and 0 - j - y in nums_2:
                          if sorted([j, y, 0 - j - y]) not in rtn:
                              rtn.append(sorted([j, y, 0 - j - y]))
                      if 0 - j - y not in [j, y] and 0 - j - y in nums_new:
                          if sorted([j, y, 0 - j - y]) not in rtn:
                              rtn.append(sorted([j, y, 0 - j - y]))
          return rtn
  
  if __name__ == '__main__':
      result = Solution().threeSum([-1, 0, 1, 2, -1, -4])
      print result
  