text: '''
  The sum of the squares of the first ten natural numbers is,
  
  1^2+2^2+...+10^2 = 385
  The square of the sum of the first ten natural numbers is,
  
  (1+2+...+10)^2 = 55^2 = 3025
  Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025−385=2640.
  
  Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
  '''
  # using some borrowed formulas we find the values
  #sum of squared natural numbers
  n = 100
  s1 = n*(n+1)*(2*n+1)/6
  
  #sum of the natural numbers sum, squared
  s2 = (n*(n+1)/2)**2
  # print the difference
  print(s2-s1)
  