text: /*
  The sum of the squares of the first ten natural numbers is,
                     1² + 2² + ... + 10² = 385
  
  The square of the sum of the first ten natural numbers is,
                  (1 + 2 + ... + 10)² = 55² = 3025
  
  Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is
                      3025 - 385 = 2640.
  
  Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
  */
  
  #include <bits/stdc++.h>
  
  #define LIMIT 100
  
  int sum_of_squares (int limit){
      int sum = 0;
      for (int i = 1; i <= limit; i++){
          sum += i*i;
      }
      return sum;
  }
  
  int square_of_sum (int limit){
      int sum = 0;
      for (int i = 1; i <= limit; i++){
          sum += i;
      }
      return sum*sum;
  }
  
  int main (){
      int diff_of_sum = square_of_sum(LIMIT) - sum_of_squares(LIMIT);
      std::cout << diff_of_sum;
      return 0;
  }
  